C OMPOSITIO M ATHEMATICA
R. R. H ALL
G. T ENENBAUM
The average orders of Hooley’s ∆
r-functions, II
Compositio Mathematica, tome 60, n
o2 (1986), p. 163-186
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163
THE AVERAGE ORDERS OF HOOLEY’S
0394r-FUNCTIONS,
IIR.R. Hall and G. Tenenbaum
C Martinus Nijhoff Publishers, Dordrecht - Printed in the Netherlands
Introduction
In this paper we
determine,
to within a factor(log n) 0(1),
the average order of the arithmetical functionintroduced
by Hooley [4]
and shownby
him to be relevant in thestudy
of
Waring’s
Problem and in certainproblems
ofDiophantine Approxi-
mation. It is usual to write à instead
of 2
and setAI
= 1.One of us
[9]
hasrecently pointed
out that the ratio03B4(n)/03C4(n)
may beinterpreted
as a concentration function in the sense of PaulLévy (1937)
and the observation may be extended to03B4r(n)/03C4r(n).
Here03C4r(n)
denotes the number of ways of
writing n
as theproduct
of rfactors,
T
= T2 ).
In fact suchproblems
in thesubject
area which has been called thepropinquity
of divisors[1], [2]
are more than 45 yearsold, dating
atleast as far back as Erdôs’notorious
conjecture
that almost allintegers
have divisors
d, d’
such that d d ’ 2d. This hasonly recently
beensettled
by
Maier and Tenenbaum[7].
We prove the
following theorems, generalizing
the recent result ofTenenbaum
[9] concerning
the case r = 2.Throughout
the paper we writelog2x, log3x
instead ofloglog
x,logloglog
x. The constantimplied by Vinogradov’s
notation « is ab-solute,
or, if there aresuscripts, depends
at most on these.If,
forinstance,
we insert the estimate of Theorem 1 with r = 3 inHooley’s
upper bound method[4]
for the numberr8(n)
ofrepresenta-
tions of theinteger n
as a sum ofeight positive cubes,
we obtainThis falls
relatively
close to theexpected
true order ofmagnitude n5/3.
Let
a ( N )
denote the number of distinctprime
factors of N. We now turn our attention toweighted
versions of the sum considered in Theo-rem
1, namely
we considerfor y
> 0. Thisgeneralization
appearsgenuinely
in someapplications and, taking advantage
of the drastic variations of theweights,
enablesone
pratically
to evaluate the sum of0394r(N)
restricted to thoseintegers
N x
having
aprescribed
number ofprime
factors.First,
we note thatTheorem 1 has the
following
This follows very
simply
from Theorem 1 if we remark that(the inequality
extends(23)
of[9]), just inverting
summations.The case y 1 is more difficult. We have
THEOREM 2: For r
2,
x16,
and0 y
1 we havewhere a is an absolu te" constant.
The
exponents
oflog
x in these results are bestpossible
in view of theinequality 0394r(N) max{1, ’Tr(N)/(log eN)r-1}.
Both Theorem 1 and itscorollary
arespecial
cases(t
=1)
of thefollowing
moregeneral
THEOREM 3 : Let r E Z
+,
t, y E Rsatisfy
r2,
t 1 and y( r - 1) tl(r’
t-
1).
Thenwhere
8(r,
t,y)
=r ty - ( r - 1) t
and yr isdefined
as in Theorem 1.Again,
theexponent
oflog
x issharp. For y (r - 1)t/(rt - 1)
thisexponent
must be atleast y - 1,
and wemight expect
ageneralization
ofTheorem 2.
However,
when t > 1 ourproof
fails - instead we deduce from Theorem 3 theCOROLLARY: Let r, t be as
above,
y( r - 1)t/(rt - 1).
ThenIn
previous
papers[3,4,5]
we definedWe see now that
for every r
1, y
> 0. This was known[3], [5] provided y
was outside anexcluded interval
(1 2, 039B+r), (where 039B+r ~ (1, 1
+1/~3)
is a function ofr).
Anexàmination
of theproofs
shows that forsuch y
the upper bounds forSr(x, y)
which could be obtained were better than thepresent
ones. Thus from[5]
we may deduce thatThe result
for y 2
issharp. Again
in[3],
if we re-definethen Theorem 1
[3] holds,
as stated. This raises aninteresting question
about the status of the various methods. It would be useful to know to what extent the
present technique (which already
has twovariants,
as inthe
proofs
of Theorems 2 and 3above),
can besharpened. Certainly
thequestion
of lower bounds has been somewhatneglected:
as far as we areaware
nothing
better thanS,(x, 1)
» xlog log
x is known for any r.2. Two lemmas LEMMA 1: We have
PROOF : We have
where
{x}
denotes the fractionalpart
of x. HenceDifferentiating,
The third term on the
right
isnegative.
The second does not exceedHence
The
proof
iscompleted by
the estimateLEMMA 2: Let
L(a), X(a)
becontinuously differentiable for
1 a (Jo andsatisfy respectively
where
~(03C3, x)
is anon-decreasing function of
xfor
eachfixed
(J. LetL(03C30) X(03C30).
ThenL(03C3) X(a) throughout
the range 1 a ao.PROOF:
Suppose
thecontrary.
Then there exists03C31 ~ (1, 03C30)
such thatL(03C31)
=X(03C31), L(03C3) X(a)
for a E(al, cr.).
Thenwhich is a contradiction.
3. The main lemma We
define,
for ul, u2, ... ,ur-1 ~
R.so that
the maximum
being
attained at(vl’ v2, ... , vr-1)
say. Forpositive
in-tegers q
we defineso that in
particular M1(n) = 03C4r(n)
andWe need an
inequality
in theopposite
direction. Let E = 0 or1, vi ui vl + 1, 1 i r.
Thenwhere the sum is over all
2 r -1
choices of the fi’ Thusand we
integrate
this over thecube vi ul vl
+ 1. Since there is nooverlapping
weget
We have to consider more
general integrals
thanMq(n).
Leta o, a1, ... , ar-1 be
non-negative integers
whose sum is q, and w ~ R.We define
where w is
subtracted,
in turn, from each ui in the last r - 1 factors of theintegrand.
Ourobjective
in this section isLEMMA 3 : Provided
max{a0,
a1, ... ,ar-1}
q - 1 we havewhere C is an absolute constant and
for
s 1 wedefine
(We
write03941(d)
= 1 so thatD1(m)
=03C4(m)).
PROOF:
By
successiveapplications
of Hôlder’sinequality
we may reduce to the case where there arejust
two non-zeroexponents a i and ak
say,where
1 * a j, ak q - 1, aj + ak = q.
There are then two cases accord-ing
asmin( j, k) = 0
or not. Of course when r = 2only
the first case occurs.In the first case we may suppose without loss of
generality that j
=0,
k = 1 and we write ao = a,
al = b.
Webegin by estimating
the sumwhere * denotes the
following
conditions of summation:so that we must have
It follows that
Hence the sum under consideration does not exceed
where the conditions of summation are marked
~
above. Forpositive integers b
we defineWe consider the
integral
which does not exceed
2bVb(m;
u2, ... ,ur - 1).
On the other hand this lastintegral is
where the condition marked
( * ~) applies
to the sums. Henceand we have
performing
theintegration
w.r.t. ul. Recall that1 a, b q -
1. Hôlder’sinequality gives
Since a + b = q, the last
integral
above does not exceedNotice that
We
apply
this upper bound to the factorV1
in the aboveintegral, leaving
an
exponent 1/(q - 1),
and thenapply
Hôlder’sinequality
to the re-maining multiple integral,
withexponents q - 1, ( q - 1)/(q - 2).
Sincewe obtain the result stated in this case.
Now suppose
min( j, k)
> 0. We make a furtherreduction, by
meansof
Hôlder,
to the case where the non-zeroexponents
are 1and q - 1,
saya1=1, a2=q-1.
We have to estimate
and we make the substitution u2 = w +
log
p. Now consider the sumwith the summation conditions
Notice that we must
have ul
+ wlog(d1d2) u1
+ w + 2. Hence thesum does not exceed
where in the inner sum, we
require
so that this does not exceed C. We now have
Therefore
and the
required
result is established in this case too. Thiscompletes
theproof
of Lemma 3.4. Proof of Theorem 3 We are
going
to show that forl,
r EZ +,
t 1 andthere exists a constant
C( l,
r, t,y )
such thatwhere 03B2(r, t, y) := rty - ( r - 1)t
and the sum is restricted to square freen. This will be done
by
induction on r, with anexplicit
upper bound forC( l,
r, t,y).
We may thenoptimize
our choice of 1 on theright
handside for
given
r, t, y and a. It is then astraightforward
matter tochange
over from the sum on the left to
Sr(x; t, y ).
Let 1 ~ 7L + be
initially fixed,
and for r ~ Z+set q
= 1 + r, and defineso that
differentiating
w.r.t. a we haveFor
integers m
andprimes p
suchthat p
m, we haveand we raise to the power q and
integrate,
to obtainWe
pick
out thediagonal
terms in which some al = q,noting
thatThere are r such terms and we deduce that
for q t,
where the *
signifies
thatmax al q -
1 and the factor r arises as anupper bound for the
q-th
root of any multinomial coefficient. HenceIn the first term on the
right
we estimate the sum over p from aboveusing
Lemma 1. Weapply
Hôlder’sinequality
withexponents q/t, q/(q - t )
to the sum over p in the second term. Thisyields
We
drop
theexponent
a in the inner sum andapply
Lemma3,
whichyields
by
Hôlder’sinequality
withexponents q - 1, ( q - 1)/( q - 2).
Recall thatWe
apply
Hôlder’sinequality
to the sum on theright,
with exponentst/( t - 1), t and 03B6 = (r - 1)1-1/t,
whichyields (for squarefree m )
Hence we have
Now let r
2, y ( r - 1) t/( r t - 1).
We assume our inductionhypothe-
sis is valid for r -
1,
viz.provided
z( r - 2) t/(( r - 1) t - 1), (z
0 when r =2).
Weapply
thiswith z =
rt - 1y/( r - 1)t -1
which ispermissible
because for r2, t 1,
we have
We also have that
for 1 03C3 2. Hence in this range,
Recalling
that 1 + r = q, we deduce that for 1 03C32,
and for the relevant valuesof y,
and hence that
where we have used the
inequality
and
simplified
theexponent
of Q - 1. Next weapply
Lemma 2. Thecorresponding
differentialequation
has the solutionX(a)
=K(a - 1) - Y
where y satisfies
whence
Next,
We
put
03C30 = 2 and werequire
thatL (2) X(2)
= K. Recall thatMq(n) 03C4r(n)q
whenceObviously
C 1 and we assume thatC( l,
r -1, t, z)
1 for relevantvalues of
l,
t, z. Since 03B3rty
it is clear that K >2"Y.
Lemma 2yields
with K as
above,
and we deduce from(1)
thatwith
C( l, r, t, y) = 2r-1K.
Since we may takeC( l, 1, t, y) = 2y
forevery
l, t
and y, the induction iscomplete.
We
require
an upper bound forC(l,
r, t,y).
In the formula forK,
we havebecause the function on the left decreases as y increases
beyond (r -
1)t/(rt - 1).
The function on theright
decreases as tincreases,
and sincer1/q
1 +3r(r - 1)/7q
for q r2,
when t = 1 it does not exceed14q/r(r - 1).
So we havewhere B =
max{84r-1/r!(r -1)!} e12.5, noticing
that2r-1r!
r r. We choose 1 to be the leastinteger
for whichso that
provided 1 03C3 03C31(r, t )
say, we obtainand
clearly
this is valid over the wholerange
1 03C3 2.We extend the sum on the left to all
integers following Hooley [6]
andTenenbaum
[9]. Any integer
N may be written in the formN = nd2
where n issquarefree,
and we have0394r(N) 0394r(n)03C4r(d2).
HenceThe sum over d on the
right
is« r,t,y 1.
Weput
Q = 1 +1/log x
so thatfor x à
16 we havewhich is
clearly
valid for all x.Finally,
as in[9]
we haveFor the first sum on the
right
we use the upper boundproved
above. Inthe
second,
weapply
theinequality 0394r(nm) 0394r(n)03C4r(m)
and reversethe order of
summation, noting
thatThis
yields
a sum« r,t, y
thatalready
considered. Theproof
iscomplete.
5. Proof of the
corollary
We have
y (r-1)t/(rt-1).
Since theright
hand side is astrictly decreasing
functionof t, tending
to zero as t - oo, there exists T > t suchthat y
=( r - 1)T/(rT - 1),
and for thisT, 03B2(r, T, y )
= y. Weput
p =
T/t >
1 andapply
Hôlder’sinequality
withexponents
p,p/( p - 1).
Thus
Next,
werequire
an upper bound for T. Hôlder’sinequality,
which inthis instance is
strict, gives
whence
But T was chosen to make the
right
hand sideequal
to1 /y
and soHence for x
x0(r, t, y),
we haveThis
gives
the resultstated, (which
isclearly
valid for xxo ).
6. Proof of Theorem 2
For
squarefree n,
we denoteby pj(n)
thej-th prime
factor of n in order ofmagnitude
and setand
where q
willultimately
be a function of k. We aregoing
to proveby
induction on r that for a suitable function
B(r, y), (r ~ Z+, y 1)
which we
estimate,
we have fork 1,
a >1,
for
r 1, k 1,
103C3 2, 0 y 1.
This is true forr = 1,
withB(1, y)
- 1.
Also, because 0394r(n) 2r-lMq(n)1/q,
it will be sufficient to obtain this upper bound for the functionLk(03C3).
Now let r 2: our inductionhypothesis
is that for every z E[0, 1)
we haveThe left hand side is at least
where
P-(h), P+(m)
denote theleast, greatest prime
factor ofh, m respectively.
Since the inner sum iswe deduce from the above that for
0
z1,
(where
we have let a - 1 +).
Now setwhere
Dr-1
was defined in Lemma 3. Werequire
an upper bound for this. Wedecompose
the variable n in the sum above in the formn =
dmh,
where d m = nk. We haveThe innermost sum is
and,
sinceP+(md) md we
now haveWe write
1 + y = 2z,
so thatz 1,
and note that(log P+(md))1+y (log P+(m))z(log P+(d))z,
wherelog P+(1)
is to be takenequal
to 1. Itis not difficult to show that
(uniformly
in1),
and so we have
(where log
0 is to beinterpreted
as0)
whenceNext,
we obtain aninequality connecting Lk+1(03C3)
andLk(03C3).
Let03C9(n)
> k. As in theproof
of Theorem 3 we havewhere the * denotes as before that max a q. For
03C9(n)
k there is nosecond term on the
right.
HenceThe inner sum does not exceed
and the innermost sum here is
We
apply
Hôlder’sinequality,
withexponents
q,q/(q - 1)
to the sumover p. We have
by
Lemma3, noting
thatr,(m)
=rk. Putting
all thistogether
we deducethat
where
Ci,
i =1, 2,
3 ... denotes an absolute constant. It is not difficult to show thatand so the sum on the
right
above isafter two
applications
of Hôlder’sinequality:
we havealready defined,
and
estimated, Rk(03C3).
So we haveWe now
replace Lk(03C3)
in the aboveby
and
Lk + 1(03C3)
be thecorresponding L*k + 1(03C3).
Thisstep
isplainly permis- sible,
and it is useful because the lower boundL*k(03C3) » rk/q (03C3 - 1) -y
iseasily
available. We use this to deduce thatusing
the upper bound forRk(03C3)
obtained above. Here B =B ( r - 1, (1
+
y)/2).
Fork ko(r, y)
we haveand
provided q 03B1k(1 - y)/( r log k)
where a is asufficiently
smallabsolute constant, we also have
whence
We use this
inequality
to derive an upper bound forL*k + 1(03C3)
in terms ofL*k(03C3)
which is itself« r,y (03C3 - 1)-y,
becauseko
=k0(r, y).
There is aslight complication
in that q =[03B1k(1 - y )/r log k)]
varies withk,
andL’k(03C3)
is a function of q.Let q’
q. We haveThe
inequality
on the left istrivial,
that on theright
is derived from(1).
Hence
and so a
change from q’ to q
increasesL*k(03C3) by
at most the factorgiven
on theright.
We may assume the values takenby q
are consecutiveso that the contribution from the factor above is
and
where
provided 03B1k0 (1 - y )/( r log k0) 2,
as we may assume. Sincelog
q =log
k +0(1)
we may deduce thatprovided ko
issufficiently large. Replacing
k + 1by k,
andusing
theinequality 0394r(n) 2r-1Mq(n)1/q,
we deduce thatthereby completing
ourinduction,
withB(r, y) = exp {4 5r log r/03B1(1 -
y) 1.
Now we are in aposition
to estimate from above the sumIn the first sum on the
right, n
= n k and weemploy
the upper boundproved
above. The second sum does notexceed,
forany § à 1,
We let k be the least
integer
eyrlog(C03C3 03C3 - 1)
andchoose
=k/(yr log(03C3/03C3 - 1)), making
the lastexpression
above0(l).
For 1 a03C31(r, y)
we deduce thatand the theorem follows in the same way as Theorem 3.
References
[1] P. ERDÖS and R.R. HALL: The propinquity of divisors. Bull. London Math. Soc., 11 (1979) 304-307.
[2] R.R. HALL: The propinquity of divisors. J. London Math. Soc. (2) 19 (1979) 35-40.
[3] R.R. HALL: Hooley’s 0394r-functions when r is large. Michigan Math. Journal (to appear).
[4] R.R. HALL and G. TENENBAUM: On the average and normal orders of Hooley’s
0394-function. J. London Math. Soc. (2) 25 (1982) 392-406.
[5] R.R. HALL and G. TENENBAUM: The average orders of Hooley’s 0394r-functions. Mathe-
matika 31 (1984) 98-109.
[6] C. HOOLEY: On a new technique and its applications to the theory of numbers. P.
London Math. Soc. (3) 38 (1979) 115-151.
[7] H. MAIER and G. TENENBAUM: On the set of divisors of an integer. Invent. Math. 76
(1984) 121-128.
[8] H. MAIER and G. TENENBAUM: On the normal concentration of divisors. J. London Math. Soc. (to appear).
[9] G. TENENBAUM: Sur la concentration moyenne des diviseurs. Comment. Math. Helvitici
(to appear).
(Oblatum 7-VI-1985)
R. R. Hall
Department of Mathematics
University of York Heslington, York Y01 5DD UK
G. Tenenbaum
Département de Mathématiques
Université de Nancy I
Boîte Postale 239 F-54506 Vandoevre Cedex France