A NNALES DE L ’I. H. P., SECTION A
S. E. C HEREMSHANTSEV
Hamiltonians with zero-range interactions supported by a brownian path
Annales de l’I. H. P., section A, tome 56, n
o1 (1992), p. 1-25
<http://www.numdam.org/item?id=AIHPA_1992__56_1_1_0>
© Gauthier-Villars, 1992, tous droits réservés.
L’accès aux archives de la revue « Annales de l’I. H. P., section A » implique l’accord avec les conditions générales d’utilisation (http://www.numdam.
org/conditions). Toute utilisation commerciale ou impression systématique est constitutive d’une infraction pénale. Toute copie ou impression de ce fichier doit contenir la présente mention de copyright.
Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
1
Hamiltonians with zero-range interactions supported by
aBrownian path
S. E.
CHEREMSHANTSEV (1)
Centre de Physique Theorique, C.N.R.S., Luminy, Case 907, 13288 Marseille Cedex 9, France
Vol. 56,n"l,1992, Physique theorique
ABSTRACT. - Hamiltonians with zero-range interactions
supported by
some closed set Q of
Lebesgue
measure zero are considered. Theapproach
we use to construct such
operators
is alimiting procedure
with ultraviolet cut-off inFourier-representation.
We consider two different cases: withoutrenormalization and with renormalization
procedure.
Conditions sufficient to the existence of nontrivial hamiltonians with zero-range interactionsare
given.
The obtained results areapplied
to the case where Q is aBrownian
path
inm = 3,
4 and 5.RESUME. 2014 On considere les hamiltoniens avec 1’interaction de radius
zero,
concentree sur 1’ensemble fermee de la mesure zero Q.L’approche qu’on
utilise pour construire cesoperateurs
c’est uneprocedure
limite avecIe
couplage
ultraviolet dans larepresentation
de Fourier. On considere deux cas different : sans renormalisation et avec uneprocedure
de renor-malisation. Les conditions suffisantes a 1’existence des hamiltoniens non
triviaux sont donnees. Les resultats obtenus sont
appliques
au cas ou Qest une
trajectoire
de laparticule
brownienne dansm = 3, 4,
et 5.e)
On leave of absence from: Leningrad Department of Steklov Mathematical Institute, Fontanka 27, Leningrad 191011, U.S.S.R.Annales de l’Institut Henri Poincaré - Physique theorique - 0246-0211
2 S. E. CHEREMSHANTSEV
INTRODUCTION
Study
of hamiltoniansdescribing
zero-range interactions is tt where research had beendoing
for along
time bothby physicists
mathematicians. We shall not
give
here thedetailled
review ofresults, referring
to[1].
Let us
only
note that most of papers aredevoted
to the caseinteractions are concentrated in a discrete
(finite
orcountable) points.
One can writeformally
such hamiltonians in thefollowing
At the same time little attention has been devoted to the corn
case: .
where Q is some closed set in of
Lebesgue
measure0,
dm~measure on Q. In
particular,
Q can be a line or a surface in~, [6]. Except
of[8]
where a nonstandardanalysis
isapplied,
the 1usually
used to constructself-adjoint hamiltonians, corresponding
is based on the
theory
of extensions ofsymmetric operators
in space. Thesymmetric operator
to be extended is2014 A ~ Co
The knownexamples
ofapplications
of the theextensions to this case are valid
only
for smooth manifolds Q. At thetime construction of
self-adjoint operators
in the case where 03A9 smooth is of interest from differentpoints
ofview,
both mathem ..11and
physical.
Inparticular,
it isimportant
in thetheory
of field(see [8])
to construct hamiltonians of
type ( 1 ),
where Q is a Brownianpath
in IRm.We shall describe a
quite general
scheme which will allow us to constructself-adjoint
hamiltonians with zero-range interactionsupported by
a closedset with
Lebesgue
measure 0 which can beparametrised. Namely,
let(X),
where (0 : X -~ X is a space with measure u. We shall assumethat the map 03C9 is
measurable,
but notnecessarily
smooth or continuous.The
approach
we use is alimiting procedure
with ultraviolet cut- off inFourier-representation.
This idea was first usedby
Berezin and Faddeevin
[9]
in the case where Q is asingle point.
Later it wasapplied by Grossmann, Hoegh-Krohn
and Mebkhout[7]
to theN-point
case. Wemay consider our method as a continuous version of
[9], [7].
The obtained results can be
applied
to the case where Q is a Brownianpath
in wherem = 3, 4,
5. Weget
a standardproof
ofcorresponding
results of
[8]. However,
we notonly
prove the existence of nontrivial self-adj oint operators ( 1 )
but alsoget
anexplicit
formula for their resolvents.This formula can be considered as a concrete realisation of abstract Krein’s
de l’Institut Henri Poincaré - Physique theorique
formula
[10].
It allows us tobegin studying
ofspectral properties
of theseoperators.
1. CONSTRUCTION OF ZERO-RANGE INTERACTIONS WITHOUT RENORMALIZATION
Let Q be a closed subset of
Lebesgue
measure 0 in o- a Borelmeasurable map from X to such that
being
a space with finite measure Jl. Let ustry
togive
arigourous meaning
to theexpression ( 1 ).
We can writeformally
where F is some real function on X.
[One
can take inparticular
F(o (t)),
where F
(x)
is a real function on One can construct anapproximation
of 8-function
by
a sequence ofseparable
interactions with ultraviolet cutT off:where in
p-representation
Let us consider a sequence of
operators
inL2 (Rm), given
inp-representa-
tionby
where
~(~)==(27r) ’"~exp(-~(~co(~)))~(~~~).
We shall assumethat F is a real measurable bounded function on X. One can
easily
seethat
operators Vn
are bounded andself...adjoint
inL2
henceHn
areself-adjoint operators
with a domain .Note also that
for
all/,
We shall use thefollowing
well-known statement[11].
4 S. E. CHEREMSHANTSEV
TROTTER-KATO THEOREM. - Let
Hn
be a sequence ofself-adjoint
oper- ators in Hilbert space Jf. Assume that there are twopoints
z + and z-such that
Im z+ >0,
0 and thestrong
limits exist:Assume that Then there exists a
self-adjoint operator
H such thatHn
converge to H in thestrong
resolvent sense.To use this theorem we have to
study
resolvents ofHn.
Letg E
L2 fn
=(Hn - z) -1 g
=Rn (z)
g. Weget
from(2)
thatDeduce a formula for a function
pn (t) --_ ( fn, en (t)). By taking
the innerproduct with en (s)
inL2
weget
where
Let us
investigate
the behaviour of the kernelsLn
as 77 -~ oo .Writing
theintegral
inpolar
coordinates weget
where 0 = 0 (s, t) _ ~ c~ (s) - ~ (t) ~,
r:tm is somepositive
constant,~~2
andfor ~=O we define
sin (R ~)/(R ~) =1.
LetA > 0, +00).
then the limit exixts
where is a Green function in From
I
sin(x)/x ~)’ ~,
0 S1,
weget
thefollowing
estimate:Annales de l’Institut Henri Poincaré - Physique theorique
uniformly
on s, t, n. In the case m = 3so
where
C1, C2
do notdepend on s, t, nand
If
~~4
then the kernelsLn (s, t, z)
do not havepointwise
limits as n oo .Therefore we shall assume in the
part
1 that ~=2 or ~=3. We shallassume also that the
following
condition is satisfied. If ~=2 then(Al)
ForIf m = 3 then
(A2)
The functionbelongs
toL2 (X2).
LEMMA 1. - Let F be a bounded real
function.
Consider a sequenceof integral
operatorsBn (z)
inL2 (X)
with the kernelsThe following
, statements hold:1. For
E N, B~ (z)
are Hilbert-Schmidt operators.2.
Bn (z)
converge as n --+ 00 in the operator norm to the operators B(z)
with the kernels
3. B
(z)
are compact inLz (X).
4.
II
B(z) ~ II
~ 0 as Im(z~~~)
~ + 00.5. B
(z)
is ananalytic operator-valued function
onC"’[O,
+00).
~roof. -
The statement 1 follows from boundedness ofBn (s,
t,z)
andfrom finiteness of measure ~. Define
~Ln (s,
t,z)
=Ln (s,
t,z) -
L(s,
t,z)
6 S. E. CHEREMSHANTSEV
and estimate the norm in
L2 (X):
where
From
(8)
weget
where
~J = ~ (L2 (~2)).
Let us show
that ~ Kn (z)
~ 0 as n ~ oo .1. Letm=2. Then
Hence
It follows from condition Al
that A=~(~)-M(~>0
for a. e.(s, t).
Hence,
for a. e.
(s, t) E ~2.
From(6) by
dominated convergence theorem weget
2. Let m = 3. From A2 we
get N (t, u)
+ oo for a. e.(t, u),
andfor a.e. so
for a. e. From
(7)
and A2by
dominated convergence theoremAnnales de , l’Institut Henri Poincare - Physique theorique .
for a. e.
(I, uj
andwhere
C (z)
does notdepend
on t, u, n.Applying again
the dominated convergencetheorem,
we obtain from( 11 ), ( 12)
and(A2)
thatThe statement 2 is
proved.
The statement 3 follows
directly
from 1 and 2.Let us prove 4. If m = 3 then
From
( 13)
and A2 weget
4. If m = 2 thenOne can show that the
integral
in(14)
tends to 0 as oo,hence,
4 is true.To prove 5 it is sufficient to show that the
following
limit exists for all+
00)
inoperator
norm:This statement can be
proved quite asily,
so we shall omit it. Theproof
of lemma is
completed.
LEMMA 2. - Let F be a real bounded
function.
Thenfor
all z: Im z ~ 0the bounded operators
(I
+ B(z))
-1 exist.Proof - Cperators
B(z) being compact,
it is sufficient to show that there are no nontrivial solutions to theequation
Multiplying (15) by f (s) F (s)
andintegrating
overX,
weget
8 S- E. CHEREMSHANTSEV
The
operators B (z)
converge to B(~j,
hencewhere
and the
limit (16)
exists.Therefore,
Since F is
real,
it follows from( 16)
and( 17)
thatand
/(/?)=
0 for a. e. p EHence,
It follows from
( 15)
and( 18) that/=0.
Theproof
iscompleted.
Remark. - It follows from the
proof
that for F(t) ~
0(a repulsive case)
the
operators (I + B (z)) -1
exist for all z = - a,Let us return to the
expression
for resolventsRn (z).
FixBy
Lemma 1 and Lemma 2
for n>N(z) operators
exist andFrom
(4)
and(5)
weget
for allAnnales de Henri Poincare - Physique theorique .
where
Obviously,
uniformly
on X. In a similar manner,where
It follows from
(20)-(22)
that converge inL2
as n oo, andTo
satisfy
to the conditions of Trotter-Kato theorem we should demons-trate that
Ran T (z)
is dense inSuppose
that it is not true andfor some
cp ~ 0, (cp, T (z) g) = 0
for all inx-represantation, g (p) _ (p2 - z) , f’ (p).
From(23)
weget
since
Since
Co
is denseL2
weget
from(24)
that cp = o.We have
proved
the main result ofpart
1.THEOREM 1. - Let 03C9 be a measurable map
from
X to Assumeconditions
Al(m
=2)
or A2(m
=3).
Let F be a real bounded measurablefunction
on X . Then there exists aself-adjoint
operator H inL2
such10 S. E. CHEREMSHANTSEV
that
Hn
converge to H in the strong resolvent sence. ForL2 (!R"’)
andz : Im
z~0
the resolventgiven by (23).
Having
constructed theself-adjoint operator H,
we canstudy
now someof its
properties.
Define It is clear that
Ho
is
a closedsymmetric operator.
LEMMA 3. - H is a
self-adjoint
extensionof H0.
Proof -
Let From(23)
we have
R(z)~==/,
since~(~)=/(jo(~))=0. Hence, /eD(H)
and(H - z) /=
g =(Ho -
Theproof
iscompleted.
It is
important
that H benontrivial
extension ofHo,
thatis,
H=~ -A) 1 H2 (Rm).
Weshall
denoteby
a ball of radius R centeredat x0. Define
LEMMA 4. - Assume that two conditions are
satisfied:
1.
((3R (xo))
> 0for
some R >0,
x0~R.2. For some M > R the
function
F(t)
isstrictly positive (or negative) for
a. e. t E
~M (xo).
Then H is a nontrivial extension
of Ho.
Proof - Suppose
that H:::; - A. LetDefine h
(s) = ((I
+ B(z)) -1 ~~p (o ( . ))) (s).
It follows from(25)
thatand
One obtain from
(26)
andthe proof
of lemma 2 hence(p =
((I
+ B(z)) h) (~’)
= h~(~’)
andby (26)
Annales de l’Institut Henri Poincaré Physique " théorique ’
Let us choose
(p(~-)
such thatc~ (x) ~ 1
for andcp (x) ~ 0
for x E From(27)
and condition 2 of lemma weget
for a. e. On the other
hand, p (00 {t)) =1
for andby condigion
1 Thiscontradiction completes
theproof.
If on
X,
then the statement of lemma holds.LEMMA 5. - The operat .or H is
bounded from
below.~’r~oo, f : - By
lemma 1 wehave [)B(z)))-~0
as Im(z ~ ~2) -~-~
+00.Hence,
for some A> 0 the inverseoperators {I + B (z)) -1
exist andfor
allRez~-A,
One caneasily
show from(23)
and(28) that uniformly
onVA
andfor all
~A.
Thisimplies (-00, -A)ep(H).
Theproof
iscompleted.
LEMMA 6. - The spectrum of H ort
( -
00,0)
is discrete withonly possible
accumulation
point
z = O.The
proof
of thislemma
isidentical
to that in lemma 12 ofpart 2,
sowe shall omit it.
LEMMA 7. -
Assume that
a.e. tEX. Then(-00, O)ep(H),
that
is, H ~
0 and there are no states withnegative
The result follows from the remark to lemma 2.An
important property
of H islocality [ 1 ] .
LEMMA 8. -
Then (Hf) (x)
= 0 a. e. onKR.
The result follows from lemma C2 of
appendix C
in[ 1 ].
Applications
1. D is a
part
of line in~2.
Forinstance, X==[0, 1], ~ (t) _ .(t, 0).
Thecondition Al is
equivalent
tothat
is true. One canapply
our resultsalso
in the case where 03A9 is apart
of a smooth curve.12 S. E. CHEREMSHANTSEV
2. Q is a
part
ofplane
in1R3.
The fact toverify
is whether a functionbelongs
toL2, loe (1R4).
One caneasily
show that N has alogarithmic singularity
at s = t, hence the condition A2 is satisfied.3. Q is a
sphere
in1R3.
Our results can beapplied
to construct hamilton-ians with zero-range interactions which are not
spherically symmetric.
4. Q is a Brownian
path
in1R2
or1R3.
LetX==[0, 1], ~ (t)
be a Brownianpath.
For m = 2 we have to show thatLet Wien be a Wiener measure on
C([0, 1];
One caneasily
show(see [8])
thatfor Õ 1.
Hence, (29)
is satisfied for a. e.(o(.)eC([0, 1];
Let m = 3. To
verify
conditionA2,
it is sufficient to show thatwhere
t) _ ~ ~ (s) - ~ (t) I.
We shall demonstrate that(30)
holds for all~~3.
One should consider allpossible orderings
ofpoints s, t,
u, v. Wemay assume that s t and u v since
points s, t and u, v
areequivalent.
There are 6 cases:
1.
stuv, 2. uvst, 3. sutv, 4. usvt, 5. suvt,
6.
The cases 1 and
2,
3 and4,
5 and 6 are similar(we
have to do asubstitution ~-~M,
/-~). Finally
we have 3essentially
different cases:1,
3 and 5. Denote
by 11, 13, Is corresponding
contributions in I.Case 1:
Annales de l’Institut Henri Poincaré - Physique theorique "
where
P = [0, 1 ] 4,
Cm
is some constant.Obviously,
Consequently,
Let us
change
the variables in(31):
M=~2014~, v = x3 - x2, Thenwhere
Obviously,
The
integral
14 S. E. CHEREMSHANTSEV can be
easily
estimated:It follows from
(33)-(35)
thatFrom
(32)
and(36)
weget
C’ase 3. - In an
analogous
manner we have to estimate theintegral
Case 5:
We have
just proved
that 3for a. e.
o(.)eC([0, 1];
Therefore we haveconstructed corresponding
semibounded self-adjoint
hamiltonians in andL2 ([R3).
This canAnnales de l’Institut Henri Poincaré - Physique theorique
be considered as a standard
proof
ofcorresponding
statements in[8]
for~~3,
obtained thereby
means of nonstandardanalysis.
2. HAMILTONIANS OBTAINED BY A RENORMALIZATION PROCEDURE
The considerations of the
part
1 show that in certain cases the construc- tionprocedure
without renormalisation fails. If~~4
then the kernelsBn (s, t, z)
have notpointwise
limit as n oo . If m = 2 and D is discreteor m = 3 and Q is discrete or a smooth curve,
operators Bn (z)
have not abounded limit as n oo.
Hence,
we need anotherprocedure.
It is wellknown in the case where S2 consists of one or several
separated points
inm = 2,
3. Thecorresponding
method was elaborated in[9], [7].
Whatwe shall
give
below for m =3, 4,
5 is a continuous version of it.The main idea is
again
to construct a sequence ofoperators Hn given by
where
%(~)==(/, en (t)), ~rn (t) _ (g, en (t)).
The difference frompart
1 is thatFn
should be now someoperators
inL2 (X) depending ( . ).
Assume that
Fn
are boundedself-adjoint operators
inL2 (X).
One cansee that
Hn
areself-adjoint
inL2 ([Rm)
with the same domain(3). By
thesame consideration as in the
part
1 weget
and
where
fn = (Hn - z) -1 g,
03C1n, an andLn
aregiven by
the sameformulae. We shall assume for a while that
Assume that
operators Fn
have bounded inverses. Thenwhere
hn
=Fn
pn. As wejust
havementioned,
theoperators Ln (z)
may havenot bounded limits as n -~ oo . Therefore we should
separate
the mostsingular part
inLn (z)
as n --+ oo :16 S. E. CHEREMSHANTSEV
Then we shall choose 1 such that
Lning
becompensated.
Letwhere A is some bounded
self-adjoint operator
inL2 (X)
which has abounded inverse. From
(40)-(41 )
weget formally
If converge in the
operator
norm to someoperators Lreg (z)
asn ~ oo and
(A + Lreg (z)) -1 exist, then hn and fn
have limits as n ~ oo .Let us elaborate this
strategy
in detail. Webegin by writing z)
in the form
where z E
CB[0,
+oo);
m =3, 4, 5; ~
= A(s, t) =
co(~) - co (t) I.
We need thatoperators
in theright-hand
side of(41 )
be invertible. Fix theoperator
A and consider afamily
ofoperators
The
operators Lning
arecompact self-adjoint
inL2 (X)
for all n,hence, A -1 1 L~ing
are alsocompact.
LetEn
be thespectrum
ofA -1
this is acountable set. Hence
E = U En
is also countable. For all then
inverse
operators Dn 1 (À)
exist for all n. We shall choose and calculate thestrong
limit ofRn (z).
Then one can take another limit as~1, ~E.
Thus,
exist for all n and are boundedself-adjoint operators
inL2 (X).
Let usstudy
the behaviour of the kernelsz)
as n oo .
If m =
3,
then for all s, t EX,
z ECB[0,
+oo )
The estimate holds
where C
(z)
does notdepend
on s, t, n.If m = 4 then for
0 (s,
Annales de l’Institut Henri Poincaré - Physique theorique
The uniform estimate holds:
If m = 5 then
for 0394>0
Hence,
It follows from
(47)
thatwhere C
(z)
does notdepend
on s, t, n.Assume that for m = 4 the map (0 satisfies to the condition A 1 of
part
1 and for m = 5 (0 satisfies to A2. As to the case m =3,
we shall not assumeanything
about (0except
ofmeasurability.
Let
Lregn (z),
Lreg(z)
beintegral operators
with the kernelsLregn (s,
t,z),
Lreg
(S,
t,Z);
Z EC"’[O,
+ex)).
LEMMA 9. - The
following
statements hold:1.
Lregn (z)
are Hilbert-Schmidt operators inL2 (X) for
all n.2.
Lregn (z)
converge in the operator norm inL2 (X)
to Lreg(z)
as n ~ ex).3. Lreg
(z)
are compact inL2 (X).
4. Lreg
(z)
is ananalytic operator-valued function
onC"’[O,
+ex)).
The
proof
is identical to that in lemma 1.LEMMA 10. - For all z:
Im z~0
the inverse operators(A + Lreg (z)) -1
exist.
Proof -
Theoperator
A isinvertible,
hencewhere
by
lemma 9 theoperator A -1 Lreg (z)
iscompact.
Therefore it is sufficient to show that theequation
has no nonzero solutions in
L2 (X).
From(50)
weget
18 S. E. CHEREMSHANTSEV
The
proof
of lemma 2implies
thatwhere
f(p) = (2n)-m/2
d~, (t) . f (t) exp ( - i (p, c~ (t))).
From(51 )-(53)
we~et
’
where the
integral
over M"" converges. Since(54) implies /(/?)==0
a. e.
By (52)-(53)
we haveLreg (z) f= 0, hence/=0.
Theproof
iscompleted.
Remark. - It follows from the
proof
thatL~ing ~ 0
and~>0.
Thus
the
inverseoperators (~, A + Lreg (z)) -1 exist
for all z:~e~.
By
the statement 2 of lemma9,
theoperators (ÀA+L~eg(z))-1
existfor n > N
(z)
and the resolventsRn (z)
aregiven by
Define
where ~
=(Â
A +(z)) ’ ~
~~(z), ~
E S(~~).
It is obvious thatwhere
The
operators
converge to henceAnnales de l’Institut Henri Poincaré - Physique théorique "
where
h = (~, ~. + Lreg (zj) - ~ a ~z).
it follows from(56),
inparticular,
thatuniformly
on Let us show thatConsider the
following integrals,
where~~:
Let us estimate the
integrals
It is obvious that for m =
3,
4where õ=O for
/~=3,
081 for~=4,
does notdepend
on~ A
andthen
where
It is easy to show
that
where y
(z)
does notdepend
on~, d
and20 S. E. CHEREMSHANTSEV
Now we can
estimate
the norm of vn inL2 (f~m).
From( 58 - ) ( 59 )
weget
form = 3,
4If m = 3
than 8
= 0 and from(57)
weget
as n~~. If m=4, 1- is bounded then by condition
inL2 (X), hence
A 1 theby (58), (59) operator
and with the(64)
wekernel get
~
vn~
~ O.Let us consider the case m=5.
By (58), (62)
andcondition
A2where J2 is a corresponding contribution
in J. As toJ1,
it can be writtenas
follows:
~)
be the operator with thekernel
be the operator with
thekernel 0394-1(03C0/2-Si(n0394)). By
conditionA2 and UM
the
dominated
convergencetheorem
From
(65)-(67)
weget
where
J~)=a,,(U(~,
Itfollows from (65), (57), (68)
and(69)
thatTo
calculate
thestrong limit
ofresolvents
weshould
consider now thefollowing
sequence inL~ (tR"’):
Annales de l’Institut Henri Poincare - Physique . theorique
It follows from considerations we have made above that
Qn
EL2 (!Rm)
forall n. Define
As we made it for
II vn~2,
we writeand it can be shown that
where U is an
operator
with the kernelOne can show from
(59)-(62)
that U is a boundedoperator
inL2 (X).
Hence from
(56)
and(70)
we havein
particular, Q
EL2 ((~m)_
We have
just
shown that for all z: the sequenceRn (z) g
converge inL2
as n oo andwhere
in
space-representation.
Theoperators Rn (z)
are resolvents ofself-adjoint operators
inL2
hence for all nTherefore
Rn (z) g
converge inL2
for all g EL2
andHowever the formula for
a (z)
holds for any gonly
for m = 3.22 S. E. CHEREMSHANTSEV
Let us show that
Ran T (z)
is dense - inSuppose
thatT
(z) g)
= 0 forall g
, E S EC~
inspace-representation
define "
By (71)
weget
since
Hence
for
all , f’E Co
This set is dense inL2 (Rm),
so cp = o.We have
proved
thefollowing
result.THEOREM 2. - Let m =
3,
4 or 5 and 03C9satisfies
to condition Alfor
m = 4 and to A2
for
m = 5. Assume that A is a bounded invertibleself adjoint
operator inL2 (X).
Then there exists a countable set E E f~ such thatfor
all ÀE the operatorsFn = (~, A -
exist.If
ÀEthen the
self-adjoint
operatorsHn given by (37),
converge in the strong resolvent sense to someself-adjoint
operator H. Its resolvent isgiven by (71 ) for
all z: Im z ~0,
g E S([Rm).
One can consider now the limit of
(71 )
as À ~ 1.Applying again
theTrotter-Kato theorem we
get
that theright-hand
size of(71)
is for À= 1 also a resolvent of someself-adjoint operator
inL2
Therefore wecan
put
~, = 1.We may
study
now someproperties
of H. The fact that H is a selfadjoint
extension ofHo
= - 0 with the domainC0~(RmB03A9
can beproved by
the same way as in lemma 3.LEMMA 11. - Assume that
(A
cp,cp)
= 0iff
cp = 0. Then H is nontrivial.Proof - Suppose
that H is trivial. Then for all z: Im z ~0,
g E Swhere
g taken in
space-represantation.
Let03C6=(A+Lreg(z))-103C1.
From(72)
we
get
Annales de ’ l’Institut Henri Poincaré - Physique " théorique ’
for all z: 1m
z#O.
From(73)
and(52)-(54)
we havehence, (cp,
A(p)
=0,
andby
condition of lemma (p = 0" ThereforeThis is not true all The contradiction proves the lemma.
The condition of lemma is
satisfied,
inparticular,
if A > 0 or A0.The
locality
of H(see
lemma8)
followsagain from [1].
The
semiboundedness
of H is a difficultproblem.
The reason is thatoperators
may have not a bounded limit as a --~ oo . Let usdiscuss this
question
in detail.By
lemma9,
lemma 10 andanalytical
Fredholm theorem
[11] ]
theoperator-valued
function(A + Lf ~~ (z)) -1
ismeromorphic
onCB[0,
+(0)
and isanalytic
on + where Sis a discrete set on
(-00, 0), having
aspossible
accumulationpoints
0and - oo .
LEMMA 12. - Let
ze(-
oo,0)BS.
Then zbelongs to
resolveut set This result followsdirectly
from(71 ).
LEMMA 13. - Assume that
(A(p, (p)~-~((p,
allThen aud it has no
negative
This result follows from lemma 12 and the remark to lemma 10.
Applications
1. Q is a
single point
in~3.
One can~(0)==1, co(0)=~6tR~.
In such case theoperator Fn
is in fact a real number(A201447c~)*B
This renormalization scheme has been considered in[9].
2. Q is a finite set in
1R3.
In this case our consideration is similar to[7].
One can
2,
...,N},
for Weassume that
yj~y1 for j~
1. Theoperator
A is a matrix such that theoperator F,~ 1 also being
a matrix:where ’
’ ’ ’ ’ in o ’ ’ sin R~(R0394)
, ii=k,
h |yi-
Yk I.
It is clear
that for i i= k there ’ exist finite limits
Therefore one can choose A such that
operators F"
beasymptotically
diagonal
oo . Let24 S. E. CHEREMSHANTSEV
Then
as n ~ oo . In this concrete case we could take
diagonal
for all n,(Ln(z))ik having
finite limits for Theoperators Fn
1 andFn
would bediagonal
for all n.However,
if Q is not a discrete set, we cannot do it and we should consider theasymptotic diagonality
ofFn.
Let us
explain
theimportance
ofdiagonality
ofFn.
As it has beenmentioned in
[ 1 ],
it can beinterpreted
asindependence
of zero-range interactions in differentpoints.
One can see it from the definition ofHn.
It seems
quite
natural that the condition ofindependence
should besatisfied,
at leastasymptotically
as n ~ oo . In[1] ]
it makes itpossible
tochoose the
N-parameter family
ofself-adjoint extensions,
the wholefamily
of extensions
being N2-parameter.
In the
part
1 this condition isobviously
satisfied since F is a function.Certainly,
one couldapply
the renormalizationprocedure
to the caseconsidered in the
part
1.However,
theoperators having
a boundedlimit
Lsing
as n ~ oo, the renormalization isequivalent
to the consideration of hamiltonians(2),
where F is a boundedself-adjoint operator
inL2 (X), Only
for where F isdiagonal,
we haveself-adjoint
extensions Hinteresting
fromphysical point
of view. Other extensions are less attractive.The situation where renormalization is
really
necessary occurs whenoperators (I
+Ln (z) F) -1
1 have not nonzero bounded limits as n oo . In this caseLsingn
have not boundedlimit,
and the mainproblem
is to chooseoperators
A such that beasymptotically diagonal.
3. Q is a Brownian
path
in1R4
orf~ 5 .
The conditions Al
(for m = 4)
or A2(for m = 5)
aresatisfied,
as wehave
proved
in thepart
1. Therefore for a. e. co we haveself-adjoint operators
withexpected properties,
whose resolvents on a dense set aregiven by (71 ). IfA~2014~1,
where~>0,
then theseoperators
are nontrivialby
lemma 11 andnonnegative (hence, semibounded) by
lemma 13. SinceL~ing ~ 0
and mostprobably
have not a boundedlimit,
we canexpect
that in some senseFn
are"negative
infinitesimal"operators.
This is in agree- ment withcorresponding
results of[8]
for~2=4, 5,
obtained thereby
nonstandard methods.
The
question
we cannot answer atpresent
is for what Aoperators Fn
are
asymptotically diagonal.
ACKNOWLEDGEMENTS
I wish to thank Dr. J. F. Brasche who
put
my attention to thisproblem.
I am very
grateful
to K. A. Makarov forstimulating
discussions.Annales de l’Institut Henri Poincaré - Physique theorique
[1] S. ALBEVERIO, F. GESZTESY, R. HOEGH-KROHN and H. HOLDEN, Solvable Models in Quantum Mechanics. Springer-Verlag, New York, 1988.
[2] B. S. PAVLOV, Boundary Conditions on Thin Manifolds and the Boundedness from Below of Three-Body Schroedinger Operator Wirh Pointwise Potential, Mat. Sbornik (in russian), Vol. 136 (178), No. 2 (6), 1988, pp. 163-177.
[3] A. S. BLAGOVESTCHENSKI and K. K. LAVRENTIEV, The Three-Dimensional Laplace Operator with the Boundary Condition on a line, Vestnik L.G.U. (in russian), No. 1,
1977, pp. 9-15.
[4] V. I. SLOBODIN, Boundary Problems for Elliptic Operators with Boundary Conditions
on Smooth Manifolds of Arbitrary Dimension, Vestnik L.G. U. (in russian), No. 4, 1988, pp. 100-102.
[5] J.-P. ANTOINE, F. GESZTESY and J. SHABANI, Exactly Solvable Models of Sphere
Interactions in Quantum Mechanics, J. Phys., Vol. A 20, 1987, pp. 3687-3712.
[6] A. N. KOCHUBEI, Elliptic Operators with Boundary Conditions on a Subset of Measure
Zero, Funct. Anal. Appl., Vol. 16, 1982, pp. 137-139.
[7] A. GROSSMANN, R. HOEGH-KROHN and M. MEBKHOUT, A Class of Explicitly Soluble, Many-Center Hamiltonians for One-Particle Quantum Mechanics in Two and Three Dimensions I., J. Math. Phys., Vol. 21, 1980, pp. 2376-2385.
[8] S. ALBEVERIO, S. FENSTAD, R. HOEGH-KROHN and T. LINDSTROM, Nonstandard Methods in Stochastic Analysis and Mathematical Physics, Academic Press, New York-San Francisco-London, 1986.
[9] F. A. BEREZIN and L. D. FADDEEV, A Remark on Schroedinger’s Equation with a Singular Potential, Soviet. Math. Dokl., Vol. 2, 1961, pp. 372-375.
[10] N. I. AKHIEZER and I. M. GLAZMAN, Theory of Linear Operators in Hilbert Space, Vol. 2. Pitman, Boston-London-Melbourne, 1981.
[11] M. REED and B. SIMON, Methods of Modern Mathematical Physics, Vol. 1, Academic Press, New York-London, 1972.
( Manuscript received June 8, 1990.)