C OMPOSITIO M ATHEMATICA
J. F. V OLOCH
Explicit p-descent for elliptic curves in characteristic p
Compositio Mathematica, tome 74, n
o3 (1990), p. 247-258
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Explicit p-descent for elliptic
curvesin characteristic p
J.F. VOLOCH
IMPA, Est. D. Castorina 110, Rio de Janeiro 22460, Brasil
Received 18 April 1989; accepted in revised form 9 October 1989 (C 1990 Kluwer Academic Publishers. Printed in the Netherlands.
Introduction
The purpose of this paper is to define the
analogue
in characteristic p > 0 of amap defined
by
Manin[5]
forelliptic
curves over function fields of characteristiczero.
Manin’s map is a
homomorphism
1À:E(K) ~ K+,
where K is a function field inone variable over C and
E/K
is anelliptic
curve. Manin used this map to obtain the function fieldanalogue
ofSiegel’s
finiteness theorem forintegral point
onelliptic
curves(and
ageneralization
of this map to prove Mordell’sconjecture
over function
fields,
thisproof actually
contained a gap which was filledby
Coleman
[0].)
Then Stiller[9] (see
also[10])
used Manin’s map to bound the rank ofE(K),
when thej-invariant
of E is non-constant.In this paper we will be concerned with
elliptic
curvesE/K
where K isa function field in one variable over a finite field of characteristic p. Under a mild restriction on E
(see §3)
we will define ahomomorphism
11:E(K) ~
K+ withkernel
pE(K).
This map will furnish anexplicit
way ofdoing p-descent
on E. Asa consequence, we shall show that the Selmer group for the
p-descent
is finite. The finiteness of the Selmer group is a result of Milne([6],
for abelian varietiesof any dimension).
We shall also
give
aproof
of the function fieldanalogue
ofSiegel’s
theorem inpositive
characteristicalong
the same lines as Manin’sproof
in characteristiczero.
Finally
we will relate our map with the reduction modulo p of Manin’s map.Conventions and notation
Throughout
this paper, K will denote a field of characteristic p > 0 and E will bean
elliptic
curve defined over K with Weierstrassequation (with
ai EK):
The invariant differential associated with
equation (1)
will be cv =dx/2y
+alx + a3 and the Hasse invariant of
equation (1)
will be the element A E K for whichC(co)
=A1/p03C9,
where C is the Cartieroperator (see [4]).
When E issupersingular
then A = 0 for any Weierstrassequation
for E. When E isordinary,
achange
of variables x =u2x1
+ r, y =u3y1
+U2SXl
+ t, u =1=0, changes A
tou1-pA.
Hence if E isordinary,
we can talkunambiguously
of theHasse invariant of
E/K
as a well-defined element ofKx/(Kx)p-1.
We shall assume
throughout
this paper thatE/K
is anordinary elliptic
curvewith Hasse invariant 1 E
Kx/(Kx)p-1. Any ordinary elliptic
curve willsatisfy
thiscondition after a
separable
extension of theground
field.Let E’ be the
elliptic
curve with Weierstrassequation
From our
assumption
thatE/K
has Hasse invariant 1 it will follow(see §1)
thatthe
p-torsion points
of E’ are defined over K.Finally,
let F : E - E’ be theisogeny given by F(x, y) = (xP, yp) and 0:
Es Ebe the
isogeny
dual to F. Both Fand 0
havedegree
p, F ispurely inseparable
and4J
isseparable
since E isordinary.
1. Descent
via 0
Before
giving
anexplicit 4J-descent procedure
we willgive
anotherequation
for E’(following Deuring [1])
that will be suitable for our purposes.Suppose
p ~ 2(for
p =
2,
see Remark1.4)
and that E has a Weierstrassequation (1)
withal=a3=O.Let
U(x), V(x) ~ K[x], deg
Up - 2.
Note that A is the Hasse invariant of(1).
LEMMA 1.1. The cover
of E defined by
zP - Az =yV(x)
is an étale coverof degree
p and isisomorphic
to E’ over K.Proof.
Since A ~0,
the cover iscertainly separable
and ofdegree
p and isunramified,
exceptpossibly
above theorigin
0 of E. Butand
y U(x)/xp
isregular
at0,
so the cover is also unramified above O.As any
ordinary elliptic
curve has anunique
étale coverof degree
p, the abovecover must be
isomorphic
to E’ over some finite extension of K. We now provethat there is an
isomorphism
over K. First note thaty U(x)/xp
vanishes at0,
so thereis a
point
0’ above 0 where z -y/x
vanishes and 0’ isobviously
defined over K.Note also that the
p-torsion points
of the cover are thepoints
above O.We have the E’ is
given by equation (2)
and so x, y are the coordinates of~(x’, y’).
Hence togive
theisomorphism
over Kpromised above,
it suffices toshow that z E
K(x’, y’).
LetPi,
i =1,...,
p -1,
be the non-trivialp-torsion points
on E’ and xi, i =
1,..., (p - 1)/2
be their x’-coordinates. Then xi EK, by Gunji’s
formula
[2].
It is easy to check that z has
poles only
at 0’ andPi,
1 i 5 p -1,
resp,z4J*co = -1 and, by above, (z - y/x)(O’)
= 0.Clearly
these conditionsuniquely
determine z. Since the Hasse invariant of(2)
isAP,
we have that the invariant differential 03C9’ of(2)
satisfies A03C9’ =4J*co. Using
this it is easy to check that the functionhas the same
properties
of z noticedabove,
so it isequal
to z. Thiscompletes
theproof.
REMARK 1.2. If c~K satisfies cp-1 = A then z -
y/x -
c vanishes at apoint
above
0,
thatis,
ap-torsion point
of E’. This shows that thep-torsion points
of E’are defined over K.
Now we are
ready
togive
theexplicit ~-descent.
Let03C0(z)
= zp - z and choosea
(p - 1)st
root c of A. Note that c~K since we assumed that the Hasse invariant ofE/K
is in(Kx)p-1.
PROPOSITION 1.3. The map a:
E(K) ~ K+ /n(K+) given by 03B1(O)
= 0 and,x(x, y)
=yV(x)/cp
is ahomomorphism
with kernel~(E’(K)).
Proof.
Let K be aseparable
closure of K and G to Galois group ofK/K.
We have a
homomorphism
03B1:E(K) ~ H 1 (G,
ker~)
obtainedby taking
Galoiscohomology
of the exact sequenceExplicitly, 03B1(P)(03C3)
=Q« - Q
for U EG,
whereQ E
E’ satisfies~(Q)
= P.The function
(z
-ylx)lc
identifiesker 0
withZ/pZ (see
Remark1.2), inducing
an
isomorphism H 1 (G,
ker~)
~H 1 (G, Z/pZ).
On the otherhand, H 1 (G, Z/pZ)
isisomorphic
toK+/03C0(K+) by u ~ (03C3 ~ 03C503C3 - v),
for some vsatisfying 03C0(03C5)
= u.Composing
all theseisomorphisms,
03B1 identifies with a as in the statement of theproposition.
REMARK 1.4. In characteristic 2 we take a Weierstrass
equation (1)
for E witha3 = a4 = 0. The étale cover
giving
E’ is then Z2 + al z = x + a2, as iseasily
checked. The
analogue
of a isa(x, y) = (x
+a2)/a21 (mod 03C0(K+)). (See [3] Prop.
1.1(a)).
2. Descent via F
Suppose p =1=
2. In theproof of Proposition
1.3 it was remarked that the function(z
-y/x)/c (where
c is a fixed(p-1)st
rootof A)
identifiesker 0
withZ/pZ.
LetPi
be thepoint corresponding
to i EZ/pZ.
Gunji
has shown that the function on E’given by
where D =
y’d/dx’,
has divisorp(Pi - 0’).
We shall usef
=fi
togive
anexplicit
F-descent.
PROPOSITION 2.1. The map
03B2: E’(K) - KX/(KX)P given by
is a
homomorphism
with kernelF(E(K)).
Proof.
We first prove thatfi
is ahomomorphism.
LetQ
EE’(K)
be fixed and consider the functiong(P)
=f(P
+Q).
The divisorof g
isp((P 1 - Q) - ( - Q)),
sothe divisor of
g/f
isThe divisor in square brackets is
principal
and defined overK,
so is the divisor of a function r EK(E’).
Hence there exists 03BB ~Kx, g
=ÂfrP,
thatis, f(P
+6) = 03BBf(P) mod(Kx)P
for all P ~E’(K).
We now show that=- f(Q) mod(Kx)P.
We havethat
and, generally,
Hence,
03BB ~f(Q)f(pQ)mod(Kx)p.
Note now thatf 0
F is thepth
power ofa function on E defined over
K,
as follows from(3).
Hencef(pQ)
=f - F(~(Q)) ~ (K’)P.
It follows that =f(Q)mod(KX)P, proving
thatfi
is ahomomorphism.
As
f -
F is apth
power inK(E),
it follows thatker 13
containsF(E(K)).
We nowprove the reverse inclusion.
Gunji [3]
showed thaty’ dfldx’
=cf and,
from(3), f E KP[x, y].
Let now 03B4 bea derivation of K. We have that
If
03B2(P)
=1,
thenf(P)
E(KX)P,
so03B4f(P)
= 0. We conclude that03B4x’(P)
= 0and,
since 03B4 wasarbitrary,
thatx’(P) E K p.
It follows from(2)
thaty’(P) E
KP soP E
F(E(K)),
as desired.REMARK 2.2. As F is
inseparable,
F-descent cannot be doneusing
Galoiscohomology.
One has to use flatcohomology
ofgroup-schemes [7].
Asa
group-scheme,
ker F isisomorphic
to 03BCp, so H1(K,
kerF)
isisomorphic
toKx/(Kx)p and 13
is the mapcoming
from thecohomology
sequence of the exact sequenceOn the other
hand,
F-descent behavesjust
like theprime-to-p
cases(see,
e.g.,[8]
ex.10.1),
the Kummerpairing being
The
proof
in theprime-to-p
case does not work in this context because ofinseparability.
REMARK 2.3. In characteristic
2,
if E has a Weierstrassequation (1)
witha3 = a4 =
0,
theanalogue
off
issimply
x’ and theanalogue
offi
is3. The
complète
P-descentLet k be a
perfect
field ofcharacteristic p
> 0 and K either a function field or a power series field in one variable over k. Assume that thep-torsion points
ofE are not defined over K. Then t =
f(P-1)-1
does notbelong
to K P. Let à =d/dt
and define
03B21: E’(K) ~
K +by f3l (P)
=t03B403B2(P)/03B2(P). Since 13
is defined modulopth
powers,
f3l
is a well-definedhomomorphism
with kernelF(E(K)).
Recall that?L(Z)
= ZP - Z.THEOREM 3.1.
Define 03BC: E(K) ~ K+ by p(P) = 03C0(03B21(Q)) for
someQ
with~(Q)
= P.Then y is a well-defined homomorphism
with kernelpE(K).
Proof.
Assume p =1= 2(for
p = 2 see Remark3.3).
Choose a Weierstrassequation (1)
for Ewith a,
= a3 = 0. Note thatchanging
the Weierstrassequation
for
E changes f by
apth
power,so 13
and03B21
areunchanged.
We can furtherchange
the Weierstrass
equation
so that A = 1.We first show
that y
isindependent
of the choice ofQ.
LetQ, Q’ ~ ~-1(P).
ThenQ - Q’ E ker 0
and we can writeQ - Q’ = iP 1,
for some i EZ/pZ.
Itfollows, by
our choice of t that
03B21(Q) = 03B21(Q’)
+ i. Hencen(pl (Q)) = 03C0(03B21(Q’)),
as desired.Now we show that
03BC(P)
E K. Let K be aseparable
closure of K and G the Galoisgroup
of K/K. Obviously p(P)
E K. Let Q E G then03BC(P)03C3 = 03C0(03B21(Q03C3)).
On the otherhand, Q03C3 - Q
Eker 0
since~(Q03C3 - Q)
= P03C3 - P = 0. Asabove,
we conclude thatn(I3l(QtI)) = 03C0(03B21(Q)),
thatis, Jl(P)tI
=1À(P).
Since 03C3 ~ G wasarbitrary
we concludethat
03BC(P)
E K.As li
isobviously
ahomomorphism,
itonly
remains to be shown thatker 1À
=pE(K).
Consider thefollowing diagram
with exact rows:We will show that this
diagram
commutes.By
the choiceof t, 03B21
identifiesker 0
with
Z/pZ. Also, by definition, 03BC~=03C003B21.
It remains to be shown thatJl(P)
~a(P)
mod03C0(K+).
This is clear fromlooking
at a as a map toH1(G,
ker~)
and
identifying ker 0
withZ/pZ via Pl.
It is obvious that
pE(K)
is contained inker y
since K has characteristic p.Conversely, if Jl(P)
=0,
thena(P)
=0,
so P =~(Q), Q E E(K).
Hence03C0(03B21(Q)) = Jl(P) = 0,
so03B21(Q) = i E Z/pZ.
Then03B21(Q - iP1) = 0,
thatis, Q = F(R)
+iP1
R ~
E(K) and, finally, pR
=~(Q - iP1)
=~(Q)
= P. Thiscompletes
theproof.
REMARK 3.2. For
completeness
it is worthmentioning
that thep-descent
for E’(or
for anyelliptic
curve with K-rationalp-torsion)
isstraightforward.
If a’ is themap
(for E’) given by Proposition 1.3,
then it is easy to check that the map13
fl3 oc’:E’(K) - Kx/(Kx)p
E9K+ /n(K+)
is ahomomorphism
with kernelpE’(K) (see,
e.g.,[12]).
REMARK 3.3. In characteristic
2,
take a Weierstrassequation (1)
for E witha3 = a4 = 0. One can further take
A(= al )
= 1 and theproof
of Theorem 3.1applies
in this case with minorchanges.
A
procedure
fordoing
2-descent in characteristic 2 wasgiven by
Kramer[3],
ina somewhat different fashion. He defined a
homomorphism
y:E(K) - H,
whereH is a certain
quotient
of KX ~a6(K+)2,
with ker y =2E(K).
When a6 is nota square in
K,
which is the case we are, in(otherwise
see Remark 3.2 and[3] Prop.
1.3(b)),
it is easy to show that H is thequotient
of Kx ~a6(K+)2 by ker Â,
where03BB(u, v)
= v +03C0(a603B4u/u)
EK +,
where 03B4 =d/da6’
Hence H isisomorphic
to K +and,
under thisisomorphism,
y becomes(x, y)
~a6/(a1x)2
+03C0(a603B4x/x) (see [3]).
On the other hand a
simple
calculation shows that this map isprecisely
p.REMARK 3.4. It is
fairly
obvious thatJl(x, y)
is a rational functionof x, y, 03B4x, b y
with coefficients in
Fp(a1,a2,a3,a4,a6), but, apparently,
there is nosimple
formula
for 1À
forarbitrary
p. In characteristic3, taking
al = a3 = a4 =0,
a2 =1,
then t = a6 andM(x, y)
=a6y/x3 - 03C0(a603B4x/y).
REMARK 3.5. Without the
hypothesis
that thep-torsion
of E is not defined overK one could still
take 03B2’ = tlf3.dPldt,
for some t EKXB(KX)P,
as ananalogue
ofManin’s map. We have
03B2’:(E’(K)) ~
K + with kernelF(E(K )).
For the relation ofthese
maps with the reduction modulo p of Manin’s map in characteristic zero seeSection 6.
REMARK 3.6. Ulmer
(personal communication)
has shown that the flatcohomology
groupH1(K,
ker[p])
isnaturally isomorphic
to tôK and that the map defined in Theorem 3.1 coincides with thecoboundary
map of thecohomology
sequence of the exact sequence4. Local
analysis
In order to prove the finiteness results below we need to take a local
analysis of y.
Throughout
this section k is aperfect
field of characteristic p > 0 and K =k((s)),
for a variable s. Let v denote the valuation on
K,
R =k[[s]],
M = sR.Let
E/K
be anelliptic
curvesatisfying
thehypotheses
of Section 3. LetElk
bethe reduction modulo v of E and
denote,
asusual, by Eo (K )
and set ofpoints
onE(K) reducing,
modulo v, to anon-singular point
on E andby E1(K)
the set ofpoints
onE(K) reducing
to theorigin
O of É. Recall thatE1(K)
=Ê(M),
whereÊ
is the formal group of E and letEr(K)
=Ê(Mr ),
r 1.Finally,
let T be theparameter in the formal group
Ê.
We will use similar notation forE’ and E. (See [8]
Chs. IV andVII).
THEOREM 4.1.
(a)
The maps y and03B21, defined
in Section3,
are continuous in thev-adic
topology. (b) If
E hasgood, ordinary,
reduction andv(dt)
= 0 then03BC(E(K))
and
03B21 (E’(K))
are contained in R.Proof.
In characteristic 2 this follows from[3], Proposition 2.2,
2.4. We willassume that p ~ 2 and take a minimal Weierstrass
equation (1)
for E witha1 = a3 = 0.
(a)
Theisogeny 0
induces ahomomorphism 4): Ê’ ~ Ê given by
a power series4)(T) E TR[[T]]. As 0
isseparable, ’(0) ~
0 so there exists 03BB ~TK [[T]]
whichis a formal inverse of
4).
It is easy to see that converges inMr,
for rsufficiently large.
Since y
and131
arehomomorphisms
betweentopological
groups, it is sufHcient to check theircontinuity
at anyparticular point.
Near0, J1 = n(f3l 0 03BB),
hence thecontinuity of J1
follows from thatof 03B21. Finally,
away from 0’ andP 1, 03B21 = t03B4f/f,
hence is continuous.
(b) Assume,
without loss ofgenerality,
that k isalgebraically
closed. Since E hasgood, ordinary,
reduction~(E’(K))
=E(K). Thus,
it suffices to prove the result for03B21.
Recall that03B21(P) = (t/dt)(d03B2(P)/03B2(P)).
We first show that t E R’. In
fact,
thereduction il of f
modulo v, is a function onÉ’ with divisor
p(P 1 - 0’),
so it does not have apole
or a zero atP-1,
as desired.All there is to be shown now is that
v(d03B2(P)) v(03B2(P))
for all P EE’(K). Suppose first that P =1= P1,
0’. Thenf3(P)
=f(P)
andf(P) ~ 0,
00, thatis, f(P)
E R’ and theresult follows. If P =
Pi
+Q, Q E E’1(K)
then03B2(P)
=t/3(Q)
and the result for P follows from the result forQ.
We now prove the result inE’1(K).
Now
f
can beexpressed
inE’1(K)
asf(T)
=T - Pg(T), g(T)
ER[[T]], by (3).
Reducing
modulo v,1 hais
apole
of order p at0’,
sog(0) ~ 0,
thatis, g(0)
E R’. As13
is defined modulo(K’)P
we cantake 13
=g(T)
inE’1(K) and,
for T ~ M,v(g(T))
=0, v(dg(T)) 0,
as desired.REMARK 4.2. It is clear that the
proof
of Theorem4.1(a) applies
to show thatthe function
03B2’,
defined in Remark3.5,
is continuous. This result was also shownby
Milne[6].
REMARK 4.3. Ulmer has obtained
precise
results on theimages
of the maps J1 and03B21 (for
the case off3l
see[11])
andapplied
these results to compute the Selmer group for thep-descent (see
hisforthcoming publications).
Assume that K is a function field in one variable over the finite field k of characteristic p and let
E/K
be anelliptic
curvesatisfying
thehypotheses
ofSection 3. Denote
by
V the set ofplaces
of K and let S ={u ~ K u E 03BC(E(Kv)),
v E
V}.
We shall show now that S is finite.THEOREM 4.4. There exists a divisor D
of
Kfor
which S is contained inL(D).
Hence,
S isfinite.
Proof.
Given v EV,
as J1 is continuous andE(K,)
is compact, there exists ev withv(03BC(P))
c,, for all P EE(Kv). Further,
c, = 0 for almost all v,specifically
forthose v
satisfying
thehypotheses
of Theorem4.1(b).
Hence03A3cvv
= D is a divisorof K and S is contained in
L(D).
SinceL(D)
isfinite, S
is finite.Clearly, J1(E(K))
is contained inS,
so we get aninjection
ofE(K)/pE(K)
intoS
which, by
the way, proves the(weak)
Mordell-Weil theorem.5.
Integral points
In this section we shall prove the function field
analogue
inpositive
characteristic ofSiegel’s
finiteness theorem forintegral points
onelliptic
curves. Ourproof will
be very similar to Manin’s
proof
in characteristic zero. Infact,
theproof
ofLemma 5.1 below is identical to the outline in
[5],
pg. 194. The addedcomplication
ofpositive
characteristic is dealt withby
Lemma 5.2.LEMMA 5.1. Let K be a
function field
in one variable over afinite field
andS a
finite
setof places of
K.(a)
LetE/K be
anordinary elliptic
curve whosep-torsion points
are notdefined
over K.
If (1) is a
Weierstrassequation for
E then the set{P
EE(K)BpE(K)|
v(x(P))
0for
all v not inS}
isfinite.
(b)
LetA/K
be anordinary elliptic
curve and assume that itsp-torsion subgroup
0393 isdefined
over K. Let F:A/0393 ~
A be theisogeny
dual to the naturalisogeny A ~ A/0393. If (1) is a
Weierstrassequation for
A then the set{P ~ A(K)B F(A/0393(K))|v(x(P)) 0, for
all v not inSI
isfinite.
Proof. (a)
Without lossof generality,
we can take a finiteseparable
extension of K and assume that the Hasse invariant ofE/K
is 1.If the conclusion is
false,
there exists v E S and a sequencePn ~ E(K)BpE(K),
with
v(x(Pn))
- - oo as n ~ 00. HencePn -+-
0 in the v-adictopology,
so03BC(Pn) ~ 0, by
Theorem4.1(a).
As03BC(Pn) ~ L(D), by
Theorem4.1,
this canonly happen
ifJ1(P n)
= 0 for all nsufficiently large.
Thisimplies
thatP nE pE(K)
forn
large,
which is acontradiction, proving (a).
(b)
Asabove,
we may assume that the Hasse invariantof A/K
is 1. We can thenuse the
function 03B2’
defined in Remark 3.5 as p was used in theproof
of(a) (see
Remark
4.2).
LEMMA 5.2. Notation and
hypotheses
as in Lemma5.1(a).
The set{P ~
E(K)|v(x(P)), v(x(pP)) 0, for
all v not inSI
isfinite.
Proof.
Assume first that p =1= 2.By changing
they-coordinate
of(1),
we canassume that al = a3 = 0. Let b E K be the x-coordinate of a non-trivial
p-torsion point Pi
inE’(K).
Note that b is not apth
powerfor, otherwise, Pi
EF(E(K)), contradicting
thehypothesis
that thep-torsion
of E is not defined over K.Enlarge S,
if necessary, so thatv(b)
= 0 and(1)
is minimal and hasgood,
ordinary,
reduction for all v not in S.Let P E
E(K ) satisfy v(x(P)), v(x(pP))
0 for all v not in S. Thenv(x(P)p - b)
0 for all such v.
Suppose
that for some such v,v(x(P)P - b)
> 0. ThenF(P)
---±P1
modE’1(Kv).
HencepP ~ ~(±P1) = 0
modE1(Kv)’
Thisimplies
thatv(x(pP))
0 contrary tohypothesis.
It follows thatv(x(P)P - b)
= 0 for all v notin S. On the other
hand,
themultiplicities
of the zeroesof x(P)P -
b are boundedsince db ~
0,
soIt follows that there are
only finitely
manypossibilities
forx(P)p - b,
henceonly finitely
manypossibilities
forP,
as desired.For p =
2,
take a Weierstrassequation (1)
for E with a3 = a4 = 0 and work with they-coordinate
instead of the x-coordinate. We leave the details to the reader.THEOREM 5.3. Let K be
a function field
in one variable overa finite field
andS
a finite
setof places of K. If A/K
is anelliptic
curve withnon-constant j-invariant
andf E K(A)
is anon-constant function
then the set{P
EA(K)|v(f(P)) 0, for
allv not in
SI
isfinite.
Proof.
It is well-known that it is sufficient to prove the theorem whenf
is thex-coordinate of a Weierstrass
equation (1)
for A(see,
e.g.,[8]
Cor.IX.3.2.2).
Letj(A)
bethe j-invariant
of A and note that A isordinary since j(A)
is non-constant.As in the
proof of Lemma 5.1,
we may assume that the Hasse invariantof A/K
is1.
Suppose
that thep-torsion points
of A are defined over K.By
Lemma5.1(b)
it issufficient to prove the theorem for
A/r.
Note now thatj(A/r)
=j(A)1/p,
hencerepeating
thisfinitely
many times wearrive,
sincej(A)
is non-constant, at anelliptic
curve Esatisfying
thehypotheses
of Lemma5.1(a)
and weonly
have toprove the theorem for E.
By
Lemma5.1(a)
it isenough
to show that the set{P ~
pE(K) |v(x(P)) 0,
for all v not inS}
is finite.Enlarge S,
if necessary, as in theproof
of Lemma 5.2. Let P =pQ, Q
EE(K), satisfy v(x(P))
0 for some v not in S. Thenv(x(Q))
0for, otherwise, Q E E1(Kv) and,
since this is asubgroup
ofE(Kv), P ~ E1 (K,),
absurd. Now the result follows from Lemma 5.2.REMARK 5.4. Theorem 5.3 is false without the
assumption
that thej-invariant
is non-constant. The best
possible
result when thej-invariant
is constant isLemma
5.1(b).
REMARK 5.5. With a bit more effort the
proof
of Theorem 5.3 can be made effective. We leave the details to the reader.6. Manin’s map
Manin’s map is characteristic zero is defined as follows. Let
E/K
be onelliptic
curve defined over the field K of characteristic zero
possessing
a derivation 03B4. LetP(03B4)
be thepolynomial
ofdegree
2 in 03B4annihilating
theperiods
ofE,
thatis,
thePicard-Fuchs
operator.
Define M :E(K) -
K + asM(P)
=P(03B4)P003C9,
where co isa
regular
differential on E. Forexample, if Eq
is the Tate curve([8])
defined overC((q))
= Kand,
under theisomorphism Eq ~ KX/qZ, co
=du/u (u
=parameter
inKx), P(d/dq) = (qdldq)’ (since
theperiods
are1, log q)
andfinally:
THEOREM 6.1. Let K be a
function field
in on variable over aperfect field
kof
characteristic p >
0, E/K
theelliptic
curveof equation (1)
and 03B4 the derivationof K/k defined
in Section 3.If /
is alifting of E/K
to characteristic zero with Manin mapM,
then there exists a E KX such thatProof. By choosing
aplace
v of K for whichE/K
hasmultiplicative
reductionand
taking
alifting 9
of v to aplace
ofK
we arereduced, by
theabove,
tocomputing p
for the Tate curve overk((q))
= K.From
equation (4)
of Section 2 we haveAs
x’(P)
=x(u, qP)
andsimilarly
fory’,
we getimmediately
thatcôx’/y’ = bu/u
hence
03B2(u)
=t03B4u/u.
AsPi corresponds
to u = q we have03B2(q)
= 1 so03B2(u)
=q/u du/dq.
As ~: E’ - E isgiven by u(mod qPZ)
Hu(mod qZ)
it follows thatFinally - qd/-l/dq
=q/dq(q/u·du/dq) ~
M(mod p), and - qd/dq
= ab for somea ~ Kx.
Acknowledgments
Part of this work was done
during
a visit to Australasia. The author would like to thankMacQuarie University
and theUniversity
ofSydney
in Australia andVictoria
University
ofWellington,
in New Zealand for theirhospitality.
Theauthor would also like to thank D. Ulmer for various comments and
suggestions
on an earlier draft of this paper.
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