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Number theory
Many values of the Riemann zeta function at odd integers are irrational
Beaucoup de valeurs aux entiers impairs de la fonction zêta de Riemann sont irrationnelles
Stéphane Fischler
a, Johannes Sprang
b, Wadim Zudilin
c,
daLaboratoiredemathématiquesd’Orsay,UniversitéParis-Sud,CNRS,UniversitéParis-Saclay,91405Orsay,France bFakultätfürMathematik,UniversitätRegensburg,93053Regensburg,Germany
cDepartmentofMathematics,IMAPP,RadboudUniversity,POBox9010,6500GLNijmegen,theNetherlands dSchoolofMathematicalandPhysicalSciences,TheUniversityofNewcastle,Callaghan,NSW2308,Australia
a r t i c l e i n f o a b s t r a c t
Articlehistory:
Received29March2018
Acceptedafterrevision17May2018 Availableonline28May2018 PresentedbyJean-PierreSerre
Inthisnote,weannouncethefollowingresult:atleast2(1−ε)log logslogs valuesoftheRiemann zetafunctionatoddintegersbetween3andsareirrational,where
ε
isanypositivereal numberandsislargeenoughintermsofε
.Thisimprovesonthelowerbound1+1−εlog 2logs that followsfromthe Ball–Rivoaltheorem. Wegive the mainideas oftheproof, which isbasedonaneliminationprocessbetweenseverallinearformsinoddzetavalueswith relatedcoefficients.©2018Académiedessciences.PublishedbyElsevierMassonSAS.Thisisanopenaccess articleundertheCCBY-NC-NDlicense (http://creativecommons.org/licenses/by-nc-nd/4.0/).
r é s um é
Dans cette note, on annonce le résultat suivant : au moins 2(1−ε)log loglogss valeurs de la fonction zêtade Riemannauxentiers impairscompris entre3and s sontirrationnelles, où
ε
estunréelstrictementpositifetsunentierimpairsuffisammentgrandenfonction deε
.Ceciaméliorelaborne1+1−εlog 2logsquidécouleduthéorèmedeBall–Rivoal.Ondonne lesidéesprincipalesdelapreuve,quiestfondéesurunprocédéd’éliminationentredes formeslinéairesenlesvaleursdezêtaauxentiersimpairsdontlescoefficientssontreliés.©2018Académiedessciences.PublishedbyElsevierMassonSAS.Thisisanopenaccess articleundertheCCBY-NC-NDlicense (http://creativecommons.org/licenses/by-nc-nd/4.0/).
Versionfrançaiseabrégée
Danscettenote, onannoncelerésultat suivant(voirlaversion anglaisepourunbrefhistorique).Onnedonnequeles idéesprincipalesdelapreuve(voir[5] pourlapreuvecomplète).
E-mailaddresses:stephane.fi[email protected](S. Fischler),[email protected](J. Sprang),[email protected](W. Zudilin).
https://doi.org/10.1016/j.crma.2018.05.007
1631-073X/©2018Académiedessciences.PublishedbyElsevierMassonSAS.ThisisanopenaccessarticleundertheCCBY-NC-NDlicense (http://creativecommons.org/licenses/by-nc-nd/4.0/).
Théorème1.Soient
ε >
0ets≥3unentierimpairsuffisammentgrand(enfonctiondeε
).Alors,parmilesnombresζ (
3), ζ (
5), ζ (
7), . . . , ζ (
s),
aumoins
2(1−ε)log loglogss sontirrationnels.
Soient
ε >
0 et sun entierimpair suffisamment grand(en fonctiondeε
). Onnote D leproduit de touslesnombres premiersinférieursouégauxà(
1−2ε )
logs,detellesortequ’ona D≤s1−ε.Ensuivantessentiellement[10],onconsidère, pourtoutentiern,lafractionrationnelleRn
(
t) =
D3Dnn!
s+1−3D 3Dnj=0
(
t−
n+
Dj)
nj=0
(
t+
j)
s+1et,pourtout j∈ {1
, . . . ,
D},onpose rn,j=
∞ m=1Rn
m+
jD
.
RappelonsquelafonctionzêtadeHurwitzestdéfiniepar
ζ (
i, α )
=∞n=0 1
(n+α)i pour
α >
0 eti≥2.EndéveloppantRn(
t)
enélémentssimples,ondémontre,commedans[10],quern,j
= ρ
0,j+
3≤i≤s iimpair
ρ
iζ
i
,
j D.
Enoutre,ennotantdnlepluspetitcommunmultipledesnpremiersentiers,onmontrequedns++11estunmultiplecommun desdénominateursdesnombresrationnels
ρ
0,jetρ
i.Lepointcrucial,commedans[10],estl’identitésuivante,valablepourtoutdiviseurddeD etpourtoutentieri≥2 :
dj=1
ζ
i
,
jD d
D
=
dj=1
ζ
i
,
j d=
∞n=0
dj=1
di
(
dn+
j)
i=
diζ (
i).
Eneffet,cetterelationmontrequ’enposantrn,d=d j=1rn,jD
d,ona :
rn,d
=
dj=1
ρ
0,jDd
+
3≤i≤s iimpair
ρ
idiζ (
i).
Notons D l’ensemble des diviseursde D. Pour toutd∈D et pourtout entiern, ona donc unecombinaison linéaire rn,d de1,
ζ (
3)
,ζ (
5)
,. . . ,ζ (
s)
.Pour toutentieri impaircompris entre3ets,lecoefficientdeζ (
i)
estρ
idi (oùlenombre rationnelρ
i dépendimplicitementden,maispasded).Sidesentierswd,d∈D,vérifientd∈Dwddi=0 pouruncertain i,alorslacombinaisonlinéaire
rn=
d∈D
wdrn,d (0.1)
ne faitplus apparaître
ζ (
i)
.Le point central dece procédé d’élimination(mis au point par letroisièmeauteur [12] pour D=2,etgénéraliséparledeuxièmeauteur[10])estquelecoefficientdidépendded,maispasden:onpeutchoisirles entiers wd indépendammentden.Pour démontrer le théorème 1, on suppose que, parmi
ζ (
3)
,ζ (
5)
, . . . ,ζ (
s)
, le nombre d’irrationnels est inférieur à 2(1−3ε)log loglogss;ilestalorsinférieurouégalà
δ
−1,oùδ
=CardDestlenombredediviseursdeD.Ilexistedoncdesindices impairsi1<
i2< . . . <
iδ−1 comprisentre3etstelsquetoutevaleurirrationnelleζ (
i)
,aveci impaircompris entre3ets, soitl’unedesζ (
ij)
.Onpeutchoisirdesentiersrelatifs wd nontousnuls(pourd∈D)telsqued∈D
wddij
=
0 pour toutj∈ {
1, . . . , δ −
1}.
(0.2)Larelation(0.1) définitalorsunesuite
(
rn)
n≥1denombresréelsquisontdescombinaisonslinéairesàcoefficientsrationnels de 1 etdesζ (
i)
pour i impair,3≤i≤s.La propriété cruciale estque lesζ (
ij)
nefigurent plus dansces combinaisons linéaires,sibienquetouslesζ (
i)
quiyapparaissentavecuncoefficientnonnulsont,parhypothèse,desnombresrationnels.En multipliant par un dénominateur commun A de ces nombres rationnels, et aussi par dns++11 (quiest un dénominateur commun des coefficients
ρ
i etρ
0,j), on obtientune suite d’entiers relatifs.Une étude asymptotique des suites(
rn,j)
n≥1 montrequecettesuited’entiersrelatifstendvers0,doncestidentiquementnulleàpartird’uncertain rang ;précisément, ona,quandn→ ∞:Adns++11
rn=
d∈D
wdd
+
o(
1)
Adns++11rn,1
,
avec 0<
limn→∞
Adsn++11rn,1 1/n<
1où o
(
1)
est une suite qui tend vers 0 quand n tend vers l’infini. Cela imposed∈Dwdd=0. Autrement dit, tout fa- mille
(
wd)
d∈D d’entiers relatifs vérifiant (0.2) devrait vérifier aussid∈Dwdd=0. Ce n’est pas le cas, car la matrice [dij]d∈D,0≤j≤δ−1 (dans laquelleon posei0=1) estinversible : sondéterminant estleproduitd’un déterminantde Van- dermondeetd’unpolynômedeSchur,quiestunpolynômeàcoefficientsentiersnaturelsévaluéenlafamilledesdiviseurs de D.
1. Introduction
When s≥2 is an eveninteger, thevalue
ζ (
s)
oftheRiemannzetafunction isa non-zerorationalmultipleofπs and, therefore,atranscendentalnumber.Ontheotherhand,veryfewresultsare knownonthezetavaluesζ (
s)
whens≥3 is odd,thoughweexpectthemalltobetranscendental.It was onlyin 1978whenApéry astonished themathematicscommunity by hisproof [1] ofthe irrationalityof
ζ (
3)
, withthenextbreakthroughinthisdirectiontakenin2000byBallandRivoal[2,8],whoprovedthefollowingtheorem.Theorem1(Ball–Rivoal).Let
ε >
0,ands≥3beanoddintegersufficientlylargewithrespecttoε
.Then dimQSpanQ(
1, ζ (
3), ζ (
5), ζ (
7), . . . , ζ (
s)) ≥
1− ε
1
+
log 2logs.
Inspiteof severalrefinements[2,11,4] for smalls,thelower bound inTheorem 1hasnever beenimprovedforlarge valuesofs.TheproofofTheorem1appliesNesterenko’slinearindependencecriterion[7] tocertainlinearcombinationsof oddzetavalues.Toimproveonthisboundusingthesamestrategy,onehastofindlinearcombinationsthatareconsiderably smaller,withnottoolargecoefficients — thiscomesouttobearatherdifficulttask.
Thesituationhasdrasticallychangedwhenthethirdauthorintroduced[12] anewmethod,whichhasbeengeneralized bythesecondauthorin[10].Foragiveninteger D
>
1 andacertainrationalfunction R(
t)
,theseries dj=1
∞ t=1 R t+
jd
,
whered|
D,
givesQ-linearcombinationsof1
,
d3ζ (
3),
d5ζ (
5), . . . ,
dsζ (
s)
withcoefficientsindependentofd(exceptthatof1).Thismakes itpossibletoeliminate fromtheentirecollectionoftheselinearcombinationsessentiallyasmanyoddzetavaluesasthe numberofdivisorsofD.Forapplicationsofthisidea,see[12,6,10,9].In thisnote, we sketch the proof of the following result, buildingupon the approach in[12] and[10]. We refer the interestedreadertothefullversion[5] ofthepaperfordetails.
Theorem2.Let
ε >
0,ands≥3beanoddintegersufficientlylargewithrespecttoε
.Thenamongthenumbersζ (
3), ζ (
5), ζ (
7), . . . , ζ (
s),
atleast
2(1−ε)log loglogss areirrational.
Incomparison,Theorem 1givesonly 1−ε
1+log 2logsirrational oddzetavalues,buttheyarelinearlyindependentoverthe rationals,whereasTheorem2endsuponlywiththeirirrationality.
OurproofofTheorem2followstheabove-mentionedstrategyfrom[12] and[10].Themainnewingredient,compared to the proof in [10], is taking D large (about s1−ε) and equal to the product ofthe first prime numbers (the so-called primorial) — suchanumberhasasymptoticallythelargestpossiblenumberofdivisorswithrespecttoitssize.
2. SmalllinearformsinvaluesoftheHurwitzzetafunction
Let sand D be positiveintegers suchthat sisodd ands≥3D.Letnbe apositive integer,such that Dniseven. We considerthefollowingrationalfunction:
Rn
(
t) =
D3Dnn!
s+1−3D 3Dnj=0
(
t−
n+
Dj)
nj=0
(
t+
j)
s+1which,ofcourse,dependsalsoonsandD,andfor j∈ {1
, . . . ,
D}welet rn,j=
∞ m=1Rn
m+
jD
.
We write dn for lcm
(
1,
2, . . . ,
n)
.Expanding Rn(
t)
into partial fractionsyields thefollowing Q-linearcombinations of valuesoftheHurwitzzetafunction.Lemma1.Foreach j∈ {1
, . . . ,
D},wehavern,j
= ρ
0,j+
3≤i≤s i odd
ρ
iζ
i
,
j Dwith
dns+1−i
ρ
i∈ Z
for i∈ {
3,
5, . . . ,
s}
and dsn++11ρ
0,j∈ Z
for any j∈ {
1, . . . ,
D}.
Wepointoutthatthecoefficient
ρ
iofζ (
i,
Dj)
inthelinearformrn,j doesnotdependon j.Theexpansionofrn,j isvery classical; onlyoddzetavaluesappearbecauseofthesymmetryphenomenonfrom[2].Theproofthatdsn+1−iρ
i∈Zforodd ifollowsthatof[3,Lemma 4.5].Thelastassertion,namelydns++11ρ
0,j∈Z,isprovedasin[10,Lemma 1.4].An important feature ofthe linear formsrn,j is that they are simultaneouslyvery small: even when multipliedby a commondenominatoroftherationalcoefficients,theystilltendto0.
Lemma2.AssumethatDlogs D largerthansomeeffectivelycomputableabsoluteconstant.Thenwehave
nlim→∞rn1/,nj
=
g(
x0) <
3−(s+1) and limn→∞
rn,j
rn,j
=
1 for any j,
j∈ {
1, . . . ,
D},
where
g
(
x) =
D3D(
x+
3)
3D(
x+
1)
s+1(
x+
2)
2(s+1)andx0istheuniquepositiverootofthepolynomial
(
X+3)
D(
X+1)
s+1−XD(
X+2)
s+1.The followingelementarylemmaaboutthenon-vanishingofgeneralizedVandermondedeterminantsisusedtogetrid ofunwantedirrationaloddzetavalues(in§3below).
Lemma3.Fort≥1,letx1
, . . . ,
xtbepairwisedistinctpositiverealnumbersandα
1, . . . , α
tpairwisedistinctnon-negativeintegers.Thenthematrix[xαji]1≤i,j≤thasnon-zerodeterminant.
3. Eliminationofoddzetavalues
Take0
< ε <
13,andletsbeoddandsufficientlylargewithrespecttoε
.WeletD betheproductofallprimeslessthan orequalto(
1−2ε )
logs,sothat D≤s1−ε.Noticethat D hasδ
=2π((1−2ε)logs)divisors,withlogδ
≥(
1−3ε )(
log 2)
log loglogss. Assume that thenumberofirrational oddzetavaluesbetweenζ (
3)
andζ (
s)
islessthanorequal toδ
−1.Let3=i1<
i2
< . . . <
iδ−1≤sbe oddintegers such that ifζ (
i)
∈/
Q andi isodd, 3≤i≤s, then i=ij for some j.Moreover, we let i0=1,andconsiderthesetDofalldivisorsofD,sothat CardD=δ
.Lemma3showsthat thematrix[dij]d∈D,0≤j≤δ−1 is invertible.Therefore,thereexistintegers wd∈Z,whered∈D,suchthatd∈D
wddij
=
0 for any j∈ {
1, . . . , δ −
1}
andd∈D
wdd
=
0.
(3.1)Thecrucialpoint(asin[10,§3])isthatforanyd∈Dandanyi≥2,
dj=1
ζ
i
,
jD d
D
=
dj=1
ζ
i
,
j d=
∞n=0
dj=1 di
(
dn+
j)
i=
diζ (
i).
Lemma1impliesthatthequantitiesrn,d=d j=1rn,jD
d arelinearformsintheoddzetavalues:
rn,d
=
dj=1
ρ
0,jDd
+
3≤i≤s iodd
ρ
idiζ (
i),
(3.2)whileLemma2leadstothefollowingasymptotics:
rn,d
= (
d+
o(
1))
rn,1 with limn→∞r1n,/1n
=
g(
x0).
(3.3)Weshallusenowtheintegers wd toeliminate
δ
−1 oddzetavalues,includingallirrationalones, asin[12] and[10].Forthat,introducern=
d∈Dwdrn,d.Eqns. (3.1)–(3.3) implythat
rn=
d∈D wd
dj=1
ρ
0,jD d+
i∈I
ρ
i d∈Dwddi
ζ (
i) =
d∈D
wdd
+
o(
1)
rn,1
,
where I= {3
,
5,
7, . . . ,
s}\ {i1, . . . ,
iδ−1}.In particular,no irrationalzetavalueζ (
i)
,where3≤i≤s,appearsin thislinear combination, and limn→∞|rn|1/n=g(
x0) <
3−(s+1) sinced∈Dwdd=0. Denoting by A a common denominator ofthe (rational)numbers
ζ (
i)
,i∈I,wededucefromLemma1that Adsn++11rnisaninteger.Nowtheprimenumbertheoremimplies thatdn1/+n1→easn→ ∞,hencefromLemma2weconcludethatthesequenceofintegerssatisfies0
<
limn→∞
|
Adsn++11rn|
1/n=
es+1g(
x0) <
e 3 s+1<
1.
ThiscontradictionimpliesthetruthofTheorem2.
Acknowledgements
WethankMichelWaldschmidtforhisadvice,andOleWarnaarforhiscommentsonanearlierdraftofthepaper.
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