J
OURNAL DE
T
HÉORIE DES
N
OMBRES DE
B
ORDEAUX
W
ADIM
Z
UDILIN
Well-poised hypergeometric service for diophantine
problems of zeta values
Journal de Théorie des Nombres de Bordeaux, tome
15, n
o2 (2003),
p. 593-626
<http://www.numdam.org/item?id=JTNB_2003__15_2_593_0>
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
Well-poised hypergeometric
service
for
diophantine problems
of
zeta
values
par WADIM ZUDILIN
RESUME. On montre comment les concepts
classiques
de sérieset
intégrales hypergéométriques
bienéquilibrées
devient crucial dans l’étude despropriétés
arithmétiques
des valeurs de la fonction zêta de Riemann. Par ces arguments, on obtient(1)
un groupe depermutations
pour les formes linéaires en 1 et03B6(4) =
03C04/90
donnant unemajoration
conditionnelle de la mesure d’irrationalité de03B6(4) ; (2)
une récurrence d’ordre deux pour03B6(4)
semblable à celles introduites par Apéry pour03B6(2)
et03B6(3),
ainsi que desrécurrences d’ordre réduit pour les formes linéaires en des valeurs de la fonction zêta aux entiers
impairs ;
(3)
un gros groupe depermutations
pour une familled’intégrales multiples généralisant
les
intégrales
dites de Beukers pour03B6(2)
et03B6(3).
ABSTRACT. It is
explained
how the classical concept ofwell-poised
hypergeometric
series andintegrals
becomes crucial instudying
arithmetic
properties
of the values of Riemann’s zeta function.By
thesewell-poised
means we obtain:(1)
apermutation
group for linear forms in 1 and03B6(4) =
03C04/90
yielding
a conditional upper bound for theirrationality
measure of03B6(4);
(2)
a second-orderApéry-like
recursion for03B6(4)
and some low-order recursions forlinear forms in odd zeta
values;
(3)
a richpermutation
group fora
family
of certainEuler-type multiple integrals
thatgeneralize
so-called Beukers’
integrals
for03B6(2)
and03B6(3).
1. Introduction
In this
work,
we deal with the values of Riemann’s zeta function(zeta
values)
at
integral points s
=2, 3, 4, ....
Lindemann’sproof
of the transcendenceof ~r as well as Euler’s formula for even zeta
values,
summarizedby
theinclusions ~ (2n)
EQ7r2n
for n= 1, 2, ... ,
yield
theirrationality
(and
tran-scendence)
of~’(2), ~’(4), ~(6), ....
Thestory
for odd zeta values is not socomplete,
we knowonly
that:~
~’ (3)
is irrational(R.
Apery
[Ap],
1978);
~
infinitely
many of thenumbers ((3), ~’ (5), ~ (7), ...
are irrational(T.
Ri-voal
~Ril], [BR],
2000);
. at least one of the four numbers
((5), ((7), ((9), ((11)
isirrational1
-(this
author[Zu3], [Zu4],
2001).
The last two results are due to a certain
well-poised
hypergeometric’
con-struction,
and a similarapproach
can beput
forward forproving Ap6ry’s
theorem
(see
[Ri3]
and[Zu5]
fordetails).
After remarkable
Apery’s
proof
[Ap]
of theirrationality
ofboth ((2)
and~ (3),
there haveappeared
several otherexplanations
ofwhy
it is so; we arenot able to indicate here the
complete
list of suchpublications
and mention the most knownapproaches:
~
orthogonal polynomials
[Bel], [Hat]
andPade-type
approximations
[Be2], [Sol], [So3];
~
multiple Euler-type
integrals
[Bel], [Hat], [RV2];
~hypergeometric-type
series[Gu], [Nel];
~ modular
interpretation
[Be3].
G. Rhin and C. Viola have
developed
a newgroup-structure
arithmeticmethod to obtain nice estimates for
irrationality
measures of~’(2)
and((3)
(see
[RV1],
[RV2],
[Vi]).
Thepermutation
groups in[RV1], [RV2]
formulti-ple integrals
can be translated into certainhypergeometric
series andinte-grals,
and this translation[Zu4]
leads one to classicalpermutation
groups(due
to F. J. W.Whipple
and W. N.Bailey)
forvery-well-poised
hypergeo-metric series.
The aim of this paper is to demonstrate
potentials
of thewell-poised
hypergeometric
service(series
andintegrals)
insolving quite
differentprob-lems
concerning
zeta values. Here we concentrate on thefollowing
features:~
hypergeometric permutation
groups for((4) (Sections 3-5)
and for linear forms inodd/even
zeta values(Section
8);
~ a conditional estimate for the
irrationality
measureof ~ (4)
via thegroup-structure
arithmetic method(Section 6);
. an
Ap6ry-like
differenceequation
and a continued fractionfor ((4)
(Section 2)
and similar differenceequations
for linear forms in oddzeta values
(Section 7);
’The first record of this type, at least one of the nine numbers ((5), C(7), C(21) is irrational,
is due to T. Rivoal [Ri2].
2We refer the reader to [Ba], Section 2.5, or to formula (69) for a formal definition, to [An]
.
Euler-type multiple
integrals
represented very-well-poised
hypergeo-metric series
and,
as a consequence, linear forms inodd/even
zetavalues
(Section
8).
All these features can be considered as a
part
of thegeneral
hypergeometric
construction
proposed recently by
Yu. Nesterenko[Ne2], [Ne3].
Hypergeometric
sums andintegrals
of Sections 3-6 areprompted by
Bailey’s integral
transform(Proposition
2below),
and it is apity
that thepermutation
group for~(4) (containing
51840elements!)
leads to anesti-mate for the
irrationality
measure of~(4)
under a certain(denominator)
conjecture only.
We indicate thisconjecture
(supported
by
our numericalcalculations)
in Section 6. Theparticular
case of the construction ispre-sented in Section
2;
this case can beregarded
as atoy-model
of thatfollows,
and its main
advantage
is a certain nice recursion satisfiedby
linear formsin 1 and
~(4).
Section 7 is devoted to difference
equations
forhigher
zetavalues;
such recursions makepossible
topredict
a true arithmetic(i.e., denominators)
of linear forms in zeta values.
The
subject
of Section 8 is motivatedby multiple integrals
that were
conjecturally Q-linear
forms inodd/even
zeta valuesdepending
onparity
of k(see
[VaD]).
D.Vasilyev
[VaD]
required
several clever butcumbersome tricks to prove the
conjecture
for k = 4 and k = 5.However,
one can see. no obvious
generalization
ofVasilyev’s
schemeand,
in[Zu4],
wehave made another
conjecture, yielding
the old one, about the coincidenceof the
multiple integrals
with somevery-well-poised hypergeometric
series.We now prove the
conjecture
of[Zu4]
in moregeneral settings
andexplain
how this result leads to a
permutation
group for afamily
ofmultiple
inte-grals.
Acknowledgements.
I amgrateful
to F. Amoroso and F. Pellarin fortheir kind invitation to contribute to this volume of Actes des 12èmes
ren-contres
arithmétiques
de Caen(June
29-30,
2001).
I amkindly
thankful’to T. Rivoal for his comments and useful discussions on the
subject
and toG. Rhin for
pointing
out the reference[Co],
where the recurrence for((4)
was first discoveredby
means ofApery’s
original
method.Special
gratitude
is due to E. Mamchits for his valuable
help
incomputing
the group 6 of Section 5 for linear forms in1,
C(4).
2. Difference
equation
for((4)
In his
proof
of theirrationality
of((3),
Ap6ry
consider the sequences unand vn
of rationalssatisfying
the differenceequation
A
prior£,
the recursion(1)
implies
the obvious inclusionsn!3vn
EZ,
but a miracle
happens
and one can check(at
leastexperimentally)
theinclusions
for each n =
1, 2, ... ;
here andlater,
by
Dn
we denote the least commonmultiple
of the numbers1, 2, ... ,
n(and
Do
= 1 forcompleteness),
thanksto the
prime
number theoremThe sequence
is also a solution of the difference
equation
(1),
and itexponentially
tendsto 0 as n -3 00
(even
aftermultiplying
itby
Dn).
A similarapproach
hasbeen used for
proving
theirrationality
of((2) (see
[Ap], [Po]),
and several otherAp6ry-like
differenceequations
have been discovered later(see,
e.g.,[Be4]).
Surprisingly,
a second-order recursion exists forC(4)
and we are now able topresent
and prove itby
hypergeometric
means.Remark.
During
preparation
of thisarticle,
we have known that the differ-enceequation
forC(4),
inslightly
differentnormalization,
had been statedindependently by
V. Sorokin[So4]
by
means of certainexplicit Pade-type
approximations.
Later we have learned that the same butagain
differ-ently
normalized recursion had beenalready
known[Co]
in 1981 thanksto H. Cohen and G. Rhin
(and
Ap6ry’s original
’acc6l6ration de laconver-gence’
method).
We underline that ourapproach
presented
below differsfrom that of
[Co]
and[So4].
We also mention that no second-order recursionfor
C(5) and/or
higher
zeta values is known. Consider the differenceequation
with the initial data
for its two
independent
solutions Un and vn.Theorem 1. For each n =
0,1, 2, ... ,
the numbers Un and vn arepositive
rationals
satisfying
the inclusionsand there holds the limit relation
Application
of Poincar6’s theorem thenyields
theasymptotic
relationsand
(see [Zul],
Proposition
2)
since the characteristic
polynomial
a2 -
270A - 27 of theequation
(3)
haszeros
135±78B/3 =
(3f2~)3.
Thus,
we can considervn/Un
asconvergents
of a continued fraction for
((4)
andmaking
theequivalent
transform of thefraction
([JT],
Theorems 2.2 and2.6)
we obtainTheorem 2. There holds the
following continued-fraction expansion:
where the
polynomial
b(n)
isdefined
in(4).
Unfortunately,
the linear formsdo not tend to 0 as n -~
00.3
A motivation of a
hypergeometric
construction considered below leans on the two series- - - "I2
(Gutnik’s
form ofApery’s
sequence[Gu],
[Nel]),
and(Ball’s sequence),
and on the coincidence of these seriesproved
by
T. Rivoal[Ri2],
[Ri3]
with ahelp
of the differenceequation
(1).
Thesearguments
make
possible
togive
a new’elementary’
proof
of theirrationality
of((3)
(see
[Zu5]
fordetails).
Consider the rational function
and the
corresponding
seriesIn some sense, the series
(11)
is a mixedgeneralization
of both(8)
and(9).
Lemma 1. There holds the
equality
Proof.
Thepolynomials
are
integral-valued
and,
as it is wellknown,
where
P"(t)
is any of thepolynomials
(13).
The rational functionhas also ’nice’ arithmetic
properties. Namely,
Hence, for j
=1, 2, ...
we obtain-Therefore the inclusions
(14), (16), (17)
and the Leibniz rule fordifferenti-ating
aproduct
imply
that the numberssatisfy
the inclusionsNow, writing
down thepartial-fraction
expansion
of the rational func-tion(10),
we obtain that the
quantity
has the desired form
(12)
withwe deduce that
Un,
Dn U;~’,
E Z asrequired.
0Now,
with ahelp
ofZeilberger’s algorithm
of creativetelescoping
Chapter
6)
weget
the rational function(certificate)
~S’n(t)
:=sn(t)Rn(t),
where
satisfying
thefollowing
property.
Lemma 2. For each
n = 1, 2, ... ,
there holds theidentity
where the
polynomial
b(n)
isgiven
in(4).
where is
given
in(23).
0 Lemma 3. Thequantity
(11)
satisfies
thedifference
equation
(3)
for n =
1,2,....
Proof.
SinceRn(t)
=O(t-3)
andSn(t)
=O(t-2)
as t -3 oo for n >1,
differentiating
identity
(24)
andsumming
the result over t =1, 2, ..
wearrive at the
equality
(n
+b(n)Fn -
3n 3(3n -
1) (3n
+ =Sn (1)
-It remains to note
that,
1,
both functions andSn(t) _
sn(t)Rn(t)
have second-order zero at t = 1. ThusSn(1)
= 0 for ~c =1, 2, ...
and we obtain the desired recurrence
(3)
for thequantity
(11).
0Lemma 4. The
coefficients Un,
Un,
Un, Un",
Vn
in therepresentation
(12)
satisfy
thedifference
equation
(3)
for
n =1, 2, ....
Proof.
Write thepartial-fraction expansion
(20)
in the formwhere the formulae
(18)
remain valid for all J~ E Za,nd j = 1, 2, 3, 4.
Mul-tiply
both sides of(24)
by
(t
+k)4,
take(4 -
j)th
derivative of theresult,
substitute t = -k and sum over all k E
Z;
thisprocedure
yields
that,
foreach j
=1, 2, 3, 4,
the numbers(21)
written assatisfy
the differenceequation
(3).
Finally,
the sequencealso satisfies the recursion
(3).
0Since
’
- .. ,
-in accordance with
(21), (22)
we obtainhence as a consequence of Lemma 4 we arrive at the
following
result.The sequences ~c" :=
Un/6
and vn
:=Vn/6
satisfy
the differenceequa-tion
(3)
and initial conditions(5);
the factIFni
2013~ 0 as n - oo, whichyields
the limit relation(7),
will beproved
in Section 4. Thiscompletes
ourproof
of Theorem 1.
The conclusion
(6)
of Theorem 1 is far frombeing precise;
infact,
(ex-perimentally)
there hold the inclusionsand,
moreover, there exists the sequence ofpositive integers
0,1, 2, ... ,
such thatThis sequence can be determined as follows: if vp is the order of
prime
p in(3n)!/n!3,
thenhere and below and
{x}
:= x -LxJ
denoterespectively
theintegral
andfractional
parts
of a real number x. Forprimes
p > we obtain theexplicit
(simple)
formulahence
where :=
r’(x)/r(x).
Thus,
we obtain that the linear formsdo not tend to 0 as n ~ oo.
3.
Well-poised
hypergeometric
construction Consider the set ofeight positive
integral
parameters
and
assign
to h the rational functionIn the last
representation
wepick
out the rational functionsof the form
(15), (13),
having
some nice arithmeticproperties
([Zu4],
Sec-tion
7).
’It is easy to
verify
that,
due to(26),
for the rational function(28)
the difference of numerator and denominatordegrees
isequal
to3,
henceThe series
Lemma 6. The
quantity
F(h) is
a linearform
in 1 and((4)
with rationalcoefficients.
Proof.
Order theparameters
hl, ... ,
h6
ashi . ~ ~ hs
and consider thepartial-fraction expansion
of the rational function(28):
where
Then we obtain
with
and the
well-poised origin
of the series(30) (namely,
theproperty
R(t
-ho) =
-R(t),
henceAjk
=by
(32),
cf.[Zu4],
Section8,
with r = 2 and
q = 6)
yields A2 = A4 = 0,
while the residue sum theoremaccompanied
with(29)
implies Al
= 0(cf.
[Nel],
Lemma1).
0Remark. The
question
of denominators of the rational numbersA3
andAo
that appear as the coefficients inF(h)
can be solvedby application
ofNesterenko’s denominator theorem
[Ne3]
(announced
by
Yu. Nesterenko in his Caen’stalk).
Namely,
consider the setwhere
mi > " - >
m5 are the five successive maxima of the set N.Unfortunately,
we have not succeeded inusing
the inclusion(33)
for arithmeticapplications; actually,
ourexperimental
calculations show thatthe
stronger
inclusion for the linear formsF(h),
indicated at thebeginning
of Section6,
holds.Using
standardarguments,
theproperty
(29)
and the fact thatR(t)
has second-order zeros atintegers
t = 1 -h_i},
I
one deduces the
following
hypergeometric-integral representation
of these-ries
(30).
Lemma 7
(cf. [Nel],
Lemma2).
There holds theequality
with
any tl
1 - hi
tlThe series
(30)
as well as thecorresponding hypergeometric
integral
(34)
are known in thetheory
ofhypergeometric
functions andintegrals
asvery-well-poised objects,
i.e.,
one cansplit
theirtop
and bottomparameters
inpairs
such thatand the second
parameter
has thespecial
form 1Remark..
As
it iseasily
seen, the sequenceFn
of Section 2corresponds
(after
a suitable shift of the summation
parameter
t)
to the choiceof the
parameters
h. Hence theequalities
Un -
U~’
= 0 in therepresentation
(12)
can be deduced from Lemma 6.4.
Asymptotics
We take the new set of
positive
parameters
and for each n =
0,1, 2, ...
relate them to the oldparameters
by
thefor-mulae
Then Lemma 6
yields
that thequantities
Fn
= :=F(h)
are linearforms in 1 and
((4)
with rationalcoefficients,
sayand the
goal
of this section is to determine theasymptotic
behaviour of these linear forms as well as their coefficients unand vn
as n - oo.To the set
(36)
assign
thepolynomial
and the function
defined in the cut
T-plane C
B
’1-I}]
U where"1i ~ ’12 ~ ... ~ "16
denotes the ordered version of the set 771, ’TJ2, ... , ’16. The first condition in(37)
implies
that(39)
is afifth-degree polynomial;
moreover, the
symmetry
under substitution "10 - T and the second condition in(37)
yield
that thispolynomial
has zerosThe last four zeros can be
easily
determinedby
solving
a certainbiquadratic
(in
terms ofr~o/2 - T)
equation.
Set andProposition
1. Thefollourlng
limit relations hold:Proof.
Theproof
is based onapplication
of thesaddle-point
method tothe
integral representation
of Lemma 7 for thequantities
F"
and a similarintegral
representation
(see
formula(48) below)
for the coefficients U,,; thefact that both limits in
(42)
areequal
followsimmediately
from the limitrelation
’I.,
-since
-Co
0Cl
under the conditions(37).
Without loss of
generality,
we will restrict ourselves to the ’most sym-metric’ case(35),
i.e.,
that
corresponds
to the linear forms in1, C(4)
constructed in Section 2. In the case(43),
the zeros(40)
of thecorresponding polynomial
(39)
are as follows:By
Lemma7,
with any ti E
1R,
-nti
0.Using
theasymptotic
formulafor z E C with Re z = const >
0,
taking
ti = -nTo andchanging
variablest =
as n -+ 00, where
Since
and To is a zero of the
polynomial
(39)
(which
is(T-3)2(T-1)6-T2(T-2)s
in the restricted
case),
we conclude thatf’(TO)
= 0 and To is theunique
maximum of the function Re
f (T)
on the contour. Thus theintegral
(44)
is determinedby
the contribution of thesaddle-point
To(see
[Br],
Section5.7):
hence
This proves the limit relation
(41).
In the
neighbourhood
of t= -k,
where k =n + 1, ... , 2n+ 1,
the functionR(t)
has theexpansion
by
(31).
On the otherhand,
and if ,C is a closed clockwise contour
surrounding
points t
= -n -1, ... ,
-2n -
1,
thenTaking
therectangle
with vertices±it2 ±
N,
for some fixed realt2
> 0 and any N > 2n +1,
as the contour ,C andusing
the estimateson the lateral sides of the
rectangle,
from(47)
we deduce thatwhere the constant in
O(N-2)
depends
ont2
only.
Tending
N - oo andmaking
the substitution t H-t - ho
= -t -(3n
+2)
in the firstintegral,
we obtain
(cf. [Zu2],
Lemma3.1).
Finally,
taket2
= -nsi =-nImTl,
change
thevariable t = -nT and
apply
theasymptotic
formulaSince
for r E C with Im T = S 1 >
0,
we obtainBy
(45)
and the definition of thepoint
71(that
is the zero of thepolyno-mial
(39)),
hence/’(71) -
4xiTi
=0,
we conclude that 7 = 71 is theunique
maximum of the function on the line Im T = sl.
Therefore,
the
saddle-point
method says that theasymptotics
of theintegral
in(49)
is determinedby
the contribution of thepoint
T = Tl thatyields
the desiredlimit relation
The
proof
ofProposition
1 iscomplete.
0Remark. The limit relation
(46)
yields
that -~ 0 as n - oo, and this is the fact that we havepromised
to prove for Theorem 1(see
theparagraph
after Lemma
5).
To behonest,
thefact,
that theasymptotics
of the linear forms and their coefficients in the case(35)
is determinedby
the zeros(3
t2v’3)3
of aquadratic
polynomial
withintegral
coefficients,
gave us theidea to look for a second-order difference
equation.
5.
Group
structure for((4)
This section can be viewed as a continuation
of
thestory
in[Zu4],
Sec-tions
4-6,
where weexplain
the Rhin-Viola group structures for~(2)
andProposition
2(Bailey’s
integral
transform[Ba],
Section6.8,
formula(1)).
There holds the
identity
where k = 1 + 2a - c - d -
e, and the
parameters
are connectedb y
therelation
By
Lemma 7 the transform(50)
rearranges theparameters h
as follows:Consider the set of 27
complementary
parameters
e,and set
Then
Bailey’s
transform can be written as follows:where 6 from
(51)
is thefollowing
second-orderpermutation
of theparam-eters
(52):
Further,
the h-trivial group(i.e.,
the group ofpermutations
of thepa-rameters
hl, h2, ... ,
h6)
isgenerated
by
second-orderpermutations
ofhk,
1 k5,
andh6.
The action of these fivepermutations
on the set(52)
isas follows:
and the
quantity
(due
to the definition(28))
is stable under the action of(56).
Setting
(58)
6 =6 (e) :
1"(e01 ,
eo2, eo4, e06 ,e02,
e03,
e05,
e12, e15, e24 ,e36 }
and
combining
the abovestability
results we arrive at thefollowing
fact. Lemma 8. Thequantity
is stable under the action
of
the groupMoreover,
thequantities h-l
andare also 0-stable.
Proof.
Routine calculations show thestability
ofH(e)/II(e)
under theac-tion of
b,
~2, ~3, ~14, ~5
with ahelp
of(55)
and(57).
HenceH(e)/II(e)
isstable under the action of the
e-permutation
groupgenerated
by
these sixpermutations
(54), (56).
The
stability
ofh_1
under the action of(56)
isobvious,
and b does notchange
theparameter
h_1
by
(51).
Finally,
that
yields
thestability
ofE(e)
under the action of 6. Theproof
isWith the
help
of a C++ program we have discovered that thegroup 6
con-sists of 51840
elements,
hence the left factor includes51840/6!
= 72left
cosets;
here6e
is identified with the h-trivial groupb2 , b3,
4,
5).
It isinteresting
to mention that the group60
acting trivially
on the set(58)
consists of
just
4 elements: go =id,
Rerraark. In the most
symmetric
case(35)
allcomplementary
parameters
(52)
areequal
to n that means that anypermutation
from 0 does notchange
thequantity
F(la).
This factexplains why
do we dub this case astmost
symmetric’.
6. Denominators of linear forms
As we have mentioned in Remark to Lemma
6,
‘trivial’ arithmetic(33)
of the linear forms
H(e)
=F(h)
does not lead us to aqualitative
resultfor
((4).
We are able to estimate theirrationality
measure of~(4)
under thefollowing
condition,
which we have checkednumerically
for several valuesof h
satisfying
(26)
and(27).
Denominator
Conjecture.
There holds theinclusion4
where
mi > m2 > m3 >
rn4 are thefour
successive maximaof
the set ein
(52)
andwith
If this
conjecture
istrue,
thentaking
any element g e 6 andwriting
conclusion of Lemma 8 aswe deduce
that,
for anyprime
p >where
9C
=6 (ge)
andordp (u( (4) -
v)
:=min{ordp u, ordp v}
for rationalnumbers u, v.
Finally,
setting
with
from
(59)
we obtain the inclusionNow,
to each =0,1, 2, ... assign
theparameters
h in accordance with(38)
and setso that the set of
complementary
parameters
e ~ ncorresponds
to the set h.Then,
in the abovenotation,
we can write the inclusion(60)
asThe
asymptotic
behaviour of the linear formsH(en)
EQ((4)+Q
and their coefficients as n - oo is determinedby Proposition
1;
inaddition,
by
the consequence(2)
of theprime
numbertheorem,
while the arithmetic lemma ofChudnovsky-Rukhadze-Hata
(see,
e.g.,[Zu2],
Lemma4.4)
yields
where
is a
1-periodic
function.Recalling
the notation ofProposition
1 andcombining
its results withsaying
above,
as in[RV2],
theproof
of Theorem5.1,
we arrive at the fol-lowing
statement.Proposition
3. Under the denominatorconjecture,
letIf Co
>C2,
then theirrationality
exponent
of
C(4)
satisfies
the estimateRecall that the
irrationality
of a real irrationalnum-ber a is the least
possible
exponent
such that for any e > 0 theinequality
has
only
finitely
many solutions inintegers
p, q with q > 0.With a
help
ofProposition
3 we are able to state thefollowing
conditional result.Theorem .3. The
irrationalaty
exponent
of
C(4)
satisfies
the estimateprovided
that the denominatorconjecture
holds.Proof. Taking q
=(68,57;
22,23,24,25,26,27)
we obtainand .
= 27 + 26 + 25 + 24 - 69.76893283... = 32.23106716....
The estimate
(61)
can becompared
with the ’best known’ estimatewhich follows from the
general
result of Yu. Aleksentsev[Al]
onapproxi-mations of ~r
by
algebraic
numbers.5
7. Further difference
equations
for zeta values A naturalvery-well-poised generalization
of Ball’s sequence(9),
where n =
1, 2, ... , gives
rise forsearching
differenceequations
satisfiedby
both linear forms and their rational coefficients.
Applying Zeilberger’s
algorithm
of creativetelescoping
in the manner of Section 2 we deduce thefollowing
result for the linear formsTheorem 4. The numbers un, 7 Wn vn in the
representation
(63)
arepositive
rationals
satisfying
the third-orderdifference
equation
with
5In fact, the result of [Al] is proved for approximations of 1r by algebraic numbers of sufficiently large degree.
where
The characteristic
polynomial
A3 _ 188A~ -
2368A + 4 of the differenceequation
(64)
determines theasymptotic
behaviour of the linear forms(63)
and their coefficients as n - oo.A similar
(but
quite
cumbersome)
fourth-order recursion with character-isticpolynomial a4 -
828A - 132246A
+ 260604A - 27 has been discoveredby
us for the linear formsF7,n
and their coefficients. These recursions allow us toverify
the inclusionsup to n =
1000,
although
we are able toprove that
where
using
our arithmetic results[Zu2],
Lemmas 4.2-4.4.Another
story
deals with thequantities
where
i4,, Wn,
vn
aarepositive
rationals. We have discovered a(quite
cum-bersome)
fourth-order differenceequation
satisfiedby
i4,,
wn,
vn;
its char-acteristicpolynomial
iswhere
On
isgiven
in(66),
while our calculations up to n = 1000 with ahelp
of the recursion mentioned above show thatWhat is a trick that makes arithmetic as it is?
8.
Multiple-integral representation
_
of
very-well-poised
hypergeometric
seriesIn
[Zu4],
Section9,
weconjecture,
forinteger
k >2,
the coincidence ofthe
very-well-poised hypergeometric
series(62)
and themultiple integral
where
Qo
:= 1 andfor k > 1. The
integrals
J2,n
andJ3,n
have been studiedby
F.Beuk-ers
[Bel]
in the connection withAp6ry’s
proof
of theirrationality
of((2)
and((3).
In(Zu4~,
we prove the coincidence ofF3~n
and with thehelp
ofBailey’s
identity
([Ba],
Section6.3,
formula(2))
and Nesterenko’sintegral
theorem([Ne2],
Theorem2),
and use similararguments
forshowing
thatF2,n
=J2,n.
Forgeneral
integer
k >2,
theintegrals
(67)
are introducedby
O. Vasilenko
[VaO]
who states several results forJk,o.
The cases k =4,5
and an
arbitrary integer n
in(67)
aredeveloped by
D.Vasilyev
[VaD];
inparticular,
heconjectures
the inclusions(cf. (65)),
and proves them if k = 5.There is a
regular
way to obtain differenceequations
for thequanti-ties
(67);
it is apart
of thegeneral
WZ theory developed by
H. Wilf andD.
Zeilberger
[WZ].
However,
differenceequations
for andJS,n
by
thesemeans are out of calculative abilities of our
computer,
so we cannot use atroutine matter’ to
verify
theidentity
Fk~n
= even when J~ =4, 5.
The aim of this section is to deduce the desired coincidence of
(62)
and(67)
from ageneral analytic
result on amultiple-integral
representation
of
very-well-poised hypergeometric series.
6As
it is mentioned by G. E. Andrews in [An], Section 16, "an entire survey paper could be written just on integrals connected with well-poised series" . The following theorem would extend this survey a little bit.Consider two
objects:
very-well-poised
hypergeometric
seriesand
multiple
integrals
Theorem 5. For each k >
1,
there holds theidentity
provided
thatRemark. Condition
(72)
isrequired
for the absolute convergence of the series(69)
in the unit circle(and,
inparticular,
at thepoint
(-1)~+i),
while condition(73)
ensures the convergence of thecorresponding multiple
integral
(70).
The restriction(74)
can be removedby
thetheory
ofanalytic
continuation if we write
r(hj
+for j
=1,
k + 2 as Pochhammer’ssymbol
whensumming
in(69).
In the case of
integral
parameters
h,
thequantities
(69)
are known to beQ-Iineax
forms ineven/odd
zeta valuesdepending
onparity
of k > 4(see
[Zu4],
Section9).
Therefore,
ifpositive
integral
parameters
a and bsatisfy
then the
quantities
(70)
areQ-linear
forms ineven/odd
zeta values.Spe-cialization + 1 and
b?
= 2n + 2gives
one the desired coincidenceof
(62)
and(67).
Thechoice aj
= rn + 1 andbj = (r
+1)n
+ 2 in(70) (or,
equivalently,
ho
=(2r+1)~+2
and hj
= rn+1for j
=1, ... ,
k+2 in(69))
with the
integer
r > 1depending
on agiven
oddinteger
kpresents
almostthe same linear forms in odd zeta values as considered
by
T. Rivoal in[Ril]
for
proving
his remarkable result on infiniteness of irrational numbersin _
the set
((3), ((5), ((7), ....
In
addition,
we have tomention,
underhypothesis
(75),
the obviousstability
of thequantity
under the action of the
(h-trivial)
group6k
of order(k
+2)!
containing
allpermutations
of theparameters
hi, ... ,
This fact can beapplied
fornumber-theoretic
applications
as in[RV1], [RV2]
and Sections5,
6 above. Inthe cases k = 2 and lk = 3 the
change
of variables(Xk- 17
Xk)
r-(1-
xk,1-xx-1)
in(70)
produces
an additional transformation G of both(70)
and(69);
for k > 4 this transformation is not
yet
available since condition(75)
is broken. The groups(02, b)
and(Ø3, b)
of orders 120 and 1920respectively
are known: see
[Ba],
Sections 3.6 and7.5,
for ahypergeometric-series
origin
and
[RV1],
[RV2]
for amultiple-integral
explanation.
G. Rhin and C. Violamake a use of these groups to discover nice estimates for the
irrationality
measures of
((2)
and((3).
Finally,
we want to note that the group6k
canbe
easily interpretated
as thepermutation
group of theparameters
as in Section 5
(see
[Zu4],
Section9,
fordetails).
Lemma 9. Theorerrc 5 is true
if k
= 1.Proof.
Thanks to alimiting
case ofDougall’s
theorem,
(see,
e.g.,[Ba],
Section4.4,
formula(1)),
provided
that >Re(hi
+hand,
theintegral
on theright
of(71)
has Eulertype,
that isprovided
that 1 +R.e ho
>Re(h1
+h2
+h3)
andRe h2
> 0.Therefore, .
multiplying
equality
(76)
by
therequired product
ofgamma-functions
wededuce
identity
(71)
if k = 1. 0Renaark. If we arrange about
Jo(ao)
to be1,
the claim of Theorem 5 remains valid if k = 0 thanks to anotherconsequence of
Dougall’s
theorem([Ba],
Section
4.4,
formula(3)).
Lemma 10
([Ne2],
Section3.2).
Let andto
E lf8 be numberssatisfying
the conditionsR,e ao > ta > 0,
R,e a > to > 0,
andReb> Reao+Rea.
Thenfor
any non-zero z EC B (1, +00)
the following
identity
holds:where
(-z)t =
Izlteitarg(-z),
_~arg(-z)
1rfor
zE C B [0,+(0)
andarg(-z)
= f:1rfor
z E(0,1~.
Theintegrals
on theright-hand
sideof
(77)
converges
absolutely.
Inaddition, if
lzl
1,
bothintegrals
in(77)
can beidentified
with theabsolutely
convergent
Gausshypergeorreetric
seriesSet ék
= 0 for k evenand Ek
= 1 or -1 for k odd.Lemma 11. For each
integer
k >2,
there holds the relationprovided
thatRe ao
> to >0, Re ak >
to
>0, Re bk
>Re ao
-E-Ileak,
and theintegral
on theleft
converges.Proof.
We start withmentioning
that the first recursion in(68)
and induc-tivearguments
yield
theinequality
By
the second recursion in(68),
Qk
=Qk-1 -
(1 - zxk)
for k >2,
whereFor each
(xl, ... , xk-1)
E(o,1)k-1,
the number z is real with theproperty
z 0 for J~ even and 0 z 1 for J~
odd,
since in the last case we haveby
(78).
Therefore,
splitting
theintegral
(70)
over[0,
1]k
=[0,
1]k-1
X[0, 1]
and
applying
Lemma 10 to theintegral
we arrive at the desired relation. 0
Proo, f of
Theorem 5. The case k = 1 is considered in Lemma 9. Thereforewe will assume that k >
2, identity
(71)
holds for k -1,
and,
inaddition,
that
The restrictions
(79)
can beeasily
removed from the final resultby
thetheory
ofanalytic
continuation.where the real number so > 0 satisfies the conditions
and the absolute convergence of the last
Barnes-type
integral
follows from[Ne2],
Lemma 3.Shifting
the variable t + s in(80) (with
ahelp
of the
equality
eEIc1rit .
eEIc-l1ris =
eA,-,7ri(t+s) -
e6l"t),
applying
Lemma11,
andinterchanging
doubleintegration
(thanks
to the absolute convergenceof the
integrals)
we conclude thatwhere sl - so +
to.
SinceR,e hk+2
1 and0, -1, -2, ... ,
the lastSubstituting
this finalexpression
in(81)
we obtainIf k is even, we take = -1 in the first
integral
and êk-l = 1 in thesecond one. Therefore the both
integrals
areequal
tothat
gives
the desiredidentity
(71).
Theproof
of Theorem 5 iscomplete.
DAnother
family
ofmultiple
integrals
is known due to works of V. Sorokin
[So2], [So3].
Recently,
S. Zlobin[Zll],
[ZI2]
hasproved
(in
moregeneral
settings)
that theintegrals
(70)
can bereduced to the form
(82)
with z = 1.Therefore,
Theorem 5gives
one away to reduce the
integrals
S(l)
to thevery-well-poised
hypergeometric
series
(69)
under certain conditions on theparameters
aj,b~,
c~, and risatisfying
natural restrictions of convergence, theintegral
S(z)
is aQfz-’]-linear combination of modified
multiple polylogarithms
Following
aspirit
of thissection,
we would like to finish the paper with thefollowing
Problem. Find a
multiple integral
over(0,1~5
thatrepresents
the seriesdefined
in(30) (or,
equavalently,
theintegral
(34))
of
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Wadim ZUDILIN
Department of Mechanics and Mathematics Moscow Lomonosov State University
Vorobiovy Gory, GSP-2 119992 Moscow Russia
ML: http://vain.0153d.ras.ru/index.html E-mail : vadimQips . ras . ru