• Aucun résultat trouvé

<span class="mathjax-formula">$q$</span>-pseudoconvex and <span class="mathjax-formula">$q$</span>-complete domains

N/A
N/A
Protected

Academic year: 2022

Partager "<span class="mathjax-formula">$q$</span>-pseudoconvex and <span class="mathjax-formula">$q$</span>-complete domains"

Copied!
8
0
0

Texte intégral

(1)

C OMPOSITIO M ATHEMATICA

G IUSEPPE V IGNA S URIA

q-pseudoconvex and q-complete domains

Compositio Mathematica, tome 53, n

o

1 (1984), p. 105-111

<http://www.numdam.org/item?id=CM_1984__53_1_105_0>

© Foundation Compositio Mathematica, 1984, tous droits réservés.

L’accès aux archives de la revue « Compositio Mathematica » (http:

//http://www.compositio.nl/) implique l’accord avec les conditions gé- nérales d’utilisation (http://www.numdam.org/conditions). Toute utilisa- tion commerciale ou impression systématique est constitutive d’une in- fraction pénale. Toute copie ou impression de ce fichier doit conte- nir la présente mention de copyright.

Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques

http://www.numdam.org/

(2)

105

q-PSEUDOCONVEX

and

q-COMPLETE

DOMAINS

Giuseppe Vigna

Suria

© 1984 Martinus Nijhoff Publishers, Dordrecht. Printed in The Netherlands.

Introduction

The Levi

problem

was

originally posed

in the

following

terms: if D is a

domain in C " with

e2 boundary

which is

pseudoconvex

is D a domain of

holomorphy?

It was then realised that the

hypothesis

on the

boundary

can be

removed if

pseudoconvexity

is

replaced by completeness,

which is a

concept that makes sense in any

analytic manifold,

and the final solution of the Levi

problem

due to Grauert says that a

complete analytic

manifold is

necessarily

Stein

[3].

The

original spirit

of the

problem

has not been

betrayed:

domains

with

C2 boundary

in C" are

pseudoconvex

if and

only

if

they

are

complete ([4]

p.

50).

The same is not true any more if Cn is

replaced by

any

analytic

manifold: a well known

example

of Grauert

provides

a subset with

C2 boundary

of a

complex

torus which is

pseudoconvex

but all

holomorphic

functions thereon are constant.

In this paper we prove that a

q-pseudoconvex

open subset of a Stein manifold is

necessarily q-complete (the

converse is also true, see

[2]).

This

seems to be one of those facts that every

complex analyst believes, perhaps

for

psycological

reasons, but no

precise

reference

is,

to my

knowledge,

available and all mathematicians whom 1 have asked so far don’t seem to know how a

precise proof

should go; the modest aim of this paper is to fill this gap and

provide

a definite reference.

Most of the ideas in the

proof

are due to Mike Eastwood to whom 1

am, once more,

deeply grateful.

We

briefly

recall the basic definitions:

DEFINITION 1: Let D be an open subset of an

analytic

manifold M of

dimension n ; we say that D has

C2 boundary

if for all x E aD there exists

an open

neighbourhood

U of x and a

C2

function (p:

U ~ R,

called

defining function

of D at x s.t. D ~ U =

(y

E U s.t.

cp(y) 01 -

and

(3)

106

d~(x) ~ 0;

in these conditions we can consider the

complex

Hessian

where zl, z2, ... , zn are local

holomorphic

coordinates at x. The

signature

of this Hermitian matrix does not

depend

on the choice of the local

holomorphic

coordinates but it does

depend

on cp. However the Levi

form

where

TxaD

=

{v

=

03A3m1v1~/~zl ~ Tx M

s. t.

03A3n1vi~~/~zi(x)

=

0}

is the holo-

morphic

tangent space of aD at x, has a

signature

that

depends only

on

D and x.

If

n ( x )

denotes the number of

negative eigenvalues of F(~)(x)

we say that D is

q-pseudoconvex

if

n(x)

q for all x E aD.

DEFINITION 2: A

complex

n-dimensional manifold D is said to be

q-complete

if we can find a

q-plurisubharmonic

exaustion

function

on D i.e.

a

C2

function 03A8 : D ~ R s.t.

(1)

for all c ~ R the set

Bc = {x ~ D

s.t.

03A8(x) c}

is

relatively compact in

D and

(2)

The

complex

Hessian

H(03A8)(x)

has at

least n - q positive eigen-

values for all x in D.

0-pseudoconvex

and

0-complete

domains are

simply

called

pseudocon-

vex and

complete.

THEOREM:

If D is a

domain with

C2 boundary

in a Stein

manifold

M and D

is

q-pseudoconvex

then it is also

q-complete.

PROOF: We shall divide the

proof

into several steps.

Step

1: As there is

always

an

analytic embedding

of M into C

N,

for some

large

N

(see [5]

p.

359)

we can suppose at once that M is an

analytic

submanifold

of CN.

Choose a

holomorphic

tubular

neighbourhood

p : V

~ M and set

D = p-1(D) (cfr. [1] proof

of Lemma

1,

p.

131).

We claim

that,

after

shrinking

if necessary,

(a)

~x ~

ah n V, aD

is

C2

at x,

(b)

If we consider

D

as an open subset

of CN

then

n ( x, ) =

n(p(x), D),

for al x E

~

n V.

Indeed,

since the

problem

is local we can suppose that local coordi- nates z1, z2, ...,zN have been chosen s.t., near x, M =

( z

S.t. zN-n+1 = ZN-n+2 =... = zN

= 0),

Zl’ Z2"" Zn are local coordinates of M at x and

p Z1, z2, ... , ZN ) = (z1,

z2, ... , zn,

0,...,0).

(4)

Let

Û

be a

neighbourhood

of x

in CN

so small that zl, z2,,..., zN are defined in

Û

and that there exists a

C2 defining

function (D : U =

~

M - R for D with

d03A6(x) ~

0 and

U c

V.

By shrinking Û

if necessary we

can also suppose that

~ p-1(U).

Define : ~ R by = 03A6 o p

i.e.

(z1,

z2, ... ,

zN) = 03A6(z1,

z2, ... , 1 z,,,

0, ... , ,0). Then

is a

defining

function for

b

at x.

Moreover

where as usual v =

03A3Ni=1vi~/~zi,

and

This proves the claim.

Step

2:

So,

if we suppose that D is

q-pseudoconvex

we have

that,

Vx OE V ~

aD, ab

is

e2

at x and

n(x, )

q.

Consider the function p :

CN ~ R given by

Where dist denotes the Euclidean distance. Since Vx E=-

aD, aD

is

C2

at x, we can conclude that there exists a

neighbourhood Û’

of aD

in CN

on

which p is

C2 (by

the inverse function

theorem).

By shrinking Û’

if necessary, we can also suppose that

Vy

in

U’

there exists

exactly

one

point c(y) ~ aD n U’

which is the closest

point

to y

under the Euclidean

distance,

that

d03C1(c(y))

~ 0 and that

n(c(y), )

q.

Let (P:

Û’ ~ ~ R

be the function (p =

log

p; we claim that the Hessian

(£cp)(y)

has at most q

positive eigenvalues B;/y.

Indeed suppose that this is

false,

i.e. there exists a

point y

in

U’

n

D

s.t.

(H~)(y)

has

(at least) q + 1 positive eigenvalues;

the

geometric interpretation

is: there are linear coordinates

(t1, t2l 1 N) of CN

s.t. the

Hermitian form

given by

the matrix

(5)

108

is

positive

definite on the linear

subspace V

of

TvCN = CN spanned by

(~/~1, ~/~t2,...,~/~tq+1).

By Taylor’s

theorem we have

where a, = 1 2~~/~ti(y)

and

bjk

=

~2~(y)/~tj~tk

are constants, and

0(|t|2)

has the

property

that

lim t ~00(|t|2)/|t|2

= 0 and so also

In order to

simplify

notation omit the limits of the summands and write

A(t)

= y +

03A3tj~/~tj , B(t)

=

exp(03A3aiti

+

Ebjktjtk)’

Then the above

equality

can be written as

03C1(A(t)) - 03C1(y)(B(t)| =

{exp03A3Cjktjtk

+

0(|t|2)) -1} 03C1(y)|B(t)| = {03A3Cjktjtk

+

0’(|t|2)}03C1(y)|B(t)|,

where the last

equality

is obtained

by expanding

in

Taylor

series the

function exp and

0’(|t|2)

has the same

properties

as

0(|t|2).

Then one has

so we can choose E &#x3E; 0 small

enough

s. t.

~t, |t|

~, one has

(a) A(t) ~ ~ ’

and

(b) p (A (t» - 03C1(y)|B(t) &#x3E; 03C1 (y)/2 · 03A3Cjktjtk.

Set u =

c(y)-y

and define an

analytic

function T on the open ball

B~ = {t ~ Cq+1 S.t. |t| ~}:

We can also suppose that E is so small that

T( t )

E

U’

if t ~

B~.

Then it

is easy to

check,

and a

picture

shows

how,

that if t

e B,

one has

(c) 03C1(T’(t)) 03C1(A(t)) - |u||B(t)| |u|/203A3Cjktjtk 0

This in

particular

proves that

T( t ) E D

for all t E

B~ - {0}, and,

since

(6)

03C1(T(0)) = 03C1(c(y0) = 0,

0 is a minimum for the function po

T : B~ ~ R,

and so,

taking partial derivatives,

Using

the chain rule and the fact that T is

analytic

we have:

(d) 03A3Nh=1~03C1/~zh(c(y))~Th/~tj(0) = 0 for j = 1,2, .., q + 1.

In other words the vectors

~T/~tj (0), j

=

1, 2,...,

q + 1, are in

Tc( v)~.

Moreover,

B;/t

in Cq+1,

we have

(e) 03A3q+1j,k=1~203C1o T(0)/~tj~tktjtk |u|/403A3q+1j,k=1Cjktjtk.

To prove this we first observe that it is

clearly enough

to check it for

small 1 t 1.

From the above

inequality (c), using Taylor series,

we deduce

for all

t ~ B~,

where

djk

=

~203C1o T(0)/~tj~tk

are constants and

0"(ltI2)

has

the same

properties

as

0(|t|2).

Then,

after

reducing E

if necessary, we

have,

Vt E=-

B,,

Let

/J

=

ei03B8tj

for

0 03B8 2 03C0; writing t’

in the above

inequality

and

observing

that the second and third term are

unchanged

under the

substitution t -

t’,

we

deduce, V0,

and

by choosing B

so that the first term is

negative

we prove the

inequality (e).

Using again

the chain rule and the fact that T is

analytic

we have that

the Hermitian form

is

positive

definite.

It follows

easily

that the Hermitian form

(~203C1(c(y))/~zh~zm)Nh,m=1

is

positive

definite on the linear

subspace

V of

7c(v)~ spanned by

the

(7)

110

vectors

~T/~Tj(0), j = 1, 2,..., q + 1 ;

in

particular

it follows automati-

cally

that these vectors are

linearly independent,

so that

dimV = q

+

1;

but

since - p is a defining

function for D at

c(y),

we have that

n(c(y), ) q + 1

and this contradicts our

hypothesis,

so that the claim is

proved.

Step

3:

By restricting ~

to

Û’

n D we find a

C2 function,

called

again

~:W = ’ ~ D ~ R

s.t.

(a) limy~~D~(y) = - ~,

(b) (,)glip)(y)

has at most q

positive eigenvalues Vy

in W.

Let F be a closed subset of M s.t. D - W ~ int F c F c

D,

and let

0 03A8 1 be a C2 bump

function s.t. ’1’ = 0

on F, ’1’

= 1 in a

neighbour-

hood of M -

D,

and supppse that F is chosen so

that ~(y)

0

for y 5É

F.

By considering

the function

qq’

= ~ ’

P,

we have that

(a) limy ~~D~’(y) = - ~,

(b) (H~’)(y)

has at

most q positive eigenvalues ~y ~

D -

F, (c) w’

0.

Now we use the fact that M is Stein and so

0-complete (see [5],

lemma

p.

358)

i.e. there exists a

0-plurisubharmonic

exhaustion function À : M - R .

’fin E

Z,

the set

Kn

=

{y ~

M s.t.

03BB(y) n}

is compact, therefore so is

F n

Kn

and there exist constants

Cn

s.t.

Now choose a

C2

function

f :

R - R with the

properties

First we notice

that, Vc E=- R, Be = {y ~

D s. t.

x(y) cl

is

contained, by

the property

( c)

of

qq’

in

f y

E D s.t.

f o 03BB (y) c}

which is

compact by

the

assumptions

on

f

and À.

Moreover Bc

is closed in D

and,

since

limy~~D’(y)

= - oo, it is also closed in M.

Thus Bc

is

compact and X

is

an exhaustion function.

For

all y E

D we have

where A(y) = (~03BB/~zi(y) · ~03BB/~zj(y))ni,j=1 is

a

semipositive

Hermitian

form. If

y E D - F

then there exists a linear

subspace

of

7§,D,

of

dimension n - q

where -(H~~’)(y)

is

positive

semidefinite.

Therefore

(H~)(y)

is

positive

definite on V.

(8)

If y E

F then

either y E Ko

~ F in which case

or y E

(Kn+1 - Kn )

~ F for some

integer n 0,

in which case

Therefore X

is also

q-plurisubharmonic

and we can

finally

say that the

theorem is

proved.

0

References

[1] K. DIEDERICH and J.E. FORNAESS: Pseudoconvex domains: bounded strictly plurisub-

harmonic exhaustion functions. Inv. Math. 39 (1977) 129-141.

[2] M.G. EASTWOOD and G. VIGNA SURIA: Cohomologically complete and pseudoconvex

domains. Comm. Math. Helv. 55 (1980) 413-426.

[3] H. GRAUERT: On Levi’s problem and the embedding of real analytic manifolds. Ann.

Math. 68 (1958) 460-472.

[4] L. HORMANDER: An introduction to complex analysis in several variables. Princeton N.J.

Van Nostrand (1966).

[5] R. NARASIMHAN: The Levi problem for complex spaces. Math. Ann. 142 (1961) 355-365.

(Oblatum 2-XI-1982) Giuseppe Vigna Suria Dip. di Matematica Fac. di Scienze Università di Trento 38050 Povo (TN) Italy

Références

Documents relatifs

Une des conséquences de la conjecture de Lusztig est que les caractères fantômes sont des vecteurs propres pour l'opérateur de torsion Sh^/p (cf. Asai a étudié l'opérateur de

Si p est un idéal premier de R, alors Ry est régulier si et seulement si le R -module DiflYÂ-, Ry\ = (Difî (Te, jR))p est libre (critère jacobien de simplicité, applicable, puisque

Soit (n, V) une représentation irréductible de G ayant un caractère central, et de dimension infinie.. Les fonctions de Kirillov

L’accès aux archives de la revue « Nouvelles annales de mathématiques » implique l’accord avec les conditions générales d’utilisation ( http://www.numdam.org/conditions )..

Prendre sur la circonférence to passant par O, A, B le point C milieu de Parc OAB, décrire de ce point une circonférence passant par O et mener la bissectiice intérieure de l'angle

Sont premiers absolus dans le domaine considéré : i° Les nombres premiers réels de la forme ^h — î -, 2° Le nombre i + i dont la norme est égale à i \ 3° Les nombres x-\-yi,

— Dans la formule qui doni^e 2 cos ma, on a divisé les deux membres par 2cos#, pour donner la même physionomie à toutes

Considérons les rectangles qui ont pour côtés respec- tivement les ordonnées des points dont les abscisses sont x = i, i -4- i,. ., et les distances égales à i qui séparent