A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
E RIC B EDFORD D AN B URNS
Holomorphic mapping of annuli in C
nand the associated extremal function
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 6, n
o3 (1979), p. 381-414
<http://www.numdam.org/item?id=ASNSP_1979_4_6_3_381_0>
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Holomorphic Mapping
and the Associated Extremal Function.
ERIC BEDFORD
(*) -
DAN BURNS(*)
Introduction.
For a
complex
manifoldQ, Chern,
Levine andNirenberg [6]
have de-fined a seminorm on the
homology
groupsH*(Q, R)
that has theproperty
of
decreasing
underholomorphic
maps. Thus aholomorphic mapping f: QI -+ Q2
is restrictedby
thenorm-decreasing property
of its induced action onhomology f*: H*(Qi , R) -+ H*(Q2’ R).
In this paper we will show that for certain domainsS2,, Q2 ç Cn, f *
is anisometry
of thehomology
groups if and
only
iff
is abiholomorphism. (In
fact we will useonly
thetop-dimensional homology
groupH2n-I.)
In the case whereQI, Q2 c Care annuli,
this result was establishedby
Schiffer[22]
and was extended to thecase of d-to-1
mappings by
Huber[12].
We will consider domains S2 of the
following special
form:(*) Do
andDi
arestrictly pseudoconvex
with smoothboundary,
,Do
isconnected and
holomorphically
convex inDI.
(If
Q is multicircular and0 rtQ,
then Q isactually
atopological annulus.)
The norm of the
homology
class r ==[3Do] == [8Di]
is defined aswhere the
family
consists of v E02(Q),
0 C v 1 which areplurisub-
harmonic and
satisfy (ddev)-
=dd’VA...Addlv
= 0. This is ahigher-dimen- (*) Department
of Mathematics, PrincetonUniversity.
Pervenuto alla Redazione il 7
Aprile
1978.25 - Ann. Scuola Norm. Sup. Pisa Cl. Sci.
sional
analogue
of harmonic measure, and it may be shown that this supremum is achievedby
the solution u of(1.1)
if u EC2(Q).
We will referto
N{T}
as the normNfs2}
of Q.THEOREM 1. Let
f : Qi - [J2 be a holomorphic mapping,
withQ,
andQ2
as
above, and
letQ1, Q2
be Reinhardt(i.e. multicircular)
domains.If N{QI}
===
N{,Q,}
and themapping f*: H2n-I([JI, R) - H2n-l(il2, .R)
is not zero, thenf
is a
biholomorphism.
This theorem is
proved by showing
that the solution of(1.1)
is theunique
function of Y which attains the supremum inNJ-VI.
Thistechnique
was used for Riemann surfaces
by
Landau and Osserman[17].
In fact theproof (see
Theorem2.1) yields
THEOREM 1’..Let
ill,
,02 be simply
connected domainsof
theform (*),
and assume that the solutions ul and U2
of (1-l-)
onill
andQ2
areof
classC4(Dj)
andsatisfy (1.4). If N{Q1}
==N{Q2}’
andf : 0D, -->- Q2
is a holomor-phic mapping
withf*
=1=0,
thenf
is abiholomorphism.
The restriction to the class of Reinhardt domains in Theorem 1 arises because it is not known whether the solution of
(1.1)
is smooth and satis- fies(1.4)
on moregeneral
domains. Anotherapproach
to thestudy
of holo-morphic mappings
via a related Dirichletproblem
has been describedby
Kerzman
[16].
If u satisfies
(dd°u)n-1
=A0, (ddcu)n ==
0 on a domain D cCn,
there is anassociated foliation Y=
:F(u)
on D : each leaf M of Y is a Riemannsurface, and UIM
is harmonic on M. The foliation Y is animportant part
of theproof
of Theorem 2.1 and seems to be the main feature whichdistinguishes
the cases n == 1 and n>2. In Section
4,
several remarks are made about F.They
center around the observation that if the normal bundle X of Y isgiven
the fiber metricddcu,
then the Ricci curvature of this metric measuresthe
antiholomorphic
twist of Y. The reason forstudying Y
in more detailis Theorem
4.6,
whichyields
THEOREM
1".
Theorem l’ remains validif
thehypothesis (1.4)
isreplaced by
theassumption that Uj
is realanalytic
onS2j, j
=1,
2.In the
beginning
of Section4,
it is shown that there is atopological
obstruction which
prevents
the solution of(1.1)
fromsatisfying (1.4)
ifDo
has more than one
component.
Some information is also obtainedconcerning
the real
Monge-Ampere equation det (a2UIaX,aXj) -
0.In order to discuss self maps of domains Q C
Cn,
one may use a continuous(generalized)
solution of(1.1 ),
which is known to exist. Thus it ispossible
to show that certain bounded domains Q C Cn are
holomorphically rigid >>
in the sense of H. Cartan
[5].
For this purpose one may define several semi-norms
Ñ
onH2n-l(il, R)
which are similar to that ofChern,
Levine andNirenberg.
Let us suppose that the boundedcomponents
ofCn"""Q
consistof
Ki
U ... u.KJ
U E where theKi
and E are closed andpairwise disjoint.
THEOREM 2. Let Q be a bounded domain in
Cn,
and assume that2Z
is notidentically
zero onH2n-I(Q, R)
but that2Z
isidentically
zero onThe
following
areequivalent for
everyholomorphic mapping f:
S2 Q:(i) f
is anautomorphism (ii) f* is injective
(iii) f * is
anisometry.
This theorem
applies,
forinstance,
to the case wheren>2
and at least oneof
Kj
hasnonempty
interior(Corollary 3.2).
Section 3 containsexamples
where various
norms 9
are zero(or nonzero)
andexamples
ofsingularities
which are removable
(or not)
forplurisubharmonic
functions.Rigidity
theorems for
plane
domains have beenproved by
Huber[13]
and Landauand Osserman
[17];
these results are moregeneral
than Theorem 2 in thecase n = 1. The reader should also compare these results with related results of Eisenman
[8,
p.72].
A different measure on
homology classes,
which we discussonly briefly,
may be defined in terms of the
Caratheodory
metric.If y
is a k-dimensionalhomology
classon Q,
thenCfy}
is the infimum of the k-dimensional Hausdorffmeasure
(with respect
to theCaratheodory distance)
taken over all chainsrepresenting
y. Let Bn be the unit ball inCn,
and letKi, K2
becompact
subsets that are convex in the
Caratheodory
metric of Bn.THEOREM 3. Let
/: BnBK, -> BnBK2 be holomorphic,
and assume thatC{aK,l
=O{oK2}. If f*
=F0,
thenf
is anautomorphism of
Bn.Examples
aregiven
to show thatN{yl
andC{y}
are notfunctionally
related.
1. - The
Cauchy problem
for thecomplex Monge-Ampère equation.
We use the notation
de = iCa - a)
so that dde, =2iôä
and(dd,,)n
=== dde /B ... /B dde .
Let us summarize some known results(see [4]
fordetails).
The
operator (ddc)n
has a continuous extension to the space ofcontinuous,
plurisubharmonic functions,
with(ddw)n being
defined as a measure on Q.If we consider the class of functions
!F’ =
fv
EC(D),
0 v1, v plurisubharmonic
and(ddev)n
=0}
then we may define a seminorm
Ny using (**)
with Freplaced by
thclarger
class f" and theintegration being
taken withrespect
to a smoothcurrent
representing
y. In connection withthis,
one is led to consider the extremal function u = sup v, where the supremum is taken over the func- tionsv IL
which areplurisubharmonic
onQi
andsatisfy
v 0 onS20: (This
function has been studied
by
Siciak[23]
andZaharjuta [26]
in other con-texts.)
The function u thus obtained isLipschitz
continuous and is ageneralized
solution of the Dirichletproblem
The
following
estimate holds:where the
integral
isinterpreted
in ageneralized
sense. Theproblem (1.1)
has been solved
explicitly
in severalexamples
and the solution isregular
and satisfies
(ddcu)n-1 0
0 in each case(but cf. §
4 on thispoint).
If U EC2(s2),
it follows that
equality
holds in(1.2)
andIf u E
C2(Q)
satisfiesthere is further structure associated with u. The
(n - .1,
n -I)-form (dd,lu)n-1
may beintegrated by
the Frobenius theorem toyield
a foliation:F =
Y(u)
of S2by complex
manifolds of dimension one(Riemann surfaces).
This foliation has the
property
thatUIL
is harmonic on L for each leaf L of Y(see [2]
fordetails).
We note that the solution u of(1.1),
if it issmooth,
always
satisfies(1.4)
in aneighborhood
of aS2 since it is constant on each(strictly pseudoconvex) boundary component.
Let
8 = {z c- C-: r(z) = 0}, dr =A 0 on 8,
r EC2(C-)
be a realhyper-
surface. We will say that S is non-characteristic for a solution u of
(1.4)
ifThis is
equivalent
to the condition that each leaf L c- Y intersects trans-versally.
This leads touniqueness
in theCauchy problem.
PROPOSITION 1.1..Let us suppose that u, v are C3 and
satisf y (1.4)
in aneighborhood of
S.Suppose
thatu(z)
=v(z)
anddu(z)
=dv(z) for
z ES,
andlet 8 be non-characteristic
for
u at zo E S.I f
u, vsatisfy (1.4)
in aneighborhood of
zo , u = v in aneighborhood of
zo.PROOF. We will show that there is an open set -W
containing
zo such thatthe foliations
:F(u)
andY(v)
concide on W in thefollowing
sense: if z EyYand
L,
Z’ are the leavescontaining z,
then the connectedcomponents
ofL r) -W and Z’ r1 W
containing z
are the same.By
the non-characteristiccondition,
the leaves are transverseto S,
and it suffices to show this for z c- S r)-w.Thus we suppose that z E S
r)-W,
and that.L,
L’ are theintegral
curvesof
(ddeu)n-l (respectively (ddv)n-1)
which passthrough
z. Since u - v van-ishes to second order
on S,
it follows that all secondpartial
derivatives of(u - v) except (u - v)rr
vanish on S. From the non-characteristic condition and from(ddeu)n
=0,
we may solve for Urr in terms of all the other se-cond
partial
derivatives at z. Thus it follows from(1.4)
that(U - v)rr
= 0on -Wr) S.
Finally,
if 3;’r) 8 and 5,-’r) S denote the foliations of 8 obtainedby intersecting
the leaves of T and :F’ withS,
then we observe that these foliations have normal bundles(dd,,u)n-’Adr
and{ddw) nw /B dr respectively.
We have seen that for
z c- S (-)TV,
the second derivatives of u and v at z areequal,
and thus the foliations n Sand :F’ n S have the sametangent
spaces.
By
theuniqueness
theorem forordinary
differentialequations,
we see that Y r) S r) W = 5,"’ n S n -W. It follows that Y and Y’ must agree in a
neighborhood
of zo, since z E L n L’implies
that L n .L’ containsa curve in
S;
and L n L’ can contain a curveonly
if L = L’.COROLLARY 1.2..Let the
function r defining S
bestrictly plurisubharmonic,
and set
If
zo E S == aSZ and there is aneighborhood
Wcontaining
zo such thatu, v E
C3(S2) satisfy (1.4)
on W n,S2
andu(z)
=v(z), du(z)
=dv(z) for
z E Wn
S,
then there is a smallerneighborhood
W’containing
zo such thatu = v on W’ r1 Q.
PROOF. Since S is
strongly pseudoconvex
at zo, we may make achange
of coordinates such that Zo =
0,
X isgiven
near Zoby
a convex functionRe Zl =
gg(Im
Zl, z2, 7 ...,zn) > 0,
andq > b
> 0 on the setWe claim that for z c D such that
Re Zl ð
and(1m zl) 2 + )znJ2
8,u(z)
=v(z).
To seethis,
let L be the leaf of:F(u) containing
z. Since usatisfies
(1.4) on D,
it follows that L may be extended toQ
with a con-tinuous
tangent plane. By
the maximumprinciple,
.L must intersect 8 ina
point’ = (C,,
...,in)
withRe ’1
6 and(Im ’1)2 + "212 +
...+ )Sn )2
8.Since S is
strongly pseudoconvex,
L can betangent
to Sonly
at an iso-lated subset of L n S.
Thus, moving
to anearby point i’ G
L r1 S if neces-sary, we find a
point
where is non-characteristic for u.By Proposition 1.1,
it follows that u = v on L.
COROLLARY 1.3
Suppose S21, Q2
are domainsof
theform ( *),
and supposeD.,
,S22
have the sacme inner or outerboundary. If S211 5 -Q2, if
the solutionUl
of (1.1) is C3(Dj) for j = 1, 2,
andi f deiiAd°uiA(dd°ui)"-1 # 0,
thenN{S2,}
>N{D2}.
PROOF.
By
the normdecreasing property
ofholomorphic mapping,
itfollows that
N{[Jl}>N{Q2}.
To show that thisinequality
isstrict,
we ob-serve
(cf. equation (3.14)
of[4])
where
F= {r = 0}, dr 0 0 on F,
the commonboundary
ofQl
andS2,.
Since
Qi § Q2
it follows thatOUl(z)/or> OU2(z)/or
for z E T. If the normsare
equal,
then it follows that8uif8r
=au2/ar
on F.By Proposition
1.1 itfollows that u, = U2, which is
impossible
sinceQl =1= il2 and uj
satisfies(1.1).
We remark that this will be a
special
case of Theorem 2.1.Uniqueness
in theCauchy problem
also holds for solutions ofwith
f
>0,
and d V is the volume form on Cn.(In
ourapplications
to holo-morphic mappings, however,
we willonly
be concerned with the casef
=0. )
PROPOSITION 1.4. Let u, u’ E C°° be
plurisubharmonic
acndsatisfy (1.6) for
somef
>0. If u(z)
=u’(z), du(z)
=du’(z) for
z ES,
then u = u’ in aneighborhood of
S.PROOF. Since u, u’
satisfy (1.6),
then w = u - u’ satisfiesdd"wA[(ddeit)n-1 + (dd,,u) ,-2 Addeul +
...+ (ddcu’)n-1]
= 0 .Let us write this as
Since
(ddeu)n> 0,
it follows that OJ is astrictly positive form,
and so L isa
strongly elliptic operator.
It is known(see Nirenberg [20])
thatunique-
ness in the
Cauchy problem
holds for second orderstrongly elliptic operators
with 000
coefficients,
and so we conclude that w = 0 in aneighborhood
of S.PROPOSITION 1.5. Let the
function
rdefining
S be realanalytic,
let Qo , Q1, be realanalytic
and letf
beanalytic
in aneighborhood of
S.If
on
S,
then there exists a realanalytic function u
in aneighborhood of
S such thatfor
z E S and(dd°u)n = f
in aneighborhood of
S.00
PROOF. If we write the solution u
= ’I (piri
as a formal power series;=0
with cpj
analytic
onS,
then the condition(1.7)
allows us to solve for ggj in terms of CPo, ..., ggj-, in theequation
The
proof
that the formal power series converges is aspecial
case of theCauchy-Kovalevsky
theorem.From
this,
one may obtainspecial
exhaustion functions forpseudo-
convex domains with real
analytic boundary.
COROLLARY 1.6. Let Q be a
bounded, strongly pseudoconvex
domacin withreal
analytic boundary
in Cn. Then there exists af unction
O EC°°(SZ)
suchthat Q =
{e 01, de =F
0 onôQ,
and(ddee)n
= 0 in aneighborhood of
aS2.PROOF.
By Proposition 1.5,
there is aplurisubharmonic
realanalytic
function n defined in a
neighborhood
of 8Q such that(ddcu)n
= 0 andaular = 1,
u = 0 on 8Q. For 8 > 0small,
we letX(t)
be a convex func-tion that is 0 for t - 8 and such that
X’(t)
= 1 for t > -8/2,
and thuse
= X(u) - x(o )
is the desired function.2. - A
uniqtleness
theorem and some corollaries.Here we show that the
plurisubharmonic
measure(i.e.,
solution of(1.1))
is the
unique
function thatgives equality
in(**).
THEOREM 2.1. Let Q c Cn be a domain
o f
thef orm (*),
and suppose that the solution uof (1.1)
is smoothof
class04(Q)
nC3(Q)
andsatisfies (1.4).
Letv E
C4( Q)
n03(Q
uaDO)
be acnotherplurisubharmonic function
with 0 v1, (ddcv)n
= 0 and(ddev)n-1 =A
0off o f
a properanalytic subvariety of
Q.If
F =
[ôDl]
andthen u = v.
Let us note some corollaries.
COROLLARY 2.2. Let
Ql, Q2
be annuli(satisfying (*)),
and assume thatthe harmonic measure u,
of S2 j
is inC4 ( SZ j )
andsatisfies (1.4). I f f : Qi -> Q2
is a
holomorphic
map withN {f*Fl}
=’N{r2},
thenf
is a proper, unrami-f ied covering of Q2 by Q,. Further, f
has some smoothness at theboundary : if
U2C2k(fl2),
thenf
C-Ck-1, -
it
U2 C-C2k(SG2),
thenf
ECk-1’1 (SGx).
PROOF. We
apply
Theorem 2.1 with Q =S2,, n
= ul, and v =/*U2,
and we conclude that U.1 =
u2( f ).
Thusf
is proper. To see thatf
is un-ramified,
we use theargument
ofKerzman, Kohn,
andNirenberg [16]:
exp
(ul)
= exp(u2(f))
is astrictly plurisubharmonic function,
and if wecompute
thecomplex
hessianusing
the chainrule,
weobtain If’
I =F 0.Taking
further derivatives with the chain rule andusing
another trick of[16],
we obtain theboundary regularity
off.
Let us note that iff
is firstknown to be smooth at
8Qi,
then Fornaess[10]
shows thatf
is unramified.REMARK. If
SZl and 92,
have C-boundaries,
then Naruki[19]
showsthat
f
is smooth of order m -4, provided
thatf
is04(Ql).
A
large portion
of theproof
of Theorem 2.1 isspent proving
Lemma 2.6.Without Lemma
2.6,
it is stillpossible
toconclude,
inCorollary 2.2,
thatU,u,(f),
and thusf
is proper.Theorem 1 is a consequence of the
following corollary,
since for a Reinhardt domainsatisfying (*)
the solution of(1.1)
is as smooth asaD, U 8Di .
COROLLARY 2.3. Let
S2,, Sd2 satisfy (*)
withn>2,
and let the solution ujof (1.1) satisfy (1.4)
and Uj E04(Q,), j == 1,
2. LetN{Ql}
=mN{Q2}
with man
integer. If f : S2,, --> SZ2 is a hoZomorphic mapping,
then thedegree of f
(i.e. f* -P,
=(deg f ) .r2) is
aninteger 0 deg f m. If S2, is simply
connectedand if deg f
= m, then m = 1 andf
is abiholomorphism.
Ingeneral, if deg f
= m =1,
thenf
is abiholomorphism.
PROOF. The
degree
off
is anon-negative integer
sincef
is aholomorphic mapping
andn>2.
Since the normdecreases, deg f c m.
Ifdeg f
= m,then
by Corollary 2.2, f
is acovering
which must be abiholomorphism
since.82
is
simply
connected. Thus m = 1.We
begin
theproof
of Theorem 2.1 with a sequence of lemmas. Ifit will
ultimately
be shown thatQ+
= Q- = ø.LEMMA 2.4. Let M be a
leaf of :F(u),
theu-foliation.
Then M reachesboth the inner and outer boundaries
of Q,
i.e.M noD, =F
0f or j
=1,
0.PROOF. M must reach the outer
boundary
sinceD1
ispseudoconvex
(see [2]).
For the innerboundary,
let c = inf{u(z): z
EM}
= minlu(z):
z c- 9}.
Ifc > 0,
letze 9
be apoint
such thatu(z’)
= c. Let M’ bethe
Y(u)
leafthrough
z’. NowM’c 9,
and soby
the maximumprinciple
u = c on
M’,
since u is harmonic on M. This is a contradictionsince
M’reaches the outer
boundary,
, and u comesarbitrarily
close to 1 on M’.LEMMA 2.5.
I f
Q- =0,
then u = v.PROOF. If u>v, then v = 0 on
8Do,
and soaular>avlar>O
there.However
where r is any smooth
defining
function forDo.
It follows that u - v === 0 =
d(u - v)
onaDo,
and so u = v in aneighborhood
ofaDo by Propo-
sition 1.1. Since the two foliations
:F(1¿)
andY(v)
must agree nearaDo,
it follows
by
Lemma 2.4 that u = v on Q.LEMMA
2.6. If
SZ+ =0y
then u = v.PROOF. If u c v, then v E
C(D)
and v =1 on8Di:
-. Let us =u/(,-,)
forê > 0
small,
and setWe will show that
holds. We recall that 8Q =
aDl - aDo
and thatdcUA (ddeu)n-1
isstrictly positive everywhere
onaDo . By (2.1)
it follows that v = 0 on8Do.
Thesolution of
(1.1 )
isunique (see [4]),
so u = v on S2.Let us first establish an
inequality
for
i >
0. This is obtainedby repeated integration by parts:
The
inequality
arose because vl onFe,
0 c v onaDo,
anddcu,A(ddev)’A A(ddcu,)n-i-i
is anon-negative
form onFe
and8Dn .
Since u solves
(1.1 ),
we obtainBy repeated application
of(2.3)
to(2.4)
we obtainThus,
in order to prove(2.2)
it remainsonly
to show that the limit of theright hand
term is0
as 6 - 0.To prove that
we
proceed by
induction on i. The case i = 0 is trivial. First we note thatThus it suffices to show that
For
this,
we note thatand thus
Assuming, by induction,
that(2.5)
holds fori - J ,
we takelim
of bothsides and
get
-
By
monotone convergence, weget
which
implies (2.5), completing
theproof.
Next we discuss the set
LEMMA 2.7.
On S,
PROOF. Let
z, c- 8
be apoint
where theexpression
in(2.6)
isstrictly positive.
We set us =(u - E)/(1- 2e)
andAn
integration by parts
and(2.1) gives
For 2 > E > 0,
, Ye{z E Q: uE(z)
=v(z)}
is acompact
subset of S2. If wesmooth u.., and v with a
non-negative smoothing kernel xa , then
the smoothedfunction 4 and va
define acompact
sety& . By
Sard’stheorem, ys
is smoothfor almost all s. Thus we may
replace
Tby
the smoothcycle yf . By
as-sumption, d(u - v)(zo)
=A0,
so that{u
=v}
is a smooth surface in aneigh-
borhood U
containing
zo .Furthermore,
there arepoints z,,’ c yfl with z,,’
->+ zo .Finally,
since u and v areplurisubharmonic, dc(ufl - vf) A0fl
is anonnegative
form on
yE ,
andThis is a contradiction since the left hand side of
(2.7) approaches
0 as8
--> 0,
and so(2.6)
holds at zo.LEMMA 2.8. Let M be a
leaf of T(u). I f X 0 Q+ 0 0,
then M cQ+.
PROOF OF THEOREM 2.1. This lemma will
give
aproof
of thetheorem,
for
by
Lemma2.4,
M must reach somepoint z_ E aDo.
Thus there is aneighborhood
Uof zo
with U naDo C 8
r1D+
and U n Q c D+. Since n > vi it follows thatd(v - u) = adr
onU r) aD,,.
Sincedr /B der /B (dd°u) "-1
> 0on
aDo,
it follows from Lemma 2.7 thatd(u - v) = 0
on U r’1aDo. Repeat- ing
now theargument
of Lemma2.5,
we conclude that u = v onM,
which is a
contradiction, proving
the Theorem.PROOF oF LEMMA 2.8. We will suppose that S2- n
X =A 0
in order to derive a contradiction.By moving
Mslightly
if necessary, we may assume that(ddcV)n-1
vanishesonly
at an isolated set ofpoints
of M.(Recall
that(ddcv),-’
= 0 is contained in avariety.)
Thus we may consider apoint zo c- N r) S r) D+ r) S2
such that(ddev(zo))n-l
=F 0. There are two casesto handle :
(a) d(u - v)
=A 0 atpoints
of 8arbitrarily
near zo ;(b) d(u - v)
= 0 in aneighborhood
of zo in S.For case
(a),
we considerzj c- S
close to zo such thatd(u - v)(zj)
=1=0,
i.e. S is smooth at z,. LetM(z)
be the leaf off(n) containing
z. Thecondition
(2.6)
says that thetangent
space ofM(z)
lies inside thetangent
space of S. Since this holds for all z E S
sufficiently
near Zj thatd( u - v)
#0,
and since the
foliation Y(,u)
was obtainedby integrating
the(2n - 2)
form(ddeu)n-I,
it follows that in aneighborhood Uj
of z;,M(z) (’) U; c S.
Fur-thermore, v
== u is harmonic on.M(z)
r1Uj,
and it follows thatM(z)
nUj
is also a leaf of
:F(v)
since(ddw)n-1 >
0. ThusM(zj)
is a leaf for bothY(’U)
and
Y(v)
and u = v onM(z,).
It follows that u = v onM(zo),
which meansthat
M(zo)
cD+,
a contradiction for case(a).
In case
(b),
we want to show thatSi’(u)
and:F(v)
have the sametangent
spaec at zo, i.e.
ddcu(zo)
andddwv(zo)
have the same kernel. Fora E 8,
welet Tan
(8, a)
denote thetangent
cone of S at a, i.e. the cone in R2n gener- atedby
the limits of secants(zj - a)/Izj - a] I
withzi c- S, (see
Federer[9],
p.
233.)
Let thetangent
spaceTaS
be the real linear span of Tan(S, a) -
We claim that on a dense set of
points a
ElJ+ n {j-, d’MR T,, 8 2n -
2for z E S in some
neighborhood
of apoint
zo E S. In this once may show(see
Federer[9],
Lemma3.3.5)
that S is acountably
rectifiable(2n - 2)-
dimensional set. This cannot
happen
in aneighborhood
oftJ+
nQ-
sincea
(2n - 2)-dimensional
set cannot disconnect Q.It suffices to show that ker
ddeu(z)
= kerddev(z)
for apoint z
E 8 ar-bitrarily
close to zo, so we may assume that dimTzo S > 2n - 1.
IfdimR Tzo S
=2n,
thendd°u(zo)
=dd°v(zo),
so we assume thatT, 8
hasdimension 2n - 1. Choose coordinates
Z j == x j + iy"
,1 c j c n,
such thatthe set
{ô/ÔXj, ô/ôYj, l,jn-l, alax,,,}
spansTzo S.
Since u- v === d(u - v)
= 0on S,
it follows that all second derivatives of u and v areequal
at zoexcept, possibly,
the02/,ðy;
derivative. If det(uii)li,in-l =F 0,
then we may solve for
02U/oy;
=a2Vlay2
in terms of the other secondpartial
derivatives in the
equation
det(uii)
= det(vij)
= 0. If det(uÜ)li,in-l = 0,
then det
(vïj)li,in-l = 0,
and both:F(u)
andY(v)
areorthogonal
todznAd£n
at zo . We may nowproceed by
induction on the spacespanned
by {a/ox" O/OYj, 1 ,j ,n - I}
to see that ddeu and ddcv have the samekernel at zo .
Now we observe that if M were a leaf of the
:F(v) foliation,
there wouldbe
nothing
to prove, sinceby uniqueness
in theCauchy problem u
= von M. The foliation
Y(v)
is of class C2and, by
theargument above,
istangent
to M at allpoints
of{j+
r15-
n M near zo . There are functions . ,(p2n-2 E C2
such that the leaves of:F(v)
aregiven
near zo in the form{z: 991(Z)
= Cl,..., f{J2n-2(Z)
=C2n-2}.
It follows thatd( f{Jj 1M)
- 0 on anypoint
of M(1 Q+
n9-. By
A. P. Morse’stheorem,
the ggj are constant on the connectedcomponents
of Mn Q+ (1lJ-.
Since one of thesecomponents
must have an accumulation
point SO
eM,
it follows that the leafM’(Co)
of
:F(v)
must coincide with M. In otherwords,
M is a leaf for both:F(u)
and
Y(v), completing
theproof.
3. - Self maps of bounded domains.
If
H2n-l(Q, R)
has more than onegenerator,
then the results of Section 2 cannot beapplied directly (see
Section4).
Much can besaid, however,
ifthe domain S2 is
being mapped
into itself. Theorem 2 will be shown to follow from a theorem of H. Cartan and the fact that the norm N is de- fined in the form(**).
We will then discuss some similar norms obtainedby changing
thefarnily Y
and themapping
theoremsthey provide.
A
compact
subset E c Cn will be said to benegligible for N (or N)
if thereis a
neighborhood
w of E such that thenorm N (or N)
isidentically
zero onH2,,,-l(ojBE2 R).
Let us assume thatf2
is a bounded domain in Cn withH2n-l(tJ, Z)
=0,
and thatK, E
aredisjoint compact
subsets ofQ.
We will assume that E isnegligible
and that K =Ki
U ... Ugl
hasfinitely
many connected
components. By
Alexanderduality,
and without loss of
generality,
, we assume thatlit(8£5, £5uK;)
>0,
forotherwise we
replace
Eby E u Ki.
Since
H2n-l(tJ, Z)
=0,
theMayor-Vietoris
sequencegives
where Q =
fiu(K
UE).
One way ofviewing
this direct sum is that if F EH,.-,(DBE),
then it may berepresented by
acycle supported
in asmall
neighborhood
of .E which isdisjoint
from K. Thus we may considerFE H2n-l(Q).
·By
the class of e.g., 8K inH2n-l(Q),
we mean the class of asmooth
compact hypersurface
inQ, bounding
asufficiently small, compact region
inf2.
Now we claim that the closure of 0 in the
seminorm N
may benaturally
identified with
H,,,-,(DBE).
It iseasily
seen that ifFl
EH2n-l([J)
andh2
EH2--l(f2BE)
, thenWe will write the induced
(finite dimensional)
normed space asTheorem 2 is a consequence of the
following
THEOREM 3.1. Let Q =
DB(K
uE)
wheref2
is a bounded domain in C’n withH,,,-,(D, Z)
=0,
and letK,
E bedisjoint compact
subsetsof D.
Weassume that E is
negligible
and that 0 C dim17
00.If
Q ->. Q is a holo-morphic mapping
then ‘thefollowing
areequivalent : (i) f
is anautomorphism of S2;
(ii) f*
is anisomorphism of H2n-l(Q, R) ; (iii) f * : n
-->-17
isnonsingular ;
(iv) if
asubsequence of
the iteratesof f, {Iil,
convergesuniformly
oncompact
subsets to a map F: Q -->12
then F is anautomorphism.
(v) f* : H -¿. n
is anisometry.
PROOF. The
implication (i)
=>(ii)
is obvious.(ii)
=>(iii). By
thenorm-decreasing property
off*,
it follows thatIt follows that
f * : H -->. 17. Since H
is finitedimensional,
it is sufficient to show thatf *
is onto. If[-Pl e 17,
letFEH2n-l(Q,R)
be arepresentative.
If .1"E
H2n-l(Q, R)
is anypreimage
underf * ,
then1*[-Pl]
=[.P],
and thusf *
is
nonsingular
onJ7.
(iii)
=>(iv).
Let{/I)
be the sequence of iterates off
and let F : Q -15
be a
mapping
to which asubsequence
of theconverge uniformly
on com-pact
subsets of Q.By
a theorem of H. Cartan[5], (or
see[18])
I’ is eitheran
automorphism
or the Jacobian determinant of I’ vanishesidentically.
In the latter case, we consider
[F] c- J7
and follow itsimage
underf * .
LetFj
be thehomology
class ofaKj
for1jl.
Thus there areintegers
Cii such thatWe may assume that
c.,j >I
forinfinitely many j
and thatR{aK,l
> 0.Thus there exists a current
Tl representing a.g1 compactly supported
in Qand a
function u,
EP(DBK.,)
nC(DBK,,)
such that(ddeu,)n
= 0 onQ"’X1
and
TldcullB(ddcul)n-l
= 6 > 0.Thus
integration by parts yields
a bound forinfinitely many j :
On the other
hand,
if T is a currentrepresenting t,
thenF*
T = 0 sincethe Jacobian determinant of F is zero and the dimension of T is
(2n - 1).
By
uniform convergence,and so
which is a contradiction. Now
(iv)
=>(i), (i)
=>(v),
and(v)
=>(iii)
areobvious,
, and thiscompletes
theproof.
We will consider the class of functions
for j
= 0 or 2:26 - An.n. Scuola Norm. Sup. Pisa Cl. Sci.
By Hartogs’ Theorem,
aholomorphic mapping
F:S2, ->,Q,
extends to.F’: Gi
-->Q2.
Thus thefamily :Fj (S22)
ismapped
into3;-,(,Ql) by
F*. It fol- lows that thenorm Ni
definedby (**) with :Fj replacing :F
decreases underholomorphic
maps.A
compact
subset E cf2
without interior iseasily
seen to benegligible
for the seminorm
N2.
Theorem 3.1with N replaced by N2 yields
COROLLARY 3.2. Let Q =
f2B,BK Cc C-, n ->- 2,
begiven
whereH2n-l(Q, Z)
= 0and int ..K is
nonempty
and hasfinitely
many connectedcomponents.
The conclusions(i), ..., (v) of
Theorem 3.2 areequivalent if 17
isreplaced by H2 (corresponding
toN2).
Inparticular (i)
=>(ii).
Let us recall that a set E c Cn is
Cn-polar
if for each z E E there is aneighborhood
U of z and a function vplurisubharmonic
on U such that U r1 E cIv
= -oo}.
Josefson[15]
has shown that if E ispolar
thereis a function v
plurisubharmonic
on Cn with .E‘ cIv
= -00}.
If K is a
compact
subset of Q cCn,
we defineIt is well known that the upper
regularization
is
plurisubharmonic.
Afunction V
on D is an upper barrier if it has theproperty
that if B c Q is a ball and u EP(S?), u V
onaB, then u ip
on B.In the
terminology
of Hunt andMurray [14]
an upper barrier is(n - 1 )- plurisuperharmonic.
If E and S2 haveregular boundaries,
then the solution of the Dirichletproblem
for theLaplacian
is an upper barrier. Atechnique
of Walsh
[25] yields
thefollowing
result.PROPOSITION 3.3. Let Q Cc Cn be a
pseudoconvex
openset,
and let there exist afunction p
EP(S2),
p0,
suchthatc!lIJbp(,)
c-,of2 = 0.If
there is an upperbarrier V
onS2BE
suchthat li m 1jJ(’)
= 0a"d,19lpY1> - 1,
thenh(E, Q)
is
continuous,
andh(E, Q)
is 0 onE,
1 on aD.PROPOSITION 3.4. Let Q c C" be
pseudoconvex,
and let E c S2 be acompact polar
set.I f
t is thehomology
classof
aD inSZBE,
thenÑ{r, QUE) =
N,,{-P, QUE)
= 0.PROOF. Since .Q is
pseudoconvex,
it has aC2, strictly plurisubharmonic
exhaustion
p(z).
We may assume that E cfp 0}y
and we mayreplace 12
by Q
={p 0}. Let w c- P(Q), w 0,
be such that E c{W
= -co}.
For k >
0,
we seta)(k) {z
c-,Q:w(z)
-kl.
Since E iscompact
and0,)(k)
is open, there is asmoothly
bounded open setUk
E cUk
cw(k).
By Prop. 3.3, hk
=h( Uk, Q)
is continuous. We defineBy Prop.
3.1 of[4],
where T is any
compactly supported
smooth currentrepresenting
t. Sincew/k h, -
1 0 it follows thatthe hk
convergeuniformly
to 1 on the sup-port
of T. Thus 0= lim R(I,
k-->Q(k)) >Ñ(r, Q/E) > No(1-’, S2BE).
COROLLARY 3.5. Let E be a
compact polar
set inQ, a pseudoconvex
subsetof
C-.If u
EC(f2)
nP(Q)
and(ddeu)n
= 0 onQ/E,
then(ddcu)n
= 0 onf2.
PROOF. Let T be a smooth current
representing
84iisupported
awayfrom E,
and let S be a current such that M = T. It follows thatCOROLLARY 3.6. Let E be a
compact polar
subsetof
apseudoconvex
domainQ,
then E is
negligible for No.
PROOF. Since
H2n-l(Q, R)
=0, H2n-l(Q,BE, R)
isgenerated by
linearcombinations of classes of the form
[aK].
But if v EYo(QUE),
thenby Corollary
3.4(ddlv),,
= 0 onD.
ThusPROPOSITION 3.7. Let E be a
compact
subsetof Cn,
and let1p>
0 be a continuous upper barrierdefined
on aneighborhood coBE
suchthat lim
C-Z1p(’)
= 0for
z E E. Thenfor
any bounded open set Qcontaining
E.PROOF. It suffices to take Q to be a
large
ballcontaining E
and to showthat