A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
A. L ORENZI
On elliptic equations with piecewise constant coefficients. II
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 3
esérie, tome 26, n
o4 (1972), p. 839-870
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CONSTANT COEFFICIENTS. II
A. LORENZI
(*)
SUMMARY - In this work we prove an existence and uniqueness theorem for solutions in
W 2, P of second order linear elliptic eqna,tions, whose coefficients are constant- valued in the half-spaces
Rn
andBn
1.
Introduction
and statementof
theproblem.
In this paper we are interested in
solving
a second order linear par- tial differentialequation
ofelliptic type,
whose coefficients are constant-va- lued in thehalf-spaces (x
ERn :
xl >0)
andR1
=~x
E0).
We carry on our
research, begun
in[6],
where square summable solutions with square summable second derivatives are dealt with : in this work welook for solutions in
W2,p (Rn) (1 p + 00).
We recall that(Rn)
denotes the Sobolev space
(1)
of all functions of LP(Rn),
that have deriva- tives in the sense of distributions of the first two ordersbelonging
toW ~~ ~ (R’~)
is a Banach space withrespect
to the norm:Our
equation
isPervennto alla Redazione il 2 Agosto 1971.
(*) Lavoro esegnito con contributo del C. N. R. nell’ambito del Gruppo Nazionale per l’ Analisi Funzionale e le sue Applicazioni.
(~)
For the properties of Sobolev spaces see, for instance,[2]
or[9].
where
aj, arj aT, a- h+,
h-(r, j = 1, 2,
... ,n)
are real constants with ther) ri -i I i I
following properties :
i)
the n X n matrices A+ =(a + )
r) and A- = ri aresymmetric
andpositive definite ;
and f
is anassigned
function in LP(Rn) (1 ~ +
In the
following
we shall be interested in the case n > 3.THEOREM.
Equation (1)
has aunique
solution u E(Rn) for
everyf
E LP(Rn) (1
p+ 00).
There exists a eonstant 0independent of
u suchthat the
following
estimate holds :From the theorem it follows
that, if p
islarge enough (~ ~ n/2),
thesolution is continuous across the
interface Xt
= 0 : ifp > n,
also the flrstderivatives are continuous across the interface.
The method used to prove the existence of the solution consists in
solving
the Neumannproblems
h . f t" .
1-1
Rn
au+ au-where g
is some function in prespectively
the tracesof -
and-2013
Remember that W s, 1)ax1 axi
1 ’for s
>
0 noninteger,
is the space of all functions whichtogether
with allderivatives of order
s (in
the sense ofdistributions)
are in Lr(Rn)
andsatisfy
theinequality
where
[s]
is thelargest integer s. WI, p (Rn)
is a Banach space withrespect
to the norm definedby
the left side of(5).
We observe that W
(Rn)
isexactly
the space of traces of first derivatives of functions inWe shall prove that
problems (3)
and(4)
have aunique
solution. Thenwe shall choose g so that the function u so defined :
is the wanted solution of
(1).
To dothus,
we shall have to solve an inte-gral equation in g :
the solution of such anequation
is obtainedby
inter-polation-techniques.
2. Fundamental
solution
of anoperator with constant coefficients.
In this section we
shall,
for the sake ofconvenience,
denote the va-riables
by (xo ,
xi ... ,(n
~2).
Consider the second order linear differential
operator
with real constant coefficientswhere A = is a
symmetric, positive
definite(n + 1)
X(n + 1)
matrixand h ~ 0.
We shall show some
properties
of the functionthat turns out to be a fundamental solution of Z. In formula
(7)
K (n-l)/2 being
the modified Hanke]function, (2),
abeing
the vector(2) For the properties of Bessel functions see
[11].
For the
following
it will be useful to recall theintegral representation
formula
that is an immediate consequence of known formulas for Bessel functions.
Then,
we should like to call to mindthat,
if.L = d - h2,
the funda-mental solution
(7)
becomes the familiar function(lz ~ x I ).
Moreover,
we observe thatwhere the function is a fundamental so-
lution of the
operator
formula
is
easily proved by using
the(see,
forinstance, [10], appendix)
and theinequalities
(that is valid for all
symmetric, positive
definite(n + 1) x (n + 1)
matricesand for all
vectors a,
x Ev
being
thelargest eigenvalue
of A.(3) (.; > denotes the scalar product in R",
Finally,
we observe thefollowing
estimates for E and thegradient
.DE of
~, that,
inparticular, imply
.E Ewhere p and v are the smallest and
largest eigenvalues
of A andI a I
,On
aregiven respectively by
Estimates
(16)
followimmediately
from(14), (15)
and knowninequalities
for Bessel functions
(see,
foristance, [10], appendix).
The samearguments
I.Annali della Scuola Norm. Sup. di Pisa.
and the formulas
give ~17).
Now we can prove two lemmas :
LEMMA 1. E is a
fundamental
solutionof L,
that isE
W
=egp [- i (x, E)]
E (x)
dx is the Fourier transform of
E.
Rn
LEMMA 2.
If f E
LP(1
p+ 00),
thefollowing properties
hold :i) E. f
E W2, P(Rn+,),
where. denotesconvolution ;
0
being
a constantindepen-
dent
of f.
PROOF OF LEMMA 1 We observe
that,
for(11),
thefollowing
formulais
easily
seen to hold :With the
change
of variables x = where M is a(n + 1)
X(n + 1)
matrix such that
M,
M = A(4),
weget easily
(4)
M 1:
is the transposed matrix of ~,To
conclude,
we rememberthat, if f is
a well-behavedfunction,
the Fourier transformof f (x)
exp is~ f (~ - ia) :
thus the lemma isproved.
PROOF LEmmA 2. To prove the lemma we can suppose
f E Co
From
Young’s inequality
it follows thatthe
integral
of Ebeing
finite on account of estimates(16). Incidentally,
wenotice that Lemma 1 and the obvious fact that E is
negative imply
theequation
The formula
where
and a theorem of H6rmander-Mihlin show that the second derivatives of
are in Ep
(Rn+l)
andthat, taking
into account(21), iii)
is fulfilled.For,
it is easy to see that the functions Tj are,following
H6rmander’sterminology, multipliers
oftype ( p, p)
for every 1p +
oo. For moredetails,
see theappendix
of this paper.Then,
from lemma 1 it follows thatthat is
ii).
The lemma isproved.
For the
following
we need to have theexpression
of the Fourier trans-form of
.E ~t, .),
where we haveput,
for the sake ofconvenience,
x =
... ,
xn) : moreover, ~
will denote the dual variable of xand,
occaa-sionally, Jz
will denote the Fourier transform withrespect
to x.The
following
lemma holds :LEMMA 3. We have
where Zf (E) and z2 (E)
are the roots of theequation
respectively
withnegative
andpositive
realpart
andis the discriminant
(5)?
a(~) and P (~) being
defined as follows :REMARK 1. Observe that the discriminant .~
(~)
has thefollowing properties :
being
astrictly positive constant, I
Moreover,
theroots z, (E) and z2 (E)
have theproperties :
Re;
Re ;
C’ and C"
being positive
constants.For the
proof,
see[6],
lemmas 1 and 3.(5) In this paper the square root of a complex number is the one with non-negative
real part.
REMARK 2. The
function - ’tJl
is a fundamental solution of theoperator
that admits
(23)
as its characteristicequation.
PROOF OF LEMMA 3. From the
properties
ofintegrability
of .E(see inequalities (16))
it follows thatFor lemma 1 and the notations introduced before the statement of lemma
3,
we can writewhere oc
(~) and f3 (~)
are definedby (25), (26).
Applying Cauchy’s
theorem onresidues,
from(30)
and(31)
weget
i. e. the assertion.
’
For the
following,
it will be useful to estimate all the derivatives of 2~: such estimatesimply,
inparticular
that jE7 isanalytic
inLEMMA
4. Let y
be any thenwhere c is defined
by (9),
and C is a constant
independent
of y.PROOF. Leibniz’s rule for the derivative of a
product, inequalities (14), ( 15),
formulas(9)
and(33) imply
that it isenough
to prove thefollowing inequa,lity
where
For the derivation of
(32)
from(34)
it is useful to bear in mind theinequality
Since there exists an
orthogonal (n -~-1)
x(n -~-1)
matrix that maps92
the
quadratic
formr2 (x)
into the canonical form(12 (x) = it
sufficesj=0
to prove
(34)
snbstituted For theintegral
re-presentation
formula(11)
weget
First we prove the
following
estimate:for
In
fact,
since is an entirefunction,
we can write theinequality
where
From the
inequality
valid for we infer that
Hence
(38)
follows from(39) minimizing
withrespect
to r E(o, + cxJ).
Then, (37)
and(38) imply that, for q
E(0,1), denoting ~ 1 by
gUse has been made of the
inequalities I (j
=0,
....n), u being
theIt
smallest
eigenvalue
ofA,
of formula(11)
and the estimates :Then,
the estimate(see,
forinstance, [10], appendix), Stirling’s
formulaand
inequality (41) imply
theassertion, if q
is chosen to beequal
to3.
The Poisson
kernel.In this
section,
and from now on, wedenote,
as in lemna3,
the va-riables
hy (t, x),
where t ER,
x =(xl , .. zn)
Now,
consider the realanalytic
functionM
where E
=(aoo ,
.., aon)
and+ aoo d
is the differentiation j!==lvXj
a ~along
the conormal direction~.
From(7)
and(11)
it follows thatwhere
It is easy to
recognize
from(43)
that P has thesign
of t.From formulas
(18), (19), (20), (43), inequalities (14), (15)
and knownestimates for Bessel functions
(see,
forinstance, [10], appendix),
we inferwhere a is defined
by (18).
(45)
establishes that P E L1(t, .)
E L1 for all t E Randfor all
x E Rn - (0). Moreover,
observe that(13), (20), (43),
imply
thatWe notice
that,
when L-- d, P
coincides with the usual Poisson kernel.Finally,
wepoint
out that the Fourier transform ofP (t~ · )
isgiven by
Indeed,
from(42)
and lemma3, recalling (17)
and(25),
weget
Obviously
P is a solution of theequation
ZM = 0 inio).
Then,
consider the convolutionthe
properties
of which are stated in thefollowing
lemmas :LEMMA
6.
If
g E N~’ ~~ p(0
sp +
thenwhere
and
Ci
and°2
are constantsindependent of
g.Moreover,
v is ananalytic function
in thehalf-space R++l
and is a so-lution
of
theequation
Lu = 0.REMARK 4. From Lemmas 5 and 6 it follows
easily that, if g E
(0 s 1,1
p+ 00), l’ (0 +, .)
= g, where the left side denotes the traceof v,
defined in the usual way.We shall
premise
theproof
of lemma 5 withLEMMA 7. The
function
P has thefollowing properties :
where A is any
positive
number and the constant 0 isinclevendent of
t and A.PROOF OF LEMMA 7.
i)
follows from(46), substituting E
= 0.Estimate
(45) implies
the chain ofinequalities
where C’ is a
constant;
henceii)
iseasily
obtainedby integration.
Now,
we can prove lemma 5: we observe thati)
is an immediateconsequence of
Young’s inequality
on convolution andi)
in lemma 7.In order to show
ii)
weproceed
as follows :It is
evident,
from the definition(22) of V,
that it isenough
to prove thatMaking
useagain
ofi)
in lemma5,
weget
From MinkowskFa
inequality
andii)
in lemma 7 we infer tha,t/y I /p
where A is any
positive
number andw (A = Sup ( 7
xn
tends to 0 as A tends to 0
-)- :
henceii)
follows at once.PROOF OF’ LEMMA 6. The
analyticity
of v is a consequence of the estimateswhere 6 is defined
by (33)
and 0C’ 8
1 :they
follow from(42)
andlemma 4.
Clearly v
is a solution of theequation
Lx(t, x)
= 0 t > 0.For the
proof
ofi)
andii)
it is necessary to observe that(46)
assertsthat
belong
to .L1=1 ... n)
for all t0.
Moreoverat
( ~ ),
ax, ( ~ )
g) (~
, ,)
for all
For,
from theequation
(49) follows, substituting $
= 0. HenceFrom the
identity
we
get
From
(48), (49), (50)
and Minkowski’sineauality
we infer thatwhere and C’ is a constant.
Now we show that
where C" is a constant
depending only
on it, p, s.For,
¡ Minkowski andHolder’s
inequalities yield
thefollowing
chain ofinequalities
where a (d~)
denotes theLebesgue
measureon ] ( =1
andNow, ii)
is an immediate consequence of(52)
and(54)
withC2
=C"C’,
while
i)
follows from MinkowskFsinequality
with measuredt,
ap-plied
to(51)
and from theequation
The constant
Cl
isgiven by
maxps), C21-
4. The Neumann
problem.
Consider the function
Since P
(t, z) > 0,
if t> 0,
it follows thatMoreover,
thefollowing
estimate holds :where a is defined
by (18),
0 0 1 andCe
is a constant.For, (45) implies that,
for every 0 01,
there exists a constant0’
such thatHence
From
(57)
onerecognizes easily
andN (t, .)
E Li(R")
for allt ) 0.
Moreover,
the Fourier transform ofN (t, .)
isgiven by
This follows from
(46)
and the fact that P E Z1(Rn+l).
We remark also
that,
for(48),
N is a realanalytic function,
thatsatisfies the
equation
.LN = 0 inI n
particular,
the coefficients aoj
( j
= 1 ..,n)
and aovanish),
then .~ coincides withand,
’hence,
N with 2E.at
Consider the convolution
The
following
lemma holds:LEMMA then
where C is a constant
independent of g :
Moreover, u
is ananalytic
function in thehalf-space R+ ’
and is a solutionof the
equation
.Lu = 0.PROOF. The
analyticity
of ufollows,
asbefore,
from estimates for the kernel:they
arewhere 5 is defined
by (33)
and0
8 1. For the derivation of(60)
weuse the formula
and estimates
(48)
for the derivatives of P.Clearly
.Lu(t, x)
= 0 if t~
0.To show
i)
itsuffices,
for the usual reasons ofdensity
y to supposeg E 0’ (R n). Young’s inequality
and(58) imply
hence
In order to prove that the second derivatives of 2L with
respect
to x arein we use the
eqnation
where v is defined
by (47)
and(62)
is a consequence of(46), (58)
andi)
in lemma 5: forSince the functions ggj are
multipliers
oftype (p,p)
for every 1[p -f-oo (see proposition
2 inappendix) )
and the functions forii)
in lemma 6ax, with s
= 1 - , satisfy
theinequality
p
then,
there exists a constant 0’ such thatSince
lemma
6
with s = 1- 1 ,
7implies
JP
Therefore,
all the derivatives of u are inL~ (R+ 1) :
moreover, theinequali-
ties
(61), (63), (65), (66)
show that and there exists a constant Cindependent of g
such thatThus,
alsoii)
isproved.
iv)
is an immediate consequence of(64)
and remark 4 after lemma6,
while
iii)
follows from theproperty
that
implies
Hence the trace of
N (t~ · ) ~ g
must coincide withN (o, . ) ~ g.
At last we state the
following
LEMMA Neuntann
proble1n
L
being defined by (6),
admits aunique
solution ugiven by
8. Ant1ali dedda Scuola Norm. Sup di Pisa.
whe)-e
and aw
0 · stands or the trace oaw .
and 20132013
(0, .) for
the traceof
20132013 .(3t
f fat
PROOF. Lemma 2 and remark 3 show that w E
W2,p f,R+’)
and satisfies theequation Lw ~ f. Hence,
for lemma8, ~ 2’ ~ (~+’)
and satisfies theequation
Lu= f
and the condition(0 + , .)
= . 9 atNow we prove that u is the
unique
solution of(67).
Let u be an arbi-trary
function inCo (R+ 1~ : put
Then v is a solution of the
problem
where
a (8) and fl (~)
are definedrespectively by (25)
and(26).
Since from
(70)
we infer that v can berepresented
asfollows:
where Z1 (~)
is the root with realnegative part
ofequation (23), V (t, ~)
isdefined
by (22)
and c(~)
is asuitable $
-function,
that is determinedby
imposing
the condition Weget
hence
From the formula
that is a consequence of lemmas 3 and
4,
we infer,,
iv
being
definedby (69).
Moreover,
for(22)
(58), (71), (72), (73) imply
that u is of the form(68):
sinceC~ (R++l)
isdense in
W 2’r (R+ ~)
theuniqueness
isproved.
5.
Proof of
thetheorem.
The
proof
of the theorem followseasily
from lammas 10 and 11 statedbelow.
Notations: we denote
by respectively
the fundamental solution and the Poisson kernels related with theoperator
.L+ in(1).
Thefunctions .E- and P - are
analogously
defined withregard
to Z- in(1);
while N - is defined as follows:
Moreover,
the functionsa± , ,B± , g ~
are connected withL± , according
toformulas
(24), (25), (26) ; zt and z-
denote the roots of theequations
respectively
withnegative
andpositive
realparts.
LEMMA 10. Let u E W 2, p
(1
p-f- oo)
be a solutionof (1).
Theassertions stated below are true :
i)
thefollowing representation formula
holds :where g is the trace
of
the normal deriva,tiveof
u on thehyperplane
t = 0a,nd
du
12013-F
ii)
g = au(0, .) ...
toW1- p ,p (Rn) of
theintegral
=
t .)
2s a solution1
(Rn) o/’
equation
where
and
1
Vice versa,
if
there exists g E(Rn) (1 p + oo)
thatsatisfies equation (7 7),
then thefunction defined by (75) belongs
toW2,p(Rn+l)
and isa solution
of (1).
The
operator U, defined by (79),
is boundedfi-om
LP intoLMA 11. The
integral equation
~ 1
where N is
defined by (78)
andf
is anygiven function
inW 2 p ’p
1
admits a
unique
solution g EW1- (Rn) (1 C p ~ -~- 00). Moreover,
g veri-fies
theinequality
C
being a
constantindependent of f.
PROOF OF LEMMA 10. Let u be a solution of
(1):
we denoteby
u+ andit-
respectively
its restrictions to and Thenu+
and u- are so-lutions of the Neumann
problems
Lemma
9, applied
to u+ and u-,implies
that u can berepresented
as in(75). Moreover,
from theequation u+ (0 +, .) = u- (0 -, ), (79)
andiii)
inlemma
8,
it followseasily
that g is a solution of(77).
1
Vice versa,
if g
EW 1 ’ (Rn)
is a solution of(77)
and we denote asbefore
by u+
and u the restrictions to and of the function u definedby (75),
lemma 9implies
that u+ and u- are solutions ofproblems (82). Consequently, u
satisfiesequation (1):
it remains to show thatu E W 2, p
( )
Thisproperty
follows from(82)
andequations (0 +, .)
_at
-h ,
at (0 2013. ’)
yu+ (0 +, .) = u- (0 2013, ’):
the former is an immediate con-at
sequence of
iv)
in lemma8,
while the latter isnothing
else but a rearrengement
of(77).
PROOF oF LEMMA 11. The existence of a solution of
equation (80)
1- 11 2013 2013 , p
belonging
to W1
(Rn)
follows from theproperty :
i)
theoperator G,
inverse of the convolution with kernelN,
is abounded
operator
from into is defined forby
theequation
1-1
«There f
and N denote the Fourier transformsof f
and N.The
uniqueness
of the solution is an obvious consequence ofproperty i)
and thefollowing
one:ii)
the convolution with kernel .N is a boundedoperator
from1-1
p2-1
pinto
Both
i)
andii)
can be shownby interpolation, using
a theorem ofHormander- Mihlin and well-known
properties
ofinterpolation
spaces W8, p(Rn) (1
s2).
For the sake ofbrevity
we provei) only.
The
quoted interpolation property (see,
forinstance, [4],
p.399, [5]. chap.
VII2 § 2,
n. 4 or[7]
theor.2.1, 2.8)
follows from the assertions :iii)
theoperator G,
definedby (83),
can be extended with a boundedoperator
fromW 1’p(Rn)
intoiv)
theoperator G
can be extended with a boundedoperator
frominto
Clearly, iv)
follows fromiii),
since G commutes with differentiations.Then we focus our attention on
iii).
Observe that from theequations
it follows that
where z+ and z2
are defined at thebeginning
of this section.We have
where
and
In
appendix
it is shown that M verifies thefollowing inequalities (that
are consequences of theproperties
ofz+
and7
being
any multi-index and0,
some constantdepending
on y.For the theorem of H6rmander.Mihlin
inequalities (84) imply
that M isa
multiplier
oftype ( p, p)
for every 1p +
oo.(For terminology
seeappendix below).
Moreover,
theoperator (1- 4)1’2
is bounded from intoL P (Rn).
This
property,
that can beeasily
seenby
a furtherapplication
of the theo-rem of
Hormander-Mihlin,
y is aparticular
case of a theorem of Calderon on spaces of Besselpotentials La (Rn). Then, property iii)
isproved.
Finally,
the estimate(81)
follows fromi).
APPENDIX
For the convenience of the reader we
recall, following [3],
the definition ofmultipliers
and some criteria that enable to ascertain whether agiven
function is a
multiplier.
-
DEFINITION.
Mq (Rn) (p, q > 1)
is the set of Fourier transforms T of alltemperate
distributions such thatThe elements in
Ml (R~’)
are calledmultipliers
oftype ( p, q).
THEOREM.
([3],
p.120)
Letf E Loo (Rn)
and assume that. n
where B is a constant and k is the least .
Then
f belongs
tofor
every 1 p-E-
oo.In
particular
we shall use thefollowing corollary (Mihlin’s Theorem,
see
[8]).
COROLLARY 1.
If f E
en(Rn
- andfor
where B is a
constants,
thenf E Mp (Rn) for
every 1p -~-
00.We prove
PROPOSITION 1. Let P and
Q
be twopolynomials
in(~, r~) (~
ERn ,
1’) ERm ,
n ¿
1,
m ~1) of
the samedegree
q : let H(~)
=(Hi (~),
... ,H,,, (~))
be a vectorin with that are
po lynomials of degree
2in ~
andsatisfy
thefollowing inequalities :
C’ and C"
being positive
constants.Then the
function
is a
multiplier of type (p, p) for
every 1~ -~-
oo.PROOF. We observe that for
i)
andii)
R is in C°°(Rn).
Moreoverwhere
is a
polynomial
in(~, l3~ ($)1’2 ,
,.. ,gm ($)1’2)
ofdegree
less orequal
to2m + 2q - 1.
CLAIM: for all multi-index y the
following equation
holds:Il., being
apolynomial
in(~, ,g1 (~)1~2 ~
... ,Hm (~~1~’)
ofdegree
less orequal
to17 1(2m + q - 1) +
q.The
proof proceeds by
induction: we suppose that(Al)
is true for ally
with I y I = r
and we show that it is valid for all 7with I r 1 = r + 1, For,
where
Clearly
is apolynomial
in(~, Hi ($)1/2),
...Hm, (~)1/2)
ofdegree
less orequal
to(1 + (2m +
q- 1) -f- q
for thehypothesis
of induction : theproof
of(Al)
is fulfilled.From
(Al)
andi), ii)
and thehypothesis
on P andQ
we infer thatthere exists a constant
0,
such thatFrom
(A2)
and anapplication
ofcorollary 1,
the assertion follows.From
proposition 1, iii)
in remark 1 after lemma3, (29),
the definitions ofz+
andZ2’
the fact that A is asymmetric positive
definite matrix anda± (8),
defined as in(25),
are linear functionsin ~,
there followseasily:
PROPOSITION 2. The
following
functions are in for everyREFERENCES
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