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C OMPOSITIO M ATHEMATICA

V AGN L UNDSGAARD H ANSEN On the fundamental group of a mapping space. An example

Compositio Mathematica, tome 28, n

o

1 (1974), p. 33-36

<http://www.numdam.org/item?id=CM_1974__28_1_33_0>

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33

ON THE FUNDAMENTAL GROUP OF A MAPPING SPACE.

AN EXAMPLE

Vagn Lundsgaard

Hansen

Noordhoff International Publishing Printed in the Netherlands

1. Introduction

The purpose of this paper is to

provide

an

example

of a

mapping

space between

connected, compact polyhedra having finitely generated homotopy

groups in all

dimensions,

such that at least one

component

in the

mapping

space has

infinitely generated

fundamental group.

Throughout

K is a

connected, compact polyhedron. Mostly

K =

Si,

the unit circle. For any

connected, topological

space

X, XK

shall denote the space of continuous maps of K into X

equipped

with the

compact-

open

topology.

In

particular XS1

denotes the free

loop

space on X. We

adopt

the

terminology

that an

aspherical

space is a

connected, compact

polyhedron X,

which is also an

Eilenberg-MacLane

space

of type (03C0, 1),

i.e.

03C01(X) =

x and

7ri(X)

= 0 for all i

~

2.

THEOREM: There exists an

aspherical

space X with

finitely generated fundamental

group, such that

the free loop

space

XS1

contains a component

with

infinitely generated fundamental

group.

A similar

phenomenon

cannot

happen

in

higher

dimensions. It

is,

in

fact,

easy to prove that if X has

finitely generated homotopy

groups in

dimensions ~ 2,

then all the

homotopy

groups of

XK

in

dimensions ~

2

are also

finitely generated.

Results on the

qualitative

structure of the

homotopy

groups of a

mapping

space were obtained among others

by

Federer

[1 J

and Thom

[4].

The

example

in the theorem above shows that Thom’s statement

([4],

Theorem

4)

is incorrect for the fundamental group.

Finally,

I want to thank J.

Eells,

A. C.

Robinson,

B.

Hartly

and

D. B. A.

Epstein

for various

helpful

remarks

during

the

preparation

of

this paper.

2. Free

loop

spaces. Their fundamental groups

In this section X is a

connected, topological

space with base

point

*.

It is well-known that the

(path-)components

in the

mapping

space

Xs’

can be enumerated

by xi (X, *).

The fundamental group of a

component

in

XS1 depends normally

on the

component

in

question.

To

describe how,

(3)

34

recall that the centralizer of an element g in a group G is the

subgroup

of

G defined

by Cg(G) = {g’ ~ Glg’g

=

gg’l.

We have then

PROPOSITION 1:

Suppose

that

1t2(X, *)

= 0 and let

f : S1 ~

X be an

arbitrary

base

point preserving

map

representing

the

homotopy

class

[f] E 7r,(X, *).

Then

PROOF: Let 03A9X denote the

ordinary loop

space on

X,

i.e. the space of based maps of

Si

into X

equipped

with the

compact-open topology.

It is

well-known that the map p :

XS1 ~

X defined

by

evaluation at the base

point

of

S’,

also denoted *, is a Hurewicz fibration with fibre 03A9X. See e.g. Hu

([2],

Theorem 13.1 p.

83).

Consider now the

following part

of

the

homotopy

sequence of that

fibration,

Since 03C01(03A9X, f) ~ 03C02(X, *)

=

0, p* is a monomorphism. Hence 03C01(XS1,

f)

is

isomorphic

to the

image of p*.

To determine this

image

observe that

a e xi

(X, *)

is in the

image of p*

if and

only

if there exists a

map S1 x sl

~ X such that

S1 {*} ~

X

represents

a

and {*}

x

S1 ~

X

represents

[f].

On the other hand such a map exists if and

only

if the Whitehead

product

of a and

[f] is

the

identity

element

of 03C01(X, *).

Since a Whitehead

product

of elements in a fundamental group coincides with the cor-

responding

commutator

product,

we

conclude,

that a is in the

image

of

p* if and only if 03B1[f]03B1-1[f]-1 =

1 or

equivalently

that a E

C[f] (03C01 (X, *)).

This proves the

proposition.

3. The

example

Let X be the

connected, compact,

2-dimensional

polyhedron

obtained

from a

cylinder

over an oriented circle with base

point by pinching

one

boundary

circle into a

figure eight

and then

identifying

the

resulting

three

boundary

circles

according

to orientation. See

Figure

1.

Fig. 1

(4)

We shall show that this

polyhedron

satisfies the

requirements

in the

theorem. This will follow

easily

from

Proposition

1 and

Propositions

2

and 3 below.

The base

point

from the circle in the

cylinder

leaves X with a base

point.

Denote the fundamental group of X

by

03C0, and consider the elements x

and y

in x

generated by

the two

loops

indicated in

Figure

1. For each

n =

0, 1, 2, ...

we

put yn

=

x"yx-".

In

particular

yo = y.

PROPOSITION 2: x is

generated by

the elements x and y

subject

to the

single

relation

x-1yx

=

y2.

The centralizer

of

y E 03C0,

Cy(03C0),

is

infinitely generated

with yo, y,, yn, ··· as a system

of

generators.

PROOF: X can be obtained from the

wedge

of the two

loops generating

x

and y by adding

on a

single

2-cell

according

to a map with the

homotopy

class

x- lyxy-2.

Hence the statement about x is

well-known,

see e.g.

Spa-

nier

([3],

Theorem

10,

p.

147).

x is an element of infinite order in x. Let F be the infinite

cyclic

sub-

group of 03C0

generated by x

and let C be the

subgroup

of 03C0

generated by

the elements y0, y1, ···, yn, - - -.

Clearly

F n C contains

only

the neu-

tral element. One proves

easily

that any word in x can be

expressed

in

the form

xmw,

where m is an

integer

and w is a word in C. Hence 7r is

generated by

F and C.

Altogether

03C0 is therefore a semidirect

product

of

the

subgroups

F and C.

Using

the relation

x-1yx

=

y2

it is easy

to prove that y2n+1

=

yn, and

hence that yn =

(yn+k)2k’ Having

this information one verifies that C is abelian.

Since non-trivial powers of x never commute

with y

=

yo, it

is now

clear that

Cy(03C0)

= C.

Clearly

C is

infinitely generated,

since one can never

produce

the ele-

ment yn+ 1 out of a

system

of éléments in C

involving only

yo , ’ ’ ’, yn . This proves

Proposition

2.

PROPOSITION 3: X is an

Eilenberg-MacLane

space

of

type

(03C0, 1).

PROOF: Let X’ denote the

polyhedron

obtained from the space in

Figure

1

by identifying

this time

only

the two

right-hand

circles. Con-

sider then the double infinite

telescope

X" obtained

by glueing together copies

of X’ in both

ends, always

such that the left-hand circle in any copy of X’ is identified with the

pair

of identified

right-hand

circles in the

neigh- bouring

copy of X’ to the left in the

telescope.

Pushing

one

stage

from the left to the

right

in the

telescope

defines in

the obvious way an action of the

integers

Z on X". The

quotient

space for this action can

clearly

be identified with X.

Furthermore,

the

quotient

(5)

36

map X" ~ X is a

covering projection.

To prove that X is an

Eilenberg-

MacLane space

of type (03C0, 1),

it suffices therefore to prove that

03C0n(X") =

0 for

all n ~

2.

For that purpose, let

f :

Sn ~ X" be an

arbitrary

based map of the

n-sphere

Sn

for n ~

2 into X".

By

a

compactness argument

the

image

of

this map lies in a finite

stage

of the

telescope.

Therefore it is easy to see that we can

homotope f into

a map g : Sn ~

X",

which maps one hemi-

sphere

of ,Sn into a

long string,

and maps the other

hemisphere

of S" into

a circle

separating

two

copies

of X’

sufficiently

far to the

right

in the

telescope. Furthermore,

we can arrange

that g

maps the common boun-

dary

of the two

hemispheres

into a

single point.

It is then clear

that g,

and hence

also f,

is

homotopic

to the constant map. Therefore

nn(X")

= 0

for

all n ~ 2,

and as

already

remarked this

completes

the

proof

of Pro-

position

3.

We are now

ready

for the

PROOF OF THE THEoREm:

By Propositions

2 and

3,

X is an

aspherical

space with

finitely generated

fundamental group.

Let 1;, : S1 ~

X be a based map

representing

the

homotopy

class

[fy] =

YEn

= 03C01(X,*). By Proposition 1, 03C01(XS1, fy)=Cy(03C0),

which is in-

finitely generated by Proposition

2. Hence the

component

of

XS1,

which

contains the

map fy,

has

infinitely generated

fundamental group. Therefore X satisfies the

requirements

in the theorem.

REFERENCES

[1] H. FEDERER: A study of function spaces by spectral sequences. Trans. Amer.

Math. Soc. 82 (1956) 340-361.

[2] S. T. Hu: Homotopy Theory. Academic Press, 1959.

[3] E. H. SPANIER: Algebraic Topology. McGraw-Hill, 1966.

[4] R. THOM: L’homologie des espaces fonctionnels. Colloque de topologie algé- brique, Louvain 1956. Thone, Liège; Masson, Paris, 1957, pp. 29-39.

(Oblatum: 4-X-1972 &#x26; 1-VIII-1973) Matematisk Institut K0benhavns Universitet K0benhavn

Denmark

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