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C OMPOSITIO M ATHEMATICA

W. H. S CHIKHOF

Borel’s theorem for C

-functions on a non- archimedean valued field

Compositio Mathematica, tome 55, n

o

3 (1985), p. 289-294

<http://www.numdam.org/item?id=CM_1985__55_3_289_0>

© Foundation Compositio Mathematica, 1985, tous droits réservés.

L’accès aux archives de la revue « Compositio Mathematica » (http:

//http://www.compositio.nl/) implique l’accord avec les conditions gé- nérales d’utilisation (http://www.numdam.org/conditions). Toute utilisa- tion commerciale ou impression systématique est constitutive d’une in- fraction pénale. Toute copie ou impression de ce fichier doit conte- nir la présente mention de copyright.

Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques

http://www.numdam.org/

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289

BOREL’S THEOREM FOR C~-FUNCTIONS ON A NON-ARCHIMEDEAN VALUED FIELD

W.H. Schikhof

@ 1985 Martinus Nijhoff Publishers, Dordrecht. Printed in The Netherlands.

In this note we prove the

following

theorem

(for explanations

see

below).

THEOREM 1: Let K be a non-archimedean

nontrivially valued field.

Let

Xo, XI’ ..

be any sequence in K. Then there exists a

C’-function f:

K ~ K such that

Dnf(0) = 03BBn for

all n E

(0, 1, 2, ... 1.

DEFINITION

([1], [2]) :

For each n E N let

~nK := {(03BE1, 03BE2,... 03BEn)

E Kn: if

i

=1= j

then

03BEi ~ ej 1.

Let

f:

K - K.

Define

èPnf: ~n+1K ~

K

inductively

as follows.

èPof:= f and,

for

n E

N,

Let

n ~ N ~ {0}. f is

a

Cn-function

if

03A6nf

can be extended to a

continuous function

03A6nf

on

Kn+1.

For such a Cn-function we set

(for n ~ N ~ {0},

x,

yEK)

f

is a

C~-function

if

f

is a Cn-function for each n E N

~ {0}.

REMARK 1: The

"ordinaiy"

definition of a Cn_function

( f

is n times differentiable and

f(n)

is

continuous)

does not lead to nice

properties.

The

stronger

definition of above restores somewhat the

damage

caused

by

the absence of the Mean Value Theorem.

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290

REMARK 2: The

following

statements can be obtained

by elementary

and

straightforward arguments (see [2]).

(i)

A

Cn+l-function

is also a C"-function.

(Locally) analytic

func-

tions are

C’-functions, "f

is a Cn-function" is a local

property.

(ii) (Taylor)

if

f

is a Cn-function then

so that

Further,

we have n !

Dn f = f(n).

(iii) (Polynomials).

Let denote the function x H x

(x e K).

Then

Djn = (n)n-J(0 j n).

For a

polynomial

function

f

defined

by f(x) = Ào

+

03BB1x

+ ...

Àmxm(x

E

K)

we have

DJ(0) = ÀJ (0 j

m)

and

03A6m+1f =

0-

REMARK 3: Observe that the characteristic of K is allowed to be ~ 0. For this reason we

prefer

to work with

Dn

rather than the less informative n-th derivative.

The next theorem reduces the number of variables involved.

THEOREM 2.

([2], 10.7):

Let K be as in Theorem

1,

let n E N. The

following

conditions on a

Cn-1-function f :

K - K are

equivalent.

( a) f

is a

Cn function.

(03B2)

For each a E

K, lim (x,

y) ~ a,

a)(x - y)-nRnf(x, y)

exists.

For the

proof

of Theorem 1 we need two estimates on

polynomial

functions K - K.

LEMMA 1: Let

Q:

x -

ao

+

Xlx

+ ...

+Àsxs

be a

polynomial function.

Then

If,

in

addition, 03BB0

=

À,

=...

= 03BBm

= 0

for

some m s then

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PROOF:

Everything

follows from the formula

LEMMA 2 : Let P :

x ~ 03BB0 + 03BB1x +

...

+Àmxm

be a

polynomial function

and let n E N U

(0),

n m. Then

PROOF: We have

03A6m+1P

= 0 so that

for all x, y e K. Hence

and

We find for x, y

E K, 1 x | 1, y l 1,

x =1= y that

Now

so that

Further, by

Lemma 1 we have

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292

so

Together

with

(*)

this proves Lemma 2.

PROOF OF THEOREM 1: Let

Then

and

for each n. Define

f :

K ~ K as follows.

Clearly f

is a C’-function at a for each a E

K, a ~

0. If rm+1

|x| rm

for some m E 1B1 then

We have

proved

the case n = 0 of the

following

statement. For each

n ~ N u

{0}

the function

f

is C" and

DJf(0) = Ày (0 j n ).

To prove

the

step

from n - 1 to n it

suffices, according

to Theorem 2 and Remark 2

(ii),

to show that

In its turn, this statement

follows, by continuity

of

Rn,

from "if

(6)

then

and it is the latter statement that we are intended to prove. So let

for some m, s à k. Then

We consider two cases.

(i)

s m.

Writing P,

=

Pm

+

Q

where

Q (t) = 03BBm+1tm+1

+ - ..

+ÀstS

we obtain

By

Lemma 2 the first

part

is

max(|x|, |y|) · max(|03BB0|,

|03BB1|,..., |03BBm|) rm max(|03BB0|, |03BB1|,.., |03BBm|) m-1 k-1.

To estimate the second

part

we may assume that s &#x3E; m.

Then |x - y| &#x3E;

|y|. Using this,

the definition of

Tn,

and Lemma

1,

we obtain

(ii)

s m. Then set

Pm = Ps + Q

where

Q(t) = 03BBs+1ts+1

+ ...

+Àmtm.

We find

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By

Lemma 2 the first

part

is

max( |x|, |y|) · max(|03BB0|,..., |03BBs|) rs max( 1 Ào 1,..., |03BBs|) s-1 k-1.

For the second

part

observe that

|x - y| &#x3E; |x| 1 and 1 Q) ) 1 = |03BBs+1xs+1

+ ...

+Àmxm 1

|x|s+1 max(|03BB0|,..., |03BBm|). Then

References

[1] D. BARSKY: Fonctions k-lipschitziennes sur un anneau local et polynômes à valeurs

entières. Bull. Soc. Math. Fr. 101, (1973) 397-411.

[2] W.H. Schikhof: Non-archimedean calculus (Lecture notes). Report 7812, Mathematisch Instituut, Katholieke Universiteit, Nijmegen (1978).

(Oblatum 20-VII-1983)

Mathematisch Instituut Katholieke Universiteit Toernooiveld

Nijmegen

The Netherlands

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