Annales Academire Scientiarum Fennicre Series A.
I.
MathematicaVolumen 5, 1980, 159-1,63
HARNACK'S INEQUALITY IN THE BORDERLINE CASE
SEPPO GRANLTIND
1. Introduction
Harnack's inequality for
generalquasi-linear elliptic
equations has been provedby Serrin
[13]and Trudinger
[1a].In both
papersthe proofis
basedon
theiteration method introduced by Moser in [7] and [8]. In this
method thelemma of John
andNirenberg [4] is
essential.We
considervariational integrals of the form
(1.1)
I(u) - vu(x)) dm(x),
! '(*'
where GcR" is a bounded domain, u<W:(q, and the kernel F: GXR"-R
satisfies
the following conditions:
(1.2) The functions x*F(x,Vu(x)) are
measurablefor all u(W:(q.
(1.3) For a.e x€G the function z* F(x, z) is convex and alrl=F(x, r)=frlzl for all z€R", whete
a,B>0 are
constants.Let o€W)1q and write F*(G):{ueWl(G)lu-E<W:.r(G)}. A function
uo(%q(G) is an extremal for the integral (1.1) if I(u)>I(u) for all uQfr*(G). lt
can be proved that
uois locally Hölder continuous in G;
see[6, Theorem
4.3.1]and [3, Remark 5.7]. Let uobe an extremal for the integral (1.1) and uo(x)>0 for x€G. Harnack's inequality
takesthe following form:
1.4. Theorem. Let B(*o,2r)cG. Then maxuo=cminus in B"(xr,r).
The constantc
dependsonly on alP
and n.Our proof is based on an oscillation lemma for monotone functions in
thespace
ILj (G)n C(G).
Lemmas of this type have been proved byGehring
[1,Lemma l]
and Mostow [9, Lemma4.l]. This makes it possible to avoid the lemma of John and Nirenberg. In the
casen:2 a similar method
has been usedearlier for linear elliptic equations;
seeGilbarg-Trudinger [2, p.
200].doi:10.5186/aasfm.1980.0507
SEppo Gn.a.NluNo
2. Preliminary
lemmasWe flrst give the definition of monotone functions.
2.1. Definition. Let GcÄ'
bea bounded domain. A function u€C(G)
ismonotone in
Gif
sup
rz(x): sup u(x) and inf u(x): inf a(x)
x€D x€AD x€D x€AD
for all domains D, DcG.
The following lemma gives an estimate for the oscillation of monotone func- tions in the space W:(q.
2.2. Lemma. Let u€C(G)aWi(G) and B"(xo,2r)cG. If u is monotone in
G, we haue,ffi
,,{'} =' (rr.!*,,rlY ul"
dm)u"'The constant
y
dependsonly
on n.Proof. The inequality can
be easilyderived from the oscillation lemma proved in [9, Lemma4.ll;
seealso [1, Lemma l].
The next lemma gives a weak
maximum principle for
the extremals ofthe iutegral (1.1). In what follows E€.W:(G) will
be fixed.2.3. Lemma. Let uo(%r(G) be an
extremalfor the integral (l.l).
Thenusis
monotonein
G.Proof.
Supposethat
thereis
adomain D, DcG, and
apoint xo€D
suchthat
uo(xo)=ryaxuo(x):a.
Define ä(x):16
{uo@),a} for x(D. Then ö<9""(D) and Vä(x):0
a.e.on
theset {x(Dluo@)=-a}. It follows from the condition (1.3) that
I r@,Yå)dm(x)- [ r@,Yur)dm(x).
DD
This is a contradiction
since zois an extremal in the
class$,o(D). Thus :tBUo(x) :
*r.rg
ro(r).
We prove the corresponding equation for minimum values exactly by the
sameargument. It follows that
uois monotone in
G.Let usQF*(O be an extremal for the integral (1.1) and no(x)>0 for x(G.
Define u(x):fsg uo(x) fot x(G.
160
Harnack's inequality in the borderline case 161
2.4. Lemma. Let B(xo,4rl3)cG.
Then*{,,nlYul" dm =
co.The constant co depends
only on alB
and n.Proof. We may assume that uo(x)>(n-11't" for x(Bn(xo,4rl3). If this
isnot the
casewe consider the function )ur, where 2>0 is large enough. The func- tion luo is an extremal for a variational integral, which is of the form (l.l)
and satisfiesthe structure condition
(1.3)with the
same constantsa
ar,Ld §.Let (€Cf"(B"(*o,arp)) be a non-negative function such that ((x):l for
x(Bo(xs,r) and lY((x)l=crlr. We
chooseh(x) : q@)+-!Q-.
us(y)"-r'
Then hEfi*,(Bn(*o,4rl3)),
andit
hasthe
generalized derivativesh*,
: uo,,+ffi €*,-(n -D #ru*, : (l -* - r#) uoxi+, # <",.
Write 5: {x6B'(x6 ,4r13)l((x):A}. Suppose that x(8"(xo, arl3)\^1.
Theconvexity and growth condition
(1.3) yieldsF(x,Yh)= (t -f, -, #) rr.,y
u o) + @-, # r(., # ?
or)
= (, -r, - rr#) F@,y
uo) -t B@7y- tv
u,.= f,., (1- @-'#)F(x'Yu') dm(x)
Bn(xg,4'
+PT#
Bn(xs,*f,,r,
lv€l'dm+ f F(x,Yuu)dru(x1.
It follows from this that
(n_1),,.,o,n{,.,#F(x,Yuo)dm(x)=B#u^6!n,,,,|vc|,,dm.
Since zo
is minimizing for the integral (1.1),
we getI F(x,yu) drn(x) <- I F(x,vh) dm(x)
Bn(xs, arl}) Bn(xs,arl})
- I F(x,vh)dm(x)+{F(x,yh)dm(x)
Bn(xs, rlB)\S S
162 Srppo GnaNluNo
Notice that B"(*0, r)n,S:0. The condition (1.3)
implies --,!,Y# dru = -§-(å)
" u*,*!nrurI
Y
..lndm 5
co'Bn(xg, r)
The constant
c0 dependsonly on al\
andn. Our lernma is
proved.Letuobe an extremal for the integral (1.1) and uo(x)>0 for x(G. Let e>0 and define u(x):1sg (ro(r)+u) for x€G. The function
uis monotone in G
since zois monotone by
Lemma2.3. We obtain a bound for the oscillation of u from
Lemma2.2
andLemma2.4:
,,?,r,f,
{u}= v(*o!*,rlYul' dm)'t'
=- vctt".Then
we havelog (max
u6*e) -log (min
u6*e) =
yrät"on the set
-B'(xo,r). Finally
we getmaxuo+s = st"t/" (minu6*e).
Harnack's inequality follows if we let e*0.
3.1. Remark. Let f:(fr,...,f): G-R" be a quasiregular mapping;
see [5], [10]. Re§etnjak [11],[2]
has shownthat
eachof the coordinate functions of/mini-
mizes a variational integral of the form (1.1). Then it follows from Theorem
1.4that Harnack's inequality is valid for the coordinate functions. This fact
has beenproved earlier by
Re§etnjak,who
usedSerrin's paper
[13].3. Proof for
Theorem L.4References
[1] GrHnrNc,
F. W.:
Rings and quasiconformal mappingsin
space.-
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[9] Mosrow,
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G.:
Space mappingswith
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Siberian Math.J. 8,
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TechnologyInstitute of Mathematics
SF-02150
Espoo
15Finland
Received 16 I|lday 1979