R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
P IERO D’A NCONA
Well posedness in C
∞for a weakly hyperbolic second order equation
Rendiconti del Seminario Matematico della Università di Padova, tome 91 (1994), p. 65-83
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for
aWeakly Hyperbolic Second Order Equation.
PIERO
D’ANCONA (*)
§
1. Introduction.We consider here the
Cauchy problem
on[0, T]
xRx ( T
>0)
where the coefficients a,
b, d, f
are C °° functions on[0, T]
xRx .
Wewill assume that Pb.
(1), (2)
isweakly hyperbolic
and that the coeffi- cienta(t, x)
isbounded, namely
and that the first order term satisfies a
Levi-type
condition of the formWe will be interested in the
global solvability
ofproblem (1), (2)
in C °° .
It is well known that the above
assumptions
are not sufficient for the wellposedness
in C °° of Pb.(1), (2);
see e.g.[CS],
where it is con-structed an
equation
of the formwith
a(t)
nonnegative
andinfinitely differentiable,
which is notlocally
solvable in C °° .
In this
counterexample
the coefficienta(t)
oscillates an infinite number of times in aneighbourhood
of the initial line. On the other(*) Indirizzo dell’A.:
Dipartimento
di Matematica, Università di Pisa, Via Buonarroti 2, Pisa.hand,
in the case when the coefficienta(t, x)
=a(t) depends only
ontime,
if it oscillatesonly
a finite number of times on[0, T],
it ispossible
to prove that the
Cauchy problem (1), (2)
is wellposed
inC °° ,
with a fi-nite loss of derivatives
depending
on the number of oscillations. More- over, in theproof
of Nishitani’s result(see [Nil])
about the local wellposedness
in C °° for(1), (2)
withanalytic coefficients,
a crucialstep
is acareful
analysis
of the zeroes ofa( t, x).
These considerations lead to the
following question:
is itpossible
toobtain a
global
existence result for(1), (2)
inC °° ,
under some apriori knowledge
of theoscillating
behaviour of the coefficienta( t, x)?
We propose here a
partial
answer. Denote withGR
therectangle [0, T ]
x[ -R, R].
LetPj(x), 1 ~ j ~
1~ - 1(k depending
ofR)
be abso-lutely continuous,
H61der continuousfunctions,
such that the set~~ (x)
=0}
has aboundary
with measure 0(or
moregenerally,
coin-cides almost
everywhere
with a set whoseboundary
has measure0).
Let moreover
0 ; ~ 1 ( x ) ~
...~ ~ k _ 1 ( x ) ~
T .Then, writing 0
for theline t =
0, ~ k
for the line t= T ,
anddenoting
withGR
the setwe shall assume that:
ASSUMPTION
(A).
3)
in eachregion Gh,
one of thefollowing inequalities holds,
forsome constant K
(depending
onj):
In § 2
we shall prove thefollowing.
THEOREM 1. Under
assumptions (3), (4)
and(A), problem (1), (2)
isglobally
2ueLLposed
in Coo.Moreover,
in § 3 we will show that a realanalytic, nonnegative
func-tion
a(t, x)
satisfiesassumption (A).
As a consequence, we shall obtain thefollowing theorem,
which extends the local result in[Nil]:
THEOREM 2. Assume
(3), (4) hold,
and thata(t, x)
is realanalytic.
Then
problem (1), (2)
isglobally
wellposed
in Coo.REMARK 1.
Assumption (A)
is of course modelled on the behaviourof real
analytic functions,
but is in fact moregeneral
than that. For in-stance,
it is satisfiedby
anyequation
of the formfor any p, q E
N, ~
e C °°(R ):
choose(and
ofcourse ~ o
=0, §
=T ).
REMARK 2. Condition A.2 is invariant under a
regular change
ofvariables. More
precisely,
suppose we aregiven
thepartial
differentialoperator
and a curve t = and
perform
a C °°change
of variables(t, x)
--~
( s, y ) leaving
the form of theprincipal part unchanged:
Denote the transformed curve with s =
~( y).
ThenUsing
anequivalent terminology,
A.2 can be restatedby saying
thatthe function t - is a time
junction
withrespect
to theoperator
d2t - a(t,x) d2x.
REMARK 3. As it is well
known,
condition(4)
is not necessary for the wellposedness
in C °° of(1), (2). Necessary
and sufficient conditionson lower order terms can be found in
[Ni3],
where theproblem
is inves-tigated
in detail.Acknowledgments.
We would like to thank Prof. S.Spagnolo
formany useful discussions about the
subject
of this work.§
2. Proof of Theorem 1.The idea of the
proof
is thefollowing.
We prove apriori
estimatesfor the solution of
(1), (2).
These estimates are of two differenttypes.
In the
regions
wherex ) ; - Kac( t, x),
we use a method due to 0.Oleinik
(see [0]).
She made a similarassumption
abouta(t, x),
but theform of the
region
was verysimple (a strip).
Here theregion
is bound-ed
by
twoabsolutely
continuous curves, and this causes some addition- al difficulties. We prove that any derivative of the solution in the re-gion
can be estimatedby
some norm of the solution restricted to the lowerboundary
of theregion.
In thecomplementary regions
weget
asimilar
result,
but thetechnique
used is the usual energy estimate of Petrowski(modified,
of course, to take into account theparticular
formof the
region).
Thus we canestimate,
in a finite number ofsteps,
thesolution on the whole
strip [0, T ]
xRx by
its norms at the timet=0.
Suppose firstly
thatu(t, x)
is a solution of(1), (2)
withcompact
sup-port (in [0, T ]
xRx)
say withsupport
contained in[0, T ]
x[ - R, R].
We can then assume that the coefficients are bounded functions
(with
all theirderivatives),
and that(4)
holds with a constant M fixed.In order to
simplify
theexposition
of theproof,
we introduce somenotations.
Given two
absolutely
continuousfunctions,
Holder continuous func- tions§(r) % §(r)
on[ -R, R],
such that the set =0 1
has aboundary
with measure 0(or
differs for anegligeable
set from a setwhose
boundary
has measure0),
and that theproducts a(~, x) ~’2,
a(~, x) ~’2
are less then1,
we writeand we call
G( ~, ~ )
aregular
domainfor
a. Sinceu( t, x )
is 0for I x I
~~
R,
we will notdistinguish
between this domain and the infinitestrip
obtained
by continuing ~, ~
as constants outside[ - R, R ].
Moreover,
ifwith y
we denote the set ofpoints
we shall write
for j integer
andv(t, x)
a C °° functionmore
generally,
for any setA,
we will writeWe
begin
with a technical lemma.LEMMA 1. Let
v(t, x)
be a Coofunction
on[ 0, T ]
xvanishing for I
~R,
and let~(x)
be a continuousfunction
on[ -R, R].
Denotewith y
the set~(t, x):
t =~(x)~.
Then there exists aC2 function w(t, x),
which is Coo outside y, and such
that,
in thepoints of y,
D " v =D " w for I « ~ I ~
2.Moreover,
w vanishesfor I x I
> R +1,
and the second deriva-tives
of
w can be estimatedby
the second derivativesof
valong
y:for
any
compact
set K there exists a constantc(K)
such thatPROOF. The
proof
is asimple application
ofWhitney’s
extensiontheorem,
for which we referto [Fe],
Th. 3.1.14. With the notations usedthere,
we define functions with a =(~( ~), ~)
E y and b ==
( t, x )
which arenothing
but theTaylor
seriesdevelopment of v( t, x )
ina, truncated to the second order and
computed
in thepoint
b. It is easy toverify
that theassumptions
ofWhitney’s
theorem are fulfilled.Moreover,
the estimate of the second derivatives of w is a consequence of theexplicit expression
for w(see [Fe],
p.226),
and w can be chosento vanish for R ’ for any R’ > R
(it
is sufficient tomultiply by
asuitable
regular
function of x alone withcompact support).
We can now prove the energy
estimates, beginning
with theregions
where
at : -
Ka.In the
following
Lemmas 2 and3,
we will assume thatv(t, x)
is asolution of the
equation
(6) (a(t, bl (t, x) vx + cl (t, x)
where
a( t, x )
is the same coefficient as in eq.(1),
while the other coeffi- cients may be different. Inparticular,
we shall assume thatFor
brevity,
in thefollowing computations
we shall omit the index 1 from the coefficients.LEMMA 2. Let G =
G(~, ~)
be aregular
domainfor
a, and supposethat
at ( t, x ) ~ - Ka(t, x )
in Gfor
some constant K. Denote with y the lowerboundary of G,
and withDt
cRx
the setThen
for inf ~ ~ t ~ sup ~
one haswhere C is a constant
depending
onM, T, ~, ~
and thecients.
PROOF.
Suppose firstly that v, vt and vx
vanishalong
y. Denote withGz
the domainGn(R,,
x[0, r]),
and define for(t, x)
EG~
The function V is well defined and continuous on
G ,
and vanishesalong
the upperboundary
ofG ;
moreoverwhere defined a.e., means 0
where ~
> r and~’
else-where
(indeed,
the functionz /~ ~ (x)
isabsolutely
continuous and hence almosteverywhere differentiable). Thus Vt
andVtx
are C °°functions;
note that
Vx
is the sum of a continuous function of(t, x),
which is regu- larin t,
and a function of xalone,
which isintegrable
on R.Multiply
nowequation (6) by Ve’,
where 0 % 0 is to bechosen,
andintegrate
overG .
Consider theresulting
terms oneby
one as in[01];
for
brevity,
we omit the domain ofintegration G,
in thefollowing integrals.
Thanks to the
particular
form of the setG ,
the firstis easy to
compute:
we have used the fact that v = vt = 0 on y, while V = 0 on the upper
boundary ~t
=~(x)~.
The second and the third
terms,
aremore
difficult,
since it is necessary tointegrate by parts
in the variablex. To
justify
this passage, it is sufficient to observethat,
at tfixed,
the( x, t )
E is open, then it consists of a countable union on in-tervals,
and in each of these theintegration by parts
can beperformed.
Since vx
vanishes on y, while V vanishes on the upperboundary
It
=~(x)~,
noboundary
terms appear. Thus we have:note
that,
thanks to(13),
theright
hand member is well defined. To es-timate the first
integral
atright
in(15),
consider the functionaV,2e"’:
thanks to
(13)
it can be differentiated w.r. tot, giving
and
hence,
asat % - Ka,
On the other
hand,
and
recalling
the Levi condition(8),
Let now 03BC = M +
I K 1. Choosing
0 = 03BC in(16)
and(17)
andsumming,
weget:
Now we
integrate
overG T. Firstly
weintegrate in t,
at xfixed,
be-tween t = and t = T
A v (x) (when
these limitscoincide,
the corre-sponding
section ofG,
isempty);
note inparticular
that(since
the function isnonnegative); but, by (13),
and hence the function
is
equal
to 0when §(r)
> r, while isequal
towhen §(r) %
r; we have used theassumption a(~, x) ~’2
1.Thus we can
integrate (18)
also in x(note
that we are forced to inte-grate first
intime,
then inspace),
toget
Now it is sufficient to observe that the functions in
(21)
are all inte-grable
onGT,
and toapply
Fubini’stheorem,
to ensure that(21)
doesnot
depend
on the order ofintegration
and is thus valid in theordinary Lebesgue
sense.The
remaining
terms areharmless; they give (recall
that 0 =~u )
We can now sum
(14), (21), (23), (24) obtaining
where the constant C
depends
on the oo norms of a,bx ,
9 c, ct , 9 d.Now the left hand member of
(25) gives
since v vanishes
along y,
whiledirectly
from def.(10)
it follows thatintroducing (26)
and(27)
in(25)
we findRearranging
the firstterm,
sincewe have
The constant
C1 depends
onM, T,
R and the supremum norms of a,bx ,
c, ct , d
(recall
that we areassuming
that v hascompact support).
To
conclude,
definefrom this it follows that
Thus
(28) implies
Applying
now Gronwall’slemma,
we conclude theproof
in thespecial
case
of v, vanishing
on the initial curve(the
boundednessof y
im-plies
the boundedness ofy’
from eq.(29) itself).
To deal with the
general
case of v notvanishing along y,
we reduceourself to the
preceding
oneby
astraightforward application
of Lem-ma 1: we consider the function
w(t, x)
furnishedby
Lemma 1 andapply
the above estimate to the difference v - w; this difference satisfies eq.
(6)
withf replaced by
anotherfunction,
whoseL 2
norm can be esti-mated
by llfll2
and the values of v and its first and second derivativesalong y (by (5)).
We now consider the
regions
where the reverseinequality holds, at ~
Ka. Let v denoteagain
a solution of(6),
such that(7), (8)
hold.LEMMA 3. Let G =
G(~, x)
be aregular
domainfor
a, and assumethat at £
Ka on Gfor
some constant K. Let as aboveDt
=t
x( x ) },
and consider the energyof
v,defined
asThen, denoting
with y the lowerboundary of G, for inf ~ ~
t ~ sup X one haswhere C is a constant
depending
onM, T,
and the supremumnorms
of
some derivativesof
thecoefficients.
PROOF. We need a formula for the derivative of an
integral
whosedomain varies with time.
More
precisely,
letF(x)
be aC 1
functionsupported
on[ - R, R ],
letan
absolutely
continuous function on[ - R, R],
and consider theintegral
where
In
general,
the function is not even continuous(consider
for in- stance the case F =1, ,8
=const.).
But if we assume that the sethas
Lebesgue
measure zero, then we claim thatIf3 (t)
isabsolutely
con-tinuous,
and its derivative isgiven
for almost any tby
the formulaindeed,
we shall prove that the setis
finite
for almostany t,
and thus the sense of(31)
is clear.To prove the
claim,
we shall use some basic tools fromgeometric
measure
theory.
The standard referenceis [Fe].
The derivative of is defined almost
everywhere,
let us denotewith
Y2
the set where the derivative off3
does not exist. We define then the setwhich is of course a
negligible
set.For a measurable set
M c Rn ,
the essentialboundary
is defined asfollows:
(where
as usualB(x, p)
is the open ball centered in x with radius p, whileIMI I
denotes the n-dimensionalLebesgue
measure of the setM).
We remark
that,
since(~’(x) ~
0 almosteverywhere,
thefollowing
holds:
( 32) a* Bf
=3~
almosteverywhere
(this
means that the two setscoincide, apart
from anegligible set).
Infact,
it is well known that the derivative of anabsolutely
continuousfunction
f3(x)
isgiven,
where itexists, by
the usual limitand
assuming
that this limit is different from 0 at somepoint x
etaking h
smallenough
it is easy to see thatBut in
fact,
ifZ,
we have instead of(32)
since,
for such valuesof t, 9~
consistsexclusively
ofpoints
whereexist and is
different from
0. This fact willplay
animportant
role in thefollowing.
We shall need a
special
case of the so-calledFleming-Rishel formu-
La
(or
coareaformula);
for thegeneral
result see[Fe 4.5.9]
or[Gi].
Itstates that if
g(x)
is anonnegative
Borel function on R(or
boundedBorel), and f (x)
isabsolutely
continuous on the bounded open set ~2c R,
then
where is the Hausdorff zero-dimensional measure on
R,
which isnothing
but thecounting
measure on R.(To
beprecise,
the usualcoarea formula holds for
f(x) Lipschitz continuous;
but in dimension 1 thisassumption
can be relaxed to since there exists([Fe] 3.1.16)
asequence of
compact
sets such thatS~ B U Kk
isnegligible
andf (x)
restricted toKk
isLipschitz).
Note the
following
consequence of the formula:given
a functionf e
the set a*f (x)
>t}
is finite for almostany t (a
fact that isnot
immediately intuitive).
We
apply
now the coarea formula with(recall
0a.e.) and,
fixedt2 > tl ,
We thus obtain
but
recalling (33),
the observationfollowing
it and the definition ofthis can be rewritten as
This means that is
absolutely continuous,
and that(31)
holds.An immediate consequence of
(31)
is thefollowing
moregeneral
for-mula,
valid for anyF( t, x )
of classC 1 (say)
andvanishing
for x outsidesome
compact
set:We shall now
apply (35)
to prove an energy estimate for solutions of(6).
Suppose v(t, x)
is a solution of(6) vanishing
with its derivatives up to the second orderalong
y. The functionv( t, x )
defined asis also
C2 (but
is a solution of(6) only T).
Now we shall construct a sequence of
absolutely
continuousfunctions such
that,
on[ - R, R ], x( x ),
0 almost every-where,
xk - xuniformly
on[ - R, R ],
andeventually
To this
end,
we take a sequence ofpositive numbers Ek 10
with theproperty
that the =± E k I
have measure 0.Moreover,
we recall that the =
0}
coincides a.e. with a set A whoseboundary
has measure 0. Let C be the closure
of R B A; C
and A have the sameboundary. Moreover,
the functionp(x)
=dist (x, C)
isLipschitz
contin-uous, and
by
theproperties
of C it follows thatp’ -
0 a.e. on C andp’ =
= ± 1 elsewhere. Then the functions = have all the
required properties.
Let now
Bt
= 0 ~ t and considerNote that
Ek (t)
is anintegral
of the formIXk(t), fulfilling
the assump- tions relative to formula(35). Applying (35)
weget,
for almostevery t,
(note
that in the last sum =t).
The firstintegral Ik(t) gives
(we
haveintegrated by parts
and usedequation (6);
note thatsince Vt
vanishes in the
region
between t = 0 and t =~(x)
the aboveinequality
is
correct,
eventhough v
is not a solution of(6) there); estimating
thelower order terms with
Ek ,
andusing
the Levicondition,
weget
(recall
the aboveexpression
for where the constant Cdepends
onthe supremum norms of
b, c,
d and onM, R,
T .Now,
sincex) x k ( x )2 ~ 1,
we haveand
summing
upIntegrating
between 0 and t(as evidently Ek(0)
=0)
we haveWe can now pass to the limit k ~ ~
observing
thatand that
Ek (t) (E(t) (in
fact we havesince v vanishes below we
get
Since
at %
Kac in theregion
G underconsideration,
the second term ist
not
greater than I K I
Thus weget
and
applying
Gronwall’s lemma we obtain the estimatewith C
depending
onM, R, T,
vo and the supremum norms of the coefficients.In the
general
case, when v does not vanish up to the second orderalong y,
weapply
as above Lemma 1.We can now conclude the
proof
of Theorem 1.Let u be a solution with
support
in[0, T ]
x[ - R, R]. Suppose
thatin the first
region GR (with
lowerboundary
the initialline) at * -
Ka(the
other case is of coursesimilar).
Then Lemma 2 allows to estimate u in the normLtoo (Lx )
and thus in the norm ofNow differentiate eq.
(1)
withrespect
to x. It is easy toverify
thatthe
equation
thus obtained isagain
of thetype (6),
with(7)
and(8)
ful- filled. Infact,
b isreplaced by
ax , for which a conditionanalogous
to(8) holds, namely
the well knowninequality (ax )2 s cllaxxlloo
a; moreover,1 + fx
+dx u,
which is a sum of terms for whichL 2
estimates arealready
available.
Similarly, proceeding by induction,
one can estimate all k- derivatives of u in theL 2
norm on the firstregion.
Now derivate withrespect
to t once, and any number of times withrespect
to x;applying
again
the Lemmas we can estimate all the derivatives of u of the formDt Dx
in term of the initial values and of the derivativesalready
esti-mated. Proceed
by
induction. At theend,
we obtain aL 2
estimate for all the derivatives of u in the firstregion.
Thisimplies
also the bound- edness in L °° of all the derivatives of uby
Sobolevimmersion; indeed,
we remark that the
embedding
theorems for Sobolev spaces holds also for ourregular domains,
with different indexesdepending
on the Hold-er
regularity
of theboundary (see
e.g.[Ma]).
Inparticular,
we have L °°estimates for the value of u and its derivatives
along
the upper bound- ary of the firstregion,
which is the lowerboundary
of the second re-gion.
Thus one can startagain
the method in the secondregion, apply- ing
Lemma 1 or 2according
to thetype
of theregion.
In a finite number of
steps,
we reach the line t = T.To
conclude,
supposearbitrary
C °° data uo , ul aregiven. Using
apartition
ofunity,
reduce theproblem
to the case in which the data uo , ul and thefunction f (t, x)
vanish forI
> R. If weapproximate
uo , ul withGevrey
data withcompact support (in
thetopology
ofC °° ),
wellknown theorems furnish us a sequence of
approximate
solutions(see [Ni2]). They
havecompact support,
since the finitespeed
of propa-gation property
holds forweakly hyperbolic equations
in the class ofGevrey
functions(see
theAppendix of [D]);
thus we canapply
the apriori
estimate obtainedabove, obtaining
the C °° convergence of theapproximate
solutions to a solution of theoriginal problem.
Finally,
we can sumtogether
the various solutionscorresponding
tothe
compactified
data: the sum will belocally
finite atevery t
> 0 since theslope
of the domain of influencedepends only
on the supremumnorm of
a( t, x),
which is boundedby assumption.
This concludes the
proof
of Theorem 1.3. Proof of Theorem 2.
Let
a(t, x)
be anonnegative,
realanalytic
function onR2.
We shallprove that the
rectangle GR = [ o, T ]
x[ - R, R ]
can bepartitioned
in afinite number of
regions satisfying assumption (A).
We shall
firstly
prove that(A)
holdslocally, i.e.
in theneighbour-
hood of each
point ( to , xo).
It is not restrictive to assume that(to, xo) = (0, 0).
We shall need the
following properties
of the functiona(t, x),
whichare
proved
in Lemma 2.2 of[Nil]. By
Weierstrass’preparation
theo-rem the set
can be described near
(0, 0)
as the union of a finite number of curves,ti (x),
... ,tm(x),
m >0, and, possibly,
of the =0).
The curvest = have the
following properties:
= 0 for allj,
and more
precisely
the first 1 functionstl (x),
...,tl (x)
are realvalued;
moreover is
analytic
for x ~0,
H61dercontinuous,
and for x -~ 0 the estimateshold,
for some rational a > 0(depending
onj). Writing
we have near
(0, 0),
for some constantsC, K,
(this
is an immediate consequence of(2.5)
in[Ni])
and(this
isexactly (2.6)
of[Nil], together
with theargument following it);
one has
analogously
Suppose
now thatat (t, x)
vanishesalong
the(real)
curve tsuch
that §(0)
= 0.By possibly restricting
theneighbouhood,
we canassume that one of the
following
alternatives holds: either~
t(x),
ort(x).
In the first case, it is easy to see thatthis follows from
(37)
and the fact thatfor some rational 7 > 0. The same
argument
shows thatNow is it
possible
to construct the curvesrequired
in ass.(A)
in aneighbourhood
of(0, 0).
Restrict theneighbourhood
so that all the ze- roes ofa(t, x), at (t, x)
can be described asabove,
and each real zero ofat (t, x)
verifies one of theinequalities
or ~t(x).
Then thewill be the real zeroes
lying
between - andt(x), plus
the two curves t = -t(x)
and t =t(x), arranged
inincreasing
order. In
fact,
A.1 isevidently satisfied,
A.2 follows from(40)
and(41), possibly restricting
theneighbourhood; finally,
A.3 is obvious in theregions
boundedby
the real zeroes of at(since
at has constantsign
onthem)
and follows from(38)
and(39)
in theremaining
upper and lowerregions.
Now to conclude the
proof,
divide therectangle GR
in horizontalstrips
ofheight
E, and divide eachstrip
intriangular
cellsaccording
tothe
pattern
shown in thepicture:
The
slope a
of theoblique
sides isgiven by
With this choice if a
piece
of oneoblique
side is used in order to construct one of the ass. A.2 will beautomatically
satis-fied
along
it.Since as 6 - 0 the diameter of the
triangles
can be madearbitrarily small,
we canapply
the above local result to eachcell;
thus we can as-sume that each cell can be
partitioned according
toassumption (A).
Now it is sufficient to
orderly patch pieces
of the horizontallines, pieces
of theoblique sides,
and the curves into eachcell,
to obtain theglobal
curvesrequired
in ass.(A).
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