C OMPOSITIO M ATHEMATICA
E DOARDO B ALLICO
On the dual variety in characteristic 2
Compositio Mathematica, tome 75, n
o2 (1990), p. 129-134
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On the dual variety in characteristic 2
EDOARDO BALLICO
Department of Mathematics, University of Trento, 38050 Povo (TN), Italy Compositio
© 1990 Kluwer Academic Publishers. Printed in the Netherlands.
Received 1 March 1989; accepted in revised form 28 November 1989.
Consider an
integral
ondegenerate variety
X c P’. Theprojective
geometry ofX is very much reflected in the geometry of its conormal
variety C(X)
c PN xPN*; C(X)
is the closure of thepairs (x, H)
with x ~Xreg
andTxX ~
H(i.e.
suchthat H is tangent to X at
x).
For instance if the dualvariety
X*(i.e.
theprojection
of
C(X)
intoP" )
is not ahypersurface
then thegeneral hyperplane
tangent to X is tangent to X atinfinitely
manypoints.
If thealgebraically
closed base field F haschar(F)
=0,
then it is known that in such a case thegeneral hyperplane
tangent to X is tangent to Xexactly along
a linear space. Without anyassumption
onX*,
whenchar(F)
=0,
many nicethings
are true:biduality (i.e. (X*)*
= X under theidentification of
(PN *)*
withPN),
the fact that in the enumerative formulas the solutions comes withmultiplicity
ones etc. Ingeneral
suchgood things
are nottrue when
char(F)
= p > 0. Wallace([15])
was the first to note this fact and to show that there is a class of varieties(the
reflexivevarieties)
for which such factsare true
(in particular
thebiduality
ofX).
Avariety
X is called reflexive ifC(X)
=C(X*) (up
to theexchange
of the factors in PN x PN* and the identification of(PN*)*
withPN).
Avariety
X c PN is calledordinary
if it isreflexive and X* is a
hypersurface.
Whenchar(F)
=0,
everyvariety
is reflexive.When
char(F)
> 0 this is not true, but the class of reflexive varieties has remarkablestability properties
and it is very nice: in the small universe of reflexive varietieseverything
is nice(see [2], [3], [4]).
But there is adisturbing
feature:char(F)
= 2. Whenchar(F)
= 2 there is noordinary variety
of odd dimension. Inparticular
thegeneral hyperplane
section Y of anordinary variety
cannot beordinary.
But it has many nice features:semi-reflexivity (see [3])
and Y* isa
hypersurface ([3], 5.9
and5.12),
i.e. thegeneral hyperplane
tangent to y is tangentonly
atfinitely
manypoints
of Y. It was asked in[3], (5.11)(iii),
if for suchX the
following
property($)
holds:($):
thegeneral hyperplane
tangent to ageneral hyperplane
section Y of anordinary variety
X is tangentexactly
at onepoint
of Y.A
proof of ($)
for allordinary
X would makeauthomatically possible
todrop
the130
unpleasant assumption "char(F) ~
2" in a few statements([3],4.10(ii);
for thenon-existence
of bitangencies
in the enumeration of the contact formula in[2], §2,
part(c)
of the maintheorem,
p.162,
see the discussion in[2],
p.169).
Unfortunately,
the answer is NO. In Section 1 we construct a very nicefamily
ofexamples; they
arehypersurfaces
and we haveexplicit equations; they
are relatedto the so-called null-correlations
(and
to the null-correlationbundles) (a
very classicaltopic:
see e.g.[1]).
But the next bestthing happens.
Theseexamples
arethe
only
ones. This isproved
in Section 2. Thus in this paper we prove thefollowing
result.THEOREM 0.1. Fix an
integral
nondegenerate variety
X inP’, dim(X)
= n.Then a
general hyperplane
tangent to ageneral hyperplane
section Yof
X is tangent at more than onepoint of Y if
andonly if
N = n +1,
n = 2k + 2 is even,and,
up to achange of the homogeneous
coordinates y,,. ..., yk, Z 1" ..., zk ofpN,
theequation f of
X has theform:
with h and b
homogeneous polynomials.
Every integral
nondegenerate hypersurface X satisfying (1)
has two geo- metricalproperties (see §1
for theirproof):
TX is the restriction to X ofa null-correlation bundle of Pn+1 and X is
canonically isomorphic
to its dualvariety.
Now we can check that such avariety X
is not normal(proof:
X issingular
on the codimension one subset{h
= b =01).
Thus we have thefollowing corollary.
COROLLARY 0.2 Fix an
integral
nondegenerate variety
X c pN. X has property($) if
it is normal orif
it is not ahypersurface.
While the work on this paper was
done,
the author was a guest at SFB 170(Gottingen);
he wants to thank very much H. Flenner for some very useful conversations. S. Kleiman detected an error in the first version of this paper and several inaccuracies in the secondversion;
the author wants to thank him both for this reason and for very strong encouragement.This paper is dedicated to Alessandra.
1. The
examples
In this paper we work
always
over analgebraically
closed base field F withchar(F)
= 2. Fix an oddinteger m
> 1 and set P := Pm. Let 0 and Q be structural sheaf and the cotangent bundle on P. It is well-known thatQ(2)
isspanned by
itsglobal
sections. Since m isodd, cm(03A9(2))
=0;
hence ageneral
sectionofQ(2)
nevervanishes. Choose a nowhere
vanishing
section s ofQ(2).
The choice of s isequivalent
to the choice of asurjection
t: TP -0(2).
Set N :=Ker(t).
N isa
rank-(m - 1)
vector bundle on P. It is called a null-correlation bundle andclassically
considered(see
e.g.[1]).
Thus s induces an exact sequence:
Choose
homogeneous
coordinates xo,..., Xm onP;
we will set m = 2k -1,
Yi:= x2i-2, 1 i m, zi:=
x2i-1, 1
i m. Consider the Euler sequence on P:The map O ~
(m
+1)O(1)
in(3)
send c ~ O into(cx°; ... ; cxm). By (3)
the choice of t isequivalent
to the choice of m + 1 linear formsl0, ...,lm
on P such thatx0l0
+ ... +xmlm
=0;
t issurjective exactly
when the forms10,
... ,lm
have nocommon zero. Furthermore
by
the dualof (3) H°(P, Q(2»)
can be identified to the setof antisymmetric (m
+1)
x(m
+1)
matrices over F(even if char(F)
=2);
thematrix
given by l°, ... , lm
has as elements in the ith row the coefficients ofli.
Thenowhere
vanishing
of s isequivalent
to the fact that thecorresponding antisymmetric
matrix L isinvertible;
hence up to achange
of coordinates s isuniquely
determined. We will choose the coordinates xo,..., xm in such a way thatl2i-2=zi
and12i-l = -Yi, 1
i m.Let X be a reduced
hypersurface
of P withhomogeneous equation f, deg( f )
= d > 2. Assume that(8/8xi)f = lig
for all i and for someform g of degree
d - 2. Since X is
reduced, g ~
0. Then the map fromTPIX
to the normal bundleOx(d)
to X factorsthrough Ox(2) ;
sincethe li
are nowherevanishing,
we see thatthe exact sequence
induces the exact sequence
which is the restriction to X
of (2).
Inparticular
TX islocally
free and TX =N|X.
Claim: X is reflexive.
Proof of
the claim. Thealternating
matrix Lcorresponding
to sgives
a
null-correlation,
i.e. anisomorphism
L between P and its dual P* such thatx ~
L(x)
for all x ~ P. Since the matrix L isalternating,
we checkeasily
that if132
y E L(x)
thenx E L(y).
Let J c P x P* be the incidencecorrespondence,
J ={(x, H):
x ~H}.
J =P(TP(-1)) (as
space overP)
and tgives
a section of J - P withimage
thegraph graph(L)
of L.Furthermore,
since TX =N|X, JI(X
xP*)
is the conormal
variety C(X)
of X. Since L is anisomorphism,
theprojection graph(L) -
P* is anisomorphism.
Hence so is its restrictionC(X) -
X*. ThusX is reflexive
(see [2]
or[3]
or[4]), proving
the claim.Since
(4)
is the restriction of(2),
for any x, y E(X)reg,
y ETxX
if andonly
ifx ~
TyX.
Furthermore if H is ageneral hyperplane,
say H =L(a)
with a e P anda
general,
for all x ~ H n(Xreg),
we have a ETxX (i.e. by
definition Y:= X n H is strange with strangepoint a).
Inparticular
every line D in H with a E D is tangentto X at all
points
of Y n D. First assume that for ageneral line
D in H with a ED, card(Y
nD)
2. Fix any such D and c, b E Y n D with c ~ b. To show that X does notsatisfy ($),
it is sufficient to check that(T, Y)
n Y =(Tb Y)
n Y. Fix ageneral eE(TcY)n
Y. Then c ~Te Y. Since a E TeY, we get b ~ TeY, hence e ~ Tb Y, hence the
thesis. We have to prove the
assumption,
i.e. that forgeneral L(a)
there is sucha line D. First assume m =
3,
i.e. X a surface. Since X isreflexive,
forgeneral
x ~
XTxX
has order of contact 2 with x atX,
hence forgeneral L(a)
ageneral line
D tangent to X n
L(a) (i.e.
ageneral
line in Hthrough a)
has contact order 2 withY at each
point
of Y nD;
since d >2,
theassumption
follows. Now assume m > 3.By
the case m =3,
we see(cutting
X with ageneral P3)
that for ageneral
x E Xand a
general
tangent line D to X at x,card(D
nX)
>1; L(x)
is the tangent space to X at x, hence contains D. Of course,L(x)
is not ageneral hyperplane.
But wemay find a
family
ofpoints a(t),
t ~T, a(t)
E P forall t,
with Tsmooth,
irreducible affine curve, and afamily
of linesD(t), t E T,
witha(t)
ED(t)
cL(a(t))
for every t(hence D(t)
tangent to X at eachpoint
ofD(t)
n Xby
the strangeness ofX n
L(a(t)),
witha(O)
= x for somepoint
0 E T,a(t) general
forgeneral t.
Forgeneral
t E T,L(a(t))
andD(t)
will work.Now we have to show that
(assuming char(F)
=2)
such varieties Xexist,
write theirequations
and find allpossible
X. First note that from(8j8zi)f
= yig(resp.
(~/~yi)f
=zig),
i =1,...,
m, we get that g contains every variables zi(resp. yi)
atan even order.
Thus g
= h2 for somepolynomial h of degree d/2;
inparticular
d iseven.
Furthermore, taking derivatives,
we see thatf - (LiYizi)h2
is a square, sayb2. Viceversa,
for any even d and any choice ofpolynomials h, b,
withdeg(h) = -1
+(d/2), deg(b)
=d/2,
definef by
theequation (1).
Thevariety X:={f
=01
will work if it is reduced and irreducible. Even thereducibility
is nota
big problem;
if it isreducible,
any of its reducible components ofdegree
> 2 would work(if
there are suchcomponents).
The reader caneasily
constructexamples
off
with Xintegral.
Here we showonly
the existence of at least oneexample, taking m
=3,
h = xl, b =(xo
+ X2 +x3)2.
Note that the restriction of this surface X to theplane
A:={x2
=01
is a curve C withexactly
asingular point (xo
= x3 ~0,
Xi =0)
while the line{x0
=01
intersects Conly
at onepoint
withX3 = 0. Hence C cannot be the
product
of(maybe reducible)
conics.2. End of
proof
In this section we will prove 0.1 and 0.2
showing
that theexamples given
insection 1 are the
only examples
of reflexive varieties without property($).
We willfix an
integral
nondegenerate variety
X cPN, dim(X)
= n, X not with theproperty
($).
Theproof
of o.1 is divided into 2 steps;essentially,
in the first step we will handle the case "N = n +1",
while in the second step we will handle the case"N > n + 1".
Step
1.By [5],
Lemma 3 p.334,
thegeneral projection
Y of X into P"+ 1 isreflexive;
of course, Y isordinary
and cannot have theproperty ($).
In this step we will work with Y i.e. we will assume N = n + 1 and X ahypersurface. By
thedefinition of
ordinary variety
and[4], 2.4(v),
there is a proper closed subset A ofX,
Acontaining
thesingular
setSing(X) of X,
such that for every x E X,x e A,
the tangent spaceTxX
is tangent to the smooth locus of Xonly
at x. Consider thefollowing
assertion(£):
(£):
for ageneral
x E X and ageneral hyperplane
Hthrough
x, the propermorphism
from the conormalvariety
of X n H in H to the dual of X n Hhas x as its fiber
through
x(set theoretically).
Note
that, fixing
H andtaking
z E H with zgeneral,
it is easy to check that(£) implies ($).
Thus if we prove(£)
we get a contradiction. For every y EXBA,
setX ( y) :=
X nTyX, X ( y)’ := X ( y)
n(Xreg ).
Since N = n +1, by
the definition of A for everyy~X(x)’, y ~ x, T(x,y) := TyX~TxX
is ahyperplane
ofTxX.
Varying y
we get afamily
ofhyperplanes
ofTxX
of dimension at most n - 1.Assume that for
general
x andgeneral
y ET(x)’, x e T(x, y).
Then a
general hyperplane H through
x does not contain anyT(x, y).
SinceTx(X
nH) = (TxX)
nH, (x, H)
will prove(£).
Thus we may assume that for
general
x E X and every y ET(x)’,
x ~T(x, y).
Ifthe
family {T(x, y)l (x fixed,
y variable inX(x)’)
has not dimension n -1, again
the
general hyperplane H through
x does not contain anyT(x, y), again giving (£).
Thus till the end of this step we will assume that for
general
x, ageneral hyperplane
ofTxX containing
x is of the formT(x, y). Counting
dimensions we see that thisimplies
that forgeneral
x E X andgeneral
y E(X
nTxX),
we havex ~
TyX.
This means that forgeneral
x EX,
theimage
of(Xreg ~ TxX)
under theGauss map g:
Xreg --+
P* is contained in thehyperplane Hx
of P*corresponding
to x. Thus for
general
x EX, g(Xreg
nTxX)
has X*n Hx
as closure in P*. Thusg*(OP*(1))
=OX(1)|Xreg.
We claim that thisgives
that the induced map incohomology g’*:H°(P*,OP*(1))~H°(Xreg,OX(1))
hasimage
contained in theimage
ofH’(P, OP(1));
indeed since X is nondegenerate, H°(P*, OP*(1))
isgenerated by
the sectionscorresponding
to thehyperplanes Hx,
with x ~ X. The134
map
g’*
isinjective
because X* is not contained in ahyperplane
as X isordinary.
Note that
(for
dimensional reasons and the claim and theinjectivity just proven) g’*
induces anisomorphism j
of P* onto P. To show that if($)
does not holdX must be of the form considered in Section
1,
it is sufficient to checkthat j-1
isa
null-correlation,
i.e.that j(c)
e c for every c ~ P*. Let M be the matrix associatedto j-1.
M isantisymmetric
if andonly if j-1
is a null-correlation. Assume that M is notantisymmetric,
i.e. thatQ:={z~P:tzMz = 0}
is aquadric.
Sinceby
construction
x~j-1(x)
for all x E X(note
that x ~TxX),
this means that X isa
quadric (which trivially satisfy ($)).
Thus we have described everyordinary hypersurface X
without($).
Step
2.(case
N > n +1).
Now we assume that X is not ahypersurface,
andthat
($)
fails forX ; by [5]
as at thebeginning
of step 1 we may assume that N = n + 2 and that ageneral projection
of X into pn+1 does not have($) (hence by
step 1 is of the type considered in Section1).
Fix apoint a
EXreg.
Fix ageneral point
P EPn+2 and let j (or jp)
be theprojection
of X into Pn+1 from P; setZ:= j(X).
Let H :=(P, TaX)
be the span of P andTaX.
Forgeneral
P we haveH~X~H
Ta X.
Fix ageneral
b E(H
nX).
Sincej(b)
ETj(a)Z, by
theclassification in the case
of hypersurfaces
wehave j(a)
eTj(b)Z,
i.e. a is in the span H’ of P andTbX. Varying
P inH,
we see that this isequivalent
to H’ = H. Hencedim(TaX
nTb X )
= n - 1.Moving P,
we see that this is true forall a, b
EX reg .
Fixa, b,
ceXreg.
Then eitherTaX
nTbX
nTeX
=TaX
nTbX
orTcX
is contained in the span H" of the union ofTa X
andTb X.
Sincedim( Ta X n TbX)
= n -1,
we havedim(H")
= n +1,
hence H" ~Pn+2.
Move c. In the latter case we getXreg~H", contradicting
the nondegeneracy
of X. In the former case allTcX,
ceX reg,
containTaX
nTb X,
hence X cannot beordinary.
Thiscompletes the proof of 0.1
and 0.2.REMARK 2.1.
By
the classificationgiven
it followsthat,
except for theexamples
of Section
1, [3], 4.10(ii),
holds true even in characteristic 2. For theexamples
ofSection 1 it fails
badly
since for ageneral
H E X*,
thehyperplane
tangent to X* at H is the dual of X n H.References
[1] Barth, W., Moduli of vector bundles on the projective plane, Invent. math. 42(1977), 63-91.
[2] Fulton, W., Kleiman, S. and MacPherson, R., About the enumeration of contacts, in Algebraic Geometry - Open Problems, pp. 156-196, Springer Lect, Notes in Math. 997, 1983.
[3] Hefez, A. and Kleiman, S., Notes on the duality of projective varieties, in "Geometry Today", pp.
143-183, Progress in Math. 60, Birkhauser, Boston, 1985.
[4] Kleiman, S., Tangency and duality, in: "Proc. 1984 Vancouver Conference in Algebraic Geometry", CMS-AMS Conference Proceedings, pp. 163-226, Vol. 6, 1985.
[5] Wallace, A., Tangency and duality over arbitrary fields, Proc. London Math. Soc. (3)6(1956),
321-342.