A NNALES DE L ’I. H. P., SECTION C
K. W YSOCKI
Multiple critical points for variational problems on partially ordered Hilbert spaces
Annales de l’I. H. P., section C, tome 7, n
o4 (1990), p. 287-304
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
Multiple critical points for variational problems
on
partially ordered Hilbert spaces
K. WYSOCKI Department of Mathematics, Rutgers University, U. S. A.
Ann. Inst. Henri Poincare,
Vol. 7, n° 4, 1990, p. 287-304. Analyse non linéaire
ABSTRACT. - We are
studying
the existence ofmultiple
criticalpoints
for functionals whose
potential operators
preserve an order structure.By using
Morsetype arguments
we prove that the existence of local minima of a functional ~ which are ordered in aspecial
way « forces » ~ to have many additional criticalpoints.
We also show how these abstract resultsapply
to a concrete situation.Key-words: Critical points, order structures, stable transition layers.
RESmvtE. - Nous etudions l’existence de
points critiques multiples
pour lesproblemes
variationnels dont lesopérateurs potentiels preservent
unestructure d’ordre en utilisant des
arguments
dutype
Morse. Nous demon- trons que, pour une fonctionnelle03A6,
l’existence de minima locauxqui
soientordonnes d’une maniere
particuliere
« force » ~ a avoirbeaucoup
d’autrespoints critiques.
Nous montrons comment ces resultats abstraitss’appli- quent
a une situation concrete.INTRODUCTION
The aim of this paper is to prove existence of
multiple
criticalpoints
of functionals 03A6 which are defined on ordered Hilbert spaces. More
preci- sely
westudy 4l E C2(H, R)
whosegradient
admits thedecomposition
Classification A. M. S. : 34B, 58E.
Annales de l’Institut Henri Poincaré - Analyse non linéaire - 0294-1449 Vol. 7/90/04/287/18/$ 3.80/@ Gauthier-Villars
288 K. WYSOCKI
Identity-K
with Kbeing compact
andincreasing
withrespect
to the orderstructure on H. The first results
concerning
functionals of thistype
were obtainedby
Hofer in[6].
Here we extend some of his results. Our Theorem 2.4 says that an order interval C which contains 2n local minima of 03A6 ordered in aspecial
way must contain at least3 n
criticalpoints.
Another
result,
Theorem2.5,
hasfollowing interpretation.
Let E be the set of all local minima of 03A6 and draw an
edge between u,
v E E iff u and v are order related and there is no such that this way we define an abstract
graph.
Then Theorem 2.5simply
states thatsubgraphs
of a certaintype correspond
to critical
points
of ~. Theproofs
of these results are based on Morsetype arguments adopted
to oursetting.
In section1,
we list someprelimi-
nary
results ;
in section2,
we prove our maintheorems ;
in section 3 weapply
our results to theproblem:
+u(l - u)(u - a(t )) - 0, u’ (O) - u’ ( 1 )
= 0. We prove that ifa(t) -1 /2
has k -1 zeros than theleast number of solutions of this
equation
isequal
to2k+ 2 + ( - 1)k-1
.3
Lastly,
we mention that in aforthcomming
paperusing
some ideas of[4]
we extend our results to cover
problems
without variational structure andapplicable
to PDE’s.1. NOTATION AND PRELIMINARIES
In this section we state some basic tools and results in critical
point
and Morse
theory.
Let H be a Hilbert space with scalar
product ( , )
andnorm )) ~.
If 03A6 E
C 1(U, R)
for some open subset U ofH, Ø ~ C cu,
and a ER,
S c R we setWe say that ~ satisfies
(PS)c (Palais-Smale
condition onC),
if forevery
sequence un ~ ~
C suchthat ~(un ) ~
is bounded and~’ (un ) --
0there is a
convergent subsequence Unk -
u E C.With
H*(X, Y)
we indicate thesingular cohomology
groups with R-coef- ficients of thepair
oftopological
spaces(X, Y),
If(X, Y)
is apair
oftopological
spaces we write(X, Y)
ETop2
if dimH ‘(X, Y)
for alli E N
U 0 j J
and defineThe
pair (X, Y)
ETop2
has a finitecohomology
ifP(X, Y) c
Z+ [t].
Itis known that if
(Xo,..., Xn)
is a(n
+1 )-tuple
oftopological
spaces suchthat
(Xi , Xi + 1)
ETop2, i = o, ... , n,
then there isQ(t ) E Z + [ [t] ] such
that,,n=o P(Xi, Xi
+1)(t)
=P(Xo,
+(1
+t)Q(t)
and if(Xi, Xi
+i)
has finitecohomology
thenQ(t)
EZ + [t].
We need the
following
definition.DEFINITION 1.1. - Let u be an isolated critical
point
of 03A6 E C1(U, R).
ThePoincare series of u is defined
by
where d =
~(u)
andWu
is an openneighborhood
of u such thatCr (~, U) r’1 Wu - ~ (u J.
If C is a closed subset of U then the Poincare series of u relative to C is defined
by
where d =
4l(u)
andWu
is an openneighborhood
of u such thatCr
(~, U)
n(
If C is a closed subset of U then the Poincare series of u relative to C is
defined by
where d =
4l(u)
andWu
is an openneighborhood
of u such that(u J.
Note that if C has
nonempty
interior and u E CrC)
n int Cthen
P~, u .
Also if u E C is an isolated local minimum then 1.The
following
lemma in the case U = C = H is well-known.LEMMA 1.2. - Let H be a Hilbert space, U open and C ~ U be closed and convex.
Suppose
that ~ EC2(U, R)
satisfies(PS)c
and itsgradient
4l ’has the
decomposition
I - K withK(C) ç
Ca)
If CrC, [a, oo)) = 0
then~a
n C is a deformation retract ofC, b)
If Cr(~, C, [a, b]) - ~
then ~a n C is a deformation retract ofc)
If Cr(~, C, [a, b)) - ~
then~a
n C is a deformation retract of4»b
n CBCr(~, C, b).
Proof.
- Theproof
is the usual one(see [8],
Lemma3.3).
To definedeformation retractions one can use the
positive
semiflow r~ associated to Vol.the differential
equation u = -,~( ~~ ~’ (u) ~) )~’ (u)
where~i(t) =
1 and=1/t,
t >_ 1.However,
in oursetting
we must make sure thatr~(t, ~)
E Cfor t *
0, ~
E C. But this follows from theassumptions
that C is closedconvex, C and the
sub-tangential
criterion(see [5],
Theo-rem
3 . 2) .
DUsing
Lemma 1.1 we canproof
thefollowing proposition.
PROPOSITION 1. 3 . - Assume that ~ E
C 2(U, R),
U is open and C c U is closed and convex. Assume that ~ satisfies(PS)c
and that 4l ’ = I - K with C. Let a b beregular
values of 03A6 on C.Suppose
thatthe set Cr
(~, C, (a, b))
is finite and if u ECr(I>, C, (a, b))
thenTop2, (d
=4l(u)).
Thenwhere
Q(t )
EZ + [ [t ] ] .
Inparticular,
if 03A6 is bounded on C and Cr(03A6, C)
is finite thenProof -
See[3J .
Weonly point
out that thearguments
of[3]
can be carried out in oursetting
because of Lemma 1.3. To prove(2)
we cantake a
info ~
and b so that Cr(~, C, [b, oo)) =
0. Thenusing
Lemma 1.1
a),
n nC)(t) =
nC, ~(t ) - P(C, ~)(t ) =1,
because C is convex. D
Before
stating
the next result we recall the Morse Lemma from[7].
Assume that H is a Hilbert
space, ~
EC2(U, R)
I - K where K iscompact. Suppose
that uo is an isolated criticalpoint
of 03A6 andH = is the canonical
decomposition
of H associatedvia the
spectral
resolution. Then there is ahomeomorphism
Ddefined in a
neighborhood
of uo in H such thatD(uo) =
uo and there is V EC2(Ho, R)
such that~(Du)=~(uo)-1/2 ~) u -uo I~2+ 1/2 I~ u+ -uo ~~2+~~u°-uo~ (3)
for all u = u-
+uo+u+
E H ~@ H° @ H + and ))
small.If p and uo are as above we denote the
negative
andby mO(uo)
the zero Morse index i . e. m -(uo)
= dimH - , m °(u°)
= dimH °
= dim ker
(~ " (u°)) .
In the next
proposition
we compute the Poincare series of criticalpoints
with certain Morse indices.
PROPOSITION 1.4. - Assume 03A6~
C2(U, R),
4l’ = I - K and K is compact. Assume that uo E U is an isolated criticalpoint
of 03A6 such that(m - (uo), mO(uo»
E(N U 0 ~ )
x{ 0, 1 ~ .
a)
Ifm°(uo) -
0 thenP~,uo (t) -
.CRITICAL POINTS AND ORDER
b)
Assume 1. Then we have three cases :i)
Ifuo
is a maximum of ’ then 1 .ii)
Ifug
is a minimum of ’ theniii )
Ifug
is a neither maximum nor minimum of 03A8 thenP03A6,u0(t)
= 0.Proof.
- We proveb),
since thepart a)
is a classical result. Forsimpli- city
we set uo = 0 and~(u°) -
0. Also we write m - -m - (0)
andBy (3)
we can writesmall.
be such that cl
(W) c
U andW_, Wo, W+
small balls around 0 inH ,
H °, H +.
Since dimH ° =1
weidentify W°
with(-6, 6) c
R. Define G :[0, 1]
x-po n W
Using (4)
it is easy to see that G and defines deformation retractions of~h°
n W onto~°
n(W_ Q+ Wo)
and(~°B ( 0 ) )
n W onto(~°~(~))
nW_O+Wo.
ThusH*(~
nW, ~h°B (0)
nW)
=H*(~h°
n(W_ O+ O°~ ~0) )
n W_O+ Wo)
In the case when 0 is a local minimum of W then
0, y ~ 0,
y E
( - 8, 8)
andusing (4)
This
implies
thatand this proves
0.
Assume now that 0 is a local minimum of if. Thenfor any y E
( - 6, 6)
and s E[0, 1]
and iffor t E
[0, 1],
x + y E~°
n W_O+ Wo
thenGl([o, 1 ]
x n W_Q+ Wo) ~
~"n
(W_ Again using (4), one can
show thatGi and Gi
define deformation retractions
Q+ Wo 0 ~
nw-Q+ Wo
ontoW_ and
W_B (0) respectively.
ThusVol. 7, n° 4-1990.
and
ii )
is obvious.Finally
assume that 0 is neither a maximum or aminimum of ~. We can assume that ’11 is
increasing
on( - 6, 6).
DefineThe
mapsG2
andprovides
deformation retractions of(W_ 0 W°) (0 n (W_
onto W_@ (- b, 0]
and W_@ ( - b, 0] B ~ 0 ~ .
Thus=
H*(W_ Q+ (-b, 0], W_ O+ (-b,
= 0and
iii )
is immediate. DThe above
proposition
hasinteresting
consequences. Let C be a closedconvex subset of
U,
int C ~ 0 and u E Cr(~, C)
n int C. If 1 then u contributes to(2)
ofProposition
1. 3 asnondegenerate
criticalpoint
or does not contribute at all.
The
following
concept will be useful later.By
an ordered Banach space we mean apair (F, P)
where F is a Banachspace and P is a closed convex subset of F such that
( - P)
n P= 0 j J
and
R +
x P c P. The set P is called a cone.Then we can define an
ordering
on Fby
If p, q E F and p s q then the set
[p, q] _ ~ x
EF ; J
is anorder interval. We say
that p,
q arecomparable if p - q E P U - P ;
otherwise
they
arenoncomparable.
Anoperator
T : F - F is order pre-serving if x s y implies Ty
andstrongly
orderpreserving
if x yimplies
TxT y.
2. EXISTENCE OF MULTIPLE CRITICAL POINTS
In this section we prove our main results
concerning
existence of mul-tiple
criticalpoints
of ~. For thefollowing
weimpose
the condition.(~) (H, P)
is an ordered Hilbert space the cone P has anonempty interior,
H is order- convex i. e. if u, v E U and u v then
[u, v ]
c:U,
4l EC2(U, R)
with agradient
~’ of the form I - K where K iscompact
andstrongly
orderpreserving.
’
If u E Cr
U)
thenK’ (u)
isstrongly
orderpreserving
and that for any u, v E satisfiesWe
point
out that if 03A6 satisfies and u, v E CrU)
such that u vthen
necessarilly
u v.Moreover,
if u E CrU)
then sinceK’ (u)
isself-adjoint
we haveK’ (u) ~ ~
> 0 and sinceK’ (u)
isstrongly
order
preserving
thenby
the Krein-Rutman result(see [1J) ~~
is aneigenvalue
ofK’ (u),
thecorresponding eigenspace
is one dimensional andspanned by
some w > 0.Using
that fact we derive :LEMMA 2.1. - Assume that ~ satisfies and that u E Cr
U)
withm _ (u)
> 1. Then there u suchthat ))
u - is small and>
4l(v).
Proof.
- Since ~ satisfies andm _ (u) >_
1 the above remarksimply
that the smallest
eigenvalue X (u)
isnegative
and thecorresponding eigenvector
w > 0. ThentP’(u
+tw) =
Xtw + andSince X > 0 we conclude that
~(v) ~(u)
and v u with v = u + swfor small s > 0. D
Let
[0,
be the standard n-cube inR n. By
V we denote the set of its vertices. A(n - 1)
dimensional face ofIn
is the set I x ... x Ix J
x I x I ... x I for some k E[ 1, ..., n J and ak equal
to 0 or 1. A(n - 2)
dimensional face of I n is a(n - 2)
dimen- sional face of some(n - 1)
dimensional face ofI,
and so on. We makethe
simple
observation that ifIi, 12
are k dimensional faces ofIn
theneither 11 = 12
orI1 ~ I2 = Ø
orI1 ~ 12 = 13
where13
is a(k - 1)
dimen- sional face. We also remark that each k dimensional face iscompletely
determined
by
its vertices and that the number of k dimensional faces ofIn
isgiven by n 2 n - k.
I is given
by
(nk) 2n-k.
We introduce an
ordering
on Vby
Now let E
:= u
EU ;
v is a local minimum With E we associatean abstract
graph (E, r)
where r ~ ~ x E is definedby
r
:= ( (u, v)
E Ex E;
u « v and thereThe elements of E are vertices and a
pair (u, v)
E r is theedge
of(E, r)
with end
points
u and v. If03A30~03A3
then0393|03A30 means ((u, v) E r ;
u,Vol. 7, n° 4-1990.
DEFINITION 2 . 2. - such that
if u,
v E andWe call
(En,
a n-cube if there is anisomorphism f: En -
Vwhich satisfies
A
pair
is a k-subcube of ifwhere
V~
is a set of vertices of some k dimensional face ofI n.
From now we will
identify
thegraphs (S, r), (En, rEn)
with their sets of verticesE,
En with theunderstanding
thatedges
are defined as above.Note that if En is a n-cube
then E"
contains the smallest and thegreatest element p and q, namely p = f -1 (o, ... , 0)
and q =f -1 ( 1, ... , 1 ) .
Withthe
n-cube En
we associate an order interval C =[p, q] where p, q
areas above.
Similarly if Ek
is a k-subcubeof En
we can associatewith 03A3k
an order interval
Ci = [pl , ql]
where PI and qI are the smallest and thegreatest
elements ofEx.
Note thatCi c
C.Moreover.
LEMMA 2 . 3. - Assume that En is a n-cube and are diffe-
rent
(n - 1)-subcubes
of E n and C =[ p, q], Ci = (i
=1, 2), corresponding
order-intervalsvia f.
Then eitherCi n C~ = 0
or there isexactly
one(n -
nE2-I
and ifC3 = [p3 , q3]
is the
corresponding
order interval thenCi n C2 .
More
precisely
there are fourpossibilities :
i)
p =pl =p2 =p3 , qi and q2 arenoncomparable
and q3 E int{C1 nC2).
ii) q
= qi = q2 = q3 , pi and p2 arenoncomparable
andp3 E
int(C nC2).
iii )
iv) pl -p3 ~ ~’2 = ~3 ~
~’1 = ~.Proof.
- Let =1, 2
be thecorresponding
viaf
set ofvertices of a
(n - I)-dimensional
faceIi of I n. Since ~ 1 -1 ~ E2-I
thenIf
Vi n V2 = ~
thenobviously Ci n C2 =
0. IfVi n V2 ~ ~
then11
nI2 = I3 .
Denoteby V3
the set of vertices of13.
Then andif
C3
is thecorresponding
order interval to v3 thenCi n C2 .
Therest of the lemma follows
easily by inspecting
vertices ofI1, I2 , 13.
QREMARK. - The
part iÜ)
andiv) simply
says thatCi n 0,
but elementsof En
which are inCi n C2
are contained inC3 .
For the rest of the paper we call an isolated critical
point
trivialif its Poincare
polynomial
isequal
to0 ;
otherwise a criticalpoint
is non-trivial. Now we can state our result.
THEOREM 2 . 4. -
Suppose
that ~ satisfies(~)
andthat En
is an-cube.Suppose
that C =[p, q]
is an order intervalcorresponding
to En andthat ~ is bounded from below on C. Assume that Cr
(~, C)
is finite andif u E Cr
(~, C)
then 1. Then there exists an odd number of nontrivial criticalpoints
in C and that number is at leastequal
to3 n.
LetCO = 1 Ci,
where theCl
are order intervalscorresponding
to all(n - 1)-subcubes
ofEn.
Then the setC°
contains an odd number of non-trivial critical
points
which are not minima of ~.Proof.
- In order to prove that we willapply Proposition
1.3 toorder intervals
[r, s], r, sEE.
Then 1 andif u E
Cr (~, [r, s])
n int[r, s]
then ~,.,sJ, u - Note also that sincemO(u)
s 1 then [r~ s], u is a monomial and the coefficient in front oftl
of the left side of
(I)
or(2)
ofProposition
1.3 is the number of criticalpoints
in[r, s]
with Poincarepolynomials t‘.
We prove the theoremby
induction.Let E1
1 be I-cube and C =[p, q]
thecorresponding
order interval.Then p, q
are theonly
local minima in C. Let ai, i E NU ( 0 ~ J
be thenumber of critical
points
in C whose Poincarepolynomials
aretI.
Then
ao = 2
andby (2)
ofProposition
1. 3for some
Q(t) - biti
EZ + [t].
After
substituting
t = 1 we getwhich
implies
that the totalnumber ~ °°_
1 ai of nontrivial criticalpoints
contained in
C° - C B ~ p, q ~ J
isodd,
and at leastequal
to 1. HenceC =
[p, q]
contains at least 3 nontrivial criticalpoints
and the number of nontrivial criticalpoints
in C is odd.Assume that the result holds for any k-cube with k s n - 1. Let 03A3n be
an-cube,
C =[p, q]
thecorresponding
order interval and letCi,..., C2n
be order intervalscorresponding
to(n - 1)-subcubes
ofEn.
By
the inductionassumption
each ofC1
contains an odd number of non-trivial critical
points
inC°
and none of them is a local minimum of ~.Denote the sets of nontrivial critical
points
inC° by Si,
i =1,...,
2n.First we claim that
Si fl ~~ - ~,
i ~j.
IfCi
nCy = 0
then this is obvious. Hence assume thatCI ~Cj ~
0. Forsimplicity
we takei =1, j
= 2and we write
C2 = [p2, q2]. By
the Lemma 2. 3 there is anorder interval
[p3 , q3]
such thatC1~C2. By
the same lemmathere are
essentially
two cases either pi =p3 ,q3
ql , q2 and ql , q2 arenoncomparable
or pip3 =p2
q3 = q2. In the later caseCl
nC2
=C12
and
then S n ~2
= ~since S n C12
=C12
= 0. In the contrary case assumethat there is u E
~1
n Consider D:=[u, ql]
n[u,
Then D is closedconvex, D has nonempty interior and D. Then
by Proposition
1 in[6]
Vol.
there is
u1 ~
D such that03A6’(u1) =
0 and Since K isstrongly
orderpreserving
qi q2 . If m -(u) ? 1
thenby
Lemma 2 .1we can find v > u, u E D such that >
03A6(03C5).
Thusu1 ~
u and ul E int D and ul is a local minimum of But then ul EC12
whichis
impossible
since u is not inC12.
If
m - (u) -
0(hence 1,
because otherwise u is a localminimum)
then since u is a nontrivial criticalpoint
we have two cases,either u is a local minimum of ’ or u is a local maximum of ’
(see
theMorse Lemma
(3)
for definition of~).
In the first case u isagain
a localminimum of In the second since is
spanned by
apositive eigen-
vector
(by
the Krein-Rutmanresult)
>03A6(03C5)
for some 0 E D. Asbefore ul is a local minimum of 03A6 and this is
impossible.
Thus§1 n ~2 -
0.With al,
i E NU ( 0 ~ denoting
the number of nontrivial criticalpoints
in C whose Poincare
polynomial
isti. By (2)
ofProposition
1.3 we haveao =
2 n
andTaking t
= 1 we set thatAs a consequence C contains an odd number of nontrivial critical
points.
Furthermore,
ifLi, L2
are different order interval in Ccorresponding
to two k-subcubes of
En, k s n - 1,
then thesets §1, ~2
of nontrivialcritical
points
of 03A6 contained inL?, Lg, respectively, satisfy 1~ 2=Ø
and then the total number of nontrivial critical
points
inU2n lCi
isequal
to b := where
Eo =
k-subcube of E n andb~o
is the numberof nontrivial critical
points
inL°,
L is an order interval associated withEo.
Butby
the inductionassumption bEo
is odd for any subcubeEo c En
and since for agiven
kE 0, ... , n - 1 ~ J
the number of allk-subcubes of
E n
is2"~ )
weget
that b is even. Since b is even and the number of all nontrivial criticalpoints
in C isodd, C°
must contain an odd number of nontrivial criticalpoints.
Finally,
since each order intervalcorresponding
to k-subcube of En(for
k =
0,..., n)
contains at least one nontrivial criticalpoint
inL°
there are at least~k= ° n k 2n ~ k - 3 n
criticalpoints
in C. 0For the next theorem
let E = {u
EU ;
u is local minimumof 03A6 }
andlet r c E x E be the set of
edges
defined as before.By
r~k we denote thecardinality
of the setTHEOREM 2. 5. - Assume that 03A6 satisfies
(03A6),
Cr(03A6, U)
is finite and 03A6 is bounded below on any[u, v],
u, v E E.Suppose
that if u E Cr(~, U)
then
mO(u) s
1. Let thecardinality I E I
of E beequal
to I and let k be thelargest integer
so that2k s
I. Then the number of nontrivial criticalpoints
of 4> is at least ..Proof.
-By
theprevious
theorem we know thatif En
isan-cube,
n >_ 1 then there is a nontrivial critical
point
which is not a local minimum contained inC°,
where C =[p, q]
is thecorresponding
order interval.Hence it is
enough
to show thatif En, E~
are different n- and k-cubes andCo, Ci k)
are order intervals associatedto En, Ek
then theabove solutions uo, ui are different.
Assume that
and
letCi
=[Pi’ ql ] ,
i =0,1.
Then u = uo =Ul E
If qo and ql arenoncomparable
thenby considering
D =[u, q°]
n[u, ql]
we can
find ul
E D so that and ~’(vl)
= O. Since u is a non-trivial critical
point
and is not a local minimum then L~ 1 is a local minimum of 03A6 andu vl
qo. Butthen vi E
En and since u EC?,
u isnoncomparable
to any element Thisimplies
a contra-diction.
Similarly,
po, pi cannot becomparable.
Hence we can assume that qo.Then p0 ~
u qo. But thenagain by
the definitionof
En, ql E En.
Thisimplies
u EC?
whichagain
is a contradiction.Thus Ul and the
proof
iscompleted.
D3. APPLICATION
In this section we illustrate the
previous
result. Weapply Proposition
2. 5to the
problem recently
studiedby Angenent,
Mallet-Paret and Peletier in[2]. They
consider anequation
in
which f (t, u)
=u(I- u)(u - a(t )) .
Here a is a C1-function [o,1 ]
-(0, 1 ) satisfying
For definitness we assume
a(0)
> 1/2. Webriefly
describe their resultsreferring
the reader to theoriginal
paper forinteresting
details.The main result of
[2]
states that if Z ={ t; a(t) = 1/2 J (by ii)
Z isfinite)
andZo E
Z is the sequence 0 1 ...t k
1 then there isan Eo > 0 such that for 0 E s Eo there is a stable solution of
(5-6)
anda’
(tl )u’ (tl )
0 for eachi,
and u is monotone in a smallneighborhood
of
each ti
and awayfrom ti
eitheru(t)
or 1 -u(t)
is small. Furthermore all stable solutions are obtained in this way.Here the
stability
of the solution u means that theprincipal eigen- value ~
of the linearizedproblem
is
nonpositive.
The
proof
of the existence of stable solutions is based on the method of super- and subsolutions. For agiven Zo ~ Z they
construct a subsolution uand a
supersolution
u for theproblem (5-6)
so that1:{(t) u(t ),
t E[0, 1 ] .
Thenthere is a stable solution u E
[u, m (see [1]).
Moreover,
for small E > 0 an order interval[u, MJ
containsexactly
onestable solution u and the
principal eigenvalue ~
of(7)
at u isstrictly
lessthan zero. Also note that the
problem (5-6)
has two obvious solutions u = 0and u == 1 and all solutions have their values in
[0, 1].
We will be interested in the
following question ;
assume that a is as aboveand Z ~ -
k. Let E besufficiently
small so that their theorem holds. We ask what is the least number of solutions of(5-6).
For the sake ofsimpli- city
we assume that e = 1. LetWe
equip
H with the innerproduct
Let P
= u
EH ; u(t ) >_ 0, t
E[0, 1]) j.
It is easy to show that
(H, P)
is an ordered Hilbert space and that P has nonempty interior.We define
The number X is chosen so that
f~, (t, ~ )
isincreasing
and~)
> 0 for t E[0, 1 ] , ~
E[0, 1].
LetThe critical
points
of 03A6 are theC2-solutions
of(1).
It is an easy exer- cise to show thatK, K’ (u)
arecompact,
that dim kerK I (u) s
1 and that ~ is bounded below on[uo, ul]
and satisfies where uo -0,
ul - l.
The maximum
principle implies
that K andK I (u)
arestrongly
orderpreserving
and if u ii aresupersolution
and subsolution of(5-6)
thenK([u, [u, M].
We remark that thestability
of a solution u of(5-6)
means that
(~ " (u)h,
0 for any h E H.Furthermore,
if u is a stable solution of(5-6)
then thenegativity
of theprincipal eigenvalue (see (7)) implies
Hence,
if u is a stable solution of(5-6)
then(~ " (u)h, h)~, >_
p( ~
hh E H and that means u is a strict local minimum of ~. On the other
hand,
if u is a local minimum of 03A6 then
(03A6" (u)h, h)03BB ~
0 and u must be astable solution. Thus all stable solutions found in
[2]
are all local minimaof ~.
We denote the set of all local minima of 03A6
by
E. Letti
...tk-l
1be the zeros of
a(t) -
1/2 andto = 0, tk -
1. With eachpoint
u E E weassociate a
k-tuplet
of numbersa(u) = -(«1, ... , ak)
in thefollowing
way :Moreover from the fact that
a’(ti)u’(ti)
0 for u EE,
i =I , ... ,
k itfollows that
a(u) = («1, ... , ak)
satisfies : ai = 1 for i oddimplies
«1 + 1 = 1 and ai = 0 for i even
implies
«I + 1 = o.A sequence of k numbers
(«1, ... , ak),
aiE 0, 1 ~
with the above pro-perty
will be called admissible of thelength
k.Let C~ = be the set of all admissible sequences of the
length
k.We introduce an
ordering
on the set C~by
The examination
of
the construction in~2]
of subsolution u and super- solution M shows that ifa(u)
_a(u) then u ~ v and
ïi s v. We also have that a : E - C~ is orderpreserving.
LEMMA
3.1.
-If u,
v E E then u v aa(u) a(v)
and if there isi E { 1, ... , k ~ J
such thatthen the order interval
[u, u]
does not contain any element of E different than u orv.Proof. -
It is obvious that u vimplies a(v).
The construc- tion of subsolution andsupersolution
u, M shows thata(u) = a(v) gives
u = v
(by
theuniqueness proved
in[2]).
If u v then we must have u ~ u anda(u) a(v)
because otherwise u. Assume thata(u) a(v)
but u and v arenoncomparable.
Sincea(v) implies have ~
uand u v. Consider D :=
[u, u]
n[u, v].
We have D and 03A6 is bounded below on D. Thus there is a criticalpoint
w of 03A6 such thatHence w is a classical solution of
(5-6)
andBut
[u, u]
containsexactly
one minimum ofnamely
u and thisgives
a contradiction. Thus
a(u) a(v) implies
u v. The lastpart
is thesimple
consequence of the
previous.
DAs in the section 2 we associate with S an abstract
graph (C~, r’ )
wherethe set of
edges
r’ is defined asLemma 3.1 says that the
graphs (a, r’ )
and(E, r),
where r is definedas in section
2,
areisomorphic.
According
to Theorem 2. 5 the total number of nontrivial criticalpoints
of 03A6 is at least
equal
Hence we have to find that number.
THEOREM 3.2. -
Let t1
...tk_
i be the set of all solution ofa(t) =
1/2. Then the least number of solutions of(5-6)
isIn order to prove that result let be the number of all I-cubes in the
graph (G, r’ )
where (~ -C~(k)
is the set of all admissible sequences oflength k.
We set 0 if k s 0 and 0 if k ~ I > 1(because i f~{k) ~ I 2k
and thepoints
of cannot form I-cubes ifk>_ I >
1).
First we prove :
LEMMA 3.3. - The numbers
N/(k) satisfy
thefollowing
recurrent for-mulas :
Proof.
- For I = 0 and k = 1 there are two admissible sequencesnamely (0)
and(1).
If k = 2 theonly
admissible sequences are(0, 0), (0, 1 )
and
(1, 1).
ThusNo(I)
= 2 andNo(2) =
3.Taking
I = 1 and k = 1 wesee that there is
exactly
one1-cube, namely
anedge ((0), ( 1 )),
and if I = 1and k = 2 there are two
edges ((0, 0), (0, 1))
and((0, 1), (1, 1)).
Hence1 and
Ni(2) =
2.Now let I >_
0,
2 and let be the set of all I-cubes inC~(k).
We can write
where
(Bo, CB is
the set of all I-cubes inC~(k)
whose sets of vertices havethe last
entry equal
to 0 and1, respectively,
and a I-cube W is an elementof
CB2
if it contains vertices with last entryequal
to 0 and also vertices with lastentry equal
to l.The sets
Go, (Bi,
andCB2
aredisjoint
and thusLet I = 0. Then
CB2
= 0 andBi
are the sets of admissible sequences with lastentry equal to i,
i =0,
1. If k is odd and(«1, ... , ak)
ECBo
thenak =
0,
can beequal
to 0 or1,
and(« 1, ... ,
E(~(k -1 ) .
ThenIf i then and
(«1, ... , a(k - 2). Hence ~ ~ 1 ~ I
=No(k - 2).
This shows thatNo(k) = No(k - 1)
+No(k - 2)
if k is odd. The case k is even similar.Now let I >_ 1 and k is odd. The other case is the same. Assume that W E
(Bo
and if
W ’ - ~ (« 1, ... , (« 1, ... ,
EW
then W ’ is a I-cube inC~(k - 1). Thus I I
=N/(k - 1).
Similarly
if W E631
then any(aI’..., ak)
E W mustsatisfy
ak-l i = ak = I and(« 1, ... , «k _ 2) E C~(k - 2),
andW ’ _ ~ (GY
1 , ... , «k _2) (GY
1 , ... ,GYk )
EW J
is a I-cube in
a(k- 2). Thus I
=N/(k- 2).
Hence we have to prove thatI CB2 = Nr-1 (k - 2).
Note that it isenough
to show that if W ECB2
thenW = («, 1, 1), (a, 1, 0) ;
a EW j
where W’ is the set of vertices of some(I - I )-cube
inC~(k - 2).
We prove the above claimby
induction.Let 1=1 and W E
CB2
be a 1-cube. Thenobviously
W= («,1,1 ), («,1, o) },
for some a E
C~(k - 2).
Vol. n° 4-1990.
Assume that our claim holds for any r-cube E
CB2
for r :s l -1. LetW E
CB2
be a I-cube inC~(k).
First we show that W does not contain ver-tices of the form
(a’, 0, 0)
with a’ EC~(k - 2).
Assume it does. Fixa =
(a’, 0, 0)
E W and letWi
be a(I - 1)-subcube
of W which containsa =
(a’, 0, 0).
ThenWl
does not contain a vertex of the form( ~3, 1, I),
because if( ~3, 1, 1) E Wi
then also( ~, 1, 0)
EWi
andby
the inductionassumption Wi = {(03B3, 1, 1), (y, 1, 0),
whereWl’
is a(I - 2)-
cube in
(k - 2).
Hence all vertices ofWI
have last entry 0. Buta =
(a’, 0, 0) belongs
toI, (I - 1)-subcubes
ofW,
andconsequently
allof these
(I - I)-subcubes
have all vertices with last entry 0. The number of vertices of(I - I)-subcubes
of W which contain a =(a’, 0, 0)
isequal
to
2/ -
1. On the otherhand,
since W ECB2
there is a vertex in W whoselast
entry
is 1 andagain applying
our inductionassumption
we can findanother vertex in W with last
entry
1. But then the number of elements of W isgreater than 2/
whichgives
a contradiction. Hence the vertices of W have the form(a, 1, 0), ( ~3, 1, 1).
Therefore the I-cube Wnecessarily
contains a(I - I)-subcube Wi
such thatwhere
Wl’
is a(I - 2)-cube
ofa(k - 2).
Let Y
= ( («, 1, 1 ) ; (a, 1, 1)
EW j.
We will show that Y is a(I - 1)-
cube in(k).
Fix(a, 1, I)
EWi .
Then(a, 1, 1)
can be connectedby
anedge
to I verticesof W ;
to(a, 1, 0),
to( ~3, 1, I) with ~3 ~ Wi’
and to(I - 2)
vertices which are of the form(y, 1, I), Wl’.
LetBB~
be a(I - I)-cube
which contains vertices(y, 1, 1), l’ E W1’ and (03B2, 1, 1).
Notethat
by
the inductionassumption W2
does not contain any vertex of theform
(a, 1, 0).
In a similar way, if
Yl = (a, 1, 0) ; (a , 1, 0)
EW
we can find a(l -1 )-cube W3
with vertices of the form(y, 1, 0),
y E
C~(k - 2)
such that and21-1= ~ iN§ ) Yl ~ -
But then sinceI W = 21
and Y we must haveY = W2 and Yl
Thisimplies
that Y and
Yl
are(I - I)-cubes
ina(k)
and thatwhere Y’ and
Yl
are(I - I)-cubes
inC~(k - 2).
Now we have to showthat Y’ =
Yi’.
Since W is a I-cube there arel21-1
1edges
inW ; (I - 1 )21- 2
of them between elements(a, 1, 1), (,~, 1, 1), a, {3
EY’, (/ - I)2/-z
between(a, 1, 0), ( ~i, 1, 0),
a,Yl’,
and the rest21-1
between
(a, 1, 1), ( (3, 1, 0),
a EY’ , ~i E Yl’.
But the last ispossible
ifa =
(3.
Hence Y’ =Y/
and our claim isproved.
DNow we can prove Theorem 2. 5.
Proof. - Using
the same notation as in the lemma we see that the last number of solutions of(5-6)
isN(k) =
First we claim thatlinéaire
CRITICAL POINTS AND ORDER
Hence the
proof
iscompleted.
DThe
following
table showscomparison
between the number of stable solutionsNo(k)
and the leastnumber, N(k),
of all solutions of(5-6)
forsome values of k.
k
No(k)
N(k)1 2 3 2 3 5
5 13 43
10 144 1 365
20 17 711 1 398 101
25 196 418 44 739 243
ACKNOWLEDGEMENTS
I wish to thank
Prof.
H. Hofer for useful discussions and sugges- tions.Vol. 7, n° 4-1990.