A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
G USTAF G RIPENBERG
Compensated compactness and one-dimensional elastodynamics
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 22, n
o2 (1995), p. 227-240
<http://www.numdam.org/item?id=ASNSP_1995_4_22_2_227_0>
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One-Dimensional Elastodynamics
GUSTAF GRIPENBERG
1. - Introduction and Statement of Results
One of the standard methods of
solving
nonlinearequations
is toreplace
the
equation
with another oneinvolving
aregularizing parameter
E, show that thisequation
has a solution and then pass to the limit eJ,
0. One of the difficulties is then to show that one obtains a solution in the limit.Usually
itis not too hard to show that the
approximating
solutions convergeweakly
insome sense, but if the
equation
isnonlinear,
this is not of much use because ifu, - u
weakly
thenf (uE)
need not convergeweakly
towardf (u).
If one knewthat u, - u in some stronger sense this would not be a
problem
in most cases.Thus the issue is one of lack of
compactness.
In the context of certain conservation
laws,
inparticular
theequations
ofone-dimensional
elastodynamics
of the formthere is successful
theory
of how to, under certainassumptions, compensate
for this lack ofcompactness
with other reasonableassumptions
that can be shownto hold true in many cases. Luc Tartar invented the method which first
appeared
in
[11] (see
also[12]) using
a crucial lemma due to Murat[7].
DiPema[2]
was the first to find out how to use the method for
systems (as
in( 1 ))
and in[10]
a more abstractquestion
related to Tartar’s method was considered. Laterdevelopments
can be found in[5]
and[6].
The lecture notes[3]
are useful asa
general
reference.The purpose of this paper is to show that this
theory
works for conservation laws of the form(1)
under weakerhypotheses
on u(concerning
the zeroes ofthe second
derivative)
than those used in e.g.[2]
and[10]. Moreover,
thesePervenuto alla Redazione il 21
Maggio
1993 e in forma definitiva il 13 Ottobre 1994.assumptions
are not too restrictive in terms of what oneusually
has to assumeof the
nonlinearity
in order to obtain theapriori bound,
see e.g.[ 1 ], although
there is
cleary
still room forimprovements.
Note that these results areapplicable
to
equations
that areperturbations
of(1)
aswell,
see[8].
Recall that a
continuously
differentiable function q :R2 --+
R is anentropy
for the conservation law(1)
withcorresponding entropy
flux q iffor every smooth solution
(w, v)
of(1).
Suchpairs (11, q)
are obtained as solutionsof the system of
equations
THEOREM. Assume that
(i)
u E is such thatinfuER u’(u)
> 0 and there exists apoint
w, E I~ U such that a’ is
nonincreasing
on(-oo, wo)
and nonde-creasing
on(wo, oo).
(ii) If
thepoint.
w,, in(i)
cannot be chosen to be ~oo, then it isunique,
u E
C(R; R),
and(w -
> 0 on the interval(wo,
wo +6)
or on the interval(wo - 6, wo) for
some 6 > 0.(iii)
w,, v, E x(0, oo); R ) for
each E E(0,1 )
and(iv)
For everycontinuously differentiable
entropy-entropyflux pair (77, q) of (1)
andfor
each bounded open set U c lI~ x(0, oo)
thefunctions 77 (w,,, v E) v E) CE(O, 1) belong
to a compact set in
H-1(U;R)
Then there
exist functions
w and v ELl (R
x(0, oo); R)
and some sequence such that Wfj --+ w, --+u(w),
and vweakly-*
inx
(0, oo); R)
asej 1
0.Moreover, if
a’ is not constant on any openinterval,
then Wfj --+ w, and Vfj --+ vpointwise
in II~ x(0, oo).
In
[2]
and[10]
itis,
instead of(ii),
assumed that U is twicecontinuously
differentiable and (1" vanishes at one
point
at most, in which case(ii)
mustclearly
be satisfied.In
[4]
it is shown how one can construct a function U which satisfies(i) (with
wo =0)
and is such that U EC2«-00,0)U(0,00);R)
andwu"(w)
> 0 whenw ~ 0,
but so that(iii)
and(iv)
do notimply
the second conclusion of the theorem.
The boundedness
assumption (iii)
couldeasily
bereplaced by
theassumption
that Wo Vf E x(0, oo) ; R)
for each f E(0, 1)
and that one hasfor every bounded open set U c R
x(0,oo),
if a
corresponding
smallchange
is made in the statement of the conclusion.One sees from the
proof
below that if a’ isstrictly decreasing
on(-oo, wo)
andstrictly increasing
on(w,,, oo),
then one can find asubsequence
so that we.and vej,
convergepointwise
almosteverywhere. Moreover,
if one can take 6 in(ii)
to beinfinite,
then it is not necessary to assume that there isonly
onepoint
for which
(i)
holds.When
proving
that the functions wE and v, are bounded and whendeciding
which of
perhaps
many weak solutions of(1)
is thephysically
relevant one, itis in most cases of crucial
importance
that theentropies
one studies are convex.In this paper, the
entropies
are notnecessarily
convex.2. - Proof
It follows
immediately
from(iii)
that there exist a sequence(ej)
andfunctions w and v E x
(0, oo); R)
so that Wfj --+ w and vE~ --+ vweakly-*
in x
(0, oo); R)
asEj 10.
By
the Div-Curl Lemma(see [3,
p.53]
or[7])
we conclude thatif >
denotes the
Young
measure at somepoint (x, t) (see [3,
p.15])
associated withsome
subsequence
then it follows(for
almost every(x, t))
thatwhere
(~, q)
and(1]*, q*)
are twocontinuously
differentiableentropy-entropy
fluxpairs,
see[3,
p.60].
Suppose
for the moment that we havealready
shown that it follows from(3)
that (1’ is constant on an intervalcontaining
the set{w
E EWe know that at the
points
where thesupport
of theYoung
measure u consists of asingle point
the functions Wfjand vll,
convergepointwise,
see[3,
p.16].
For the otherpoints
we deduceby
a similarargument
that the distance from to an interval where (1’ is constant tends to 0. Because the sequencefwjl
convergesweakly
in for every measurable bounded subset E of R x(0, oo)
aswell,
there are convex combinations of this sequences that converge in the norm ofL2(E; R) (see, [9,
Thm.3.13])
and hence somesubsequence
of these convex combinations that convergespointwise.
But if forsome
point (x, t)
the distance from thepoint
to an interval where a’ is constant tends to 0, then00
where
L
1 and thus we can conclude that the weak-* limit j=kmust
which,
of course, is the crucialpoint
in the statement of thetheorem.
In the
remaining parts
of theproof,
in view of the aboveargument,
weonly
have to show that it follows from(3)
that is constant on an intervalcontaining
the set~w
E E or, inparticular,
that thesupport
of JL consists of asingle point.
In thisargument
we may and shall without loss ofgenerality
assume that we have w,, = 0 unlessIwol =
oo.Although
theentropy-entropy
fluxpairs
that we shall consider and the firststeps
of theproof
are almost standard ones, we shall forcompleteness
andnotational convenience describe them in
fairly
close detail. Theentropies
areof the form
0..
and the
corresponding entropy
fluxes arewhere k > 0 and order for
(2)
to be satisfied the function1/; It
must be a solution of the differentialequation
(Note
that with this formulation of theentropy-entropy
fluxpairs
theexpansions usually employed
are in way hidden in the relation(5)).
Werequire
that1/J1t
satisfies the initial condition
where M is some
sufficiently large
number so that thesupport of it
is contained in[-M, M]
x[-M, M].
With this initial condition(5)
has aglobal
solution.Next,
weinvestigate how 0,,
behaveswhen lit
-~ oo and we assume that(J is twice
continuously
differentiable. LetIt is clear that px is a solution of the
equation
and if we solve this
equation
we obtain thefollowing expressions
for px:Is is
straightforward
to see that if0,,(w)
>infsER
does not hold for somew E
[-M, M],
then weget
a contradiction from(5).
Therefore it follows from(7)
thatWe claim that it is
possible
to conclude from(7)
that in additionTo see
this,
consider forexample
the case x > 0 and note thatwhen -M - 1 t w M. Thus it follows from
(7)
thatThe
proof
of the claim now follows from the fact thatand when x - oo the first term converges to
1 / (2F)
and the second to 0(by (8)
and thecontinuity
of~’ (· )),
bothuniformly
for w e[ - M, M].
If 03C3 is not twice
continuously differentiable,
then the distribution derivative is a continuous measure withlocally
bounded variation and it is easy tosee that
(8) holds,
andalthough (9)
need not hold we have at leastand that will be sufficient for our purposes in this case.
Finally
we letA
simple
calculation shows thatIf we
integrate
both sides of thisequality
over(w 1, w2 ),
do anintegration by parts,
and use the definition of§x
once more, then we conclude thatThus it follows from
(9)
and the definition of0,,
thatThis
completes
ourinvestigation
of the function Let 03A9 = a,03B2
E{ -1,1 },
and letw
(see
thepicture below).
Thefunctions
are the so-called Riemann invariants and one could take them as oindependent
variables instead of wand v.We denote
by (wa,o, va,o)
thepoint
where the curvesr«,_a
intersectand
by (wo,,8, vO,,8)
thepoint
where the curvesr a,,8
andr-,,,,6
intersect.(If
(J’ = 1and Q =
+ v ( 1 },
then(wa,o, va,O)
isactually
thepoint (a, 0)
and(wo,,8, vo,a)
is thepoint (o, ~3)).
Let be a
probability
measure that one obtains as the weak limit(of
some
subsequence)
of the sequence ofprobability
measuresas k 2013~ 00. It is
quite
easy to see from(6), (8),
and( 12)
that the supportof is contained in
Let us now choose
’q *
= andq*
= in(3)
where a,/?~{-!,!}
and k > 0. If we divide both sides of
(3) by f
and leta
l~ --~ oo, then we obtain from
(4), (8),
and the definition of thatNext we take q = ?7-.,-P,k and q = q-,,,-P,k, divide both sides of
equation (13)
by f 77-,,-P,k(W,
and let A; 2013~ oo. The conclusion we shallget
is thatQ
If then
(14)
follows from the fact that in this case we haveIf on the other hand
r~ = T’_a,_p,
then if follows that the functionw
(w, v)
’2013~a + ,Qv
is constant on S2 and if we combine this result0 w w
a
with
(10)
and with the fact that = e 0 ~ 1 thenwe see that = ~-~,-/3 and this
gives,
of course,(14).
From
(13)
and(14)
we furthermore deduce thatNext we show that
Since all cases are similar it suffices to prove that
va,o) c 0’a:,¡3.
·Suppose
that this is not the case. Then we
take q
= and q = qa:,-¡3,k in( 13),
divideboth sides
by v)li(dwdv)
and let k --> oo. Because we assumed that0
the
support
is bounded away from the curver«,_a
we conclude thatThus we
get
and since
~’
isstrictly positive,
we have a contradiction.Let
/3*
E{ - l,1 }
be such that who,,. > who,-;. Then w > w’ for all(w, v)
Ef2l,,8.
and(w’, v’)
ESZ_ 1,_,~* .
Therefore it follows from(14) (with
a = 1and
~3 =/3*)
and(16)
that if (1’ is monotone on[w-i,o, w i,o],
then it must be aconstant.
Thus it remains to consider the case where u’ has its minimum
point
0inside the interval
[w-,,o,wl,ol
and we shall derive a contradiction from theassumption
that S2 is not asingle point.
First we consider the case where wo,,3* > 0 or 0.
Suppose
thatthe first
inequality
holds. Because the inflectionpoint
0 of (1 isunique by (ii)
we know that
Q’ (wo,,~* )
>u’(0).
w
Denote
by
p+ the valueof
onIFI,,6*
andby
p- the valueo
on
r_ l,_,~* .
It follows from our choice of{3*
that we must have p+ > p- unless S2 consists ofexactly
onepoint.
Note that on the setsQl,,3*
andS2_l,_a*
wew
have
~3*v = p± 2013 ~
Thus we can, whenintegrating
over these sets,o
replace
03BC±1,±03B2*by
measures v±supported
on[wo,,6*,wi,ol
andrespectively.
In
(15)
we take « = 1,~3 = /3*, ?y
=and q
= where k > 0 anduse the notation
presented
above.By (4)
and(6)
we then haveLet G be the
support
of u". From the fact that >Q’(o)
it follows that we must haveG n (o, wo,a* ) ~ ~.
Therefore we conclude from(7)
that forsufficiently large
values of k we havefor some
positive
constant cl . On the other hand we haveby (8)
and(10)
thatwhere c2 is some
positive
constant.Inserting
these twoinequalities
into(17)
we
get
tU
-k f
where c3 cie o .
Moreover,
it is easy to check that becausew
-
-
+ is constant on the curveconnecting
thepoints
0
and we have
W-t,0
Because 0 we
have
0 and therefore it follows fromo
( 16)
and( 19)
that( 18) gives a
contradiction when k --4 oo and theproof
iscompleted
in this case.The final case that we have to consider is the one where wo,,6. = = 0.
In order to
simplify
the notation we define w+ = wl,o and w- = w-l,o.Let us first show that the
supports
of v+ and v- cannot intersect the set To do this wemultiply
both sides of(17) by ke-kp+
andusing
the fact that p+ > p- we
get by (9)
when k --+ oo thatSince u" is
nonnegative
on thesupport
of v+ it follows that thissupport
cannot intersect the set where u" isstrictly positive. Similarly
one shows that thesupport
of v- cannot intersect the set where u " isstrictly negative.
Let us, without loss of
generality,
assumethat u"(w)
> 0 if 0 w6,
where 6 is somepositive
number. When we combine thisassumption
with(16)
and with the result derived
above,
we conclude that andIn
(15)
we now take a = 1,,Q
= 1, 77 = 77-1,1,k, and q = and k > 0.w
By (4)
and the fact that v =P::J:. - f
onQij
andQ-i,-i, respectively,
o we have
and,
sinceby (19),
weget
Therefore it follows from
(20)
and(21)
when we let k - oo that v- must havea
point
mass at w-. Moreprecisely,
we see from(9)
that we must haveBecause the
support
of v- cannot intersect the set we have~ "(w_ )
= 0 =Q "(o)
and it follows from(9)
thatand we
get
from(11)
and the definition of§k
thatSince
we see
by (the
firstpart of) (23)
and(24)
thatwhere
because wo = 0 was
unique.
From the second part of(20)
we see that there issome
positive
constant c4 so thatIf we insert
(25)
and(26)
in(21)
we conclude with the aid of(the
secondpart
of) (23)
that ’If we now let k -+ oo we get a contradiction from
(22) because 1
> 0. Thiscompletes
theproof.
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