Linear independence of values of
acertain
generalisation of the exponential function 2014
a newproof of
atheorem of Carlson
par ROLF WALLISSER
RÉSUMÉ. Soit
Q
unpolynôme
non-constant à coefficients entiers,sans racines sur les nombres entiers
positifs.
Nous donnons ici,essentiellement avec la méthode de Hermite, une nouvelle démon-
stration de
l’indépendence
linéaire de certaines valeurs aux pointsrationnels de la fonction
xn Q(1)Q(2) ... Q(n).
ABSTRACT. Let Q be a nonconstant
polynomial
with integercoefficients and without zeros at the non-negative integers. Es-
sentially
with the method of Hermite, a newproof
is given onlinear
independence
of values at rational points of the functionxnQ(1)Q(2)... Q(n).
1. Introduction
Let
Q
E be a nonconstantpolynomial
ofdegree
q withinteger
coefficients and without zeros at the
non-negative integers.
Carlson[2]
investigated already
in 1935 the arithmetical nature of values of the functionFor n = 0 we define
Q(1) ... Q(n)
to beequal
to one.Carlson proves:
Theorem 1. Let al, ... , ah be any
pairwise
distinct non-zero rationalnumbers. Then we have
for
thefunction
G(compare (1))
that the valuesare
linearly independent
over thefield Q of
rational numbers.Remarks.
i)
G satisfies a linear differentialequation
oforder q
with coefficients which arepolynomials
overQ.
Therefore it is notpossible
toreplace
in the theorem the order
(q - 1)
of differentationby
ahigher
one.ii)
One can assume that the numbersa~ (1 j G h)
in the theorem areintegers.
To showthis,
let us denoteIf the theorem is
proved
forintegers
aj we use this result for the function""" ’"""
The term on the left in this relation is
by
definition of G* anda*
:==equal
toCarlson’s
proof depends
on a certainPad6-approximation
ofG,
a rep- resentation of the remainder termby
anintegral
and a careful evaluation of this termusing
a Laurentdevelopment
aboutinfinity. Applying
themethod of
Siegel-Shidlowskij
similarresults, qualitative
andgood quanti-
tative ones, were obtained
mainly by
the Russian school(compare [4],
pp.128-136).
In this paper we use in
principle
the same method which Hermiteapplied
to establish the transcendence of the basis of the natural
logarithm.
LikeHilbert
[7]
and Hurwitz[8]
weapply divisibility properties
to show thenon-vanishing
of a certain sum ofintegers.
Aside theexponential function,
this way was
mainly
usedby
Skolem[12]
toget
results on theirrationality
of certain numbers. We take the method of Hermite in the form as it is described in Perron
[10]
and Skolem[12],
andregain
in asimple
way the result of Carlson.2. The method of Hilbert-Perron-Skolem Let
One chooses a
"starting-polynomial"
and derives from P m other
polynomials:
The "approximating-polynomial"
P*belonging
to P is thefollowing:
m
Remark. If
f
denotes theexponential
function(e.g Q(x)
= x orkn
=1,)
n.one has the relation
°
Using
the relations(4)
and(5)
one obtainsand with
f (0)
=ko
= 1Finally
it follows for the " remainder-term"with
(7)
and(8)
To prove theorem 1 one has to show that for every non-zero vector
the linear form
does not vanish.
To show this one uses the
"approximating-polynomial"
P*(compare (6))
to introduce the linear form
Using
the "remainderterm" 0(x) (compare (9))
onegets
thefollowing
connection between the linear forms 1’1 and
If one chooses an
appropriate "starting-polynomial"
P one can showfirstly
that the linear form A* is different from zero and
secondly
thatIn this way one
gets
from(14)
Form this
inequaliy
one concludesA ~
0 which proves theorem 1.Remark. In the paper of Skolem
[12]
and in[1]
one finds furtherapplica-
tions of the method of Hilbert-Perron-Skolem.
3. The form of the
polynomials P~,
in thespecial
case of thefunction G defined in 1.
We
apply
now the method of Hilbert-Perron-Skolem described inChap
2 to the function G defined in
Chap
1. In this case the valueskn
in(3)
aregiven by
Let 6 denote the
operator x-4-.
The function G(compare (1))
satisfies the linear differentialequation
oforder q, (compare [4], Chap 2,
6.1. formula(85)).
If one
applies
toP,,
onegets
If the
"starting-polynomial" Po(x)
:=P(x)
vanishes at zero with multi-plicity
mo, it followsand from
(19)
we haveAt the end of this
chapter
we will prove a connection of theoperators ð
andD =
d giving
with(21)
thefollowing representation
of thepolynomials
The coefficients are
integers
and ifQ
E has the formone
gets
for thehighest
coefficient ofP,
Lemma 1. For 6 =
x dx
and D= dx
we haveBeweis. The lemma holds
for j
= 0. Assume that the lemma has been verifiedfor j
=0,1, ... ,
k. From this inductivehypothesis
one deduces:The lemma follows
by
induction.Beweis. From Lemma 1 we
gain
(ii)
We use induction.Clearly
the formula holds for J1 = 0. Assume thatii)
is
proved
for J1 =0, l, ...
,1~. For thefollowing
it is not necessary to havean
explicit expression
for the numbers aj,,for j = 0, ... , 1, /~>1.
To finish the
proof,
we see4. A survey of some results on
higher
congruencesLet P denote the set of
prime
numbers. For theproof
of theorem 1one needs some results on those
primes
p E P for which the congruence=
0(modp)
is solvable. Here denotes apolynomial
with ra-tional
integer
coefficients which is notidentically
zero(modp).
Moreoverresults on those
primes
p are needed for which thegiven polynomial splits
mod p in
degree
off (deg f )
linear factors. Inalgebraic-number-theory
onecan find many papers in this direction
going essentially
back to Dedekind[3]
and Hasse[6].
Gerst and Brillhart[5]
havegiven
an excellent moreelementary
introduction to theseproblems.
For betterreadability
of thiswork I mention here some
notations, definitions,
conclusions and theorems.All
proofs
of these results can be found in[5].
Definition 1. A
prime
p for whichf (x)
is notidentically
zero(modp)
and for which the congruence
f (x) - 0( mod p)
is solvable is called aprime
divisor of
f .
Proposition
1. Schur[11]
has shown that every nonconstantpolynomial
f
has an infinite number ofprime
divisors.Definition 2. Let
f (x)
=all /3i
EZ, /3i
>0, fi(x)
E dis-tinct, primitive
andirreducible)
be theunique
factorisation off (x)
intoirreducible
polynomials.
will be said to"split completely" (mod p),
pa
prime,
iff eachfi(x)
iscongruent (mod p)
to aproduct
ofdeg fi
distinctlinear factors and p doesn’t divide the discriminant of
g(x) == I1 fi(x).
If f(r) "splits completely" (mod p)
then iscongruent (mod p)
to aproduct
ofdeg f
linear factors of the form ax +b,
a, b EZ,
It is thisproperty
which is needed in our prove of theorem 1.Theorem 5 of the work of Gerst and Brillhart
[5] gives
ageneral
infor-mation on the
prime
divisors of apolynomial.
Thefollowing Proposition
2is
proved
there as acorollary (compare [5],
page258).
Proposition
2.Every
non-constantpolynomial f (x)
has an infinite num-ber of
prime
divisors p for which it"splits completely" (mod p).
5. The choice of
the "starting-polynomial" P
and somedivisibility properties
of the valuesTo prove theorem 1 one can assume that in
(11)
or(12)
not all of thenumbers s(v) ( 1 j h, 0 v q - 1)
are zero.Let the value be the
"highest"
term in(11)
which is different from zero; that is:So in case
(25)
the linear form A* of(13)
has the formLet p E P be a
prime
number which satisfies the relation:(26) Q "splits completely" (mod p)
(compare
Definition 2 andProposition
2 inChap 4).
Choose asufficiently large
p with(26)
which fulfills in addition the conditionsL.
Define the
"starting-polynomial"
P of the method of Hilbert-Perron- Skolem(compare Chap 2, (4))
in thefollowing
way:Then the derivatives of P
satisfy
the relations:The
Taylor development
at x = 0 ofthe "starting-polynomial"
Pbegins
with the term
cxp’q,
0. Therefore one concludes from(20)
From
(22)
onegets for p
p - qand from this follows with
(29) for >
pFrom
(27), (32)
and(33)
one concludesWith
(29)
and(31)
onegets (the
same holds for ao :=0),
To find such
properties for J-L 2:
p, one takes therepresentation
which follows from(5)
and one expresses -yn -
kn-/-L (compare
the definition ofkn
in(17))
in thefollowing
way:For ti > p the
product Q((n -
J-l +1)... Q(n)
has at least p factors.By
the
assumption (26)
that thepolynomial Q "splits completely" (mod p)
inq linear factors of the form ax +
b,
pf a,
onegets
If one remembers that the aj,
1 j h,
could be chosen asintegers (compare
remarkii)
to theorem1)
onerecognizes
from(4)
and(28)
that thecoefficient
qn kn
of thestarting polynomial
P is also aninteger.
Thereforewe have from
(37)
and(38)
From this we conclude with
(36)
6. The values and the
non-vanishing
of the linear form A*
We
apply
thedivisibility properties proved
inchapter
5 to show that the linear form A* of(251)
does not vanish. P*
(compare (6))
is defined with thepolynomial
P of(28)
by
It follows from
(5)
and(30)
Tr
and from
(32)
and(35)
With
(40)
weget
from(43)
Therefore we have
which is the same
(compare
the definition of A* in(251))
asFrom
(32)
weget
Because of
(40)
the second term on theright
of(46)
is amultiple
ofpq
whereas the first term is not divisible
by pq (see (34)).
Therefore weget
from
(46)
Since we assumed in
(27)
p,~
weget
with(47)
Together
with(45)
one derives now theimportant
relation7. A lower bound for A*
Let t be a
prime
number and let pt denote the numberI f... I I
denotes thecardinality
of the set{... }.
After
Nagell [9]
one has the estimatewhere K denotes the number of irreducible factors of
Q.
Let p C P be the
prime
number which was chosen inChapter
5(compare (26), (27)).
In(37)
we have seen that for fc ~ p every coefficient 7n in therepresentation (36)
of(aj)
contains the factorIn all these
products
theargument
ofQ
goes at leastthrough
p consecutivepositive integers. Therefore, using
the definition of pt in(49),
in each oneof these
products
theprime
number t occurs at least in order /-It[1[].
Inconsequence
for p
> p, everynumber P(p) (aj)
is divisibleby
apositive integer Bp
withRegarding
the construction of P*(compare (41))
one hasby(43)
The same
divisibility property
can beproved
for ao := 0 so one hasFor j
=jo
and v = vo it was shown in(46)
The second term on the
right
isby
theargument
aboveagain
divisibleby
Bp.
For the first term onegets by (32)
and(33)
From the relations
(49) - (54)
we conclude thatcan be divided
by
that means
One has
This
gives,
because q,Finally
onegets
from(50), (56)
and(57)
the lower bound8. An estimate of the remainder
0(x)
was defined in(10).
Since we have qn = 0 for 0 rz q ~ p, weget
1
We have
Q
E andQ
is ofdegree
q. Therefore exists aninteger no(Q)
so that
In
(59)
we have p > n > q p. From(60)
follows thatif p
issufficiently large
we have
Since we can take the
prime
number p, chosen in(26)
and(27),
aslarge
aswe want, we can consider
only
numbers x with theproperty
Then one
gets
the estimateLet P* denote the
polynomial
With
(59)
and(63)
followsIf P and 4
E arepolynomials,
one writes
From the definition of P in
(4)
and(28)
it follows that there are constants ci > 0 and c2 >0,
whichdepend only
on a 1, ... , ah so that we haveand
For a p E P that satisfies
we
get
from(65)
and(68)
Here C3 > 0 is a constant, which
depends
on a 1, . - - , ah andQ,
but not onpEW.
9. Proof of the linear
independence over Q
of the numbersWe have to show that for every non-zero vector in
(11)
the linear formis different from zero.
In
(14)
we have seen that the linear forms A and A* are connected in thefollowing
way:If H denotes the
height
of the vector in(11),
it follows from
(72)
with(58)
and(70)
where c4 > 0 is a constant
independent of p
and H. From(74)
onegets
forsufficiently large
p(depending
onH)
(75) A # 0,
which proves the linear
independence over Q
of the numbers1, G(al), ... ,
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ROlf WALLISSER
Mathematisches Institut der Universitat Freiburg
Eckerstr. 1
79104 Freiburg, Deutschland
E-rrtail : rova@sunl . mathemat ik . uni-f re iburg . de