A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
S TANLEY K APLAN
Abstract boundary value problems for linear parabolic equations
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 3
esérie, tome 20, n
o2 (1966), p. 395-419
<http://www.numdam.org/item?id=ASNSP_1966_3_20_2_395_0>
© Scuola Normale Superiore, Pisa, 1966, tous droits réservés.
L’accès aux archives de la revue « Annali della Scuola Normale Superiore di Pisa, Classe di Scienze » (http://www.sns.it/it/edizioni/riviste/annaliscienze/) implique l’accord avec les conditions générales d’utilisation (http://www.numdam.org/conditions). Toute utilisa- tion commerciale ou impression systématique est constitutive d’une infraction pénale.
Toute copie ou impression de ce fichier doit contenir la présente mention de copyright.
Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
FOR LINEAR PARABOLIC EQUATIONS
STANLEY KAPLAN
(1)
In a
previous
note[1]
we sketched a new method forproving
the exi-stence of weak solutions to the first
boundary
valueproblem
in thecylin-
drical domain
T) (S~
a bounded open set in for theequation
where the coefficients aij are
real, bounded,
andmeasurable,
and the diffe-rential
operator given by
the sum in(1)
isuniformly elliptic
inQ.
It isour purpose in the
present
work to describe the details of thatmethod, along
with some relatedresults;
we dothis, however,
for the moregeneral
« abstract
parabolic boundary
valueproblem »
as it is set forth in[2], Chap-
ter IV. To
start,
let us recall what is meantby
a weak solution u = u(x, t)
of(1)
which « assumes >>, for t =0, given
initial data uo = ito(x)
and which« vanishes » on the lateral
boundary
8!J X(0, T).
Let usput
H = L2(S2),
1T =
Ho (,Q),
and introduce the formPervenuto alla Redazione 1’ 8 Novembre 1965.
(i) Visiting Professor at the University of Pisa, 1964-65, under the auspices of the
C. N. R.
We assume that
(i, e.,
the Hilbert space of thoseweakly
measurable functions
for which
Then, by
a weak solution u, we mean a solution of thefollowiiag:
PROBLEM: Find u such that
a)
u E L2rO, T ; Vl
and ,for
all 99 E .L~[0, T ; V]
such that J.12[0, T ; H]
and 99(1’)
= 0.Here, a)
expresses the«vanishing»
of ~c on the lateralboundary
ofQ,
and
b)
expresses both the fact that 2c satisfies(1),
in the weak sense, andthat u
(t)
« assumes » the value uo for t = 0. In thepresent work, following:
[2],
we start with two abstractseparable
Hilbert spaces .g andV,
withY C H
(the
inclusionbeing continuous)
and V dense inH,
and a functiona
(t ;
u,v)
with theseproperties :
(i)
For almost every t E(0, T),
a(t ;
u,v)
is asesqui-linear form
on V m V(i.
e., it is linear in the firstvariable, complex-conjugate
linear in thesecond.) (ii)
For every u, v EV,
a(t ;
u,v)
is a measurablecomplex-valued function
on
(0, T) ;
moreover,for
all t E(0, T) (except perhaps
a setof
measure zerowhich does not
de p end
on u orv)
where M is a
positive
numberindependent of
u and v.(iii)
There exist constants A~ 0,
m> 0,
such thatfor
all t E(0, T) (with
thepossible exception of
a setof
measure zero which does notdepend
on
u)
we haveTHEOREM :
([2], Chapter IV,
Theorem1.1)
Given anyT; HJ,
there
unique
solution the Problem above.The
proof given
in[2]
holds even in the moregeneral
case whereF E L2
[0, T; V’j : here,
V’ is the anti-dualof V,
i. e., the space of continuouscomplex-conjugate
linear functionals F :V - G (v 2013~ (~ ~ ))? given
the usualnorm
(which
makes it a Hilbert space,by
the Riesztheorem.)
Of course, inb)
we now write F(t),
99(t) )
instead of(F (t),
99(t))~ .
The theoremgives,
with the
appropriate
choice ofH, V,
and a(t ;
2c,v),
existence anduniqueness
theorems for a
large
class ofparabolic problems, including
thespecial
casealready
mentioned.Thus,
inparticular,
one may consider(1)
with lower orderterms
added,
or theanalogous parabolic equation
of order 2m in the spacevariables,
or even aparabolic system
ofequations,
all with agreat variety
of
boundary
conditions(see [2], Chapter VI,
forexamples.)
To
justify
ourseeking
anothermethod,
let us reconsider the first boun-dary
valueproblem
for(1),
but this time withinhomogeneous
lateral boun-dary
data. Oneusually
assumes that the initial andboundary
data aregiven
as the trace of a
function g
defined in all ofQ. Then,
one looks for a so-lution u of
(1)
suchthat u - g
« vanishes » on D x(0) U aS~
X(0, T).
Ifwe set w = u - g, then 2o must be a weak
solution,
inL2 [0, T ; V],
ofFor the above Theorem to
apply,
theright
hand side of thisequation
mustbe in L2
[0, T; V’] (= L2 [0, T ;
in thiscase.) Thus,
ingeneral,
wewould need
and
B) ag E
L2[0, T ; V’].
at
We would then be able to assert the existence of a
unique
solutionto our
problem, u
= w+
g, which would have these same twoproperties.
Condition
A)
is naturalenough ; B), however,
isperhaps
a littlestrange.
Thus,
there is a reason forextending
the above Theorem to coverequations
with a
larger
class ofinhomogeneous terms,
which we do(Theorem 2,
be-low,)
under theassumption, however, that Uo = 0 ;
to some extent this losscan be
recouped by making
the initial data reappear aspart
of theright
hand
side,
in the usual way(see
Theorem4, below.) Applying
Theorem 2to the first
boundary
valueproblem,
we see thatB)
may bereplaced by
the two conditions
and
Thus,
for any gsatisfying A), B’)
andC)
thereexists, by
Theorem2,
asolution it of our
problem
which also satisfiesA), B’),
andC). By
way ofcomparison,
Theorem 4gives
a necessary and sufficient condition in order that the solutiongiven
in[2] satisfy B’)
andC) :
itis,
of course, acondi-
tion on uo , i. e., that uobelong
to a certain Hilbert space intermediate between V and H.The heart of our method is Theorem
1,
which is an existence theorem for weak solutions of an abstractparabolic equation
on the whole realline ;
1
its
proof
uses the Fourier transform and the spaceH2, thereby extending
methods used in
[2] (Chapter IV,
Theorem2.2)
in the discussion ofregula- rity
of solutions. The easy lemmas at thebeginning
of Section 2 enable usto
identify
certain classes of functions on(0, T),
and bilinear forms definedon those function
classes,
with the restrictions ofcorresponding
entitiesdefined on the whole real
line; then,
Theorem 2 is seen to follow from Theorem1, essentially by
restriction.Theorem 3 is a weak
regularity
theorem which asserts that under aslight
furtherassumption
on theinhomogeneous term,
our solution u iscontinuous,
as a function from(0, T)
toH,
a fact which does not follow from the fact that u satisfiesA), B’),
andC) (see [3].)
Theorem 3 is similar to Theorem 2.1 ofChapter
IV of[2]
inintent;
its scope is somewhat dif- ferent. Itsproof
isaccomplished using
methods introduced in[2]
and[3].
Our
dependence
on ideas and methods introducedby
J. L. Lions isobvious ;
inaddition,
we owe Prof. Lions a debt ofgratitude
for ahelpful
discussion of the
present work,
which influenced its final formulation. Prof.Lions was able to derive our Theorem 1 and Theorem 2 from the results of
[2], using
thetheory
ofinterpolation;
this should appear in the forth-coming
book on thatsubject by
Lions and Peetre. We should also like to thank P. Grisvard for a useful discussion of Theorem3, and,
inparticular,
for
pointing
out to us an error in what we took to be theproof
of a stron-ger result.
1.
A parabolic equation
on thewhole
realline.
We write
9l
forL2 [- oo, oo ; H] and C))
for L2[- oo, oo ; V] ; thu4,
and a similar
expression applies
forv)cp.
We aregiven
a continuoussesqui-linear
formA ( t1, v ) on flfl
XC)J:
for all
(if
apositive constant) which,
inaddition, satisfies,
for some m >0,
for all
We look for a solution of the
following problem:
find u which satisfies theequation
for every « test function » v. Our first
step
is togive
thisproblem
aprecise
-
meaning.
To thisend,
we introduce the Fourier transform 1ft 2013udefined
by
for those u in
qe
withcompact support
in(- oo, oo).
If it both havecompact support
and in addition assumeonly
a finite number of values inH, then, by
the Planchereltheorem,
y we haveBy
a standardapproximation argument,
such functions are dense inIM;
hence 7 extends,
via(4),
to aunitary
transformation ofck
onto itself. Si-milarly 9: C19-,
isunitary.
We consider the
subspace ~
of9~
defined as follows : u E9V
if andonly
if1
(cW
is often called .g2[-
00, 00 ;H];
see[2], [3].)
Thesignificance
of thisspace for us lies in the
following:
If u E hascompact support,
and isdifferentiable, i. e.,
1*1
exists,
the limitbeing
taken in9(,
then i r u E9(,
where i r udenotes,
of1^1
course, the function T -- 2
(T), and,
we haveIf both u and v are
differentiable,
withcompact support,
thenapplying (4), (5),
and theCauchy-Schwarz inequality,
we conclude thatSince such functions are dense in we may extend
(at
in aunique
qmanner to a continuous on
flfl M (6)
tell usthat
By
a similarapproximation argument,
we conclude that for allFinally,
we introduce the Hilbertspace 9C
with the scalarproduct
Since, by assumption, 3
C>
0 such that for allthe scalar
product
in9C
is seen to beequivalent
to the more naturalone,
i.e.,
We
introduce %
because it is the natural domain of definition for the formmore
precisely,
.E is a continuoussesqui-linear
formon %
XEY.
Thus .Edefines a continuous linear
mapping
Lof %
into the anti-dual of~, by
means of the relationwhere the brackets on the left denote the
duality between %
and~’.
Note that .E is not coerciveon ~ ; nonetheless,
we have thefollowing :
THEOREM 1 : L is an
isomorphism
onto~’.
PROOF : Since we
already
know thatL : ~
into9(/
iscontinuous,
itsuffices to show that
(a)
The range of L is dense in and(b) 3 N > 0
such that((b)
tells us that Z-I iscontinuous ; (a)
that it isdensely defined.)
(a): Since SC
is a Hilbert space, it suffices to show thatif vESt’
is such thatfor all then v = 0.
But, by definition,
this meansfor all in
particular,
and, therefore, by (7),
from which it
follows, by (3),
that v = 0.(b) :
We introduce the linear transformation u-+;¡
defined as follows:where
9N
is themultiplication operator
definedby
It is obvious that
and
for all for all
Moreover,
for u E it is clear that we haveIf,
for u ESt
we write F =Lu, then, by definition,
Setting
= u in theabove,
andtaking
first realparts
and then absolutevalues of both
sides,
we obtain-
Setting v
= u in the sameequation,
we obtainand hence
by (8). Adding
this lastinequality
to(8),
we havewhich
gives (b),
with2.
Application
toproblems
on a finiteinterval.
We here
apply
Theorem 1 to thestudy
of the Problem of our intro-ductory
section.Thus,
we aregiven a (t ;
u,v) satisfying (i), (ii),
and(iii)
ofthat section. For the moment we assume that
(iii)
holds even with  ~0 ;
this further
assumption
will not enter in our final result. We may extenda
(t ; u, v)
in such a way that(i), (ii),
and(iii) (with À
=0)
continue to holdon all of
(-
oo,co). Indeed,
we may, forexample,
definefor With a so
extended,
we definefor all
A,
sodefined,
is asesqui-linear
formon flfl
x which satisfies(2),
andfor all - I
an
inequality
whichimplies (3). Thus,
withB, E,
and L defined as in Sec- tion1,
Theorem 1applies : given
F E~’
there is aunique u (=
E-1(~’))
in9~
such that Lu = F.We shall say that
for
= 0 for every v E
SC
such that forLEMMA 1 :
If
F = 0for t 0,
then .L-1(F)
= 0(a. e.) for t
0.PROOF : We write u =
(F) ;
since u E9~
inparticular
the functiont
(t) ~~$
is in L1[-
oo~ oo ;dt]. Thus, by
the well-known theorem ofLebesgue,
the function ..is a. e.
defined,
and wehave cp (t) = u (t) Ilk
a. e. in(-
00,cxJ).
To accom-plish
ourproof
we shall in fact show that q(t)
is defined and = 0 for all t 0. Given t0,
let E > 0 be smallenough
so that t+ 8
0. We definee
(i)
= e,t (i)
asfollows: (!
is continuous for all T, =1 for zc t,
= 0 forT ~ t
+
E, and linear in between. We shall first show that theequality
holds for all u E
9V.
Since themapping u
-+ eU is continuous fromW
into~ (in fact,
it followseasily
from(11)
below thatboth sides of
(10)
are continuous functions of u E9V . Thus,
it isenough
toprove
(10)
for u inW
withcompact support
and such thatau ai
a,c exists(in
In this case, v = eu is also differentiable inH,
and we havewhere
Ôôe = 0 -- 1
and = 0 fora 8
-E-
Thus,
we find thatfrom which
(10)
followsimmediately.
From u = Lw
(F),
weobtain,
inparticular
since (2u E
St,
and vanishes for T>
0.Thus, by (10),
we haveLetting e
-+0,
we obtainsince both terms on the left hand side of this
equality
arenon-negative,
our
proof
iscomplete.
Our next
step
is to characterize the restrictions to(0, T)
of the Hil- bert spacesV
andCU9 (and
thesubspace
ofW consisting
of those func-tions u E
9V
which vanish for t0.)
The restriction ofV
to(0, T)
is ofcourse
just L2 [0, T ~ V].
Rather than treatsimply 9d,
for later use it is convenient to considerCU9a,
for 1>
« h0,
whereCU9a
is the Hilbert spaceconsisting
of thoseu E qe
for whichIn
particular W. Using
the Plancherel relation(4),
an easy calcula-2
tion
gives
the well.knownidentity
for 0
a 1,
where Ga isgiven by
14. Annali della Scuola Norm. Sup. - Pisa.
With this in
mind,
we define the spacesWa, W.0 ,
andW« by
means ofthe norms
We shall consider
only
y a in the interval1 L 2’ ’ 1
· thus for 1t tobelong
torV2 (resp. W;)
it is necessary that 1t «vanish» at 0(resp. T) sufficiently rapidly (a
Dini condition inH.) Conforming
to ourprevious notation,
wewrite
simply
W° and WT forW1û
andlV1T.
.. 2 2
"
LEMMA 2 :
(i) u
ErVa if
andonly if
there9d~
such thatin that may be chosen so that
where 0 is a
positive
constantsindependent of
uand Z.
(ii)
u ETV a 0 (resp. Wa ) if
andonly if
thereexists Z E
0for
t 0(resp.
t> T )
such thatin that may be chosen so that
where ’YJ is a
positive
constantindependent of
uand u .
PROOF :
(i):
The «if»part
isobvious, by (11).
On the otherhand, given u
EWa ,
weconstruct Z
as follows : we extend it first to(- T~ T ) by
reflection about t =
0,
then to(- T, 3T ) by
reflection about t = T. To ob- tain u, wemultiply
the resultby
afixed, real-valued,
7 smoothfunction e,
defined on
(- T7 3T),
which assumes the value 1 on[0, T]
and the value/ /Tt B N
0 outside of
2013 2013 3T ;
weput
= 0 outside of(- T, 3T).
To see that2’
2J /
’)
u is in
CU9a
and that(12) holds,
it suffices to consider the result of a re-flection,
about t =0,
forexample. Thus, given u
EWa ,
wedefine u*
a. e. on(- T, T)
as follows :for for
From considerations of
symmetry,
y all we need estimate is theintegral
we find that
from which our result follows.
(ii) First,
suppose u is the restriction to(0, T)
of;¡¡ E with u = 0
for t 0.
Then,
we haveand hence u E
Wo. Conversely, given u
EW~°,
we construct itsextension
as follows : first we extend u to
(0, 2T) by
reflection about t =T,
and thento
(-
oo?oo) by setting u = 0
outsideof (0, 2T).
The calculationjust above, along
with that used in theproof
of(i), yields
our assertion. Similar reaso-ning applies
in the case of and ourproof
iscomplete.
Now, given
u E W °(resp. W T)
W T(resp. W°)
we may define thesesquilinear
formwhere Z and Z
are any extensions of u and v toCU9, vanishing
on theappropriate
half-lines. For this definition to makesense, B C u, v )
must notdepend
on which extension we choose.LEMMA 3 :
If u and v E CU9,
2oith u = 0for t a,
and v = 0for
then
B ( u, ro ) = 0.
-PROOF : Without loss of
generality,
we take a = 0.Let e be
a smoothreal-valued function with
support
in[-1,1~
such thatWe
define u.
= where Lo,(t)
=~ ~ (2013) ~
· it is easy to see that ~2013~in
~
as 8 -~ 0.Thus7
it suffices to show thatBut,
we haveThus, taking
K -sup (t) I,
we obtainBut,
both of these lastintegrals
tend to zero as 8 --~0, by
Lemma 2(ii),
and our
proof
iscomplete.
Thus,
we havedefined B ( u, ~ )
as a continuoussesquilinear
form onW o >C W T
(or W 1) : continuity follows,
infact,
from Lemma 2(ii).
We next extend this form to an even
larger
domain : we shall callW~
thespace of those u E W for which there exists a,n h E H such that u - h E lV°.
Such
an h,
if itexists,
isuniquely
determinedby u, and, furthermore,
ifu is such that
lim u (t)
exists(in H),
thenh == lim u (t).
Thisjustifies
ourt-o+ t-o+
writing h
= u(0).
Wegive W,~
the normIt is clear that we have
in
fact,
WO is thesubspace
of those u EW2
for whichu (0)
= 0. For u inW ° ,
v in 9 we defineREMARK :
If f is
differentiable in L2[0, T ; H], then,
as iseasily
seen, themapping f : [0, T ] -+ H
isuniformly
continuous(after
modification ona set of measure
zero), and,
infact,
we haveFrom this it follows that
f
is inif,
inaddition, f ~T )
=0,
thenf
isalso in
Using
Lemma21
oneeasily
shows that the differentiable fuuc- tions in]
are dense in and those which vanish at t == 11are dense in
If f
is differentiable inL2 [0, T; H],
thenfor all
if,
inaddition, f (T ~
=0,
thenv
for all u E
W ~ .
Thus,
thefollowing gives
a solution of the Problem stated in our in-troductory
section :THEOREM 2 : 1
Suppose a (t ;
u,v) satisfies (i), (ii),
and(iii). Then, given
g~ E
W.0
and ’tjJ E L2[0, T ;
iV’],
there exists aitniqtte
u E[0, T ; V] ] satisfying
jor
all .L2[0; ~’ ; V]. (The
bracket in theintegral
on theright of (15) represents
theduality
between V’ andV, of course). Furthermore,
themapping
--~ u is continuous
from W~°
X L2[0, ~’ ; V’]
intoL 2 [0, T ; V] ] (given
the naturaltopology o f
a?2intersection.)
PROOF :
a) First,
assume that(iii)
holds with 1 = 0. Wewrite 99
forthe extension
of 99 -
99(0)
to the wholeline,
defined as in theproof
ofLemma 2
(ii).
Inparticular, ;=0
fort 0.
We defineas follows :
for for
Finally,
we define F E9(’ by setting,
for w E9C
Clearly,
F - 0 for t0, by
Lemma 3.Applying
Theorem 1(with A u, v >
defined as at the
beginning
of thissection)
exists in9~
andsatisfies
for every
- -
By
Lemma1, u
= 0 for t 0. We take u to be the restrictionof u
to(0~ T ) ; by
Lemma2,
Givenits extension v, as defined in Lemma 2
(ii)
is in9C
and vanishes fort>T.
Thus, putting 10 = v
in the lastequation,
we obtain(15).
Theuniqueness
of u follows
easily
from Lemma1;
thecontinuity
assertion follows from the fact that themapping q)
-~ ~c is thecomposition
of(q,
~F,
F -+
Z,
and u, all of which areclearly continuous,
in theappropriate topologies.
b)
In thegeneral
case, we use the standard device ofmultiplication by
anexponential.
We observe thatmultiplication by
a realconstant,
is an
isomorphism
of each of the spacesW°, W ° , W T~ .L2 [o, T ; Y Jy
andL2
[0, T; V’]
onto itself. Inaddition,
wehave,
for w EWO
and v E W ~’In
fact, by
the Remarkabove,
it suffices to prove(16)
for u’ a differen-tiable function in but in this case, it is
trivial, by (14).
Wenext note that the form
I
satisfies
(i), (ii),
and thestronger
version of(iii)
used ina).
Since A0,
and ;p and ;;
vanish for t0,
we may define F *69C" by taking,
for w Emoreover, the
mapping (q, y~) --~ ~’ ~
iscontinuous,
and F* = 0 for t 0.Thus, by
thereasoning
used ina),
we may find E W ° which satisfiesfor all v E L2
[0, T; V ] ;
moreover, themapping (q, 1p) -~. u~
is conti-nuous.
Now,
we setu = elt u* ;
the lastequality becomes, using (16)
which
gives
us(15), by
our earlier observation about theisomorphism properties
ofmultiplication by
anexponential. Uuiqueness
andcontinuity
are immediate consequences of the same observation.
3.
Continuity of solutions.
Our
problem
here is thefollowing:
what further conditions on q and 1Jl in Theorem 2guarantee
that our solution it iscontinuous,
as a functionfrom
[0, T
to H We note first thefollowing :
b ifa 1 ,
2then la
cW °.
In
fact, if q-)
EWa ,
then after modification on a set of measure zero, (p satisfies the Holder conditionfor 0
--- t, s
~T,
where~a
is apositive
numberdepending only
on a. Let99 be the extension
of 99 given by
Lemma 2~i~ ; by
a standardargument,
it suffices to prove
(17)
in thespecial
case inwhich 99
hascompact support.
Then, modifying 99
on a set of measure zero, wehave,
for 0 ~ t :T,
and hence
from which
(17) follows, using
Lemma 2(i).
THEOREM 3 :
Suppose
9’ EWa
some oc~ 1 2 ~
E .L2[0, T; > V’ .
Then the solution u
corresponding, by
Theorem2,
totp)
may beredefined
on a set
of
measure zero so as togive
a continuousmappircg from [0, T] into H,
with u(0)
= 0.PROOF : For the sake of
simplicity
wegive
theproof only
in thespecial
case considered in theintroductory
section: H=L2(Q),
V=H~ (Q),
where S~ is a bounded open set in R’~.
Then, below,
we indicate what must be done in thegeneral
case.First,
we consider the unboundedoperator
onH, A,
definedby
meansof the relation
for all
the domain of A consists of those u in V for which the
mapping
is a continuous anti-linear functional on the set
V, given
itstopology
asa subset of H. In
general,
~1 isself-adjoint and h Ao >
0([21, Chapter II).
In our
special
case, it is well-known that ~1(which
isjust
thenegative Laplacian,
defined on functions which vanish at00)
has acompact
inverse.The
problem
thus has an
infinity
ofpositive eigenvalues
0Âo
_Â1
c ... and cor-responding eigenfunctions (ok),
elementsof V,
which in fact form a com-plete
orthonormal basis in H. For it inH,
we writeThen,
moreover, y u E V if andonly
if is squaresummable;
in that case, we haveFinally,
for u E V’ we defineit is then easy to see that is
square-summable,
andWe
shall,
infact,
prove thefollowing
whichby
Lemma2, implies
our Theorem : and satisfies
where q
Ea > 1 2 and y E L2 [2013
o0 00 ; · V,], then,
> after modification on
I 2)
a set of measure zerol the
mapping u : (-
oo, is bounded anduniformly
continuous. Ourproof
consists of twosteps :
a) Let e (T, 1)
be anon negative
function with theproperty
Let it E
ge
be such thatThen,
after modification on a set of measure zero, u :(-
oo,oo)
-+ H isuniformly continuous,
and we have-
PROOF : If u has
compact support, then, redefining it
on a set ofmeasure zero, we have
thus, it
isuniformly continuous,
and we haveHence,
-
which
gives (19).
Forgeneral
weapproximate 2c simultaneously
inH
and in theIII
.Ille
normby
a sequence(vn)
of functions in9(,
withv
compact support.
The sequence(vn)
of inverse Fourier transformsapproaches
u in
cY;
it is also aCauchy
seqnence in the uniform norm,by (19),
andhence has as limit a
uniformly
continuous H-valuedfunction,
which mustagree almost
everywhere
with u.b)
We now show that under theassumptions
made on uabove,
andwith the choice
the
hypotheses
ofa)
are satisfied. Sincex > 2013 ?
an easy calculation veri- 2fies the first. For the
second,
y we first note thatin
fact, taking V (t)
= e(t)
iy , ywhere p
is anarbitrary
testfunction? (18),
combined with
(6), gives
from which
(20)
follows at once.Thus,
we may conclude thatand therefore
Hence,
wehave, applying
Planchereland our
proof
iscomplete.
For the
general
case, theeigenfunction expansion is,
of course, not available. But thisexpansion
isjust
aspecial
case of the von Neumanndiagonalization
theorem usedby
Lions in a similar context([2], Chapter IV,
Theorem2.1,
and[3]). Using
thistheorem,
theproof
goesthrough, formally
withoutchange (an integral
over a half-linereplacing
the sum overdiscrete
eigenvalues).
4.
Comparison
with thesolution
in[2].
In
[2], Chapter IV,
an existence theorem(Theorem 1.1)
isgiven
whichprovides
a solution~6Z~[O~T; V] J corresponding
togiven
initial data Uo E H. To compare the scope of this theorem with our Theorem 2 it will suffice to answer thefollowing question:
For which ~o E .g does thereexist cp E W
n L2[0, T ; V] J
suchthat q (0)
=u, I
In the formulation of ouranswer, and its
proof,
it isagain
more convenient to treatonly
the samespecial
case considered in Section3 ;
the remarks made there about the extension to thegeneral
caseapply again
here.THEOREM 4 : Given
h E H,
thereexists 99
EW~° tl ~2 ~0~ T; V] ]
such thatq
(0) = h if
andonly if
PROOF : Given E
H,
we defineIt is
easily
seen thatg;*
EW n L2 [0, T ; V] ;
in factand
where
Moreover,
we haveBut since
the « if »
part
of our assertion follows from(21) by
Fubini’s theorem. Con-versely, Vl with cp (0) = h,
weapply
Theorem 2to assert the existence of a u E
T ; V]
which satisfiesfor all
~~,
We shall show a. e. in[0,T];
hence
cp*
willbelong
to(with cp* (0)
=h)
and the «only
if »part
willfollow from
(21), using
Fubini’s theoremagain.
To thisend,
we writein
(22),
we take v(t)
= e(t)
Gk, where e is anarbitrary
smooth real-valued function with
compact support
in(0, T). (22)
thengives
us(see
the Remark of Section
2)
from which it follows at once
that,
after modification on a set of measurezero, ~~
(t)
is constant on[0, T].
But sincewe must have 1jlk
(t) ..~. hk
a. e. in[0, T~,
andhence,
forevery k ~-1~ 2, ...
from which our assertion follows.
COROLLARY :
Suppose a (t ;
it,v)
is as Theorems 2. Given Iz EH,
thereexists ac ~c E
W °
fl L2[0, T ; V]
with u(0)
=h, satisfying
for
all v E W ~’ f1L2 [0, T ; V] if
andonly if
hsatisfies (20).
PROOF : If such a u
exists,
then h satisfies(20), by
Theorem 4. Con-versely,
if h satisfies(20), then, by
Theorem4,
there is a 99 E n L2[0, T; V]
with
qJ (0) = h. Then, by
Theorem2,
there exists] satisfying
for all
clearly
has all of the desiredproperties.
BIBLIOGRAPHY
[1]
KAPLAN, S. « Sull’esistenza di soluzioni deboli di equazioni paraboliche » Atti del Convegnosu le equazioni alle derivate parziali, Nervi, 25-27 febbraio 1965. Edizioni Cremonese - Roma.
[2]
LIONS, J. L. «Equations Différentielles Opérationnelles » Springer Verlag 1961.[3]
LIONS, J. L. « Espaces intermédiaires entre espaces hilbertiens et applications » Bull Math.R. P. R. Bucharest 2, 419-432 (1958).