R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
P. N. A NH
Direct products of linearly compact primary rings
Rendiconti del Seminario Matematico della Università di Padova, tome 76 (1986), p. 45-58
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Linearly Compact Primary Rings.
P. N. ANH
(*)
SUMMARY - Numakura [4], [5] gave criterions for
compact rings
to be directproducts
ofprimary rings.
In this note we extend these results tolinearly compact rings. As
a consequence weget
a characterization of thoserings
which are direct
products
of divisionrings,
of uni-serialrings (i.e.
suchartinian
rings
in which the Pk(k
= 1, 2, ... ) are all the one-sided ideals where P denotes theunique
maximalideal)
and ofrings
ofcomplete
discrete valuations on division
rings.
1. All
rings
considered will be associativerings
withidentity.
In what follows denotes
always
aring
and 3 is its Jacobson radical(briefly: radical).
Aring
.R is said to betopologically
artinian ortopo- logically
noetherian if it is the inverse limit of artinian or noetherian left .R-modules endowed with the inverse limittopology.
Atopological ring
.R is calledlinearly compact
if open left ideals form a base forneigh-
bourhoods of zero and every
finitely
solvablesystem
of congruencesx =
xk(mod Lk)
where theLk
are closed leftideals,
is solvable. Remarkthat every
topologically
artinianring
islinearly compact (see [2]
satz
4)
and everycompact ring
istopologically
artinian(see [4]
Lemma
5).
By
a classical result of Artin every artinianprimary ring
is a matrixring
over a localring.
In[3] Leptin proved
that everytopologically
artinian
primary ring
is a matrixring (not necessarily
of finitesize)
over a local
ring.
These results can be considered as ageneralization (*)
Indirizzo dell’A. : Mathematical Institute of theHungarian Academy
of Sciences, Realtanoda u. 13-15,
Budapest,
H-1364,Hungary.
of Artin-Wedderburn Theorem on
simple
artinianrings. Throughout
this note a
primary ring
is understood in a moregeneral
sense thanwhat is usual. We call a
ring primary
if the factorby
its radical is theendomorphism ring
of a vector space over a divisionring.
Nowour purpose is to characterize direct
products
oflinearly compact rings
of some kind.Before
turning
to the main results we need somepreparations.
For every subset .A. of a
topological
space we denoteby
A itstopological
closure. Define for every ideal I of atopological ring
thefollowing
ideals ~if 1 is a limit
ordinal ,
yif A is a limit
ordinal ,
yif I is a limit ordinal.
Then there is an
ordinal 21
for which~1 == 711, I
=I, 1~ == 171
for all~>1’}.
TheseI, 171
will be denotedby *1, I, 1*
and1.*1
=*1,
12 *
= 1,
*1*.1
=1*
holdclearly.
If*1
=0(I* = 0 ) ,
then I is calledl(r -) transf initety nilpotent.
If I =0,
then I is said to betransfinitely nilpotent.
~
PROPOSITION 1
([2] (3)). If
the setof
closedleft
ideals in alinearly compact ring
has thef inite
intersectionproperty,
thenholds
for
every closedleft
ideal A.PROPOSITION 2
([2] Lemma).
For any two(one-sided)
ideals Aand B
of
atopological ring
we haveAB=AB=AB=AB.
PROPOSITION 3
([2]
Satz9).
The radicalof
atopologically
artinianring
isr-transfinitely nilpotent.
PROPOSITION 4
([2] (4)). If A
and B are closed(left)
ideals in a lin-early compact ring,
then A+
B is closed.PROPOSITION 5
([2]
Satz4).
continuousisomorphism
betweentopologically
artinianrings
is atopological isomorphism.
PROPOSITION 6
([3]
Satz1). Every linearly compact
module over asemisimple linearly compact ring
is a directproduct of simple
modules.PROPOSITION 7. Let .A and B be closed
(left)
ideals in alinearly compact
R.If
A+
B = .Rholds,
then we haveA i +
Rtor
everyordinal ~ ~ 1.
PROOF. We prove the assertion
by
transfinite induction.By
the
assumption we
have.A1 + B1
= A+
B = .~.Suppose
thatthen there are elements such that
By2b-b2
cBi
we have+ -~- Bç ==
R. Thisimplies
the existence of elements a* and b* EB~
such that a*+
b* = 1. This shows that(b*)2
= 1 - 2a*+
-f - (a* )2
= 1 - c with c = 2a* -(a*)2
E from which we obtain+ BÇ+1 =
R.If we have now the
equality Ai + Bç
= R for everyordinal $
i~~where Z is a limit
ordinal,
then for each IA A it is true thata,nd
that
is, .Åç + B,~
= 1~ holds forevery ~,
,u Â.Now we have
by Proposition
1 for everyfixed p
Awhich
implies
This
completes
theproof.
PROPOSITION 8..F’or any closed
(left)
ideals A and Bsatisf yiny
A
+
B = .R in alinearly compact ring
= BAimplies
A B =PROOF.
implying
implying
2. A
topological ring
is called offinite type
if the set of all iso-morphism
classes ofsimple
submodules in all factors of anyfinitely generated
discrete R-module is finite. Consider now atopologically
artinian
ring
R. Let be the set of all maximal closed ideals of .R where I is the index set andP~
for i=F j, i, j
E I.In case i
# j by Proposition
4 the idealPi + P3
is closed in .,Rand hence we
get Pi --E--
.R. Therefore we obtain(Pi ) ~ -~- (P;)ç
= 1~for every
ordinal ~ by Proposition
7. Thus(Pi) * + (P,)*
= 1~ holds.Henceforth for any finite set
f(PI) ... , (Pn) *~
we haveby
the Chinese Remainder TheoremPROPOSITION 9. Let .R be a
topologically
artinianring of f inite type.
any i =1=
j, i, j
E I and any limit ordinals~,
~,(Pi)*
= o.i
PROOF. First we obtain , f or
any i =:/= j,
E I and any
ordinals ~
and 21. Weproced by
double transfinite induction.Suppose
that forsome ~
and some fixed 77, we have(Pi)x(Pj)1J
=(Pj)1J(Pi)x
for everyy ~.
Then we haveby Proposition
2and the
associativity
of themultiplication
of idealsif now
(Pi);
=(Pi);
holds for some fixed 1] andevery;
Âwhere A is a limit
ordinal,
then there exists a limit ordinal r such that q = r+
n for some naturalnumber n,
and hence we haveagain by Proposition
2 and theassociativity
of themultiplication
of idealsFinally
welet n
vary andcomplete
theproof
in the same way.Assume now
indirectly that n (Pi)* 0
0. Then there is an elementi
c E R and an open left ideal L with c E
n (Pi)*
andc w L.
Since .R isi
of finite
type,
there arefinitely
many maximal closed idealsPa,
sayPl,
... ,Pn
such that everysimple
submodule of each factor of.R/L
is annihilated
by
some one of them. Consider now the submodule if ofR/L consisting
of those elements which are annihilatedby
...
(Pn) * .
We claim M = Infact,
if then thereexists an element m E such that
(Rm +
issimple,
becauseis artinian. Therefore
(Rm +
is annihilatedby
someP,,
say
Pl.
We obtain nowand
consequently
m E M, which is a contradiction. Thus M =holds. This
implies
thatc ~ .R j.L = 0,
i
i.e.
c E .L,
a contradiction. Thereforen (Pi) * = 0
and theproof
iscomplete.
iAs
(Pi) *
is a closed ideal of thetopologically
artinianring .R,
thefactor
.Ri
=R/(Pi) *
is atopologically
artinianring,
too. We denoteby JB
the directproduct
of theThen R
endowed wita theproduct topology
is atopologically
artinianring. R
istopologically isomorphic to R by
thefollowing proposition.
PROPOSITION 10.
I f Ai (i
EI )
are closed ideals in atopologically
artinian
ring
such that f1Ai
= 0+ Ai
= 0 holdfor
all i0 j;
E
I,
then .R istopologically isomorphic
to the directproduct 11
PROOF.
Taking
themapping
q: .R -* defineby
-
(...,
xi,...)
with xi = x+ (Ai) E .R/Ai
i forevery i E I,
we have ahomomorphism
from R into11
Further = 0implies
xa = 0f or each i E
I,
i. e. hence x = 0.Thus y
is aninjective homomorphism,
and it is clearthat y
is continuous.Finally,
y let(...y~~...)
be any element ofIl RIA j,
thenMi
=== is a coset of the ideal
Ai
i in .1~ where i is the naturalprojection
of R ontoBlAi.
Hence we can express as x,+ .Ai, Taking
any finite number of say 7 wehave
by
the Chinese RemainderTheorem,
hencesince .R is
topopogically
artinian.Choosing
an elementit is obvious that
y(x) = (..., xi, ...).
Thisimplies that y
iEl
is a continuous
isomorphism.
Since R istopologically artinian, by Proposition 5
99 is ahomeomorphism.
Thiscompletes
theproof
of theassertion that .R is
topologically isomorphic
ton RIAI.
PROPOSITION 11. The
rings Ri,
i E I areprimary rings.
PROOF. Let
Pi = .Pi/(.Pi) * .
Then which is thenendomorphisnl ring
of a vector space over a divisionring.
Since theradical of
Ri
is the intersection of all maximal closed ideals which areexactly
theimages
of maximal closed ideals uf .Rby
the natural homo-morphisni
R -.Ri, Pi
isclearly
the radical ofRi.
This means thatthe
rings .Ri (i
EI)
areprimary rings.
The above considerations
yield
thefollowing
THEOREM 12. Let R be a
topologically
artinian Thefollowing
conditions are
equivalent
1)
R is a directpi-oduct of topologically
artinianprimary rings Ri,
i E I.2)
Let E11
be the seto f
all maximal closed ideals in R then theequalities PiPj
=P i(P i)). ==
=hold
for
all i =1=j, i, j
E I and limit ordinals fl, A and R isof finite type.
3)
Theequalities Pi Pi -
I =(Pj)ÂPo
I ==hold
for
all i =1=j, i, j
E I and limit ordinals p,A,
and Ris
of f inite type.
4) Any
ideal Kof
R such that K =K2,
is a unitalring.
PROOF. 1 z--> 2. This
implication
istrivial,
since maximal closedideals in ..R are the
products
of a maximal closed ideal in onecomponent
with the other
components.
For anydiscrete, finitely generated module,
let ... ,
rn)
be agenerator
set of M. The annihilator annR xi of Xiis an open left ideal of
.I~,
and hence it contains almost all There- fore annR(x,,
... , contains almost all.Ri .
This shows that almost allI~i
is contained in the annihilator annr 31 of ~1 and henceforth Mcan be considered as a discrete module over a finite direct sum of
primary rings
sayRl
X ... X Since the set ofisomorphism
classesof discrete
simple
factors ofX Rn
isclearly finite,
.lYl isobviously
of finite
type,
i.e. I~ is of finitetype.
2 ~ 3. This
implication
is alsotrivial,
since A = Bimplies A - B.
3 => 1. This
implication
is the consequence of the fact that Rand R
aretopologically isomorphic.
1 ~ 4. Let ggi denote the natural
projection
of .l~ onto.Ri
foreach i E I. For
gi =
it followsby [6]
Lemma 6.1 that K isthe direct
product
of theKi, i
E I. Since K =~2,
we have.Ki
= Iand hence either
gi
= 0 orRi,
becauseRi
is aprimary ring
and its radical isr-transfinitely nilpotent.
This shows that .K is aunital
ring.
4 => 1. From the
assumption
it followsby Pi = Pi
thatPi
hasan
identity
ei . It is easy to see that isa primary ring.
To come to the end of the
proof
of theimplication
4 => 1 we show For this aim let x be anarbitrary
elementin n P;.
~/
*
iEl
*
Then we have x = xei for each i E I and xc-
(~ Pi =
J. Assumete7
that x is an element of
J,,. By
J = 0 we can considerJ,,IJZ+,
as a
right RfJ-module.
we havex( 1 - ei ) = 0
andhence = 0 where d denotes the
image
of in Thisimplies
thatbelongs
to On the other hand the radical J isr-transfinitely nilpotent
so we have x = 0.Similarly,
toproposition
7it is routine to
verify
thatPi -[- P? ==
.R for everyordinal $ and i =1= j.
6 6
Therefore we have
Pa + P3
= R for all i# j
and thusby Proposi-
tion 10 I~ is
topologically isomorphic
to theproduct
of theprimary rings .Ri
and thiscompletes
theproof
of Theorem 12.If
n
Jn = 0holds,
y we have thefollowing.
COROLLARY 13. Let R be a
topologically
artinianring satisf ying n Jn
= 0. Thef ollowing
assertions areequivalent
direct
product of topologically
artini anprimary rings,
2)
where the setof
maximal closedideals
of
R.3) Q3Qi
whereQi == n P~.
4) Every
ideal Kof
R with K== K2
is a unitalring.
5)
First we prove the
following.
PROPOSITION 14. Let R be a
topologically
artinianring satisf ying n Jn
= 0. any openleft
ideal L there are(not necessaril y different)
maximal closed ideals
P.,,
... ,Pn
withPn
... L.PROOF. Since .L is open, the left R-module is artinian. Be-
cause
(L + In) holds,
y there is a naturaln n
number t with Jt+k
+
L = Jt+
L for everynon-negative integer
k.Hence L contains Jt. The artinian module
.R/(J + L)
can be con-sidered as a left
.R/J-module,
and thenby Proposition
6 it is a iinitedirect sum of
simple modules,
i.e. it is noetherian. Consider the artinian R-module(J+ L) j(J2 + L). By J[(J -~- L)/(J2 + L)]
= 0 it can beconsidered as an
RfJ-module
and henceby Proposition
6 it is a finitedirect sum of
simple
modules. Thus it is noetherian.Iterating
thisprocess in t
steps
weget
that(Jtm + .L) j(Jt + L)
==(Jt-1 + .L)/L
is noetherian. Thus is
noetherian., i.e.,
it has acomposition
serieswhere is
simple.
LetPk
bethe annihilator ideal of
Mk/Mk+1 (k
=1,
...,n),
then thePk
are(not necessarily different)
maximal closed ideals and(Pn ... Pl).R jL
=0,
thus
Pn
...P,
c L. Thiscompletes
theproof
ofProposition
14.PROOF OF COROLLARY 13.
By
Theorem 12 we have 1 => 4 and 1 ~17
1 ~ 3. Next we show 2 ~ 5.Suppose
thatPiPi
=P; Pi
holds for any
i, j
E I. If there were an element 0 ~ c En Qi,
theniEl
we should have an open left ideal L with
c 0
L.By Proposition
14there are maximal closed ideals
P1, ... , Pn
withP1... PnkL.
Thisshows
by Propositions
7 and 8 thatwhich contradicts
c 0
.L.Similarly
we can see that 3 ~ 5.Finally,
y suppose Let FromProposition
iiEI
we
get immediately Qi + P~ _
..R forj.
This showsclearly
that
Pi/Qi
is the radical ofBy
therings .RZ
are
primary rings.
Consider the directproduct
By Proposition
10 we have.R.
Thiscompletes
theproof
of Cor-ollary
13.PROPOSITION 15.
If
in atopologically
artinianring
R theproducts of
any two maximal openle f t
idealscommute,
then so do thoseof
any two maximal closed’icleals,
andRIP
is a divisionring for
each maximal closed ideal P.PROOF. Let .P be a maximal closed ideal. Since P contains the
radical, .R/P
is aprimitive ring, consequently
it is theendomorphism ring
of a vector space over a divisionring.
To show thatR/P
is adivision
ring,
we assumeindirectly
that is theendomorphism ring
of aright
vector space T~ over a divisionring
and the dimension of V’ is at least 2. Hence there is a basis E7}
in V such that the cardinal number of 7 isgreater
than 1. be any two distinct index in I and we define theendomorphisms e and e; by setting
It is obvious that
(.R/P) ei
and ei are two maximal open left ideals in For theendomorphism eij
defindeby
1ve obtain from which it follows that
(RIP)
ei -=
(RIP)
ej.Similarly
we can see that e;.(R/P)
c2 =(RIP)
e~ .Since
(RIP) ci
and(RIP) ei
are two distinct maximal open leftideals,.
we have that their
products
do not commute. This contradicts to theassumption.
Thisimplies
that P is a maximal open left ideal in R and hence thevalidity
of theproposition
is verified.As an immediate consequence of
Proposition
15 andCorollary
13we have
COROLLARY 16. A
topologically
artinianring satisfying (~
In = 0is a direct
product of
localrings if
andonly if
theproducts o f
any two maximal openleft
ideals commute.In what
follows,
let .R be atopologically
artinian localring
satis-fying n
pn = 0 where P denotes its maximal open ideal. We assumethat I~ satisfies the additional condition:
There exists no one-sided open ideal bettveev P and P2.
PROPOSITION 17.
I f
P2 is notopen in P,
then P = 0.PROOF. For any open left ideal L in P the left ideal p2
+
L is open and it holds+
L:) P2. Hence P2+
L = P. This show s that P2 iseverywhere
dense inP,
so P2 = P is true.By
induction weget
Pn - P. Theref ore P =n
p-n = 0.PROPOSITION 18.
~==1~2~...} forms a fundamental system of neighbourhoods of
zero.PROOF. Let L be any open left ideal in .R. Since E = E
+ + (n P.-) - n (L + Pn)
and is an artinianmodule,
there isan
integer n
with pn k L. This meansby [4]
Lemma 6 that L is apower of .P.
(Note
that in this case Pk is a union of translates of Pt for everyt ~ k). Suppose
now Pn = 0 for some n, and let k be the leastinteger
with thisproperty,
i.e. Pk =0,
0. we prove that R is artinian in this case, or in otherwords,
0 isipen.
Infact,,
since allllon-zero open left ideals are powers of P
containing Pk-1, they
cannot form a fundamentalsystem
ofneighbourhoods
of zero, hence 0 must also be open.PROPOSITION non-zero one-sided ideal
(closed
ornot)
in R coincides with some
R),
n =0, 1, 2,
....PROOF. Let 0 ~ .R be any left ideal in R and 0 ~ c E L. The .Rc is a closed left ideal in 1~. This
implies
Re = Rc+ (n Pn) -
-
n (Rc + Pn).
Since+
Pn is Open, Rc+
Pn = Pkn for each n.By 0,
0 there exists aninteger t
with .Rc = Pt. There- fore L is open and henceby
theproof
ofProposition
18 .Lequals a
power of P.
By
theassumption
it is easy to see that R istopologically
artinian from the
right,
too.By symmetry
the assertion ofPropo-
sition 19 is true.
THEOREM 20. Let .R be a
topologically
ai-tinian localring satisfying n F
= 0 and suppose that there exists no one-sided ideal between P and 1’’ where P denotes its maximal non-zero open ideal. Then R hasno zero-divisors
i f
andonly if pn =F-
0for
each ~2.PROOF. The
necessity
is obvious.Conversely, by Proposition
19 there is an element a contained in P but not inP2,
and then P = Ra = oR andby
induction Pn = anR == If x
and y are
non-zero elements in.R,
then there areintegers k,
I such that X EPk+l, y
E Thus it follows that wecan express x and y as :x = 2’a where 2c, v must be units in R.
Therefore xy = uakrai l =
uv1ak+z
where v, is a unit with theproperty
= ak r. This
implies xy =F
0.If a and b are any two non-zero elements of
R,
from theproof
ofTheorem 20 and
by Proposition
19 we have Ra =Pk,
Rb = P’ forsome
integers k,
Z. Hence a, b have a common leftmultiple
c= b,a
== al b = o. By
Ore’s well-known result one can now construct aquotient
divisionring
d of R whose elements are thequotients
a-1 b.’we define the
following
valuations v on .R: _+
oo; if is any element ofR,
then there is aninteger it
with a EPn+’,
and let
v(a)
= n. It is routine to check that v defines a discrete valuation on .R in the sense of[1] Chap.
VI. In the classical way wecan extend v to 4 and it is easy to see that v is a discrete valuation
on d. We show that R is the
ring
of the va,luation v on 4. Infact,
let x = be any element of 4 which is not contained where
a, b
E R. Then we can b = cl t for c E P -P2,
andu, t
units in .~. Since andv-1, u
ER,
we have k l. Hence x-1 = = zc-1 cl-k t E ..R. Since R iscomplete,
d iscomplete
in thetopology
inducedby
v.From the above we have
THEOREM 21. Let .R be a
linearly compaet
localring satis f ying n
7 = P denotes its maximal open ideal. Thefollowing
con-.ditions are
equivalent.
1)
0for
each n and there exi sts no one-sided ideal between.P and P2.
2 )
.R is thering o f
acomplete,
discrete valuation on a divisionring.
THEOREM 22. Let .R be a
linearly compact ring
withn
In = 0-R is a direct
prod2cct of rings of complete,
discrete val2cations on divisionrings, of
local uni-serialrings,
andof
divisionrings if
andonly if
theproducts of
any two maximal openleft
ideals commute and there existsno one-sided open ideal between P and P2
for
each maximal open ideal Pof
.R.In what follows we shall
investigate topologically
noetheria,nlinearly compact rings.
First we proveTHEOREM 23. A
linearly compact ring
R istopologically
noetherianin the
equivalent Leptin-topology if
andonly if *J
=0,
i.e. its radical isl-transfinitely nilpotent.
PROOF. Assume that .R is
topologically
noetherian. For any open left ideal .L of R we haveJ[(*J + L) /L] _ (*J + L) IL
and henceby Nakayama’s
Lemma we have( *J ~ L)IL
=0, consequently
and therefore
*J =
0.Conversely
if*J = 0,
then we proveby
induc-tion that
R/ tiJ
istopologically
noetherian for every ordinal p from which the statement followsclea~rly.
For p = 1 the assertion is ob- vious. If istopologically noetherian,
then can be con-sidered as
R/J-module
and hence it isobviously topologically
noetherianin the
Leptin-topology.
Therefore issuch,
too. If  is a limitordinal and is
topologically
noetherian for all pÂ,
thereis the inverse limit of
RIIJ
istrivially topologically noetherian,
too.This
completes
theproof.
A
topological ring
.R is called ofcofinite type
if the set of all iso-morphism
classes ofsimple
factors of all submodules in anyfinitely generated
discrete R-module is finite.Similarly
toProposition
9 wecan prove the next statement.
PROPOSITION 24. Let R be a
topologically
noetherianlinearly
com-pact ring of cofinite type. If
the set~Pi :
ic.11 of
all maximal closedideals in R
satisfies tPiPj === Pj Pi,
I and(P,),a(Pi)e
===
for
anyj, i, j
E I and any limit ordinalsE,
A, thenr* (Pi ) =
o.iEl
PROOF.
Similarly
toProposition
9 we obtain =for
any i
=1=j, i, j
E I and anyordinals ~
and 27. Assume nowindirectly
that Then there is an element c E .1~ and an open left ideal L with c E
n *(Pa)
andc í L.
Since .R is of cofinitetype,
therei
are
finitely
many maximal closed idealsPi ,
sayPi ,
... ,Pn
such thatevery
simple
factor of each submodule inRfL
is annihilatedby
someone of them.
By
Zorn’s Lemma there exists a minimal submodule if ofBIL
such that is annihilatedby *(Pl)
...*(Pn).
We claim~l’ = 0. In
fact,
if then M as a submodule of the noetherian moduleBIL
isfinitely generated.
Therefore M. Sincecan be considered as a module over
.R/J,
it is a finite direct sum ofsimple
R-modulesby Proposition
6. Thus there is a submodule N of such that is annihilatedby
somePi,
sayPi .
Henceforthwe obtain now
which contradicts to the
minimality
of M. Thus = 0 holds. Thisimplies by c
E c*(P1)
...*(Pn)
that =0,
i.e. c EL,
whichi
is
impossible.
Thereforen *(Pi) =
0 and we are done.i
Consider now a
topologically
noetherianlinearly compact ring
.Rsatisfying
the condition ofProposition
24. In the case i~ ~ by Proposition
4 the ideal.Pi + Pi
is closed in .I~ and hence w eget Pi + -E-
.R.Similarly
toProposition
7 we obtain~(P~) + ~(P9)
= Rfor every
ordinal ~.
Thus*(PE) + *(P9) _ .R
holds. Henceforth for any finite set*(Pn)~
we haveby
the Chinese Remainder TheoremAs
*(Pi)
is a closed ideal ofR,
the factorring
= is atopo- logically
noetherianlinearly compact ring,
too.Similarly
toProp-
osition
11,
one can see that therings .Ri
areprimary rings.
As it wasdone in
Proposition 10,
we can prove that R isisomorphic
to the directproduct n Ri
and thisisomorphism
iscontinuous,
but ingeneral,
itis not a
topological isomorphism. Furthermore,
thetopology
in~ .I~i
induced
by
this continuousisomorphism
isequivalent
to theproduct topology.
Therefore thisisomorphism
istopological
if we endow .Rwith the
equivalent Leptin-topology.
Thus theproof
of thefollowing
theorem is similar to that of Theorem 12 and hence we omit it.
THEOREJB’I 24. Let R be a
topologically
noetherianlinearly compact 1’ing
endowed with theequivalent Leptin-topology.
Thefollowing
conditionsare
equivalent.
1 )
R is a directproduct of topologically
noetherianlinearly compact primary ring .Ri .
2)
.R isof cofinite type
andif (P, :
i EI}
is the setof
all maximal closed ideals in.R,
then theequalities
=P? Pi ,
(P;)a~ (Pi),~
holdfor
all i =1=j, i, j
E I and limit ordinals ,u, A.3)
R isof cof inite type
and theequalities ,
j
E I and limit ordinals p, A.4) Any
ideal Kof
R such that K = K2 is a unitalring.
ACKNOWLEDGEMENT. I express my sincere thanks to Professor A.
Orsatti and the referee for many remarks and much
helpful
advice.REFERENCES
[1] N. BOURBAKI, Commutative
algebra, Addison-Wesley,
1972.[2] H. LEPTIN, Linear
kompakte
Moduln undRinge,
Math. Z., 62 (1955), pp. 241-267.[3] H. LEPTIN, Linear
kompakte
Moduln undRinge,
Math. Z., 66(1957),
pp. 289-327.
[4] K. NUMAKURA,
Theory of
compactrings
I, Math. J.Okayama
Univ., 5 (1955), pp. 79-93.[5] K. NUMAKURA,
Theory of
compactrings
II, Math. J.Okayama
Univ., 5 (1956), pp. 103-113.[6] K.
NUMAKURA, Theory of
compactrings
III,Compact
dualrings,
DukeMath. J., 29 (1962), pp. 107-123.
Manoscritto pervenuto in redazione il 6 dicembre 1984.