C OMPOSITIO M ATHEMATICA
J OSEPH H. S ILVERMAN
Integral points on abelian surfaces are widely spaced
Compositio Mathematica, tome 61, n
o2 (1987), p. 253-266
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Integral points
onabelian surfaces
arewidely spaced
JOSEPH H. SILVERMAN
Mathematics Department, Boston University, 111 Cummington Street, Boston, MA 02215, USA Received 2 April 1986; accepted 20 July 1986
Martinus Nijhoff Publishers,
An affine subset of an
elliptic
curve hasonly finitely
manyintegral points,
afamous result due to
Siegel. Lang
hasconjectured
that the same is true forabelian varieties of
arbitrary
dimension. In this paper we show that if an affine subset of an abelian surface were to haveinfinitely
manyintegral points,
thenthe
(logarithmic) height
of thosepoints
would growexponentially.
Since it is well known that theheights
of the rationalpoints
on an abelianvariety
growpolynomially,
our theorem shows thatintegral points
on an abelian surface arerelatively
rare; or, as we shall say, that theintegral points
arewidely spaced.
We note that
[Mumford, 1965],
hassimilarly
shown that the rationalpoints
ona curve of genus at least two are
widely spaced, (a
result notentirely superceded by Faltings’ proof [Faltings, 1983]
of the Mordellconjecture;
seethe discussion in
[Szpiro, 1985],
XI§§1,2).
Our method ofproof,
whichinvolves
computations
with localheight functions,
is rather different from that ofMumford; although
we do use(essentially)
the same lemma on almostorthogonal
subsets of lattices in Euclidean space to finish ourargument.
In order to state our main theorem more
precisely,
we set thefollowing notation,
which will remain fixedthroughout
this paper.KIQ
s
Rs AIK
UcA
U(Rs) h
c, c’,
...a number field
a finite set of
places
of Kcontaining
the infiniteplaces
the
ring
ofS-integers
of Kan abelian
variety
a
(non-empty)
affine open subset ofA,
say with affine coordi- nates xi 1... xNthe set of
S-integral points
of U.(I.e.
the set of P eU( K )
suchthat
Xi(P) ERs
forall 1
i N. To indicate thedependence
onxl, ... , 1 XNI we use the notation
Ux(Rs).)
a
(logarithmic)
canonicalheight
on Acorresponding
to someample, symmetric
divisorpositive
constants which maydepend
on all of the abovedata,
and which may vary from line to line.
Our main result is the
following
estimate for the size of the set ofS-integral
points
in an open affine subset of an abelian surface.Theorem 1
Assume that A is an abelian
surface. ( l. e. dim(A)
=2.)
ThenSince
h
is apositive
definitequadratic
form onA(K)/(torsion),
oneeasily
obtains an
asymptotic
estimatewhere r = rank
A(K) (see,
e.g.[Lang, 1983],
ch.5,
thm.7.5).
Thus Theorem 1 says that in the set of rationalpoints
on an abeliansurface,
theintegral points
are
quite
rare. It may becompared
with the result of[Brown, 1984-85],
whouses
techniques
from transcendencetheory
to prove that(However,
Brown’s result is valid for abelian varieties of alldimensions.)
We also note that Theorem 1 is
equivalent
to the fact that if thepoints
inU(RS)
arearranged
in order ofincreasing height,
sayPl, P2,...,
then(This
is the way Mumfordphrases
his result on the Mordellconjecture [Mumford, 1965].)
§1.
Reduction lemmasSiegel’s
theorem forelliptic
curvesactually
shows that a certain set of whatmight
be called’quasi-integral’ points
is a finite set(see [Silverman, 1986],
IX.3.1 for a
discussion.)
We will prove that the’quasi-integral’ points
on anabelian surface
satisfy
the conclusion of Theorem 1.Generally,
let us say thata set 2
~ A(K)
iswidely spaced
if#{P~03A3:(P)H}c log(H).
We also set the further notation:
hD
absolutelogarithmic
Weilheight corresponding
to the divisor D(cf. [Lang, 1983],
ch.4,
ch.10).
03BBD(·, v )
localheight
functioncorresponding
to a divisor D andplace v (cf.
[Lang, 1983]
ch.10,
wherethey
are called Weilfunctions).
Moregenerally, 03BBX(·, v)
is the localheight
functioncorresponding
tothe subscheme X and
place v (see [Silverman,
toappear]
for thedefinition and standard
properties of 03BBX. Intuitively,
03BBX(P, v ) = - log("v-adic
distance from P toX ") .
Thus À
X(P, v)
islarge
if andonly
if P isv-adically
close toX.)
~ > 0 a constant
(the
c’s may alsodepend on ~).
We will prove the
following theorem,
from which Theorem 1 can beeasily
deduced
(see
Lemma3).
Theorem 2
Assume that A is an abelian
surface,
and let D EDiv( A)
be anample, effective
divisor. Then the set
is
widely spaced.
Remark
The set in Theorem 2 consists of the
points
with ’D-defect’ at least e, in thesense of
Vojta’s Nevanlinna-type conjectures (cf. [Vojta, 1986], §3).
Moreprecisely,
the defect03B4(D)
is defined to be thelargest
~ 0 for which the set inTheorem 2 is Zariski dense in A. Then
Vojta’s generalization
ofLang’s conjecture
asserts that03B4(D)
= 0([Vojta, 1986], conj. 3.3),
which is(essentially) equivalent
to the fact that for every >0,
the set in Theorem 2 is finite. Thus Theorem 2provides
someslight
additional evidence forVojta’s conjectures.
Most of our
proof
of Theorem 2 will be valid for abelian varieties ofarbitrary
dimension. We will thus
postpone
theassumption
thatdim( A )
= 2 for aslong
as
possible.
As will be seen, theproblem
becomes that ofdealing
with acertain
exceptional
set, which we canpresently only
handle in dimension 2.(And
eventhere,
we will have recourse toFaltings’ proof
of the Mordellconjecture!)
We start with a number of reductionsteps,
for which we set thefollowing
additional notation.0(1)
a bounded function(i.e.
with theproperty that 1 0(l) c.)
0,(I)
anMk-bounded
function(i.e.
a collection of bounded functions with theproperty
that for all butfinitely
many v eMK, Ov(1)
is identi-cally 0;
cf.[Lang, 1983],
ch.10).
Further,
for each effective divisor D eDiv(A),
define subsets ofA(K)
asfollows.
We start
by showing
that Theorem 2implies
Theorem 1.Lemma 3
Suppose
that03A31(D, E )
iswidely spaced for
everyample, effective
divisorD E
Div( A )
and every E > 0. ThenU(RS)
iswidely spaced.
Proof
First,
suppose that y1,..., ym is another set of affine coordinates for U. Theneach YI E r( U, (9ul
=K[x1,..., xN ].
Let S’ be a set ofplaces
of Kcontaining S,
and suchthat yl ~ RS’[XI’..., XNI
for all1 y
M. Then it is clear thatUx(RS) ~ Uy(RS’).
Since the set S isarbitrary,
this shows that it suffices to prove Lemma 3 for any one choice of affine coordinates for U.Next,
letDl
=(xi).
be thepolar
divisor of x,, and let D =sup ( Dl} (i.e.
D
Dl
forall i;
and ifD’ Di
for alli,
then D’D).
Then thesupport
of D isclearly A -
U(i.e.,
thecomplement
of U inA).
It follows from([Mumford, 1974],
p.62)
that D isample.
Further,
we note that for any n >1,
a basis for theglobal
sections to theline bundle
OA(nD)
is a set of affine coordinates for U. Hencereplacing
Dby nD,
it suffices to prove thatUx(RS)
iswidely spaced
under theassumption
that there is a very
ample
effective divisor D such thatf xo,
xl, ... ,lx,1
is abasis for
r( A, (9A(D».
We may further assume that xo = 1.Let
be the
embedding
of Acorresponding
to our choice of basis for0393(A, OA(D));
and let H E
Div(PN)
be thehyperplane Xo
=0,
sof *H
= D.Further,
for each i, writeSince D is very
ample,
and thex,’s
form a basis forr( A, (9A(D»,
it followsthat
~ Supp(El) = Ø. (I.e.
TheE,’s
havedisjoint support.)
Hence from([Lang, 1983],
ch.10,
cor.3.3),
we conclude thatFurther,
Weil’sdecomposition
theorem([Lang, 1983],
ch.10,
thm.3.7)
says thatNow let
Hence if the
0(1)
in this last time is boundedby
c, then it follows that we havean inclusion
Since D is
(very) ample,
the latter set is finite. Henceif ¿1(D, 1 2)
iswidely spaced,
then so isU(RS).
DFrom Lemma
3,
we are reduced tostudying
sets of the form¿1(D, f)
forample,
effective divisors D. For reasons which will becomeapparent later,
itturns out to be
technically
easier to dealonly
with irreducibledivisors,
so ournext reduction
step
is to show that this is sufficient.(However,
note that inorder to do
this,
we must lookat 03A32(D, E ).
It iscertainly possible
for¿l (D, E )
to be
non-widely spaced
for an irreducible divisorD.)
Lemma 4
if E 2 (D, E ) is widely spaced for
every irreducibleeffective
divisor D and every~ > 0,
then03A31(D, E)
iswidely spaced for
everyample effective
divisor D andevery E > 0.
Proof
Let D be an
ample
effectivedivisor,
and write D as a sum of(not necessarily
distinct)
irreducible effective divisorsThen for all
Thus
Next,
since D isample, ([Lang, 1983],
ch.4,
prop.5.4) implies
thatCombining
these last twoinequalities,
we see thatSince the latter set is
finite,
andby assumption
all ofthe 03A32(D1, ~)’s
arewidely spaced,
it follows that03A31(D, E )
is alsowidely spaced.
DFor the next reduction
step,
we consider functionsFor such a
function,
defineLemma 5
03A32(D, E )
iswidely spaced for
every E > 0if
andonly if 03A33(D,
E,03C4)
iswidely spaced for
every E > 0 and everyfunction
r as above.Proof
One direction is
trivial,
and the other is the usual reduction to simultaneousapproximation (see,
forexample, [Lang, 1983],
ch.7, §2).
Oneactually
obtainsan inclusion of the form
where the union is over a certain finite collection of T’s which
depends only
on the number of elements in S. D
We will also have need of the
following elementary counting lemma,
whichsays that almost
orthogonal
subsets of a lattice arewidely spaced.
This issimilar to the lemma used
by [Mumford, 1965].
Lemma 6
Let 039B be a
finite dimensional lattice,
q apositive definite quadratic form
onA,
nan
integer,
and a, b > 0 constants.Suppose
that 03A3 c 039B is a subset with the property thatfor
any n distinctpoints Pl’...’ Pn
EL,
Then there is a constant c >
0, depending
onA,
q, n, a, andb,
such thatProof
This is a standard
counting argument. Intuitively,
the condition on 2 says that for any npoints
of 2having approximately
the samelength,
at least two ofthem make a
fairly
wideangle.
DFinally,
it turns out to be easier to dealonly
with divisors which do notequal
any of their translates. The
following
lemma often lets one reduce to this case.Lemma 7
For each
effective
divisor D EDiv(A),
let( Here DT
is the translationof
Dby
T. Note that 4) is theproduct of
an abeliansubvariety
and afinite subgroup of A.) Further,
let ep : A -A 10
be the naturalprojection.
Thenfor
every E > 0 there exists an E’ > 0 such thatProof
From the definition of
03A6,
we have D =~*(~D).
Hence for all P~ 03A32(D, ~),
Further,
since h is definedusing
anample
divisor onA,
h - T will dominate anyheight
onAIO.
In otherwords,
for any choiceof A
onA /4Y,
there is aninequality ch - (p
+0(1). (Note
the twoh’s
aredifferent.)
It follows that for allP E ¿2(D, l),
and so
§2.
Anorthogonality
resultWe are now
ready
to prove our mainorthogonality result,
which says that thepoints of 03A33(D,
e,T )
are almostorthogonal (in
the sense of Lemma6), provided
that eachn-tuple
ofpoints in 03A33(D,
e,03C4)
satisfies a certain Zariski open condition. The idea of theproof
is as follows. Assume forsimplicity
thatS
= {v}
containsonly
one element. Thenpoints of 03A32(D, E )
can bethought
of as
points
which arev-adically
close to D. Given two suchpoints
P andQ,
we want to show that
(P- Q )
isfairly large.
NowP - Q
need not bev-adically
close toD,
but it iscertainly
close to the set of differences(Of
course,generally
D - Dequals
all ofA;
but if we work instead on aproduct An, then
thisdifficulty disappears.) Using
thisidea,
weget
the desired estimate for(P - Q ) provided
that P -Q
does notactually belong
to the setD - D. It is this last
proviso
which leads to anexceptional
set ofpoints
whichmust be treated
separately.
Theorem 8
Let D E
Div(A)
be aneffective
divisor. For eachinteger
n1,
let( I. e. Wn
is the setof
all translatesof Supp( D ) n
c A nby
an elementof
thediagonal of An.) Suppose
thatP1,..., Pn ~ 03A33(D,
E,T )
have the property that( Pl, ... , Pn) e Wn .
ThenRemark Note that
Thus if we choose n >
dim(A),
thenWn
will be a proper Zariski-closed subset ofAn;
so ingeneral
one wouldexpect
that a random set of npoints
would notlie on
Wn.
Proof
Define a
differencing
mapNotice that another
description
of»:z
is thengiven by
Now let
P1,...,Pn~A(k)
bepoints
withP=(P1,...,Pn)~Wn.
We do aformal calculation
using
localheight
functions.First,
note that D n(considered
as a subscheme ofAn )
is the intersection of’17i*(D)
for1 i n ,
where03C0i:An~A
is thei th projection.
Hence from([Silverman,
toappear],
thm.2.1b),
Next,
weclearly
have an inclusion nn c03C3*(03C3(Dn)),
so([Silverman,
toappear],
thm.
2.1d,h) implies
Next,we
choose a finite set of divisorsE1,..., Er E Div(An2)
such thatn Ei
=a(Dn) ([Silverman,
toappear],
lemma2.2).
Then from([Silverman,
toappear],
thm.
2.1b)
In this last
line,
the functionshEl
areheight
functions withrespect
to divisors.In other
words, they
are Weilheight functions,
which are defined at allpoints
of
An2.
Weemphasize
that thevalidity
of this lastinequality depends
on thefact that
03C3P~Supp(~El) (i.e.
P ~Wn).
Ingeneral,
one has aninequality hE 03BBE(·, v) + Ov(1)
which is valid for allpoints
not in thesupport
of the divisor E.(In
essence, thisinequality
isnothing
more than afancy
version ofthe
product formula.)
Now let
03C0ij: An2 ~ A
be the variousprojections;
and let à c-Div( A )
be theample
divisor used to defineh . Then £ 03C0*ij(0394)
isample
onAn2.
Therefore([Lang, 1983],
ch.4,
prop.5.4),
Finally,
we note thatCombining
the aboveinequalities,
we have now proven that for every P =( Pl, ... , Pn ) E An(K)
with P ~Wn,
there is aninequality
If we now add the additional
hypothesis
thatP1,...,Pn~03A33(D,
E,r),
andsum over all v e
S,
then we obtain the lower boundSince S is
finite, combining
these last twoinequalities gives
the desiredresult,
§3.
Abelian surfacesWe now add the
assumption
thatdim(A)
=2,
andproceed
with theproof
ofTheorem 2.
Combining
Theorem 7 with Lemma 6(and
the other reductionlemmas),
we see that it suffices to show that forsufficiently large n,
any set ofn distinct
points P1,..., Pn~03A32(D, e) satisfy (P1,..., Pn) ~ Wn. Further,
fromLemma
4,
we may assume that D is an irreducible divisor. Since A is anabelian
surface,
this means that D is an irreducible curve contained in A. As in Lemma7,
for each effective divisor D EDiv(A)
we defineWe start with the case
that (D(D)
is infinite.Proposition
9Let D E
Div(A)
be aneffective
divisor on an abeliansurface. Suppose
that03A6(D)
isinfinite. Then 03A32(D, f)
isfinite.
Proof
From Lemma
7,
we haveNow the fact
that 03A6=03A6(D)
is infinite means that it is theproduct
of a finitegroup with an
elliptic
curve.(Remember
we areassuming
thatdim(A)
=2.)
Hence the
quotient AIO
is anelliptic
curve.Further, (pD e Div(A/0)
is aneffective
diviser,
henceample.
It follows from the refined version ofSiegel’s
theorem
(cf. [Silverman, 1986], IX.3.1) that 03A32(~D, fI)
isfinite,
and so theabove inclusion shows that
~(03A32(D, E»
is also finite.Next,
suppose that we fix apoint
03C0 EA/03A6,
and look at the set ofP
~03A32(D, f)
such thatcp(P) =
qr. Thenusing
the definitionof 03A32(D, e)
andthe fact that
~*(~D)
=D,
we see thatNow for a
given
03C0, theright-hand-side
isfixed,
so there areonly finitely
many choices for P. Thiscompletes
theproof that 2.2(D, E )
is finite. DCombining
Lemma 7 andProposition 9,
we areessentially
reduced to the caseof divisors
satisfying 03A6(D)={0} (i.e.
D is notequal
to any of itstranslates).
We now prove a
purely geometric
lemma which describes how thedifferencing
map affects these divisors. As in the
proof
of Theorem8,
we define thedifferencing
map on Aby
We will also use the
following
notation: for any set2,
letLemma 10
Let D e
Div(A)
be aneffective
divisor on an abeliansurface
with the property that 0(D) = {0}.
Thenfor
allsufficiently large
n, the mapis
injective. ( In
otherwords,
distinctn-tuples of
distinctpoints
in the supportof
Dhave distinct sets
of differences.)
Proof
For any
T E A,
the divisorDT
isalgebraically equivalent
toD,
so the intersectionproduct D. DT
isindependent
of T.Hence,
if we choose n >D2,
then we will have
Now suppose that
P, Q ~ Supp(D)n>
> ando(P)
=o(Q).
Since a is a homo-morphism
whose kernel is thediagonal
ofAn,
it follows that there is a T ~A such thatPl
=Qi
+ T for every1
i n. ThereforePl E Supp(D)
~Supp(DT)
forall 1
i n.But
by
definition ofSupp(D)n>,
thePl’ s
are distinct. It follows from ourchoice of n above that D =
DT,
soT~03A6(D).
Butby hypothesis, 03A6(D)
={0},
from which we conclude that T = 0 and P =
Q.
This proves that a isinjective
on
Supp(D)n>.
The next
proposition provides
the last fact needed to prove Theorem 2. In itwe use
Faltings’
theorem(Mordell conjecture)
to prove that fortrivial 03A6(D)
and
sufficiently large
n, theexceptional
set in Theorem 8 isempty.
Proposition
11Let D ~
Div(A)
be an irreducibleeffective
divisor on an abeliansurface,
andassume
that 03A6(D)={0}.
Thenfor
allsufficiently large
n, the set( I. e.
There are nopoints ( Pl, ... , Pn)~Wn
with the property that thePl’s
aredistinct and
defined
over K. For thedefinition of Wn,
see Theorem8.) Proof
Since D is
irreducible,
we may treat it as an irreducible curvelying
on theabelian surface A. Now abelian varieties do not contain rational curves, so
genus(D) ~
0.Similarly,
ifgenus(D)
=1,
then D would be a translate of anelliptic
curve, andso 03A6(D)
would be infinite. We conclude thatgenus(D)
2.(Note
that if D issingular,
the genus of D means the genus of the normal- ization ofD.)
FromFaltings’
theorem[Faltings, 1983],
we know thatD(K)
isfinite. Choose n to be any
integer greater
than#(K)
such that the map in Lemma 10 isinjective.
Now suppose that
P~A(K)n>
~Wn.
From the definition ofWn,
we haveWn
=03C3-1(03C3(Dn)),
soa(P)
E03C3(Dn). Further,
since thePi’s comprising
Paredistinct,
we see thata(P) E 03C3(Dn>).
Now we use Lemma10,
which says thata is
injective
onDn>.
In otherwords,
the mapis an
injective morphism
defined over K. It follows that any K-rationalpoint
in the
image (such
asa(P))
comes from a K-rationalpoint
inDn>.
LetQ
bethe inverse
image
of P. ThenQ1,...,Qn~D(K),
and theQ;’s
are distinct.This contradicts the choice of n. Therefore
A(K)n> ~ Wn = Ø.
DProof of
Theorems 1 and 2From Lemma
3,
we see that Theorem 2implies
Theorem 1. It thus suffices to prove Theorem 2.Next, using
Lemma4,
it suffices to provethat 03A32(D, e)
iswidely spaced
for every irreducible effective divisor D and every > 0.Next consider the
set 03A6(D). If C(D)
isinfinite,
then fromProposition 9,
the
set 03A32(D, E ) is actually
finite. On the otherhand,
if03A6(D)
isfinite,
thenthe map ~:
A~A/03A6(D)
is finite. Sousing Proposition 7,
we see that itsuffices to show
that 03A32(~D, ~’)
iswidely spaced.
In this way, we reduce tothe case
that 03A6(D)={0}.
Now let n be an
integer large enough
so that the conditions ofProposition
11
hold, namely
It follows in
particular
thatTherefore Theorem 8 holds for every
n-tuple
of distinctpoints
Now Lemma 6
implies that 03A33(D,
e,T )
iswidely spaced,
and then Lemma 5 allows the same conclusion to be madefor 03A32(D, e).
DReferences
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