C OMPOSITIO M ATHEMATICA
X U M INGWEI
The hyperosculating points of surfaces in P
3Compositio Mathematica, tome 70, n
o1 (1989), p. 27-49
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27
The hyperosculating points of surfaces in P3
XU MINGWEI
Institute of Mathematics, Academia Sinica, Beijing, P.R. of China
Received 2 May 1988; accepted in revised form 30 August 1988
Compositio 27-49,
© 1989 Kluwer Academic Publishers. Printed in the Netherlands
0. Introduction
Let X c
Pi
be a smooth surface overk,
where k is analgebraically
closedfield of characteristic p, and if =
O(1)
be the sheaf of linear sections of X.For any subspace h’
c V =H0(X, O(1)),
we have thefollowing canonical homomorphisms
where
PsX(1)
is the sheaf of thesth principal parts
of Y on X.Many
authorstreated al for the
generic subspaces
V’ of dimensions 2 and 3. It resulted ina
restudy
forpolar
loci(see
Kleiman[1] and
Piene[2]).
But it seems thatthere are few results about the
higher as
for the wholespace perhaps
forlacking
of"genericness".
For the space V the relevantquestions
seem to beas follows.
(a)
How to determine the least s whichmakes as injective?
The existence of such an s wasproved by
Mount andVillamayor
in[3]
for ageneral
case. In[5]
we called such an s a coordinate gapnumber,
denotedby b2(X).
(b)
How to describe the schemeI,
definedby
theFitting
ideal¡l’b2 -4 (coker ab2 ),
wherenb2
is the rankof Pb2X
Inparticular,
if dim I =0,
how toget
the0-cycle expression
ofI,
hence the number of itspoints (with corresponding multiplicities)?
Indeed thepoints
of I are thehyperosculating points
in thesense of Pohl
[4],
which were calledb2 -inflections
in[6]
so as tocorrespond
to the curve case.
(c)
What X hasonly
a finite number ofb2 -inflections? Corresponding
tothese
questions,
our main results are thefollowing.
(a) b2 =
2 orpm
for some m1; and b2 = pm if
andonly
if thedefining polynomial
for X can be written aswhere
pm
is thelargest
number for such a form.(b)
If X has a finite number ofpm-inflections
then the0-cycle expression
of I is
and therefore the number of
pm-inflections
is(c) If b2 - pm
anddeg X
= 1 +pm ,
then X has a finite number ofpm-inflections.
Furthermore,
for ageneric
surface inP3a with b2 = pm
anddeg X
=1 +
kpm,
the number ofb2(X)-inflections
is finite.Throughout
this paper wealways
assumep =1=
2.1. Coordinate gap number First let us set up notations.
Let X be a
non-degenerate,
smooth surface inP3,
and Y =O(1).
Wehave the canonical
homomorphisms
defined
by
where p, q : X x X ~ X denote the first and the second
projections, respectively, A
is thediagonal
in X xX,
and(9Ós
=OX X/s+10394, fA
is theideal of definition for A in X x X. For more details we refer to
[7].
DEFINITION: The least
integer
s which makes asinjective
is said to be coor-dinate gap
number,
denotedby b2(X). Obviously, b2
2.PROPOSITION 1.1: Let X be
defined by
thehomogeneous polynomial G(Xo, Xl , X2, X3).
The necessary andsuficient
conditionsfor b2
> 2 areGij =
0for
all
0 i, j 3,
whereGij
=~2G/~Xi~Xj;
inparticular,
we havedeg
G = 1 +
kp for
someinteger k
1.Proof:
See Theorem 3.1 and itscorollary
in[5].
Then
b2
> 2implies
p > 0.Therefore,
in what follows wealways
assumep is odd and
positive
since the caseb2 =
2 has been treated in[6].
LEMMA: There is a coordinate system in P3 such
that, if
thepolynomial for defining
X is G =Y-’ 0 XiFi(X0,
...,X3)pm,
then any twoof
the divisors[F0], [F1], [F2], [F3] on
X have no common component.Proof.-
Since X issmooth,
the linearsystem generated by [Fi] is base-point free,
so it determines amorphism
It is obvious that there are four linear
independent planes in 3,
such thatany two of their intersections with
F(X)
have no commoncomponent.
Thenpulling
them back toX,
we see that any twoof 03A33j
=0aijFj,
i =0,
... ,3,
withdet(aij)
=1= 0 for some constants aij, have no commoncomponent.
Therefore, considering
the transformationsbringing
G intoG’,
we haveand the
proof
iscomplete.
THEOREM 1.2 :
If b2
>2,
thenb2 = pm for
some m; andb2 = pm if
andonly if deg
X = 1 +kpm for
somek 1,
and thepolynomial for defining
X canbe written as
where
deg Fi
= k andpm
is thelargest exponential for
such anexpression.
Proof:
Sinceb2
>2,
we haveG¡j
=0;
so we can write G in the aboveform,
and theF’s
can be assumed tosatisfy
the assertion of the lemma sinceb2 (X )
and
pm
are invariant under anonsingular
linear transform.Let us calculate
b2(X)
as follows. Without loss ofgenerality,
we canassume F3 ~
0. On U =(X0 ~ 0)
n(F3 i= 0)
let us take x =X1/X0, y = X2/X0, z = X3/X0
to be the affinecoordinates,
and calculateb2(X)
neara
point Q = (x0, y0, z0) ~
U. For this purpose consider thecompletion
R ofthe
regular
localring B = OX,Q
withrespect
to its maximalideal,
which hasa
system
of uniformparameters {x -
x0, y -y0}.
Since(OX(1))Q ~ OX,Q
and B ~ its
image
inR,
we canidentify VQ
with theimage
of B ~ Bx G)By ffl Bz
in R Q RxQ Ry
QRz, PsX(1)Q
with itsimage
inPsR,
and as,Qwith dsR·~ by definition, where 0: B ~ Bx Q By ~ Bz ~ B
+ Bx +By
+ Bz cR, dsR = idR
+TsR : R ~ PsR,
andTR
is theoperator
of s-truncatedTaylor
series(see [3]).
Now
PR
is a free R-module with basis1, dx, dy,
...(dx)S , (dxy-ldy,
...,
(dy)s,
andas,Q(z) = dsR·~(z)
isuniquely expressed
aswhere
Ri, Rj e R, s »
0.Moreover,
on X we haveSetting Fi(1,
x, y,z) = f (x, y, z) ~ B ~ R,
weget
where dx = 1 (D x - x Q 1.
Writing
we then have
Substituting (*)
into(**)
andidentifying
the coefficientsof dx, dy, dx2 , dxdy, dy2,
... with zero, we obtainObviously, R0,pm, Rpm,0
E B =OX,Q.
From
( 1 )-(4),
we seethat b2(X) pm.
We concludethat b2 = pm.
Other-wise,
we would haveR0,pm = Rpm,0 = 0 in (9x,Q.
Then there is aneighborhood
U’ c U
of Q
such thatR0,pm
andRpm,o
vanish on U’. On the otherhand,
onU’ we have
and
where
Fji(X0,
...,X3) = ~Fj/~Xi.
Therefore it follows from(4)
that on U’we have
But since X is
irreducible, (***)i, (i
=1, 2)
is valid on X.Moreover,
let usverify
that(***)i
is valid for i =0,
3:(***)3
is anidentity;
as for(***)0, multiplying X
to(***)i (i
=1, 2, 3),
thensumming
them up, we obtainSince
we have
so
(***)o is
valid.Now we claim that
In
fact,
from(***)
we see thatFpm3
= 0implies Fp2mi (03A3jXjFpmji)
=0;
therefore, [Fp2m3] [Fp2mi(03A3j XjFpmji)]
as divisors on X.By
thelemma, [Fp2m3]
and
[Fp2mi ] (i
=13)
have no commoncomponents,
hence[Fp2m3] [03A3j XjFpmji].
On the other
hand,
sincedeg [F3P2’ ]
=(deg X)(kp2m)
>deg[I:j XjFpmji]
=( pm (k - 1)
+1)deg X,
we see that(****)
are validon X,
hence our claimsince
deg
G >deg(03A3j XjFpmji).
The
difi’erentiating (****)
withrespect
toXj,
weobtain Fji
= 0 forall i,
j,
and therefore eachFi
can bewritten
asHi(Xp0, ..., Xp3),
which contradictsour choice
of pm.
Theproof is complete.
2.
p"‘-inflections
DEFINITION: Let the coordinate gap number of X be
b2.
TheFitting
idealËb2 -4 (coker ab2 )
defines a subschemeI in X,
calledb2-inflection
locus. And33
a
point
of I is said to be ab2-inflection;
themultiplicity
of an inflection is defined as themultiplicity
of thepoint
in I.In
[6]
we have treated the 2-inflection locusalready,
atpresent
we workonly
onb2 = pm, where m
1. For this purpose weproceed
in severalsteps
as follows.
Step
1. Thefundamental diagrams [ 7]
The
following diagrams
are fundamental for our purpose:where ao, al are
surjective
since X issmooth;
-X’ =ker al
and lff = ker ao, hence the rows in(A1)
are exact; moreover, the second column from theright
is exactaccording
to the structure ofPsX(),
andby
5-lemma the second column from the left also is exact.Similarly,
we havewhere sm denotes the
operator
of the m-thsymmetric product, 03A9X
the sheafof Kähler differentials.
In
(A2),
thehomomorphism a2 · i
factorsthrough (SIÇI,)(Y).
More-over, a2
·i(K) =
0.Otherwise, by
the exactness of theright column,
we would have
that a2
isinjective, contradicting pm
> 2. Thusker a2 ~ K
and
im(a2) ~ P1X(). Inductively proceeding
up to(Apm-1),
we haveker(apm-1) ~
K andim(apm-1)
=P1X(). Finally,
in(Apm),
we have a com-mutative
diagram
with exact rows and columnsSinceA’7
=id.: P1X() ~ Ppm-1X() ~ P1X(), where h = b2··· bpm-1,
the bottom row is
splitting,
and then(coker j )
islocally
free.By
theproperty
ofFitting
ideal(see [9]), fp--4 (coker apm) = F(pm+2)-42(coker apm) =
Fpm(coker i). Locally, nx
are free in an open set.Taking
the open set as the one in Section1,
we may assumedx, dy
to be the basisof 03A9X, z
to thatof Therefore,
and
Fpm(coker i )
isgenerated by (Rij)i+j=pm.
35
Step
2.Passing
to ELet E =
Proj
Si =P(&’)
and Y =P(03A9X()).
We have adiagram
where and a are the structure
morphism
of Eand Y, respectively; 03B2
isdefined
by
thehomomorphism:
0 ~ ~Vx
in(Al); , f ’
is a rational map determinedby 6 - 03A9X()
in(Al). Indeed, E
is the incidencevariety
of Xin
P3, i.e.,
E ={(x, h)
E X x3|x
EH,
where h isrepresented by Hi.
Therefore E is the space of linear sections of X
parameterized by 3,
and03B2-1 (point) corresponds uniquely
to a divisorG 1 [Y] 1.
On
E,
consider thecomposition
where
Spm03C0*03A9X() ~ Sp"lQE(n* 2)
is determinedby
the exact sequenceSpm03A9E ~ Spm03A9E/3
is determinedby
the exact sequenceThe left side of
(3)
isinjective
at the smoothpoints
ofj8.
The scheme ofsingular
locusof fi
isexactly
that ofsingular points
of the fiber offi (cf. [], IIID),
so it turns out to beP(), i.e.,
the subscheme{(Q
EX,
thetangent plane
sectionpassing Q)}
cE,
inother words,,
theprojective
conormalbundle of X in
P3.
Write W = E -P().
Now we take an open set U ~ X small
enough that {1,
x, y,z}
is a basisof VX when restricted in U, i.e., VU = {~
+ Àx + my +vzl; besides,
we canassume that
{x,
y,z}
is a basisof & 1 u,
and z is a basisof 1 u; it
follows that(x, y)
is the local coordinate inU, (17, Â,
Il,v)
is the coordinate in03C0-1(U).
QE
e3 islocally
free in W n U with rank 1.Identifying E
with a subschemeof X 3 = P(X),
we have an exact sequenceOX 3 ( - E )
is the ideal of definition for Ein X 3, which
canlocally
beexpressed
ars 1+ Âx
+ My + vz, hence03C8(~
+ Àx + My +vz) = Â
dx +pdy
+v dz ;
sinceal (z) -
0 onE,
we haveQE/P3
=(9Edx
+OEdy
mod( dx
+Il dy).
It follows from the discussion above that
A(z) = (03A3i+j=pm Rij03BBj03BCi t)
and tis a basis of
QE/P3’
henceF0(coker A)
isgenerated by (03A3i+j=pm Rij)! Ili)
onW n
U;
thereforeF0(coker A)
defines a scheme J’ withcodimWJ’ -
1.By
sequences(1)
and(3),
andapplying
Porteous’formula,
we haveSince
A4Q£
= the canonical sheafKE
of E and03B2*03A93 ~ fl*(9(- 4) ~ OE(- 4), finally
we haveStep
3.Passing
to YLet us consider the
diagram (B)
and the rational mapf
once more. Thehomomorphism é - 03A9X()
canlocally
beexpressed
as Âx + My +vz H Âx + My, hence the map is a
correspondence
with(x, y; Â,
y,v)
H(x,
y;03BB, Il)
and defined on W = E -P(K).
The closure J of the scheme- theoretic inverseimage
of J’ in Y is definedby
ideal(03A3i+j=pm RUAi lli),
thesame form for
defining J’;
in otherwords,
the scheme-theoreticimage
of Jcoincides with J’
on W, i.e., f-1(J) =
J’.In virtue of
codimEP() =
2 on E and well-known facts(e.g.,
see[8]),
we have Pic W ~ Pic E ~ n*Pic X
+ {OE(1)};
moreover, Pic Y =a*Pic X +
{OY(1)}
on Y.Therefore,
it followsfrom f*(03B1*Pic X) =
n*Pic Xand f*OY(1)
=OE(1) that f*
is anisomorphism (noting
that oc* and 03C0* aresplitting).
On the other
side,
we have thefollowing
exact sequences on E:and
Therefore,
weget
hence
This shows that the ideal of definition for J is
isomorphic
toStep
4.Passing
to ZLet Z =
P(Spm03A9X() ).
We have an immersion g : Y ~ Z overX,
definedby OY(pm):
Alternatively g
is definedby
thefollowing composition
ofhomomorphisms
Locally,
it turns out to be the Veronesemorphism (cf. [10]).
Let us show that there exists a
unique
divisor D on Z such that D n Y = J.In
fact, by Step 1,
for everypoint Q
E X there is aneighborhood U of Q
suchthat J is defined by (03A3i+j=pm Rij03BBj03BCi) on 03B1-1(U), so g*:03B1-1(U) ~ 03B3-1(U) can
be
expressed
as(x,
y;03BB, Il)
H(x,
y;Apm, 03BBpm-1 03BC,
...,Ir),
and therefore1
Rij 03BBj 03BCi
H 1Rij Tij is
an 1-1correspondence
between the set ofpm-forms
in03BB, 03BC
and the set of 1-forms inTij. Then,
on each03B1-1(U)
there exists such aD and these forms are invariant under linear
transformations,
so we canpiece
themtogether
toget
such an effective divisor D on Z as desired.Now,
the idealOZ(- D)
can be determined as follows. Sinceg*(y*
PicZ) =
a* Pic
Y and g*OZ(1)
=OY(pm),
we see thatg* :
Pic Z ~ Pic Y isinjective by
the same reasons as shown inStep 1;
moreoverConsequently
LEMMA:
F"(coker i )
=Fpm-1(03A9D/X).
Proof:
Consider thefollowing
exact sequencewhere
OD(-D)
islocally generated by 1 Rij Tij.
Ineach {Trs ~ 01
lettij
=Tij/Trs.
Then03B4(03A3 Rijtij)
=dz/x(I: Rijtij)
= 03A3Rijdtij. Consequently
Fpm -1
(03A9D/X)
isgenerated by (Rij)i+j=pm
whichis just y *FI’ (coker i),
as shownin
Step
1.Note that the lemma shows that
Fpm-1(03A9D/X)
defines the schemey-1 (I ) by
the
properties
ofFitting
ideals(e.g.
see[9]);
this is a newstarting-point
ofour argument.
Step
5.Pulling
back to YThen we have the exact sequence
which
defines f
as the kernel. On the otherhand,
in thefollowing
exactsequence
O(-J)|J 03A9Y/X|J ~ fljlx --+
0 we have 6 = 0. Infact,
fromSection
1, (1)-(4), we
havelocally O(-J)
=(R03BBpm
+Se),
where R -R0,pm,
s =
Rpm,0,
so03C3(R(x, y)ÂP’
+S(x, y)03BCpm = dY/X(R03BBpm
+Sllpm) =
0. Conse-quently 03A9Y/X|J ~ 03A9J/X,
thus it is alocally
free sheaf of rank 1.Using (6)
wethen have
Consider the fundamental
diagrams
for Z ~ X andOZ(1).
In a similar way toStep
1 we haveand
(A2)’, (A3)’,
...,(Apm)’.
Let tij
=Tij/T0pm be
the affine coordinates on03B3-1(U) =
U x PP’. Then{tij}
is a basisOf Qz/x(1).
In
(As)"
for any s, thehomomorphism
factors
through Hs(1),
the kernel of thefollowing composition
Twisting a’s·i’
withO(-1),
we obtainIn
addition,
we have the natural maps(see [ 11 ]),
which can belocally expressed
as(dtij)r
HTr(03BBi) for r s,
whereTr(03BBi)
=(03BB
+dÂ)’ - Â’
is the r-truncatedTaylor
series of Âi.Let
Fs
be the kernel ofThen we
have us : g*Hs ~ Js. Setting ’s
= u, -g*vs,
we have thefollowing
commutative
diagram:
where ( = 03B6pm-1|J, ~ is a
self-évidentsurjective
map, and the bottom row isjust (6).
Let us showthat (
is alsosurjective.
Infact,
rankQz/x =
rankJpm-1
+ 1 =pm ,
andlocally,
a basis ofg*Qz/x is {tij},
where i+ j = pm
and i ~
0,
a basis off7P"’-1
is{d03BB, (d03BB)2,
... ,(d03BB)pm-1},
moreover,((tij)
=Tpm-1(03BBi)
=03A3n~i(in)03BBnd03BBi-n
for ipm
and((tpm,o)
=0,
and therefore the matrixof (
withrespect
to these bases isConsequently (
issurjective.
Let W be the kernel of
0,
N the kernel ofg*03A9Z/X|J
-and J
thekernel
of (.
Then we have ahomomorphism i:
~fi
with its kernel and cokernel 1.Now,
we have thefollowing diagram:
Moreover from the exact sequence
we known that
g*OD(-D)
=OJ(-J) ~ N
issurjective, hence 03BE
iszero.
Indeed,
it follows fromStep
3 thatOJ(-J)
isgenerated locally by
RApm +
Se,
so((RApm
+Se)
=0,
and therefore U = and A = X.In the
diagram above,
let us break up the left column into twoparts:
where the sheaf 1 is
locally free,
and(b)
can bereplaced by
Then we can prove the
following proposition:
PROPOSITION 2.1:
03B1-1(I) is defined by F0(Im 1").
Proof:
From the lemma we see that03B3-1(I)
is definedby Fpm-1(03A9D/X),
soa-’ (I )
is definedby g*Fpm-1(03A9D/X) = Fpm-1 (g*03A9D/X). Moreover, applying
Fpm-1
to the bottom row of thediagram
above andnoting
rankni/x
=1,
we have
Fpm-1(g*03A9D/X) = Fpm-2().
Nowapplying
Fp"’ - 2 to(a)
andnoting
rank 1 =
pm - 2,
we obtain what we want.THEOREM 2.2:
If
X hasonly
afinite
numberof p’"-inflections, then,
as acycle,
where
[KX]
denotes the divisor associated withKX,
etc.,[KX]2
is the intersectionof
divisors and ci is the operatorof
i-th Chern class.Consequently
Proof: By
ourhypothesis, codimJ03B1-1(I)
= 1. Since(b)’
is the resolution of(Im r),
it follows fromProposition 2.1,
that I isexactly
thedegeneracy
locusof
(9J( - J) ~
with rank J =1,
hence it has a "correct dimension". Thenapplying
Porteous’ formula to(b)’ (cf. [8]
in thesimplest case),
we haveLet us calculate cl
().
Sinceis exact, we have
From
and the
splitting principle,
we also haveAs for el
(Jpm-1), using
the séquence fordefining Jpm-1 and
the fundamentaldiagrams
ofY/X,
we obtainMoreover, by
the last formula inStep 3,
we seehence
Since a is flat we have
[a-’(I)]
=a*[I].
So from theprojection
formula03B1*(c1(O(1))
na*[I]) = [I]
we seewhere si
is theoperator
of the i-thSegre class,
henceThe
proof
iscomplete.
EXAMPLE:
Suppose
that X is definedby
We shall prove in the next section that X has
only
a finite number ofp-inflections.
Then Theorem 2.2 tells usIt is
interesting
that this result canget
verifiedby
a direct calculation.In affine coordinates the
equation
isAccording
to the notations in Section 1 we haveThen we have three groups of solutions as follows.
(1) x = 0, y = 0
and z=ei(i== 1, ... , p + 1), where ei
are the(p
+1)th
roots of - 1.By
thesymmetry
of theequation,
these solutions amount to6(p
+1).
(2)
x =0, zp2-1 - yp2-1 =
0.Let y =
wiz( j
=1, ..., p2 - 1), where wy are the (p2 - 1 )th roots of unity. Then we have whenever ( 1
+wp+1j) ~ 0,
the
equation
has(p
+1)
solutions for z. Since suchwy’s
amount to( p2 -
p -2),
this group consists of4(p
+1)(p2 - p - 2)
elementsby
symmetry again.
(3) Xp2-l = yp2-1 = zp2-1 =
0.Substituting
x = wizand y =
wjz into theequation where wi and wj
are the(p2 - l)th
roots ofunity,
we haveIf
(1
+Wf+l
+wp+1j) ~ 0,
then there are( p
+1)
solutions for z. If 1 + wi =0,
then we have(1
+wp+
1 +wp+1j) ~
0 for every wj, so the number of(w. wj)
with1 + wp+1i = 0
and 1 +wp+
1 +wp+1j
1 ~ 0 is(p
+1)(p2 - 1).
If 1 +Wf+l =1= 0,
the numberof wi
with 1 +wp+1i
+wp+
1 = 0 is( p
+1),
the number of(wi, wj)
with 1 +wp+1i ~
0 and1 +
wp+1i
+Wf+l =1= 0 is (p2 -
1 -(p
+1))2.
In sum, all these solutionsamount to
( p
+1)3(p2 - 3p
+3).
Consequently
the total number of solutions is the very same number asgiven by
Theorem2,
2.3. Finiteness
Let us
adopt
all the notations in Section 1. Letdeg X = 1
+kpm
andb2(X) = pm.
Thenby
Theorem1.2,
for some coordinatesystem,
X is definedby
Suppose
that C is irreducible and reduced curve onX,
and[F]*
(i
=0,
... ,3)
are divisors determinedby
sections ofF,
on C. We say that C possesses theproperty (GX)
if it satisfies thefollowing
conditions:(a)
Notwo of divisors
[Fi]*
have commoncomponent point; (b)
C is not containedin
any X
= 0 for i =0,
... , 3.LEMMA 1 :
Suppose
C possesses(GX)
and is contained in thepm - inflection
locusof X. Then,
on C we haveProof:
Since C cI by
ourhypothesis,
we haveR0pm 1 c
= 0 =Rpmo 1 c,
henceby
Section1, (4),
on CThen, nothing
remains but to imitate theargument
in Section1, nearly
verbatim.
LEMMA 2: For the
given
C on X there is a ùoordinate system under which C possesses(GX)
where G is thepolynomial for defining
X.Proof:
Theproof
is also similar to that of the lemma in Section 1. It is sufficient to find out fourindependent planes suçh
that the intersection of any two of them does not meet theimage
of C inP3.
Inaddition,
since sucha choice is
generic, pulling
them back toP3
we can still choose coordinateplanes,
notcontaining
C.LEMMA 3:
If for
some coordinate system we have*)i 1 c
= 0for
all i, so dowe
for
any other system.Proof:
Assume in coordinate{xi}
we haveon C. Let
where det
(aij) ~
0 and(aij)-1 = (bij).
Then the
polynomial
G is transformed intoso we have
and
Hence the lemma.
THEOREM 3.1 : C c I
if and only if (****)i|C = 0 for
i =0,
... ,3.
Proof:
A direct consequence of lemma1, 2,
3.PROPOSITION 3.2:
If deg X
= 1+ pm
andb2(X) = pm,
then X hasonly a finite
numberof pm-inflections.
Proof: By
ourhypothesis, Fi
=03A33j=0 aijXj,
anddet (aij)
is invertible. Then(****)i(i
=0,
... ,3)
areexpressed
ashence the solution of
(****)
contains no curve.The
following examples
show that there are surfaces which take curves aspm-inflection
locus even if p does not divide k =deg Fi.
EXAMPLE: G =
X0(Xp0
+X0Xp-11)pm-1
+Xl (XJXf-2
+Xp1)pm-1
+Xpm+12
1 +Xpm+13.
ThenF j2 = F j3 =
0 forall j,
and the sections ofplanes Xo =
0 andXI =
0 on X both are contained in I.EXAMPLE: G =
X0(X20
+ 2 .3p-m X0X1
+3p-m X21)pm
+2X2pm0X1
+X2(X22 -
2 .
3,P-’X2X3
+3p-m X23)pm
+2X3 X2pm2.
Then the line{X0 = Xl , X2 = X3}
iscontained in I.
In
general,
we haveTHEOREM 3.3: Under
a fixed
coordinate system, ageneric surface
withb2 - pm
and
deg
X = 1 +kpm
hasonly
afinite
numberof pm-inflections.
Proof.
The surfaces withb2(X) = pm
anddeg
X = 1 +kpm
are determineduniquely by Fo,
... ,F3
up to a constantmultiplication,
thus the setof such surfaces can be
parametrized by
an open setSk,pm
inPN,
whereN =
4(k+33) -
1.Let Y
be the surface definedby (****)i. Then Yi
is smooth if andonly
ifthe four surfaces
Fji(j = 0, ... , 3)
have no commonpoint
inP3;
it is wellknown that this is an open condition of those coefficients in
Fji(j
=0, ... , 3),
so hereafter we assume all
the Y
are smooth. Now fixYo
and take apoint Q
inYo .
The section of a surfacethrough Q,
cut outby Yo, is singular at Q
if and
only
if the surface istangent
toYo
atQ. A general
surfacetangent
toYo at Q
submits to 3independent equations,
so we seeby
dimensioncomputations
that the subset ofSk,pm consisting
of those surfaces to whichthe corresponding Y,
aretangent
toY0, has
dimension(4(k-1+33) - 1)
+ 5.Since dim
Sk,pm - 4(k+23) -
4 =2(k
+1)(k
+2) -
5 >0,
it follows that almost every surfaces inSk,pm
has theproperty
that itsYI,
cut outby Yo,
gives
a smooth section.Moreover,
since the divisor onYo,
determinedby
this
section,
isample,
the section is connected andconseqûently
irreducible.It follows that the
homogeneous
ideal(03A3XjFpmj0, 03A3 XjFpmj1)
isprime.
Now weshow that to a
general point
inSk,pm
thecorresponding Y2
intersects itsYo n Fi in
a finite number ofpoints only.
If to thecontrary,
the intersection would contain a curve, thus itcoinciding
with the intersection ofYo and Y,
since the latter is irreducible.
By
Nullstellensatz we have03A3 XjFpmj2
E(03A3XjFpmj0, 03A3 XjFpmj1),
hence03A3 XjFpmj2
=a 03A3XjFpmj0
+b 03A3 XjFpmj1
where a and b are con- stants for the sake ofdegree.
Differentiating
them withrespect
toXi,
we obtainF2"’
=aFô
+bffm,
where j = 0,
... , 3 and(a, b) =1 0,
thusresulting
in3(k+23) -
1 relationsamong their coefficients. Since dim
Sk,p"’ - 3(k+23)
+ 1 >0,
we concludefinally
that the scheme definedby (****)
of ageneral point
inSk,pm
containsno curve.
Therefore,
ourproof is complete by
3.1.References
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Oslo (1977) pp. 297-396.
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196-235.
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