A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
J AIGYOUNG C HOE
The isoperimetric inequality for a minimal surface with radially connected boundary
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 17, n
o4 (1990), p. 583-593
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Minimal Surface with Radially Connected Boundary
JAIGYOUNG CHOE
As an extension of the classical
isoperimetric inequality
for domains in Euclidean space, it isconjectured
that for any k-dimensionalcompact
minimal submanifold M of R7,where Wk is the volume of the k-dimensional unit ball.
The first
partial proof
of theconjecture
was obtainedby
Carleman[C]
in 1921, who usedcomplex
functiontheory
to prove theisoperimetric inequality
for
simply
connected minimal surfaces in R7. Then,using
the Weierstrassrepresentation
formula for minimal surfaces in~3,
Osserman and Scl,,ffer[OS]
showed in 1975 that the
isoperimetric inequality
holds fordoubly
connectedminimal surfaces in
R3.
Their method wasgeneralized by Feinberg [F]
todoubly
connected minimal surfaces in ~n for all n.
Recently Li, Schoen,
and Yau[LSY] proved
theisoperimetric inequality
for minimal surfaces in with
weakly
connected boundaries. Theboundary
aE of a surface £ in R" is said to be
weakly
connected if there existsa
rectangular
coordinate system of R7 none of whose coordinatehyperplanes const}
ever separate The Poincareinequality plays
acrucial role in their paper.
They
also showed that for any minimal surface £ in with twoboundary
components(not necessarily doubly connected),
aE isweakly
connected and hence Z satisfies theisoperimetric inequality.
In this paper we
give
another sufficient condition for minimal surfaces in Rn tosatisfy
theisoperimetric inequality.
Let be a union ofcurves and p a
point
in Rn. We say that C isradially
connected from p if I ={r :
r =dist(p, q),
q EC}
is a connectedinterval,
thatis,
nospheres
centeredat p separate C.
Obviously,
every connected set in Ran isradially
connected from any p E Rn. We prove that theisoperimetric inequality
holds for every minimal surface E in R7 whoseboundary
aE isradially
connected from apoint
in Z.Research at MSRI supported in part by NSF Grant DMS-812079-05.
Pervenuto alla Redazione il 10 Marzo 1990.
Note
that,
like weak connectedness of[LSY],
radial connectedness of aEplaces
no restrictions on the
topology
of the surface E. Itimmediately
follows that every minimal surface £ in > 3) with twoboundary
components satisfies theisoperimetric inequality
since a~ isradially
connected from apoint
of 1:which is the same distance away from each
component
of 9E.Most papers about the
isoperimetric inequality
for minimal surfaces haveused the
inequality
I 1 I-where r is the Euclidean distance function from a fixed
point
p E R~ and v is the outward unit normal vector to aE on X. In this paper,however,
we use asharper inequality
where p )?( aE is the cone from p over aE. Therefore the
isoperimetric inequality
for the minimal surface £ will follow if we prove the
isoperimetric inequality
for the cone p >x al. Since every cone can be
developed
onto aplane domain, preserving
its area and thelength
of itsboundary,
theoriginal isoperimetric inequality
on the minimal surface reduces to the classicalisoperimetric inequality
on the
plane,
which is known to be true.In this process of
developing
the cone p * al onto aplane
domain D 3 p,we should
verify
that theplane
curve C c c~Ddeveloped
from 91 is connected and that C winds around pby
at least 360°. Connectedness of C follows from radial connectedness of aEby
way ofcutting
andinserting
arguments. Toverify
the second
fact,
we have to show that if p E E, thenwhere
(p ~ B1:)oo
is the infinite cone obtainedby indefinitely extending
a~across and
B’n(p, 1)
is the n-dimensional unit ball with center at p. We prove(3) by showing
thatlog
r is a subharmonic function on the minimal surface 1.(3)
was obtained alsoby
Gromov[G].
Although
we show thathigher
dimensional minimal submanifoldsMI,
k > 3, have the
properties corresponding
to(2)
and(3),
ourargument
does notcarry over to the
proof
ofhigher
dimensionalisoperimetric inequality (1)
withk > 3. This is
partly
because ingeneral
one candevelop
the cone8Mk
onto a domain in
only
if k = 2.. Here we should mention thatAlmgren [A]
recently
obtained theisoperimetric inequality
forabsolutely
areaminimizing integral
currents.We
give
some remarks and openproblems
in the last section.Finally,
we would like to thank Richard Schoen for his interest in this work.1. -
Isoperimetric inequality
for conesDEFINITION. Let S c R~ be a k-dimensional rectifiable set and p a
point
in R~. We define the k-dimensional
angle
of S from p,Ak (8, p)
to be the k-dimensional mass of(p w s)oo counting multiplicity.
Note that
where
S, p)
denotes the(k + I)-dimensional density
of p * ,S at p.Using this,
we can also define theangle
of a set in a Riemannian manifold. Note also that Gromov’s definition of the visual volume of ,S from pVis(S’; p)
isequivalent
to the k-dimensionalangle
of ,S from p in thatTHEOREM 1. Let C be a union
of
closed curvesCi,
0 i m, in andp E I~n a
point
not in C.If
C isradially
connectedfrom
p andp)
> 27r, thenI 1
PROOF. For any nonclosed space curve A c R~ and any p E A is
obviously
flat. Therefore we candevelop
A onto aplane
curve A’ in a2-plane
ncontaining
p,preserving
the distance from p and the 1-dimensionalangle
fromp.
Clearly
thisdevelopment
also preserves thearclengths
of A andA’,
and theareas of p * A and p * A’.
Moreover,
we candevelop
A in such a way that undera suitable
parametrization
ofA’,
A’ winds around p counterclockwise(nowhere moving
backward orclockwise)
at allpoints
of A’ except for a(possibly empty)
subset at which A’ is a subset of rays
emanating
from p.For each closed curve
Ci,
choose apoint qi
ECi
such thatdist(p, qi )
=dist(p, Ci),
anddevelop
the nonclosed curve{qi }
onto a curveCZ
in a2-plane
n 3 p as above.By hypothesis, dist(p, Ci)
> 0 for all i. We constructa connected
plane
curve Cby cutting C’i
andinserting C~
intoCil
as follows.Let
qi and qi2
be the two endpoints
ofC2.
SinceCi
isclosed,
we haveAssume without loss of
generality
thatIt follows from radial connectedness of C that for each 1 i m, there exists
a
point g~
in a curve E{a, ... , i - 1 },
such thatFirst,
letCi (9) : fall
] - n be aparametrization
ofCi’, t
=0, 1, by
theangle
0 taken with
respect
to a fixed ray from p in n counterclockwise. For somevalues of 0
Ci’(0)
may be a linesegment.
Then there exists x 1 E[ao, bo]
such that =
q’. Let po
be the map of counterclockwiserotation
on naround the
origin
pby
theangle
of 0. We then construct a curve in- - ... ..
By (4)
and(5)
we see thatC1
is a connected curve and thatEven if
Ci (8)
is a linesegment
for some 0, the above construction is well defined.Secondly,
letC2 (9)
be aparametrization
ofC2 by
theangle 0
witha2 9 b2. Again by
radial connectedness of C there exists x2 E I such thatNow we can construct a curve defined
by
Then
(4), (6),
and(7) imply
thatC2
is a connected curve and thatContinuing
this process until we connect all the subarcs ofCo, ... , Cm,
we canobtain a connected curve such that
Remember that
Therefore the
following
lemma willcomplete
theproof
of Theorem 1.LEMMA 1. Let
reo),
a 0 b, be a connectedplane
curveparametri.zed by
theangle from
theorigin. If dist(O, r)
>0,
b - a > 27r, andthen
Here
Area(O>x r)
countsmultiplicity,
andfor
some valuesof 0, reO)
may be aline segment which is a subset
of
a rayemanating from
theorigin. Finally, equality
holdsif
andonly if
r is a circle and b - a = 27r.PROOF. If b - a = 27r, then r is the
boundary
of a domain and the lemma follows from the classicalisoperimetric inequality.
Thus let us assume b-a > 27r.Define a subset
ra
of rby
Then the function
f (x) :
R+ ~[0,
b - a] definedby
is
monotonically nonincreasing
and lower semicontinuous. Since and limI(x)
= 0, there exists/3
> 0 such thatX-00
In case
f (x)
is continuous at x =Q,
let rl =r J3
and r2 = r -r,8.
In casef (x)
is not continuous at x =
~3,
let = r :dist(O, q) = (3}.
It follows from(9)
that there exists a subset of
rg,o
such thatLet rl =
r J3
U andF’
= r -r1.
In either case, then,by (10) (and (8)
ifr(a), r(b)
Erp)
we can see that after suitable rotations around 0 components of rl fittogether
to form theboundary
of a domain D 3 0 with the property thatHence,
by
theisoperimetric inequality
for D, we haveMoreover,
since the circleC(o, ,Q)
of radiusQ
with center at 0 lies insideD,
we have
Therefore
where the last
inequality
follows from the fact thatr2
lies inside the circleC(0, Q).
Hereequality
holds if andonly
ifr2
= S and D is adisk,
thatis,
r isa circle and b - a = 27r. This
completes
theproof.
We can
easily
see that if 0 E r, we do not need to assume b - a > 27r in Lemma 1. Thus we get thefollowing corollary
of Theorem 1.COROLLARY 1.
If C is a
unionof
closed curves in which isradially
connected
from
apoint
p in C, thenREMARK. In the
isoperimetric inequality
of Theorem 1 andCorollary 1, equality
holds if andonly
if p xK C can bedeveloped,
aftercutting
andinserting,
1-1 onto a disk.
2. - Volume and
angle
viadivergence
theoremPROPOSITION 1.
If Mk
C is a compact k-dimensional minimalsubmanifold
withboundary
and p is apoint
in JRTt, thenPROOF. Let r(x) -
dist(p, x),
x E M. From theharmonicity
of linearcoordinate functions of R~ on
Mk,
we haveIntegrating
this over M, we getwhere v is the outward unit conormal vector to aM. For q e aM, let be the
position
vector of q from p. Thenr(q)
and the tangent space of aM at q determine the k-dimensionalplane
n which containsr(q)
andTq(aM).
Letq(q)
be the unit vector in n which is
perpendicular
to aM andsatisfying q .
r > 0.Let 0 and Q be the
angles
betweenF and q,
and vrespectively.
Then we haveHence
It follows from
(14)
and(15)
thatLEMMA 2.
(i) log
r is subharmonic on any minimalsurface M2 (ii)
For k >3, r2-k
issuperharmonic
on any k-dimensional minimalsubmanifold Mk
PROOF.
since
on M.PROPOSITION 2. Let
Mk
C R7 be a compact k-dimensional minimalsubmanifold
withboundary
and p an interiorpoint of
M. ThenMoreover,
equality
holdsif
andonly if Mk
is astar-shaped
domain in ak-plane
with respect to p.
PROOF. Let
Me
= M -B-(p, -)
andBe
=Mn8Bn(p,ê)
for -dist(p, aM).
Suppose
k = 2.By
Lemma2(i),
It follows from
(15)
thatObviously, equality
holds if andonly
if1, V r ~
= 1 on M, and0 = p on
aM,
thatis,
M is astar-shaped
domain in aplane.
Now suppose l~ > 3.
By
Lemma2(ii),
Since
we obtain
completing
theproof.
THEOREM 2.
If
I is a minimalsurface
in whoseboundary
isradially
connected
from
apoint
p on L, then Isatisfies
theisoperimetric inequality.
And
equality
holdsif
andonly
is aplanar
disk.PROOF.
Proposition 1,
Theorem 1(or Corollary
1 if pE aE), Proposition 2,
and Remark.COROLLARY 2.
Every
minimalsurface I
in R" whoseboundary
consistsof
two componentssatisfies
theisoperimetric inequality.
PROOF. Choose any two
points
p and q, one from each component of 8L.Then there exists a
hyperplane
n C Rn which bisects and isperpendicular
tothe line segment pq.
By
connectedness ofE,
E n n is nonempty.Clearly
aE isradially
connected from anypoint
in I D n. Hence thecorollary
follows from Theorem 2.3. - Remarks and open
problems
(i)
Dual to radial connectedness isspherical
connectedness: A set X C R~is said to be
spherically
connected from p if theimage
of X under the centralprojection
of R7 -{p},
from p, ontoSn-I
is connected. Ingeneral, given
afamily
of maps from R" into a set U, we say that a set X c Rn is{7ri}iEI-connected
if is connected for every i E I. Therefore X isweakly
connectedaccording
to[LSY]
if X is{7r XI’ ... ,
7r Xn}-connected
for somerectangular
coordinate system{ x 1, ... ,
in R7, where7rxi«XI,..., Xn))
= Xi.(ii)
Given a k-dimensional submanifoldNk
of R7, how can one finda
point
p E Rn such thatVolume(p >x N) = minqEJRn Volume(q >x N)?
LetMC(N) = {p
E R7 :Volume(p >x N) = minq,Rn Volume(q >x N) }
and let uscall
MC(N)
theminimizing
center of N. IsMC(N)
a subset ofH(N),
theconvex hull of N? Is it true that
MC(N)
=H(N)
if andonly
if N is a convexhypersurface
of a(l~
+I)-plane
in R7?(iii)
Let C C R~ be a closed curve. Then it is not difficult to prove thatfor any p E
H(c)
since every closed curve oflength
27r on the unitsphere
in Ran is contained in an open
hemisphere (see [H]).
In view of this fact andProposition 2,
it istempting
toconjecture
that if £ c I~n is acompact
minimal surface withboundary
thenfor any
p
EH(aE).
If thisconjecture
is true, we will be able to prove theisoperimetric inequality
for some minimal surfaces with three or fourboundary components.
Indeed if we can choosepoints
= 3 or 4, one from eachcomponent of
aE,
in such a way that thepoint
p which is the same distance away from lies insideJ?(9E),
then theisoperimetric inequality
followsfrom Theorem 1 since aE is
radially
connected from p. Inparticular,
if thereexist three
points
in 8I., one from each component of aE, such thatthey
makean acute
triangle,
then the orthocenter of thetriangle
lies inside and 8I.is
radially
connected from the orthocenter.(iv)
How can one find apoint
p such that = maxqERnAk(N, q)?
(v) Proposition
1 andProposition
2 are valid even for astationary
set,S which is a connected union of k-dimensional minimal submanifolds of
Along sing(S),
thesingular
set ofS,
whose Hausdorff dimension is dim S’ - 1, several minimal submanifolds meet each other and the sum of conormal vectorson S to
sing(S)
vanishes because ofstationarity
of S.Therefore,
whenapplying divergence theorem,
we canregard
as a subset of the interior of S. Infact,
if p Esing(S’), (16)
can bereplaced by
Area
minimizing
2-currents mod 3 andcompound
soap films areexamples
ofstationary
sets.(vi)
ProveProposition
1 andProposition
2 for minimal submanifolds in S n or Hn.(vii)
There are minimal surfaces constructedby
F.Morgan
which areneither
weakly
connected norradially
connected. Let11
and L2 be areaminimizing
annular minimal surfaces inR3
which arespaced sufficiently
far fromeach other in such a way that
all
and8L2
lie in fourparallel planes. Bridge 1,
and12
with a thinstrip 13
whoseboundary
lies in aplane perpendicular
tothe four
planes.
Then thisbridged
minimal surface I is notradially
connectedfrom any
point
of itself.However,
E isweakly
connected.Now, along 8L3
attachsufficiently
many small minimal handles which are tilted in almost every direction of the space. Then oneeasily
sees that theresulting multiply
connectedminimal surface is neither
radially
connected norweakly
connected. As this surface is areaminimizing,
it satisfies theisoperimetric inequality.
(viii)
Both the method ofdeveloping
a cone into aplanar
domain and themethod of
cutting
andinserting
arepurely
two-dimensional. For this reason, we are not able to extend our arguments to the case ofhigher
dimensional minimal submanifolds.Moreover, by
N. Smale’sbridge principle [S],
there exists a3-dimensional minimal submanifold M C
R~
obtainedby joining, by
along
thin
bridge,
boundaries of two compact minimal submanifolds with no Jacobi fields which arearbitrarily
far apart from each other. ThenVolume(p)3« am)
can be
arbitrarily larger
thanVolume(M)
and hence it isimpossible
to provethe
isoperimetric inequality
for the cone p)3« aM as in Theorem 1.REFERENCES
[A]
F.J. ALMGREN, Jr., Optimal isoperimetric inequalities, Indiana Univ. Math. J., 35 (1986), 451-547.[C]
T. CARLEMAN, Zur Theorie der Minimalflächen, Math. Z., 9 (1921), 154-160.[F]
J. FEINBERG, The isoperimetric inequality for doubly connected minimal surfacesin
RN,
J. Analyse Math., 32 (1977), 249-278.[G]
M. GROMOV, Filling Riemannian manifolds, J. Differential Geom., 18 (1983), 1-147.[H]
R.A. HORN, On Fenchel’s theorem, Amer. Math. Monthly, 78 (1971), 380-381.[LSY]
P. LI - R. SCHOEN - S.-T. YAU, On the isoperimetric inequality for minimal surfaces, Ann. Scuola Norm. Sup. Pisa Cl. Sci. (4), 11 (1984), 237-244.[OS]
R. OSSERMAN - M. SCHIFFER, Doubly-connected minimal surfaces, Arch. RationalMech. Anal., 58 (1975), 285-307.
[S]
N. SMALE, A bridge principle for minimal and constant mean curvature submanifolds ofRN,
Invent. Math., 90 (1987), 505-549.Mathematical Sciences Research Institute
Berkeley, California
Current Address:
Postech
Pohang, Korea