C OMPOSITIO M ATHEMATICA
A RMAND B RUMER
K ENNETH K RAMER
The conductor of an abelian variety
Compositio Mathematica, tome 92, n
o2 (1994), p. 227-248
<http://www.numdam.org/item?id=CM_1994__92_2_227_0>
© Foundation Compositio Mathematica, 1994, tous droits réservés.
L’accès aux archives de la revue « Compositio Mathematica » (http:
//http://www.compositio.nl/) implique l’accord avec les conditions gé- nérales d’utilisation (http://www.numdam.org/conditions). Toute utilisa- tion commerciale ou impression systématique est constitutive d’une in- fraction pénale. Toute copie ou impression de ce fichier doit conte- nir la présente mention de copyright.
Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
The conductor of
anabelian variety
ARMAND
BRUMER1
& KENNETHKRAMER2
1 Mathematics Dept., Fordham University, Bronx, NY 10458; 2Mathematics Dept., Queens College (CUNY), Flushing, NY 11367
Received 26 February 1993; accepted in revised form 14 June 1993
1. Introduction
In a recent paper,
Lockhart,
Rosen and Silverman[7]
find bounds for theexponents
of conductors of abelianvarieties,
which arefairly sharp
in the caseof
elliptic
curvesexcept
over certain 2-adic fields.They conjecture
the correctupper bound for the conductor of
elliptic
curves ingeneral
and ask for the behavior of the conductor of an abelianvariety
in the case of wild ramification.We settle these
questions
hereby
methods related to theirs. Moresystematic
use of group
theory
enables us to derive all the boundspurely
from theformalism of Artin conductors and the
study
of the twosimplest
cases. Thesecorrespond
to extensions whose Galois group is either thequaternion
groupor
cyclic
ofprime
order.Since some of the facts were not in the exact form needed
here,
we felt thatthe reader would be best served
by
a treatment as self-contained aspossible.
The
hope
thatonè might get
better bounds in the presence of realmultipli-
cations
provided
theoriginal impetus
for this work. Anunexpected application
of our results to
endomorphism rings
of modular abelian varieties can be found in[1].
A finite extension K
of Qp
with absolute ramificationindex eK
=vK(p)
willbe called a
p-adic
field. Our results appear to be true over any Henselian field withperfect
residue field andv(p)
oo, but this is of noimportance
for ourapplications.
We introduce thefollowing
function onintegers:
where n =
Li=oripi
is thep-adic expansion of n,
with0 ri
p - 1.Our main result
gives
asharp
answer(cf. Propositions
6.5 and6.6)
to thequestions
raised in[7].
THEOREM 6.2. Let A be an abelian
variety of dimension g defined
over thep-adic field
K. We have thefollowing
boundfor
the exponentof
the conductor:where d is the greatest
integer
in2gl(p - 1).
If one has more information about the
reduction,
then the refined estimate ofProposition
6.11 may be used.We deduce the results for abelian varieties from new bounds on the conductors of
F[G]-modules V,
where G is the Galois group of an extensionL/K
ofp-adic
fields. It is assumedthroughout
that F is a field of characteristic different from p and that modules arefinitely generated.
Asusual,
we writeF(~)
for the extensiongenerated by
the values of the character 9 of arepresentation
defined over a fieldcontaining
F.Our
inequality
is mosteasily
stated here for the Artin conductorexponent
of an irreduciblecomplex
character. See Theorem 5.5 for the more technical estimate needed in theapplication
to abelian varieties.THEOREM 5.1’.
Suppose that 9 is an absolutely
irreduciblecomplex
characterof G
=Gal(L/K).
Let91 be a
non-trivial irreducible component,of degree pd, of
its restriction to the
ramification
groupG1.
Then we have[Q(~1): Q] = (p - 1)ph-1 for
some h andThe
following simpler
consequence, whichgeneralizes
the bound for abelian characters([15],
p.216),
can also beproved
moredirectly.
PROPOSITION 5.4’. Write
ph(G1) for
the exponentof G1
and letpd
be themaximal dimension among
absolutely simple
componentsof
V as anF[G1]-
module. Then
Throughout,
wewrite ’n
for aprimitive
nth root ofunity
and let J.1n =03B6n>.
We are most
grateful
to the authors of[7]
formaking
theirpreprint
available and to Oisin McGuinness for his comments.
2. Preliminaries on conductors
Let K be a
p-adic
field and let L be Galois overK,
with G =Gal(L/K).
Write03C0L for a uniformizer of L. We have the
descending
normal filtration oframification groups
([13], IV)
in whichGo is
the inertia group andThen
[G : Go]
=fL/K
is the residuedegree, [Go : G,]
is the tame ramificationdegree
andG 1
is a p-group.For a finite dimensional
F[G]-module V
over a field F of characteristic 0 orl ~ p, the conductor
exponent
is definedby
where Vi
=VG1
is thesubspace
of V fixedby Gi
and gi is the order ofGi.
Notethat this is an additive function of V, and that it does not
change
underextensions of F.
We shall call the least
integer
c such that the kernel of therepresentation
afforded
by V
containsGc+1 1 the depth
of V relative toLIK.
If V is asimple F[G]-module
ofdepth
c, we find thatWe may express the conductor
exponent
aswhere the Swan conductor is defined
by
By using
the Swanconductor,
thecomputation
of conductors is reduced toconsideration of the wild ramification group
G1.
Thefollowing
lemma isimmediate from the definition and the fact that the order of
G
1 is invertible in F.LEMMA 2.4. Denote the
fixed field of G1 by K1.
The Swan conductorsw(V, LIK)
is additive on exact sequencesof F[G]-modules
andThe Artin conductor
exponent
of a classfunction 9
onG,
with values in afield F of characteristic zero, is defined as
(cf. [13], VI, §2)
In
particular,
if 9 is the character affordedby
anF[G]-module E
thenf(V, L/K)
=f(cp, L/K).
The Artin conductor behaves well withrespect
to induction or passage to aquotient.
Moreprecisely,
let H be asubgroup
of Gwhose fixed field M has discriminant
bM/K
and let x be a character of H. Then the conductor of the induced characterindH(x)
isgiven by
If
L~
is the subfield of L fixedby
the kernel of therepresentation belonging
to9
and -
is thecorresponding
faithful character ofGal(L~/K),
thenWhen our
representation
isgiven
over a field of non-zerocharacteristic,
wemay use the
following
lemma to lift to characteristic zero.LEMMA 2.7.
Suppose
that k is afield of prime
characteristic l and the orderof
G is invertible in k. Let W be a
k[G]-module affording
theabsolutely
irreducible character v. Then there isa finite
extension Fof Q and
anabsolutely simple F[G]-module V,
with character IVFI such that x is the reductionof xF
modulo theprime
above l.We have
dimk WN = dimF vN for
everysubgroup
Nof
G. Inparticular
W andV have the same dimension and the same conductor.
Proof.
Over a finite extensionka
ofFl(~),
there exists anabsolutely simple ko[G]-module Wo affording
the character X, and kQko Wo
= WReplacing
Wand k
by Wo
andko,
we may assume that k =ko
is a finite field. There existsa finite extension F
of 0,,
withring
ofintegers
O and residue field k’ ~k,
anda torsion-free
(9 [G]-module
T such thatk’ ~O
T =k’Q9k W (see [5], V, § 12).
Moreover,
V = F(D,
T isabsolutely simple.
It now suffices to assume thatk’ = k.
Let N be a
subgroup
of G. Let À : T ~ T bemultiplication by
aprime
elementof O. If l does not divide
INI,
then À induces anisomorphism
onH’(N, 1).
Taking
invariants of the exact sequenceyields
the exact sequenceIt follows that
rank, TN = dimk WN. Clearly dim, VN - rank, TN
and thereforedimf VN = dimk WN.
D3. The
cyclic
andquaternion
casesIn this
section, L/K
is atotally wildly
ramified extension with Galois group G.Our
goal
is to bound the conductor in thespecial
case where G is eithercyclic
of order p or
quaternion
of order8,
andonly complex
characters of G are considered. We also describe the conditions under which the bounds areachieved. In order to
study
therationality
of the Artinrepresentation,
Fontaine[3] gives
a wealth of information on ramification groups. The reader will find in hisPropositions
4.2 and 4.3 results related to some of the materialpresented
here.
We shall need Hensel’s estimate on the
discriminant,
asquoted by
Serre([13], III, §6).
Theproof
is reviewed here toemphasize
that the bound isattained
precisely
whenvK(bL/K)
--- -1(mod pn).
LEMMA 3.1.
If L is a totally ramified
extensionof
Kof degree pn,
thenwith
equality if
andonly if vK(b L/K)
~ -1(mod pn).
Proof.
We haveuK(bL/K)
=vL(DL/K),
where1)L/K
is the different.Suppose
thatL is obtained from K
by adjoining
a root 7rL of an Eisensteinequation
with
vK(apn)
= 0. ThenvL(jaj03C0j-1L) ~ j -
1(mod p")
are distinctfor j =1, ... , p".
Therefore,
we haveand
clearly vL(jaj03C0j-1L)
~ -1(mod pn)
if andonly if j = pn.
COROLLARY 3.2.
Suppose
that G iscyclic of
order p and let ~ be a non-trivial characterof
Gof degree
1. Thenwith
equality if and only if f(g, LIK)
~ 1(mod p).
View V= Q(03BCp)
asa faithful
0 [G]-module.
Thenf(V, L/K)
p - 1 + peK.Proof.
Weapply
the lemma and(2.5), noting
that V affords theregular representation
of G less theidentity. By transport
of structure,conjugates
of 9 have the same conductor. HenceREMARK 3.3. Another
description
of when acyclic
extension attains the maximal conductor may be found in([11],
Satz1).
With the notationabove,
the
equalities vK(L/K)
= p - 1 + peK andf(g, L/K)
= 1 +peK/(p - 1)
occur ifand
only if J1p
c K and there exists an element a E K such that a E LP andvK(a) =1=
0(mod p).
The
remaining
lemmas are needed to treat thequaternions,
butthey
arejust
as
easily proved
forgeneral
residue characteristic and may also be useful instrengthening
the bound for certainabsolutely
irreduciblerepresentations
ofdimension p. Recall that the index function is defined
by i(03C4)
=vL(03C4(03C0L) - 03C0L)
for i E
G - {1}.
The minimal break in the ramificationnumbering
is controlled in thefollowing
lemma. Here03A6(G)
denotes the Frattinisubgroup
ofG, generated by p th
powers and commutators.LEMMA 3.4.
Suppose
that thefirst
gap in the lowerramification numbering
occurs at G = Gfo-1 ~ G
We have the boundIf equality holds,
then G iscyclic.
Proof.
SinceG fo is
a normalsubgroup
of G andG/Gf0 is
anelementary
abelian p-group, we have
03A6(G)
cG fo
and thereforeT e 03A6(G).
Let x be a non-trivial character of G of
degree
1 whose kernel containsG fo. By
the definition of conductorexponent
and(2.6),
we havefo
=f(~, L/K)
=f(~, L~/K).
Thenf0 1
+peKI(p - 1) by Corollary
3.2applied
tothe extension
L.
over K.Suppose
thatequality
holds. Let K’ be the fixed field of i and let K"be the fixed field of TP. Choose a non-trivial
character 9
ofGal(L/K’)
ofdegree
1 which vanishes onGal(L/K"). By (2.1)
and(2.6),
we havefo
=f(cp, LIK’)
=f(-, K"IK’).
In view of the fact thatfo
~ 1(mod p),
we havefo
= 1 +peK’/(p - 1) by Corollary
3.2applied
to K" over K’. It follows thateK. = eK; hence K’ = K and G
= 03C4>
iscyclic.
D Animprovement
in the standard conductor bound for acyclic
tower ispossible
if thebeginning
of the tower is "small" in the sense of[12].
Letand let
NLK
be the norm map from L to K.LEMMA 3.5.
Suppose
that ~ is an irreducible characterof
thecyclic
group G.Then, for
anyinteger t
such thatf(cppB L/K)
1 +eK/(p - 1),
we havef(cp, L/K)
1+ teK
+eK/(p - 1).
Proof. By (2.6),
we may assume that ~ is faithful. If M is the subfield of L fixedby
the kernel ofcppB
thenf(cppB L/K)
=f(cppB M/K) = f,
say.According
to
([13], XV, § 2,
Cor. 2 to Thm.1), f
is the usual conductor of abelian local class fieldtheory,
in the sense that it is the minimalinteger
such thatU(f)K ~ NMK(UM).
Fix m to be the
greatest integer
less than orequal
to1+teK + eK/(p-1).
Ifu~U(m)K,
then u is apt
power inK,
say u =u it
for someu1 ~ U(m-teK)K.
Sincem - teK f by assumption,
Ut is a norm from M.Write u1
=NMK(uM)
for someuM ~ UM. Then
Thus every element of
U(m)K
is a norm from L. We conclude thatf(cp, L/K) m.
DREMARK 3.6. A
partial
inverse of Lemma 3.5 may be found in([3], Prop. 4.3),
orproved by
class fieldtheory
as above.Namely,
iff(gP’, L/K)
1 +
eK/(p - 1),
thenf(cp, L/K)
=f(cppt, L/K)
+teK .
PROPOSITION 3.7.
Suppose
G is thequaternion
groupof
order 8.If 03C8
isthe character
of
afaithful representation of
Gof
dimension2,
thenf(03C8, L/K)
2 +6eK. Equality
holdsif
andonly if
there exists an element a E Ksuch that
a ~ L2
andvK(a) is
odd.Proof.
Forany 03C4~G-{1},
of order4,
letK,
be its fixed field and choose afaithful linear
character xt
of H =Gal(L/K03C4).
Since the kernel ofxi
isHi(03C4),
thedefinition of conductor or
(2.2) gives
usIn
particular,
suppose that ! E G has minimal index. Thenby
Lemma3.4, r
has order 4 and
i(03C4) 2e,.
It follows from(3.8)
and the bound of Lemma 3.5that
f(X,, L/K03C4) 1 + 4eK.
Thenby (2.5)
and Lemma3.1,
we haveAccording
to Remark3.3,
if there is no element a E K such thata E L2
and
vK(a)
isodd,
thenvK(K03C4/K) 2eK. Therefore,
theinequality
in(3.9)
isstrict,
as claimed. Assume there is such an element a. We must show thatf(t/J, L/K)
= 2 +6eK.
Among
elements of G of order4,
chooseanother 03C3 ~
i of maximal index.Let (p,
(resp. ~03C3)
be a character ofdegree
1 on G with kernelequal
toGal(L/K,), (resp. Gal(LIK(1)). By (2.6)
and the definition of conductor(2.1),
wehave
and
But
by
Remark3.3, precisely
two of the threequadratic
extensions of K in L have conductorexponent
1 +2eK .
Sincei(03C4)
x2eK
we must have(i(03C3)
+i(T»/2 = 1 + 2eK. Therefore, i(03C3) =
2 +4eK - f(r).
Inparticular, 1(a)
> 1 +2eK.
By (3.8)
with ireplaced by
6, we havef(x§, L/K03C3)
=i(6).
Remark 3.6therefore
gives
usThen
by (2.5),
we have4. Some
représentation theory
of p-groupsConductors were bounded for
cyclic
andquaternion
groups in the last section.The
group-theoretical
resultsgathered
here will be used to handle thegeneral
case. The reader may consult
[2]
forrepresentation theory
and[5]
forp-groups.
In this
section,
G willalways
denote a p-group and F a field in which p isinvertible. For any commutative
ring R,
anyR-algebra
S and R-moduleM,
weuse the notations
MS
for S~R
M and n·M for the direct sum of ncopies
of M.We recall the
decomposition
of thecharacter 03C8
of asimple F[G]-module V
in terms of the Galois
conjugates
of a character x affordedby
anabsolutely simple component:
where m =
mF(V)
is the Schur index of V over F. The divisionalgebra EndG(V)
has
degree m2
over its center, which isisomorphic
toF(x),
the field of character values of x. The Hurwitz order A =Z[i, j, k, (1
+ i+ j
+k)/2]
in the usualquaternions
K over Q will be ofparticular importance
for the case p = 2.By
abuse oflanguage,
we shall say that anF[G]-module
V is real if it isF[G]-isomorphic
to itscontragredient
V* =HomF(V, F).
Asimple F[G]-
module will be called
unitary
if it is not real. We say that a real module is*-simple
if it does not contain a non-trivial proper real submodule. Because * is an involution on theisomorphism
classes ofF[G]-modules,
if V is*-simple
but not
simple,
then V xé W(9
W * with Wunitary.
It follows that any real module is the direct sum of*-simple F[G]-modules.
Note that if V admits a
non-degenerate
bilinearform ,> :
V x V - F whichis G-invariant in the sense that
gv, gw) = v, w)
forall v,
w E Vand 9
EG,
thenV is real.
Recall the
representations
of abelian groups.LEMMA 4.2. Let A be an abelian p-group and let V be a
simple F[A]-module.
For some n
0,
we have V ~F(03BCpn),
with the actionof
A on V inducedby
asurjection
x : A ~ J.1pn. Two choicesof
X lead toF [A]-isomorphic
modules Vexactly
whenthey
areGal(F(03BCpn)/F)-conjugate,
and V*corresponds
tox-1. If
V
is faithful, then x is
anisomorphism
and A iscyclic.
Special
attention will bepaid
to the non-abelian2-groups
with acyclic subgroup x>
of order 2n and index 2.They
aregiven by
G =x, y>,
whereyxy-1 =
x" andexactly
one of thefollowing
holds:y2 =
1 and a = - 1 for the dihedral groupDn (n 3),
y2 =
1 and a = -1 +2n -1
for the semi-dihedralgroup Sn (n 3), y2 = x2n
1 and oc = -1 for thegeneralized quaternions Qn (n 2), y2
= 1 and a = 1 +2n -1 for n
2.LEMMA 4.3
(Cf. [5],
1§ 14.9
and III§ 7.6).
Let G be a p-group. Then oneof
thefollowing
holds:(i)
G iscyclic,
(ii)
G =Dn, Sn or Qn, as above,
(iii)
G has anon-cyclic
abelian normalsubgroup.
The theorem of Blichfeldt asserts that
absolutely
irreduciblerepresentations
of p-groups are monomial. We need two refinements for F-rational represen- tations. To ease the
notation,
we omit thesubscript
F on the Schur index when the context makes it clear.PROPOSITION 4.4. Assume that the
field
Fsatisfies [F(03BCpn):F] = pn-1(p - 1) for n
= 2when p is
odd(resp. n
= 3 when p =2).
Let G be a p-group and let V be a non-trivialsimple, faithful F[G]-module.
Then oneof the following
holds:
(i)
G iscyclic of
order p andm(V)
=1;
(ii)
G =Q2
andm(V)
= 1 or 2according
as the F-centralsimple algebra
~ZF splits
or not;(iii)
there is a propersubgroup
Hof
G and asimple F[H]-module
W with.
Proof.
Let A be an abelian normalsubgroup
of G and letWo
be asimple F[A]-submodule
ofresÂ( V).
From Lemma4.2,
we haveW0 ~ F(J1pn),
with theaction of A
given by
asurjection x : A -
J1pn. DefineH = {g~G|gW0 ~ W0 as F[A]-module},
that is H ={g~G|~g = x°
for some03C3~Gal(F(03BCpn)/F)}.
Clif-ford’s theorem shows that V ~
indGH(W)
with W =03A3g~H g Wo.
It follows thatresGA(V)
=~gi W, where gi
runsthrough
asystem
of left cosetrepresentatives
for G modulo H and so the restrictions to A of distinct
conjugates
of W haveno
components
in common. Afortiori, absolutely
irreduciblecomponents
canonly
occur with the samemultiplicity
in V as in W. Hencem(V)
=m(W).
If His a proper
subgroup
ofG,
case(iii)
holds.We may thus assume that H = G which
implies
thatXg
is a power of x foreach g
in G and soresGA(V)
is a sum of powers of x. Because V isfaithful,
x must beinjective
and we conclude that A iscyclic. Moreover,
there is ahomomorphism
such that
~(g-1ag) = ~(a)~(g).
We have a contradiction unless every abelian normal
subgroup
of G iscyclic.
This leaves the groups listed in Lemma
4.3(i)
or(ii).
Ourassumption
on rootsof
unity,
which forces[F(03BCpj): F]
=pj-1(p - 1)
forall j 1,
will now be used.Suppose
that G = A iscyclic.
When n =1,
we are in case(i)
and otherwise V is induced from theunique
faithful module for thecyclic subgroup
of G oforder p. The
proposition
therefore holds for abelian groups, withm(V)
=m(W)
= 1.Let G be one of the non-abelian
2-groups
in Lemma4.3(ii). Write 6a
for theelement of
Gal(E/F)
which actsby (Ja((2n) = (2n
on E =F(03BC2n).
If G =Dn
orS",
thenresGA(V) ~
E has the structure of anF[G]-module
with the action of y inducedby
(Ja. Consider thesubgroup
C =x2n-1, y)
of order 4 and aone-dimensional
F [C]-representation
Zaffording
a character03BB:C ~ {±1}
with
03BB(x2n-1)=-1.
ThenV = indGC(Z)
and case(iii)
holds withm(V) = m(W )
= 1.Suppose
G= Qn
andE n + = F((2n
+(2n1).
Then G has aunique faithful, simple representation Vn
over F whose Schur index is 1 or 2according
asA
~ZE+n splits
or not. Since(ii)
holds when n =2,
we may assume n >2,
in which case Gproperly
contains the usualquaternions
C =x2n-2, y> ~ Q2
oforder 8. Then V =
Vn
satisfiesREMARK. We have
mo(V)
=mo(W)
in case(iii)
above. In contrast, when F =Q(J - 7),
we have 2.V3
=ind8:(V2)
andmF ( V2)
= 2 whilemF (V3)
= 1.COROLLARY 4.5. Let V be a
simple F[G]-module
with F as in theProposition.
Then there is
a finitely generated torsion-free Z[G]-module
M such thatM.
issimple
andMoreover
mQ(MQ)f(V, L/K)
=mF(V)f(MQ, L/K).
Proof.
We use theassociativity
andadditivity
of tensorproducts,
as wellas the Galois
condition,
to conclude the claim from the case in which V is faithful andsimple
and G =1,
G =Z/pZ
or G =Q2.
The modules in thosecases were
explicitly
described above and can be defined over Z. Thesimplicity
of
MQ
may beproved
as in the more delicate versiongiven
in the nextproposition.
DWe next show that real modules may be lifted.
PROPOSITION 4.6. Assume G is a
2-group, [F(03BC8):F]=2
and2 fi F2.
Then all G-modules have trivial Schur
multipliers.
Let V be a*-simple, faithful F[G]-module.
Thenthere is a finitely generated torsion- free Z[G]-
module M such that
Mo is simple
andmQ(MQ)·
V ~MF. Moreover,
mQ(MQ)f(V, L/K)
=f(MQ, L/K).
Proof
Under ourassumptions
onF,
the Galois grouprn
=Gal(F(03BC2n)/F)
isgenerated by 03C3l:03B6 ~ 03B6l,
with = ± 3(mod 8).
Thekey
is that the action of the groupgenerated by r 00
and * on therepresentation ring of F[G]
mimics that ofGal(Q(03BC2~)/Q)
on therepresentation ring of Q[G].
The
proof
will beby
induction on the size of G once thespecial 2-groups
are handled.
First let G be
cyclic
of order 2". Our claim holds when n = 0 or 1.For n 3,
we note from the
description
in Lemma 4.2 that there are twonon-isomorphic simple F[G]-modules, interchanged by
* andcorresponding
to orbits ofabsolutely
irreducible characters underrn .
Hence theonly *-simple
module istheir sum, which is induced from the non-trivial
representation
on the sub-group of G of order two. The same conclusion obtains in case n =
2, except
that the*-simple
module isF [G]-simple when J.14 cf.
F.Similarly,
the groups G =Sn, Dn
andQn
each admit aunique *-simple
andfaithful
F [G]
module V. The reduction of theZ[G]-module
M referred to inthe last
corollary
is V when G= Sn
orDn
and twocopies
of V when G =Qn.
So the
proposition
is verified when all abelian normalsubgroups
of G arecyclic.
Let A be a
non-cyclic
abelian normalsubgroup
and letWo
be a*-simple F [A]-submodule of resGA(V).
Asbefore,
defineand
W=.
Then W ~ W * and Clifford’s theorem shows that V ~indH(W). Again,
thesimple components
of W areisomorphic
to E =F(J.12n)
with an action induced
by
asurjection
x : A ~ J.1pn. If H wereequal
toG,
we would conclude thatresÂ(V)
is a sum of powers of x becauseXg
would beGal(E/F)-conjugate
toY±’ for
eachg ~ G.
Because V isfaithful,
x would then beinjective
and Acyclic,
in violation of ourhypothesis.
So H is a proper
subgroup
of G. The inductionhypothesis provides
us witha
Z[H]
module N such thatm(NQ)·
W xéNF.
The desiredlifting
isprovided by
the induced module M= Z[G] OI[H]
N. Infact,
our construction and the Galois conditionimply
that the restrictions to A ofg1W
andg2 W (resp. g Nu
and
g2No)
can havecomponents
in commononly
ifg1H
=g2H
since all theodd powers of x
(resp.
of a lift ofx)
must occur in W(resp.
inresGA(NQ)).
Hencethe
multiplicities occurring
in V and W(resp.
inM.
andN Q)
are the same, sothat the Schur indices are also
equal.
Finally,
wespecialize
theMackey
formalism(cf. [2],
Theorem10.23)
toprove
irreducibility. Namely,
for any commutativering R,
anysubgroup
H ofa group G and any
R[H]-module L,
writeHx
=xHx -1
n H and ’L for theR-module L with action
of y~xHx-1 given by l ~ x-1 yxl.
Then one haswhere x runs
through
a set of double cosetrepresentatives
forHBG/H.
Inparticular, HomQ[A](NQ, xNe)
vanishes unless xbelongs
to H and we concludethat
It follows from the
simplicity
ofN.
that these are the same divisionalgebra
and so
M.
issimple.
D5. Conductor bounds
We derive bounds for the conductor of a
finitely generated F[G]-module V,
where G is the Galois group of an extension
L/K
ofp-adic
fields and thecharacteristic of F is different from p. For
typographical
reasons, we introducethe notation
for V
simple
with Schur index m =mF(V).
Thesubscript
F may be omitted when it is clear from the context.We
begin by assuming
thatL/K
istotally wildly ramified,
so that G is ap-group.
THEOREM 5.1.
Suppose
thatL/K
istotally wildly ramified.
Let cp be anon-trivial
absolutely
irreduciblecomplex
characterof
Gof degree pd.
Thenwhere h is
defined by [0 (9) : Q] = (p - l)ph-l. If
V is asimple 0 [G]-module,
then
Proof.
For a character cp affordedby
anabsolutely simple component
ofK
we have dim V =
m(V)[Q(~): Q]~(1) according
to(4.1).
Sinceconjugates ouf 9
have the same
conductor, f(V, L/K)
=m(V)[0 (9) : Q]f(~, L/K).
It follows that the claimed bounds areequivalent.
We prove the second one
by
induction on the order of G.By (2.6),
we mayassume that V is faithful. Our bound is valid for G
cyclic
of order pby Corollary
3.2 and for G =Q2 by Proposition
3.7.Otherwise, Proposition
4.4 shows that there is a propersubgroup
H of G ofindex pn
and asimple Q[H]-module W
withm(W)·
V ~m(V)· indGH(W).
LetM be the fixed field of H. The induction
hypothesis,
the discriminant bound of Lemma 3.1 and(2.5) imply
thatm(W)f(V, L/K)
=m(V)[f(W, L/M)
+VK (b MIK)
dimW]
since
m(W)
dim V =pnm(V)
dim W and eM =p"ex . D
As a
corollary,
we show that the bound above may be used to control the conductor of anF[G]-module
V over a moregeneral
field F. We continue toassume that
L/K
istotally
ramified.Suppose
that x is anabsolutely
irreducible character which is defined over a fieldcontaining
F. One sees that there is acomplex
character cp and a choice ofhomomorphism ,
suchthat
i(~(g)) = ~(g)
for allg E G, using
Lemma 2.7 to passthrough
an 1-adicfield when the characteristic of F is
1 *
p.By
abuse oflanguage,
we referto 9
as a
lift
of x. Let us define theslippage s(~, cp)
=sF(~, ~) by
Recall that the
depth
of V relative toL/K
is the leastinteger
c such thatGc+
1is in the kernel of the
representation
affordedby
V.COROLLARY 5.2.
Suppose
thatL/K
istotally wildly ramified
and that V is asimple F[G]-module of depth
c relative toL/K.
Let 9 be the characterafforded by
anyabsolutely
irreduciblecomplex representation of G/Gc+
1 which is nottrivial on
G,.
Write[0 (9) : Q] = (p - 1)ph-1
and~(1)
=pd.
ThenFurthermore,
we havesw(V, L/K) [03B4F(V)
+sF(~, cp)
+p/(p - 1)]eK dim
V.Proof. According
to the relation(2.2)
forsimple representations,
we haveOur first
inequality
follows from the bound on the conductor of 9 in Theorem 5.1.In
particular,
we may choose 9 to be a liftof X
described above.By
definitionof
slippage
and thedecomposition
intoabsolutely
irreducible characters(4.1),
we have dim V =mpd+h-1-sF(~,~)[F(03BCp): F].
We concludeby using
thefirst
inequality
and(2.3).
Note that since V issimple,
we may assume thatV0 = 0.
DCOROLLARY 5.3.
Suppose
thatL/K
istotally wildly ramified.
Assume that W is anF[G]-module
and oneof the following
holds:(i)
W issimple
and either p is odd with[F(J1p2) : F]
=p(p - 1),
or p = 2 with[F(03BC8):F] = 4;
(ii)
W is real and*-simple,
p =2, [F(03BC8):F]
= 2 and2 ft F2.
Then
sw(W, L/K) [03B4F(W) + p/(p - 1)]eK dim
W.Proof
We saw inCorollary
4.5 andProposition
4.6 that there is aZ[G]-module
M such thatMQ
isQ-simple, mQ(MQ)W ~ mF(W)MF
andBy rewriting
the bound forf(MQ, L/K) given
in Theorem 5.1 in terms of dim W andbF(W),
we find thatf(W, L/K)
dim W +[03B4F(W)
+p/(p - 1)]eK dim
W.We may assume
Wo
=0,
so thatsw(W, L/K)
=f(W, L/K) -
dim Wby (2.3).
D We now suppose that L is not
necessarily totally
ramified over K. Recall thatK1 is
the fixed field ofG 1 and
that we writeVo
=VG° and V1
=VG1. Depending
on how much information is available about the
F[G1]-simple components W
of
V/ Vl,
one may bound the conductor of Vby using
Corollaries 5.2 or 5.3 tocontrol
sw(W, L/K1)
andapplying (2.3)
and Lemma 2.4.PROPOSITION 5.4. Write
ph(G1) for
the exponentof G1
and letpd
be themaximal dimension among
absolutely simple
componentsof VIV,
asa G1-module.
Then
Proof. By extending
the field ofscalars,
we may assume thatV/ Vl splits completely
as anF[G1]-module.
Denote anycomponent by W
and itscharacter
by
x.By assumption, 03B4(W)
d. We mayapply Corollary
5.2 withthe crude estimate
sF(~, ~) h(G1) -
1 to obtain the boundTo prove the claimed
inequality,
we now useadditivity, (2.3)
and Lemma2.4,
noting
that g 1 eKi = g0eK. EWe now
proceed
to our main result for the conductors of Galoismodules,
stated here in terms of the Swan conductor. One may use(2.3)
to obtain abound for
f(V, L/K).
THEOREM 5.5. Let
L/K
be a Galois extensionof p-adic fields
with G =Gal(L/K)
and let V be anF[G]-module.
Assume oneof the following
holds:(i)
either p is odd with[F(Pp2) : F]
=p(p - 1),
or p = 2 with[F (9 8): F]
=4;
(ii)
p =2,
V ~ V* asG1-modules, [F(98): F]
= 2 and2 ~ F2.
Then we have the bound
where the
integer dl
isdefined by dim(V/V1) = (p - 1)dl.
Proof.
WriteV
=VIV,
and letTV
=~ Wj
be thedecomposition
as a directsum of
simple
or*-simple F[G1]-modules according
as we are in case(i)
orcase
(ii). By additivity
andCorollary 5.3,
we haveBecause
W
does not admit theidentity representation
ofG1,
one sees from(4.1)
thatdim W
=m(Wj)(p - 1)p’
with i =03B4(Wj).
Defineintegers si by
so that
dl
=Li Sipi
and03A3j03B4(Wj) dim W
=(p - 1) (p-1)03BBp(d1),
be-cause of the basic observation that E
iripi 03BBp(03A3 ri pi)
for anynon-negative integers
ri.The bound for
sw(V,L/K)
results from(5.6)
and Lemma2.4,
sinceg1 eK1 = g0eK.
REMARK 5.7.
Suppose
that wedrop
theassumption V ~
V* in case(ii)
above. Note that
2f(V, L/K)
=f(V C V*, L/K). By applying
Theorem 5.5 to thereal module V EB V* and
using (2.3),
we find the weakerinequality
with
d
=dim(V/V1).
This bound is in fact taken on.
Suppose
thatJ.12" c K
and let L bethe
splitting
field of the Eisensteinpolynomial h(x) = .TC2n -
03C0K. Then G =Gal(L/K)
acts on V =Fl(03BE2n) by multiplication by (2n.
For 1 =± 3 (mod 8),
we have
dim V = 2n-2.
SinceV~V*
is induced from the non-trivial one-dimensional
representation
of thesubgroup
of G of order2,
it follows from(2.5),
Lemma 3.1 and Remark 3.3 thatf(V, L/K)
=2n-2[1
+(n
+1)eK].
6. Conductors of abelian varieties
As the main
application
of ourbounds,
we estimate the conductor of an abelianvariety A,
defined over ap-adic
field K.Write
g(A) = Tl(A)
00,,
whereTl(A)
is the 1-adic Tate module. Denote thekernel of
multiplication by l by A[l]
and the 1-division fieldby
L =K(A[l]).
Let G =
Gal(L/K)
and let I =I(K/K)
be the inertia group.According
to Grothendieck([4], §4),
for 1 ~ p, the conductorexponent
of A iswhere
e(A/K) = dim(Vl(A)/Vl(A)I)
is the tame conductor. Each term above isindependent
of l :0 p.THEOREM 6.2. Let A be an abelian
variety of
dimension gdefined
over thep-adic field
K. We havethe following bound for
the exponentof
the conductor:where d is the
greatest integer
in2g/(p - 1).
Proof.
We may choose l to be aprimitive
root modp2
if p is odd(resp.
1 = + 3
(mod 8),
if p =2), prime
to thedegree
of somepolarizationt
of Adefined over K. The latter condition
implies
that the Weilpairing
induces anon-degenerate Gl-invariant symplectic
form onA[l].
ThereforeA[l]
is realas
G1-module
and Theorem 5.5yields
the estimatewith
(p - 1)d1
= dimA[l] -
dimA[lJG1.
Since03B5(A/K)
dimVl(A) = 2g,
weobtain an
inequality
from(6.1)
at least asgood
as the stated bound onf(A/K).
n This bound is best
possible
in astrong
sense; it is attained for eachinteger
g and
p-adic
field K. Wepresent
two families ofexamples.
~We thank Alice Silverberg for reminding us to include this assumption.
The
following general
construction wassuggested by [6]
and([7], §3).
LEMMA 6.3. Let K be a
p-adic field,
with p odd.Suppose
thath(x)
is aseparable polynomial
inK [x] of
odddegree 2g
+ 1 3 and that B is the Jacobianvariety of
thehyperelliptic
curvey2 = h(x) of
genus g.Suppose
that h =hl...hr
withhi
irreducible over K. Let
Oi
be a rootof hi(x)
andMi
=K(03B8i).
We havewhere L =
K(B [2]). Equality
holds when h is irreducible and the extensionM1/K is totally ramified.
Proof.
Denoteby
oo theunique point
atinfinity
on thehyperelliptic
curve.Note that L is the
splitting
field of h. For eachi,
with 1 i r, writeHi
=Gal(L/Mi)
andPi,(1 = (03C3(03B8i), 0) -
oc, where o- ranges overGlHi.
Thedivisors
Pi,03C3 represent points
of order 2 on B which spanB[2]
overF2,
withthe
only
relationLi,(1 Pi,(1 ’"
0.Define the
Z2[G]-module X by
the exact sequencein which the
G-map
i is determinedby
There is a
splitting
of i inducedby 03C3Hi ~ 1/(2g
+1).
SinceHi
is the stabilizer of03B8i
in thepermutation representation
of Gacting
on the rootsof h,
we see thatB[2]
=F2 0
x.The sequence
(6.4)
remains exact upontensoring
wih eitherF2
or02
orpassing
to submodules fixedby
anysubgroup
of G. Let W =E9 (1)2[G/HJ =
E9 indGHi(1Hi).
We find thatf(B [2], L/K)
=f(W, L/K). Computing
the latterby additivity
and(2.5),
we obtainWe write V for the 2-adic Tate space of B. In view of the