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arXiv:2101.06316v2 [math.AP] 30 Apr 2021

GROUPS

WAGNER AUGUSTO ALMEIDA DE MORAES

ABSTRACT. We present sufficient conditions to have global hypoellipticity for a class of Vekua-type oper- ators defined on a compact Lie group. When the group has the property that every non-trivial representation is not self-dual we show that these sufficient conditions are also necessary. We also present results about the global solvability for this class of operators.

1. INTRODUCTION AND PRELIMINARIES RESULTS

In this paper, we are interested in the study of global properties for a class of operators defined on a compact Lie group G. We will present necessary and sufficient conditions to obtain the global hypoellipticity and the global solvability of the operatorP:C(G)→C(G)given by

(1.1) Pu:=X uqupu,

whereX is a normalized vector field on Gand p,q∈C, with p6=0. The case p=0 was studied in [5]. Notice that when p6=0 the operatorP isR-linear but is notC-linear. We say that Pis globally hypoelliptic if the conditionsu∈D(G)andPuC(G)implyuC(G).

The local solvability for classes of such operators was considered in [6] and [7] and the global solv- ability on the torusT2was studied in [1] in the case whereG=T2.

Our results were inspired by the article [1] by A. Bergamasco, P. Dattori, and A. Meziani, where the authors consider the caseG=T2and they use Fourier analysis to obtain their results. Since the Fourier analysis on compact Lie groups is well developed, we were able to give sufficient and necessary condi- tions for the global hypoellipticity of the operatorPgiven in (1.1) and for the necessary condition we were led to assume that every non-trivial representation ofGis not self-dual. With this same assumption we have discussed the global solvability of P, but using a different notion of solvability from the one considered on [1].

Date: May 3, 2021.

2020Mathematics Subject Classification. 35H10, 35R03, 43A80.

Key words and phrases. Global hypoellipticity and Global solvability and Fourier series and Vekua operators and Compact Lie groups.

This study was financed in part by the Coordenac¸˜ao de Aperfeic¸oamento de Pessoal de N´ıvel Superior - Brasil (CAPES) - Finance Code 001 and by the Methusalem programme of the Ghent University Special Research Fund (BOF) (Grant number 01M01021).

1

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In [10], M. Ruzhansky, V. Turunen, and J. Wirth have given sufficient conditions for the global hy- poellipticity for a class of pseudo-differential operators on compact Lie groups in terms of their matrix- valued full symbols, that will be defined on (1.6). This approach works well in the case where p=0 (see [5]) because in this case, the operator Pis linear. When p6=0, evenPbeing a left-invariant operator, its symbol depends onxG, so we do not have the expected propertyPu(ξc ) =σP(ξ)u(ξb ), for every [ξ]∈G. For this reason, our approach will be done by analyzing the Fourier coefficients ofb Puatξ and ξ¯ to obtain a suitable expression that relatesPuandu.

In Section 2 we present sufficient conditions for the global hypoellipticity of the operator P. In Section3we present necessary conditions for the global hypoellipticity of the operatorPwhenGhas the property that its non-trivial representations are not self-dual. In Section 4 we discuss the global solvability of the operatorPwith the same additional hypothesis from Section3. In Section5we study the operatorPon SU(2), which is a compact Lie group where every representation is self-dual.

Throughout this paper, we will use the notation and results about Fourier analysis on compact Lie groups based on the book by M. Ruzhansky and V. Turunen [8] to study the global hypoellipticity and the global solvability of the operatorPdefined on (1.1).

LetGbe a compact Lie group and let Rep(G)be the set of continuous irreducible unitary representa- tions ofG. By the compactness ofGeveryφ∈Rep(G)has finite dimension and it can be viewed as a matrix-valued functionφ:G→Cdφ×dφ, wheredφ =dimφ. We say thatφ∼ψif there exists an unitary matrixA∈Cdφ×dφ such thatAφ(x) =ψ(x)A, for allxG. We will denote byGbthe quotient of Rep(G) by this equivalence relation. Givenφ∈Rep(G), we define its conjugate representationφ:G→Cdφ×dφ

asφ(x):=φ(x)and we have thatφ∈Rep(G). Whenφ∼φ we say thatφ is a self-dual representation.

For fL1(G)we define the group Fourier transform of f atφ∈Rep(G)is fb(φ) =

Z

Gf(x)φ(x)dx,

wheredxis the normalized Haar measure onG. By the Peter-Wyel theorem, we have that

(1.2) B:=np

dimφ φi j;φ= (φi j)di,φj=1,[φ]∈Gb o,

is an orthonormal basis forL2(G), where we pick only one matrix unitary representation in each class of equivalence, and we may write

f(x) =

[φ]Gb

dφTr(φ(x)bf(φ)).

and the Plancherel formula holds:

(1.3) kfkL2(G)=

[φ]Gb

dφ kbf(φ)k2HS

1/2

=:kbfk2(bG), where

kbf(φ)k2HS=Tr(bf(φ)bf(φ)) =

dφ

i,j=1

bf(φ)i j2.

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For each[φ]∈G, its matrix elements are eigenfunctions of the Laplace-Beltrami operatorb LGcorre- spondent to the same eigenvalue−ν[φ], whereν[φ]≥0. Thus

−LGφi j(x) =ν[φ]φi j(x), for all 1≤i,jdφ, and we will denote by

hφi:= 1+ν[φ]1/2

the eigenvalues of(I−LG)1/2.

It is possible to characterize smooth functions and distributions on G by relations between their Fourier coefficients atφandhφi. Precisely, we have

(1) fC(G)if and only if for eachN>0, there existsCN>0 such that

(1.4) |bf(φ)i j| ≤CNhφiN,

for all[φ]∈Gband 1≤i,jdφ.

(2) u∈D(G)if and only if there existC,N>0 such that

(1.5) |bu(φ)i j| ≤ChφiN,

for all[φ]∈Gband 1≤i,jdφ, whereu(φb )i j:=

u,φji . ForxG,X∈gand fC(G), we define

X f(x):= d

dt f(xexp(tX))

t=0

.

Notice thatX f(x) =X f(x), for allxG,X∈gand fC(G).

The symbol of a continuous linear operator P:C(G)→C(G) in xG and φ ∈Rep(G), φ = (φi j)di,φj=1is defined by

(1.6) σP(x,φ):=φ(x)(Pφ)(x)∈Cdφ×dφ,

where(Pφ)(x)i j:= (Pφi j)(x), for all 1≤i,jdφ, and we have the following quantization P f(x) =

[φ]Gb

dim(φ)Tr

φ(x)σP(x,φ)bf(φ)

of the operator P, for every fC(G)and xG. WhenP:C(G)→C(G) is a continuous linear left-invariant operator its symbolσPis independent ofxGand

P fc(φ) =σP(φ)bf(φ), for all fC(G)and[φ]∈G.b

LetX∈gbe a vector field normalized by the norm induced by the Killing form. It is easy to see that the operatoriX is a left-invariant symmetric operator onL2(G). Thus, for all[φ]∈Gbwe can choose a

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representativeφsuch thatσiX(φ)is a diagonal matrix, with entriesλm∈R, 1≤mdφ. By the linearity of the symbol, we obtain

σX(φ)mn=mδmn, λj∈R. In this case we have by (1.6) thatσX(φ) =σX(φ), that is,

σX(φ)mn=−mδmn. Moreover, we have

m(φ)| ≤ hφi, for all[φ]∈Gband 1≤mdφ.

2. SUFFICIENT CONDITIONS FOR THE GLOBAL HYPOELLIPTICITY

LetGbe a compact Lie group andX∈gbe a normalized vector field. In this section we deal with the global hypoellipticity of the operatorP:C(G)→C(G)given by

Pu:=X uqupu,¯

where p,q∈C, withp6=0. The case p=0 was studied in [5]. Foru∈D(G), we define its conjugate u¯by

hu,ϕ¯ i:=hu,ϕ¯i, ϕ∈C(G)

and it is clear that ¯u∈D(G). Hence, we can extend the operatorPto the space of distributionsD(G).

We recall that the operator Pis globally hypoelliptic if the conditions u∈D(G) and PuC(G) implyuC(G).

Our goal is to obtain necessary and sufficient conditions for the global hypoellipticity of Pand for this we will analyze the behavior of the Fourier coefficients ofPu.

First, for each[ξ]∈Gbwe choose a representative such that

σX(ξ)mn=m(ξ)δmn and σX(ξ¯)mn=−m(ξ)δmn,

for 1≤m,ndξ, whereδmnis the Kronecker’s delta. This assumption means that if[ξ]6∼[ξ], then the representatives chosen for each one of this equivalence classes satisfyξ(x) =ξ(x), for allxG. Notice that with this choice we haveλm(ξ¯) =−λm(ξ), for all[ξ]∈G, 1b ≤mdξ.

Hence, for[ξ]∈Gbwe obtain

Pu(ξc )mn=X u(ξc )mnqu(ξb )mnpbu(ξ¯ )mn

= [σX(ξ)u(ξb )]mnqu(ξb )mnpbu(ξ¯ )mn

= (iλm(ξ)−q)u(ξb )mnpbu(ξ¯ )mn

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Similarly,

Pu(c ξ¯)mn=X u(c ξ¯)mnqbu(ξ¯)mnpbu(¯ ξ¯)mn

=

σX(ξ¯)u(bξ¯)

mnqbu(ξ¯)mnpu(ξb )mn

= (iλm(ξ¯)−q)u(bξ¯)mnpu(ξb )mn

= (−m(ξ)−q)u(bξ¯)mnpu(ξb )mn

Now, using the fact thatbu(ξ¯ ) =u(bξ¯), we obtain the following system of equations

(2.1)



Pu(ξc )mn= (iλm(ξ)−q)u(ξb )mnpbu(ξ¯ )mn Pu(ξc )mn= −p¯u(ξb )mn +(iλm(ξ)−q)b¯ u(ξ¯ )mn Denote

(2.2) ∆(ξ)m:=−λm(ξ)2+|q|2− |p|2i2λm(ξ)Re(q).

and by (2.1) we obtain

(2.3) ∆(ξ)mbu(ξ)mn= (iλm(ξ)−q)c¯ Pu(ξ)mn+pPu(ξc )mn Theorem 2.1. The operator P:D(G)→D(G)given by

Pu:=X uqupu¯ is globally hypoelliptic if one of the following statements holds

(1) |p|>|q|;

(2) |p|<|q|andRe(q)6=0;

(3)M>0such that

hξi ≥M =⇒ λm(ξ)2−(|q|2− |p|2)≥ hξiM, for all1≤mdξ.

Proof. Let u∈D(G) such thatPu= fC(G). Let us prove that uC(G) if one of the three statements above holds. Since fC(G), for allN>0 there existsCN>0 such that

(2.4) |bf(ξ)mn| ≤CNhξiN, 1≤m,ndξ,[ξ]∈G,b and the same estimate is valid for f.

Assume that 1. holds, that is,|p|>|q|. In this case, we have

|∆(ξ)m| ≥ |Re(∆(ξ)m)|=| −λm(ξ)2+|q|2− |p|2| ≥ |p|2− |q|2>0.

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By (2.3) we obtain

|bu(ξ)mn| ≤ 1

|∆(ξ)m|

|m(ξ)−q¯||bf(ξ)mn|+|p||bf(ξ)mn|

≤ 1

|p|2− |q|2(|λm(ξ)||bf(ξ)mn|+|q¯||bf(ξ)mn|+|p||bf(ξ)mn|)

≤ 1

|p|2− |q|2(hξi|bf(ξ)mn|+|q||bf(ξ)mn|+|p||bf(ξ)mn|).

Hence, givenN>0 we obtain from (2.4)

|bu(ξ)mn| ≤

CN+1+CN(|q|+|p|)

|p|2− |q|2

hξiN and we conclude thatuC(G)by (1.4).

Assume now that 2. holds, that is,|p|<|q|and Re(q)6=0. If|λm(ξ)|212(|q|2− |p|2)then

|∆(ξ)m|2≥ |Re(∆(ξ)m)|2= (−λm(ξ)2+|q|2− |p|2)2≥1

4(|q|2− |p|2)2>0.

On the other hand, if|λm(ξ)|2>12(|q|2− |p|2)then

|∆(ξ)m|2≥ |Im(∆(ξ)m)|2=4Re(q)2λm(ξ)2≥2Re(q)2(|q|2− |p|2)>0.

Thus we obtainC>0 such that

|∆(ξ)m| ≥C,

for all[ξ]∈G, and 1b ≤mdξ. Analogously to the previous case we conclude thatuC(G).

Finally, assume that 3. holds, so there existsM>0 such that

λm(ξ)2−(|q|2− |p|2)≥ hξiM, for all 1≤mdξ, wheneverhξi ≥M. Hence, forhξi ≥Mwe have

|∆(ξ)m| ≥ |Re(∆(ξ)m)|=| −λm(ξ)2+|q|2− |p|2| ≥ hξiM. Following the same steps as the first case, we obtain

|bu(ξ)mn| ≤ hξiM(hξi|bf(ξ)mn|+|q||bf(ξ)mn|+|p||bf(ξ)mn|).

Using the fact that fC(G), forN>0 we have

|bu(ξ)mn| ≤(CN+M+1+CN+M(|q|+|p|))hξiN, for all 1≤m,ndξ, wheneverhξi ≥M. Since the set

{[ξ]∈G;b hξi<M} is finite, we can obtainCN >0 for eachN>0, such that

|bu(ξ)mn| ≤CN hξiN,

for all[ξ]∈G, and 1b ≤m,ndξ. ThereforeuC(G)and the theorem is proved.

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Example 2.2. Let G be a compact Lie group and let X∈g. Consider the operator P1defined by P1u:=X uiu−2u,

that is, p=2and q=i. From the condition 1 of Theorem2.1 the operator P1is globally hypoelliptic.

Consider now the operator P2given by

P2u:=X u−6u−(3+4i)u,

that is, p=3+4i and q=6. From the condition 2 of Theorem2.1the operator P2is globally hypoelliptic.

To give an example where we need to apply the condition 3 of Theorem 2.1 we need to know the behavior of the symbol ofX. For the next example, we will follow the notation and results from [9] and Chapter 11 of [8] to analyze an operator defined on SU(2).

Example 2.3. Let G=SU(2) and let \

SU(2) be the unitary dual of SU(2), that is, \

SU(2) consists of equivalence classes [t]of continuous irreducible unitary representations t:SU(2)→C(2ℓ+1)×(2ℓ+1), ℓ∈ 12N0, of matrix-valued functions satisfying t(xy) =t(x)t(y) and t(x) =t(x)1 for all x,ySU(2). We will use the standard convention of enumerating the matrix elementstmnoft using indices m,n ranging between −ℓ towith step one, i.e. we have −ℓ≤m,n≤ℓwith ℓ−m, ℓn∈N0.For ℓ∈ 12N0we have

hℓi:=D t

E=p

1+ℓ(ℓ+1).

Let X =∂0, where0is the neutral operator. There is no loss of generality assuming that the vector field is0because all vector fields define on SU(2)can be conjugated to0and this conjugation does not affect lower order terms. We have thatσ0(ℓ)mn=imδmn,for allℓ∈12N0, that is,

λm(ℓ) =m, for allℓ∈12N0,−ℓ≤m≤ℓwithℓ−m∈N0.

Consider the operator P3given by

P3u:=∂0uiu− 1

√3u, that is, p=1

3 and q=i. Notice that m2

1−1

3 =

m2−2

3 >1

3,

for all m12Z. Therefore, the operator P3is globally hypoelliptic by the condition 3 of Theorem2.1.

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3. NECESSARY CONDITIONS FOR THE GLOBAL HYPOELLIPTICITY

The Theorem2.1gives us sufficient conditions for the global hypoellipticity of the operatorP. Our next result says that these conditions are also necessary for the global hypoellipticity ofP in the case where we have [ξ]6= [ξ¯],for all non-trivial[ξ]∈G. The next proposition gives us the first necessaryb condition for the global hypoellipticity ofG.

Proposition 3.1. Assume that[ξ]6= [ξ¯],for all non-trivial [ξ]∈G. Ifb ∆(ξ)m=0for infinitely many [ξ]∈G,b 1≤mdξ, then P is not globally hypoelliptic.

Proof. Let{[ξj]}jNbe a sequence inGbsuch that∆(ξj)mj=0, for some 1≤mjdξj. We may assume thatξj6=ξk, for any j,k∈N. Since

∆(ξ)m=−λm(ξ)2+|q|2− |p|2i2λm(ξ)Re(q), andλm(ξ¯) =−λm(ξ), we have

∆(ξ¯)m=∆(ξ)m,

for all[ξ]∈G, 1b ≤mdξ. In particular, ∆(ξ¯j)mj =0, for all j∈N. Define

b

u(ξ)mn=









mjj)−q,¯ if[ξ] = [ξj],m=mj p, if[ξ] = [ξj],m=mj

0, otherwise.

Notice thatu(ξb )mnis well–defined because our assumption [ξ]6= [ξ¯], for all non-trivial representation.

Let us prove that bu(ξ)mn is the Fourier coefficient of a distribution u∈D(G) that is not a smooth function. Indeed, we have

|bu(ξj)mn| ≤ |mj)−q¯| ≤ |λmj|)|+|q| ≤(1+|q|) ξj

, for all 1≤m,ndξj, and

|bu(ξ¯j)mn| ≤ |p| ≤ |p|ξ¯j ,

for all 1≤m,ndξ¯j. Hence forC=max{1+|q|,|p|}, we have

|bu(ξ)mn| ≤Chξi,

for all[ξ]∈G, 1b ≤m,ndξ, which implies thatu∈D(G)by (1.5). Notice that

|bu(ξ¯j)mjn|=|p| 6=0,

for all j∈N, so we conclude thatu∈D(G)\C(G)because (1.4) does not hold.

Let us show now thatPu=0. We know that c

Pu(ξ)mn= (iλm(ξ)−q)bu(ξ)mnpbu(ξ¯)mn.

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It is enough to show thatPu(ξc j)mjn=Pu(c ξ¯j)mjn=0, for all j∈N. Indeed, we have c

Pu(ξj)mjn= (iλmjj)−q)bu(ξj)mnpu(bξ¯j)mn

= (iλmjj)−q)(iλmjj)−q)¯ −pp¯

=−λmjj)2+|q|2− |p|2i2Re(q)λmjj)

=∆(ξj)mj

=0.

Moreover,

Pu(c ξ¯j)mjn= (iλmj(ξ¯j)−q)u(bξ¯j)mnpu(ξb j)mn

= (iλmj(ξ¯j)−q)pp(iλmjj)−q)¯

= (−mjj)−q)pp(mjj)−q)

=0.

ThereforePu=0 and we conclude thatPis not globally hypoelliptic.

Notice that to construct a singular solution for the equationPu=0 in the proof of the last proposition we define the Fourier coefficient ofuat[ξj]and[ξj]and this was possible because our assumption that [ξ]6= [ξ], for all[ξ]∈G. Ifb [η] = [η]for some [η]∈G, then there exists a unitary matrixb Asuch that Aη(x) =η(x)A, for all xG, witch implies that Abu(η) =u(η)A. In this case, we could not defineb indiscriminately the values ofubatη and atη. In Section5we will present this result for a group that does not satisfy this hypothesis.

Theorem 3.2. Assume that[ξ]6= [ξ¯],for all non-trivial[ξ]∈G. If P is globally hypoelliptic, then oneb of the following conditions holds:

(1) |p|>|q|;

(2) |p|<|q|andRe(q)6=0;

(3)M>0such that

hξi ≥M =⇒ λm(ξ)2−(|q|2− |p|2)≥ hξiM, for all1≤mdξ.

Proof. Let us prove by contradiction. If none of the assumptions are satisfied, then we have two possi- bilities:

(a) |p|<|q|,Re(q) =0, and 3. does not hold;

(b) |p|=|q|and 3. does not hold.

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If (a) holds, then

∆(ξ)m=−λm(ξ)2+|q|2− |p|2, and for everyk∈N, there exists[ξk]∈Gbsuch thathξki ≥kand

|∆(ξk)mk|=| −λmkk)2+|q|2− |p|2| ≤ hξkik, for some 1≤mkdξk. Since∆(ξ¯k)mk=∆(ξk)mk andhξki=ξ¯k

, we also have

|∆(ξ¯k)mk| ≤ hξkik. If (b) holds, we have

∆(ξ)m=−λm(ξ)2+i2Re(q)λm(ξ), and for everyℓ∈N, there exists[ξ]∈Gbsuch thathξi ≥ℓand

(3.1) |λm)| ≤ hξi,

for some 1≤mdξ. In particular we have|λm)| ≤1, for allℓ∈N. Notice that

|∆(ξ)m|=|λm)|(|λm)|+2|Re(q)|)≤(1+2|Re(q)|)hξi for allℓ∈N, and again the same is true for the dual representation ¯ξ.

Hence, in both cases there exist a sequence{[ξk]}kNinGbandC>0 such thathξki ≥kand (3.2) |∆(ξk)mk| ≤Ckik, k∈N,

for some 1≤mkdξk. From now we will treat both cases altogether. Moreover, sincePis globally hypoelliptic we may assume, by Proposition 3.1, that there exists L>0 such that∆(ξk)mk 6=0, for all kL. Thus

0<|∆(ξk)mk| ≤Ckik, kL.

Define

bf(ξ)mn=



∆(ξ)m if[ξ] = [ξk]or[ξ] = [ξ¯k],m=mk

0, otherwise.

By (3.2) we have that{bf(ξ)mn}are the Fourier coefficients of a function fC(G). Let us construct now a singular solution forPu= f. Define

b

u(ξ)mn=



m(ξ)−q¯+p if[ξ] = [ξk]or[ξ] = [ξ¯k],m=mk

0, otherwise.

Notice that

|bu(ξk)mkn| ≤ |λmkk)|+|pq¯| ≤Cki,

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for allk∈N, which implies thatu∈D(G). Moreover, c

Pu(ξk)mkn= (iλmkk)−q)bu(ξk)mknpu(bξ¯k)mkn

= (iλmkk)−q)(iλmkk)−q¯+p)p(iλmk(ξ¯k)−q¯+p)

=∆(ξk)mk

= bfk)mkn.

ThereforePu(ξc )mn= bf(ξ)mn, for all[ξ]∈G, 1b ≤m,ndξ. It remains to show thatu∈/C(G). There are three situations to be consider:

(I)Re(p−q)¯ 6=0.

Notice that

|bu(ξk)mkn| ≥ |Re(u(ξb k)mkn)|=|Re(pq)¯ |>0, for allk∈N, which implies thatu∈/C(G).

(II)Re(p−q) =¯ 0 and Im(p−q)¯ 6=0.

Sinceλmk(ξ¯k) =−λmkk), we may assume without loss of generality that sgn(λmkk)) =sgn(Im(p−q)),¯

whenλmkk)6=0. Hence,

|bu(ξk)mkn| ≥ |Im(u(ξb k)mkn)|=|λmkk) +Im(p−q)¯ |>|Im(p−q)¯ |>0, for allk∈N, and again we conclude thatu∈/C(G).

(III)p=q.¯

For this case, let us construct a singular solution forPu=i f. Define

b

u(ξ)mn=



−λm(ξ)−i2p if[ξ] = [ξk]or[ξ] = [ξ¯k], m=mk

0, otherwise.

As before we haveu∈D(G). If Re(p)6=0, then

|bu(ξk)mkn| ≥ |Im(u(ξb k)m

kn)|=2|Re(p)|>0, that is,u∈/C(G). If Re(p) =0, then Im(p)6=0, becausep6=0. So,

|bu(ξk)mkn|=|λmkk)−2Im(p)|>|Im(p)|>0,

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forklarge enough, where the last inequality comes from (3.1). Henceu∈/C(G). Finally, Pu(ξc k)mkn= (iλmkk)−q)bu(ξk)mknpu(bξ¯k)mkn

= (iλmkk)−p)(¯ −λmkk)−i2p)p(−λmk(ξ¯k)−i2p)

=−mkk)2+Re(p)λmkk)

=i∆(ξk)mk

=ibfk)mkn.

So,Pu(ξc )mn=ibf(ξ)mn, for all[ξ]∈G, 1b ≤m,ndξ, hencePu=i f, which is a contradiction because

Pis globally hypoelliptic.

In order to apply Theorem3.2to give an example of an operatorPthat is not globally hypoelliptic we need to verify if the compact Lie groupGsatisfies the hypothesis [ξ]6= [ξ¯],for all non-trivial[ξ]∈G.b Since this assumption holds for Td, for any d ∈N, we conclude that the hypothesis is verified for Td×G, for anyd∈Nand any compact Lie groupG. We refer [2] and [4] for a detail discussion about representations of a product of compact Lie groups.

Example 3.3. Consider the compact Lie group G=T1×SU(2)and let P the operator defined by Pu(t,x):=∂tu(t,x) +0u(t,x)25iu(t,x)u(t,x), (t,x)∈T1×SU(2),

where0is the neutral operator on SU(2)as in Example2.3. We haveGb∼Z×12N0and the symbol of X:=∂t+∂0is given by

σX(τ, ℓ)mn=i(τ+m)δmn,

for allτ∈Z,ℓ∈12N0,−ℓ≤m,n≤ℓwithℓ−m, ℓn∈Z. Clearly conditions 1 and 2 of Theorem3.2 do not hold. Let us see that condition 3 also fails. Indeed, we have

(τ+m)2− 5

4−1=

(τ+m)2−1 4 =0

forτ=0and m=12, so condition 3 does not hold because m=12appears for allℓ∈12N0\N0. Therefore the operator P is not globally hypoelliptic.

Corollary 3.4. Assume that[ξ]6= [ξ¯],for all non-trivial[ξ]∈G, andb |p|=|q|. If P is globally hypoel- liptic, then G is isomorphic to a torus.

Proof. SincePis globally hypoelliptic, we are in the situation 3. of the Theorem3.2. Hence, using the fact the|p|=|q|, there existsM>0 such that

hξi ≥M =⇒ |λm(ξ)| ≥ hξiM,

(13)

for all 1≤mdξ. This property implies that the vector fieldX is globally hypoelliptic (Theorem 3.3 of [5]). ThereforeGmust be isomorphic to a torus, because the Greenfield-Wallach conjecture is valid for compact Lie groups, proved by Greenfield and Wallach in [3].

We point out that whenG=T2the results obtained in this section extend the results in [1] about the global hypoellipticity of the operator

Pu=∂tu+c∂xuqupu,¯

whenc∈Rbecause∂t+c∂x∈Tc2andT2satisfies the hypothesis in Theorem3.2.

Although the hypothesis Im(c)6=0 is a forth condition in Theorems2.1and3.2onT2(see Theorem 1, [1]), this does not hold in general for compact Lie groups. For instance, consider the operator

Pu=∂tu+c∂0uqupu¯

defined inG=T2×SU(2), where∂0is the neutral operator on SU(2), withc,p,q∈Csatisfying Im(c)6= 0 and|p|=|q|. The elements onGbcan be identified withZ×12N0and we have

σ0(ℓ)mn=imδmn, for allℓ∈12N0,−ℓ≤m,n≤ℓ,ℓ−m, ℓn∈Z.

Since inT2we have the property[ξ]6= [ξ¯], for all non-trivial representations[ξ]∈Tc2, this property also holds for the productT2×SU(2). In this case we can reply the same argument before the statement of Theorem2.1to obtain

∆(τ, ℓ)m=−|τ+cm|2+|q|2− |p|2i2Re(q(τ+cm)),¯

for allτ ∈Z,ℓ∈12N0,−ℓ≤m≤ℓ,ℓ−m∈Z. Moreover, we can easily adapt Proposition3.1 to this operator. Hence,

∆(0, ℓ)0=0,

for allℓ∈N, that is,∆(τ, ℓ)m=0 for infinitely many representations, which implies thatPis not globally hypoelliptic by Proposition3.1.

We also can construct a counter-example that satisfies the condition 2. on Theorem2.1. Consider the operator

Pku=∂tu+ic∂0uqupu,¯

withc,q∈R\{0}, andp∈Csatisfying|q|2−|p|2=|c|2k2, withk∈N. Notice that|p|<|q|, Re(q)6=0, and

∆(τ, ℓ)m=−|τ+icm|2+|q|2− |p|2i2qτ, for allτ∈Z,ℓ∈12N0,−ℓ≤m≤ℓ,ℓ−m∈Z. Hence,

∆(0,k)k=−|c|2k2+|q|2− |p|2=0,

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for allk∈N, which implies thatPk is not globally hypoelliptic by Proposition3.1.

4. GLOBALSOLVABILITY

A natural question that appears on the study of properties of an operator is the existence of solutions, that is, given f ∈D(G), do there existu∈D(G)such thatPu= f?

For the operator Pdefined on (1.1) there are some compatibility conditions about which f we can expect to solve the equationPu= f. Precisely, ifPu= f, then from (2.3) we have

(4.1) ∆(ξ)mu(ξb )mn= (iλm(ξ)−q)¯ bf(ξ)mn+pbf(ξ¯)mn,

for all[ξ]∈G, 1b ≤m,ndξ. Therefore, if∆(ξ)m=0, the distribution f must satisfy (4.2) (iλm(ξ)−q)¯ bf(ξ)mn+pbf(ξ¯)mn=0,

for every 1≤ndξ. ConsiderEthe subspace ofD(G)of distributions that have this property, that is, E:={f∈D(G);∆(ξ)m=0 =⇒ (iλm(ξ)−q)¯ bf(ξ)mn+pbf(ξ¯)mn=0, 1≤ndξ}.

We call the elements ofE admissible distribution for the operator Pand we say that P is globally solvable if for every f∈Ethere existsu∈D(G)such thatPu= f, that is,P(D(G)) =E.

This notion of solvability is different from the one studied on [1], where the authors considered solvability on spaces of finite codimension. For us, global solvability means to solve the equation Pu= f, for every f which this equation makes sense in terms of the compatibility condition (4.2).

Given f ∈E, our goal is to determine u∈D(G)to obtain Pu= f. By (4.1), when∆(ξ)m6=0 we have

(4.3) u(ξb )mn= 1

∆(ξ)m

(iλm(ξ)−q)¯ bf(ξ)mn+pbf(ξ)mn

When ∆(ξ)m=0 we are led to look for the conjugate representation and for this reason we will assume the condition [ξ]6= [ξ¯],for all non-trivial [ξ]∈G. Notice that ifb ∆(ξ)m=0, then∆(ξ¯)m=0.

Thus, for each pair([ξ],[ξ¯])define

(4.4)







 b

u(ξ)mn=0 b

u(ξ¯)mn=−bf(ξ)mn

¯ p ,

for every 1≤ndξ. Let us check thatPu(ξc )mn= bf(ξ)mn. Indeed, by (2.1) we have cPu(ξ)mn= (iλm(ξ)−q)u(ξb )mnpu(bξ¯)mn

=−p

−bf(ξ)mn

¯ p

= bf(ξ)mn

(15)

and

Pu(c ξ¯)mn= (−m(ξ)−q)u(bξ¯)mnpu(ξb )mn

= (−m(ξ)−q)

−bf(ξ)mn

¯ p

=

m(ξ) +q¯ p

fb(ξ)mn

Since f∈E, we have

m(ξ) +q¯ p

bf(ξ)mn= bf(ξ¯)mn, which implies that

c

Pu(ξ¯)mn= bf(ξ¯)mn= bf(ξ¯)mn,

for all 1≤ndξ. We point out that the solution given by (4.4) is not unique.

Notice that when∆(ξ)m=0, the decay ofu(ξb )mnand bf(ξ)mnare the same, then in order to guarantee thatu∈D(G)we need to estimate∆(ξ)m1, when∆(ξ)m6=0.

Theorem 4.1. Assume that[ξ]6= [ξ¯],for all non-trivial[ξ]∈G. Then P is globally solvable if and onlyb if one of the following conditions holds:

(1) |p|>|q|;

(2) |p|<|q|andRe(q)6=0;

(3)M>0such that

λm(ξ)2−(|q|2− |p|2)≥ hξiM, for all1≤mdξ, wheneverλm(ξ)2−(|q|2− |p|2)6=0

Proof. By the previous discussion, given f∈Ewe need to proof that the sequence of Fourier coefficients given by (4.3) and (4.4) defines a distribution u∈D(G). The proof of the sufficiency has the same estimates from the proof of Theorem2and will be omitted.

To prove the necessity, assume that none of the conditions 1-3 are satisfied. Proceeding analogously to the proof of Theorem3.2, we can obtain a sequence{[ξk]}kNsuch that

(4.5) 0<|∆(ξk)mk| ≤Ckik,

for some constantC>0 and 1≤mkdξk, for allk∈N. We may assume thatξk6=ξ¯, for everyk, ℓ∈N. Let us construct an admissible distribution f ∈E such that there is nou∈D(G)satisfying Pu= f. Define

fb(ξ)mn=



p1, ifξ =ξ¯kandm=mk, 0, otherwise.

(16)

Notice that this sequence of Fourier coefficients define an admissible distribution f ∈E, because if

∆(ξ)m=0, thenξ 6=ξk andξ 6=ξ¯k, for allk∈N, by (4.5). Suppose thatPu= f for someu∈D(G).

Then by (4.1) we have

∆(ξk)mku(ξb k)mkn= (iλmkk)−q)¯ bfk)mkn+pbf(ξ¯k)mkn (4.6)

= (iλmkk)−q)0¯ +pp1 (4.7)

=1, (4.8)

for all 1≤ndξk. Hence,

|bu(ξk)mkn|=|∆(ξk)mk|1C1kik,

which contradicts the fact thatu∈D(G). We have shown that there is nou∈D(G)satisfyingPu= f, with f∈E, thereforePis not globally solvable, which concludes the proof.

The next corollary is a direct consequence of Theorem3.2and Theorem4.1.

Corollary 4.2. Assume that[ξ]6= [ξ¯],for all non-trivial[ξ]∈G. If P is globally hypoelliptic then P isb globally solvable.

Thus, we have a class of examples of operatorsPthat are globally solvable by considering globally hypoelliptic operators defined on groups that satisfy the hypothesis about the representations. Let us see now that the converse does not hold.

Example 4.3. We have seen in Example3.3that the operator

Pu(t,x):=∂tu(t,x) +0u(t,x)25iu(t,x)u(t,x), (t,x)∈T1×SU(2),

is not globally hypoelliptic. However, this operator is globally solvable by condition 3 of Theorem4.1.

Indeed, if (τ+m)2− 5

4−1=

(τ+m)2−1 4 6=0, for someτ∈Zand m12N0, then (τ+m)2−1

4 > 1

4, which implies condition 3 of Theorem4.1.

Finally, let us see an example of an operator that is not globally solvable.

Example 4.4. Let G=T×SU(2)andα∈Rbe an irrational Liouville number. Consider the operator Pu(t,x):=∂tu(t,x) +α∂0u(t,x)iu(t,x)u(t,x), (t,x)∈T1×SU(2).

Notice that P does not satisfy neither condition 1 nor 2 of Theorem4.1. Assume that P satisfies condition 3, then in particular there exists M>0such that

|(τ+αℓ)2| ≥ h(τ, ℓ)iM,

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for τ ∈Z and ℓ∈N0, (τ, ℓ)6= (0,0). However, this implies that α is not a Liouville number, so the operator P is not globally solvable.

In [1] the authors proved thatPis globally hypoelliptic if and only ifPis solvable. However, since we are using a different notion of solvability, we do not have this equivalence here, as seen in the previous example.

By the expressions (4.3) and (4.4) that we have obtained for the solution of the equationPu= f, we have the following corollary:

Corollary 4.5. Assume that[ξ]6= [ξ¯],for all non-trivial[ξ]∈G. If P is globally solvable, then for everyb admissible smooth function f ∈E, there exists uC(G)such that Pu= f .

5. THE OPERATORPONSU(2)

We have supposed on Proposition3.1, Theorem3.2and Theorem4.1that every non-trivial irreducible unitary representation of the groups is not self-dual. This hypothesis came from the technique that we have used to prove these results, which was based on the torus case. In this section, we present these results for SU(2), where we have

[ξ] = [ξ¯], for all[ξ]∈ \

SU(2).

Recall from Example 2.3 that SU(2)\ consists of equivalence classes [t]of continuous irreducible unitary representations t : SU(2)→ C(2ℓ+1)×(2ℓ+1), ℓ∈ 12N0 and we use the standard convention of enumerating the matrix elementstmnoftusing indicesm,nranging between−ℓtoℓwith step one, i.e.

we have−ℓ≤m,n≤ℓwithℓ−m, ℓn∈N0.Forℓ∈ 12N0we have hℓi:=D

t E

=p

1+ℓ(ℓ+1).

Consider the operator

(5.1) Pu:=∂0uqupu,¯

where∂0 is the neutral operator, and q,p∈C, with p6=0. As mentioned in Example2.3, there is no loss of generality assuming that the vector field is ∂0because all vector fields define on SU(2) can be conjugated to∂0. We have that

σ0(ℓ)mn=imδmn, for allℓ∈12N0. Hence, we obtain

Pu(ℓ)c mn= (im−q)bu(ℓ)mnpbu(ℓ)¯ mn

= (im−q)bu(ℓ)mnpu(bℓ)¯mn,

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where ¯ℓ:=t. By the properties of representation on SU(2), we have that t(x)mn= (−1)mnt(x)mn. Hence,

b u(ℓ)¯mn=

Z

SU(2)u(x)t(x)nmdx= Z

SU(2)u(x)(−1)mnt(x)mndx

= (−1)mnu(ℓ)b mn

Therefore,

(5.2) Pu(ℓ)c mn= (im−q)u(ℓ)b mnp(−1)mnu(ℓ)b mn From (2.2) and (2.3) we obtain

∆(ℓ)mu(ℓ)b mn= (im−q)¯ Pu(ℓ)c mn+pcPu(ℓ)¯mn

= (im−q)c¯ Pu(ℓ)mn+p(−1)mnPu(ℓ)c mn, (5.3)

where

∆(ℓ)m=−m2+|q|2− |p|2i2mRe(q).

Proposition 5.1. Either∆(·)·vanishes for infinitely many representations or∆(·)·never vanishes.

Proof. Letκ∈12N0and−κ≤r≤κsuch thatκ−r∈Z. Hence, we obtain

∆(κ)r=−r2+|q|2− |p|2i2rRe(q) =∆(κ+j)r,

for all j∈N, because −(κ+j)≤ −κ ≤r≤κ≤κ+jand (κ+j)r= (κ−r) +j∈Z. Thus, if

∆(κ)r=0 then ∆(κ+j)r=0, for all j∈N. This means that once ∆(·)· vanishes, it will vanish for

infinitely many other representations.

Proposition 5.2. We have∆(ℓ)m6=0, for allℓ∈12N0,−ℓ≤m≤ℓ,ℓ−m∈N0 if and only if one of the following statements holds:

(1) |p|>|q|;

(2) |p|<|q|andRe(q)6=0;

(3)M>0such that

hℓi ≥M =⇒ m2−(|q|2− |p|2)≥ hℓiM, for all−ℓ≤m≤ℓ.

Proof. We have seen in the proof of Theorem2.1 that both conditions 1. and 2. imply that∆(ℓ)m6=0, for allℓ∈12N0. Notice that condition 3. says that Re(∆(ℓ)m)6=0, for allhℓi ≥M. In particular we obtain by the last proposition that Re(∆(ℓ)m)6=0, for allℓ∈12N0, which complete the proof of the sufficiency.

Notice that condition 3 is equivalent to

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