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A simple expression for the map of Asplund's distances with the multiplicative Logarithmic Image Processing (LIP) law

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HAL Id: hal-01576183

https://hal.archives-ouvertes.fr/hal-01576183v2

Submitted on 24 Jan 2018

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A simple expression for the map of Asplund’s distances

with the multiplicative Logarithmic Image Processing

(LIP) law

Guillaume Noyel, Michel Jourlin

To cite this version:

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A simple expression for the map of Asplund’s distances with the

multiplicative Logarithmic Image Processing (LIP) law

Guillaume Noyel*, and Michel Jourlin

*International Prevention Research Institute, 95 cours Lafayette, 69006 Lyon, France, www.i-pri.org

Noyel and Jourlin (2017) have shown that the map of Asplund’s distances, using the mul-tiplicative LIP law, between an image, f ∈ I = [0, M]D, D ⊂ RN, M ∈ R, M > 0, and a

structuring function B∈ [O, M]DB, D

B⊂ RN, namely the probe, is the logarithm of the ratio

between a general morphological dilationλBf and an erosionµBf, in the lattice (I, ≤):

As△× B f = ln  λBf µBf  = ln ∨h∈DB{ef(x + h)/eB(h)} ∧h∈DB{ef(x + h)/eB(h)} ! , with f > 0 and ef = ln 1 − f/M. (1) The morphological dilation and erosion with a translation invariance (in space and in grey-level) are defined, for additive structuring functions as (Serra, 1988; Heijmans and Ronse, 1990):

B(f))(x) =h∈DB{f(x − h) + B(h)} = (f ⊕ B)(x) , (dilation)B(f))(x) =h∈DB{f(x + h) − B(h)} = (f ⊖ B)(x) , (erosion)

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and for multiplicative structuring functions as (Heijmans and Ronse, 1990): ∨h∈DB{f(x − h).B(h)} = (f ˙⊕B)(x) , (dilation)h∈DB{f(x + h)/B(h)} = (f ˙⊖B)(x) , (erosion).

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If f > 0 and B > 0, we have (f ˙⊕B) = exp (∨h∈DB{ln f(x − h) + ln B(h))}) = exp (ln f ⊕ ln B). Let us define, the reflected structuring function by B(x) = B(−x) and bf = ln (−ef). We obtain:

λBf = ∨h∈DB n

ef(x + h)/eB(h)o=∨−h∈DB n

ef(x − h)/eB(−h)o = (−ef) ˙⊕(−1/eB)

= exp∨−h∈DB n

ln (−ef(x − h)) + ln (−1/eB(h))o, with ef < 0 and eB< 0 = expln (−ef) ⊕ (− ln (−eB))= expbf ⊕ (−bB).

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Similarly, we haveµBf = (−ef) ˙⊖(−eB) = exp



bf⊖ bB. Using the previous expressions ofλBf

andµBf into equation 1, we obtain:

As△× B f = ln  λBf µBf  = ln  exp  bf ⊕ (−bB) expbf⊖ bB   =hbf⊕ (−bB)i−hbf⊖ bBi=δ−bBbf− εbBbf. (5)

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References

Heijmans H, Ronse C (1990). The algebraic basis of mathematical morphology i. dilations and erosions. Com-puter Vision Graphics and Image Processing 50:245 – 295.

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