C OMPOSITIO M ATHEMATICA
W. H. S CHIKHOF
Non-archimedean representations of compact groups
Compositio Mathematica, tome 23, n
o2 (1971), p. 215-232
<http://www.numdam.org/item?id=CM_1971__23_2_215_0>
© Foundation Compositio Mathematica, 1971, tous droits réservés.
L’accès aux archives de la revue « Compositio Mathematica » (http:
//http://www.compositio.nl/) implique l’accord avec les conditions géné- rales d’utilisation (http://www.numdam.org/conditions). Toute utilisation commerciale ou impression systématique est constitutive d’une infrac- tion pénale. Toute copie ou impression de ce fichier doit contenir la présente mention de copyright.
Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
215
NON-ARCHIMEDEAN REPRESENTATIONS OF COMPACT GROUPS
by W. H. Schikhof
Wolters-Noordhoff Publishing Printed in the Netherlands
Introduction
In
[7 ] Monna
andSpringer
introduced anintegration theory
in whichthe scalar field was a field Kwith a non-archimedean valuation. In
[10] a
non-archimedean Fourier
theory
has beendeveloped, mostly
for abeliangroups. This paper deals with continuous
representations
oflocally
com-pact
groups G into non-archimedean Banach spaces.It is an easy exercise to show that in order that G has
sufficiently
many of suchrepresentations
G must be 0-dimensional. Like in the ’classical’case, a
general
treatment appears to beextremely
difficult. As a firststep, however,
this paper tries to show that the n.a.representation theory
forcompact
groups is at least as smooth as the ’classical’theory.
One canprove non-archimedean
analogues
of thePeter-Weyl
Theorem andthe Tannaka
Duality
Theorem. Adisadvantage
is the lack of Hilbert spaces in the non-archimedean situation. In this paper we do introducea sort of a non-archimedean Hilbert space
(0.2),
but still some work isinvolved to show that an invariant
subspace
has an invariantcomplement.
(Lemma 4.2).
On the otherhand,
thegeneralized
Fourier transformation is anisometry,
whichphenomenon
does not occur in the classical situa- tion.(4.10).
Since a 0-dimensionalcompact
group G isprojective
limitof finite groups, it will not come as a
surprise
to the reader that our basic tools are Maschke’s Theorem and theorthogonality
relations of re-presentations
of finite groups. Infact,
we will show that’unitary’
repre- sentations of G into n.a. Hilbert spaces over K have very intimate re-lationships
withrepresentations
of finite groups into vector spaces over the residue class field of K(5.1
and5.2).
As to a treatment of represen-tations for
locally compact
groups, theonly
result is in fact Theorem 3.1which shows that there is a 1-1
correspondence
betweenrepresentations
of G and
of L(G).
The nextstep
should be some sort of a Gelfand-Raikov Theorem. The classicalproof involves positive
functionals and the Krein- Milman Theorem and a direct translation of thisproof
seems to beimpos-
sible. For the ’classical’
theory
ofrepresentations
we refer to[2].
0. Preliminaries
Let K be a
complete
non-archimedean valued field. The valuation issupposed
to be non-trivial. A(K-) Banach-space
is a K-vector spaceE, together
with a real-valuedfunction ~ ~,
defined onE,
such thatfor
all 03BE, ~
EE, Â
EK,
and such that E iscomplete. By 1 IEI ~ and |K|
wemean
Um ~ ~,
resp.Im |I .
A collection
(e03B1)03B1~I
in E is called orthonormal if for all finite subsets J c Iwe have
An orthonormal set
(e03B1)03B1~I
is called an orthonormal basis in case its linear hull is dense in E. Thenevery 03BE
E E can be written as aconvergent
sumwhere
Two
subspaces S,
T are calledorthogonal
in case forevery 03BE
ES,
YI E T wehave
In 4.7 we need the
following
0.1 LEMMA. Let E be a Banach space, let
(e03B1)03B1~I, (f03B1)03B1~I
be subsetsof
Eand
E* respectively. Suppose ~e03B1~
~1, ~f03B1~
~ 1for
all oc andwhere |d03B1|
= 1. Then(e03B1)
and(f03B1)
are orthonormal.PROOF. Let
f
=03A303BB03B1f03B1(03B1
EK). Clearly 1 if 11 |
~max |03BB03B1|.
Conversely 1 Ifl ~ ~f(e03B1)~/~e03B1~ ~ ~f(e03B1)~ (
=|03BB03B1|
for all oc. A similarproof
works for thee03B1’s.
The
following concept
of non-archimedean Hilbert spaces, due to vander Put is different from that of Kalisch
[5].
Wegive
the statements with-out
offering
theproofs.
Most of them areunpublished
results of vander Put. Some
proofs
can be found in[8].
0.2. DEFINITION. Let E be a Banach space
with ~E~ = |K|.
E is calleda n.a. Hilbert space
if
oneof the following equivalent
conditions issatisfied.
(i) Every
closedsubspace
has anormorthogonal complement.
(ii)
For every closedsubspace
S’ c E there is aprojection
Pof
E ontoS with
JIPII
= 1.(iii) Every
orthonormal set can be extended to anorthonormal
basis.(iv) Every
maximal orthonormal set is an orthonormal basis.Before
giving
a classification of n.a. Hilbert spaces we introduce a Iresidue classspace’
as follows. Let E be a n.a. Hilbert space.Then
É
={03BE
E E :~03BE~
~1}/(03BE
E E :~03BE~ 1}
is in the obvious waya vector space over the residue class field k of K. A
K-linear map ~ :
E ~ Fwith
~~~
~ 1 defines in a natural way a k-linearmap ~ : E ~ F.
Theassignment
E 1-+E
is functorial. A set(e03B1)03B1~I ~
E is orthonormal if andonly
if(e03B1)03B1~I
forms anindependent
set. From this we can see that finite dimensional K-vector spaces with an orthonormal basis are n.a. Hilbert spaces. It is also easy toverify
that every K-Banach space E with1 IEI
=IKI
over a discrete valued field is a n.a. Hilbert space. Withoutproof
wemention that every n.a. Hilbert space is one of the above
types.
Note thatsubspaces, quotient
spaces, and finitedirect
sums of n.a. Hilbert spa-ces are n.a. Hilbert spaces. In 5 we need the
following
lemma.0.3 LEMMA. Let
E,Fbe
n.a. Hilbert spaces.Let 0 :
E - F be a K-linearmap with
~~~
~ 1. Then(i) ~ =
0iff ~~~ 1,
(ii) ~
isbijective iff ~
is asurjective isometry.
PROOF. Left to the reader.
A n.a. Banach
algebra
over K is a Banach space A overK, together
witha
multiplication
such that A becomes aK-algebra
and suchthat 1 lfgl
~~f~ ~g~ for all f, g E A.
We willsay that
a net(u03B1)03B1~I
isan approximate identity
for Aif 1 lu,,, 11 I
~ 1 for all a andlim fu03B1
= limu03B1f
=f
for allf ~ A.
1. G-modules and A-modules
Throughout
this paper G is alocally compact
0-dimensional group withidentity e
and Kis acomplete
non-archimedean valued field. The valuation issupposed
to be non-trivial.1.1. DEFINITION. A G-module is a Banach space
E, together
with a map 03C4 : G E ~ E(written
as(x, 03BE)
F-+x03BE)
such that(i)
i isseparately
continuous and linearin ç
(iii)
there is M > 0with /1 xC; 1
~M~03BE~,
for all x, y E
G, 03BE
E E.If we
put Ux(03BE)
=x03BE,
we obtain a bounded and astrongly
continuousrepresentation x
HUx
of G with E as arespresentation
space.Conversely,
a bounded and
strongly
continuousrepresentation
of G withrepresenta-
tion space E induces on E a structure of a G-module. Bothviewpoints
areequivalent.
From(i), (ii), (iii)
it followseasily
that the structure map r isjointly
continuous. If G iscompact,
condition(iii)
follows from(i)
and(ii): for 03BE
EE,
the map x~ ~x03BE~ is bounded,
the uniform boundednessprinciple implies
that themaps 03BE
Hx03BE(x
EG)
areuniformly
bounded.1.2. It is clear what one should mean
by (continuous) homomorphisms
of G-modules and G-submodules. If S is a G-submodule of a G-module
E,
thenE/S
with the obvious structure map and thequotient
norm is aG-module. Let
E,
F be G-modules andlet 0 :
E - F be ahomomorphism.
Then
Ker 0
andlm 0
are G-modules. E and F are calledtopologically equivalent (notation
E -F)
in case there exists ahomomorphisms
E ~ F that is an
isomorphism
oftopological
vector spaces.If,
inaddition, 0
can be chosen to be anisometry
we call E and F iso-metrically equivalent (notation
E ~F).
Let
E,
F be G-modules. Thespace E (D
F with the normand the structure map
is
a G-module,
called the direct sum of E and F.A G-module is called
simple (irreducible)
in case it hasonly
trivial sub-modules.
1.3. Isometrical G-modules.
Let E be a non-zero G-module. Define
It is an easy exercise to show that
n(E) ~
1. We call E an isometrical G- .module in casen(E)
= 1. This isequivalent to IIxçll I = lIçll
for allx E
G, 03BE
E E.Every
G-module E istopologically equivalent
to an isometrical G-module: define on E the newnorm ~03BE~’
=supx~G Ilx. çll,
and observethat ~ ~’ ~ ~ ~ and ~x·03BE~’ = ~03BE~’ (x ~ G, 03BE ~ E).
For isometrical G-modules we define
arbitrary
direct sums as follows.let
(E03B1)03B1~I
be a collection of isometrical G-modules. The space{(03BE03B1)03B1~I ~
03A003B1 E03B1 : lim03B1 ~03BE03B1~
=0} together
with the normand the structure map defined via
is
easily
seen to be an isometricalG-module,
called the direct sum of theE03B1,
notation~03B1~I E03B1. (In fact,
it is the direct sum in thecategory
of isometricalG-modules,
themorphisms being
G-modulehomomorphisms
with
norm ~ 1).
A Hilbert G-module is an isometrical G-module
E,
where E is a n.a.Hilbert space
(See 0.2.).
1.4 Finite
dimensional
G-modules.Let E be a finite dimensional G-module. Its character XE is defined via
XE is a continuous function: G ~
K; XE(XY)
=XE(YX)
for all x, y EG;
if
E,
F are finite dimensional then ~E~F =xE +
XF,1 if E -
F then XE = XF. Theproofs
are classical.1.5 DEFINITION. Let A be a K-Banach
algebra
withapproximate identiy.
An A-module is a Banach space
E, together
with a map p : A E ~ E(written
as( f, ç) ~ f03BE)
such that(i)
p is bilinearand
continuousWrite
Tf(03BE) = f03BE.
Themap f H T f
is anon-degenerate
continuous re-presentation
of A withrepresentation
space E.Conversely,
anon-dege-
nerate continuous
representation
of A withrepresentation
space E induces on E the structure of an A-module. Let(u03B1)03B1~I
be anapproximate
iden-tity
of A. Conditions(i), (ii), (iii)
areequivalent
to(i), (ii)
andPROOF:
Clearly (iii)’ implies (iii).
To show that(iii)’
follows from(i), (ii), (iii),
consider the setEo = (j
E E :u03B103BE
~03BE}.
Sinceu03B1f03BE ~ f03BE
for allJE A, Eo
is dense in E. We claim thatEo
is closed: letÇn
EE0, 03BEn ~ 03BE.
Then there is C > 0 such that
By choosing
first nproperly
and then 03B1, we canmake ~03BE - u03B103BE~
small.1.6. The remarks in 1.2
through
1.4 can be made for A-modules aswell,
of course with the obvious modifications. To find the
counterpart
of an isometricalG-module,
define for a non-zero A-module E:Again,
we haveq(E) ~
1. Ifq(E)
= 1 we call E anormalized
A-module.Every
A-module E istopologically equivalent
to a normalized A-module.(Define ~03BE~’
=sup {~f03BE~/~f~ :f ~ A, f ~ 0}).
It is also clear how oneshould define infinite direct sums of normalized A-modules. If E is finite
dimensional,
defineThe
properties
of03A6E
are similar to those mentioned in 1.4 for characters.2. Vector-valued Haar measure
Let E be a K-Banach space.
By C~(G ~ E)
we mean the space of continuous functions : G ~ E that vanish atinfinity.
With the supremumnorm
C~(G ~ E)
is a Banach space. Define 0 :C~(G ~ K)
0 E ~C~(G ~ E)
viaIf one
puts
onCoo(G -+ K)
Q E thegreatest
cross-norm(03C0-norm),
0 be-comes an
isometry
with denseimage,
hence 0 can be extended to an iso-morphism
of Banach spaces(again
called0)
Let mK :
C~(G ~ K) -
K be acontinuous,
non zero, left invariant linear function(i.e.,
MK is a left Haarintegral).
Define mE :C~(G ~ E) -
Eby
Then mE is
continuous,
non-zero, and left invariant.Further, let 0 :
E - Fbe a continuous linear map. Then
The
proofs
arestraightforward
and are omitted. The above observations lead to thefollowing
2.1. DEFINITION. K is called suitable with
respect
to G in casefor
eachK-Banach space E there exists a continuous map mE :
C~(G ~ E) ~
Esuch that
(i)
mE is continuous and non zero(11)
mE isleft
invariant(iii) for
every continuous linearmap ~ :
E ~F(E,
F Banachspaces)
we have
~(mE(f))
=mF(~
0f).
2.2. THEOREM.
If mE
andmÉ satisfy (i), (ii), (iii) of Definition
2.1. thenthere is À E K such that mE =
03BBm’E for
all E.Further,
K is suitable withrespect
to Gif
andonly if a
K-valuedleft
Haarintegral
onC~(G ~ K)
exists.
PROOF.
Let 03BE
E E.Define ~ :
K ~ Eby ~(03BB) = Àç(À
EK).
Then wehave
Now
(~ f)(x) = f(x)03BE
=03B8(f ~ 03BE).
SomE(~ f)
=(mK à 1)(f ~ 03BE)
=
mK(f)03BE. Similarly, m’E(~
of) = m’K(f)03B6.
Since the K-valued Haar measure isunique (see [7]),
there is À E K with mK =03BBm’K.
HencemE =
Àmi
on functions of thetype 03B8-1(f ~ ç)
hence for all functions.The second
part
of the theorem has beenproved
at thebeginning
of thissection.
2.3 In the
sequel TG
will be the collection of thecompact
open sub- groups of G. The characteristic of a field L is denotedby x(L ),
the residueclass field of K
by
k.A necessary and sufncient condition for K to be suitable with
respect
to G is
given
in[7].
For reasons ofsimplicity
we shall workmostly
with
pairs G,
K that have thefollowing property:
eitherx(k)
= 0 or Gis
p-free
wheneverx(k)
=p ~
0.(Here p-free
means that for everyHl, H2 ~ 0393G, Hl
cH2,
the index(H2 : Hl )
is not divisibleby p).
Then K is suitable with
respect
to G and moreover we can choose mK suchthat |mK(H)| =
1 for all H E0393G.
For more details we refer to[10].
In[7],
a Fubini Theorem isproved
for K-valuedintegrals. Using
the de-finition of mE
it
is not very hard to prove a Fubini Theorem for the vec-tor-valued Haar
integral.
3. G-modules and
L(G)-modules
In this section we assume that G admits a left Haar
integral
mK withImK(H)/ =
1 for allH ~ 0393G .
Instead ofmE(f)
we sometimes write~f(x)dx (f E C~(G ~ E)).
It is shown in[10],
that the’integral
norm’on
CJG
~K)
equal
to the supremum norm, and that|mK(f)| ~ ~f~~ ( f E C~(G ~ K)).
It is not very hard to show that
also ~mE(f)~ ~ ~f~~(f ~ C~(G ~ E)).
Further,
it is also shown in[10],
that the spaceC~(G ~ K)
forms aBanach
algebra L(G)
under convolution and that{uH :
H~ 0393G}
forms anapproximate identity
forL(G).
HereH1 ~ H2
iffH1 ~ H2
and uH isdefined as follows
Let f:
G ~ K and XE G. Wedefine fx by fx(y) = f(x-1y), (y
eG).
3.1. THEOREM Let E be a G-module. The map
(f, 03BE) ~ f03BE given by
makes E into an
L(G)-module. Conversely, if
E is anL(G)-module,
thenthe map
(x, 03BE)
~x03BE, given by
makes E into a G-module. The above constructions
yield
a 1-1 correspon- dence between the G-module structures and theL(G)-module
structures onthe Banach space E.
PROOF. Since for each
03BE, f the
function x H-x03BEf(x)
is inC~(G ~ K), f03BE
is a well-defined element of E.Further, IJfçll = ~ lg x03BEf(x)dx~ ~
~
sup..G~x03BEf(x)~ ~ supx~G ~x·03BE~· ~f~~. Finally, for f,
g~ L(G ~ K)
and 03BE
E E :(f *g)03BE = x03BEf(xy)g(y-1)dydx = x03BEf(y)g(y-1x)dydx
=
Il x03BEf(y)g(y-1x)dxdy = f f yx03BEf(y)g(x)dxdy.
On the otherhand,
f(g03BE)
=I x(g03BE)f(x)dx
=SI xy03BEg(y)f(x)dydx.
Now let E be an
L(G)-module,
and let x ~ G. The setEo
={03BE ~
E:lim
(UH)xÇ existsl
is a linear space. Forf ~ C~(G ~ K)
we have:(uH)x(fç) = «UH)X *f)03BE = (uH *f)x03BE ~ fx03BE.
HenceEo
is dense in E.Now let
Çn
EEo,
limÇn = Let H,
H’ becompact
opensubgroups.
Then~(uH)x03BE - (uH’)x03BE~ ~
max(q(E)~03BE - 03BEn~, ~(uH)x03BEn - (uH’)x03BEn~).
By choosing
first nlarge enough
and then H and H’sufficiently
small wecan make the left hand
expression arbitrarily
small. HenceEo
is closedand
Eo = E,
sox03BE
is well defined.Next,
Finally
weonly
need to check(xy)03BE
=x(y03BE) where 03BE
is of theformf11 (f ~ L(G), ~
EE) : (xy)f~ =
lim(uH)xy(f~) =
lim((uH)xy*f)~ =fxy~,
whereas
x(yf17)
=x(fy17) = (fy)x17
=lxy17.
The 1-1correspondence
between the G- and
L(G)-module
structures will follow from thefollowing
formulasTo prove
(1), let 03BE
EE,
x E G and e > 0. For H Er G
we have:f y03BE(uH)x(y)dy = S y03BEuH(x-1y)dy = 1 xy03BEuH(y)dy.
Choose H such that~xy03BE - x03BE~
e for ally E H.
ThenIn order to show
(2),
it suffices to establish the formula for the case whereç
has theform g~ where 9
EL(G), 1
e E. So we have to checkNow the left hand
expression
isequal
to(f * g)~ = (~f(x)gxdx)~ = (mL(G)(h))~,
where h is the function xi-+f(x)gx
ofC~(G ~ L(G)).
Define a
map 0 : L(G) ~
E viaBy
Definition 2.1(iii)
we haveEXAMPLE. The left
regular representation. L(G)
is anL(G)-module
un-der the map
( f, g) H f *
g. Thecorresponding
G-module structure isgiven by xf
=fx ( f E L(G),
x EG).
3.2. THEOREM. Let
E,
F be G-modules and letÈ, F
be thecorresponding
L(G)-modules
in the senseof
Theorem 3.1respectively.
Then we have(i) n(E)
=q(Ê).
Inparticular,
E is an isometrical G-moduleif
andonly if E
is a normalizedL(G)-module.
(ii) 0 :
E ~ F is a G-module mapif
andonly if 0 ~ F is
anL(G)-
module map.
(iii)
E andE
have the same submodules.(iv)
E rvF iff ~ F;
E -F iff ~ F.
(v)
E issimple if and only if
issimple.
PROOF.
(i)
follows from theproof
of Theorem 3.1.(iii), (iv), (v)
fol-low from
(ii).
To prove(ii), let 0 :
E ~ F be a G-module map.By
De-finition 2.1
(iii)
and Theorem 3.1 we have forf E L(G), 03BE
E EConversely, let 0 : E --+ F
be anL(G)-module
map. Then for x EG,
ç
E E we have4J( xç) = 0(lim (uH)x ç)
= lim0«UI)x ç)
= lim(uH)x~(03BE)
=x~(03BE).
3.3. THEOREM. Let E be a
finite dimensional
G-module. Let XE and03A6E
be the
trace functions defined
in 1.4 and 1.6respectively.
Then we havePROOF. Write
Ux(03BE) = xj
andTf(03BE)
=f03BE(x
EG, f ~ L(G), 03BE
EE).
ThenlJJE(f) = tr (03BE ~ f03BE) = tr (Tf)
=tr (S Uxf(x)dx) = ~ tr (Ux)f(x)dx
==~f(x)~E(x)dx. Next, XE(X)
= tr(Ux)
= tr(lim T(uH)x)
= lim tr(T(..).)
= lim
03A6E((uH)x)·
3.4 THEOREM. Let E be a
finite
dimensional G-module. Then Ker E ={x
E G :xç = çfor all 03BE
EEl is
an open normalsubgroup of
G.PROOF. Ker E is a normal
subgroup
of G. Consider thecorresponding L(G)-
module structure on E and writeTf(03BE) = f03BE(f ~ L(G), 03BE
EE). By
1.5 we have lim
UHÇ = ç
for all03BE,
henceTUH
converges to theidentity
operator.
Since u,, isidempotent Tufi
is aprojection
andH1 ~ H2 implies
Im
TuHI
c ImTuH2 .
So there is anHo
eF.
withuH003BE = 03BE. Let x
eHo.
Then
xç
= lim(uH)x uH0 03BE = ç.
Hence Ker E is open.3.5 THEOREM. Let G be
compact
and let E be asimple
G-module. Then dim E oo.PROOF.
Let 03BE ~ E, 03BE ~
0. SinceuH
there isH E TG
such thatuH03BE ~
0. The linear space{fuH03BE : f E L(G)j
is non-zero, finite dimensional(every
function of thetype f *
uH is constant on left cosetsof H),
and anL(G)-submodule,
hence a G-submodule. Since E issimple,
dim E oo.4.
Compact
groupsIn this section we prove a non-archimedean variant of the
Peter-Weyl
theorem. A
supernatural
number is a formalproduct IT pnp
where p runsthrough
the set of theprimes
andwhere np
is aninteger
0 or oo. Itis clear how to define
products, l.c.m., g.c.d.
of elements of a set of super- natural numbers. We define the order(G : 1)
of G as1.c.m. {(G/H : 1) :
H E
FGI.
The index(G : 1)c
is definedsimilarly.
4.1. THEOREM. Let G be
compact
and let~(K) (G : 1)
whenever~(K)
~ 0. Then G has
suffciently
many continuous irreduciblerepresentations.
PROOF. Let
XE G (x =f. e).
There isH ~ 0393G, H normal,
withx ~ H.
Thanks to Maschke’s Theorem the left
regular respresentation
ofGfH (which
isfaithful)
iscompletely reducible,
since~(K) (G/H : 1).
Hencethere is an irreducible
représentation
ofG/H
withvx mod H =f.
1. V in-duces an irreducible
representation
U of G withU, :0
1.The next lemma is very useful when
trying
todecompose representa-
tions into irreducible ones. From now on in 4 and 5 we suppose that G iscompact
and that a K-valued Haar measure mK exists on G withImK(H)1
= 1
for
all H EFc.
We takemK(G)
= 1.4.2 LEMMA. Let
E,
F be isometrical G-modules andlet 0 :
E - F be acontinuous linear
operator. Define 4J’ by
Then we have
(i) ~’
is a G-module map : E -F, ~~’~ ~ ~~~,
(ii) if
E = Fand 0
is aprojection
onto a G-submodule rS’of E,
then~’
is aprojection, ~’(E) = S,
Ker0’
is a G-submodule.PROOF.
(i) The continuity
of x H(x-l, x) H (x-’, x03BE)
H(x-’, ~(x03BE))
1-+
x-1~(x03BE) yields
noproblems.
Hence~’(03BE)
is well-defined and linear in03BE. Next,
whence
~~’~ ~ ~~~. Further,
fory ~ G : ~’(y03BE) = ~x-1~(xy03BE)dx =
= S yx-1~(x03BE)dx
=y~’(03BE).
(ii) For 03BE
E E :4J(xç)
eS,
hencex-1~(x03BE)
E S. Thus4J’(E)
c S.If 03BE
ES,
thenx-1~(x03BE)
=x-1xç = 03BE.
So we haveThat Ker
0’
is a G-submodule follows from(i).
Let E be a finite dimensional G-module. Let el’ ..., en be a basis of E.
The functions
span a finite dimensional space of continuous K-valued
functions,
calledPJl E( G).
It is clear that another choice of the basis doesn’tchange PJl E( G),
and that E -
Fimplies eE(G) = PJl F( G).
Define
PJl( G)
to be the K-linear spacegenerated by {RE(G) : E
isa
simple G-module}.
4.3. LEMMA. The
following
sets areequal.
(1 )
The K-linear spanof {RE(G) :
E is asimple
HilbertG-modulel.
(2) R(G).
(3)
The K-linear spanof {RE(G) :
dlm Eool.
(4)
The spaceof
thelocally
constantfunctions.
(5) {f ~ L(G) : (!s)seG
spans afinite
dimensionalspacel.
PROOF. We show
(1) c (2) c (3) c (4) c (5) c (1).
(3)
c(4)
follows from Theorem 3.4. The rest,except (5)
c(1),
isobvious. Let
f E (5).
The left ideal I cL(G) generated by f is
finite di-mensional.
Considering
I as a G-module under the leftregular
represen-tation,
we canapply
Maschke’s theorem and find that I = QIi (in
thealgebraic sense),
where theIi
aresimple.
Thus we may assume that I issimple.
I is a n.a. Hilbert space, and 7 is an isometrical G-module. Let~
EI*
be thefunction f ~ f(e)(f ~ I). Thenf(x) = ~(fx), hence f ~ RI(G).
4.4. LEMMA. Let
E,
F besimple
G-modules and let E ~F, f ~ PJl E( G),
g E
PJl F( G).
ThenPROOF.
Let 0
EE* and il
E F.By
Lemma 4.2 the map0’ :
E - F de-fined via
is a G-module map, hence
0’ =
0. So forall 03BE ~ E, 03C8
eF*
we have:4.5. COROLLARY.
Every simple
G-module istopologically equivalent
to asimple
Hilbert G-module.PROOF. Let E be a
simple
G-module and letf
Ef!ll E( G).
If for every Hilbert module F we had E ~ Fthen ~f(x)g(x-1)dx
= 0 for all 9 Ef!ll F( G). By
Lemma 4.3 we thenhad ~f(x)g(x-1)dx
= 0 for all g Ee(G).
Sincef!ll( G)
isdense, f
= 0. Contradiction.4.6. DEFINITION. Let G be a
compact
group, and let k be the residue classfield of
K. K is called asplittingfieldfor
G in caseÇn -1
= 0 has ndifferent
roots in k whenever
n |(G : 1)c.
In the
terminology
of[1]
our definition isequivalent
to : ’k is asplitting
field for
G/H
for each normal H EFG"
4.7. THEOREM
(Peter-Weyl)
Let K be asplitting field for
G. Let(Ea)aeI
be a
complete
set(modulo -) of simple
Hilbert G-modules. For each a,let
e03C31, ···, e’
be an orthonormal basisof Ea. Define for
6 EE,
1 ~i, j ~ d,
Then
PROOF. To show
(1)
we may assume J = r(Lemma 4.4).
There is anormal
subgroup H ~ 0393G
such that theUu
are constant on the cosets ofH. The left hand
expression
of(1)
is thenequal
toSince
d03C3(G : H)
we haveIdal
= 1.(2)
follows from the fact that theufj
spanR(G)
and from Lemma0.1, by taking
theu03C3ij
fore03B1’s,
and themaps f ~ ~f(x)u03C4kl(x-1)dx for, f03B1’s.
4.8. COROLLARY. Let K be a
splitting fzeld for
G where G is abelian. Thenthe continuous characters: G ~
K.f’orm
an orthonormal basisof L(G).
PROOF. Let E be a
simple
G-module.By [1 ], (27.3), 4J :
E ~ E is aG-module map
implies 4J = À1(À
EK).
Hence dim E = 1. Nowapply
Theorem 4.7
(2).
4.9. COROLLARY Let K be a
splitting field for
G and let E and E’ befinite
dimensional G-modules. Thenthe following
statements areequivalent.
PROOF.
By
Theorem 3.2 and Theorem 3.3 weonly
have to show(2) ~ (1).
Let firstE,
E’ besimple. By Corollary
4.5 we may assume thatE,
E’ are Hilbert G-modules. Theorthogonality
relationsyield
Hence the
assumptions
XE = XE’ and E ~ E’ arecontradictory.
The ge-neral case can
easily
beproved by decomposing
E and E’ into a directsum of
simple
modules.4.10. COROLLARY. Let K be a
splitting field for
G and let(E03C3)03C3~E be
as inTheorem 4.7. For
f E L(G) define
where
IIflla
= suplllf. 03BE~/~03BE~ : 03BE
EE03C3, 03BE ~ 0}.
Then~f~^
=~f~.
PROOF.
Write f = 03A3 03BB03C3iju03C3ij(Theorem
4.7(2)).
Then it follows that5. Hilbert G-modules for
compact
G.The left
regular representation
ofL(G)
can(in
case K is asplitting
field for
G)
bedecomposed
into a direct sum(in
the sense of1.3)
ofirreducible
representations.
This follows from Theorem 4.7. Note thatL(G)
need not be a n.a. Hilbert space. We nowtry
todecompose
arbi-trary representations.
We canonly get
some results in case the represen- tation space is a n.a. Hilbert space.(Theorem 5.3).
Throughout
this section we assume that E is a Hilbert G-module. With the definitionx . ç = x·03BE(x
EG, 03BE
EE, ~03BE~ ~ 1), E (see 0.2)
becomes aG-module
(in
thealgebraic sense).
E HÉ
is functorial. The crucial pro-perty
is thefollowing.
5.1. THEOREM. Let
E,
F be Hilbert G-modules and let ocE ~ F
be a G- module map. Then there is a G-modulemap ~ :
E - Fwith
oc.PROOF. There exists a continuous linear
map 03C8 :
E ~ Fwith
= 03B1.Write
Ux(03BE)
=x03BE, Vx(17)
=xq(x
EG, 03BE
eE, 17
EF).
DefineBy
Lemma4.2, 0
is a G-module map. WriteHx = 03C8Ux - Vx03C8.
ThenHx
=03B1Ux - Vx03B1
=0,
soby 0.3, (i)
wehave IIHxl1
1 for all x ~ G.Hence ~ = 03C8 =
x.5.2. COROLLARY. Let
E,
F be Hilbert G-modules. ThenE ~ F implies
E ~ F. In case K is a
splitting field
wehave,
inaddition, the following.
(i)
E issimple if
andonly if E
issimple.
(ii)
LetE,
F besimple
andlet 0 :
E ~ F be atopological equivalence of
G-modules. Then there is À E Kwith 0 = 03BB03C8, where 1/1
anisometry.
Inparticular,
E - Fimplies
E ~ F.PROOF. Let x :
É - F
be anisomorphism
of G-modules.By
Theorem5.1 there is a G-module
map 0 :
E ~ Fwith ~
= x.By 0.3, (ii) 0
is anisomorphism
of Banach spaces. To prove(i),
let E be besimple.
Letx :
E ~ É
be a G-module map. There is a G-modulemap ~ :
E ~ E with~
= x.By [1], (27.3), 0 = 03BBI, |03BB| ~
1. Hence x =03BBI,
soE
issimple.
Now let
E
besimple. Let 0 :
E ~ E be aprojection
and a G-modulemap.
Then ~
is aprojection, so ~ =
0 orI, whence 0 =
0 or I. Thus Eis
simple.
To prove(ii),
choose03BB-1
E K suchthat ~03BB-1~~
= 1. Then03BB-1 ~ ~ 0,
hence abijection by
Schur’s lemma. It follows that03BB-1~
is anisometry.
5.3. THEOREM. Let E be a Hilbert G-module. Then E is an
orthogonal
direct sum
of simple
G-modules. In case K is asplitting field
thisdecompo-
sition is
unique
in thefollowing
sense. Let E =~03B1~I En03B103B1 =~03B1~J Fm03B103B1
betwo
decompositions
in the above sense(E03B1 ~ Ep if oc :0 fi;
n03B1 is themultipli- city ; same for F03B1’s).
Then there is abijection
(J : I ~ J such thatPROOF. We first show that E has
simple
submodules. There exist HE TG and 03BE
E E such thatuH 03BE ~
0. The G-submodulegenerated by
thisvector is finite
dimensional,
hence it containssimple
G-submodules. The existence of adecomposition
of E now caneasily
beshown, using
Lemma4.2 and Zorn’s Lemma. To show the
uniqueness property,
let a EI, 03B2
e J and consider the G-module mapIf
E03B1
~F03B2,
this map is the zero map. Definea(a)
to be theonly 13
forwhich the above maps are non-zero. The
identity
on E sendsEn03B103B1
intoFm03C3(03B1)03C3(03B1);
it must be onto. Since dimE03B1
oo, acardinality argument
can showthat n03B1
=m03C3(03B1). By Corollary
5.2(ii) E03B1 ~ F03C3(03B1) implies E03B1 ~ F03C3(03B1).
6. The Tannaka
duality
theoremWe formulate the Tannaka
Duality
Theorem in thelanguage
of[3 ]y
11.3. A
Hopf algebra
is aK-algebra
H withidentity together
withalgebra homomorphisms
L1 : H - H (8) H and e : H - K such that thediagrams
commute. It is useful to consider the
multiplication
as amap ~ :
H Q H- H and the
identity
as amap 11 : K --+
H. TheHopf algebra
then iscompletely
describedby
the5-tuple (H, ~,
11,A, e).
Let X be a
compact
0-dimensional Hausdorff space and let K be a field.Let R(X)
denote the space of thelocally
constant functions : X - K. ThenR(X)
is a commutativeK-algebra
withidentity, generated by
its idem-potents. Conversely,
if A is such analgebra
then the set of allalgebra homomorphisms:
A ~ K with thefinite-open topology
is a 0-dimensionalcompact
Hausdorff space. In fact the above functorsyield
aduality
be-tween the
category
of 0-dimensionalcompact
Hausdorff spaces and thecategory
of the commutativeK-algebras
withidentity, generated by
itsidempotents. (See [9], Chapter III).
Now if S is a
compact
0-dimensionalsemigroup
withidentity,
let-q(S)
be the
K-algebra
of thelocally
constant functions on S. It is a commutativeHopf algebra
underwhere 6, 03C0, e are defined
by
If H is a commutative
Hopf algebra, generated by idempotents,
letG(H)
be the collection of all
algebra homomorphisms :
H - K. Under thefinite-open topology
and with themultiplication
G(H)
becomes a 0-dimensionalcompact
Hausdorffsemigroup
with iden-tity
e. We now have thefollowing
theorem theproof
of which is left tothe reader.
6.1. THEOREM. Let !7 be the category
of 0-dimensional Hausdorff semi-
groups with
identity,
and let H be the categoryof
the commutativeK-Hopf algebras generated by idempotents.
Then thefunctors
fi :P ~ H :
Ghave the
properties
G R ~idg
and WG -idH.
Thesenatural equivalences js :
S ~GPÃ(S)
andjH :
H ~RG(H)
aregiven by
and
We now can
give
a very shortproof
of a well-known result(See [4], (8.19)).
6.2. COROLLARY.
Every
0-dimensionalHausdorff semigroup
with iden-tity
isprojective
limitof finite semigroups.
PROOF. We show that every element
f
e H e 3Q lies in a finitedimensional
sub-Hopf algebra. By [6], (2.5) f
is contained in a finitedimensional sub-coalgebra
C. Thesubalgebra generated by
C iseasily
seen to be a
sub-Hopf algebra,
and it is also finite dimensional since we caninterpret
H as anR(S)
for some S.An
antipode
in aHopf algebra
H is a K-linear map co : H ~ H such that thediagram
commutes. If G e P is a
topological
group, thenR(G)
has anantipode
defined
by
It is not very hard to show that
R(S)
has anantipode
if andonly
if Sis a
topological
group. Thisremark, together
with Theorem 6.1 and Lem-ma 4.3 form the non-archimedean
analogue
of the TannakaDuality
Theorem.
REFERENCES C. CURTIS, I. REINER
[1] Representation theory of finite groups and associative algebras. New York, 1962.
E. HEWITT, K. Ross
[2] Abstract harmonic analysis. New York, I, 1963; II, 1970.
G. HOCHSCHILD
[3 ] The structure of Lie groups. San Francisco, 1965.
K. HOFMANN, P. MOSTERT
[4] Elements of compact semigroups, Columbus Ohio, 1966.
G. KALISCH
[5] On p-adic Hilbert spaces. Ann. Math. 48 (1947). 180-192.
R. LARSON
[6] Cocommutative Hopf algebras. Can. J. Math. 19 (1967), 350-360.
A. MONNA, T. SPRINGER
[7] Intégration non-archimédienne I, II. Indag. Math. 25 (1963), 634-654.
A. MONNA, T. SPRINGER
[8] Sur la structure des espaces de Banach non-archimédiens. Indag. Math. 27 (1965),
602-614.
M. VAN DER PUT
[9] Algèbres de fonctions continues p-adiques (Thesis). Utrecht, 1967.
W. SCHIKHOF
[10] Non-archimedean harmonic analysis (Thesis). Nijmegen, 1967.
Oblatum: 16-XI-1970 Dr W. H. Schikhof,
Mathematisch Instituut, R.K.-Universiteit, Driehuizerweg 200, NIJMEGEN