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DOI: 10.4310/ARKIV.2019.v57.n2.a8

c 2019 by Institut Mittag-Leffler. All rights reserved

Weighted estimates for the Laplacian on the cubic lattice

Evgeny L. Korotyaev and Jacob Schach Møller

Abstract. We consider the discrete Laplacian Δ on the cubic lattice Zd, and deduce estimates on the groupeitΔand the resolvent (Δz)1, weighted byq(Zd)-weights for suitable q2. We apply the obtained results to discrete Schrödinger operators in dimension d3 with potentials fromp(Zd) with suitablep1.

1. Introduction and main results 1.1. Introduction

We consider the Schrödinger operator H acting in2(Zd), d3 and given by

(1.1) H= Δ+V,

where Δ is the discrete Laplacian onZd defined by

(1.2)

Δf (n) =1

2 d j=1

fn+ej+fn−ej ,

forf=(fn)n∈Zd2(Zd). Heree1=(1,0, ...,0), ..., ed=(0, ...,0,1) is the standard ba- sis ofZd. The spectrum of Δ is absolutely continuous andσ(Δ)=σac(Δ)=[−d, d], and the threshold set – critical energies of Δ in its momentum representation – is τ(H)=τ(Δ)=(2Z+d)∩[−d, d].

The operatorV is the operator of multiplication by a real-valued potential func- tion, V=(Vn)n∈Zd. The potentials we work with will always satisfy that

Key words and phrases:discrete Laplacian, resolvent, Bessel function, Birman-Schwinger.

2010 Mathematics Subject Classification:81Q10, 81Q35, 47A40, 33C10.

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limn→∞Vn=0, and consequently the essential spectrum of the Schrödinger oper- atorH on2(Zd) isσess(H)=[−d, d]. However, this does not exclude appearance of eigenvalues and singular continuous spectrum in the interval [−d, d].

Before describing our results, we recall some well known classic results by Kato for the continuous case, established in the famous paper [10]. Kato considered the Laplacian Δ acting in the spaceL2(Rd) ford2. He proved the following estimates:

(i) Letd2 andq >2. Then for allt∈R\{0}andu∈Lq(Rd), we have (1.3) ueitΔuCd,q|t|dqu2q,

for some constantCd,q depending ondandqonly.

(ii) Letε>0 andd>2+ε. For anyu∈Ldε(Rd)∩Ld+ε(Rd), we have (1.4) λ∈C\[0,) : u(−Δ−λ)1uCd,ε

u2dε+u2d+ε

, for some constantCd,ε depending ondandεonly.

These estimates have a lot of applications in spectral theory, see [25]. Note that (1.3) is a simple example of a dispersive (or Strichartz) estimate. Dispersive estimates are very useful in the theory of linear and non-linear partial differential equations, see [27] and references therein. Note that the estimate (1.3) implies (1.4) and that the operator-valued function u(−Δ−λ)1u is analytic in C\[0,∞) and uniformly Hölder up to the boundary.

In the present paper we prove a dispersive estimate of the type (1.3) for the discrete Laplacian (1.2), and we show that by replacing theq-norm with a weighted q-norm on the right-hand side one may improve the time-decay. This is the content of Theorem1.1 below. Secondly, we establish resolvent estimates of the type (1.3) that are better than what is implied by our dispersive estimates. See Theorem1.3.

That is, unlike the continuous case studied by Kato, one does not get good resolvent bounds merely by integrating a dispersive estimate of the type (1.3). Instead we an- alyze and exploit the pointwise decay of the summation kernel for the free resolvent.

The starting point for our analysis is a representation of the summation kernel of the propagator in terms of a product of Bessel functions. Our estimates then follow from a careful use of recent optimal estimates on Bessel functions by Krasikov [17]

and Landau [18]. Finally, in Theorem 1.5, we deduce consequences for the spec- tral and scattering theory for the Hamiltonian (1.1) with potentials from a suitable p(Zd) space. The proof of this last theorem revolves around Birman-Schwinger type arguments.

For the discrete Schrödinger operators on the cubic lattice, most results were obtained for uniformly decaying potentials for theZ1case, see for example [3], [8], [13], [31]. For real-valued finitely supported potentials in Zd, Kopylova [14] has established dispersive estimates, Shaban and Vainberg [28] as well as Ando, Isozaki

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and Morioka [1, Thm. 7.7], studied Limiting Absorption away from thresholds, and Isozaki and Morioka [7, Thm. 2.1] proved that the point-spectrum of H on the interval (−d, d) is absent. Note that in [5] the authors gave an example in dimensiond5 of an embedded eigenvalue at the endpoint{±d}. Recently, Hayashi, Higuchi, Nomura, and Ogurisu computed the number of discrete eigenvalues for finitely supported potential [4].

For Schrödinger operators with decreasing potentials on the latticeZd, Boutet de Monvel and Sahbani [2] used Mourre’s method to prove absence of singular continuous spectrum and local finiteness of eigenvalues away from threshold energies τ(H), a technique revisited by Isozaki and Korotyaev [6], who also studied the direct and the inverse scattering problem as well as trace formulae. In a recent preprint, Mandiche [20] constructed a Wigner-von Neumann type long-range potential with an eigenvalue embedded in the interior of the essential spectrum.

Ford/2(Zd)-potentials, Rozenblum and Solomyak [26] gave an upper bound on the number of discrete eigenvalues in terms of thed/2(Zd)-norm of the potential.

Recently, Ito and Jensen [9] expanded the free resolvent integral kernel in momentum space near each threshold energy, i.e., near eachλ∈τ(Δ). This analysis complements that of [1], which also relies on a detailed investigation of the resolvent in its momentum representation.

For closely related problems, we mention that the results of Sahbani and Boutet de Monvel [2], were recently extended to general lattices by Parra and Richard [21]. In addition, the result in [7], on absence of embedded eigenvalues (away from {−d, d}) for finitely supported potentials, has a generalization to other lattices in [1, Thm. 5.10], where the inverse problem is also considered. Finally, scattering on periodic metric graphs associated with Zd was considered by Korotyaev and Saburova in [15].

1.2. Estimates of free time evolution

Our first result consists of weighted estimates for the propagator of the discrete Laplacian onZd. To fix some notation, we write p(Zd) for the space of sequences f=(fn)n∈Zd equipped with the norm

(1.5) fpp=fpp(Zd)=

n∈Zd

|fn|p<∞.

Forp1 andˇ0, we shall make use of the weighted spacespˇ(Zd), consisting of sequences with finite weighted norm

(1.6) fpp,ˇ=fppˇ(Zd)=

n∈Zd

ρnpˇ|fn|p,

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where

(1.7) ρn=

d j=1

(1+|nj|)1, n∈Zd.

For p=∞ this amounts to f∞,ˇ=supnρ−ˇn |fn|. For bounded operators T on 2(Zd), we writeT for the operator norm ofT.

We are now ready to formulate our first result on weighted estimates on the propagatoreitΔ.

Theorem 1.1. Letd1. The following holds true:

(a)Let q2. Then for allt∈R\[1,1]andu, v∈q(Zd),we have

(1.8) ueitΔvC

2d q

Lan|t|2d3quqvq, where the constant CLan<4/5.

(b)Let a>1/2, 2qandq−2q . Then for all t∈R with |t|1 and u, v∈qˇ(Zd), we have

(1.9) ueitΔvC

2d q

LanC

dˇ

aa|t|d

2 3q+2aˇ

uq,ˇvq,ˇ, where Ca=3

1+2a−12a

. (For q=∞ the obvious interpretation of the estimate ap- plies.)

Remarks1.2. (1) One can find Landau’s optimal constantCLan with sev- eral decimals in [18].

(2) By allowing for the ρ-weights in (b), one may improve the time-decay of theq-weighted time evolution from (a) slightly.

1.3. Estimates of the free resolvent

Letγ∈[0,1],d>2+2γand q2. Ifq >2, we define

(1.10) Γ(q, d, γ) =

⎧⎪

⎪⎪

⎪⎪

⎪⎨

⎪⎪

⎪⎪

⎪⎪

3+12−(5+2γ)q12(q−2) 3(q−2)q

, if d=3

3+2 5q2

8−(3+γ)q

1+4(q−2)q 4(q−2)q

if d=4

3+6d−(2d+1+3γ)q6d(q−2)

d(q−2)q

if d>4.

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If q=2 and d=4, we set Γ(2, d, γ)=1 and finally we set Γ(2,4, γ)=(1−γ)−1. We furthermore need

(1.11) Cdγ=

⎧⎪

⎪⎪

⎪⎪

⎪⎩

1−2γ2 +8 if d=3,

2

1γ if d=4,

d−410 if d>4.

and

(1.12) γd,q=

⎧⎨

6

q52, d=3

2d

q 2d+13 , d4.

Our second main theorem is the following weighted resolvent estimates.

Theorem 1.3. Let d3. Letu, v∈q(Zd)with

(1.13) 2q <

⎧⎨

12

5 if d=3,

6d

2d+1 if d4.

Then the operator-valued functionY0:C\[−d, d]→B(2(Zd)),defined by

(1.14) Y0(z) :=u(Δ−z)−1v

is analytic and H¨older continuous up to the boundary. More precisely,it satisfies:

(a)For allz∈C\[−d, d],we have

(1.15) Y0(z)

1+Cd0Γ(q, d,0)

uqvq.

(b)Let γ∈[0,1] satisfy the constraint γ <γd,p. For all z, z∈C\[−d, d] with Im(z),Im(z)0,we have

(1.16) Y0(z)−Y0(z)|z−z|γ

1+CdγΓ(q, d, γ)

uqvq. Remark 1.4. We observe the following consequences:

(1) The weighted resolventY0(z) is analytic inC\[−d, d] and extends by con- tinuity fromC± to a Hölder continuous function onC±. We denote the extension fromC± to [−d, d] byY0±i0).

(2) Ifd=3 andq=2 the Hölder exponent must satisfy the constraintγ <1/2 and ford=4 andq=2 we have γ <1. However, ifd5 andq=2, the extended weighted resolvent is Lipschitz continuous. In fact, one retains Lipschitz continuity ford5 provided

(1.17) 2q < 6d

2d+4.

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(3) At the cost of a possibly larger prefactor, we actually get resolvent estimates in Hilbert-Schmidt norm. See Theorem3.3for a precise formulation.

(4) While the window of exponentsqin (1.13) is fairly small, it turned out to be crucial for an application to the Laplacian on the cubic metric graph [16]. In that paper we need Theorem1.3to be valid for someq >2.

In [6, Lemmas 5.3 and 5.4], the authors establish free resolvent estimates in d=1 andd=2 with2(Zd)-weights. These estimates blow up at the threshold set τ(Δ), which is no coincidence, cf. [9]. In dimensionsd3, [6, Lemma 5.5] establishes free resolvent estimates across thresholds but with mixed2-weights andρ-weights.

In [6] a Hölder estimate on a suitably weighted free resolvent is also derived, but with no control over the Hölder exponentγ.

1.4. Applications to Schrödinger operators

Finally we investigate some consequences of the resolvent estimates for a par- ticle in a cubic lattice, subject to an external potential. We consider the Schrödinger operator H=Δ+V acting in 2(Zd), d3, where the real-valued potential V= (Vn)n∈Zd is an element of a suitablep(Zd) space. In particular, H is a bounded operator withσess(H)=[−d, d].

Recall the decomposition

(1.18) 2(Zd) =Hac⊕Hsc⊕Hpp

of the Hilbert space into the absolutely continuous, singular continuous subspaces ofH and the closure of the span of all eigenstates ofH.

Theorem 1.5. Letd3 andV∈p(Zd)with

(1.19) 1p <

⎧⎨

6

5 if d=3,

3d

2d+1 if d4.

(a)All eigenvalues λ∈σpp(H)are of finite multiplicity.

(b)The closure of the set σpp(H)∪σsc(H) has zero Lebesgue measure. If, in addition, Vp<(1+Cd0Γ(2p, d,0))1, then: σpp(H)=σsc(H)=∅.

(c)The wave operators

(1.20) W±:= s− lim

t→±∞eitHe−itΔ exist and are complete, i.e.; W±2(Zd)=Hac.

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(d)Ifd5 and

(1.21) 1p < 3d

2d+4, thenσpp(H)is a finite set andσsc(H)=∅.

Remark 1.6. Sincepd/2 andd3, it is a consequence of a result of Rozenblum and Solomyak [26, Thm. 1.2] thatσ(H)\[−d, d] is a finite set. Finiteness ofσpp(H)∩

[−d, d] is typically a much harder question, here settled in the affirmative ford5.

Example 1.7. Let d3 and let ˇ:Zd→Zd be injective and θ: Zd→C satisfy

n|1 for alln. Define a potential by setting

(1.22) Vn=

⎧⎨

0 if n∈ˇ(Zd)

θnd

j=1ρˇ1(n)j if n∈ˇ(Zd) Consider the Hamiltonian

(1.23) Hg= Δ+gV.

We conclude from Theorem1.5that:

(1) the wave operators exist and are complete. If in addition g is sufficiently small, more precisely |g|<(1+Cd0Γ(11/10, d,0))−1ρ−d11/10, then the operator Hg

has no eigenvalues and the singular continuous spectrum is empty.

(2) ifd5, then we additionally have, for anyg∈R, that the operatorHghas at most finitely many eigenvalues, all of finite multiplicity, and the singular continuous spectrum is empty.

Note that the critical coupling in (1) does not depend onˇandθ. Even ifˇ(n)=n andθn=1 alln, the potential is long-range in the direction of each coordinate axis.

Playing withˇ, one can engineer sparse potentials with arbitrarily slow decay.

We end this section with a discussion of the momentum representation of the discrete Laplacian.

One may diagonalize the discrete Laplacian, using the (unitary) Fourier trans- form Φ :2(Zd)→L2(Td), whereT=R/(2πZ). It is defined by

(1.24) (Φf)(k) = ˆf(k) = 1 (2π)d2

n∈Zd

fnein·k, wherek= (kj)dj=1Td.

Here k·n=d

j=1kjnj is the scalar product in Rd. In the resulting momentum representation of the discrete Laplacian Δ, we write ˆΔ=ΦΔΦ. We recall that the

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Laplacian is transformed into a multiplication operator

(1.25) ( ˆΔ ˆf)(k) =

d

j=1

coskj

f .ˆ

The operatoreitΔ, t∈Ris unitary onL2(Td) and has the kernel (eitΔ)(n−n), where forn∈Zd:

(1.26)

(eitΔ)(n) = 1 (2π)d

Tde−in·k+itdj=1cos(kj)dk

= d j=1

1 2π

0

e−injk+itcos(k)dk

=i|n|

d j=1

Jnj(t),

where|n|=n1+...+nd. HereJn(z) denotes the Bessel function:

(1.27) Jn(t) =(−i)n

0

einkitcos(k)dk (n, z)Z×R.

We have collected some basic properties of Bessel function with integer index in (A.1).

1.5. Plan of the paper

In Section 2 we determine properties of the free time evolution and prove Theorem 1.1. Section 3contains basic estimates on the free resolvent and a proof of Theorem 1.3. In Section 4 we apply the above results to discrete Schrödinger operators and prove Theorem1.5. In AppendixA andBwe recall and expand on some key estimates of Bessel functions. Finally, in AppendixC, we have collected some useful discrete estimates.

2. Estimates for the free time evolution

Our first lemma establishes a basic mapping property of the summation kernel of the free propagatoreitΔ.

Lemma 2.1. Let2r∞, s∈[1,2]and 1r+1s=1. Then for allt∈R (2.1) eitΔfrC2d(

1 s12)

Lan |t|2d3(1s12)fs f∈s(Zd)., whereCLan is one of Landaus optimal constants from LemmaA.1.

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Proof. Note that the operator eitΔ is unitary on 2(Zd). In particular eitΔf2=f2.

Iff∈1(Zd)∩2(Zd), then it follows from (A.4) thateitΔfCLand td3f1. By the discrete Riesz-Thorin Interpolation Theorem (TheoremC.1), eitΔ extends uniquely to a map froms(Zd) tor(Zd) and satisfies (2.1).

Now we describe the more regular case.

Lemma 2.2. Leta>12, c∈[0,1]and lett∈Rwith|t|1. AbbreviateCa=3 1+

2a−12a

.

(a)If d=1, then the following estimates hold true:

ρaeitΔρaCa|t|12, (2.2)

ρaceitΔρacCac|t|c2. (2.3)

(b)Ifd1,then the following estimates hold true:

ρaeitΔρaCad|t|d2, (2.4)

ρaceitΔρacCadc|t|cd2 . (2.5)

Proof. To establish (a), we estimate ford=1 using PropositionA.3 ρ(n)2a|eitΔ(n−m)|2ρ(m)2a= |Jn−m(t)|2

(1+|n|)2a(1+|m|)2a

t12 1

(1+|n|)2a(1+|m|)2a(|n−m|13+||n−m|−t|)12, (2.6)

for allt>0 andn, m∈Z. Invoking (A.2) and LemmaC.3(withα=2aandβ=1/2), we estimate in Hilbert-Schmidt norm:

ρaeitΔρa2B2

n,m∈Z

ρ(n)2a|eitΔ(n−m)|2ρ(m)2a

2

n∈Z

1

(1+|n|)4a+t12

×

n,m∈Z

1

(1+|n|)2a(1+|m|)2a(1+||n−m|−t|)12

2

1+2

0

(1+x)−4adx

+1 t

2

(α−1)2+ 4α

1)(pα1)1p321r

6

+1 t

2(2a)2

(2a−1)2+ 4(2a)

(2a−1)(6a−1)133223

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2 t+1

t

2(2a)2

(2a−1)2+ 4(2a) (2a−1)2133223

=

2 (2a)2

(2a−1)2+32 2a 2a−1+2

1 t9

1+ 2a

2a−1 21

t. (2.7)

This proves (2.2) and (2.3) now follows from the estimate TTB2 valid for Hilbert-Schmidt operators, and Hadamard’s Three Line Theorem applied for ψ∈

2(Zd) with ϕ(z)=ψ, ρazeitΔρazψ for z∈C with 0Rez1. See [24, App. to IX.4].

To conclude, we observe that the statements in (b) follow from (a).

Proof of Theorem1.1. We begin with (a). It suffices to proof the claim for t1. From (2.1), we recall the estimate

(2.8) ∀f∈s(Zd) : eitΔfrCLanˇ tˇ3fs, where ˇ= 2d 1

s−1 2

,

and 2r∞with 1r+1s=1. Thus, ifu∈q(Zd) withq2, thenr=(1/2−1/q)−12 such that we may estimate foru, v∈q(Zd) using (2.8) and Hölder’s inequality (2.9)

ueitΔ2uqeitΔrC

2d q

Lant2d3quqsC

2d q

Lant2d3quqvqϕ2, which yields (1.8).

We now turn to (b). It follows from (1.8) and (2.5) that we have

(2.10)

∀a >0, c[0,1] : ρaceitΔρacCacd|t|dc2,

∀q2 : ueitΔvC

2dq

Lan|t|3q2duqvq. HereCa is the explicit constant from Lemma 2.2.

Letψ∈2(Zd),u, v: Zd→[0,∞) with finite support, and put (2.11) ϕ(z) =ψ, ρac(1−z)uzeitΔvzρac(1−z)ψ.

Writingϕas a double sum, we see thatϕis analytic in 0<Rez <1 and continuous on the closure of the strip. Moreover,ϕ is bounded in the closed strip so we may apply Hadamard’s Three Line Theorem. The estimates in (2.10) now interpolates to the estimate

(2.12) ρabcu1−beitΔv1−bρabcC

2d(1−b) q

Lan Cadbc|t|−βu1q bv1q b, valid foru, v:Zd→[0,∞). Here

(2.13) β= 2d

3q(1−b)+d 2b=d

2(1−b) 3q +bc

2

.

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Foru, v:Zd→Cwith finite support, we can now estimate forb, c∈[0,1] andq2:

(2.14)

ueitΔv=|u|eitΔ|v|=ρabc(u)1−beitΔ(v)1−bρabc

C

2d(1−b) q

Lan Cadbc|t|βu1q bv1q b, whereu1−babc|u|1−b1 andv1−babc|v|1−b1 .

Let q2 and 0ˇa(q−2)/q be the exponents from the formulation of the theorem. In order to end up with aq norm, we must pick b∈[0,1] such that q= q(1−b) and to ensureq2, we get the constraint 0b(q−2)/q. We get best time decay by pickingb=(q2)/q, in which case we end up with the estimate

(2.15) ueitΔvC

2d q

LanC

dc(q−2)

a q t−d 2

3q+c(q2q2)

uq,acq2

q vq,acq2

q .

Ifq >2, then we may choose c=aˇq/(q−2)∈[0,1] to arrive at the desired estimate (1.9), at least foru, v with finite support. If q=2, the same conclusion holds im- mediately. After extension by continuity to arbitraryu, v∈qˇ(Zd), we conclude the proof.

3. Estimates on the free resolvent

We have the standard representation of the free resolvent R0(λ) in the lower half-planeC given by

(3.1)

R0(λ) =−i

0

eit(Δ−λ)dt=R01(λ)+R02(λ), R01(λ) =−i

1 0

eit(Δ−λ)dt, R02(λ) =−i

1

eit(Δ−λ)dt,

for allλ∈C. Here the operator valued-functionR01(λ) has analytic extension from C into the whole complex planeCand satisfies

(3.2) ∀λ, μ∈C: R01(λ)1 and R01(λ)−R01(μ)|λ−μ|. We shall need the following lemma.

Lemma 3.1. Let d3 and γ∈[0,1] be such that d>2+2γ. Then for each (t, n)∈R×Zd the following estimate holds true:

(3.3)

1

tγ(eitΔ)(n)dtCdγˇ˜dγ(n),

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where the constant Cdγ is defined by (B.2),

(3.4) ˇdγ(n) =

d j=1

ˇγd(nj)

andˇdγ is defined in (B.3).

Proof. Using (1.26) and (B.1), we obtain for alln∈Zd:

1

tγ|(eitΔ)(n)|dt=

1

d j=1

tγd|Jnj(t)|dt d j=1

1

tγ|Jnj(t)|ddt 1/d

Cdγˇ˜γd(n), (3.5)

which yields (3.3).

The above lemma yield estimates on the summation kernel ofR02(λ).

Proposition 3.2. Letd3. The following estimates for the summation kernel ofR02(λ)hold true:

(a)For allm∈Zd andλ∈C\R:

(3.6) |R02(m, λ)|Cd0ˇ˜0d(m), whereˇ˜d0 is defined in (3.4).

(b)Supposeγ∈[0,1]andd>2+2γ. Then for allm∈Zd and λ, μ∈C\R:

(3.7) |R02(m, λ)−R02(m, μ)|Cdγˇ˜γd(m)|λ−μ|γ.

Proof. Consider first the case λ, μ∈C. From (3.1) and the estimate (3.3) (withγ=0), we find that

(3.8) |R02(m, λ)|

1

|(eitΔ)(m)|dtCd0ˇ˜d0(m).

where the sequence ˜ˇ0p=( ˜ˇp0(n))n∈Zd is given by (3.4).

The Hölder estimate (3.7), follows from the identity (3.1) and the estimates

|e−itλ−e−itμ|tγ|λ−μ|γ and (3.3):

|R02(m, λ)−R02(m, μ)||λ−μ|γ

1

tγ|(eitΔ)(m)|dtCdγˇ˜γd(m)|λ−μ|γ. For λ, μ∈C+, the two estimates follow from what has already been proven together with the identityR02(m, z)=R02(−m, z).

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Proof of Theorem 1.3. Consider the caseλ∈C and letu, v∈q(Zd) withd3.

DefineY02by

Y02(z) =u R02(z)v, ∀z∈C\[−d, d].

The estimate (3.6) yields an estimate of the Hilbert-Schmidt norm ofY02(z):

Y02(z)2B2=

n,n∈Zd

|un|2 |R02(n−n, z)|2|vn|2 (Cd0)2

n,n∈Zd

|un|2ˇ˜d0(n−n)2|vn|2

and applying the Young inequality from TheoremC.2at 2q+1r=1, we obtain

(3.9)

Y02(z)2B2(Cd0)2

n,n

ˇ˜d0(n−n)2|un|2|vn|2 (Cd0)2u2qv2qˇ˜d02r.

Note that

(3.10) ˇ˜0dr=

n∈Zd

ˇ˜0d(n)r 1r

=

n∈Zd

d j=1

ˇd0(nj)r 1r

=ˇd0dr.

In order to ensure finiteness ofˇ˜0drwe must therefore, according to LemmaB.2, require thatr>r0d, wherer0dis defined in (B.13). Noteq=2r/(r−1) and that this ex- pression is decreasing inr2. Sincer0d2, we may therefore express the constraint r>r0d by the constraintq <2r0d/(rd0−1) onqinstead. Inserting the expression forr0d from (B.13), we arrive at the constraint in (1.13). Furthermore, employing the first estimate in (3.2), and the estimate from LemmaB.2withγ=0, we arrive at (1.15).

(Recall thatTB2T.)

The estimate (3.7) and the Young inequality from TheoremC.2with 1p+1r=1, implies

Y02(z)−Y02(z)2B2=

n,n∈Zd

|un|2 |R02(n−n, z)−R02(n−n, z)|2|vn|2 (Cdγ)2|λ−μ|

n,n∈Zd

|un|2 ˇ˜γd(n−n)2|vn|2 (Cdγ)2|λ−μ|u2qv2qˇ˜γd2r

(Cdγ)2|λ−μ|u2qv2qΓ2(q/2, d, γ), since – due to LemmaB.2– we have:

(3.11) ˇ˜γdr=

n∈Zd

ˇ˜γd(n)r r1

=

n∈Zd

d j=1

ˇdγ(nj)r 1r

=ˇdγdrΓ(q, d, γ).

This, together with the second estimate in (3.2), completes the proof.

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In the proof Theorem 1.3, we actually estimated the R02(z) contribution in Hilbert-Schmidt norm, only theR01(z) contribution was estimated directly in op- erator norm, cf. (3.2).

We end this section with resolvent estimates in Hilbert-Schmidt norm, where we must investigate theR01 contribution more closely. LetB2 denote the Hilbert- Schmidt class. We writeKB2 for the Hilbert-Schmidt norm of an operatorK.

Theorem 3.3. Letd3. Let u, v∈q(Zd)with

(3.12) 2q <

12

5 if d=3,

6d

2d+1 if d4.

Then the operator-valued functionY0:C\[−d, d]→B2, defined by

(3.13) Y0(z) :=u(Δ−z)−1v

is analytic and H¨older continuous up to the boundary. More precisely,it satisfies:

(a)For allz∈C\[−d, d],we have (3.14) Y0(z)B2

Dq,d+Cd0Γ(q, d,0)

uqvq, whereD2,d=1andDq,d=(q/2)d(q−2)q

(b)Let γ∈[0,1] satisfy the constraint γ <γd,p. For all z, z∈C\[−d, d] with Im(z),Im(z)0,we have

(3.15) Y0(z)−Y0(z)B2|z−z|γ

Dq,d+CdγΓ(q, d, γ)

uqvq.

Proof. We only need to estimate theR01contribution, since theR02 contribu- tion was estimated in Hilbert-Schmidt norm in the proof of Theorem1.3.

We abbreviateY01(z)=uR01(z)v and estimate using Lemma A.4 (3.16) Y01(z)2B2

n,m

|un|2 1

0

|eitΔ(n−m)|dt 2

|vm|2

n,m

|un|2ρn−m|vm|2. Recall from (1.7) the definition of the function ρ. Let r=∞ if q=2 and r=(1− 2/q)1=q−2q ifq >2. By the discrete Young inequality, TheoremC.2, we conclude the estimate

(3.17) Y01(z)B2ρruqvq.

Forq >2, we estimate (using (C.8)) (3.18) ρrr=

n∈Zd

d j=1

(1+|nj|)r=

m∈Z

(1+|m|)r d

r

r−1 d

=qd 2d.

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Similar, we estimate for anyγ∈[0,1] andz, z in the same half-plane (3.19) Y0(z)−Y0(z)B2|z−z|γDq,duqvq.

This completes the proof.

4. Schrödinger operators

Let V∈p(Zd) with p1 and write q1=|V|1/2. Note that q1q(Zd) with q=2p2. Chooseq2q(Zd), such thatV=q1q2. The specific choiceq2=q1sign(V) would work, but we shall exploit the freedom to chooseq2differently in the proof of Theorem 4.8 below. Note that for n∈supp(V)=supp(q1), we have q2(n)=

sign(Vn)q1(n).

We say thatf∈L2(Zd) solves theBirman-Schwinger equation atλif

(4.1) f=−q1R0(λ+i0)q2f.

We write σBS(H) =

λ∈RThe Birman-Schwinger equation has a non-zero solution atλ . (4.2)

Note that any solutionf∈2(Zd) of the Birman-Schwinger equation satisfies

(4.3) supp(f)supp(V),

which in particular implies thatσBS(H) does not depend on the choice ofq2. Remark 4.1. In principle one should also consider the Birman-Schwinger equa- tion with the limiting resolvent coming from the lower half-plane, defined by q1R0(λ−i0)q2. This would however give rise to the same Birman-Schwinger spec- trum, so we do not introduce a separate notation. Indeed, choose q2=sign(V)q1, and define a unitary transformation by setting (U f)n=sign(Vn)fn if Vn=0 and (U f)n=fn otherwise. Then

(4.4) q1R0−i0)1q2=Uq2R0−i0)q1U=U

q1R0(λ+i0)q2 U,

which implies that the Birman-Schwinger spectrum does not depend on the choice of limiting resolvent.

Note that since q1R0(λ+i0)q2 is compact, the solution space to the Birman- Schwinger equation (for a given λ) is finite dimensional, i.e., all λ∈σBS(H) are of finite multiplicity.

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Lemma 4.2. For anyλ∈R, we have the limits−limμ0μR0(λ+iμ)=0.

Proof. Letg∈2(Zd) andε>0. Pickδ >0 such that1[|Δ−λ|<δ]gε/2. We may now, for μ∈R with 0<|μ|<εδ/2, estimate μ(Δ−λ+iμ)−1gε. This com- pletes the proof.

Lemma 4.3. We have σpp(H)⊆σBS(H) and the map g→q1g takes nonzero eigenfunctionsHg=λg into nonzero solutions of (4.1)atλ.

Proof. SupposeHg=λg, for some non-zerog∈2(Zd). Putf=q1gand compute (4.5) q1R0(λ+iμ)q2f=q1R0(λ+iμ)(λΔ)g=−q1g−iμq1R0(λ+iμ)g.

Taking the limit μ→0, using Lemma 4.2, we arrive at f=q1g being a solution of the Birman-Schwinger equation (4.1). It remains to argue thatf=0. Iff=0, then V g=0 and consequently, (Δ−λ)g=(H−λ)g=0. This is absurd, since Δ does not have eigenvalues.

The Birman-Schwinger equation with limiting resolvent, has been used pre- viously by Pushnitski [22] to study embedded eigenvalues, in view of the above lemma.

We are now in a position to give:

Proof of Theorem1.5(a). We show that eigenvalues ofHhave finite multiplic- ity. Letλ∈σpp(H) and denote byHλthe associated eigenspace. By Lemma4.3, the linear mapHλg→q1g∈L2(Zd) is injective and takes values in the vector space of solutions of (4.1) atλ. Since this vector space is finite dimensional (q1R0(λ+i0)q2

being compact), we may conclude that the eigenspaceHλis finite dimensional.

In what remains of this section, we shall use the abbreviations (4.6) Y0(z) =q1−z)1q2, and Y0(z) =q2−z)1q2

forz∈Cwith Imz=0. Forλ∈R, we write Y0(λ±i0) andY0(λ±i0) for the limiting objects. By a limiting argument, we observe that the identityY0(z)=sign(V)Y0(z) valid forz∈Cwith Imz=0 extends to

(4.7) Y0(λ±i0) = sign(V)Y0(λ±i0) for anyλ∈R.

We shall single out energiesλ∈R, where the following Lipschitz estimate holds true:

(4.8) ∃L >0∀0< μ1 : Y0(λ±iμ)−Y0(λ±i0)Lμ.

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We write

(4.9) Lip(H) =

λ∈R|(4.8) is satisfied atλ .

Clearly R\σ(Δ)=R\[−d, d]⊆Lip(H), and we may write Lip(H) as in increasing union of subsets

(4.10) Lip(H;L) =

λ∈Lip(H)|(4.8) is satisfied atλwith constantL . The sets Lip(H;L) are closed, since λ→Y0(λ±iμ) are continuous for μ0. It is obscured by the choice of notation, that the sets Lip(H) and Lip(H;L) may depend on the choice ofq2 made in the factorization ofV.

Lemma 4.4. Let L>0 and suppose λ∈σBS(H)Lip(H;L) and f a solution of (4.1). Thenq2f∈D((Δ−λ)1)and(Δ−λ)1q2f2Lf2. Furthermore, (4.11) (Δ−λ)1q2f= lim

μ→0R0(λ+iμ)1q2f.

Proof. Let f∈2(Zd) be a solution of (4.1) at energy λ∈R. Denote by Eq2f

the spectral measure for Δ associated with the stateq2f. Thenq2f∈D((Δ−λ)−1) if and only if

R(x−λ)2dEq2f(x)<. Compute forμ>0

R((x−λ)22)−1dEq2f(x) = (q2f, R0(λ−iμ)R0(λ+iμ)q2f)

= 1 2μ

f,(Y0(λ−iμ)−Y0(λ+iμ))f

= 1 2μ

f,(Y0(λ−iμ)−Y0(λ−i0))f

+ 1 2μ

f,(Y0(λ+i0)−Y0(λ+iμ))f

+ 1 2μIm

f,Y0(λ+i0)f . (4.12)

Note that by the Birman-Schwinger equation (4.1), as well as Eqs. (4.3) and (4.7):

(4.13)

Im

f,Y0(λ+i0)f

= Im

sign(V)f, Y0(λ+i0)f

=Im

sign(V)f, f

= 0.

The result now follows from (4.8), (4.12), and the monotone convergence theorem.

As for the claimed identity, we need to argue that limμ→0R0(λ+iμ)−1q2f= (Δ−λ)1q2f. But this follows from the computation

(4.14) R0(λ+iμ)q2f−−λ)1q2f=iμR0(λ+iμ)(Δ−λ)1q2f, together with Lemma4.2.

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