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(1)

On strategically equivalent contests

Jang SCHILTZ (University of Luxembourg) joint work with

Jean-Daniel GUIGOU (University of Luxembourg),

& Bruno LOVAT (University of Lorraine)

June 2, 2016

(2)

Outline

1 Basic Framework - Deterministic rent

2 General Framework - Risky rent Strategically equivalent contests

Situations in which the proportional contest dominates

(3)

Outline

1 Basic Framework - Deterministic rent

2 General Framework - Risky rent Strategically equivalent contests

Situations in which the proportional contest dominates

(4)

Outline

1 Basic Framework - Deterministic rent

2 General Framework - Risky rent Strategically equivalent contests

Situations in which the proportional contest dominates

(5)

General description of the contest

Two players compete for a prize V .

Each player chooses an effort level xi given the expected effort level xj of his rival.

The vector of efforts (xi, xj) determines what each player will finally get.

(6)

General description of the contest

Two players compete for a prize V .

Each player chooses an effort level xi given the expected effort level xj of his rival.

The vector of efforts (xi, xj) determines what each player will finally get.

(7)

General description of the contest

Two players compete for a prize V .

Each player chooses an effort level xi given the expected effort level xj of his rival.

The vector of efforts (xi, xj) determines what each player will finally get.

(8)

General description of the contest

Two players compete for a prize V .

Each player chooses an effort level xi given the expected effort level xj of his rival.

The vector of efforts (xi, xj) determines what each player will finally get.

(9)

The assumptions

Assumption 1. The contest success function pi, describing the effort of player i relative to the total effort is given by

pi = xi

xi + xj

.

There are two possible interpretation for pi.

In a Proportional contest, it is interpreted as a share of the prize, in a Lottery contest as a win probability.

Assumption 2. Players are expected utility maximizer.

(10)

The assumptions

Assumption 1. The contest success function pi, describing the effort of player i relative to the total effort is given by

pi = xi

xi + xj

.

There are two possible interpretation for pi.

In a Proportional contest, it is interpreted as a share of the prize, in a Lottery contest as a win probability.

Assumption 2. Players are expected utility maximizer.

(11)

The assumptions

Assumption 1. The contest success function pi, describing the effort of player i relative to the total effort is given by

pi = xi

xi + xj

.

There are two possible interpretation for pi.

In a Proportional contest, it is interpreted as a share of the prize, in a Lottery contest as a win probability.

Assumption 2. Players are expected utility maximizer.

(12)

The assumptions

Assumption 1. The contest success function pi, describing the effort of player i relative to the total effort is given by

pi = xi

xi + xj

.

There are two possible interpretation for pi.

In a Proportional contest, it is interpreted as a share of the prize, in a Lottery contest as a win probability.

Assumption 2. Players are expected utility maximizer.

(13)

The assumptions

Assumption 1. The contest success function pi, describing the effort of player i relative to the total effort is given by

pi = xi

xi + xj

.

There are two possible interpretation for pi.

In a Proportional contest, it is interpreted as a share of the prize, in a Lottery contest as a win probability.

Assumption 2. Players are expected utility maximizer.

(14)

Strategically equivalent contests

Definition (Chowdhury and Sheremeta (2014))

Contests are effort equivalent if they result in the same Nash equilibrium level of effort.

(15)

Strategically equivalent contests

Definition (Chowdhury and Sheremeta (2014))

Contests are effort equivalent if they result in the same Nash equilibrium level of effort.

(16)

The case of a deterministic rent

Lottery contest (L) Payoff

πLi = (V − xi, −xi; pi, 1 − pi) . Expected utility

EUπiL(x ) = xi xi+ xj

Ui(V − xi) + xj xi + xj

Ui(−xi).

Proportional contest (P) Payoff

πiP = (piV − xi; 1) . Expected utility

EUπPi (x ) = U( xi

xi+ xjV − xi).

(17)

The case of a deterministic rent

Lottery contest (L)

Payoff

πLi = (V − xi, −xi; pi, 1 − pi) . Expected utility

EUπiL(x ) = xi xi+ xj

Ui(V − xi) + xj xi + xj

Ui(−xi).

Proportional contest (P) Payoff

πiP = (piV − xi; 1) . Expected utility

EUπPi (x ) = U( xi

xi+ xjV − xi).

(18)

The case of a deterministic rent

Lottery contest (L) Payoff

πLi = (V − xi, −xi; pi, 1 − pi) .

Expected utility

EUπiL(x ) = xi xi+ xj

Ui(V − xi) + xj xi + xj

Ui(−xi).

Proportional contest (P) Payoff

πiP = (piV − xi; 1) . Expected utility

EUπPi (x ) = U( xi

xi+ xjV − xi).

(19)

The case of a deterministic rent

Lottery contest (L) Payoff

πLi = (V − xi, −xi; pi, 1 − pi) . Expected utility

EUπiL(x ) = xi xi+ xj

Ui(V − xi) + xj xi + xj

Ui(−xi).

Proportional contest (P) Payoff

πiP = (piV − xi; 1) . Expected utility

EUπPi (x ) = U( xi

xi+ xjV − xi).

(20)

The case of a deterministic rent

Lottery contest (L) Payoff

πLi = (V − xi, −xi; pi, 1 − pi) . Expected utility

EUπiL(x ) = xi xi+ xj

Ui(V − xi) + xj xi + xj

Ui(−xi).

Proportional contest (P)

Payoff

πiP = (piV − xi; 1) . Expected utility

EUπPi (x ) = U( xi

xi+ xjV − xi).

(21)

The case of a deterministic rent

Lottery contest (L) Payoff

πLi = (V − xi, −xi; pi, 1 − pi) . Expected utility

EUπiL(x ) = xi xi+ xj

Ui(V − xi) + xj xi + xj

Ui(−xi).

Proportional contest (P) Payoff

πiP = (piV − xi; 1) .

Expected utility

EUπPi (x ) = U( xi

xi+ xjV − xi).

(22)

The case of a deterministic rent

Lottery contest (L) Payoff

πLi = (V − xi, −xi; pi, 1 − pi) . Expected utility

EUπiL(x ) = xi xi+ xj

Ui(V − xi) + xj xi + xj

Ui(−xi).

Proportional contest (P) Payoff

πiP = (piV − xi; 1) . Expected utility

EUπPi (x ) = U( xi

xi+ xjV − xi).

(23)

The case of risk-neutral players

If players are risk-neutral expected utility maximizer (U(z) = z) EUπiL(x ) = xi

xi + xj

V − xi ≡ UE πiL(x ) ≡ UπiP(x ).

Dxi( xi

xi+ xjV − xi) = V xj

(xi+ xj)2 − 1. Theorem

The two contests have Nash equilibrium x = V /4 and are thus strategically equivalent.

(24)

The case of risk-neutral players

If players are risk-neutral expected utility maximizer (U(z) = z) EUπiL(x ) = xi

xi + xj

V − xi ≡ UE πiL(x ) ≡ UπPi (x ).

Dxi( xi

xi+ xjV − xi) = V xj

(xi+ xj)2 − 1.

Theorem

The two contests have Nash equilibrium x = V /4 and are thus strategically equivalent.

(25)

The case of risk averse players

Assumption 3. The players have constant absolute risk-averse (CARA) preferences represented by the negative exponential utility function

u(πi) = − exp(−r πi),

where r > 0 represents the coefficient of absolute risk aversion. We can then show that

xP = V4.

xL = 2r (eeVrVr−1+1) = 2r1 tanh(Vr2 ).

(26)

The case of risk averse players

Assumption 3. The players have constant absolute risk-averse (CARA) preferences represented by the negative exponential utility function

u(πi) = − exp(−r πi),

where r > 0 represents the coefficient of absolute risk aversion.

We can then show that xP = V4.

xL = 2r (eeVrVr−1+1) = 2r1 tanh(Vr2 ).

(27)

The case of risk averse players

Assumption 3. The players have constant absolute risk-averse (CARA) preferences represented by the negative exponential utility function

u(πi) = − exp(−r πi),

where r > 0 represents the coefficient of absolute risk aversion.

We can then show that xP = V4.

xL = 2r (eeVrVr−1+1) = 2r1 tanh(Vr2 ).

(28)

The case of risk averse players

Assumption 3. The players have constant absolute risk-averse (CARA) preferences represented by the negative exponential utility function

u(πi) = − exp(−r πi),

where r > 0 represents the coefficient of absolute risk aversion.

We can then show that xP = V4.

xL = 2r (eeVrVr−1+1) = 2r1 tanh(Vr2 ).

(29)

The case of risk-neutral players

Hence,

2r (xP − xL) = 2r (V 4 − 1

2r tanh(Vr 2 ))

= Vr

2 − tanh(Vr 2 ) > 0, since x ≥ tanh(x ), ∀x ≥ 0

(30)

The case of risk-neutral players

Hence,

2r (xP − xL) = 2r (V 4 − 1

2r tanh(Vr 2 ))

= Vr

2 − tanh(Vr 2 ) > 0, since x ≥ tanh(x ), ∀x ≥ 0

(31)

The case of risk-neutral players

Hence,

2r (xP − xL) = 2r (V 4 − 1

2r tanh(Vr 2 ))

= Vr

2 − tanh(Vr 2 ) > 0, since x ≥ tanh(x ), ∀x ≥ 0

(32)

Outline

1 Basic Framework - Deterministic rent

2 General Framework - Risky rent Strategically equivalent contests

Situations in which the proportional contest dominates

(33)

Notations

In this section we suppose that the rent V is a random variable with density f .

It’s Laplace transform f is defined by

f(t) = E [exp(tV )].

(34)

Notations

In this section we suppose that the rent V is a random variable with density f .

It’s Laplace transform f is defined by

f(t) = E [exp(tV )].

(35)

The proportional contest

Expected utility:

Eu(πi) = E (−e−r πi) = Z +∞

−∞

(−e−r (piu−xi))f (u)du

= −erxi Z +∞

−∞

e−rpiuf (u)du

= −erxif( −rxi xi + xj). This gives us an equilibrium effort

xP = 1 4

fr20

fr2

! .

(36)

The proportional contest

Expected utility:

Eu(πi) = E (−e−r πi) = Z +∞

−∞

(−e−r (piu−xi))f (u)du

= −erxi Z +∞

−∞

e−rpiuf (u)du

= −erxif( −rxi xi + xj

).

This gives us an equilibrium effort xP = 1 4

fr20

fr2

! .

(37)

The proportional contest

Expected utility:

Eu(πi) = E (−e−r πi) = Z +∞

−∞

(−e−r (piu−xi))f (u)du

= −erxi Z +∞

−∞

e−rpiuf (u)du

= −erxif( −rxi xi + xj

).

This gives us an equilibrium effort xP = 1 4

fr20

fr

! .

(38)

The lottery contest

Expected utility: Eu(π1) = x1

x1+ x2( Z +∞

−∞

(− exp(−r (u − x1))f (u)du) + x2

x1+ x2(−erx1)

= −x1exp(rx1) x1+ x2

( Z +∞

−∞

exp(−ru)f (u)du) − x2

x1+ x2

(erx1)

= −x1exp(rx1)

x1+ x2 f(−r ) − x2exp(rx1) x1+ x2 . This gives us an equilibrium effort

xL= 1 − f(−r ) 2r (1 + f(−r )).

(39)

The lottery contest

Expected utility:

Eu(π1) = x1

x1+ x2( Z +∞

−∞

(− exp(−r (u − x1))f (u)du) + x2

x1+ x2(−erx1)

= −x1exp(rx1) x1+ x2

( Z +∞

−∞

exp(−ru)f (u)du) − x2

x1+ x2

(erx1)

= −x1exp(rx1)

x1+ x2 f(−r ) − x2exp(rx1) x1+ x2 .

This gives us an equilibrium effort

xL= 1 − f(−r ) 2r (1 + f(−r )).

(40)

The lottery contest

Expected utility:

Eu(π1) = x1

x1+ x2( Z +∞

−∞

(− exp(−r (u − x1))f (u)du) + x2

x1+ x2(−erx1)

= −x1exp(rx1) x1+ x2

( Z +∞

−∞

exp(−ru)f (u)du) − x2

x1+ x2

(erx1)

= −x1exp(rx1)

x1+ x2 f(−r ) − x2exp(rx1) x1+ x2 . This gives us an equilibrium effort

xL= 1 − f(−r ) 2r (1 + f(−r )).

(41)

Differential equation

Strategically equivalent contests thus exist if 1

4

(f)0(−2r)

f(−r2) = 1 − f(−r ) 2r (1 + f(−r )), where f is the Laplace transform of the density of the rent.

This is a nonlinear, non local differential equation.

(42)

Differential equation

Strategically equivalent contests thus exist if 1

4

(f)0(−2r)

f(−r2) = 1 − f(−r ) 2r (1 + f(−r )), where f is the Laplace transform of the density of the rent.

This is a nonlinear, non local differential equation.

(43)

First set of solutions : The exponential law

Let V be exponentially distributed with parameter λ > 0. Then, f (x ) = λe−λx, f(t) = λ−tλ for t < λ and (f(t))0 = λ

(t−λ)2. Hence,

xP = 1 4

fr20

fr2

!

= 1 4

λ

(r2−λ)2

λ λ−−r2

= 1

2r + 4λ and

xL= 1 − f(−r )

2r (1 + f(−r )) = 1 −λ−−rλ

2r (1 +λ−−rλ ) = 1 2r + 4λ

xP = xL = 1 2r + 4λ.

(44)

First set of solutions : The exponential law

Let V be exponentially distributed with parameter λ > 0.

Then, f (x ) = λe−λx, f(t) = λ−tλ for t < λ and (f(t))0 = λ

(t−λ)2. Hence,

xP = 1 4

fr20

fr2

!

= 1 4

λ

(r2−λ)2

λ λ−−r2

= 1

2r + 4λ and

xL= 1 − f(−r )

2r (1 + f(−r )) = 1 −λ−−rλ

2r (1 +λ−−rλ ) = 1 2r + 4λ

xP = xL = 1 2r + 4λ.

(45)

First set of solutions : The exponential law

Let V be exponentially distributed with parameter λ > 0.

Then, f (x ) = λe−λx, f(t) = λ−tλ for t < λ and (f(t))0 = λ

(t−λ)2.

Hence,

xP = 1 4

fr20

fr2

!

= 1 4

λ

(r2−λ)2

λ λ−−r2

= 1

2r + 4λ and

xL= 1 − f(−r )

2r (1 + f(−r )) = 1 −λ−−rλ

2r (1 +λ−−rλ ) = 1 2r + 4λ

xP = xL = 1 2r + 4λ.

(46)

First set of solutions : The exponential law

Let V be exponentially distributed with parameter λ > 0.

Then, f (x ) = λe−λx, f(t) = λ−tλ for t < λ and (f(t))0 = λ

(t−λ)2. Hence,

xP = 1 4

fr20

fr2

!

= 1 4

λ

(r2−λ)2

λ λ−−r2

= 1

2r + 4λ

and

xL= 1 − f(−r )

2r (1 + f(−r )) = 1 −λ−−rλ

2r (1 +λ−−rλ ) = 1 2r + 4λ

xP = xL = 1 2r + 4λ.

(47)

First set of solutions : The exponential law

Let V be exponentially distributed with parameter λ > 0.

Then, f (x ) = λe−λx, f(t) = λ−tλ for t < λ and (f(t))0 = λ

(t−λ)2. Hence,

xP = 1 4

fr20

fr2

!

= 1 4

λ

(r2−λ)2

λ λ−−r2

= 1

2r + 4λ and

xL = 1 − f(−r )

2r (1 + f(−r )) = 1 −λ−−rλ

2r (1 +λ−−rλ ) = 1 2r + 4λ

xP = xL = 1 2r + 4λ.

(48)

First set of solutions : The exponential law

Let V be exponentially distributed with parameter λ > 0.

Then, f (x ) = λe−λx, f(t) = λ−tλ for t < λ and (f(t))0 = λ

(t−λ)2. Hence,

xP = 1 4

fr20

fr2

!

= 1 4

λ

(r2−λ)2

λ λ−−r2

= 1

2r + 4λ and

xL = 1 − f(−r )

2r (1 + f(−r )) = 1 −λ−−rλ

2r (1 +λ−−rλ ) = 1 2r + 4λ

xP = xL = 1 2r + 4λ.

(49)

Second set of solutions : A polynomial function

Let f(t) = a + bt + ct2. Then, (f(t))0 = b + 2ct

and we can compute the equilibrium efforts as xP = 14( b−cr

a−br2+cr 24 ) xL = 2r (1+a−br +cr1−a+br −cr22).

(50)

Second set of solutions : A polynomial function

Let f(t) = a + bt + ct2.

Then, (f(t))0 = b + 2ct

and we can compute the equilibrium efforts as xP = 14( b−cr

a−br2+cr 24 ) xL = 2r (1+a−br +cr1−a+br −cr22).

(51)

Second set of solutions : A polynomial function

Let f(t) = a + bt + ct2. Then, (f(t))0 = b + 2ct

and we can compute the equilibrium efforts as xP = 14( b−cr

a−br2+cr 24 ) xL = 2r (1+a−br +cr1−a+br −cr22).

(52)

Second set of solutions : A polynomial function

Let f(t) = a + bt + ct2. Then, (f(t))0 = b + 2ct

and we can compute the equilibrium efforts as xP = 14( b−cr

a−b2r+cr 24 )

xL = 2r (1+a−br +cr1−a+br −cr22).

(53)

Second set of solutions : A polynomial function

Let f(t) = a + bt + ct2. Then, (f(t))0 = b + 2ct

and we can compute the equilibrium efforts as xP = 14( b−cr

a−b2r+cr 24 ) xL = 2r (1+a−br +cr1−a+br −cr22).

(54)

Second set of solutions : A polynomial function

Both contests are strategically equivalent and f is a density function of a random variable iff a = 1, c = 0 and 0 < b < 2/r .

In that case, xP = xS = 2(2−br )b . Moreover,

f (t) = dirac(t) + b dirac(1, t), where dirac(1, t) denotes the derivative of dirac(t).

(55)

Second set of solutions : A polynomial function

Both contests are strategically equivalent and f is a density function of a random variable iff a = 1, c = 0 and 0 < b < 2/r .

In that case, xP = xS = 2(2−br )b .

Moreover,

f (t) = dirac(t) + b dirac(1, t), where dirac(1, t) denotes the derivative of dirac(t).

(56)

Second set of solutions : A polynomial function

Both contests are strategically equivalent and f is a density function of a random variable iff a = 1, c = 0 and 0 < b < 2/r .

In that case, xP = xS = 2(2−br )b . Moreover,

f (t) = dirac(t) + b dirac(1, t), where dirac(1, t) denotes the derivative of dirac(t).

(57)

Open question 1

Are these all possible solution?

(58)

The normal distribution

If the rent is normally distributed with mean V and variance σ2 then f(r ) = exp(rV + 12r2σ2) and (f(r ))0= r σ2+ V e12r2σ2+Vr. The contest equilibrium levels are then given by

xP = (f)0(−r2) 4f(−2r) = 1

4V −1 8r σ2 and

xL = 1 − f(−r )

2r (1 + f(−r )) = 1 − e12r2σ2−Vr

2r (1 + e12r2σ2−Vr) = 1

2r tanh(r

2(V −1 2r σ2)). Hence,

xP − xL = 2r (1 4V −1

8r σ2) − tanh(2r (1 4V −1

8r σ2)) > 0 since x ≥ tanh(x ) ∀x ≥ 0.

(59)

The normal distribution

If the rent is normally distributed with mean V and variance σ2 then f(r ) = exp(rV +12r2σ2) and (f(r ))0= r σ2+ V e12r2σ2+Vr.

The contest equilibrium levels are then given by

xP = (f)0(−r2) 4f(−2r) = 1

4V −1 8r σ2 and

xL = 1 − f(−r )

2r (1 + f(−r )) = 1 − e12r2σ2−Vr

2r (1 + e12r2σ2−Vr) = 1

2r tanh(r

2(V −1 2r σ2)). Hence,

xP − xL = 2r (1 4V −1

8r σ2) − tanh(2r (1 4V −1

8r σ2)) > 0 since x ≥ tanh(x ) ∀x ≥ 0.

(60)

The normal distribution

If the rent is normally distributed with mean V and variance σ2 then f(r ) = exp(rV +12r2σ2) and (f(r ))0= r σ2+ V e12r2σ2+Vr. The contest equilibrium levels are then given by

xP = (f)0(−r2) 4f(−2r) = 1

4V −1 8r σ2 and

xL = 1 − f(−r )

2r (1 + f(−r )) = 1 − e12r2σ2−Vr

2r (1 + e12r2σ2−Vr) = 1

2r tanh(r

2(V −1 2r σ2)). Hence,

xP − xL = 2r (1 4V −1

8r σ2) − tanh(2r (1 4V −1

8r σ2)) > 0 since x ≥ tanh(x ) ∀x ≥ 0.

(61)

The normal distribution

If the rent is normally distributed with mean V and variance σ2 then f(r ) = exp(rV +12r2σ2) and (f(r ))0= r σ2+ V e12r2σ2+Vr. The contest equilibrium levels are then given by

xP = (f)0(−r2) 4f(−2r) = 1

4V −1 8r σ2

and

xL = 1 − f(−r )

2r (1 + f(−r )) = 1 − e12r2σ2−Vr

2r (1 + e12r2σ2−Vr) = 1

2r tanh(r

2(V −1 2r σ2)). Hence,

xP − xL = 2r (1 4V −1

8r σ2) − tanh(2r (1 4V −1

8r σ2)) > 0 since x ≥ tanh(x ) ∀x ≥ 0.

(62)

The normal distribution

If the rent is normally distributed with mean V and variance σ2 then f(r ) = exp(rV +12r2σ2) and (f(r ))0= r σ2+ V e12r2σ2+Vr. The contest equilibrium levels are then given by

xP = (f)0(−r2) 4f(−2r) = 1

4V −1 8r σ2 and

xL = 1 − f(−r )

2r (1 + f(−r )) = 1 − e12r2σ2−Vr

2r (1 + e12r2σ2−Vr) = 1

2r tanh(r

2(V −1 2r σ2)).

Hence,

xP − xL = 2r (1 4V −1

8r σ2) − tanh(2r (1 4V −1

8r σ2)) > 0 since x ≥ tanh(x ) ∀x ≥ 0.

(63)

The normal distribution

If the rent is normally distributed with mean V and variance σ2 then f(r ) = exp(rV +12r2σ2) and (f(r ))0= r σ2+ V e12r2σ2+Vr. The contest equilibrium levels are then given by

xP = (f)0(−r2) 4f(−2r) = 1

4V −1 8r σ2 and

xL = 1 − f(−r )

2r (1 + f(−r )) = 1 − e12r2σ2−Vr

2r (1 + e12r2σ2−Vr) = 1

2r tanh(r

2(V −1 2r σ2)).

Hence,

(64)

The uniform distribution

If the rent is uniformally distributed on an invertavl [a, b] then f(r ) = er (b−a)rb−era and (f)0(r ) = −r2(a−b)1 ear − ebr− arear + brebr. The contest equilibrium levels are then given by

xP = 1 4r

1 e12ar − e12br



2e12ar − 2e12br+ are12ar − bre12br and

xL = e−br − e−ar + br − ar 2re−ar − 2re−br − 2ar2+ 2br2. Again, one can show that XP > XL.

(65)

The uniform distribution

If the rent is uniformally distributed on an invertavl [a, b] then f(r ) = er (b−a)rb−era and (f)0(r ) = −r2(a−b)1 ear − ebr− arear + brebr.

The contest equilibrium levels are then given by

xP = 1 4r

1 e12ar − e12br



2e12ar − 2e12br+ are12ar − bre12br and

xL = e−br − e−ar + br − ar 2re−ar − 2re−br − 2ar2+ 2br2. Again, one can show that XP > XL.

(66)

The uniform distribution

If the rent is uniformally distributed on an invertavl [a, b] then f(r ) = er (b−a)rb−era and (f)0(r ) = −r2(a−b)1 ear − ebr− arear + brebr.

The contest equilibrium levels are then given by

xP = 1 4r

1 e12ar − e12br



2e12ar − 2e12br+ are12ar − bre12br and

xL = e−br − e−ar + br − ar 2re−ar − 2re−br − 2ar2+ 2br2. Again, one can show that XP > XL.

(67)

The uniform distribution

If the rent is uniformally distributed on an invertavl [a, b] then f(r ) = er (b−a)rb−era and (f)0(r ) = −r2(a−b)1 ear − ebr− arear + brebr.

The contest equilibrium levels are then given by

xP = 1 4r

1 e12ar − e12br



2e12ar − 2e12br+ are12ar − bre12br

and

xL = e−br − e−ar + br − ar 2re−ar − 2re−br − 2ar2+ 2br2. Again, one can show that XP > XL.

(68)

The uniform distribution

If the rent is uniformally distributed on an invertavl [a, b] then f(r ) = er (b−a)rb−era and (f)0(r ) = −r2(a−b)1 ear − ebr− arear + brebr.

The contest equilibrium levels are then given by

xP = 1 4r

1 e12ar − e12br



2e12ar − 2e12br+ are12ar − bre12br and

xL = e−br − e−ar + br − ar 2re−ar − 2re−br − 2ar2+ 2br2.

Again, one can show that XP > XL.

(69)

The uniform distribution

If the rent is uniformally distributed on an invertavl [a, b] then f(r ) = er (b−a)rb−era and (f)0(r ) = −r2(a−b)1 ear − ebr− arear + brebr.

The contest equilibrium levels are then given by

xP = 1 4r

1 e12ar − e12br



2e12ar − 2e12br+ are12ar − bre12br and

xL = e−br − e−ar + br − ar 2re−ar − 2re−br − 2ar2+ 2br2.

(70)

Open question 2

Does the proportional contest always dominate the lottery contest?

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