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HAL Id: hal-00318066

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Submitted on 3 Sep 2008

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An interval map with a spectral gap on Lipschitz functions, but not on bounded variation functions

Sébastien Gouëzel

To cite this version:

Sébastien Gouëzel. An interval map with a spectral gap on Lipschitz functions, but not on bounded variation functions. Discrete and Continuous Dynamical Systems - Series S, American Institute of Mathematical Sciences, 2009, 24 (4), pp.1205-1208. �10.3934/dcds.2009.24.1205�. �hal-00318066�

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LIPSCHITZ FUNCTIONS, BUT NOT ON BOUNDED VARIATION FUNCTIONS

EBASTIEN GOU ¨EZEL

Abstract. We construct a uniformly expanding map of the interval, preserving Lebesgue measure, such that the corresponding transfer op- erator admits a spectral gap on the space of Lipschitz functions, but does not act continuously on the space of bounded variation functions.

To study the statistical properties of uniformly expanding maps, a very successful strategy is to find a Banach space on which the transfer operator of the map admits a spectral gap (see e.g. [Bal00] and references therein).

In dimension d≥2, several Banach spaces have been considered, suited to different situations. However, in one dimension, it is commonly acknowl- edged that the spaceBV of bounded variation functions is the best space to work with (see nevertheless [Kel85] for examples of suitable function spaces when the derivative is only H¨older continuous).

The purpose of this note is to exhibit a very specific example showing that, quite surprisingly, the behavior on Lip can be better than the behavior on BV: we will construct a uniformly expanding mapT of the intervalI = [0,1), preserving Lebesgue measure, such that the transfer operator L associated to T (defined by duality by R

f ·g◦ TdLeb = R

Lf ·gdLeb) admits a spectral gap on the space Lip of Lipschitz functions, while it does not act continuously on BV.

The main motivation for this short note is the articles [DDV08] and [Dur08], in which the authors prove results on empirical processes assuming that the transfer operator admits a spectral gap on Lip. Since similar re- sults were already known when the transfer operator admits a spectral gap on BV, our example shows that these articles really have new applications.

Our example is a Markov map of the interval, with (infinitely many) full branches. The difficulty in constructing such an example is that the usual mechanisms that imply continuity on Lip also imply continuity on BV: if Lv denotes the part of the transfer operator corresponding to an inverse branch v of T (so thatL =P

vLv), one has kLvkBV→BV ≤CkLvkLip→Lip, for some universal constant C. To take this fact into account, our example will therefore involve pairs of branchesvandwsuch thatLv andLw behave badly on Lip, while the sum Lv+Lw behaves nicely, thanks to nontrivial compensations.

Date: September 2, 2008.

1

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2 EBASTIEN GOU¨EZEL

Iff is a function defined on [0,1), we will writekfkLip= sup|f|+ Lip(f), where Lip(f) = sup|f(x)−f(y)|/|x−y|.

Let us fix a sequence (an)n∈N of positive real numbers, withP

an<1/4, as well as an integer N > 0. Our construction will depend on them, and we will show that a good choice of these parameters gives the required properties.

Let In = [4Pn−1

k=1ak,4Pn

k=1ak). We decompose this interval (of length 4an) into two subintervals of length 2an that we denote respectively by In(1)

and In(2). We have Z 1

0

an(1 + 2 cos2(2πn4x)) dx= Z 1

0

an(1 + 2 sin2(2πn4x)) dx= 2an. We can therefore define two mapsvnandwnon [0,1), with respective images In(1) and In(2), such that vn(x) =an(1 + 2 cos2(2πn4x)) andwn(x) =an(1 + 2 sin2(2πn4x)). We define T on In by imposing that vn and wn are two inverse branches of T. It remains to define T on J := [4P

n=1an,1). We cut this interval into N subintervals of equal length, and let T send each of these intervals affinely onto [0,1).

Main theorem. If an = 1/(100n3) and N = 4, then the map T preserves Lebesgue measure and the associated transfer operator has a spectral gap on the space of Lipschitz functions, with a simple eigenvalue at 1and no other eigenvalue of modulus 1. On the other hand, the transfer operator does not act continuously on the space of bounded variation functions.

For the proof, we will work with general values ofanandN, and specialize them only at the end of the argument.

Lemma 1. The map T preserves Lebesgue measure.

Proof. At a pointx, the sum of the derivatives of the inverse branches of T is equal to

X

n=1

(vn(x) +wn(x)) +N · |J|/N

=

X

n=1

an(2 + 2 cos2(2πn4x) + 2 sin2(2πn4x)) +|J|

=

X

n=1

4an+|J|= 1.

LetLbe the transfer operator ofT associated to Lebesgue measure, given by Lf(x) =P

T(y)=xf(y)/T(y). Let also Lnf(x) = X

T(y)=x, y∈In

f(y)/T(y) =vn(x)f(vnx) +wn(x)f(wnx), and Mf(x) =P

T(y)=x, y∈Jf(y)/T(y), so that L=P

nLn+M.

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Lemma 2. Assume that lim supn4an = ∞. Then, for any k ≥ 1, the operator Lk does not act continuously on the space BV of bounded variation functions.

Proof. Let us fix an inverse branch v of T with v(I) ⊂ J (v is affine and its slope is |J|/N). Fix k >0. Letχn be the characteristic function of the intervalvk−1◦vn(I). Its variation is bounded by 2. Moreover, Lkχn(x) = an(1 + 2 cos2(2πn4x))(|J|/N)k−1, hence the variation of Lkχn is at least C(k)ann4, for someC(k)>0. This concludes the proof.

The next lemma is the crucial lemma: it ensures thatLnbehaves well on Lip, while we have seen (in the proof of Lemma 2) that it is not the case onBV. We should emphasize that each branch ofLnbehaves badly on Lip:

this is the addition of the two branches that gives a better behavior, thanks to the compensations of the bumps ofvn and wn.

Lemma 3. We have kLnfkLip≤an(32πn4an+ 8)kfkLip. Proof. Let us decomposeLn/an as

Lnf(x)/an= (1 + 2 cos2(2πn4x))f(vnx) + (1 + 2 sin2(2πn4x))f(wnx)

= (f(vnx) + 3f(wnx)) + 2 cos2(2πn4x)(f(vnx)−f(wnx))

=:L(1)n f(x) + 2L(2)n f(x).

We have L(1)n f

C0 ≤4kfkC0. Moreover, sincevnandwnare contracting by a factor at least 3an, we have Lip(L(1)n f) ≤ 12anLip(f) ≤ 3 Lip(f).

Hence, L(1)n f

Lip≤4kfkLip.

Let us now turn toL(2)n . It satisfies L(2)n f

C0 ≤2kfkC0. Moreover, for any x, y

L(2)n f(x)− L(2)n f(y) = (cos2(2πn4x)−cos2(2πn4y))(f(vnx)−f(wnx)) + cos2(2πn4y)((f(vnx)−f(vny))−(f(wnx)−f(wny))).

Since the derivative of cos2(2πn4x) is bounded by 4πn4, the first term is at most 4πn4|x−y||f(vnx)−f(wnx)|. The distance betweenvnxandwnxbeing at most the length of In, i.e., 4an, we therefore get a bound 16πn4an|x− y|Lip(f). For the second term, cos2(2πn4y) is bounded by 1, and|f(vnx)− f(vny)| ≤3anLip(f)|x−y| ≤Lip(f)|x−y|. Similarly,|f(wnx)−f(wny)| ≤ Lip(f)|x−y|. This second term is therefore bounded by 2|x−y|Lip(f). We obtain

Lip(L(2)n f)≤(16πn4an+ 2) Lip(f).

This proves the lemma.

Let us fix once and for allan=c/n3, with csmall enough so that (1)

X

n=1

kLnfkLip≤ 1

2kfkLip.

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4 EBASTIEN GOU¨EZEL

Using Lemma 3, one can check thatc= 1/100 is sufficient.

Lemma 4. If N ≥4, the operator L satisfies kLfkLip≤ 3

4kfkLip+kfkC0.

Proof. The operatorMsatisfies by constructionkMfkC0 ≤ |J| kfkC0, and Lip(Mf)≤ |J|Lip(f)· |J|N (since every inverse branch of T on J contracts by a factor|J|/N). With (1), we obtain

kLfkLip≤ 1

2+ |J|2 N

kfkLip+|J| kfkC0.

This gives the desired conclusion ifN ≥4, since|J| ≤1.

Proof of the main theorem. By Lemma 2, the choice of an ensures that the transfer operator L does not act continuously on BV. On the other hand, since the inclusion of Lip inC0 is compact, Lemma 4 and Hennion’s theorem show that the essential spectral radius of Lacting on Lip is ≤3/4<1.

It remains to study the eigenvalues of modulus 1 ofL. Letf be a nonzero eigenfunction for such an eigenvalueλ. Letxbe such that|f(x)|is maximal, then

|f(x)|=| Lf(x)|=

X

T(y)=x

f(y)/T(y)

≤ X

T(y)=x

|f(y)|/T(y)≤ X

T(y)=x

sup|f|/T(y) =|f(x)|.

There is equality everywhere in these inequalities. Hence, |f(y)| = |f(x)|

for any preimage y of x, and the complex numbers f(y) all have the same argument. This shows that f is constant on the set T−1(x). Applying the same argument to Ln, we see that f is constant on T−n(x). This set being more and more dense as n tends to infinity, this shows that f is constant,

concluding the proof.

References

[Bal00] Viviane Baladi,Positive transfer operators and decay of correlations, Advanced Series in Nonlinear Dynamics, vol. 16, World Scientific Publishing Co. Inc., River Edge, NJ, 2000. MR1793194.

[DDV08] Herold Dehling, Olivier Durieu, and Dalibor Voln´y,New techniques for empirical process of dependent data, Preprint, 2008.

[Dur08] Olivier Durieu, A fourth moment inequality for functionals of stationary pro- cesses, Preprint, 2008.

[Kel85] Gerhard Keller, Generalized bounded variation and applications to piecewise monotonic transformations, Z. Wahrsch. Verw. Gebiete69(1985), no. 3, 461–

478. MR787608.

IRMAR, Universit´e de Rennes 1, 35042 Rennes, France E-mail address: sebastien.gouezel@univ-rennes1.fr

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