C AHIERS DE
TOPOLOGIE ET GÉOMÉTRIE DIFFÉRENTIELLE CATÉGORIQUES
A. C AVICCHIOLI
F. H EGENBARTH
F. S PAGGIARI
Topological properties of high-dimensional handles
Cahiers de topologie et géométrie différentielle catégoriques, tome 39, n
o1 (1998), p. 45-62
<http://www.numdam.org/item?id=CTGDC_1998__39_1_45_0>
© Andrée C. Ehresmann et les auteurs, 1998, tous droits réservés.
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TOPOLOGICAL PROPERTIES OF HIGH-
DIMENSIONAL HANDLES
by A. CA VICCHIOLI,
F. HEGENBARTH AND F.SPAGGIARI
C’AHIERSDETOPOLOGIEET
GEOMETRIE DIFFERENTIELLE CATEGORIQUES
J ’olume ,EXXXLX-1 (1998)
R6sum6. Dans cet article on donne une d4monstration plus breve d’un r6- sultat de [3] concernant le groupe des auto-6quivalences d’homotopie, qui gardent 1’orientation, de la somme connexe X -
#p (S1
X sn) de p> 1 copies de Sl x Sn, modulo les homotopes a 1’application identique. Ce r6-sultat se rapporte a un article pr4c4dent de Hosokawa et Kawauchi [7] sur
les surfaces non nou6es dans des espaces a quatre dimensions. En effet, on
4tend leur r4sultat principal (en generalite plus grande) pour les plongements f : X - Rn+3 de X dans 1’espace euclidien (n + 3)-dimensionnel. Par cons6-
quent on classifie le type d’homotopie du compl4mentaire de
f(X)
dans R"+3en donnant des exemples de vari4t4s qui ont le meme type d’homotopie qu’un bouquet de sph6res et qui ne peuvent 6tre fibr6es sur un cercle.
1. Introduction and results.
Through
the paper we work in thepiecewise-linear (PL) category
in thesense of
[17],
and we shall omit theprefix
PL. Therefore the terms homeo-morphism
andhomotopy equivalence
mean PLhomeomorphism
and PL ho-motopy equivalence, respectively.
In the
following
Xalways
denotes the connected sum of pcopies
ofSl
X8n,
i.e. we set
In
[3]
we gave aproof
of thehigh-dimensional
version of a classical theorem of Montesinos on handlepresentations
of closed orientable PL 4-manifolds[15].
For this we studied the group of orientation-preserving
auto-homeomor-phisms
resp.homotopy self-equivalences
of X =#p(S1
XSI), p > 1,
mo- dulo thosepseudo-isotopic
resp.homotopic
to theidentity.
Recall that twohomeomorphisms f,g:
X - X are said to bepseudo-isotopic
if there is ahomeomorphism
F : X x I - X x I(I
=[0,1])
such thatF(x, 0)
=f(x)
andkey words and phrases: Homotopy equivalences, handlebodies, pseudo-isotopies, ob-
struction theory, handle presentations of manifolds.
1991 Mathematics Subject Classification. 57 N 37, 57 N 65, 57 R 65.
Work performed under the auspices of the G.N.S.A.G.A. of the C.N.R. (National
Research Council) of Italy and partially supported by the M.U.R.S.T. (Ministero per la Ricerca Scientifica e Tecnologica) of Italy within the projects Geometria Reale Complessa
F(x,1)
=g(x)
for all x E X(see
forexample [2], [10],
and[19]).
LetD0(X)
bethe group of
pseudo-isotopy
classes oforientation-preserving homeomorphi-
sms
of X,
andE0(X)
the groupof homotopy
classes oforientation-preserving homotopy self-equivalences
of X.Essential for the
proof
is thefollowing
Theorem 1. Given X =
#p (Si
XSn), n > 2, p > 1,
there exists a shortexact sequence
where
II1 = II1 (X) =
*Z is the free group with p generators, andOut (II1)
p
is the outer
automorphism
groupof II1,
i.e.automorphisms
modulo innerautomorphisms.
Observe that the group
Do (X )
is not a direct sum of the other two terms of the sequence for p > 1.Indeed, diffeomorphisms
ofX ,
whichpermute
thep summands
81
XSn,
alsopermute
the p rotationsalong n-spheres.
In
[3]
we gave ageometric proof
of Theorem1,
and also indicated analgebraic
one. One purpose of thepresent
paper is togive
a shorteralgebraic proof
of Theorem 1using
the group.6o(X).
This is based onalgebraic
lemmaswhich are
interesting by
themselves(see
Lemmas 6 and9).
Infact,
with thesewe can
simplify
theproof
of the main result of Hosokawa and Kawauchi[7]
on unknotted surfaces in
four-spaces, extending
it(in
greatergenerality)
for
embeddings f :
X -->Rn+3
of X into the Euclidean(n
+3)-space.
Wealso
classify
thehomotopy
type of thecomplement
off (X )
inRn+3, giving examples
of manifoldshomotopy equivalent
to abouquet
ofspheres
whichcannot be fibered over a circle.
More
precisely,
we say that alocally
tamesubspace
oflEBn+3
is a knot-ted
(orientable)
O-handle of genus p if h’ ishomeomorphic
to X . Two knot-ted 8-handles K and K’ are
equivalent
if there is anorientation-preserving auto-homeomorphism
ofRn+3 sending
K onto 1(’. Theequivalence
class ofknotted 9-handle is called its knot type. We say that Il is unknotted in Rn+3 if there exists an
(n + 2)-dimensional (solid) handlebody
Y#p(S1
XDn+1),
standardly
embedded inRn+3,
such that 8Y = 1(. For n= 1,
this coincideswith the
concept
of unknotted(orientable)
surface in the Euclidean4-space,
first introduced and studied
by
Hosokawa and Kawauchi in[7].
The
following
theorems extend some results of[7]
to dimension n(for
moredetails on definitions see Section
4).
Theorem 2. Let
Kn+1
be a knotted â-handleof genus p in lEBn+3.
Then the fundamental groupofRn+3BK
isisomorphic
to Z if andonly
if Ii isstably
unknotted in
Rn+3,
i.e. an unknotted â-handle can be obtained from Kby hyperboloidal
transformationsalong
trivial 1-handles.. Theorem 3.
Suppose
thatKn+1
is a knotted â-handle of genus p inRn+3,
n >
2,
withII1(Rn+3BK)=
Z. Then thecomplement Rn+3 B K
is(simple
homotopy equivalent
to thewedge V psn+1
VSi
Vsn+2 .
We remark that manifolds
homotopy equivalent
to awedge
ofspheres
ofvarious dimension were also treated in
[6].
There the classification of thicke-nings
of awedge
ofspheres
is reduced to the classification of concordance classes ofembeddings
of a number of solid tori in theboundary
of a solidhigh-dimensional handlebody.
For other related resultsconcerning
manifoldswith free fundamental group we refer to
[1]
and[4]. Concepts
and notationsfrom
homotopy theory
arestandard,
and can be found forexample
in[5], [8],
and
[14].
For a reference onhomological algebra
see[16].
2.
Homotopy self equivalences
ofThroughout
the section we shall assume n> 3. In this case we haveThe
arguments
for n = 2(in
which caseII3(S2)= Z)
areslightly
different.In this section we are
going
to prove thefollowing
Proposition
4. Let00: £o(X) - Out(II1)
be the canonicalhomomorphism.
Then there is an exact sequence
In the next section it will be
proved
that6)pZ2 injects
intoFo(X).
Theproof
ofProposition
4 is based on obstructiontheory (see
forexample [5]
and
[18]).
We first need somealgebraic
lemmas which areinteresting by
themselves.
Lemma 5. Let
f,9:
X - X be twodegree
one maps. Iff *
= 9*:III
-II1,
then
for
all q
n.Proof.
We observe thatIIi(X)
= 0 for 1 i n, hencef*=
g* :lIq
-->llq
for
all q
n.By [12],
p.341,
Poincar4duality
anddeg( f )
=deg(g)
=1,
wehave the
following
commutativediagrams
where
f,g:X--> X
are theliftings
off, 9 respectively
to the universalcovering
spaceX
of X .Since the
hypothesis f.
=9.: lIt
-II1 directly implies f**
=g* ,
it followsthat
f *
=§*: Hn (X ; Z) --> Hn (X; Z).
Then the Hurewiczisomorphism
implies
thatf*
= g* :H,,
--ifIn
asrequired.
0Lemma 6. Let A =
Z[II1]
be the groupring
ofII1 (X),
whereX =
#P(S1
XSn).
Let g1, g2, ... ,gp E II1 (X ) be
canonical generators and letThen the A-module
IIn(X)
isA-isomorphic
to(®pA)/oA.
Proof.
Observe thatby
the Hurewiczisomorphism
theorem andby
Poincar4duality.
Let
X(q)
be theq-skeleton
of the standard cellulardecomposition
of X. Then the chain
complex
gives
Here c is the
augmentation
map,/(A) = Ker(E)
is theaugmentation ideal,
and
i#: HOmA(A,A)--+ HomA(I(A),A)
is thehomomorphism
inducedby
i :
I (A) -->
A.The
augmentation
idealI (A) = ®pA
has generatorsg1 -1, g2 -1, ... , ,gp-1.
Given cp E
HomA(A,A),
theni# (cp) corresponds
toproving
the lemma. 0Lemma 7. The canonical map
is an
isomorphism.
Proof.
This is a consequence of the universal coefficientspectral
sequenceThe
only
contributions fornn(x; TIn(X))
areand
For the latter
isomorphism
observe that thewedge VpS1
is theclassifying
space of the group
*PZ.
0Remark.
Using
withwe obtain the
following
exact sequence:homomorphism
because a goes to zero. Hence we obtain moreprecisely
However we do not need this
specific
result in our context.Corollary
8. Letf, g:
X - X beorientation-preserving homotopy equiva-
lences with
f *
= g* :II1 (X ) --> II1 (X).
Then theonly
obstruction for the existence of ahomotopy
betweenf and g
lies inHn+1 (X; IIn+1 (X)).
Proof. Obviously
there is no obstruction on the 1-skeleton.By
standard ob- structiontheory f and g
are thenhomotopic
overx(n-1).
The n-dimensional obstruction lies inand it is
equal
tohence vanishes
by
Lemma 5. 0The
proof
ofProposition
4 will follow fromCorollary
8 and from theisomorphism given
below.Lemma 9.
Proof.
LetE-, En 2,
... ,En p-1
C X =#p(S1
xsn)
ben-spheres
which aredetermined
by
the connected sums. Let X* denote the space obtained from Xby adjoining (n
+1)-discs along Ei
for i =1, 2, ... , p -
1. Inparti-
cular X* is
homotopy equivalent
tovp(s 1
XSn).
Moreover let us denoteXo = XB{(n + 1)-
opendisc}.
It is not difficult to see that thefollowing
sequence of
homotopy equivalences
holds:Hence we have
and
Let us consider the
homotopy
sequence of thepair (X,Xo):
Since
IIn+1(X,X0)= A, fIn(Xo) ££ OpA
andIIn(X) = (CpA)/oA (by
Lemma
6),
it follows that the short sequenceis exact. This
implies
that thehomomorphism IIn+1 (X0) --> IIn+1 (X)
issurjective.
Now we have
and therefore the
homomorphism
is also
surjective,
i.e.is a direct sum of
copies
ofZ2.
We consider now the exact
homotopy
sequence of thepair (X*, X).
SinceIIn+1 (X*, X) = ®P-1 A
andIIn+1 (X*)= IIn+1(X*)
is a direct sum ofcopies
of
Z2,
we obtainhence
Z®A IIn+1 (X)
-->Z®A IIn+1 (X*)
issurjective.
So we have thefollowing composition
ofsurjective homomorphisms
Since
IIn+1 (X*)
has at least pcopies
ofZ2
we obtainhence Z 0A
IIn+1(X)= ÐpZ2.
Thiscompletes
theproof. D
In order to finish the
proof
ofProposition
4 we have to prove thesurjecti- vity
of£0(X) ---> Out(lll(X)).
For this we refer to[12]. Any g
EOut(II1(X))
can be realized
by
ahomeomorphism f :
X --+ X. Iff
hasdegree 1,
then[f] E go(X). If f
hasdegree -1,
we composef
with thehomeomorphism
where r is the reflection on the first coordinate.
Remark: Theorem 1 would follow from an
equivariant
version ofCorollary
16.4 of the textbook of Hu
(see [8]).
However we shallexplicitely
constructall the elements of
®pZ2
in the next section.3. The
injection ®pZ2 --> E0(X).
Now we are
going
to realize the obstructions involved in Theorem 1.Let
{gi}, i
=1, ... , p,
be a free basis ofII1(X) = *pZ,
whereX =
#p (Sl
XSn), p > 1, n >
3.Obviously gi
is thehomotopy
class of the i-th Sl-factorSi
of X. LetAut(II1 )
be the group ofautomorphisms
of thefundamental group
II1 = II1 (X)
of X . Asproved
in[11]
and[12],
the groupAut(II1)
isgenerated by sliding 1-handles, twisting
1-handles andpermuting
1-handles. More
precisely,
for i =2, ... , p (p
>1)
defineOi
EAut(II1 ) by
setting Øi(g1)
= g; ,Øi(9i)
= 91 andØi(gj)
= 9j foreach j# i, j =
1. Permu-ting
the 1-handles giand 9j corresponds
to theautomorphism Oi oOj oOi-1.
Itfollows that
0?
= 1 andby [11], [12]
there existhomeomorphisms fi :
X --> X(permuting 1-llandles)
such thatfi* = Oi.
Then define a EAut(II1) by setting a(gi )
=g1-1
andor(gi)
= gifor i=1. Twisting
the 1-handle gi cor-responds
to theautomorphism Oi
o a oqi-1. Obviously o2
= 1. Furthermore there existhomeomorphisms
of X(twisting I-handles)
which realize (1 andOi
0 (1 oqi-1
for i > 2.Finally
wedefine ’0
EAut(II1 ),
p >1, by setting
’Ø(91)
= 9192 and’Ø(9i)
= gi for i > 2(sliding I-handles).
Let
Ei = Sni
be the i-th Sn-factor of X =#p (S1 x Sn), p > 1,
n > 3.
Following [11],
we show that rotations of Xparallel
to Ei generate the obstructionsubgroup
Let
be a
loop representing
ahomotopy
class ofTII (SO(n+ 1)) - Z2 (n > 3).
Then a induces a
homeomorphism
defined
by
for all x E Sn and t E I =
[0, 1]. Obviously ha
is theidentity
on theboundary â(sn X I) = Sn
X 0 U Sn X 1.Now let
Mn+1
be a closed oriented(n
+l)-manifold
and let En be anoriented
n-sphere
embedded in M.Suppose
w : Sn X I --> M is an orientation-preserving embedding
such thatcp(Sn
X0) =
E. Becauseha - identity
ona(Sn
XI),
one obtains ahomeomorphism
defined
by
We call the
homeomorphism hE
the a-rotation of Mparallel
to E(briefly,
a
rotation). Obviously
thepseudo-isotopy
class ofhE depends only
on thehomotopy (resp. isotopy)
class of a(resp. E).
sn-factor of X. We set
for i =
1, ... ,p
and[a]
ETIl (SO(n
+1)) = Z2.
One can choosehi,a
to bethe
identity
on the unionUf=lEi.
Because(hi,a)* = identity
onHq(X)
forall
q
n, we have thathz,a
EKerO0, i
=1, ... , p (Here 00
is the canoni- calhomomorphism £o(X)--> Out(II1)
considered in Section2).
Moreoverhi,a
ohj,13 = hj,B
ohi,a (i j),
eachhi,a
commutes with the generators ofAut(II1)
andhi,a
ispseudo-isotopic
to theidentity
if andonly
if[a]
= 0. Thuswe have shown that the rotations
hi
=hi,,
of Xparallel
to then-spheres Ei
generate Ker 00
if[a]
is thegenerator
ofII1 (SO(n
+1))= Z2.
Inparticular,
this shows that the term
®pZ2 injects
intoD0(X)= £0(X).
More
precisely,
we caninterpret
our results in thefollowing
way(which
isrelated to Lemma 5.4 of
[11]):
Proposition
10. Let X =#p (Si
XSn), p > 1,
n >3,
and letf :
X - X be anorientation-preserving homeomorphism
such thatO0(f)
=1,
i.e.
f* = identity
onII1 (X).
Then there existloops (obstructions
(i
=1, 2, ... , p)
suchthat f
ispseudo-isotopic
to theproduct
Moreover,
thepseudo-isotopy
can be chosenkeeping
the unionUpi Ei
fixed.In other
words,
therotations hi
=hi,a (i
=1, ... , p)
constitute a free basis ofwhere
[a]
is thegenerator of II1 (SO(n
+1))= Z2.
4. Unknotted handles in Euclidean spaces.
In this section we are
going
to prove Theorems 2 and 3.Let
Kn+1
be a knotted 0-handle of genus p inRn+3,
i.e. K is alocally
tame
subspace homeomorphic
to X =#p(S1
Xsn).
An oriented(n
+2)-cell
B in
Rn+3
is said tospan K
as a 1-handle if B n K =(,9B)
fl K and this intersection is the union ofdisjoint
two(n+ 1)-cells
and(KUôB)B int( ôBnK)
has an orientation
compatible
with both the orientations ofKB int(OB
nK)
(induced
fromK)
and9BB int(aB
UK) (induced
fromB).
IfBi,
... ,Bq
aremutually disjoint
oriented(n
+2)-cells
inRn+3
which span K as1-handles,
then the knotted a-handle of genus p
+ q
with orientation induced from
KB int(K
nUq 1 aBi)
is said to be obtained from Kby hyperboloidal
transformationsalong
1-handles(see [7]
for n =1).
A 1-handle B on K in
Rn+3
is trivial if there exists an(n
+3)-cell
N inRn+3 containing
B such that N fl K = 8N fl k and this intersection is an(n + 1)-cell.
Note that theattaching
two(n + 1)-cells
of B to I( are containedin the
(n
+1 )-cell
8N n K since we haveHyperboloidal
transformationsalong
trivial 1-handles do not alter the funda- mental groups of thecomplements
inRn+3.
Inparticular,
if K isunknotted,
then
II1(Rn+3BK)= II1 (Rn+3Bsn+1)=Z,
sinceSn+ 1C
Rn+3 is the stan-dardly
embedded(n
+1 )-spheres
inRn+3.
Proof of T h eorem 2.
Sufficient condition.
If h’
=h1 (K; B1, ... , Bq)
is unknotted for some q, then we havebecause
Bi
are trivial 1-handles.Necessary
condition.Clearly,
there are 1-handlesB1, ... , Bq
on Ii suchthat
h1 (K; B1, ... , Bq )
is unknotted inRn+3.
The assertion now follows from the lemma below.Lemma 11.
If II1(Rn+3BK) = Z,
then anarbitrary
1-handle B on K istrivial.
Proof.
Let a be asimple
proper arc in B such that the union K U a is aspine
of the union K U B.By sliding
aalong
K andby deforming
a itselfwe can assume that a is attached to
KBB
as follows. There is agenerating 1-sphere
C of K which intersects a into twoendpoints
x+ and x-. Let61
be aregular neighborhood
ofx+-
in a and define a’ =cl(aB(6+
Ub-)).
We now
join
theendpoints
of a’ with asimple
arc y such that theloop
y U a’ C
R n+3 BK. Obviously, -y
U a’ is ingeneral
nothomologous
to zeroin
Rn+3 BK. However, by twiting 7 along
C we can assume that thesimple loop y
U a’ ishomologous
to zero inRn+3BI( (use H1(Rn+3BK)=
Z andthe fact that the
generator
ofH1(Rn+3BK)
isgiven by
aloop
transversal toC).
SinceH1(Rn+3BK)= II1(Rn+3BK), y U a’
isnull-homotopic
inRn+3 BK.
Hence it bounds a
singular
2-disk.By general position
and the embeddeddisk
theorems
U a’ bounds an embedded 2-disk inRn+3BK
as n + 3 > 5(the
case n = 1 was treated in[7]
so we can assume n >1).
Then IW U a isambient
isotopic
toK,
so we can find an(n
+3)-cell
Ncontaining
B suchthat N n K =
(aN)
n A and this intersection is an(n
+1)-cell,
i.e. B is atrivial 1-handle on K. 0
Proof of Theorem 3.
Suppose
thatII1(Rn+3BK)= Z, n
> 1. It is convenient to consider h’ in the(n
+3)-sphere an+3
U{oo} = Sn+3.
We shallidentify II1(sn+3BK)=
Z.Then for every i
(1
in )
we havewhere X =
#p(S1
XSn)
asusual,
andZ[Z]
is theintegral
groupring
of Z.Now
Hi(X; Z[Z]) injects
intoHz(X; A),
where A =Z[*pZ].
Thus we obtain
for 1 i n, and
(use
Lemma6)
since a is zero on
Z[Z].
Hence
Hi(sn+3BK;Z)=
0 for 1i n, andHn+l (Sn+3BK; Z)
isZ[Z]-free
of rank p.Next,
we shall show thatHn+2(Sn+3BK; Z)=
0.Let M be the
(n+3)-manifold
obtained fromsn+3 by removing
the interiorof a
regular neighborhood
of K inSn+3.
The exacthomology
sequencesplits,
hencei.e.
Hn+2 ( M;Q)=
0. Thisimplies
thatHn+2(M;Q)
isfinitely generated
over
Q. Using Hn+3 (M; Z)= 0,
from thepartial
Poincaréduality
theorem for infinitecyclic coverings (see [9])
we obtainHn+2 (M; Q)= Ho (M, aM; Q)=
0as 9M is connected. In
fact,
thehomomorphism H1(aM;Z)--> H1 (M;Z)
isonto since we have
Now
Hn+1 (M;Z)
is torsion free as follows from theMayer-Vietoris
exactsequence
where
and
is Z-free. However
Hn+2 (M;Z)= Hn+2(M; Z[Z])
is a torsion free abelian group.Therefore
Summarizing
we have obtainedLet
f1, ... , fp: (S’+’,*)
--->(Sn+3BK,x0)
be mapsrepresenting
aZ[Z]-basis
for
and let
be a map
representing
agenerator
ofII1(Sn+3BKx0)=
Z.The
wedge
of mapsclearly gives
ahomotopy equivalence (and
hence asimple homotopy equiva-
lence since the Whitehead group of Z is
trivial).
Therefore
Rn+3BK
=(sn+3BK)B {oo}
ishomotopy equivalent
to thewedge
Vpsn+1
VS1
VSn+2
asrequested.
0Using
Theorem3,
andfollowing
inpart [7],
we also prove the non-fibered property of the exterior of a knotted 9-handle inSn+3.
Moreprecisely,
wehave
Proposition
12. For any knotted a-handleKn+1
of genus p(p> 1)
inSn+3,
thecomplement sn+3BK
cannot be fibered over a circle.Proof.
Let M be the(n
+3)-manifold
obtained fromSn+3 by removing
theinterior of a
regular neighbourhood
of k inSn+3. Suppose
that n > 1(for
n = 1 see
[7]).
Ifsn+3BK
and hence M is fibered over acircle,
then theinfinite
cyclic
connectedcovering
M of M can be written as thetopological product
of a compact connected(n
+2)-manifold
N and the real line R. Inparticular,
we have thatis
finitely generated
overQ. However,
we aregoing
to show thatHn+1 (M; Q)
is of rank p
as Q
t>-module, where Q
t > is the rational groupring
of the
covering
translation group t > of M. Notethat Q
t > is aprincipal
ideal domain. ThusHn+1 (M;Q)
would beinfinitely generated
overQ, giving
a contradiction.Therefore,
forp > 1,
M and henceSn+3BK.cannot
be fibered over a circle.
First we observe that
In order to show that
let us consider the
following part
of theWang
exact sequencewhere 7r: M --> M is the
covering projection.
SinceH1(M;Q)= Q,
it followsthat
and hence
is
surjective.
We setwhere T denotes
the Q
t >-torsionpart
ofHn+1 (M;Q).
Since
H1(M,âM;Q)=
0(because H1(M, aM;Z)= T Hn+1 (M;Z)
asshown in the
proof
of Theorem3),
it follows thatH, (M, aM; Q)
is afinitely generated Q
t >-torsionmodule,
and thatLet us consider a
decomposition
of
H1(M, aM;Q). According
to thepartial
Poincaréduality
theorem for infinitecyclic coverings (see [9],
Theorem 2.3(II)),
T isQ
t>-isomorphic
to
and hence
t - 1: T--> T is a Q t >-isomorphism. Therefore,
we have theexact sequence
since
by
thepartial
Poincar6duality
theorem[9].
From this it follows that r = p, i.e.as
requested.
Thus theproof
iscomplete.
DExample.
In[20]
Zeeman defined the process ofk-twist-spinning
a smoothn-knot in
sn+2.
The result is a smooth(n+1 )-knot
inSn+3, uniquely
deter-mined
by
theoriginal
n-knot and theinteger
k. Thecomplement
of such ak-twist-spun
knot inSn+3
is a bundle over a circle withcovering
groupZk,
and
typical
fiberhomeomorphic
with the k-foldcovering
ofSn+2
branchedover the
original
n-knot.Moreover, S1
acts onSn+3
so as to leave the k-twist spun knot setwiseinvariant,
and map thecomplement
fiberwise. Inparticu- lar,
if k= 1,
then the result is unknotted. Morerecently,
Litherland[13]
showed that
combining
certainrollings
with twistsyields (n + 1 )-knots
whichare
again
fibered overS1.
Now any bundle overS1
withtypical
fiber F isequivalent
to a fibration oftype
where g : F - F is a
homeomorphism,
and F X 981
denotes thequotient
space obtained from F x
[0, 1] identifying
x x 0 withg(x)
x 1 for anypoint
xEF.
Let us consider a knotted 9-handle
kn+1
obtained from a k-twist spun knotEn+1
inSn+3 (k:/±1) by
ahyperboloidal
transformationalong
a trivial1-handle. Then K is knotted since
is not
isomorphic
to Z(use k#±1).
Here 9*:II1(F) --> fir( F)
is theinduced
automorphism
onIIi. Furthermore,
if G is a group and h : G --> G anautomorphism,
then Gx h Z
t > denotes the extension of Gby
the infinitecyclic group Z
t >generated by t
in whichconjugation by
t induces h onG.
Finally
thecomplement Sn+3BK
is not fibered overS’ by Proposition
12.REFERENCES
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Authors’ addresses:
Alberto
Cavicchioli, Dipartimento
diMatematica,
Universita diModena,
Via
Campi 213/B,
41100Modena, Italy.
E-mail: [email protected]
Friedrich
Hegenbarth, Dipartimento
diMatematica,
Universita diMilano,
Via Saldini
50,
20133Milano, Italy.
E-mail:
[email protected]
Fulvia
Spaggiari, Dipartimento
diMatematica,
Universita diModena,
ViaCampi 213/B,
41100Modena, Italy.
E-mail: