A NNALES DE LA FACULTÉ DES SCIENCES DE T OULOUSE
A NDRZEJ J. M ACIEJEWSKI M ARIA P RZYBYLSKA
Differential Galois approach to the non-integrability of the heavy top problem
Annales de la faculté des sciences de Toulouse 6
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123
Differential Galois approach
tothe non-integrability
of the heavy top problem
ANDRZEJ J.
MACIEJEWSKI(1),
MARIAPRZYBYLSKA(2,3)
ABSTRACT. - We study integrability of the Euler-Poisson equations de- scribing the motion of a rigid body with one fixed point in a constant gravity field. Using the Morales-Ramis theory and tools of differential algebra we prove that a symmetric heavy top is integrable only in the
classical cases of Euler, Lagrange, and Kovalevskaya and is partially inte- grable only in the Goryachev-Chaplygin case. Our proof is alternative to that given by Ziglin
(Functional
Anal. Appl.,17(1):6-17,
1983; FunctionalAnal. Appl.,
31(1):3-9, 1997).
RÉSUMÉ. - Nous étudions l’intégrabilité des équations de Euler-Poisson
qui décrivent le mouvement d’un solide rigide avec un point fixe dans
un champ gravitationnel constant. En utilisant la théorie de Morales- Ramis et des outils d’algèbre différentielle, nous prouvons qu’un solide symétrique est intégrable seulement dans les cas classiques d’Euler, La-
grange et Kowalevski, et est partiellement intégrable seulement dans le cas
Goryatchev-Tchaplygin. Notre preuve est une alternative à celle donnée par Ziglin
(Functional
Anal. Appl.,17(1):6-17,
1983; Functional Anal.Appl.,
31(1):3-9, 1997).
Annales de la Faculté des Sciences de Toulouse Vol. XIV, n° 1, 2005
(*) Reçu le 2 octobre 2003, accepté le 29 avril 2004
(1) Institute of Astronomy, University of Zielona Gora, Podgorna 50, PL-65-246 Zielona Góra, Poland.
E-mail: maciejka@astro.ia.uz.zgora.pl
(2) INRIA Projet CAFÉ, 2004, Route des Lucioles, B.P. 93, 06902 Sophia Antipolis Cedex, France.
(3) Torun Centre for Astronomy, Nicholaus Copernicus University, Gagarina 11, PL- 87-100 Torun, Poland.
1.
Equations
of motion and motivationEquations
of motion of arigid body
in external fields areusually
writtenin a
body
fixed frame.Here,
we use thefollowing
convention. For a vectorv we denote
by
V ==[V1, V2, V3]T
its coordinates in abody
fixedframe,
andwe consider it as a one column matrix. The vector and scalar
products
oftwo vectors v and w
expressed
in terms of thebody
fixed coordinates aredenoted
by [V,W]
and(V,W), respectively.
We consider a
rigid body
of mass m located in a constantgravity
field ofintensity
g. Onepoint
of thebody
is fixed. The distance between the fixedpoint
and the mass centre of thebody
is D.Assuming
thatgD =f- 0,
wechoose units in such a way
that y := mgD
=1. The
Euler-Poissonequations
describe the rotational motion of the
body.
In the aboveequations
M de-notes the
angular
momentum of thebody,
N is the unit vector in the di-rection of the
gravity field,
and L is the unit vector from the centre of massof the
body
to the fixedpoint;
J is the inverse of the matrix ofinertia,
so03A9 := JM is the
angular velocity
of thebody.
Theprincipal
moments ofinertia
A, B,
and C areeigenvalues
ofJ-1.
For our further consideration it isimportant
to notice that in(1.1)
thebody
fixed frame isunspecified,
sowe can choose it
according
to our needs. Abody
fixed frame in which J isdiagonal
is called theprincipal
axes frame. This frame isuniquely
defined(up
to thenumbering
of theaxes)
when J has nomultiple eigenvalues.
If Jhas a
multiple eigenvalue,
e.g. when A =B,
we say that thebody
is sym- metric. Then theprincipal
axes frame is defined up to a rotation around thesymmetry
axis.System (1.1) depends
onparameters A, B, C,
and L butphysical
con-straints restrict the allowable values of
parameters
to a set ’P CR6
definedby
thefollowing
conditionsEuler-Poisson
equations
possess three firstintegrals
It is known that on the level
the Euler-Poisson
equations
are the Hamiltonian ones, see e.g.[1, 36, 2]
Remark 1.1. -
Configuration
space of arigid body
with a fixedpoint
is the Lie group
SO(3, M) (all possible
orientations of thebody
withrespect
to an inertial
frame). Thus, classically,
thephase
space for theproblem
isT* SO (3, R).
Hence it is a Hamiltoniansystem
with threedegrees
of freedomand it possesses one additional first
integral Hl (first integral H2
is identi-cally equal
to one in thisformulation).
The existence of this firstintegral
is related to the
symmetry
of theproblem (rotations
around the direction of thegravity field)
and this allows to reduce thesystem by
onedegree
of freedom. The Euler-Poisson
equations
can be viewed as an effect of re-duction of the
system
onT*SO(3, R)
withrespect
to thissymmetry.
Thephase
space of the reducedproblem
can be considered as thedual g*
to Liealgebra g
of group ofrigid
motions G ==R3 SO(3, R).
Here x denotes the semi-directproduct
of Lie groups. We canidentify (N, M)
as element ofg* = R3* so(3, R)* using
standardisomorphisms
betweenso(3, R)
andR3,
and between
R3*
andIR3.
Let(X, A)
EG,
with X ER3
and A ESO(3, R).
Then the
coadjoint
actionAd*(X,A) : g*
---+g*
is definedby
Functions
Hl
andH2 given by (1.3)
are orbitsinvariant, i.e.,
on each orbitof
coadjoint
actionthey
have constant values.They
are called Casimirs. Orbits ofcoadjoint
ac-tion defined above coincide with
Mx
which isdiffeomorphic
toTS 2.
As it iswell
known,
orbits of acoadjoint
action aresymplectic
manifoldsequipped
with the standard Kostant-Berezin-Souriau-Kirillov
symplectic
structure[18, 44].
On four dimensional orbitsMx
the Euler-Poissonequations
areHamiltonian with H
given by (1.2)
as the Hamilton function.Thus,
as a Hamiltoniansystem
onMx
the Euler-Poissonequations
havetwo
degrees
of freedom and areintegrable
onMx
if there exists an addi- tional firstintegral H3
which isfunctionally independent
with H onM..
Equivalently,
we say that the Euler-Poissonequations
areintegrable
if thereexists a first
integral H3
which isfunctionally independent together
withH, Hl
andH2.
We say that the Euler-Poisson
equations
arepartially integrable
ifthey
are
integrable
onMo.
The known
integrable
cases are thefollowing:
1. The Euler case
(1758) corresponds
to the situation when there is nogravity (i.e. when J1
=0)
or L == 0(the
fixedpoint
of thebody
is thecentre of
mass).
The additional firstintegral
in this case is the totalangular
momentumH3 = (M, M).
2. In the
Lagrange
case[26]
thebody
issymmetric (i.e.
two of itsprin- cipal
moments of inertial areequal)
and the fixedpoint
lies on thesymmetry
axis. The additional firstintegral
in this case is theprojec-
tion of the
angular
momentum onto thesymmetry
axis. If we assume that A= B,
then in theLagrange
caseLI
=L2 = 0,
andH3 = M3.
3. In the
Kovalevskaya
case[20, 21]
thebody
issymmetric
and theprincipal
moment of inertiaalong
thesymmetry
axis is half of theprincipal
moment of inertia withrespect
to an axisperpendicular
tothe
symmetry
axis.Moreover,
the fixedpoint
lies in theprincipal plane perpendicular
to thesymmetry
axis. If A = B -2C,
then(after
anappropriate
rotation around thesymmetry axis)
we have inthe
Kovalevskaya
caseL2 = L3 = 0.
The additional firstintegral
hasthe form
4. In the
Goryachev-Chaplygin
case[15]
thebody
issymmetric and,
asin the
Kovalevskaya
case, the fixedpoint
lies in theprincipal plane perpendicular
to thesymmetry
axis. If we assume that the thirdprincipal
axis is thesymmetry axis,
then in theGoryachev-Chaplygin
case we have A = B = 4C and
L2
=L3
= 0. In theGoryachev- Chaplygin
caseequations (1.1)
areintegrable only
on the levelHl
= 0 and the additional firstintegral
has thefollowing
form:For a
long
time thequestion
if there are otherintegrable
cases of theEuler-Poisson
equations except
those enumerated above was open,although
many
leading
mathematicians tried togive
apositive
answer to it.The
problem
wascompletely
solvedby
S.L.Ziglin
in a brilliant way.First,
in[49]
heproved
thefollowing.
THEOREM
1.2 (ZIGLIN, 1980).
-If (A - B)(B - C)(C - A) ~ 0,
thenthe Euler-Poisson
system
does not admit a realmeromorphic first integral
which is
functionally independent together
withH, Hl
andH2.
Later,
hedeveloped
in[50]
anelegant method,
which now is called theZiglin theory,
andusing
it heproved
in[51]
thefollowing
theorem.THEOREM 1.3
(ZIGLIN, 1983).
- Thecomplexified
Euler-Poisson sys- temfor
asymmetric body
isintegrable
onMo
withcomplex meromorphic first integrals only
in thefour
classical cases.This result was
improved
in[52].
THEOREM 1.4
(ZIGLIN, 1997). -
The Euler-Poissonsystem for a
sym- metricbody
isintegrable
onMo
with realmeromorphic first integrals only
in the
four
classical cases.We know that in the
Euler, Lagrange
andKovalevskaya
cases the Euler-Poisson
system
isintegrable globally,
i.e. the additional firstintegral
existson an
arbitrary symplectic
manifoldMx.
In theGoryachev-Chaplygin
casethe Euler-Poisson
equations
areintegrable only
onMo,
and this fact wasalso
proved by Ziglin.
Remark 1.5. - We do not even
try
to sketch the very richhistory
ofinvestigations
of theproblem
of theheavy top.
We refer here to books[14, 27, 23, 8]
and references therein.However,
several works where the ques- tion ofintegrability
of theproblem
wasinvestigated
are worthmentioning.
In
[22]
it was shown that for anon-symmetric body
the Euler-Poisson equa- tions do not admit an additional realanalytic
firstintegral
whichdepends analytically
on a smallparameter
u, see also[23,
Ch.III].
For asymmet-
ric
body
when the ratio of theprincipal
moments is smallenough (i.e.
forthe case of the
perturbed spherical pendulum)
the non-existence of an ad- ditional realanalytic
firstintegral
wasproved
in[24, 25].
A similar result for aperturbed Lagrange
case was shown in[12, 6].
Anovel,
variationalapproach
forproving
thenon-integrability
was elaboratedby
S. V. Bolotin in[7]
where he showed the non-existence of an additional realanalytic
firstintegral
for asymmetric heavy top
for the case when the fixedpoint
lies inthe
equatorial
and the ratio of theprincipal
moments of inertia isgreater
than 4.The
Ziglin theory
is a continuation of the idea of S. N.Kovalevskaya
who related the
(non)integrability
with the behaviour of solutions of theinvestigated system
as functions of thecomplex
time. The mainobject
inthe
Ziglin theory
is themonodromy
group of variationalequations
arounda
particular non-equilibrium
solution. As it was shownby Ziglin,
if the in-vestigated system
possesses ameromorphic
firstintegral,
themonodromy
group of variational
equations
possesses a rational invariant.Thus,
for anintegrable system,
themonodromy
group cannot be too ’rich’. The maindifficulty
inapplication
of theZiglin theory
is connected with the fact that’except for
afew differential equations,
e.g., the Riemannequations,
Jordan-Pochhammer
equations
andgeneralised hypergeometric equations,
the mon-odromy
group has not beendetermined’, [45],
p. 85. For other second order differentialequations only partial
results areknown,
see e.g.[3, 9]. Having
this in
mind,
one can notice that theanalysis
of the variationalequations
and détermination of
properties
of theirmonodromy
groupgiven by Ziglin
in his
proof
of Theorem 1.3 is amasterpiece. Later,
theZiglin theory
wasdeveloped
andapplied
for astudy
ofnon-integrability
of varioussystems but,
as far as weknow, nobody
usedZiglin’s
brillianttechnique developed
in his
proof
of Theorem 1.3.In the nineties the
theory
ofZiglin
was extendedby
a differential Ga- loisapproach.
It was doneindependently by
C.Simó,
J. J.Morales-Ruiz,
J.-P. Ramis
[37, 38, 39, 40]
and A.Braider,
R. C.Churchill,
D. L. Rod and M. F.Singer [10, 4]. Nowadays,
thisapproach
is called the Morales-Ramistheory.
Thekey point
in thistheory
is toreplace
aninvestigation
of themonodromy
group of variationalequations by
astudy
of their differential Galois group. The main fact from thistheory
is similar to that ofZiglin:
theexistence of a
meromorphic
firstintegral implies
the existence of a rational invariant of the differential Galois group of variationalequations. Forget- ting
about differences inhypotheses
in main theorems of boththeories,
thebiggest advantage
of the Morales-Ramistheory
is connected with the fact thatapplying it,
we have at ourdisposal developed
tools andalgorithms
ofdifferential
algebra.
Thanks to thisfact,
it can beapplied
moreeasily.
We
applied
the Morales-Ramistheory
tostudy
theintegrability
of sev-eral
systems,
see e.g.[28, 29, 32, 30, 31, 34, 33],
and we notice thatobtaining
similar results
working only
with themonodromy
group isquestionable,
or, at least difficult. Thisgives
us an idea toreanalyse
theZiglin proof
of Theo-rem 1.3 which is rather
long (about
10 pages in[51]).
We wanted topresent
a new, much shorter and
simpler proof
which is based on the Morales-Ramistheory
and tools from differentialalgebra.
Infact,
at thebeginning,
we be-lieved that
giving
suchproof
would be a nice andsimple
exercise butquickly
it
appeared
that we were wrong. A ’naive’application
of the Morales-Ramistheory
leadsquickly
to very tedious calculations or unsolvablecomplica-
tions. As our aim was to
give
an’elementary’ proof,
weput
a constrainon the
arguments
which are allowable in it: nocomputer algebra.
Thus wespent
a lot of timeanalysing
sources of difficulties andcomplications,
andthe aim of this paper is to
present
our own version ofproofs
of Theorem 1.3 and Theorem 1.4. As webelieve,
theseproofs present
the whole power andbeauty
of the Morales-Ramistheory.
The
plan
of this paper isfollowing.
To make it self-contained in the next section weshortly
describe basic facts from the Morales-Ramis andZiglin
theory.
We collected morespecific
results aboutspecial
linear differentialequations
inAppendix.
In Section 3 we derive the normal variational equa- tion. Sections 4 and 5 contain ourproofs
of Theorem 1.3 and 1.4. In the last section wegive
several remarks and comments.2.
Theory
Below we
only
mention basic notions and factsconcerning
theZiglin
andMorales-Ramis
theory following [50, 4, 38].
Let us consider a
system
of differentialequations
defined on a
complex
n-dimensional manifold M. Ifcp(t)
is anon-equilibrium
solution of
(2.1),
then the maximalanalytic
continuation of~(t)
defines aRiemann surface r with t as a local coordinate.
Together
withsystem (2.1)
we can also consider variational
equations (VEs)
restricted toTrM,
i.e.We can
always
reduce the order of thissystem by
oneconsidering
the in-duced
system
on the normal bundle N : -Tr M/T r
of r[50]
Hère vr :
T0393M ~
N is theprojection.
Thesystem
of s = n -1equations
ob-tained in this way
yields
the so-called normal variationalequations (NVEs).
The
monodromy
group M ofsystem (2.2)
is theimage
of the fundamental group Tri(F, to )
of r obtained in the process of continuation of local solutions of(2.2)
defined in aneighbourhood
ofto along
closedpaths
with the basepoint to. By definition,
it is obvious that M CGL(s, C).
A non-constant rational functionf (z)
of s variables z =(zl, ... , zs)
is called anintegral (or invariant)
of themonodromy
group iff(g· z)
=f(z)
forall g
E M.From the
Ziglin theory
we need the basic lemma formulated in[50]
andthen
given
in animproved
form in[52].
LEMMA 2.1. -
If system (2.1)
possesses ameromorphic first integral defined
in aneighbourhood
Uc M,
such that thefundamental
groupof
r isgenerated by loops lying in U,
then themonodromy
group Mof
the normalvariational
equations
has a rationalfirst integral.
If
system (2.1)
isHamiltonian,
thennecessarily
n = 2m and M is a sym-plectic
manifoldequipped
with asymplectic
form w. Theright
hand sidesv == VH of
(2.1)
aregenerated by
asingle
function H called the Hamiltonian of thesystem.
Forgiven
H vector field vH is definedby w( v H, u) =
dH - u,where u is an
arbitrary
vector field on M.Then,
of course, H is a first in-tegral
of thesystem.
For agiven particular
solution~(t)
we fix the energylevel E =
H(~(t)). Restricting (2.1)
to thislevel,
we obtain a well definedsystem
on an(n - 1)
dimensional manifold with a knownparticular
solution~(t).
For this restrictedsystem
weperform
the reduction of order of varia- tionalequations. Thus,
the normal variationalequations
for a Hamiltoniansystem
with mdegrees
of freedom have dimension s -2(m - 1)
and theirmonodromy
group is asubgroup
ofSp(s, C).
In the Morales-Ramis
theory
the differential Galoisgroup 9
of normalvariational
equations plays
the fundamentalrole,
see[38, 39].
For aprecise
definition of the differential Galois group and
general
facts from differentialalgebra
see[16, 41, 5, 35, 47].
We canconsider 9
as asubgroup
ofGL(s, C)
which acts on fundamental solutions of
(2.2)
and does notchange polyno-
mial relations among them. In
particular,
this group maps one fundamental solution to other fundamental solutions.Moreover,
it can be shown that Mc 9 and 9
is analgebraic subgroup
ofGL (s, C). Thus,
it is a unionof
disjoint
connectedcomponents.
One of themcontaining
theidentity
iscalled the
identity component of 9
and is denotedby go.
Morales-Ruiz and Ramis formulated a new criterion of
non-integrability
for Hamiltonian
systems
in terms of theproperties
ofg0 [38, 39].
THEOREM 2.2. - Assume that a Hamiltonian
system
ismeromorphi- cally integrable
in the Liouville sense in aneigbourhood of
theanalytic
curver. Then the
identity component of the differential
Galois groupof
NVEs as-sociated with 0393 is Abelian.
In most
applications
the Riemann surface r associated with thepartic-
ular solution is open. There are many reasons
why
it is better to work withcompact
Riemann surfaces. Because ofthis,
it iscustomary
tocompactify
radding
to it a finite number ofpoints
atinfinity. Doing
this we need a refinedversion of Theorem
2.2,
for details see[38, 39]. However,
in the context ofthis paper, the thesis of the above theorem remains
unchanged
if instead of r and the variationalequations
over r we work with itscompactification.
3. Particular solutions and variational
equations
To
apply
theZiglin
or the Morales-Ramistheory
we have to know anon-equilibrium
solution. Let us assume that the fixedpoint
is located ina
principal plane. Then,
infact,
we can find a one parameterfamily
ofparticular
solutions which describe apendulum
like motion of thebody.
Fora
symmetric body
thisassumption
is not restrictive(if
necessary we canrotate the
principal
axes around thesymmetry axis).
We choose the
body
fixed frame in thefollowing
way. Its first two axeslie in the
principal plane
where the fixedpoint
is located and the first axis has direction from the fixedpoint
to the centre of mass of thebody.
We callthis frame
special.
A mapgiven by
transforms
equations (1.1)
to the formwhere
Now,
ifsymbols
with tildecorrespond
to theprincipal
axesframe, then, taking
into account ourassumption
about the location of the fixedpoint,
we have
Taking
weobtain
where
Thus,
theprescribed
choice of Rcorresponds
to the transformation from thespecial
to theprincipal
frame. Without loss ofgenerality
we canput
b = 1. For asymmetric body we
assume that A= B ~
C. Under thisassumption,
if d =0,
then13 = 0, and,
in this case, thespecial
framecoincides with the
principal
frame.From now on we consider the
complexified
Euler-Poissonsystem,
i.e. weassume that
(M, N)
EC6.
3.1. Case
d ~ 0
It is easy to check that manifold
is
symplectic
sub-manifold ofMo diffeomorphic
to TS1C
C TS2 (by SmC
wEdenote m-dimensional
complex sphère). Moreover, N
is invariant with re-spect
to the flowgenerated by (1.1).
The Euler-Poissonequations
restrictecto
JU
have thefollowing
formand are Hamiltonian with
HIN
as the Hamiltonian function. For each level of HamiltonianHIN ==
e :=2k2 -l,
we obtain aphase
curve0393k.
We restrictour attention to curves
corresponding
to e E(-1,1]
so that k E(0, 1].
Asolution of
system (3.2) lying
on the levelHIN == 2k 2 -
1 we denoteby (M2(t, k), N1(t, k), N3(t, k)).
For a
generic
value of kphase
curveFk
is analgebraic
curve inC3{M2,N1,N3} and,
as intersection of twoquadrics
is an
elliptic
curve(for
k = 1 it is a rationalcurve).
We cancompactify
it
adding
twopoints
atinfinity
which lie in directions(0, ±i, 1). Thus,
ageneric 0393k
can be considered as a torus with twopoints
removed. In ourfurther consideration we work with
subfamily rk
with k E(0, 1). Only
inSection 5 we refer to the
phase
curveFi corresponding
to k = 1.Equations (3.2)
describe thependulum-like
motions of thebody:
thesymmetry
axis of thebody
remainspermanently
in oneplane
and oscillatesor rotates in it around the fixed
point.
For a
point
p =(M, N)
EMo by
v =(m, n)
we denote a vector inTpMo.
Variationalequations along phase
curveFk
have thefollowing
formwhere
(M2, N1, N3) = (M2(t, k), N1(t, k), N3(t, k))
~rk. They
have thefollowing
firstintegrals
As it was shown
by Ziglin,
the normal variationalequations
aregiven by
We assume that the
particular
solution is not astationary point (M2 (t, k)
-=0, Ni (t, k)
=-± 1, N3 (t, k)
=-0) .
Under thisassumption
we reduce the abovesystem
to the formWe can write the above
system
as one second orderequation
with coefficients
and
Now,
we make thefollowing
transformation ofindependent
variablewhich is rational
parametrisation
ofthé complex
circleS1C
Then we obtain
where
After transformation
(3.5) equation (3.4)
readswith coefficients
and
where we denote
(Zl,
z2, z3,z4) = (i, -i, s, -s), and
We can see that
equation (3.6)
is Fuchsian and it has fourregular singular points zi
over the Riemannsphere CP1.
Theinfinity
is anordinary point
for this
equation.
We assumed that k E(0, 1),
so s E(0,oo).
Here it isimportant
to notice that for real values of a, c, andd,
and for all s E(0, 00)
equation (3.6)
has four distinctregular singular points, i.e,
the number ofsingular points
does notdepend
on s. For further calculations we fix s = 1.Let us note here that transformation
(3.5)
is a branched double cover-ing
of Riemannsphere CP1 ~ rk. Moreover,
thebranching points
of thiscovering
areprecisely
the fourpoints
whereequation (3.6)
hassingularities.
Making
thefollowing change
of thedependent
variablewe can
simplify (3.6)
to the standard reduced formwhere
r(z)
can be written aswith coefficients
The differences of
exponents Di = 1 + 4ai
atsingular points zi
are thefollowing
3.2. Case
L3 =
0Let us assume that
L3 =
0.Then, obviously
d =0, and,
as wealready mentioned,
thespecial
frame coincides with theprincipal
axes frame. Aswe consider a
symmetric body
with A = B =1,
thenadditionally
we havef
=0,
andThanks to that
equation (3.7)
has asimpler
form and it can be transformed to a Riemann Pequation.
Insteadof making
a direct transformation in(3.7)
it is more convenient to start from
equation (3.4). Then,
instead of trans- formation(3.5)
we make thefollowing
oneand we obtain
For this Riemann P
equation
the difference ofexponents
at z = 0 is3/4,
at z = 1 is
1/2,
and at z = oo isLet us notice that as in the case
d ~
0 transformation(3.10)
is a branchedcovering
of Riemannsphere CP1 ~ 0393k,
and thebranching points
of this cov-ering
areprecisely
the threepoints
whereequation (3.11)
hassingularities.
3.3. Case
L3
= 0. Secondparticular
solutionWhen
L3 -
0 we have at ourdisposal
anotherfamily
ofparticular
so-lutions. Under our
assumption
A = B = 1 and L =[1, 0, 0]T,
thefollowing
manifold
is invariant with
respect
to the flow ofsystem (1.1). Similarly
asN,
manifolN1
isdiffeomorphic
toT St
CT S2
and it is asymplectic
sub-manifold (Mo.
The Euler-Poissonequations
restricted toNI,
readWe consider a
family
ofphase
curves k ~rl
of the aboveequations given
by
where e ==
2k 2 -
1. For k E(0,1)
curvesri
arenon-degenerate elliptic
curves. Variational
equations along phase
curveri
have thefollowing
formand
they
have thefollowing
firstintegrals
The normal variational
equations
aregiven by
Now,
the reduction of the abovesystem
to the second orderequation give
Let us notice that from
equations (3.13)
and(3.14)
it follows thatThus, putting
we obtain the
following equation
determining
the Weierstrass functionv(t) == D(t;
g2,g3)
with invariantsHence,
we can expressNi,
andM 3 2 (using (3.14)),
in terms of the Weier- strass functionp(t; g2, g3).
The discriminant and the modular function ofD(t; g2, g3)
arefollowing
Hence,
we can rewriteequation (3.15)
in the form of the Laméequation
where
It is
important
to notice here thephysical
restriction onparameter C, namely,
we have C E(0, 2).
4. Proof of Theorem 1.3
In our
proof
of Theorem 1.3 wetry
to be as close aspossible
to theproof
of
Ziglin. Namely,
first we show that a necessary condition forintegrability
is
L3 =
0(or Li = 0,
but thisgives
thealready
knownintegrable
case ofLagrange).
In fact this is the most difficultpart
of theproof. Then,
we usethe second
family
ofparticular
solutions and we restrict thepossible
valuesof the
principal
moment of inertia.Finally, using
the firstsolution,
we limitall allowable values of C to those
corresponding
to the knownintegrable
cases.
We
organise
the threesteps
of theproof
in the form of three lemmas.Only
the first one is somewhatinvolved,
theremaining
two are verysimple.
The first
step
is to show that a necessary condition forintegrability
isd =
0,
see formulae(3.1).
LEMMA 4.1. - Let us assume that
d ~
0. Then theidentity component of
thedifferential
Galois groupof equation (3.7)
is not Abelian.Proof.
- In ourproof
we use Lemma 8.2 and8.3,
seeAppendix.
If(3.7)
is reducible then the
identity component gO
of its differential Galois groupis Abelian in two cases:
when 9
is asubgroup
ofdiagonal
group D or when it is a propersubgroup
oftriangular
group T.First we show
that 9 e
D. Let us assume theopposite.
Then there exist twoexponential
solutions of(3.7)
which have thefollowing
formwhere ei,l for ~ =
1, 2
areexponents
atsingular point
z2,i.e.,
Here
0394i for
i =1, ... , 4
aregiven by (3.9).
Theproduct
of these solutionsv = W1W2
belongs
toC(z)
and it is a solution of the secondsymmetric
power of
(3.7),
i.e.equation (8.3)
with rgiven by (3.8).
Thisequation
hasthe same
singular points
asequation (3.7). Exponents
03C1i,l atsingular points
zi, and at
infinity
03C1~,l for the secondsymmetric
power of(3.7)
aregiven by
where
Ai
for i =1,2,3,4
aregiven by (3.9).
If we write v =P/Q
withP, Q
EC[z]
thenand ni = -03C1i,l ~ N
for certain l.However, if d ~ 0,
then pi,l is not anegative integer
for i =1, 2, 3, 4
and l =1,2,3.
Thisimplies that Q ==
1.Hence, equation (8.3)
has apolynomial
solution v =P,
anddeg P = - 03C1~,l ~
2.But v is a
product
of twoexponential
solutions of the form(2.1),
so we alsohave
Consequently,
ei,m+ ei,l
is anon-negative integer
for i -1, 2, 3, 4.
As ford ~ 0,
we have2ei,l ~
Z for i =1,2,3,4
andl = 1, 2,
we deduce that in(4.1) m ~ l.
But ei,l + ei,2 ==1,
for i =1, 2,3,4. Thus,
we haveWe have a contradiction because we
already
showed thatdeg P ~
2.It is also
impossible that 9 conjugates
toTm
for a certain m ~ N becausewhen d =1=
0exponents
for z1 and Z2 are not rational. Thisimplies
also that9
is not finite.The last
possibility
thatg0
is Abelian occurswhen 9
isconjugated
witha
subgroup
ofDt.
We show that it isimpossible.
To thisend,
weapply
thesecond case of the Kovacic
algorithm,
seeAppendix.
Theauxiliary
sets forsingular points
arefollowing
In the Cartesian
product E
=Eco
xEl
x... xE4
we look for such elementse for which
is a
non-negative integer.
There are two suchelements, namely
We have
d(e(1))
= 1 andd(e(2))
== 0. We have to check if there existspolynomial
P = p1 z+po
which satisfies thefollowing equation
where
Inserting
P into the aboveequation
we obtain thefollowing system
of linearequations
for its coefficientsThe above
system
for po and pl has a non-zero solution ifd 2+ F2
=0,
butfor a real d and F it is
possible only
when d == 0 and F = 0. D As thecovering t
~ zgiven by (3.5)
does notchange
theidentity
component
of the differential Galois group of the normal variational equa- tions(3.3),
from the above lemma it follows that if the Euler-Poisson equa- tions areintegrable,
thenFor a
symmetric body
when A =B =1= C,
the above conditionimplies
thateither
Ll - 0,
and thiscorresponds
to theintegrable
case ofLagrange,
orL3 =
0.Hence,
we have toinvestigate
the last case. Notice that in this case thespecial
frame is theprincipal
axes frame so we haveL
= L =[1, 0, 0]T,
a =
1/A
=1/B
= b = 1 and c =1/C ~
1. At thispoint
it is worth toobserve that now the
identity component
of the differential Galois group ofequation (3.7)
is Abelian forinfinitely
many values of c. Let us remind here that from thephysical
restriction it followsonly
that c E(1/2, oo).
PROPOSITION 4.2. -
If L3
= 0 then theidentity component of
thedif- ferential
Galois groupof equation (3.7)
is Abelian in thefollowing
cases:where l is an
integer.
Proof.
- WhenL3 ==
0 then theidentity component
of the differential Galois group ofequation (3.7)
is Abelian if andonly
if the differential Galois group ofequation (3.11)
is Abelian(transformation
from(3.7)
to(3.11)
is
algebraic).
Thenapplying
Kimura Theorem 8.4 toequation (3.11)
weeasily
derive the above values of c for which theidentity component
of the differential Galois group of thisequation
is Abelian. DThus, applying
the Morales-Ramis orZiglin theory
andusing
the firstparticular
solution we cannot provenon-integrability
of the Euler-Poisonequations
for all values of c listed in the aboveproposition.
This iswhy,
inthe lemma
below,
we consider normal variationalequations corresponding
to the second
particular
solution.LEMMA 4.3. - Assume that C E
(0,2)
andC 54 m/4, for
m =1,..., 7,
then
for
almost all e ER,
thedifferential
Galois groupof equation (3.16)
isSL(2, C).
Proof.
- We assume first thate ~
±1. Then the discriminant of theelliptic
curve associated withD(t;
g2,g3)
does notvanish,
and we canapply
Lemma
8.5,
seeAppendix.
We considersuccessively
three cases from thislemma.
For the Lamé-Hermite case, we have a =
n(n + 1)
for n ~ Z. Thisimplies
that C
n/2,
andhence,
as C E(0,2)
we have C E{1/2, 1, 3/2}.
For the
Brioschi-Halphen-Crawford
case, we have a =n(n + 1)
andm = n +
1/2
E N.Thus,
we haveSo,
this case can occuronly
when CE {1/4, 3/4, 5/4, 7/4}.
In the Baldassarri case we notice that the
mapping
is non-constant and continuous.
Hence, by
DworkProposition 8.6,
for afixed C this case can occur
only
for a finite number of values of e. D As C =1/2,
C = 1 and C =1/4 correspond
to theKovalevskaya,
Eulerand
Goryachev-Chaplygin
cases,respectively,
we have toinvestigate
casesTo this end we return to
equation (3.7).
As weshow,
for d = 0 it can betransformed to the form
(3.11) and,
moreover, this transformation does notchange
theidentity component
of its differential Galois group. We can prove thefollowing.
LEMMA 4.4. - For C E
{3/4, 5/4, 3/2, 7/4}
thedifferential
Galois groupof (3.11)
isSL(2, C).
Proof.
- For C E{3/4, 5/4, 3/2, 7/4}
therespective
values of the differ-ence of
exponents
atinfinity 0394~ (see
formula(3.12))
forequation (3.11)
are
following
Now,
a directinspection
ofpossibilities
in the Kimura Theorem 8.4 shows that Riemann Pequation (3.11)
withprescribed
differences ofexponents
does not possess a Liouvilliansolution,
so its differential Galois group isSL(2,C).
0Now the