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On finite-dimensional projections of distributions for solutions of randomly forced 2D Navier–Stokes equations

A. Agrachev

a,b

, S. Kuksin

b,c

, A. Sarychev

d

, A. Shirikyan

e,

aSISSA-ISAS, via Beirut 2–4, Trieste 34014, Italy

bSteklov Institute of Mathematics, 8 Gubkina St., 117966 Moscow, Russia

cDepartment of Mathematics and Maxwell Institute for Mathematical Sciences, Heriot-Watt University, Edinburgh EH14 4AS, Scotland, UK dDiMaD, University of Florence, via C. Lombroso 6/17, Firenze 50134, Italy

eDépartement de Mathématiques, Université de Cergy-Pontoise, Site de Saint-Martin, 2, avenue Adolphe Chauvin, 95302 Cergy-Pontoise Cedex, France

Received 1 February 2006; accepted 19 June 2006 Available online 13 December 2006

Abstract

The paper is devoted to studying the image of probability measures on a Hilbert space under finite-dimensional analytic maps.

We establish sufficient conditions under which the image of a measure has a density with respect to the Lebesgue measure and continuously depends on the map. The results obtained are applied to the 2D Navier–Stokes equations perturbed by various random forces of low dimension.

©2006 Elsevier Masson SAS. All rights reserved.

Résumé

L’article est consacré à l’étude de l’image des mesures de probabilité sur un espace hilbertien par des applications analytiques de dimension finie. On établit des conditions suffisantes sous lesquelles l’image d’une mesure possède une densité par rapport à la mesure de Lebesgue et dépend continûment de l’application. Les résultats obtenus s’appliquent aux équations de Navier–Stokes 2D perturbées par diverses forces aléatoires de dimension peu élevée.

©2006 Elsevier Masson SAS. All rights reserved.

MSC:35Q30; 60H15; 93C20

Keywords:2D Navier–Stokes system; Analytic transformations; Random perturbations

0. Introduction

Let us consider the 2D Navier–Stokes equations on the torusT2⊂R2:

˙

u+(u,)uνu+ ∇p=f (t, x), divu=0, x∈T2. (0.1)

* Corresponding author.

E-mail addresses:[email protected] (A. Agrachev), [email protected] (S. Kuksin), [email protected] (A. Sarychev), [email protected] (A. Shirikyan).

0246-0203/$ – see front matter ©2006 Elsevier Masson SAS. All rights reserved.

doi:10.1016/j.anihpb.2006.06.001

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Hereu=(u1, u2)andp are unknown velocity field and pressure,ν >0 is the viscosity, andf is an external force.

Eqs. (0.1) are supplemented with the initial condition

u(0)=u0, (0.2)

whereu0 is a given function belonging to the spaceH of divergence-free vector fields in L2(T2,R2). It is well known [20,5,21] that if the right-hand sidef satisfies some mild regularity assumptions, then problem (0.1), (0.2) has a unique solutionuin an appropriate functional class. Our aim is to study some qualitative properties of solutions in the situation whenfis a random process with a sufficiently non-degenerate distribution. More precisely, let us assume thatf is a stochastic process on the positive half-lineR+ with range inL2(T2,R2)such that the distribution of its restriction to any interval[0, T]is a non-degenerate decomposable measure (see Condition (P) in Section 1.1). One of the main results of this paper says that for any finite-dimensional subspaceFH and anyt >0 the distribution of the projection ofu(t )toF has a density with respect to the Lebesgue measure. Similar properties are true in the case whenf is a white noise in time or a sum of independent identically distributed random forces. Furthermore, if the random dynamical system associated with (0.1) generates a Markov process, then the above-mentioned property is valid for any stationary distribution. These results are important since for a number of problems in pure and applied mathematics only finitely many Fourier components of a solutionumatter; these components correspond to a finite- dimensional subspace ofH.

The fact that a solution of a nonlinear SDE stirred by a degenerate noise has a continuous density against the Lebesgue measure is very well known. The proofs are usually based on the Malliavin calculus (see [17] and the references therein). There have been a few works in which various versions of the Malliavin calculus were developed for some stochastic PDE’s (for instance, see [18,4,6,15,8,16]). In particular, it was proved in [16] that iff is white noise in time and sufficiently non-degenerate in the space variables, then the distribution of the projection of solution for (0.1), (0.2) to any finite-dimensional subspace has a smooth density with respect to the Lebesgue measure.

The approach of this paper is completely different and is based on the controllability of (0.1) in finite-dimensional projections and an abstract result on the image of probability measures under analytic mappings. We emphasise that our method does not use the Gaussian structure of the noise, and the proof is simpler and shorter compared to the papers quoted above. At the same time, if the forcef is white in time, and the results of those works apply, then our information on the density of the distribution for the projection ofu(t )is weaker than, say, that obtained in [16].

The paper is organised as follows. In Section 1, we have compiled some preliminary results on decomposable measures on Hilbert spaces. Section 2 contains two abstract results on the transformation of probability measures under analytic mappings. In Section 3, we apply them to the 2D Navier–Stokes equations with different types of additive noise. Finally, in Appendix A, we prove some auxiliary results used in the main text.

0.1. Notation

LetX be a Polish space, i. e., separable complete metric space. We denote byBX(a, R) the closed ball in X of radiusR centred ata. Ifa coincides with a selected point0X, then we writeBX(R). Let B(X)be the Borel σ-algebra onXand letP(X)be the family of probability measures on(X,B(X)). The spaceP(X)is endowed with the total variation norm:

μ1μ2var:= sup

Γ∈B(X)

μ1(Γ )μ2(Γ ), μ1, μ2P(X).

Ifμ1, μ2P(X)andμ1is absolutely continuous with respect toμ2, then we writeμ1μ2. For a random variableξ, we denote byD(ξ )its distribution.

For any Banach spaceX, we denote by · Xthe norm inX. IfY is another Banach space, thenL(X, Y )stands for the space of bounded linear operators fromXtoY. In the caseX=Y, we shall writeL(X). IfXis finite-dimensional, thenXdenotes the Lebesgue measure onX.

LetJ⊂Rbe a closed interval and letR+= [0,+∞). We use the following functional spaces.

Cb(X)is the space of bounded continuous functionsf:X→Rendowed with the norm f=sup

xX

f (x).

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C(J, X)is the space of continuous functionsu:JX.

Lp(J, X)is the space of Bochner-measurable functionsu:JXsuch that uLp(J,X)=

J

u(t )p

Xdt 1/p

<.

Lploc(R+, X) is the space of functionsu:R+X whose restriction to any finite interval J ⊂R+ belongs to Lp(J, X).

IfXis a Hilbert space andFXis a closed subspace, thenPF:XF denotes the orthogonal projection inX ontoF.

1. Decomposable measures on Hilbert spaces

1.1. Definitions and examples

Let X be a separable Hilbert space with a scalar product (·,·) and the corresponding norm · X. We denote byB(X)the Borelσ-algebra onXand byP(X)the family of probability measures on(X,B(X)).

Definition 1.1.We shall say that a measureμP(X)isdecomposableif there is an orthonormal basis{gj} ⊂Xsuch that

μ= j=1

μj, (1.1)

whereμj is the projection ofμto the one-dimensional spaceXj generated bygj and⊗denotes the tensor product of measures.

Example 1.2.LetμP(X)be a Gaussian measure (for instance, see [3]). It is well known that there is a vectoraX and a self-adjoint nuclear operatorKL(X)such that the characteristic function ofμhas the form

ˆ

μ(z)=exp

i(a, z)−1

2(Kz, z) , zX. (1.2)

In this case, the vectorais the mean value ofμ, a=

X

xμ(dx),

andKis the covariance operator forμ, (Kz, z)=

X

(z, xa)2μ(dx);

we refer the reader to Chapter 2 in [3] for more details. Let{gj}be an orthonormal basis inX formed of the eigen- vectors ofKand letλj be the eigenvalue ofKcorresponding togj. If a vectorzXis written in the form

z=

j=1

zjgj,

then relation (1.2) takes the form ˆ

μ(z)= j=1

exp

i(a, gj)zj−1

2λjz2j . (1.3)

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It follows that μ admits decomposition (1.1) in which μj is a one-dimensional Gaussian measure with mean value(a, gj)and variance λj. Note also that if λj =0 for somej 1, then the measureμ is degenerate in the sense that its support is contained in a proper affine subspace ofX.

In what follows, we shall deal with decomposable measures possessing some additional properties. Namely, we consider a measureμP(X)satisfying the following condition.

(P) The measureμis decomposable and has a finite second moment

X

x2Xμ(dx) <. (1.4)

Moreover, every measureμj in (1.1) possesses a continuous density ρj with respect to the Lebesgue measure onXj.

The following lemma describes the random variables whose distribution satisfies property (P); its proof is obvious.

Lemma 1.3.The distribution of anX-valued random variableξ satisfies condition(P)if and only ifξ has the form ξ=

j=1

bjξjgj, (1.5)

where {gj} is an orthonormal basis in X,{ξj} is a sequence of scalar independent random variables such that Eξj2=1 and the law ofξj has a continuous density with respect to the Lebesgue measure, and bj >0 are some constants satisfying the condition

j=1

bj2<. (1.6)

Example 1.4. LetμP(X)be a Gaussian measure with a mean value aX and a covariance operatorK. We claim thatμsatisfies condition (P) if and only if it is non-degenerate, i.e., all eigenvalues ofKare positive. Indeed, Fernique’s theorem (see [3]) implies that condition (1.4) is satisfied for any Gaussian measure. Furthermore, it fol- lows from (1.3) that the projectionμj ofμtoXj is a one-dimensional Gaussian measure with varianceλj. Thus, μj possesses a continuous density with respect to the Lebesgue measure if and only ifλj>0.

For the sequel, we note that ifμP(X)is a non-degenerate Gaussian measure, then

μ(B) >0 for any ballBX; (1.7)

see Section 3.5 in [3] for a proof.

1.2. Support of decomposable measures

Let X be a separable Hilbert space and letμP(X) be a measure possessing property (P). Denote by {gj} an orthonormal basis in X for which representation (1.1) holds and, for any integer N 1, define X(N ) as the N-dimensional space spanned bygj, 1jN. Let

μ(N )= N

j=1

μj, ν(N )= j=N+1

μj. (1.8)

IfaX(N )andR >0, then we denote byBN(a, R)the closed ball inX(N )of radiusRcentred ata. In the casea=0, we writeBN(R).

Proposition 1.5.LetμP(X)be a measure satisfying condition(P). Then there is a point A=

j=1

ajgjX (1.9)

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such that1

ρj(aj) >0 for allj1. (1.10)

Furthermore, ifAXis a point satisfying(1.10), then for any integerN1there isrN>0such that suppμBN(AN, rN), AN=

N

j=1

ajgj. (1.11)

Proof. To prove the existence ofA, denote byA0=

jaj0gjany point in the support ofμ. Thena0j∈suppμjfor any j 1. SinceμjXj (whereXj denotes the Lebesgue measure onXj), there isaj∈Rsuch that|ajaj0|j1 and (1.10) holds. DefiningAXby relation (1.9), we obtain the required result.

When proving the second part of the proposition, we shall assume, without loss of generality, thatA=0. Let us fix any integerN1. It follows from (1.8) and (1.10) that

suppμ(N )BN(rN), (1.12)

whererN>0 is sufficiently small. We claim that (1.11) holds for the same constantrN>0. Indeed, letxBN(rN) andε >0. Consider anX-valued random variableξ with distributionμ. By Lemma 1.3, it has the form (1.5). We wish to show that

P

ξxXε

>0. (1.13)

To this end, define ϕN=

N

j=1

bjξjgj, ψN= j=N+1

bjξjgj.

It is clear that (1.13) will be established if we prove that P

ϕNxXε/2

>0, P

ψNXε/2

>0. (1.14)

The first inequality follows immediately from (1.12). To prove the second, choose an integerM > N and write ψN2X=

M

j=N+1

bj2ξj2+ j=M+1

bj2ξj2=SM+RM. (1.15)

In view of (1.6) and the relationEξj2=1, we have ERM=

j=M+1

b2j→0 asM→ ∞. By Chebyshev’s inequality, it follows that

P{RMδ} →1 asM→ ∞, (1.16)

whereδ >0 is an arbitrary constant. Furthermore, inequalities (1.10) with aj=0 imply that, for any fixedM > N andδ >0, we have

P{SMδ}>0. (1.17)

Combining (1.15)–(1.17) and recalling thatRM andSM are independent, we arrive at the second inequality in (1.14).

This completes the proof of the proposition. 2

1 In what follows, we identifyXj with the real line and regardρjas a function of a real variable.

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1.3. A zero-one law for analytic functions

LetXbe a separable Hilbert space and letf:X→Rbe a continuous function. Recall thatf is said to beanalytic if for anyx0Xthere isδ >0 such that

f (x)=f (x0)+ m=1

Lm(xx0) forxBX(x0, δ), (1.18)

whereLm:X→Ris anm-linear functional and the series in (1.18) converges regularly. The latter means that

m=1

Lmδm<,

where · stands for the norm of multilinear functionals:

Lm = sup

xX1

|Lmx|.

We refer the reader to [13] or [21] for more details.

For any continuous functionf:X→R, we set Nf =

xX: f (x)=0 .

It is well known that if dimX <∞andf is analytic, then eitherX(Nf)=0 orf≡0. The following theorem shows that a similar result is true in the infinite-dimensional case.

Theorem 1.6.Letf:X→Rbe an analytic function and letμP(X)be a measure possessing property(P). Then

μ(Nf)=0or1. (1.19)

Furthermore, iff is not identically zero, thenμ(Nf)=0.

Proof. We shall need a result from [7]. To formulate it, let us introduce some definitions.

Recall that the one-dimensional spacesXj are defined in condition (P) and thatX(N )stands for the vector space spanned byXj, 1jN. Denote byX(N ) the orthogonal complement ofX(N )inXand setX()=

NX(N ). We shall say thatAB(X)is a finite zero-oneμ-set if

ν(N )

yX(N ): μ(N ) AN(y)

=0 or 1

=1 for any integerN1,

whereAN(y)= {xX(N ): x+yA}, and the measuresμ(N )andν(N )are defined by (1.8).

According to Theorem 4 in [7], ifμis a decomposable measure onX, then for any finite zero-oneμ-setAB(X) there isAB(X)such that

A+X()=A, μ(A)=μ(A).

Applying the Kolmogorov zero-one law (see [9]), we see thatμ(A)=0 or 1. Thus, the measure of any finite zero-one μ-set is either zero or one.

To prove (1.19), note that if f is analytic, then for any integer N 1 and any yX(N ) , we have either N(Nf(y))=0 orN(X(N )\Nf(y))=0, where N denotes the Lebesgue measure on X(N ). Since μ(N )N (see condition (P)), we see that

μ(N ) Nf(y)

=0 or 1 for anyyX(N ).

Thus,Nf is a finite zero-oneμ-set, and (1.19) follows from what has been said above.

We now suppose thatf ≡0. In this case, there isx0Xsuch thatf (x0)=0, and since{gj}is a basis inXandf is continuous, there is no loss of generality in assuming thatx0X(N )for some integerN1. In view of (1.19), the required assertion will be established if we show that

μ

xX: f (x)=0

=0. (1.20)

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The restriction off toX(N )is an analytic function on a finite-dimensional space. It follows that f (x)=0 forN-almost everyxX(N ).

Recalling Proposition 1.5, we can find a pointx0∈suppμsuch thatf (x0)=0. By continuity, there isδ >0 such that f (x)=0 forxB(x0, δ).

This implies that{f (x)=0} ⊃B(x0, δ), and therefore (1.20) holds. 2 2. Image of measures under analytic maps

2.1. Formulations of the results

Let(U, d) be a metric space and letX andF be finite-dimensional vector spaces. Consider a continuous oper- ator f:U×XF. For any probability measure μP(X) and any uU, denote byf(u, μ)the image ofμ underf (u,·).

Theorem 2.1.Suppose that, for anyuU, the functionf (u,·)is analytic and the interior of the setf (u, X)is non- empty. LetμP(X)be a measure possessing a continuous densityρ(x)with respect to the Lebesgue measure onX.

Then the following assertions hold.

(i) For anyu0U, the measuref(u0, μ)is absolutely continuous with respect toF.

(ii) The functionf(·, μ)fromUto the spaceP(F )endowed with the total variation norm is continuous.

Our next goal is to study the case in whichX is an infinite-dimensional space. More precisely, suppose that X is a separable Hilbert space and F is a finite-dimensional vector space. Recall that condition (P) is introduced in Section 1.1.

Theorem 2.2. Let f:U×XF be a continuous function such thatf (u,·)is analytic for any uU and the derivativeDxf (u, x)is continuous with respect to(u, x). Suppose that, for anyuU, there is a ballBu in a finite- dimensional subspaceXuXsuch that the interior of the setf (u, Bu)is non-empty. Then for any measureμP(X) satisfying condition(P)statements(i)and(ii)of Theorem2.1take place.

2.2. Proof of Theorem 2.1

Let us fix any pointu0Uand denote byDxf (u0, x)the derivative (Jacobian) of the mapf (u0,·):XF at the pointxX. We first show that the matrixDxf (u0, x)has a minorm(x)of the size dimF such that

m(x)=0 forμ-almost everyxX. (2.1)

To this end, recall that a pointxXis said to beregularforf (u0,·)if the rank ofDxf (u0, x)is maximal. Any point that is not regular is said to be singular. In view of Sard’s theorem (see [19]), the image under the smooth functionf (u0,·)of the set of its singular points has zero Lebesgue measure. Since the interior off (u0, X)is non- empty, we conclude thatf (u0,·)has a regular pointx0X.

Let m(x)be the minor of Dxf (u0, x)that is non-zero at x0. Sincem(x) is analytic, we see thatm(x)=0 al- most everywhere with respect to the Lebesgue measureX. Sinceμis absolutely continuous with respect toX, we conclude that (2.1) holds.

For anyε >0, we denote Xε=

xX: |x|ε1,m(x)ε . Then

νε:=μ X\Xε

→0 asε→0.

Let us take anyxXεand write it asx=(x1, x2), wherex1denotes the variables entering the minorm(x). Accord- ingly, the spaceXcan be represented as a direct productX=X1×X2. Applying the implicit function theorem, we

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can find open ballsV1X1 andV2X2 such that for anyx2V2 anduBε=BX(u0, rε),the mapf (u,·, x2) is a diffeomorphism of the domainV1onto its imageW (u, x2). Hererε>0 is a constant that goes to zero withε.

Accordingly, we can writex1in terms ofuBε,x2V2andy=f (u, x1, x2)W (u, x2):

x1=g(u, y, x2).

The setsV =V1×V2corresponding to variousxXεform an open cover of the compact setXε. Let us find a finite sub-cover{Vj}. We denote by{ϕj(x)}a continuous partition of unity onXε subordinate to{Vj}. That is, ϕj0, suppϕjVj, and(

ϕj)(x)=1 forxXε. Letμj=ϕjμ. Then

μj=ϕj(x)ρ(x)dx1dx2=ϕj(x1, x2)ρ(x1, x2)m(u, x1, x2)1dydx2, (2.2) wherem(u, x)is the minor ofDxf (u, x)corresponding tox1, andx1=g(u, y, x2)on the right-hand side of (2.2).

Hence,f(u, μj)=gj(u, y)dy, where gj(u, y)=

˜

ϕj(y, x2)ρ(y, x˜ 2)m(u, y, x2)1dx2

withϕ˜j(y, x2)=ϕj(g(u, y, x2), x2), etc. Let us denoteμε=(

ϕj)μ. Thenμμεvarνε. We have

f(u, με)=gε(u, y)dy, (2.3)

wheregε(u, y)=

gj(u, y)is a continuous function ofuBεandy. Clearly, f(u, με)f(u, μ)

varνε for anyuBε. (2.4)

Relations (2.3) and (2.4) withu=u0andε→0 imply assertion (i). Indeed, for any measurable setQF with zero Lebesgue measure, we have

f(u, μ)(Q)=

f(u, μ)f(u, με)

(Q)+f(u, με)(Q), sof(u, μ)(Q)νεfor eachε. Hence,f(u, μ)(Q)=0.

To prove (ii), we fix anyγ >0 and chooseε >0 such thatνε<13γ. Due to (2.4), foruBεwe have f(u, μ)f(u0, μ)

varε+f(u, με)f(u0, με)

var

ε+1

2 gε(u, y)gε(u0, y)dyγ ,

ifuis sufficiently close tou0. Sinceu0is an arbitrary point, what has been said implies (ii).

Remark 2.3.Analysing the proof given above, one easily sees that, instead of assuming the existence of interior points for the setf (u, X), we could require that the functionf (u,·)should have at least one regular point for anyuU(cf.

the beginning of the proof).

2.3. Proof of Theorem 2.2

Step 1. Let us fix anyu0Uand show that there is finite-dimensional subspaceX1Xspanned by some vectors of the basis{gj}such that dimX1=dimF and (2.1) holds, where m(x)denotes the determinant of the matrix for the restriction ofDxf (u0, x)toX1. Indeed, by the hypothesis, there is a ballBu0 in a finite-dimensional subspace Xu0Xsuch that the interior off (u0, Bu0)is non-empty. Since{gj}is a basis inX, for anyδ >0 there is a finite- dimensional subspaceYXspanned by some vectors of{gj}such that

PYyyXδ for anyyBu0, (2.5)

wherePY:XX is the orthogonal projection in X onto the subspace Y. Now note thatf (u0,·) is continuous andBu0 is compact. Therefore for anyε >0 we can findδ >0 such that

f (u0, z)f (u0, y)

F ε foryBu0,zyXδ. (2.6)

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Combining (2.5) and (2.6), we see that for anyε >0 there is a finite-dimensional subspaceYXspanned by some vectors of{gj}such that

f (u0,PYy)f (u0, y)

Fε foryBu0.

Choosing ε >0 sufficiently small and applying Proposition A.1 of the Appendix (see Appendix A), we conclude that the interior of the set f (u0, Y ) is non-empty. Since dimY <∞, Sard’s theorem implies that the function f (u0,·):YF has at least one regular pointx0Y. Let us denote byX1 a subspace spanned by some vectors of the basis{gj}such that the restriction ofDxf (u0, x0)toX1is an isomorphism fromX1ontoF. Thenm(x0)=0.

Sincem(x)is an analytic function, the required result follows from Theorem 1.6.

Step 2. We now repeat the argument used in the proof of Theorem 2.1. Let us representX as the direct product X=X1×X2, whereX1 is constructed in Step 1 andX2denotes the orthogonal complement of X1inX. Denote by λ1andλ2the projections of μ to the subspacesX1 andX2, respectively, and byρ(x1)the density ofλ1 with respect toX1. For anyε >0, let us choose a compact setXεXsuch that

xXε1, m(x)ε forxXε, νε:=μ X\Xε

ε.

As in the proof of Theorem 2.1, we can find a constantrε>0 going to zero withεand a finite cover{Vj=V1j×V2j} of the compact set Xε such that V1jX1 andV2jX2 are balls, and for any x2V2 anduBε=BX(u0, rε), the map f (u,·, x2)is a diffeomorphism of the domainV1 onto its imageW (u, x2). We denote by x1=g(u,·, x2) the inverse function off (u,·, x2). Let{ϕj(x)}be a continuous partition of unity onXεsubordinate to{Vj}and let μj=ϕjμ. Then we have (cf. (2.2))

μj=ϕj(x)ρ(x1)dx1λ(dx2)=ϕj(x1, x2)ρ(x1)m(u, x1, x2)1dyλ(dx2),

wherem(u, x)denotes the determinant of the restriction ofDxf (u, x)toX1, andx1=g(u, y, x2)on the right-hand side of the formula. The rest of the proof is literally the same as that of Theorem 2.1, and therefore we omit it.

Remark 2.4.The proof given above implies that the claim of Theorem 2.2 remains true if we replace the condition of existence of interior points for the setf (u, Bu)by the following one: for anyuU, there is a pointxuXand a finite-dimensional subspaceXuXsuch that the restriction ofDxf (u, xu)toXuis an isomorphism fromXuontoF (cf. Step 1 of the proof).

3. Applications

Throughout this section, we use the standard functional spaces H andV arising in the theory of Navier–Stokes equations; they are defined in Subsection 3.1. We shall also use the spaces

X=C(R+, H )L2loc(R+, V ), XT =C(JT, H )L2(JT, V ), whereT >0 andJT = [0, T].

3.1. Navier–Stokes equations perturbed by a time-discrete random force

Let us consider the 2D Navier–Stokes (NS) system on the torusT2=R2/2πZ2. Define the spaces H=

uL2 T2,R2

: divu=0 onT2

, V =H1 T2,R2

H,

endowed with natural norms. Here Hs(T2,R2)denotes the space of vector functions (u1, u2)whose components belong to the Sobolev space of orders. LetΠ:L2(T2,R2)Hbe the orthogonal projection inL2(T2,R2)ontoH. After applying the projectionΠ, the NS system reduces to the following evolution equation inH:

˙

u+νLu+B(u, u)=g(t, x), (3.1)

whereν >0 is the viscosity,L= −Π , andB(u, v)=Π ((u,)v). In this subsection, we assume that g(t, x)=

k=1

Ik,T(t )ηk(x), (3.2)

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whereT >0 is a parameter,Ik,T(t )is the indicator function of the time interval[(k−1)T , kT ), and{ηk}is a sequence ofH-valued i.i.d. random variables defined on a probability space(Ω,F,P). Standard theorems on well-posedness of the 2D NS system (e.g., see [5]) imply that, for almost everyωΩ, problem (3.1), (3.2) has a unique solution uXthat satisfies the initial condition

u(0)=u0, (3.3)

whereu0H is an arbitrary function. We shall denote bySt:HHthe random operator that takesu0tou(t ). Our aim is to study the distribution for projections of the random variablesSkT(u0)to finite-dimensional subspaces ofH.

Let{ej}be a complete set of eigenfunctions forLindexed in an increasing order of the corresponding eigenval- uesαj and letHNbe the vector space spanned byej,j=1, . . . , N. We shall assume that the i.i.d. random variablesηk

satisfy the following condition.

(D) The random variablesηkhave the form ηk=

j=1

bjξj kej, (3.4)

wherebj0 are some constants such that

j=1

b2j<, (3.5)

andξj kare independent scalar random variables whose distributionπjpossesses a continuous density with respect to the Lebesgue measure, and suppπj0 for anyj0.

The following theorem shows that, under the above condition, all finite-dimensional projections of the distribution forSkT(u)have continuous densities with respect to the Lebesgue measure, provided thatkis sufficiently large andT does not belong to a discrete exceptional set.

Theorem 3.1.Suppose that condition(D)is fulfilled. Then there is an integerN1 not depending onν and{ηk} such that the following two statements hold, provided that

bj=0 forj =1, . . . , N. (3.6)

(i) For any constantν >0 and any finite-dimensional subspaceFH, there is a discrete subsetT=T(ν, F )⊂ R+\ {0}such that ifT /TandR >0, then for anyuBH(R)and an appropriate integerk=k(ν, F, R)1 the distribution ofPFSkT(u)possesses a density with respect toF.

(ii) Let us setλu(t )=D(PFSt(u)). Thenλu(kT )continuously depends onuBH(R)in the total variation norm.

Remark 3.2.It is possible to give a more precise description of the integerN in (3.6). Namely, it is the minimal integerN 1 such that the vectorse1, . . . , eN form a saturating set (see Section A.3 in Appendix A for a definition of a saturating set). In particular, if the eigenfunctions ofLare indexed in a suitable way, then one can takeN=6.

Proof of Theorem 3.1. Step 1. We wish to apply Theorem 2.2 and Remark 2.4. LetH0H be the subspace spanned by those vectorsej for whichbj=0 and letXk be the direct product ofkcopies ofH0. We fix a finite-dimensional subspaceFHand consider the operator

fk:R+×H×XkF, (T , u0, η1, . . . , ηk)PFu(kT ),

whereR+=R+\ {0}andu(t )denotes the solution of problem (3.1)–(3.3) in which{ηk}is regarded as a sequence of deterministic functions inH0. In view of Proposition A.2, the operatorfk is analytic onR+×H ×Xk. Fur- thermore, if condition (D) is fulfilled, then for any integerk1 the distribution of the Xk-valued random variable ηk=1, . . . , ηk)satisfies property (P). Suppose we have established the existence of a discrete subsetT⊂R+pos- sessing the following property:

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(C) for anyR >0 there is an integerk1 such that ifT /Tandu0BH(R), then the derivative

(Dηkfk)(T , u0,ηk):XkF (3.7)

is surjective for at least one pointηk=1, . . . , ηk)Xk.

In this case, statements (i) and (ii) of the theorem are straightforward consequences of Theorem 2.1 and Remark 2.3 in whichX=Xk andU=BH(R).

Step 2. To prove (C), we first assume thatu0=0. Let us denote byR1:L2(J1, H )H the operator that takes each functiongL2(J1, H )tou(1, x), whereuX1is the solution of (3.1), (3.3) withu0=0. By Proposition A.5, there is an integerN 1 such that the Navier–Stokes system (3.1) with gL2(J1, HN)is solidly controllable in time 1 for the projection toF. (See Definition A.4 for the concept of solid controllability.) In particular, there is a compact subsetKL2(J1, H )and a constantε >0 such thatΦ(K)BF(1)for any continuous map satisfying the inequality

sup

gK

Φ(g)PFR1(g)

F ε. (3.8)

For any integerm1, denote byYmL2(J1, HN)the subspace of functions that are constant on any interval of the form[lm1,ml), 1lm. It is clear that

mYmis dense inL2(J1, HN). SinceKis compact, for anyδ >0 we can find an integerm1 such that

sup

gK

gPYmgV δ.

It follows from the continuity of R1 that for anyε >0 there is an integerm1 such that (3.8) is satisfied for Φ(g)=PFR1(PYmg). This implies that

PFR1(Ym)BF(1). (3.9)

Now note that if we denote byIl,m(t )the indicator function of the interval[lm1,ml)and identify the function g(t, x)=

m

l=1

Il,m(t )ηl(x)Ym

with the vectorη=1, . . . , ηm)Xm, then we can write fm

m1,0,ηm

=PFR1(g). (3.10)

Combining (3.9) and (3.10), we conclude that there is a finite-dimensional subspaceXXmsuch that fm

m1,0, X

BF(1).

Sard’s theorem now implies that the derivative (Dηmfm)

m1,0,ηm

:XmF

is surjective for at least one pointη0mXm. Since(Dηmfm)(T ,0,η0m)is an analytic function with respect toT >0, we see that there is a discrete setT⊂R+such that

(Dηmfm)

T ,0,η0m

:XmF is surjective for anyT /T. (3.11)

Step 3. We can now verify property (C). Let us fix anyT /T andR >0. We claim that if an integerl1 is sufficiently large andk=l+m, then the linear operator (3.7) is surjective forηk=(0, . . . ,0,η0m)and anyu0BH(R).

Indeed, the definition offkimplies that fk

T , u0,η0k

=fm

T , u(lT ),η0m ,

whereu(t )is the solution of (3.1), (3.3) withg≡0. It follows that Im

(Dηkfk)

T , u0,η0k

⊃Im

(Dηmfm)

T , u(lT ),η0m

, (3.12)

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where Im{A} denotes the image of a linear operator A. In view of (3.11) and the continuity of Dηmfm, we can findr >0 such that

Im

(Dηmfm)

T , v,η0m

=F for anyvBH(r). (3.13)

Furthermore, the dissipation property of the homogeneous Navier–Stokes system implies that

u(lT )BH(r) for anyu0BH(R), (3.14)

wherel=l(R, T )1 is sufficiently large. Combining (3.12)–(3.14), we arrive at the required result. 2

Remark 3.3.Analysing the proof given above, it is possible to establish the following property, which shows that the

“bad” subsetTconstructed in Theorem 3.1 cannot accumulate to zero if we allow the integerkto depend onT:

• For any constant ν >0 and any finite-dimensional subspace FH there is T0>0 such that if T(0, T0] andR >0, then for anyuBH(R)and an appropriate integerk=k(ν, F, R, T )1 the distribution ofPFSkT(u) possesses a density with respect toF and continuously depends onuin the total variation norm.

We now study stationary solutions of (3.1), (3.2). Since{ηk}are i.i.d. random variables inH, for any deterministic initial function u0 the sequence {u(kT ), k0}is a Markov chain. Thus, the set of all solutions restricted to the timeskT form a Markov family inH. LetPk(u, Γ )be the corresponding transition function and letPkbe the Markov operator associated withPk. Using standard a priori estimates for solutions of the Navier–Stokes system and applying the Bogolyubov–Krylov argument (e.g., see [12]), one can show thatPk has at least one stationary distributionμ:

Pkμ=μ for allk1. (3.15)

A simple consequence of Theorem 3.1 is the following result:

Corollary 3.4.Suppose that the conditions of Theorem3.1are fulfilled. LetFH be a finite-dimensional subspace and letT /T(ν, F ). Then for any stationary measureμthe projectionPFμpossesses a density with respect to the Lebesgue measure onF.

Proof. LetΓF be a Borel set of zero Lebesgue measure and letε >0. Choose a constantR >0 so large that μ

BH(R)

1−ε. (3.16)

By assertion (i) of Theorem 3.1, we can find an integerk1 such that

(PFPk)(u, Γ )=0 for alluBH(R). (3.17)

Combining (3.15)–(3.17), we derive PFμ(Γ )=

H

(PFPk)(u, Γ )μ(du)=

BHc(R)

(PFPk)(u, Γ )μ(du)μ BHc(R)

ε,

whereBHc(R)denotes the complement ofBH(R). Sinceε >0 was arbitrary, we conclude thatPFμ(Γ )=0. This completes the proof of the corollary. 2

3.2. Navier–Stokes equations with a non-degenerate random perturbation

In this subsection, we consider the NS system (3.1) with a right-hand side of the form

g(t, x)=h(t, x)+η(t, x). (3.18)

We assume that hL2loc(R+, H ) is a deterministic function andηis a random process whose trajectories belong toL2loc(R+, H0), whereH0His a closed subspace. Denote byμT,T >0, the distribution of the restriction ofηto the intervalJT and bySt:HH the random operator that takes eachu0H tou(t ), whereuX is the solution of (3.1), (3.3), (3.18).

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Theorem 3.5.There is an integerN1 not depending onν >0such that ifhL2loc(R+, H )is a given function, T >0 is a constant, H0H is a subspace containing HN, and μT is a decomposable measure on L2(JT, H0) satisfying property(P), then for anyu0Hand any positivetJT the following statements take place.2

(i) LetFH be a finite-dimensional subspace and letλu(t )be the distribution ofPFSt(u). Thenλu(t )F. (ii) The measureλu(t )continuously depends onuH in the total variation norm.

Proof. Both assertions are straightforward consequences of Theorem 2.2 and Propositions A.2 and A.5. Indeed, let ft:H×L2(JT, H )F be the operator that takes each pair(u0, η)toPFu(t ), whereuXT is the solution of prob- lem (3.1), (3.3), (3.18) with deterministic functionshandη. By assumption, the distributionμT of the restriction ofη toJT satisfies condition (P), and by Proposition A.2, the operatorft is analytic with respect to(u0, η). Furthermore, taking into account Proposition A.5 and repeating the argument used in Section 3.1, for anyuH and any positive tJT we can find a ballBu in a finite-dimensional subspaceXuL2(JT, H )such thatft(u, Bu)F has at least one interior point. Thus, the conditions of Theorem 2.2 are fulfilled, and we can conclude that assertions (i) and (ii) hold. 2

Example 3.6.Let us consider an example of a random forceη(t, x)for which the hypotheses of Theorem 3.5 are satisfied for any T >0. LetH0H be any finite-dimensional subspace and let {η(t ), t0}be a homogeneous Gaussian process inH0with a correlation functionK(t ). (For the existence of such a process, see [11, Chapter 3].) Suppose thatK(t )is a positive-definite operator for anyt0. Then, for anyT >0, the distribution of the restriction ofηtoJT is a non-degenerate Gaussian measure. As is explained in Example 1.4, such a measure satisfies property (P).

3.3. Navier–Stokes equations perturbed by a white noise

This subsection is devoted to studying the NS system (3.1), (3.18), in which hL2loc(R+, H )is a deterministic function andη(t, x) is a random process white in time andH2-regular in the space variables. More precisely, we define the spaceU=VH2(T2,R2)endowed with theH2-norm and assume that there is a non-negative nuclear operatorQL(U )such that

η(t, x)=

∂tζ (t, x), (3.19)

whereζ is a Gaussian process inUwith continuous trajectories and the covariance operator K(t, s)=(ts)Q, t, s0.

It follows that ζ (t, x)=

j=1

bjβj(t )gj(x),

where{gj}is an orthonormal basis inU formed of the eigenvectors ofQ,b2j is the eigenvalue ofQcorresponding togj, and{βj}is a sequence of independent standard Brownian motions. It is well known (see [21,10]) that for almost every value of the random parameter the Cauchy problem for (3.1), (3.18), (3.19) has a unique solution in the spaceX, and we denote bySt:HHits resolving (random) operator.

Theorem 3.7.There is an integer3N1 not depending onν >0such that ifhL2loc(R+, H )is a given function and the image ofQcontainsHN, then for anyu0H andt >0assertions(i)and(ii)of Theorem3.5hold, and

suppλu(t )=F. (3.20)

2 See Remark 3.2 for a more precise description ofN.

3 A more precise description ofNcan be found in Remark 3.2.

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