C OMPOSITIO M ATHEMATICA
L UC D UPONCHEEL
Non-archimedean (uniformly) continuous measures on homogeneous spaces
Compositio Mathematica, tome 51, n
o2 (1984), p. 159-168
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159
NON-ARCHIMEDEAN
(UNIFORMLY)
CONTINUOUS MEASURES ON HOMOGENEOUS SPACESLuc
Duponcheel
Compositio Mathematica 51 (1984) 159-168
© 1984 Martinus Nijhoff Publishers, The Hague. Printed in The Netherlands
1. Introduction
Let Wbe a
complete
non-archimedean valued field. Let G be alocally compact
zerodimensional group. If G has an opencompact q-free
sub-group,
where q
is the characteristic of the residue class fieldof MT ,
thenfor every closed
subgroup
H of G thehomogeneous
space of all left cosets of H in G has a Jsvaluedquasi-invariant
measure IL(see [4]).
LetM~(G/H)
be the space of all measures onG/H.
In this paper we will prove thefollowing
result : an element À ofM~(G/H)
translates continu-ously
for thestrong (resp. weak) topology
onM~(G/H)
if andonly
ifX = fp
wheref
is a boundeduniformly
continuous(resp. continuous)
function on
G/H.
Il. Functions and measures
Let W be a
complete
non-archimedean valuedfield.
Let X be alocally compact
zerodimensional space. LetBc(X)
be thering
of all open compact subsets of X. If A is an element ofBc(X)
then03BE(A)
will be the Jsvalued characteristicfunction
of A. LetBC(X)
be the space of all bounded continuous -X’-valued functions on X. With thenorm ~f~
=:supx~X|f(x)|, (lE BC(X)), BC(X)
becomes a non-archimedian Banach space over With theseminorms px(f) =: |f(x)|, (f ~ BC(X); x ~ X), BC(X)
be-comes a non-archimedean
locally
convex space over K. Thetopology (resp. uniformity)
onBC(X)
inducedby
thenom 1 will
be called theuniform topology (resp. uniformity).
Thetopology (resp. uniformity)
onBC(X)
inducedby
the seminorms px(x
EX)
will be called thepointwise topology (resp. uniformity).
LetBUC(X)
be the space of all boundedU-uniformly
continuous K-valued functions on X where U is a non-archi- medeanuniformity
on Xcompatible
with thetopology
on X. LetCoo( X)
be the space of all continuous Y-valued functions on X which vanish at
infinity.
BothBUC(X)
andC~(X)
aresubspaces
ofBC(X).
In the sameway as
BC(X), BUC(X)
andC~(X)
can be made into a non-archi- medean Banach space and alocally
convex space over K. LetM~(X)
bethe space of all bounded additive K-valued functions on
Bc(X).
Theelements of
M~(X)
will be called measures on X. With the norm~03BB~=:supA~B(X)|03BB(A)| (03BB ~ M~(X)), M~(X)
becomes a non-archi-medean Banach space overy.
(M~(X), ~ ~)
is thedual space
of(C~(X), Il ~).
Theduality
isgiven by
Let À be an element of
M~(X).
If for every x in X we defineN03BB(x)
=:infA3x supB~A|03BB(B) 1 then
for every A inBc(X)
we havesUPBcAIÀ(B)1 = supx~AN03BB(x).
Inparticular
we have~03BB~
=supx~XN03BB(x).
With the semi-norms
qx(03BB)
=:N03BB(x) (x ~ X, 03BB ~ MI(X», M~(X)
becomes a non-ar-chimedean
locally
convex space overJf. Thetopology (resp. uniformity)
on
M~(X)
inducedby
thenorm ~~
will be called the strongtopology (resp. uniformity).
Thetopology (resp. uniformity)
onMI(X)
inducedby
theseminorms qx (x
EX)
will be called the weaktopology (resp.
uniformity).
If À is an element of
M~(X)
and g is an element ofBC(X)
we candefine an element
gÀ
ofM’(X) by setting:
It is not difficult to see that
Ng03BB(x) = |g(x)|N03BB(x).
III. PROPOSITION
(1):
Let 03BB be an element01 MOO(X)
withinlxExNÀ(x) ’;i:.
m > 0. The
map g ~ g03BB is a
linearhomeomorphism from BC(X)
with theuniform (resp. pointwise) topology
onto a closedsubspace of M~(X)
withthe
strong ( resp. weak) topology.
PROOF: It is clear
that
the mapg ~ g03BB
fromBC(X)
with the uniform(resp. pointwise) topology
toM~(X)
with thestrong (resp. weak) topol-
ogy is a linear
homeomorphism.
Weonly
need to prove that itsimage
isclosed.
For the the uniform
topology
onBC(X)
and thestrong topology
onM~(X) this is
trivial.For the
pointwise topology
onBC(X)
and the weaktopology
onM~(X)
this runs as follows: let(f03B103BB)03B1~I
be a net inM~(X) converging weakly
to jn. It is clear that the net(f03B1)03B1~I in BC(X)
convergespointwise
to a
function f.
We have161
Therefore
From the
inequalities (1)
and(2)
it is easy to conclude that1 E BC(X).
(Notice
that the functionNf(x)03BB-03BC
isuppersemicontinuous
andNf(x)03BB-03BC(x)= 0).
Nowand we may conclude that p
= f03BB
and we are done.IV.
Groups
andhomogeneous
spacesLet G be a
locally compact
zerodimensional group. For every open compactsubgroup K of G
we can define anequivalence
relation on Gby setting:
Using
thoseequivalence
relations we can define the so calledleft (resp.
right)
groupuniformity
on G which iscompatible
with thetopology
on G.Let
BL UC( G ) (resp. BR UC( G ))
be the space of all boundedleft (resp.
right) uniformily
continuous K-valued functions on G. Iff
is an element ofBC(G)
and s is an element ofG,
we can define an elementRsf (resp.
L,f )
ofBC(G) by setting:
If
f
is an element ofBC(G)
then the functions s -LS f
and s ~Rsi
fromG to
BC( G )
are continuous for thepointwise topology
onBC( G ).
An
element f
ofBC(G)
is an element ofBLUC(G) (resp. BRUC(G))
if and
only
if the function s ~R s f (resp. s
~LsI)
from G toBC( G )
iscontinuous for the uniform
topology
onBC( G ).
It isimportant
to noticethat
C~(G)
is asubspace
ofBLUC(G) (resp. BRUC(G)).
Let H be a closed
subgroup
of G. LetG/H
be the set ofall left
cosetsof H in G. Let 77: G ~
G/H
be the naturalquotient
map from G toG 1 H.
With the
quotient topology G/M
also becomes alocally compact
zerodi- mensional space. G has an action onG 1 H by setting:
For every open
compact subgroup
K of G we can define anequivalence
relation on
G/H by setting:
Using
thoseequivalence
relations we can define the so calledhomoge-
neous
uniformity
onG 1 H
which iscompatible
with thetopology
onG 1 H.
Let
B UC( G/H )
be the space of all boundeduniformly
continuous Jsval- ued functions onG/H.
Iff
is an element ofBC( G/H )
and s is anelement of G we can define an element
Lsf of BC( G/H ) by setting:
If
f
is an element ofBC( G/H )
then the function s~ Lsf
from G toBC(G/H)
is continuous for thepointwise topology
onBC(G/H).
Anelement
f of BC( G/H )
is an element ofBUC(G/H)
if andonly
if thefunction
s ~ Lsf
from G toBC(G/H)
is continuous for the uniformtopology
onBC(G/H).
It isimportant
to notice thatC~(G/H)
is asubspace
ofBUC(G/H).
V.
Quasi-invariant
measures onhomogeneous
spacesLet G be a
locally
compact zerodimensional group. Let H be a closedsubgroup
of G. LetG/H
be thehomogeneous
space of all left cosets of H in G. We suppose that G has an opencompact q-free subgroup where q
isthe characteristic of the residue class
field
of :f. In that case G has aninvariant measure m. H also has an invariant measure n. Let à be the modular
function
on G. Let 03B4 be the modularfunction
on H. Letf
be anelement of
C~(G).
We can define anelement fb
ofC~(G/H) by setting:
The
map f~fb
fromC~(G)
toC~(G/H)
is linear and continuous andusing duality
we can define a linear and continuousmap 03BB ~ 03BB#
from163
M~(G/H)
toM~(G).
We have:For every s in G we have
NX(7T(s»
=N03BB#(s).
A
quasi-invariant
measure onGIH
is a measure Il such thatti’
= pm,where p is an invertible element of
BRUC(G).
Such a measure doesalways
exist and it isunique
up to an invertible element ofB UC( G/H ).
We can even say more: for every open
compact subgroup
K of G thereexists a
quasi-invariant
measure p onG/H
with03BC#
= pmwhere Ipl
~ 1and p is constant on the
right
cosets of K(see [4]).
VI.
(Unif ormly)
continuous measuresLet À be an element of
M~(G/H)
and s an element of G. We can definean
element 03BBs
ofM~(G/H) by setting:
An element À of
M~(G/H)
is called a continuous(resp. uniformly continuous)
measure if the function s -Às
from G toM~(G/H)
isweakly (resp. strongly)
continuous.It is clear that the function s ~
Às
from G toM~(G/H)
isweakly (resp. strongly)
continuous if andonly
if the function s ~(03BB#)s
from Gto
MOO( G)
isweakly (resp. strongly)
continuous. In order to find the continuous(resp. uniformly continuous)
measures onG/H
it suffices to find the continuos(resp. uniformly continuous)
measures on G.Let
(Ka)aEI be a
fundamentalsystem
of opencompact q-free
sub-groups of G. We can define functions
(u(K03B1))03B1~I
from GtoJfby setting
VII. PROPOSITION
(2):
Let À be an elementof MOO( G).
Let m be aninvariant measure on G. X is a
uniformly
continuous( resp. continuous)
measure
if
andonly if À
=fm for
some elementf of BRUC(G) (resp.
BC(G)).
PROOF:
(1)
If À= fm
for someelement f
ofBRUC(G) (resp. BC(G))
thenthe
function s ~ 03BBs
from G toMOO(G)
isstrongly (resp. weakly)
continu-ous as can
easily
be verified.(2) Suppose
now that the function s-+ À s
from G toMOO( G)
isstrongly
(resp. weakly)
continuous. Forevery f in C~(G)
we can define an elementf
* À ofM~(G) by setting:
We will prove that
u(K03B1)*03BB
convergesstrongly (resp. weakly) to 03BB. (*)
From this it follows
(using Proposition 1)
that it suffices to prove that for everyf
inC~(G)
there exists an element F ofBRUC(G) (resp.
BC(G)) with f
* À = Fm. DefineIt is clear that F is an element of
BRUC(G) (in particular
it is an elementof
BC( G )).
Let g be an element ofC~(G).
165
and we may conclude that
f
* À = Fm. We still need to prove( * ):
- For the
strong topology
this runs as follows:Using
theinequality
we see that
- For the weak
topology
this runs as follows:and we see that
thus
Using
theinequality
we may conclude that
and we are done.
VIII. REMARK: The
function f of
theforegoing proposition
is theuniform ( resp. pointwise)
limitof
thefunctions (F03B1)03B1~I defined by:
PROOF: À =
lim03B1~Iu(K03B1)*03BB
=lim03B1~IF03B1m
=(lim03B1~IF03B1)m
withIX. THEOREM: Let À be an element
of MOO(GIH).
Let 03BC be aquasi-in-
variant measure on
G 1 H. À
is auniformly
continuous(resp. continuous)
measure
if
andonly if À
=f ju for
some elementof f of BUC(G/H) ( resp.
BC(G/H)).
PROOF: Let p be the invertible function of
BR UC( G )
with03BC#
= p m . Thefunction s
~ 03BBs
isstrongly (resp. weakly)
continuous if andonly
if thefunction s -
(03BB#)s
isstrongly (resp. weakly)
continuous.(a)
If the functions ~ (03BB#)s
from G toM~(G)
isstrongly (resp.
weakly)
continuous there exists an element g ofBR UC( G ) (resp. BC( G ))
with
03BB#
= gm. It is easy to see that À= f03BC where f(03C0(s))
=:[g(s)/p(s)]
isan element of
BUC(G/H) (resp. BC(G/H)).
(b)
If there exists anelement f of B UC( G/H ) (resp. BC(G/H))
withÀ
= f03BC
then it is easy to see that03BB#
= gm whereg(s)
=03C1(s)f(03C0(s))
is anelement of
BRUC(G) (resp. BC( G ))
and therefore we see that the function s ~(03BB#)s
from G toM°°(G)
isstrongly (resp. weakly)
continu-ous.
167
X. REMARK: The
function f of
theforegoing
theorem is theuniform ( resp.
pointwise)
limitof
thefunctions (Fa) a E 1 defined by:
PROOF: Let v be a
quasi-invariant
measure onG/H
withv#
= pm whereIpl = 1
and p is constant on everyright
coset of everyK03B1(03B1~I).
IfÀ = gv then g is the uniform
(resp. pointwise)
limit of the functions(G03B1)03B1~I
whereNow
and
so we may conclude that
If
03BC = hv
for some invertible element h ofBUC(G/H) then,
in thesame way, h is the uniform limit of the functions
(H03B1)03B1~I
whereIf 03BB=f03BC=(g/h)03BC
then we see thatf
is the uniform(resp. pointwise)
limit of the functions
(Fa)aEJ
whereand were are finished.
XI. Final remark
The most
important
results of this paper can be reformulated as follows:Let IL be a
quasi-invariant
measure onGIH.
The mapf ~ f03BC from BUC(GIH)
with theuniform topology (resp. BC(GIH)
with thepointwise topology)
toM~(G/H)
with the strong(resp. weak) topology
is a linearhomeomorphism
onto a closedsubspace of MOO(GIH).
Thissubspace
consists
exactly of
those measures wich translatecontinuously for
the strong( resp . weak) toplogy
onMOO(GIH).
We can
always
find aquasi-invariant
measure IL onGIH
withNp.
~ 1.In that case the map
f ~ f03BC
fromBUC(G/H)
toM~(G/H)
is a linearisometry.
References
[1] A.C.M. VAN ROOIJ: Non-archimedean Functional Analysis, Marcel Dekker, Inc., New York and Basel (1978).
[2] N. BOURBAKI: XXIX, Elem. de Math., Livre IV, Intégration chap. 7 et 8, Hermann, Paris (1954).
[3] L. DUPONCHEEL: Non-archimedean Induced Representations and Related Topics, Thesis (1979).
[4] L. DUPONCHEEL: Non-archimedean quasi-invariant measures on homogeneous spaces.
Indag. Math., Volumen 45, Fasciculus 1 (1983).
(Oblatum 26-1-1981) Department Wiskunde Vrije Universiteit Brussel Pleinlaan 2, F7 1050 Brussel
Belgium