A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
J EAN -M ARC D ESHOUILLERS
F RANÇOIS D RESS
Sums of 19 biquadrates : on the representation of large integers
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 19, n
o1 (1992), p. 113-153
<http://www.numdam.org/item?id=ASNSP_1992_4_19_1_113_0>
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On the Representation of Large Integers
JEAN-MARC DESHOUILLERS* -
FRANÇOIS
DRESSWe
give
a detailedproof
of thefollowing result,
announced in[4] by Balasubramanian,
Deshouillers and Dress.THEOREM.
Every integer larger
than10361
is a sumof
19biquadrates.
In the first edition of his Meditationes
Algebraicae,
in1770, Waringl
statesthat every natural
integer
is a sum of at most 4 squares, 9cubes,
19biquadrates.
A few years
later,
he adds that a similar statement holds forhigher
powers.Those "statements" would be
phrased nowadays
as"conjectures",
and we referto them as
"Waring’s problem".
The case of the squares was solved
by Lagrange
in1770,
and that of the cubesby
Wieferich andKempner
in 1909-1912.After Liouville
proved
around 1859 that everyinteger
is the sum of atmost 53
biquadrates,
there have been different numericalimprovements
of hisresult,
as well as extensions to somehigher
powers. Hilbert gave in 1909 the firstproof
of the fact that for any 1~ > 1 there exists aninteger
s such thatevery
integer
is the sum of at most sperfect kth
powers.(We
denoteby g(k)
the least admissible such
s).
His method does not lead to the determination ofg(k).
Hardy
andRamanujan
introduced in 1917 apowerful analytical
methodfor
dealing
with additiveproblems:
the circlemethod,
whichthey originally applied
to thestudy
ofpartitions. Shortly afterwards, Hardy
and Littlewoodgave a new
proof
of Hilbert’s theorem:typically,
their method leads to the existence ofeffectively computable
constantss(k)
andN(k)
such that everyinteger larger
thanN(k)
is a sum ofs(k) perfect
powers. In the case ofbiquadrates, they
showed in 1925 thats(4)
= 19 is an admissible value[17],
* This research has been supported in part by the Institute for Advanced Study, Princeton,
NJ 08540.
1 References to the papers which appeared before 1920 are to be found in Dickson’s History of the Theory Numbers.
Pervenuto alla Redazione il 26 Luglio 1991.
opening
the route towards the solution ofWaring’s problem
forbiquadrates.
Auluck
[1] ] proved
in 1940 that everyinteger larger
than exp exp(204)
is asum of 19
biquadrates.
Let us
shortly
describe the status ofhigher
powers. J.A. Euler observed around 1772 thatg(k)
is at least2k
+[(3/2)k] -
2,by considering
theinteger
[(3/2)k] 2~ - 1.
In1934, Vinogradov [26]
succeeded inobtaining by
the circlemethod,
admissible values of notexceeding 2 k+ [(3/2)~] -
2, and he evenproved [27]
that one may takes(k)
as small aslog k).
This means that thelarger k is,
the easier is the determination ofg(k),
this numberbeing
controlledby
therepresentation
of smallintegers. Indeed,
in1936,
Dickson[16]
and Pillai[21] ] independently
gave theexpression
ofg(k)
for k between 7 and a fewhundreds,
and theirwork, completed by Rubugunday
and Niveneventually
ledin 1944 to the
complete
determination ofg(k)
for k > 6(the complexity
of thecomputation
of is discussedby
Delmer and Deshouillers in[10]).
In
1938, Davenport [8]
introduced a new idea which turned out to bespecially
efficient for small Forbiquadrates [9],
his method relies on the direct consideration of numbers which are sums of 4biquadrates,
counted each withweight
one,regardless
of their number ofrepresentations
under thegiven
form. He
proved
that everysufficiently large integer
which is not congruent to 0 or 15 modulo 16 is a sum of at most 14biquadrates.
Thedifficulty
inusing Davenport’s
method for actualcomputation
is itsdependence
on the maximumof divisor-like
functions;
one canfigure
out theimportance
of such termsby noticing
that the maximum of the usual divisor functiond(n)
for n up tolOloo
islarger
than1015,
whereas it is a well known fact thatd(n) =
forany
positive
6’. Thisdifficulty delayed
the solution ofWaring’s problem
for5 th
powers to
1964,
when ChenJing-run [7] proved
thatg(5)
= 37. Forbiquadrates, Davenport’s
method has led Thomas[23]
to prove in 1974 thatg(4)
22, and Balasubramanian[2]
and[3]
to announceg(4)
21 in 1979 andg(4)
20 in 1985.(Those
two latter papersrely
on a numerical announcementby
Thomaswhich has been
subject
to criticism[12],
but is not usedby
Thomas in hisproof
ofg(4) 22).
The second article[3]
contains an innovative idea in the treatment ofWeyl’s trigonometrical
sums which allows his author to show that everyinteger larger
than10700
is a sum of 19biquadrates,
whereas Thomas obtained the bound101409.
That same year
1938,
Hua[18]
introduced anotheridea,
which enabled him togive
anasymptotic
estimate for the number ofrepresentations
of aninteger
as a sum of2k
+ 1perfect k -th
powers.Apparently,
Hua’s method hasthe same drawback as that of
Davenport,
in thatthey
bothdepend
on estimatesfor the maximum of divisor-like
functions;
on the otherhand,
Hua’s methodcan lead
only
to the existence ofrepresentations
oflarge integers
as sumsof 17
biquadrates,
whereasDavenport’s
method is efficientalready
with sumsof 14
biquadrates.
The first named author of this paper noticed however that the maximum of theimplied
divisor function may bereplaced by
an average of those values. The reader should rememberthat,
the maximum ofd(n)
ofn
lOloo
is at least1015,
whereas the mean-value ofd(n)
over the same rangeis less than 231.
Although
theaveraging
isperformed
over the values of apolynomial,
this remark led to theproof
that everyinteger
less than10625
is asum of 19
biquadrates [ 11 ] .
The two innovations introduced in
[3]
and[11] fortunately
turned out tobe
compatible:
whencombined, they imply
that everyinteger larger
than10530
is a sum of 19
biquadrates.
Theremaining
gapwould,
still now, be hard to coverby
numericalcomputations,
ifonly possible.
The last main
ingredient
was a carefulstudy
of the divisor sumimplied
in the modified Hua’s method. We succeeded
[13]
in that way to reduce theasymptotic
boundbeyond
which everyinteger
is a sum of 19biquadrates,
to asize, 10400,
which was within the range ofpossible computation.
At the sametime,
the second named author noticed animprovement
in Balasubramanian’s method: theasymptotic
bound fell below10367,
well within the range ofcomputation;
we indeed showed at that time that everyinteger
less than10378
is a sum of 19biquadrates: Waring
wasright!
Although
we have now extended ourcomputation [15]
to10~, making
itpossible
to relax some of thearguments
in theasymptotic
part of theproof,
wethink that it may have some historical interest to
provide
acomplete,
almostself-contained,
and accessibleproof
of our maintheorem, following
the linespresented
in[4]
and[5].
This is madepossible, through
this paper and the articles[13]
and[14].
Davenport
has shown thatonly finitely
manyintegers
cannot beexpressed
as sum of 18
biquadrates.
Under a strong numericalevidence,
oneconjectures
that
only 79, 159, 239, 319, 399,
479 and 559require
as many as 19biquadrates,
and it seems desirable to substantiate this statement.
Although
our method leadsto an effective bound
beyond
which everyinteger
is a sum of 18biquadrates,
wedoubt that it may soon lead to the determination of the
integers
that cannot bewritten as sums of 18
biquadrates.
Landreau[19]
could reduce the contribution of the divisor functionimplied
inDavenport’s method,
thanks to anaveraging
over a
sufficiently large
set, and this could lead to a"revenge"
ofDavenport’s approach.
Acknowledgement.
Whenworking
on thisproblem
we(either
orboth)
received
encouragement
andsuggestions
from E.Bombieri,
H.Halberstram,
H.Iwaniec,
H.Maier,
C.Stewart,
G. Tenenbaum and W. Schmidt: it is ourpleasure
to thank them for their
help.
CONTENTS
§ 1.
General outline of theproof
1. Hua’s version of the circle method 2. Notation. The
Farey
dissection§2.
Contribution of themajor
arcs1. The
singular integral
2. GauB sums
3. The
singular
series4.
Approximation
of5. Contribution of the
major
arcs§3.
Hua’sinequality:
reduction to a divisor sum1. On the
congruence x4 - y4 (mod k)
2. Divisor sums
3. Hua’s
inequality
1
§4. Upper
bound foro
§5. Upper
bound for theWeyl
sums on the minor arcs§6.
Proof of the main theoremFormulae have been
extensively
numbered in order tohelp
the reader infinding
his/her waythrough
the paper.§ 1. -
General Outline of the Proof 1.1 Hua’s versionof
the circle methodLet N be a
positive integer.
We define t as theinteger
in the interval[4, 19]
which is congruent to N mod 16.By
P we denote aninteger
in theinterval
[0. 14Nl/4 0. 17N 1/4]
which will be chosen later on. Our aim is to show that the number of ways, let us call itr(N),
to represent N as a sum of the fourth powers of t oddintegers
in]2P, 4P]
and s = 19 - t evenintegers
in thesame interval is
strictly positive.
For that purpose, we follow the circlemethod,
based on theintegral representation
where
The interval
[o,1
] isdecomposed
as a union of two distinct sets .M and m,respectively
called themajor
and minor arcs. Aprecise
definition isgiven
insection
1.2; roughly speaking,
.M iscomposed
of those a’s which are close to arational with a small denominator. Because of this arithmetic
property,
a lower bound of the contribution of .M to theintegral
1.1.1 can beobtained;
this isthe aim of the second
chapter.
On the minor arcs, we use Hua’s
method,
that is to say that werely
on1
upper bounds
for
o The firststep,
whichstrictly
follows[ 11 ],
isto reduce the
problem
tofinding
an upper bound for the mean value of the number of ways to represent the values of a certainpolynomial
as aproduct
of 3
integers.
This is done in the thirdchapter.
We dealt with this divisor sumin an
independent publication [13],
and wesimply exploit
it inchapter
4.The next step is to get an upper bound for the maximum of the
jigo-
nometrical
sums
over the minor arcs; weagain
invoke anindependent publication, namely [14]
which presents animprovement
on Balasubramanian’s method[3].
In the last
chapter,
we puttogether
the differentestimates,
in order to show that the contribution of themajor
arcs islarger
than that of the minor arcs,concluding
thatr(N)
> 0, and thus that N is the sum of 19biquadrates
when N >
10364,
which is a bit stronger than stated in the Theorem.1.2 Notation. The
Farey
dissectionBy
vo we denote a real number in the interval[85, 151],
the existence of which is asserted in section 2.1.By
N, we denote aninteger > 101°;
theintegers
s and t are definedby
the relations
We denote
by Po
and P thequantities
We call
major
arcs the union .Ivl of thepairwise
distinct intervals0 a q,
(a, q) =
1.The minor arcs m is the
complementary
set of Jvl in the interval- 975 11 9751
p3
1p3
Finally,
for - E{ o, 1 },
we writewhere
e(u)
= For anintegral
q, we writeeq(u)
=e(u/q).
§2. -
Contribution of themajor
arcsWith the notation introduced in section
1.2,
we haveTHEOREM 2. Let N be an
integer larger
than10320;
we have2.1 The
singular integral
PROPOSITION 2.1. There exists a real number vo E
[85, 151 ]
such that on haswhere
PROOF OF PROPOSITION 2.1. We consider a
family (Xl, ... , X19)
of inde-pendent
randomvariables, equidistributed
on the interval[1,2],
and we letWe have
2
The
integral
can beinterpreted
as the characteristic function1
2 9
(i.e.
Fouriertransform)
ofXi; thus,(I 2 e(,3t4)dt) represents
the characteristicu 7
function of Z, and
by
inverse Fouriertransform, K(v)
represents thedensity
ofZ at v.
By
theBienayme-Cebysev theorem,
we havewhence the result.
2.2.
GauJ.3
sumsFor s E
{0, 1 },
we get an upper bound for the sumsA
general
result forbiquadratic trigonometrical
sum isgiven by
Necaevand
Topunov. However, using directly
this result would lead to a constant inProposition 2.2,
toolarge
for our purpose. We shall derive the main result of this section from anupperbound
for GauB sums of theshape
given
in the thesis of Thomas[23],
and that we shall proveagain,
for the sakeof the
completeness.
PROPOSITION 2.2. For v
integer,
a and qcoprime,
and - E{0, 1 ~,
we haveLEMMA 2.2.1
(NECAEV
AND TOPUNOV[20]).
LetF(X)
=a4X4
+a3X3
+a2X 2
+ a 1 X be apolynomial
withintegral coefficients,
and let p be aprime
number and s a
positive integer
such thatWe have
in the
following
cases:LEMMA 2.2.2
(THOMAS [23]).
Let a, b and q be threeintegers
such thatgcd(a, b, q)
= 1.We have
PROOF OF LEMMA 2.2.2.
By
themultiplicativity
of thetrigonometrical
sums, we have
If we denote
by c(p)
the factors in the RHS of2.2.6,
Lemma 2.2.2 anda direct
computation imply
that one hasexcept when p is
2, 5, 13,
17 or41,
in which cases one hasfrom which Lemma 2.2.2 follows. D
PROOF OF PROPOSITION 2.2. In a first step, we reduce the
majorization
ofto that of
Go(a,
q;v),
since we haveso
that,
for odd v we getand for even v, Lemma 2.2.1 leads to
Since a
and q
arecoprime,
theg.c.d.
of 16a, v and q is a divisor of16;
let us call it
2k(with k 4).
We haveand
by
Lemma2.2.2,
we havesince k is at most 4.
Proposition
2.2 now follows from2.2.9,
2.2.10 and 2.2.12.2.3 The
singular
seriesPROPOSITION 2.3. Let us
define
where
For any
integer
N, the seriesS (N)
convergesabsolutely,
and one hasPROOF OF PROPOSITION 2.3. The absolute convergence of 2.3.1 comes
from
Proposition
2.2. Let us denoteby M(q, N)
the number of solutions of the congruenceBy
the Chinese remaindertheorem,
the arithmetic function q- M(q, N)
ismultiplicative. Moreover, by detecting
the congruence mod q with an additive character onereadily
getswhich
implies
two facts:(2.3.5)
the function d HA(d, N)
ismultiplicative
so that S can be written as an Eulerproduct.
(2.3.6)
each factor of thisproduct
can be written as limp-18n M(pn, N).
n-~oo
Our
problem
is thus reduced togetting
a lower bound forM(pn, N).
LEMMA 2.3. For
prime
p, a lower boundfor M(pn, N)
isgiven by
thefollowing
relationsPROOF OF LEMMA 2.3. A common
ingredient
in theproof
of the differentinequalities
is that above anynon-singular
solution off (xo, - - ., xs) -
0(mod p),
one can find solutions of
----
For 3 and
5,
a directcomputation
can beperformed by hand,
since theonly biquadrates
are 0 and 1. Forexample,
one hasone computes in a similar way
M(3, 0), M(3, 1), M(3,2), M(5, 0), M(5,1), M(5, 2), M(5, 4),
and gets 2.3.8 and 2.3.9.For odd p, it is sufficient to consider a lower bound for
M(p, N) -
1,which is itself a lower bound for the number of
non-singular
solutions of 2.3.4.Following [6] (p. 15),
we getwhich
readily
leads to 2.3.10 and 2.3.11.Finally,
when p = 2, our choice of s and t leads toLet now n be > 4, and consider
integers
yl, ... yt solutions ofthe
integers
x +2n-3, ... , xs
+2n-3,
yl +2n-3,... yt
+2n-3
are also solutions of 2.3.15. If we denoteby L(2n, N)
the number of arrays(xl, ... ,
xs, yl, ... ,yt)
ofintegers satisfying
and
2.3.15,
we haveWe now compute
L(2n, N) by
induction on n. Let(Àl,..., Às,
J-ll,...,lit)
Ef 0, 11 19;
wehave,
modulo2n+l:
Since t > 0 and
(2yt + 1 )
is invertible mod 2, to eachcan be associated a
unique >t
inf 0, 1)
such that one hasThus,
for n > 4, one hasNow,
2.3.7 follows from2.3.14,
2.3.17 and 2.3.20. D We return to theproof
of theProposition
3.3.By
the Lemma 2.3 and the facts 2.3.5 and2.3.6,
we haveand a hand
computation
leads to 2.3.3. F-12.4
Approximation of Se(a)
On the interval
a - 975 a
+qP3 ’
wegive
anapproximation
ofsea)
q q
qp3 I
g pp e( )
in terms of the Gaul3 sums q;
0)
introduced in2.2.1,
and of theintegral
PROPOSITION 2.4. For
a - a
+{3,
with 0 a q,(a, q) =
1 andg
1{31 975/(qp3
we haveq
In
particular, , for
qp112,
we haveBefore
embarking
on theproof
ofProposition 2.4,
we state and prove thefollowing
lemmaLEMMA 2.4. Let P > 0,
~/3~ 975/(qP3)
and havewhere
Furthermore, if
PROOF OF LEMMA 2.4. As in Lemma 9.3 from
[23],
we follow Titchmarsh[25],
except that we use his Lemma 4.5(stationary phase method). Integrating by
parts leads us towe then
apply
Titchmarsh’s Lemma withthis leads to
2.4.4; furthermore, if |03B2| ( 1024qp3)-1 or Ivl I
>106,
we noteh
G ,
hG I. 320000q
that G
F ismonotonic,
continuous and Fl( )
is at most320000q v 2
over[2P, 4P] .
DPROOF OF PROPOSITION 2.4. Let
J(h)
be the intervalwe note that there are at most 2 values of h mod q such that either
endpoint
of
J(h)
is aninteger.
We havewhere 101
1, and the asterisk means that aweight 1/2
is attached to any termcorresponding
to anendpoint
ofJ(h).
By
Poisson summationformula,
we havewhich
easily
leads toBy
Lemma 2.4 andProposition 2.2,
the RHS of 2.4.10 is at mostwe get an upper bound for the last sum
by using
atechnique already
usedby
Thomas
[23],
whichrely
on theinequality
which is valid for any
integral j.
By
the definition ofG,,
we getApplying
three more times thistechnique,
we getThe relation 2.4.2 follows then from
2.4.10,
2.4.11 and2.4.14,
and relation2.4.3 is a direct consequence of 2.4.2. D
2.5 Contribution
of
themajor
arcsThe
key
result of this section is thefollowing
PROPOSITION 2.5. For P >
1060
we havewhere K is
defined by
2.1.2.Under the conditions of
Proposition 2.4,
we havewhere
and
We first get an
upperbound
forI(,Q, N).
LEMMA 2.5.1. We have
PROOF OF LEMMA 2.5.1. The first
upperbound
is trivial. Let us assume now that# f0;
wechange
the variable andintegrate by
parts,getting
whence
and so 2.5.5 is proven. 0
LEMMA 2.5.2. We have
PROOF OF LEMMA 2.5.2.
step. From Lemma 2.5.1 and
Proposition 2.2,
we get2nd
step. LetT(a)
For 6- CfO, 11,
u in Z+ and ain we have
whence
PROOF OF PROPOSITION 2.5. We
perform
the summation over themajor
arcs, and use 2.5.7 in
conjunction
with the relationsBy changing
thevariable,
thequantity
and this leads to 2.5.1.
PROOF OF THEOREM 2. Because of the definition of
S (N) (cf.
2.3.1 and2.3.2),
and theProposition 2.2,
we haveWe notice that both the double sums in the LHS’ of
Proposition
2.5 arereal.
Combining
2.5.1 and 2.5.14 we getWe now recall the definition 2.0.2 of
Po,
that of vo inProposition
2.1 and the lower bounds 2.1.1 and 2.3.3 forK(vo)
andS(N) respectively.
We getand Theorem 2 follows from the fact that for N >
10320, po
islarger
than10~g
and so the second term in the
right
hand side of 2.5.15 ispositive.
D§3. -
Hua’sinequality:
reduction to a divisor sumIn section
3.3,
we shall prove thefollowing
resultTHEOREM 3. For - = 0 or 1, we assume that there exists a real number
B,(P) satisfying
the relations .where the summation condition is
where A is any real number with 0 ~ 0.5.
3.1 On the congruence
x4 - y4 (mod k)
PROPOSITION 3.1. Let X >
10g~
andwe have
We should notice that an effective result on
prime
in the arithmetic pro-gressions
mod 4 would lead to an upper boundA(X)
X)~.
Let
N(k)
denote the number of solutions of thecongruence 03BE4 = q4
(mod k).
We havewhere all the congruences are taken modulo k.
The function N is
multiplicative,
and wesimply
show an upper bound of which isgood enough
for our purpose. We denoteso that
LEMMA 3.1.1. For any
prime
number p, we havePROOF OF LEMMA 3.1.1. As soon as p
divides ~ and ç4 -
it divides 77;but,
if pdivides ~
and q, thenp4 divides ç4 - 7y~;
this leads to 3.1.6.Let now £ > 5, and consider the solutions of
We
let ~
= py, so that 3.1.9 isequivalent
toand each of the solutions of
leads to
p6
solutions of 3.1.10. This shows 3.1.7.From 3.1.6. and
3.1.7,
we havewhence we get
which is
equivalent
to 3.1.8.LEMMA 3.1.2. For any odd
prime
numbers p, we haveREMARK. We have indeed =
4(p - 1)
or2(p -
1)according
as p is congruent to 1 or 3 modulo 4.PROOF OF LEMMA 3.1.2. Let a E
[0,p[
and let r(cx) denote the number of~
in[0,p[
such thatç4 ==
a[p].
Since if andonly
if a = 0, we havesince p is
prime,
thecongruence ~4 =
a[p]
has at most 4solutions,
and sowhich proves the first part of
3.1.1 l;
we computedirectly Nl (3).
Let now £ > 2 and
(x, y)
be a solution ofSince p does not divide
4xy,
this solution isnon-singular,
and aboveit,
thereare
exactly
pnon-singular
solutions[p~],
whence 3.1.12.From
3.1.12,
we getwhich
implies
whence 3.1.13.
LEMMA 3.1.3. We have
PROOF OF LEMMA 3.1.3: We prove 3.1.17
by
a directcomputation. By noticing
that(x
+2k-3)4
iscongruent
tox4
modulo2k-l,
but not modulo2’~
when k > 5 and x
odd,
we showby
induction on k that there are2k-4
oddbiquadratic
residues modulo2k
and that each of them is obtained 8times,
fork > 4. This leads to 3.1.18. The relation 3.1.19 is then
straightforward.
DLEMMA 3.1.4. We have
PROOF OF LEMMA 3.1.4. It is a
straightforward application
of the relation3.1.5 and the three
previous
lemmas. For theprime
2, we get from3.1.6,
3.1.8 and 3.1.19 the relationwhich is 3.1.20.
When p is
odd,
we get from 3.1.8 and 3.1.13 the relationWhen
p = 3,
relations 3.1.23 and 3.1.11 lead towhich is 3.1.21.
For a
prime
p > 5, relations 3.1.23 and 3.1.11 lead toso that we have
whence 3.1.22 is proven. D
PROOF OF PROPOSITION 3.1.1.
By inequality 3.1.2,
we haveBy
Lemma3.1.4,
this leads toFrom 3.1.6 and
3.1.11,
we haveN(p) 4p,
so that we getCombined with the relation
(3.18)
from Rosser and Schoenfeld[22],
our last relation 3.1.24 leads tofrom where
Proposition
3.1easily
follows.3.2 Divisor sums
In this
section,
wegive
some upper bounds for mean-values of divisor functions.PROPOSITION 3.2. Let P >
1074 ; for
0 A 0.5, we haveand, for
1 /c 2, we haveThese results are
by
no means bestpossible,
but their derivation is com-pletely elementary
and easy, andfurthermore, they
are not far frombeing
bestpossible
in the range where we shall use them. The reader should not have anydifficulty
inproviding
aproof
for thefollowing lemma;
ifneeded,
a referencecan be the work of Chen
[7].
LEMMA 3.2.1. Let X > 1 have
and
where
PROOF OF 3.2.2. It is
enough
to prove 3.2.2 for K = 1 and x = 2, and thenapply
Holder’sinequality.
The case x = 1 isfairly straightforward (inversion
ofsummations);
for /c = 2, we haveBy
thecase j
= 1 of3.2.3,
the sum under consideration is at mostwhich is less than
LEMMA 3.2.2. For X > 1 and 0 ~ 0.5, we have
PROOF OF LEMMA 3.2.2.
By
Hölder’sinequality,
it isenough
toverify
the cases A = 0 and A =
1 /2.
The case A = 0 of 3.2.6 reduces to the
case j =
2 of3.2.4,
sinceL d(8)0
=d(n).
81n
For A =
1 /2,
we notice thatCauchy’s inequality implies
we
thus
havewhere the last
inequality
comes from thesubmultiplicativity
of the divisor function. The case A =1/2
of Lemma 3.2.2 now followsdirectly
from the casesj = 1 and j = 2
of 3.2.4. DPROOF OF 3.2.1. Let us denote
by Sa
the LHS of 3.2.1.We have
-
where the variables y and k
satisfy
expanding
the square, we findWe let with m = mi ni ; we have
where the summation conditions are
We thus have
for the sum over s2 we use Holder’s
inequality
and 3.2.3:we now sum this relation
by parts,
which leads toin 3.2.13 the sum over r2 is
trivial,
and that over r 1 is dealtwith,
thanks to thefollowing
easyinequality
Indeed,
if one denotesby g(z)
the LHS’ of3.2.16,
it is easy to checkthat g
isconstant on any y interval
121 2 n n + 1 ,
that one hasBy 3.2.14, 3.2.15, 3.2.16,
theinequality
3.2.13 becomesSince P >
10~4,
we deduce from 3.2.17 thatWe now use Lemma 3.2.2 and get
which is 3.2.1.
3.3 Hua’s
inequality
In this
section,
we prove Theorem 3.Let us denote
by Io
the interval]P - -/2,
2P --/21.
step.
By
Parseval’sidentity,
we havewhere
we may thus write
where
If
h~0,
relation 3.3.4implies
thath,
1 has the samesign
as h, so thatFor a
given positive hl,
the function y H(2y
+_)3
+ +e)2
+(2y + -) + 2h 3 1
isstrictly increasing
on10;
we haveFrom 3.3.5 we get
which leads to
and so we have
From 3.3.5 and Parseval’s
equality,
we getand
finally, Proposition
3.1 and relations3.3.13, 3.3.7,
and 3.3.12 lead to1
We may notice here that Greaves has proven that .
indeed
=o
O(P2);
however hisresult, though effective,
wouldimply
a tremendous constant;on the other
hand,
3.3.14 will enter our final resultonly
as anegligible
error-term.
3nd
step. On onehand,
we writeso that we have
and
by
Parseval’s relationOn the other
hand, by applying Cauchy’s inequality
to3.3.2,
we getwhere
We may thus write
where
From
3.3.20,
we see thatQ2(hl, h2, y)
vanishesonly
whenh,
orh2
is zero, so thatIf h is not divisible
by 16,
then Ch,2 = 0. If h is divisibleby 16,
and different from0,
we write h =16.~;
the coefficient c 15~,2 is at most twice the number of waysto write Itl I
as aproduct
of threepositive integers: indeed,
ifhl =
±u,h2 - v, lhl
we have to solve3(2y
+ c +h,
+h2)2 + hl + h2
1 2 = wwith
2y
+ ~ +h,
+h2
> 0, which admits at most one solution. We thus havewhere
B,(P)
satisfies relations 3.0.1 and 3.0.2.By
3.3.15 and3.3.21,
we haveWe now use 3.3.16 and 3.3.17 for
estimating
thebh,2’s
and 3.3.23 and3.3.24,
for the We getwhere we let
By 3.3.14,
we getWe now use
3.0.1;
for P >10~4,
weget
4th
step. As we start to be used to, we writeso that we have
and
In connection with
3.3.18,
we introduce thefollowing
notation. For aninteger k,
we letIf is non empty, we choose a
triple
that we denote(hl(k), h2(l~), I(k)),
such thatis empty, which is
surely
the case when 41~ >P2,
we defineWe further write
and we discard the value k = 0 in
SE by defining
From 3.3.18 we deduce
and
by Cauchy’s inequality,
weget
for 0 A 2The
expression
may be rewritten aswhere
and
with this
notation,
we havewhere
We shall retain from 3.3.45
only
thefollowing
relationsand,
From 3.3.37 and
3.3.44,
we getCombined with
3.3.30,
this leads toand
Cauchy
and Schwarzinequalities
allow to writeTogether
with3.3.46, 3.3.32,
3.3.31 and3.3.29,
this leads toIn order to solve the
quadratic inequality 3.3.52,
we notice that for x > 0 wehave
so
that,
for a > 0 and b > 0 we haveFrom 3.3.52 and
3.3.54,
weget
We use 3.3.47 and 3.3.48 to
majorize
thech,3’s:
1
We have now reduced the
majorization of
to that of divisor0
sums, for which we
apply Proposition
3.2. Weget,
for 0 ~ 0.5which leads to
3.0.4, by using
the upper bound 3.0.1 forBe
in the second termof the RHS. D
1
~4. - Upper
bound forJ
0
We combine Theorem 3 with the main result of
[13],
in order to derivethe
following
THEOREM 4. Let P be
larger
than and u and v be twointegers
suchthat 4 v 16 and u + v = 16. We have
We
quote
the main result of[13].
PROPOSITION 4.0. With the notation
of
Theorem 3, we may take,for
P >
lO8o
with
Co
= 1.734.10-2
and Ci = 8.18.10-4.
PROOF OF THEOREM 4. Thanks to Holder’s
inequality
we haveand we can use Hua’s
inequality
to get a bound for eachintegral
in the RHSof 4.0.3
(cf.
4.0.7 and4.0.10).
In the case when c = 0, we use Theorem 3 with A = 0.24.
By
3.0.4 and4.0.2,
we getsince
Log
P > 200, we haveand so, from 4.0.4 and
4.0.5,
we getIn order to compare it with the
integral
of,Sl (a),
we shall use thefollowing
In the case when 6 = 1, we use Theorem 3 with A = 0.12.
By
3.0.4 and4.0.2,
we getsince
Log
P > 200, we haveand,
from 4.0.8 and4.0.9,
weget
We come back to 4.0.3. Since v > 4, and the RHS of 4.0.10 is smaller than that of 4.0.7, we have
which leads to 4.0.1.
§5. - Upper
bound forWeyl
sums on the minor arcsTHEOREM 5. With the notation
of
section 2.0, wehave, for
a E m andP >
1080:
where e = 0 or 1.
By
Dirichlet’sapproximation theorem,
for any a E m, we may find apair (a, q)
ofcoprime integers
withWhen q
islarger
than 4.106P,
the main result of[14]
tells usprecisely
that 5.0.1 holds. It may be
interesting
at thatpoint
to underline thequality
of
5.0.1,
whichimplies
that for P =1091,
wehave 394 P~~g
on theminor arcs, it
being possible
to reduce this boundthrough
theimprovements explained,
but notperformed
in[14].
Proposition
5.1 will close theproof
of Theorem 5.5.1 Contribution
of
the minor arcs associated to smallq’s
PROPOSITION 5.1. Let a be a real number
for
which one canfind integers
P, q, a, such thatfor c
= 0 or 1 we havePROOF OF PROPOSITION 5.1. From 2.4.2 in
Proposition 2.4,
we haveWe then use
Proposition 2.2,
and rewrite 2.2.3 asas well as the trivial upper bound
We get
which is 5.1.2. D
§6. -
Proof of the main theoremThe
general
route has beenexplained
in the firstchapter.
With the notation of 1.0.1 we want to prove thatr(N)
> 0 for N >10364.
Because of 2.0.2 and the fact that vo 151, we have P > 1.4 -109°,
and we canapply
Theorems2,
4 and 5.
By
Theorem 4 and5,
we haveand
by
Theorem2,
we haveThe ratio of the RHS of 6.0.2
by
that of 6.0.1 is a function P which isincreasing
for P > 1.4 -109°,
and takes the valuefor P = 1.4.
.1090.
Thisimplies
that for P > 1.4 ..1090,
we haveand so every