R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
M ARCEL H ERZOG
F EDERICO M ENEGAZZO
On deficient products in infinite groups
Rendiconti del Seminario Matematico della Università di Padova, tome 93 (1995), p. 1-6
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MARCEL
HERZOG(**) -
FEDERICOMENEGAZZO(***)
1. Introduction.
In
[2]
groups with the deficient squaresproperty
werecompletely
characterized. It was shown in
[3]
that a group G has the deficient squaresproperty
if andonly
if it does not contain an infinitefully-inde- pendent
subset.In this paper we
investigate
infinite groups with deficientproducts properties.
To make this moreprecise,
let G be an infinite group and let n,k E=- N, k ->
2. A subset of G with n elements will be called an n-set of G . We say that G EDP( n, k)
if allk-tuples Xl , X2 ,
... ,Xk
of n-sets in Gsatisfy
In
particular,
G EDP(n)
stands for G EDP(n, 2). Finally,
we say that G E DP if G EDP(n, k)
for somepositive integers n, k E N,
k > 2. Our main results areexpressed
in thefollowing
theorems.THEOREM 1. Let G be an
infinite,
group and Let n e N. Then G EDP( n ) if
andonly if
G is abelian.This theorem follows
immediately
from(*) This article was written
during
the first author’s visit to theUniversity
of Padova. He would like to thank the
Department
of Mathematics for the invita- tion and for their kindhospitality.
(**) Indirizzo della.: School of Mathematical Sciences,
Raymond
and Be-verly
SacklerFaculty
of Exact Sciences, Tel-AvivUniversity,
Tel-Aviv,Israel.
(***) Indirizzo dell’A.: Universita di Padova,
Dipartimento
di MatematicaPura e
Applicata,
Via Belzoni 7, 35131 Padova,Italy.
2
THEOREM 2. Let G be an
infinity
non-abelian groups. Then G con-tains two
infinite product-independent
subsets.Two subsets A and B of G are
product-independent
if whenevera, a’ e A and
b,
b’ EB,
then ab ~ b’ a’ and ab = a’ b’ or ba = b’ a’only
if a = a’ and b = b’.
We say that a group G satisfies G E FIZ if its center is of finite in- dex. With
respect
to the DPproperty
we proveTHEOREM 3. Let G be an
infinite,
group. Then G E DPif
andonly if
G E FIZ.Theorem 3 follows
easily
fromTHEOREM 4. Let G be an
infinite,
group. Then G containsNo
mu-tually product-independent infinity
subsetsif
andonly if G ~
FIZ.The
proofs
of Theorems1, 2,
3 and 4 will bepresented
in Section 2.It is easy to see that similar
proofs yield
thefollowing generaliza-
tions of Theorems 1 and 3. In order to state these
generalizations,
we need some additional notation. For each k e
N,
k > 2 we define((n), k) = (nl ,
n2 , ... ,nk ),
where nl , n2 , ... ,~ ~ N’
We say thatG E DP((n), k)
if allk-tuples Xl , X2 , ... , Xk
of subsets of G withX 1 I~
,!X2!,
...,lXk 1) = (nl, n2, ..., nk) satisfy
Finally,
we say that G E DP * if G EDP((n), k)
for some((n), k),
k ;::: 2.The
generalized
theorems are:THEOREM 1’. Let G be an
infinite,
group. Then G EDP((n), 2) if
and
only if
G is abelian. ,THEOREM 3’. Let G be an
infinity
group. Then G E DP*if
andonly if
G E FIZ.Section 3 deals with a
related,
butdifferent, topic. Following [4]
we say that G EPn
if XY = YX for all n-setsX,
Y in G and G EPn
if every infinite set of distinct n-sets of G contains apair X,
Y of distinct members such that XY = YX. In[4]
it was shown that G EPn
if andonly
if G is abelian and in[5]
the second authorshowed that G E
P)
for n > 1 if andonly
if G is abelian. Theorems1, 3,
1’ and 3’ aregeneralizations
of the first mentioned result and we extend the second resultby considering
groupsG E P * ,
which
satisfy
theproperty
that every infinite set of distinct finitesubsets of G of
specified
sizes not less than two contains apair
of distinct members
X,
Y such that XY = YX. We proveTHEOREM 5. Let G be an
infinity
group. Then G E P *if
andonly if
G is abelian.The
following
notation and definitions will be used in this paper.The letter G denotes an infinite group and N denotes the set of
positive integers.
The lettersi, j , l,
m, n,-~
a, p, z will denotepositive integers.
A subset S of G will be called a Sidon set if whenever x, y, z, w E S and
I ix, Y,
z,w ~ ~ ~ 3,
then xy ~ zw.2.
Groups
with deficientproducts.
In this section we shall prove Theorems
1, 2,
3 and 4. Ourproofs
re-ly
on thefollowing important
results of B. H. Neumann and of Babai and S6s.THEOREM A
(B.
H. Neumann[6]).
Let G be a groups. Then G E FIZif and only if G
does not contain aninfinite,
subset Usatisfying
uv ~ vuwhenever u, v E U and u ~ v.
THEOREM B
(L.
Babai and V. T. S6s[1]). If
U is aninfinity
subsetof
a groupG,
then U contains aninfinite
Sidon set.We
proceed
with ourLEMMA 1. Let G be an
infinity
group. and let k denote apositive integer
orNo.
Then there exist kinfinite
sequencesAi
=(a’, a2 , ... ),
i =
1, 2, ... , k of
elementsof
G such thatand
for X # a if and
only
if i =1~and j
= l.If G ~ FIZ,
we may choose theAi
in such a way, that in addition to the above mentionedproperties they
willsatisfy
PROOF.
Suppose, first,
thatG ~
FIZ.By
Theorem A there existsan infinite sequence B =
(gl ,
g2 ,... )
of distinct elements of G such that4
gi g~ ~ g3 g~
ifi ~ j . By
Theorem B there exists an infinitesubsequence
U =
(u1,
U2,...)
of B suchthat Ui Uj
= uk ulimplies
that either i =1~ andj
1(i.e.
or i= j
and 1(i.e. U?
=U2).
Partition the setU into k
disjoint
infinitesubsequences Ai
=a,2 , ...),
i =1, 2,
... , 1~.Then
(2.1), (2.2)
and(2.3)
hold. Theproof
in the caseG ~
FIZ iscomplete.
If G E
FIZ,
thenZ(G)
is of infinite order andby
Theorem BZ(G)
contains an infinite sequence U = U2,
... )
of distinct elements such that =implies
that either i = kand j
= 1(i.e.
= ori = j
and k = l(i.e. u2 U2)
or i= l and j
= k(i.e.
uiuj =ujui).
Con-struct the sequences
Ai (a’, ... )
for i =1, 2, ..., k
as before. Then(2.1)
and(2.2) hold,
as claimed.We are
ready
now to prove Theorem 2.PROOF OF THEOREM 2. If
FIZ,
then Theorem 2 follows from Lemma1,
with = 2. So suppose that G E FIZ. ThenZ(G)
isinfinite,
G ’ is finite andZ( G ) /H
isinfinite,
where H =Z(G)
f 1 G ’ . Let T be atransversal of H in
Z(G)
and let U be an infinite subset of T such thatE
C/}
is a Sidon set inZ(G)/H.
This means that if u, v,w, t
E Usatisfy
uvH = wtH thenI vH, wH, tH ~ ~ I 3,
hence alsoI
v, w,t ~ ~ I
3. Nowsplit
U into two infinitedisjoint
subsets R andS;
fix elements x, y E G with xy ~ yx andfinally
set A =xR, B
=yS.
Ifa = xr,
a’ = xr’, b = ys
andb’ = ys’,
withr,r’eR
ands, s’ E S, satisfy
ab= b ’ a ’,
then xrys =ys ’ xr’,
whichimplies [ x, y] rs
= s ’ r’and
[x, y] E H.
But then rsH = s’ r’ H and it follows that s,~, ~ }~ I
3 and r =r’,
s =s’,
whichimplies [x, y]
=1,
a con- tradiction. Thus whenever a, a’ E A andb,
b’ EB,
then ab # b’ a’.Sup-
pose, now, that ab = a ’ b ’
(or ba = b ’ a ’ ).
Then xrys =xr’ ys ’ (or
ysxr= ys’ xr’ ),
whichimplies
rs = r’ s ’(or
sr =s ’ r’ )
and as abover =
r’ ,
s= s ’, yielding a
= a ’ and b = b ’ . Hence A and B are infiniteproduct-independent
subsets of G and theproof
of Theorem 2 iscomplete.
Theorem 1 follows
immediately
from Theorem 2.We
proceed
with aproof
of Theorem4,
from which Theorem 3 fol- lowseasily.
PROOF OF THEOREM 4. If
G ~ FIZ,
then G containsNo mutually product-independent
infinite subsetsby
Lemma 1. On the otherhand, if G E FIZ,
thenG : Z(G) I
= n for some n E N. LetAI, A2 ,
... ,An
+ 1be infinite subsets of G. Then there exist s E G and
i, j
e N such that1 i, j n
+ f1sZ(G) # 0 and Aj
f1sZ(G) #
0. It follows thatAi
andAj
are notproduct-independent,
and inparticular
G does notcontain
No mutually product-independent
infinite subsets.Finally
we prove Theorem3,
in which theDP-groups
are character-ized.
PROOF OF THEOREM 3.
Suppose, first,
that G E FIZ andI G: Z(G) I
= m. ThenG E DP( 1, m + 1 )
sincegiven
m + 1 elements gl , 92, ... , gm + 1 ofG,
at least two of thembelong
to the same coset ofZ(G)
in G and therefore commute with each other. Thisimplies
that
and hence G E
DP( 1,
m +1),
as claimed. But thisimplies
that G EDP,
thus
completing
theproof
in one direction.Suppose,
now, that G e DP. Then G EDP(n, k)
for somepositive
in-tegers
n, k with k ~ 2. It followsimmediately by
Theorem 4 thatG E FIZ.
3.
Sequences
withequal products.
In this section we shall prove Theorem 5.
PROOF OF THEOREM 5. If G is abelian then
clearly
G E P *. So sup- pose that G E P * and G is non-abelian. We shall reach a contradiction from ourassumptions.
Let(nl ,
n2 ,...)
be an infinite sequence of inte- gersgreater
orequal
to two.Pick x,
y E G such that xy ~ yx.If
G E
FIZ thenby
Lemma 1applied
to G and k =No,
the subse-quences Ui
=(aÏ, an,)
of the infinite sequencesAi
==
(aÏ, ... ), i
=1, 2,
...satisfy Ui Uj
f1 = 0 fori = j
and henceG ~ P *,
a contradiction.So suppose that G E FIZ. Then
Z(G)
is infinite andby
Lemma 1 ap-plied
toZ(G)
and k =3,
there exist threedisjoint
infinite sequencesa2 , ... ), ( bl , b2 , ... )
and( tl , ...)
of distinct elements ofZ( G )
suchthat Define the
following
infinite sequence of sequences:6
and so on.
Suppose
that for somei ~ j
we have = Sincetk , al , bm
EZ(G)
for allk,
x, y,Z(G)
and wemust have which
implies
xy = yx, a contradiction.Thus
G ~ P *,
a final contradiction.REFERENCES
[1] L. BABAI - V. T.
Sós,
Sidon sets in groups and inducedsubgraphs of Cay- ley graphs, Europ.
J. Combinatorics, 6 (1985), pp. 101-114.[2] M. HERZOG - P. LONGOBARDI - M. MAJ, On a combinatorial
problem
ingroup
theory,
Israel J. Math., to appear.[3] M. HERZOG - C. M. SCOPPOLA, On
deficient
squares groups andfully-inde- pendent
subsets,preprint.
[4] J. C. LENNOX - A. M. HASSANABADI - J. WIEGOLD, Some
commutativity
cri- teria, Rend. Sem. Mat. Univ. Padova, 84 (1990), pp. 135-141.[5] F. MENEGAZZO, A property
equivalent
tocommutativity for infinite
groups, Rend. Sem. Mat. Univ. Padova, 87 (1992), pp. 299-301.[6] B. H. NEUMANN, A
problem of
Paul Erdös on groups, J. Austral. Math.Soc. (Series A), 21 (1976), pp. 467-472; Selected Works
of B.
H. Neumannand Hanna Neumann, vol. 5, pp. 1003-1008.
Manoscritto pervenuto in redazione 1’1