R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
M ARTIN S CHECHTER New linking theorems
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MARTIN
SCHECHTER (*)
SUMMARY - We prove new
linking
theorems related to those of Schechter- Tintarev which allow us to obtainlinking
for sets which did not link under theolder theories. This allows us to prove new theorems for nonlinear
prob-
lems.
1. - Introduction.
Let G be a
C1
functional on a Banach spaceE,
and assume that E ==
M Q9 N,
whereM,
N are closedsubspaces,
one of which is finite dimen- sional. Assume thatfor some 6 >
0,
whereOne of the results of the
present
paper isTHEOREM 1.1. Under the above
hypotheses,
there is a sequencec E such that
Interest in such a theorem stems from the fact that for many
applica-
(*) Indirizzo dell’A.:
University
of California, Irvine, CA 92697-3875, USA.Research
supported
in partby
an NSF grant.Mathematics
Subject
Classification.Primary
35J65, 58E05, 49B27.tions, (1.3) implies
the existence of a solution ofWe shall
present
some of theseapplications
here. WhenTheorem 1.1 is well known
(cf. [Ra,
Theorem4.6]). However,
theproof
rests
completely
on the fact that M is finite dimensional. This is so much so, that no one seems to havesuspected
that the theorem is true evenwhen dim M = o . We shall show that this indeed is the case. As a result
we can solve
problems
which could not be considered before.We
apply
Theorem 1.1 to semilinearboundary
valueproblems.
Let Qbe a bounded domain in
Rn,
and let A be aselfadjoint operator
onwith
compact
resolvent andeigenvalues
We assume that the
eigenfunctions
of A are bounded.Let f(x, t)
be aCarath6odory
function on Q x Rsatisfying
and
where and the
only
solution ofis u = 0. We let
We have
THEOREM 1.2. Assume that
for
some L > 0 there are constants1 such that
Then the
equation
has at least one nontrivial soLution.
We also have
THEOREM 1.3. Assume that
for
0 there are constants v~ L +
1 such thatThen
(1.11)
has at least one nontrivial solution.The
equation (1.6) approximates (1.11)
whenI
islarge.
Theo-rem 1.2 cannot be
proved by using previous linking
theorems. On the otherhand,
Theorem 1.3 does follow[Si,
Theorem1.15].
It is included here because of itssimilarity
to Theorem 1.2.Theorem 1.1 is
proved
in Section 4along
with other theorems on link-ing
stated in Section 2. Theorems 1.2 and 1.3 areproved
in Section 3.They
are based on aslight
variation of Theorem 1.1. Otherlinking
methods can be found in
[MW, BN, Ra, Si].
2. - The method.
We
present
a refined version of the newlinking concept
introducedin
[ST].
Let E be a Banach space and let 0 be the set of all continuous maps T = from E x[ o , 1 ]
to E such that1) T( o )
=I,
theidentity
map.2)
For each t E[0, 1 ),
is ahomeomorphism
of E onto E andr-~)eC(~x[0,l)~).
3) T( 1 ) E
is asingle point
in E and convergesuniformly
toT( 1 ) E
as t -~ 1 for each bounded set A c E.4)
For eacht0 E [0, 1 )
and each bounded set A c EDEFINITION. For
A, B c E
we say that A links B ifa) An B=0,
b)
for each there is a t e(0, 1 ]
such thatWe have
PROPOSITION 2.1.
If A,
B c E are closed andbounded, EBA
ispath-
wise connected and A links
B,
then B links A.PROPOSITION 2.2.
If F
EC(E, Rn ) and Q
c E is such thatFo
= isa
homeomorphism of Q
onto the closureof
a bounded open subset Qof R n
I then linksF -1 (~ro ) for
eachTHEOREM 2.3. Let G be a
C 1 functionaL
onE,
and letA,
B be sub-sets
of
E such that A is bounded and links B. AssumeLet
1jJ(t)
be apositive nonincreasing function
on( 0 ,
such thatThen there is a sequence c E such that
COROLLARY 2.4. Under the
hypotheses of
Theorem2.3,
there is a se-quence c E such that
PROPOSITION 2.5. Let H be a
homeomorphism of
E ontoitself
suchthat H and
H -1
map bounded sets into bounded sets.If A ,
B c E and A linksB,
then HA links HB.PROPOSITION 2.6. Let
A , Bn ,
n= 1, 2 , ...,
be subsetsof
E such thatA is bounded and links
Bn for
each n.Suppose
where
and there is a set B c E such that
Then A links B.
COROLLARY 2.7. Let
M,
N be closedsubspaces of E,
oneof
which isfinite
dimensional and such thatthen M
n aB R
links Nfor
each R > 0.COROLLARY 2.8. Let
M,
N be closedsubspaces of
E such that(2.11)
holds with one
of
thembeing finite
dimensional. Let wo be an elementof MB{ 0 },
and let 0 rR,
Then A links B.
3. - The
application.
We now
give
theproof
of Theorems1.2,
1.3.PROOF OF THEOREM 1.2. Let
where D = and
With this norm D becomes a Hilbert space. Under
hypothesis (1.4)
it iseasily
shown that G is aC
1 functional on D andFrom this it follows that u is a solution of
(1.10)
ifLet N be the
subspace spanned by
theeigenfunctions
of A cor-responding
to theeigenvalues ~, o , ~,1, ... , ~, L ,
and letE(A 1)
be theeigenspace
ofA 1.
Let n D.By (1.8)
we haveMoreover,
I claim that foreach e
> 0sufficiently
small either(a)
there issatisfying
or
(b)
there is an E > 0 such thatAssume this for the moment. Since
(3.6)
exhibits a nontrivial solution of(1.11),
we needonly
addressoption (b).
Let o, c be such that(3.7)
holds.Let and take
Then
(3.5)
and(3.7) imply
for
some E0 > 0.
On the otherhand, (1.10) implies
To see
this,
let be any sequence in 1 such that 0 k == 1. Hence there is a renamed
subsequence
such thatweakly
inD, strongly
inL 2 ( SZ )
and a.e. in Q.Moreover, ( 1.4)
im-plies
and
(1.5) implies
Thus
and
Since ||w||D 1, ( 1.10) implies
that theright
hand side of(3.16)
is > 0.The
only
way it could vanish is if we E(£ i)
andSince the
integrand
in(3.17)
isnonnegative,
we must haveFrom this it follows that i-v is a solution of
(1.6). By hypothesis,
this im-plies
that iv =0, showing
that theright
hand side of(3.16)
does not van- ish. Hence the left hand side of(3.16)
converges to apositive
limit forevery such sequence,
showing
that(3.10)
holds. Once we knowthis,
wetake R such that
Let
G1(u) = -G(u).
ThenBy Corollary 2.8,
A links B. Hence there is a sequence such thatThus
and
where we write
f(u)
inplace
off(x, u).
If Q k =Iluk
we letUk
== Then = 1 and there is a renamed
subsequence
such thatweakly
inD, strongly
inL 2(Q)
and a.e. in S2. We thenobtain
from
(3.21)
andfrom
(3.22).
Thisimplies that Ilullb equals
the left hand side of(3.23)
and that u is a solution of(1.6).
Thusby hypothesis
we must have u = 0. Butthis contradicts
(3.23).
Hencethe O k
are bounded. We can nowapply
wellknown
techniques
to show that there is a solution of(1.11) satisfying
= 0. Since
Gi(0)
=0,
we see that u is a nontrivial solution of(1.11).
It remains to prove
(3.7).
First we haveLEMMA 3.1.
If (1.9) holds,
thenfor each o
> 0sufficiently
smallthere is a
positive
E such thatPROOF. Since
E(~, l ) c L °° ( S~ ),
there is a o > 0 such thatwhere 3 is the constant in
(1.9).
Let w = v + y, where v ENL _ 1,
y EE(~, 1).
If
then
Consequently, (3.27) implies
By (3.12)
where a > 2. If we
take (2 sufficiently small,
thisimplies (3.25).
Once we have
inequality (3.25),
we prove(3.7) by assuming,
on thecontrary,
that there is a sequence = VkE(~, L )
suchthat and
By (3.25)
we see that Vk ~ 0. ThusIIYk Iln
->O. Since
E(£ z)
is finite dimen-sional,
there is a renamedsubsequence
such that inE(A 1)
andIlylln
= e.By (3.32)
If p
is such that(3.27) holds,
then(1.9) implies
But
(3.33)
saysFrom
(3.34)
and(3.35)
we see thatLet
~(x)
be any function inCo (S~).
Then for t > 0sufficiently
smallIf we take the limit as t ~
0,
we haveFrom this we conclude that
Since y
E E(~ l ),
thisimplies
that y is a solution of(3.6),
theoption
whichwe discarded. This
completes
theproof
of the theorem.PROOF OF THEOREM 1.3. We
only
sketch theproof
because of itssimilarity
to that of Theorem 1.2. We use the notation of theproof
ofTheorem 1.2.
By (1.12)
Moreover, (1.13) implies
that foreach Q
> 0sufficiently small,
either(a)
there is a solutiony e E(£ 1) )( 0 )
of(3.6)
or(b)
there is suchthat
This is
proved by
the same method used in theproof
of(3.7).
Since theexistence of a solution of
(3.6) implies
the conclusion of thetheorem,
wemay assume that
(3.37)
holds. be such that(3.37)
holds and let be fixed. TakeThen
(3.36)
and(3.37) imply
thatfor some
E o > 0. Moreover, (1.14) implies
Again,
this isproved
in the same way that weproved (3.10).
Next we take I-~ solarge
thatThen
II.
We know that A links B
(this
follows fromCorollary 2.8,
but it wasknown
previously [Si,
Lemma1.14]).
Thusby
Theorem 2.3 there is a se-quence {uk}
c E such that(3.20)
holds withG1 replaced by
G. The rest ofthe
proof proceeds
as before.4. - The
linking
theorems.In this section we
give
theproof
of the theorems of Section 2. Proofs ofProposition
2.1 and 2.2 weregiven
in[ST] (the
definition of the set 0given
there wasslightly
different from thatgiven
in Section2,
but theproofs
are notaffected.)
PROOF OF THEOREM 2.3. If the theorem were
false,
there would be a3 > 0 and a 1/J
satisfying (2.5)
such thatAssume first that
bo a,
and reduce 6 so that3 cS a - bo .
SinceG E C1(E, R),
there is alocally Lipschitz
continuousmapping Y(u)
ofG ’ (u) =0}
into E such thatholds for some 0 > 0. Let
and let
a~(t)
be the flowgenerated by
The
mapping W(u)
islocally Lipschitz
continuous on the whole of E and is bounded in normby
1. We havesince
and y
isnonincreasing. By
the definition(2.4)
of ac, there a T E Q such thatSince A is
bounded,
M is finiteby
the definition of 0. Let T be such thatThis can be
accomplished because y
satisfies(2.5).
Let v = wherese
[ o , 1 ]
and u E A. If there is at1
~ T such thata(t1)v/EQ1’
thenby (4.5)
and(4.7). Otherwise,
for all t E[0, T ]
andHence
Let
Then T 1 E 0. Since
we see
by (4.11)
thatBut this contradicts the definition
(2.4)
of as. Hence(4.1 )
cannot hold foru
satisfying (4.2).
Ifbo
= a, weproceed
asbefore,
but we cannot use(4.13)
toimply (4.14). However,
we note that(4.5) implies
for This shows that
For the
only
way we can have is ifBut this
implies a(i)u
EQ2 - Consequently,
which cannot
happen
if Thus(4.16)
holds.Similarly, (4.11)
shows thatCombing (4.16)
and(4-17),
we see thatcontradicting
the fact that A links B. Thiscompletes
theproof
of thetheorem.
We prove
Corollary
2.4 betaking
=1 /( 1 + r).
PROOF OF PROPOSITION 2.5. Let r be an
arbitrary
map in 0. Then is in ~. If A linksB,
then there is ansl E [ 0 , 1 ]
suchthat
Thus
Since 1, was
arbitrary,
HA links HB.PROOF OF PROPOSITION 2.6. Let T be any map in 0. Then
For n
sufficiently large
Now
for
some t1
E[ o, 1 ].
Butby (4.18)
and(4.19).
HenceConsequently
Thus A links B.
PROOF OF COROLLARY 2.7. If dim M oo~ the result follows from
Proposition
2.2 if wetake Q
= M nBR and
let F be theprojection
of Eonto
Q.
U
and
where
wo e M
andIlwo II
= 1. It follows fromProposition
2.2 thatBn
linksA when R n.
By Proposition
2.1 we also have that A linksBn .
If we nowtake B =
N,
we canapply Propositions
2.6 to conclude that A links B.PROOF OF COROLLARY 2.8. Let
If r 1~ n, it follows from
Propositions
2.1 and 2.2 that A andBn
linkeach other
(no
matter whichsubspace
is finitedimensional).
We now ap-ply Proposition
2.6 to obtain the desired conclusion.REFERENCES
[BN] H. BREZIS - L. NIRENBERG, Remarks on
finding
criticalpoints,
Comm.Pure
Appl.
Math., 44 (1991), pp. 939-964.[MW] J. MAWHIN - M. WILLEM, Critical Point
Theory
and HamiltonianSys-
tems,Springer,
New York (1989).[Ra] P. H. RABINOWITZ, Minimax methods in critical
point theory
withappli-
cations to
differential equations,
Conf. Board of Math. Sci.Reg.
Conf.Ser. in Math., No. 65, Amer. Math. Soc. (1986).
[Sc] M. SCHECHTER, The intrinsic mountain pass, Pacific J. Math., 171 (1995),
pp. 529-544.
[Si] E. A. DE B. E. SILVA,
Linking
theorems andapplications
to semilinearelliptic problems
at resonance, Nonlin. Anal. TMA, 16 (1991) pp.455-477.
[ST] M. SCHECHTER - K. TINTAREV, Pairs
of
criticalpoints produced by
link-ing
subsets withapplications
to semilinearelliptic problems,
Bull. Soc.Math.
Belg.,
44 (1992), pp. 249-261.Manoscritto pervenuto in redazione il 2 settembre 1996.