Arithmetic sequences
Season 02
Episode 08 Time frame 4 periods
Prerequisites :
Objectives :
•
Disover the onept of arithmeti sequene.•
Find out the main formulae about arithmeti sequenes.Materials :
•
Answersheet for the teamwork.•
Lesson about arithmeti sequenes.•
Exerises about arithmeti sequenes.•
Terms from seven dierent sequenes.•
Beamer1 – Matching game 10 mins
Papers with numbers are handed out to the lass. Students mingle to nd the other
numbers thatouldbepart ofthe samesequene. Firsttermsare speiedwitha staron
the paper.
2 – Team work 45 mins
Working inthe teamsfromthe previous part,students have tollananswer sheetabout
their sequene.
3 – Lesson 30 mins
The main results about arithmeti sequenes are shown with a beamer.
4 – Exercises Remaining time
Exerises about arithmetisequenes have tobe done ingroups of 3 or4 students.
Arithmetic sequences
Season 02
Episode 08
Document Answer sheet
1
. Write inthe ells belowthe rst ve terms of your sequene, inthe orret order.2
. Write inthe ells belowthe next veterms of your sequene.3
. Write in the ells below the terms of your sequene whose indies are given. Forexample, inthe rst ellyouhave towrite the
20
thterm in your sequene.20 25 50 100
4
. What isthe ommondierened
between twoonseutiveterms inyoursequene?d =
5
. Let's notea 1
the rst term in your sequene,a 2
the seond term and so on. Givethe notation not the value of the term next toeah of the terms below.
a 6 a 12 a 153 a n
6
. Find arelation between any terma n
and the next term.7
. Find arelation between aterma n
, the ommondierened
and the rst terma 1
.8
. Usetheformulayoufoundinthepreviousquestiontoomputediretlytheseterms.a 200 a 250 a 500 a 1000
9
. Find arelation between any terma n
and the terma 2
.10
. Find arelation between any terma n
and the terma 5
.11
. Find arelation between any two termsa n
anda m
.12
. Plae the rst ten terms of your sequene on the graph below. To do so, hoose aonvenient sale onthe
y
-axis.1 2 3 4 5 6 7 8 9 10
13
. What do you notie about the graph of this sequene?14
. Compute the sum of the rst ve terms of your sequene.15
. Find a relation between the sum of the rst ve terms, the number of terms, therst term and the fthterm.
16
. Find a relation between the sum of the rst ten terms, the number of terms, therst term and the tenth term.
17
. Find arelationbetween the sumof the rstn
terms, thenumberof terms,the rstterm and the
n
-thterm.Arithmetic sequences
Season 02 Episode 08 Document Lesson
1 Denition and riterion
A sequene of numbers
(a n )
isarithmeti ifthe dierene between twoonseutive termsisa onstant number. Intuitively,togofromoneterm tothenext one, wealways addthe
same number.
Definition 1 Arithmetic sequence
A sequence of numbers ( a n ) is arithmetic if, for any positive integer n , a n +1 − a n = d where d is a fixed real number, called the common difference of the sequence. We can also write that
a n +1 = a n + d.
This equality is called the recurrence relation of the sequence.
Proposition 1 Graph of an arithmetic sequence The graph of an arithmetic sequence is a straight line.
2 Relations between terms
Proposition 2 Explicit definition For any positive integer n ,
a n = a 1 + ( n − 1) × d.
This equality is called the explicit definition of the sequence.
Proof. First, this equality is true when
n = 1
, asa 1 = a 1 + 0 × d = a 1 + (1 − 1) × d
. Then, suppose that it is true for a valuen = k
,meaning thata k = a 1 + ( k − 1) × d
.Then, from the denition ofthe sequene,a k +1 = a k + d = a 1 + ( k − 1) × d + d = a 1 + k × d
.So theformula is true forn = k + 1
too.Soit's trueforn = 0
,n = 1
,n = 2
,n = 3
,et, forall values ofn
.Proposition 3 Relation between two terms For any two positive integers n and m ,
a n = a m + ( n − m ) × d.
Proof. From the expliit denition of the sequene
( a n )
,a n = a 1 + ( n − 1) × d
anda m =
a 1 + ( m − 1) × d
,soa n − a m = ( a 1 + ( n − 1) × d ) − ( a 1 + ( m − 1) × d ) = n × d− m × d = ( n − m ) d
. Therefore,a n = a m + ( n − m ) × d
.Theorem 1 Limit of an arithmetic sequence
The limit of an arithmetic sequence ( a n ) of common difference d
• is equal to + ∞ when d > 0 ;
• is equal to −∞ when d < 0 ;
• is equal to a 1 , trivially, if d = 0.
Proof.
•
Suppose thata 1 > 0
andd > 0
, and onsider any real numberK
. Then, the inequationa n > K
, ora 1 + ( n − 1) d > K
,is solved by anypositive integern
suh thatn > K − a 1
d + 1
.Thismeans thatforanyrealnumber
K
,thereexist someintegerN
suhthatfor anyn > N
,a N > K
.Thisisexatlythe denition ofthefatthatlim a n = + ∞
.•
Suppose thata 1 > 0
andd < 0
, and onsider any real numberK
. Then, the inequationa n < K
, ora 1 + ( n − 1) d < K
,is solved by anypositive integern
suh thatn > K − d a 1 + 1
.Thismeans thatforanyrealnumber
K
,thereexist someintegerN
suhthatfor anyn > N
,a N < K
.Thisisexatlythe denition ofthefatthatlim a n = −∞
.•
The last situation,whend = 0
,isobvious, asallterms areequal toa 1
.4 Sums of onseutive terms
Theorem 2 Sum of consecutive terms
Let ( a n ) be an arithmetic sequence, The sum S n of all the terms between a 1 and a n , S n = a 1 + a 2 + . . . + a n
− 1 + a n , or more precisely S = P n
i =1 a i , is given by the formula S = n ×
a 1 + a n 2 .
Proof. The trik to prove this formulais to write the sumin two dierent ways, one based on
the rstterm, the other basedon the last term.Using the formula of proposition 1.2, we have,
on one hand
S n = a 1 + a 2 + . . . + a n
− 1 + a n
S n = a 1 + a 1 + d + . . . + a 1 + ( n − 2) d + a 1 + ( n − 1) d
and on theotherhand
S n = a 1 + a 2 + . . . + a n
− 1 + a n
S n = a n − ( n − 1) d + a n − ( n − 2) d + . . . + a n − d + a n .
Whenwe addthesetwoexpressionof
S n
,alltermsinvolvingd
areanelledandweendupwith asmany timesthe suma 1 + a n
arethere wereof termsinS n
,so2 S n = n ( a m + a n ) S n = n ×
a 1 + a n
2 .
Arithmetic sequences
Season 02
Episode 08 Document Exercises
8.1
Asinglesquareismadefrom4mathstiks.Twosquaresinarowneeds7mathstiksand 3squares inarowneeds10 mathstiks.This proess denes asequene. Determine,
for this sequene,
1
. the rst term;2
. the ommon dierene;3
. the formulafor the generalterm;4
. how many mathstiks are in arow of 25squares.8.2
A triangular number is a natural number suh that the shape of an equilateraltriangle an be formed by that number of points. For
n > 1
, letu n
be the dierenebetween the
n
-thtriangularnumber and the previous one.1
. Find the six rst triangular numbers.2
. Givethe 5rst terms of the sequene(u n )
. What kind of sequene ouldit be?3
. Write thesix rsttriangularnumbers usingonseutive termsof thesequene(u n )
.4
. Dedue a formulato nd diretly then
-thtrianguler number.5
. Usethis formulatoomputethe36
thtriangularnumber. Isthis numberfamous forother reasons?
8.3
The third term of an arithmetisequene is -7and the 7th
term is 9.Determine :1
. the rst terma 1
and the ommondierened
;2
. the51 st
term.8.4
In an arithmeti sequene, the rst and seventh terms arex 2
and6 + x − 5x 2
,respetively.If the ommondierene is
x
, determine the possiblevalues ofx
.8.5
Thetwelfthtermofanarithmetisequeneis5,andtheommondierenebetweensuessive termsis 3. Determinewhihterm has avalue of 47.
8.6
In a given arithmeti sequene, the rst term is 2, the last term is 29and the sum8.7
A horizontal line intersets a piee of string at four points and divides it into veparts, as shown below.
b b b b
1
2 3
4 5
Ifthepieeof stringisintersetedinthisway by19parallellines,eahofwhihintersets
it atfour points, nd the number of parts intowhihthe string willbe divided.
8.8
These two problems appear on the Rhind Papyrus. This papyrus was named afterAlexander Henry Rhind, a Sottish antiquarian, who purhased the papyrus in 1858 in
Luxor, Egypt; it was apparently found during illegalexavations in or near the Rames-
seum (the memorial temple of Pharaoh Ramesses II). The British Museum, where the
papyrus is now kept, aquired it in 1864. It is one of the two well-known Mathematial
Papyri along withthe Mosow Mathematial Papyrus.
Problem 40. Divide 100 hekats of barley among 5 men so that the ommon dierene
is the same and so that the sum of the two smallest is 1/7 the sum of the three
largest.
Problem 64. Divide 10 hekats of barley among 10 men so that the ommon dierene