R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
G IUSEPPE DE M ARCO
Real ideals in the maximal ring of quotients of C(X )
Rendiconti del Seminario Matematico della Università di Padova, tome 49 (1973), p. 347-351
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GIUSEPPE DE MARCO
(*)
1. Introduction.
Let X be a
completely regular
Hausdorff space; denoteby C(X)
the
ring
of real valued continuous functions onX, by Q(X)
the maximalring
ofquotients
ofC(X) (for
definition andproperties
ofQ(X),
see
[FGL]).
A maximal ideal M ofQ(X)
is called real whenis
isomorphic
to the real field.In a recent work
[P],
Parkproved
that if X isrealcompact,
sepa-rable,
andperfectly normal,
then the absence of isolatedpoints
in Ximplies
the absence of real ideals inQ(X).
In the same year 1969 work
[H] appeared: Hager proved
thatQ(X)
isisomorphic
to someC( Y)
if andonly
if the isolatedpoints
of Xare dense in X
(unless
measurable cardinals areconsidered).
His
techniques
involve99-algebras
and their uniformcompletions.
By pasting together
threepropositions
from[H] (3.1, 2.2, 1.6),
it canbe shown that Park’s result holds for
« practically»
allcompletely regular T2
spaces. In otherwords,
if X has non measurablecardinality,
then every real ideal of
Q (X )
is the ideal of all « functions » inQ (X )
which vanish on some isolated
point
of X.In this paper, we shall
give
a directproof
of this fact. As a sideresult,
we obtain also anotherproof
ofHager’s
main result.(*)
Indirizzo dell’A.: Istituto di MatematicaApplicata
dell’Università - Via Belzoni, 3 - 35100 Padova,Italy.
This work was
supported by
the C.N.R.348
2. Prehninaries.
Some basic facts are needed on
Q (X ) . They
all can be found in[FGL].
The
ring Q(X)
is considered here as the direct limit of therings C(V),
V
ranging
over the dense open subsets ofX,
with restrictionmappings
as
morphisms.
It is well known thatQ(X)
is a von Neumannregular ring,
so that every element ofQ(X)
is associated to anidempotent,
and every ideal of
Q(X)
is an intersection of maximal ideals.Moreover,
in the maximal
spectrum
ofQ(X),
the setsare a
clopen
basis for when e runsthrough
theidempotents
of
Q(X).
3. Results.
Let us start with a
simple
observation.PROPOSITION. Let p be an isolated
point of X,
and denoteby
e~the characteristic
function of
on X. Then is a maximalideal
of Q(X),
and isisomorphic
to R.PROOF. Since p
belongs
to every dense subset ofX,
the formula=
g(p),
gE Q(X )
defines ahomomorphism Q (X ) ~
R.Clearly
WI) is
surjective
and its kernel is sinceg(p)
= 0 isequivalent
to = g, for all g
E Q (X ) .
THEOREM. Let M be a maximal ideal
of Q(X).
Consider the
f ottowzng propositions : (i)
M is an isolatedpoint of
(ii)
M isgenerated by
anidempotent of Q(X);
(iii)
M isgenerated by
e,, where e9 is the characteristicfunction (on X) of X~{p~,
p an isolatedpoint of X;
(iv)
M r1C(X) = MfJ’
p an isolatedpoint of X;
(v) Q(X)IM
isisomorphic
to R.Then:
(i) through (iv)
arealways equivalent
andimpl y (v) . If I
is
non-measurable,
then(v) implies (iv)
and allfive propositions
areequivalent.
PROOF.
(i)
isequivalent
to(ii). Clearly,
if is isolated inif and
only
if =V(e),
with eidempotent (see
Sect.2).
This isequivalent
to say that if is theunique
maximal ideal ofQ(X)
con-taining
e; and since theprincipal
ideal eQ(X)
is an intersection of maximal ideals(Sect. 2),
we have thateQ(X)
= M.(ii) implies (iii)
Assume that if isgenerated by
theidempotent
e;observe that
(1- e) Q (X )
is afield, being isomorphic
toQ(X) /eQ(X).
Suppose
that 1- e EC( TT),
TT dense and open in X . Then(1
-e)Q(X)
contains a copy of
( 1- e ) C ( Y ),
which isisomorphic
toC(~[{0}]),
hence
C(e~ [~0}] )
must be anintegral domain,
so that~"[{0}]
con-sists of a
single point p, clearly
isolated in V and hence in X. Obvi-ously, e
= ep .(iii)
isequivalent
to(iv)
Since p is isolated inX, ifp
= eDC(X ) _ C(X);
ande~ Q (X )
is maximal inQ(X), by
thepreceding Proposition.
Trivially, (iii) implies (ii).
From the aboveproposition,
it follows that(iii) implies (v).
The
remaining
statement will beproved
later on. At thispoint
we are
already
in aposition
to proveHager’s
result[H] :
Assume that is nonmeasurable. T hen
Q(X)
isisomorphic
tosome
C(Y) if
andonly it
the isolatedpoints of
X are dense in X.PROOF. The
sufhciency
is obvious: if the set Y of isolatedpoint
is dense in
X,
then Y is the smallest(open)
dense subset ofX,
so thatQ (X ) ~ C( Y) canonically. Conversely,
assumeQ(X) isomorphic
toa
C( Y) . Then,
sinceQ(X)
isrationally complete,
we haveQ ( Y)
=C(Y).
By [FGL, 3.5]
Y is anextremally
disconnectedP-space,
which thenonmeasurability
condition forces to be discrete. Thenfl(Q(X)),
identified with
f1(C(Y)),
has a dense subset of isolatedpoints. By (i)
and(iv)
of thetheorem,
for every y E Y there existsan isolated
point
such thatThus,
weobtain a y E
Y}
of isolatedpoints
ofX,
which isclearly
dense in
X, since n {O} implies n Mp(y)
=={0}.
yve return nowyey yey
to the
proof
of the lastpart
of the theorem. Thisproof
makes useof a suitable modification of an
argument
due to Isbell[GJ, 12H].
350
Let M be a real maximal ideal of
Q (X ) .
Put P =Ifn C(JT).
ThenP is a
prime
ideal ofC(X),
and = R contains a copy of hence also a copy of its field of fractions.F’;
and thisimplies
that P is a real maximal ideal of
C(X) since, otherwise, F
is non-archimedean
(see [GJ, 7.16]).
Hence for apoint p E X
(since Q(X) = Q ( v X ),
we mayprovisionally
suppose Xrealcompact).
We want to prove
that,
ifIXI
isnonmeasurable,
then p is an isolatedpoint
of X. We assume that it is not and weget
a contradiction.By
Zorn’slemma,
there exists afamily 8
ofpairwise disjoint
open subsets of.X,
such thatp c- clxs,
for everyS E 8,
maximal with re-spect
to theseproperties.
Then Y = V ~ is(open and)
dense in X.For, otherwise,
is anonempty
open subset ofX,
which can-not be
fp} since, by assumption,
p isnonisolated;
and hence thefamily 8
can beenlarged, contradicting
itsmaximality.
Let now be a one-one
indexing
of 8by
a set ~l. ofcardinality .
Consider !~. as a discrete space, and denoteby
c~ themapping
from
C(!1)
intoQ(X)
definedby _ f (,) e, where e,,
is the char-El1
acteristic function of
Sg
on V. Sincepartitions
V intodisjoint
open
subsets,
and V is open and dense inX,
theeg’s
areorthogonal idempotents
ofQ (X) ; by
consequence cv is aring homomorphism.
Let ~c be the
homomorphism
ofQ(X)
onto R whose kernel is M. Thennow is a
(nonzero) ring homomorphism
of ontoR;
and sinceU
_ ~ ~ ~ 1
is nonmeasurable(being
notlarger
thanlXI),
~l is real-compact, i.e.,
thereexists EA
such =f ( )
for allThis shows that
1- e~,
which is the characteristic function of AE ~lB f ~~~
onV, belongs
to M. Take g EC(X)
such that g iszero on
Se,
and 0(this
ispossible, since, by construction, Clearly, ~(12013~)
= g inQ (X ),
since Thushence
C(X) == Mp.
Butg( p ) ~ 0,
a contradiction.COROLLARY. Let X be a
Tychonoff
spaceof
nonmeasurable cardinal.Then the real ideals
of Q(X)
areprecisely
the ideals where e, is the characteristicfunction o f
p an isolatedpoint o f
X.REFE RENCE S
[FGL]
N. J. FINE - L. GILLMAN - J. LAMBEK,Rings of Quotients of Rings
of
Functions, McGillUniversity
Press,Montreal,
1965.[GJ] GILLMAN - M. JERISON,
Rings of
Continuous Functions, trand, Princeton, N. J., 1960.[H] A. W. HAGER,
Isomorphism
with aC(Y) of
the maximalring of
quo- tientsof C(X),
Fund. Math., 66 (1969), 7-13.[P]
Y. L. PARK, Onquotient-like
extensionsof C(X),
Canad. Math. Bull., 12, no. 6 (1969).Manoscritto pervenuto in redazione il 30 ottobre 1972.