The p-part of Tate-Shafarevich groups of elliptic
curves can
be arbitrarily large
par REMKE KLOOSTERMAN
RÉSUMÉ. Nous montrons dans ce papier que pour
chaque
nombre premier p ~ 5, la dimension de la partie de p-torsion du groupe de Tate et Shafarevich,III(E/K),
peut être arbitrairementgrande,
où E est une courbe
elliptique
définie sur un corps de nombres K dedegré
borné par une constantedépendant
seulement de p. En utilisant cerésultat,
nous obtenons aussi que la partie de p-torsiondu
III(A/Q)
peut être arbitrairementgrande,
pour des variétées abéliennes A de dimension bornée par une constantedépendant
seulement de p.
ABSTRACT. In this paper we show that for every prime p ~ 5 the dimension of the p-torsion in the Tate-Shafarevich group of
E/K
can be
arbitrarily large,
where E is anelliptic
curve defined overa number field K, with
[K : Q]
boundedby
a constantdepending only
on p. From this we deduce that the dimension of the p- torsion in the Tate-Shafarevich group ofA/Q
can bearbitrarily large,
where A is an abelian variety, with dim A boundedby
aconstant
depending only
on p.1. Introduction
For the notations used in this introduction we refer to Section 2.
The aim of this paper is to
give
aproof
ofTheorem 1.1. There is a
function
g : 7~ --~ 2 such thatfor
everyprime
number p and every k E2>0
there existinfinitely
manypairs (E, K),
withK a nurrzber
field of degree
at mostg(p)
andE/K
anelliptic
curve, such thatdimIF p Lll (EIK) p]
> k.Manuscrit reçu le 13 octobre 2003.
Mots clefs. Tate-Shafarevich group, elliptic curve, abelian variety.
The author wishes to thank Jaap Top and Bas Edixhoven for many useful conversations on this topic. The author wishes to thank Jasper Scholten for suggesting [10]. The author wishes to thank Stephen Donnelly and René Schoof for pointing out mistakes in earlier versions and an
anonymous referee for suggesting many improvements.
The
proof
of this theorem starts on page 796.Using
Weil restriction ofscalars,
we obtain as a direct consequence:Corollary
1.2. For everyprime
nurraber p and every k E there existinfinitely
manynon-isomorphic
abelian varietiesA/Q,
with dim Ag(p)
and A is
simple
overQ,
such thatIn
fact,
arough
estimateusing
thepresent proof
reveals thatg(p) =
O(p4).
It is an old openquestion
whetherg(p)
can be taken1, i.e.,
for any p, thep-torsion
of the Tate-Shafarevich groups ofelliptic
curvesover Q
areunbounded.
For p E
{2, 3~ 5},
it is known that the group[p]
can bearbitrarily large. (See ~1~, [2], [5]
and[8].)
So we may assume that p >5,
infact,
ourproof only
uses p > 3.P.L. Clark communicated to the author that he
proved by
different meth-ods that if
E / K
has fullp-torsion
thenIII (EIL) [p]
can bearbitrarily large
if L runs over all extension of K of
degree
p, but E remains fixed. Thisgives
asharper
bound in the case that E haspotential complex multiplica-
tion. The
elliptic
curves we describe in theproof
of Theorem 1.1 all have manyprimes
p for which the reductionat p
issplit-multiplicative.
Hencethese curves do not have
potential complex multiplication.
The
proof
of Theorem 1.1 is based oncombining
thestrategy
used in[5]
to prove that
dimJFs
can bearbitrarily large
and thestrategy
used in[7]
to prove thatdimJFp
can bearbitrarily large,
where Eand K vary, but
(K : Q]
is boundedby
a functiondepending
on p oftype
o(p).
In
[7]
thestrategy
was to find a fieldK,
such that[K : Q]
is small anda
point
P EXo(p)(K)
such that P reduces to one cusp for manyprimes
p and reduces to the other cusp for very few
primes
p. Then to P we can associate anelliptic
curveE / K
such that anapplication
of a Theorem ofCassels
[3]
shows thatSP (E / K) gets large.
The
strategy
of[5]
can be described as follows.Suppose K
is a fieldwith class number 1.
Suppose E/K
has a K-rationalpoint
of order p, with p > 3 aprime
number.Let p :
E -> E’ be theisogeny
obtainedby dividing
out the
point
of order p. Then one can define a linear transformationT,
such that the
p-Selmer
group isisomorphic
to the kernel ofT,
while the~-Selmer
group isisomorphic
to the kernel of anadjoint
of T. One canthen show that the rank of
E(K)
and ofE’(K)
is boundedby
the numberof
split multiplicative primes
minus twice the rank of T minus 1.Moreover,
one can prove that if the difference between the dimension of the domain of T and the domain of theadjoint
of T islarge,
then thedimension of the
p-Selmer
group of one of the twoisogenous
curves islarge.
If one has an
elliptic
curve with two rational torsionpoints
of order p and qrespectively (or
fullp-torsion,
if one wants to take p =q),
one canhope
that for one
isogeny
the associated transformation hashigh rank,
while forthe other
isogeny
the difference between the dimension of the domain of T and itsadjoint
islarge.
Fisher usespoints
onX (5)
to findelliptic
curvesE /Q
with twoisogenies,
one such that the associated matrix haslarge rank,
and the other such that the 5-Selmer group is
large.
We
generalize
this idea to numberfields,
without the class number 1 condition. We can still express the Selmer group attached to theisogeny
as the kernel of a linear transformation T. In
general,
the transformation for the dualisogeny
turns out to be different from anyadjoint
of T.Remark. Fix an
element ~
E Restrict this element toThen ~ gives
a Galois extension L ofK(E[P])
ofdegree p
orp2, satisfying
certain local conditions.
(For
the case of acyclic isogeny,
these conditionsare made more
precise
inProposition 2.1.)
To check whether agiven
classin comes from an element in
8P(E / K)
we need also tocheck whether the Galois group of
LIK(E[p])
interacts in someprescribed
way with the Galois group of
K(E[p])IK.
The
examples
ofelliptic
curves withlarge
Selmer andlarge
Tate-Shafare- vich groups in[5], [7]
and this paper have onething
in common,namely
thatthe
representation
of the absolute Galois group of K onE[p]
is reducible. In this case the conditions on the interaction of the Galois groupwith the Galois group of almost
disappear.
The level of
difficulty
to constructlarge p-Selmer
groups(and large
p-parts
in the Tate-Shafarevichgroups)
seems to be encoded in the size of theimage
of the Galoisrepresentation
onE[p].
Elliptic
curvesE / K
withcomplex multiplication
over a proper extension of K have an irreducibleGalois-representation
onE[p]
for all butfinitely
many p, but the
representation
isstrictly
smaller thanGL2 (Fp) .
In view of the above remarks it seems that if one would like to
produce examples
ofelliptic
curves withlarge p-Selmer
groups, and an irreduciblerepresentation
of the Galois group onE[p],
one could start with the case ofelliptic
curves withcomplex multiplication. Unfortunately,
we do not havea
strategy
toproduce
suchexamples.
The
organization
of this paper is as follows: In Section 2 we prove several lower and upper bounds for the size ofw-Selmer
groups, where w is anisogeny
with kernelgenerated by
a rationalpoint
ofprime
order at least5. In Section 3 we use the modular curve and the estimates from Section 2 to prove Theorem 1.1.
2. Selmer groups
In this section we
give
several upper and lower bounds for thep-Selmer
group of an
elliptic
curveE/K
with a K-rationalpoint
of order p, and(p
E K. We combine two of these bounds to obtain a lower bound fordimfp
Suppose
K is a numberfield, E/K
is anelliptic
curve and cp : ~ 2013~ E’ isan
isogeny
defined over K. LetH1 (K,
be the firstcohomology
group of the Galois moduleDefinition. The
w-Selmer
group ofE/K
isand the Tate-Shafarevich group of
E / K
isIn the usual definition of the
cp-Selmer
group one takes theproduct
over all
primes,
also the archimedean ones. If rp is of odddegree
then= 0 for all archimedean
primes
p, so in that case we may exclude the archimedeanprimes.
Notation. For the rest of this section fix a
prime
number p >3,
a numberfield K such that
(p
E K and anelliptic
curveE / K
such that there is anon-trivial
point
P EE(K)
of order p. Let p : E -~ E’ be theisogeny
obtained
by dividing
out(P~.
Letrp :
E’ --~ E be the dualisogeny.
To rp we associate three sets of
primes.
Let81 (rp)
be the set ofprimes p
COK ,
suchthat p
does not divide p, the reduction of E issplit multiplicative
at p, and P E
Eo(Kp) (notation
from[18, Chapter VII]).
Let be theset of
primes p
C such that p does not divide p, the reduction of E issplit multiplicative
at p, andP ~ Eo(Kp).
Let be the set of allprimes
above p.Suppose
S is a finite sets of finiteprimes.
LetK(S, p)
:==~x
Evp (x) =-
0 modp Vp g S, p non-archimedean}.
Let
CK
denote the class group of K. DenoteGK
the absolute Galois group of K. Let M be aGK-module.
LetH1(K, M; S)
be thesubgroup
ofH1 (K, M)
of all classes ofcocycles
not ramified outside S.For any
cocycle ~
E denote~p resp (~)
EM) .
Let6p
be the mapinduced
by
theboundary
map.Note that
81(0)
=52(p)
and5’z(c,~)
=(To
define we needto start with a K-rational
point
P of order p. Since(p
EK,
we have that#E’(K)(cp~ _
p, so we can take anygenerator
P of the kernel of~3.)
If noconfusion arises we write
S,
andS2
for81(cp)
andProposition
2.1. We have that is the kernelof
ED pc, s3
°Proof. Suppose
p is aprime
such that p divides theTamagawa
number cE,p.Since 4
p
we have that the reduction at p issplit multiplicative.
Using
Tate curves oneeasily
shows that 1. This combined with if p~’ (p)
then 2(see [21, Proposition 3])
and[15,
Lemma
3.8] gives that t* : H1(Kp, E)
is eitherinjective
or the zero-map. A closer
inspection
of[15,
Lemma3.8]
combined with[7, Proposition 3]
showsthat t*
isinjective
if andonly
if p E82 (cp).
Theproposition
then follows from[16, Proposition 4.6].
DRemark.
Proposition
2.1 is false when thedegree
of theisogeny
is 2 or 3.For
degree
3 a similarproposition
is stated in[16, Proposition 4.6].
First ofall,
if thedegree
is2,
one need to include a conditions for the archimedeanprimes. Moreover,
one needs togive
conditions fornon-split multiplicative primes (if
thedegree
is2)
and conditions for the additiveprimes (if
thedegree
is either 2 or3).
Consider for
example
thecurve y2
= + ax +a),
for somesquare-free
odd
integer
a.Let p
be theisogeny
obtainedby dividing
out{O, (0, 0)}.
Then
S2
is anempty
set, andS,
consists of a subset of allprimes
divid-ing a -
4. We can twist this curve such thatS2
remainsempty
and allmultiplicative primes
aresplit.
If the aboveproposition
were true for de-gree
2,
then the size of thecp-Selmer
group woulddepend
on the numberof
prime
factors of a - 4.Using [18, Proposition X.4.9]
one canproduce
a such that the
c.p-Selmer
group is much smaller than the kernelgiven
inProposition
2.1.Definition. Let
Sl
and~S2
be twodisjoint
finite sets of finiteprimes
ofK,
such that none of the
primes
in these sets divides(p).
Let
- - - S’ - , ...
be the
Fp-linear
map inducedby
inclusion. Let be the rank of T. In thespecial
case of anisogeny
(~ : E -~ E’ with associated sets and as above we write :=m(81(cp), 82(cp)).
Lemma 2.2. Wc have
Hence the domain
of
T isfinite-dimensional.
Proof.
Since(p
we have that K does not admit any realembedding.
The above formula is a
special
case of[11, Proposition 12.6].
DProposition
2.3. We haveand
Proof.
This follows from the identificationZ/pZ ~
the factL*/L*p
for any field L of characteristic different from p(see
[13, X.3.b]),
andProposition
2.1. DProposition
2.4. We haveProof. Using
Hilbert 90([13, Proposition X.3])
and[21, Proposition 3]
weobtain that for every
prime
pwhere
e(p/p)
is the ramification index ofp/p, if p
divides p and zero other- wise. Thisyields
The above bound combined with Lemma 2.2 and
Proposition
2.3gives
usFor the other
inequality,
we obtainusing Proposition
2.3Using ~63 ~ [K : Q]
andapplying
Lemma 2.2 to theright
hand side of thisinequality yields
ó)
Lemma 2.5. We have
Proof.
This follows from thefollowing
sequences ofinequalities
The first
inequality
follows from the fact thatE(K)
hasp-torsion,
thesecond one follows from the
long
exact sequence incohomology
associatedto 0 -
E ~~ --~ E --~ E -~ 0
and the third one follows from the exact sequence(See [16,
Lemma9.1].)
Applying Proposition
2.4gives
By
a theorem of Cassels we cancompute
the difference ofdimJF p
and
dimpp S‘~(E’/K).
We do not need theprecise difference,
butonly
anestimate, namely
Lemma 2.6. There is an
integer
t, withIt I 2[K : Q]
+ 1 such thatProof.
This follows from[3] (see [7, Proposition 3]
for thedetails).
Lemma 2.7.
Proof.
Afterpossibly interchanging
E and E’ we may assume that#S2.
FromProposition
2.4 we knowFrom this
inequality
and Lemma 2.6 we obtain thatSumming
bothinequalities gives
the Lemma.Lemma 2.8. Let
rank E(K),
thenProof.
The exact sequence(See [16,
Lemma9.1]) implies
The lemma follows now from the
following inequality coming
from thelong
exact sequence in Galois
cohomology
Lemma 2.9.
Leto : E2
be sorraeisogeny
obtainedby dividing
out aK-rational
point of
order p, withE1 K-isogenous
to E. ThenProof.
Use Lemma 2.5 for theisogeny 0
to obtain the bound for the rankof
E(K).
Then combine this with Lemma 2.7 and Lemma 2.8 and use that3. Modular curves
In this section we prove Theorem 1.1. We construct certain fields
K/Q
such that
X (p)(K)
containspoints
with certain reductionproperties.
Thesereduction
properties
translate into certainproperties
ofelliptic
curvesE / K admitting
twocyclic isogenies
y~, such that is muchlarger
then#S2(~o)) (notation
from theprevious section).
Thenapplying
the results of the
previous
sectiongives
us aproof
of Theorem l.l.The
following
result will be used in theproof
of Theorem 1.1.Theorem 3.1
([6,
Theorem10.4]).
Letf
EZ[X]
be apolynomial of degree
at least 1. Let d be the nurrzber
of
irreduciblefactors of f . Suppose
thatfor
everyprirrae ~,
there such thatf (y) 0
0 mod £. Thenthere exists a constant n
depending
on thedegree of f
and thedegree of
itsirreducible
factors
such that there existinfinitely
manyprimes t,
such thatj(f)
has at most nprime factors. Moreover,
letthen there exist 6 >
0,
such thatAny improvement
on the ra willgive
a better functiong(p) (notation
from Theorem
1.1),
but the newg(p)
will still be oftype O(p~).
The
proofs
for most of the below mentionedproperties
ofXo(p)
andX(p)
can be found in[17]
or[20].
See also[4, Chapter 4].
Notation. Denote the
compactification
of the curveparameteriz- ing pairs ((E, 0), f )
where(E, O)
is anelliptic
curve andf
is an isomor-phism f : Z/pZ
xEp]
with theproperty
that the standardpairing
on the left
equals f composed
with theWeil-pairing.
Denote the curve obtained
by dividing
out the Galois-invariant Borelsubgroup
ofAut(X(p))
=SL2(Z/pZ), leaving
invariant((E, O),
The curve
Xo(p)
is a course moduli space forpairs ((E, 0), ~0)
where cp : E ~ E’ is an
isogeny
ofdegree
p.(See
forexample [9, Chapter
2~.)
Let
Ri
EXo(p)
be the unramified cusp(classically
called’infinity’),
letR2 E Xo(p)
be the ramified cusp.Let 7ri :
X (p) ~ Xo(p)
be themorphism
obtainedby mapping (E, f)
to
(E, where pi
is theisogeny
obtainedby dividing
outf (7G/p7G
xwhen i =
1,
and xpp)
when i = 2. The maps 7ri are defined overQ.
Let P E
X(p)
be apoint,
which is not a cusp. Theisogeny
Wpi is obtained as follows: To7ri (P)
EXo(p)
we can associate apair (Ep, cpP,2)
representing 7ri (P) .
Definition. Let T be a cusp of
X(p).
We say that T is oftype (Ó, E)
E{1,2}~
if7ri(T) = R~
and~r2(T)
=R,.
Being
oftype (d, E)
is invariant under the action of the absolute Galois group ofQ,
since themorphisms
7ri are definedover Q
and the cusps onXo(p)
areQ-rational.
Suppose
T is a cusp oftype (6, e) .
Then for all number fieldsK/Q((p)
and all
points
P EX (p) (K)
we have thatif p ~’ (p)
is aprime
of K suchthat P - T mod p then p E and p E
8E(rpP,2).
This statement canbe shown
by
an easy consideration on the behavior of theTate-parameter q
of the curve
representing
thepoint P
EX (p) (K)
and the relation between q and thej-invariant. (Compare [7,
Proof ofProposition 3].)
Lemma 3.2.
X(p)
has(p- 1)/2
cuspsof
eachof
thetypes (2, 1)
and(1, 2).
The other
(p - 1)2/2
cusps areof type (2, 2).
All cuspsof type (1, 2)
areQ-rational.
Proof.
A cusp oftype (1, 1)
wouldgive
rise toelliptic
curvesE/Kp,
withmultiplicative
reduction such that its reduction Emodulo p
hasas a
subgroup,
but over analgebraically
closed field L of characteristic p,we have
#E(L) ~p~
p, a contradiction.The ramification index of every
point
in is p, hence there are(p- 1)/2 points
in7r;1 (R1).
From this it follows that there exists(p- 1) /2
cusps of
type (1, 2)
and(2,1), respectively.
Theremaining
cusps are oftype
(2, 2).
°An
argument
as in[12,
page 44 and45]
shows that there is a cusp oftype (1,2)
that isQ-rational.
From this it follows that all cusps of type(l, 2)
areQ-rational. (See [4, Chapter 4].)
DProof of
Theorem 1.1. Let D be an effective divisor onX (p),
such that D isinvariant under
GQ ,
thesupport
of D is contained in the set of cusps oftype
(1, 2),
the dimension of the linearsystem I D
is at least 2 and themorphism wj Dj : X (p) ->
P’ isinjective
at almost allgeometric points
ofX (p).
Let Lbe a 2-dimensional linear
subsystem
ofIDI containing
D and such that thecorresponding morphism
isinjective
at almost allgeometric points.
Let C Cp2
be theimage
ofX (p) given by
L. We may assume that the intersection of X = 0 with C isprecisely
D. Anautomorphism ’lj;
ofp2 fixing
the lineX = 0,
is of the form~X,Y, Zy-->
It is easy to see that we can choose al,
bi,
ci in such a way that none of the cusps is on the line Z =0,
and the function x =X/Z
takes distinct values at anypair
of cuspswith x 0
0. So we may assume that we havea fixed
(possibly singular)
modelC/Q
forX(p)
in such that the line X = 0 intersects Conly
in cusps oftype (1, 2)
and no otherpoints,
all x-coordinates of other the cusps are distinct and
finite,
and ally-coordinates
of the cusps are finite. Denote H E
Z[X, Y, Z]
adefining polynomial
of C.Set
y)
:=H(X,Y, 1).
Let
f6,,
E be thesquare-free polynomial
with roots all x-coordinates of the cusps oftype (6,,E)
ofX (p)
and content 1. After a simultaneous transformation of thef6,,
of the form m--> cx, we may assume that/2 i(0) =
1 and
f2,1 E Z[X].
Let n denote the constant of Theorem 3.1 for thepolynomial f2,1.
The discriminant of/i,2/2,1/2,2
is non-zero, since every cusp hasonly
onetype
and all cusps have distinct x-coordinate.Let B consist of p, all
primes t dividing
theleading
coefficient or the discriminant off l,z f2.i f2,2,
allprimes t
smaller then thedegree
off2,1
andall
primes dividing
theleading
coefficient ofres(h, f2,2, x),
the resultant of h andf2,2
withrespect
to x.Let
P2
be the set ofprimes
not in 13 such that every irreducible factor of/2,i(~)(~ 2013 1)
mod P and every irreducible factor ofres(h, f2,1, x)
mod Chas
degree
1. Note thatby
Frobenius’ Theorem([19])
the setP2
is infinite.The condition mentioned
here, implies
that if we take atriple (xo, P, yo)
with xo E
Z,
thepriIne £
EP2
dividesf2,1(xo)
and yo is a zero ofy)
then every
prime
q ofQ((p, yo)
over f satisfiesf (qlf)
=1,
wheref (qlf)
denotes the
degree
of the extension of the residue fields.Fix
Si
andS2
twofinite, disjoint
sets ofprimes,
notcontaining
an archi-medean
prime
such thatsi
f113 =0
andS2
CP2,
withm(51, 52)
as defined in Section 2.(The
exis-tence of such sets follows from Dirichlet’s theorem on
primes
in arithmeticprogression
and the fact that t ES2 implies £ *
1 modp.)
Lemma 3.3. There exists an such that
· x~ - 0
modf, for
allprimes t
smaller then thedegree of f2,1
and allf
dividing
theleading coefficient of f2,1,
~ ro - 0
mod Q, for
E51,
.
f2,2(XO)
= 0mod £, for
ES2,
.
f2,1(xo)
has at most nprime divisors,
~
h( XO, y) is
irreducible.Proof.
The existence of such an xo can be proven as follows. Take an a E Zsatisfying
the above three congruence relations. Take b to be theproduct
of allprimes
mentioned in the above congruence relations. Definef(Z)
=f2,1 (a
+bZ).
We claim that the content off
is one.Suppose f
divides this content. Then t divides the
leading
coefficient off .
From thisone deduces that f divides b. We
distinguish
several cases:~ then
/z,2(~) =
0 mod f and t does not divide the discriminant of theproduct
of the so we havef (0) - f2,1(a) -t 0 mod ~.
~ If £ divides b and is not in
S,
US2
thenf (0)
=f2,1 (0) -
1 mod R.So for all
priInes £ dividing
b we have thatf 0
0 mod ~. This proves the claim on the content off .
Suppose £
is aprime
smaller then thedegree
off ,
then/(0)
= 1 mod R.If £ is different from these
primes,
then there is a coefficientof f
which isnot divisible
by £
and thedegree
off
is smaller then f. So for everyprime
f there is an zg E Z with 0 mod ~. From this we deduce that we can
apply
Theorem 3.1. The constant forf depends only
on thedegree
ofthe irreducible factors of
f ,
henceequals
n. The setE 7G: has at most n
prime divisors}
is not a thin set. So
is not
empty by
Hilbert’sIrreducibility
Theorem[14, Chapter 9].
Fix suchan ~1 E ~-l. Let xo = a + This proves the claim on the existence of
such an D
Fix an xo
satisfying
the conditions of Lemma 3.3.Adjoin
a root yo ofh(xo, y)
toQ((p).
Denote the fieldQ((p, yo) by K1.
Let P be thepoint
on
X (p) ( K 1) corresponding
to(xo,yo).
Let be theelliptic
curvecorresponding
to P. Let K = Then if q is aprime
suchthat
E/Kq
hasmultiplicative
reduction thenE/Kq
hassplit multiplicative
reduction.
For every
prime
p of K over ESl
we have that P mod q is a cusp oftype (1, 2).
Over everyprime
ES2
there exists aprime
q such that P mod q is a cusp of type(2, 2).
From ourassumptions
on xo it follows that p does not dividef (qlf).
Let7í
consists of theprimes
of Klying
overthe
primes
in LetT2
be the set ofprimes
q such that q lies over aprime in S2
and P mod q is a cusp oftype (2,2).
Note that the set of
primes
of K such that P reduces to a cusp oftype
(2, 1)
has at mostn~K : Q]
elements.We have the
following diagram
Since p
~’
for all f ES2,
the arrow in theright
column isinjective.
This
implies
Since
S2(~P,2~K) ~K : Q]n
and~K : Q] ~ 2(p - 1) deg(h)
we obtainby
Lemma 2.9 that for some E’isogenous
to E we haveNote that
deg(h)
can be boundedby
a function oftype O(~3),
hence[K : Q]
can be boundedby
a function oftype O(p~).
DTo
finish,
we proveCorollary
1.2.Proof of Corollary
1.2. LetE/k
be anelliptic
curve such thatand
~K : ~~ g(p).
Let R :=
ResK/Q(E)
be the Weil restriction of scalars of E. Thenby [10,
Proof of Theorem1]
From this it follows that there is a factor A of
R,
withdimlfp
k. D
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Remke KLOOSTERMAN
Institute for Mathematics and Computer Science (IWI) University of Groningen
P.O. Box 800
NL-9700 AV Groningen, The Netherlands Current address:
Institut fur Geometrie Universitat Hannover
Welfengarten 1
D-30167 Hannover, Germany
E-mail: kloosterman~math.uni-hannover.de