C OMPOSITIO M ATHEMATICA
B. J. G ARDNER
Polynomial identities and radicals
Compositio Mathematica, tome 35, n
o3 (1977), p. 269-279
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269
POLYNOMIAL IDENTITIES AND RADICALS
B.J. Gardner
Noordhoff International Publishing
Printed in the Netherlands
There are a number of
parallels
between the theories of varieties and Kurosh-Amitsur radical andsemi-simple
classes ofrings.
In[12]
we obtained necessary and sufficient conditions
(when
the universalclass ’W for radical
theory
is avariety)
for varieties to be radicalclasses and for varieties to be
semi-simple
classes. When W is the class of associativerings,
such varieties can be describedquite explicitly ([13], [23]).
In this paper we
explore
the associative case a little further. We areprincipally
concerned with twoquestions.
(1)
For which radical classes pli do there existpolynomial
identitiessatisfied
by
allrings
in e ?(2)
How close can a non-radicalvariety
come tobeing
a radicalclass? In
examining (1)
we find that withessentially
oneexception,
ifa radical class contains
nilpotent rings,
there is nopolynomial identity
satisfied
by
all its members. On the otherhand, using
the standardidentities,
we are able to exhibit many radical classes ofhereditarily idempotent rings (as
definedby
Andrunakievich[2])
whose memberssatisfy
fixed identities.Specifically,
if Pli is a radical class of here-ditarily idempotent rings,
so is{A E PA lA
satisfies the standardidentity
ofdegree n}
for each n. This is a consequence of our characterization of the lower radical class defined
by
thevariety
ofrings satisfying
the standardidentity
ofdegree n
as the class(A[A12B (A)
satisfies the standardidentity
ofdegree n}.
We shall use the
following
notationthroughout
the paper:N: Nil radical class.
2B : Baer lower
(= prime)
radical class.un: Standard
identity
ofdegree
n.C(n): Variety
definedby
03C3n.A B : A is an ideal of B.
All
rings
are associative unless otherwise indicated.1. Radical classes with
nilpotent
membersThe
proof
of thefollowing
result is similar to that of ananalogous
result for A-matrix
algebras
over a commutativering A
withidentity (see
e.g.[20]
Theorem5.1,
p.22).
LEMMA 1.1: Let R be a
ring
such that thering R (n
xn) of
n x nmatrices over R
satisfies
a multilinearhomogeneous identity 03B2 of degree
k 2n. Then there exists a non-zerointeger
m such thatmR k
= 0.PROOF:
Let 6
be anidentity
of the formwhere 8 is a set of
permutations
of{1, 2, ..., kl containing
theidentity,
c. It mayclearly
be assumed that n,# 0. For aE R,
let[a lij
denote the matrix whose(i, j) entry
is a and whose others are 0. If k = 21 is even, consider the matricesand if k = 21 - 1 is
odd,
considerwhere ai, a2, ..., ak are any elements of R. We have
respectively,
and theproducts
in any other order are zero. Hencewhere r = 1 or 1 +
1,
asappropriate.
It follows thatn,,Rk
= 0.Let P be a non-empty set of
primes, 2p
the class ofrings
whoseadditive groups are direct sums of divisible p-groups
with p
E P. Theclasses
DP
are radical andprovide
the sole occurrence ofexceptional properties
in a number of instances[10], [11], [18]; they
appear in asimilar role in our first theorem.
THEOREM 1.2:
Every ring
in every2p satisfies
theidentity
xy = 0.On the other
hand, if
a radical class PA contains anilpotent ring
whoseadditive group is not torsion
divisible,
there is nopolynomial identity satisfied by
everyring
in R.PROOF: The first assertion is well
known,
sosuppose e
contains anilpotent ring R
whose additive group is not torsion divisible(and
thus
R ~ 0).
ThenR/pR
E PA for allprimes
p, so e contains anon-zero
nilpotent ring
A whose additive group is either torsion-free divisible or a reduced p-group, for someprime
p. It then follows from Theorem 2.5 of[11] ]
that e contains thezeroring
on the additivegroup of A and hence
([9],
Theorem4.2)
either(i)
allB-rings
withdivisible additive groups or
(ii)
allB-rings
whose additive groups are p-groups.If there is a
polynomial identity f3
ofdegree k,
satisfiedby
everyring
inR, f3
may be assumed to behomogeneous ,and
multilinear([19],
Theorem 3.8: theproof
is valid forZ-algebras).
Let B be aB-ring
whose additive group is torsion-free divisible or a p-group.Then these
properties
are sharedby
thering B(n x n)
of n x n matrices overB,
for each n ; inparticular B (n
xn ) satisfies 6
when2n k. But then Lemma 1.1 says that
mBk = 0
for some non-zerointeger
m. If B has torsion-free divisible additive group and isnilpotent
of index >k,
this isclearly impossible.
On the otherhand,
the Zassenhaus
algebra
C([6],
pp.19-20)
over thering
ofintegers
mod.
p r,
wherep’ > m,
is in -0? and isadditively
a p-group, butMCk =
mC# 0.2. A theorem of Osborn and some consequences
The
following
result can be obtained from Theorem 11.15 of[19]
and its
proof.
THEOREM 2.1: The
following
conditions areequivalent for
aring
Awith
N(A)
= 0.(i) Every
non-zerohomomorphic image of
A has a non-zero ideal whichsatisfies
a multilinearidentity
whichpossibly depends
onthe
ideal,
but which hasdegree :5
afixed positive integer
d.(ii)
Asatisfies
the standardidentity of degree 2[d/2].
It is indicated in
[19]
that the conditionX(A) = 0
in Theorem 2.1can be
replaced by
therequirement
that A besemiprime,
this resultbeing
attributed to Martindale. A weaker form of the theorem forsemiprime rings
isadequate
for our purposes, and wegive
a moreelementary proof
of this.THEOREM 2.2: Let A be a
semiprime ring
such that every non-zerohomomorphic image of
A has a non-zero idealsatisfying
un. Then Asatisfies
on.PROOF: Since every
ring
which satisfies Un-1 mustsatisfy
an, it isenough
that we prove thatN(A)
= 0 and invoke Theorem 2.1.Now A itself has a non-zero ideal I
satisfying
on.Then I ~ N(A)
isa nil ideal and satisfies on, so i rl
N(A) Ç; 1-54(A)
= 0([17],
Theorem4).
Let
By
Zorn’sLemmas
has a maximal element M ~ 0. If M ~A,
thenA/M
has a non-zero idealK
=K/M
which satisfies un. Now(K/M)
n[(N(A)
+M)/M]
is a nilring satisfying
an and hencebelongs
to B. Butthen
so
(K/M) ~ ([N(A) + M]/M)
isisomorphic
to an idealof B(N(A)) = M(A)
nB (A)
= 0. Thus we have K nX(A)
ÇM,
whence K nK(A)
CM flK(A)
= 0.By maximality
ofM,
K does notsatisfy
un; onthe other
hand,
M andK/M do,
whileN(K)
= K flK(A)
= 0. Now letL be an ideal of
K,
L~ K. If M CL,
thenKIL,
as ahomomorphic image
ofKIM,
satisfies an, while ifM ~ L,
we have 0 ~(M + L)/L KIL
and(M
+L)/L ~ MIM
~ L satisfies on.By
Theorem2.1,
K satisfies an,violating
themaximality
of M in 9(if
M ~A).
HenceM = A and
N(A ) = 0.
COROLLARY 2.3:
If
asemiprime ring
A has an ideal I such that I andA/I satisfy
on, then Asatisfies
on.PROOF: Let J be an ideal of
A,
J ~ A. IfI C J,
thenA/J = (A/7)/(J/I)
satisfies a-n, while ifI a: J,
we have 0 #(I
+J)IJ
dA/7
and(I
+J)IJ ~ ili
n J satisfies an. The result now follows from Theorem 2.2.3. The lower radical class defined
by CI(")
Those varieties which are also radical classes are
completely
known
[12], [13]. They
are theonly
varieties which contain nonilpotent rings.
As we sawin § 1,
the presence ofnilpotent rings
in aradical class
generally
means there will be nopolynomial identity
satisfied
by
allrings
in the class. Inparticular,
if V is avariety
withsome
nilpotent members,
there is no propervariety containing
thelower radical class
L(V)
definedby V,
soL(V)
is considerablelarger
than V. We can thus
ask, informally:
how manyrings
inL(V)BV
areput
thereby
thenilpotent
members of V? Thisprovides
us with a sortof measure of the extent
by
which V fails to be a radical class. Weshall,
in thissection,
answer thequestion
for the varietiesC (n)
definedby
the standard identities an. There are some similarities between this work and that of Freidman[7], [8].
For each n let
e(n)
denote the class ofrings
A for which there is aseries
where each
A+i/A E B
U(6(").
We demonstrate a few closureproperties
ofR(n).
PROPOSITION 3.1:
Rn
ishereditary.
PROOF: Let A E
e(.)
have a series(*)
and let I be an ideal of A.Then we have a series
with
PROPOSITION 3.2:
R(n) is homomorphically
closed.PROOF: If A has a series
(*)
and IA,
wehave,
foreach i,
where the last
ring
is ahomomorphic image
ofAi+,/Ai
and sobelongs
to B U
C(n).
Hence the factors ofPROPOSITION 3.3:
R(n)
is closed under extensions.PROOF: Let A be a
ring
with an ideal I such that I andA/I
E9A(n).
Then there are series
and
with factors in B U
C(n).
The same is true of the factors ofTHEOREM 3.4: A
ring
Abelongs
toe(n) if
andonly if A/B(A) E C(n).
The
proof
of this theoremrequires
LEMMA 3.5: Let R be a
semiprime ring
with an ideal j EC (n)
such thatR/J
E B. Then R EC(n).
PROOF OF THEOREM 3.4: Let A be in
R(n).
ThenAle(A)
ER(n)
sothere is a series
with factors in 2B U
Clnl.
SinceA/B(A)
issemiprime,
so is eachAi/B(A),
soA 1/B (A) belongs
to«¿(n).
Now[A2/e(A)]/[Al/e(A)l
E Bor
C(n);
if theformer,
thenA21g)J(A) E C(n) by
Lemma3.5,
if thelatter,
then
A2/B(A)
E(C(n by Corollary
2.3. In any case,A2/B(A)
is inC(n).
Repetitions
of thisprocedure
lead to the conclusion thatA/B(A)
EC(n).
The converse is clear.THEOREM 3.6:
e(n) is a
radical classfor
each n.PROOF: Let R be a
ring, {IAIA
EA}
a chain of ideals of Rbelonging
to
R(n), I = U aEn I".
Thenwhere
[I" + Ç!)J(I)]IÇ!)J(I) ~ IA/IA
nB(I )
=IAIÇ!)J(IA)
E(c (-) -
HenceI/B(I) E C(n), i.e. l E !1l(n). By Propositions 3.1,
3.2 and 3.3 and the characterization of radical classes in[1], R(n)
is ahereditary
radicalclass.
Recall the Kurosh lower radical construction
(as
modified in[24]):
Let M be a
non-empty homomorphically
closed class ofrings.
Define.Áae1
=.Áae,
.Áaen+1
=JAIA/I
has a non-zero ideal in .;Un whenA/I ~ 01
for n =
1, 2, ...,.Áaew
=Un Mn.
Then.Áaew
is the lower radical class definedby
JK.COROLLARY 3.7:
for
each n.PROOF: Let A be a non-zero
ring
inR(n).
ThenA/B(A) e C(n),
soA E
C(n)
ifB(A)
=0,
while A has an ideal I withI2 = 0 ~ I otherwise,
and such an I is in
C(n).
Thus A has a non-zero ideal inC(n)
and thesame goes for any non-zero
homomorphic image
ofA,
so A EC2(n).
Hence
R(n)
çC2(n)
CL(C(n). Conversely,
if B EC(n),
thenB/2B(B) e
C(n),
so B ER(n).
SinceR(n)
is a radicalclass,
we haveL(C(n)
CR(n).
By
the theorem in[4],
ahereditary homomorphically
closed classJK has lower radical class
M3.
There are varieties k withL(M)
= .Al =.Jae1 and
we havejust
seenexamples
whereL(M) = M2 ~ M1.
It would beinteresting
to know whether threesteps
are ever necessary in the lower radical construction over avariety.
Before
proceeding,
we take note of acouple
of resultsresembling
Theorem 3.6. Freidman
[7]
has shown that if A is a localhereditary
radical class
(e.g.
the Jacobson or Levitzki radicalclass)
then so is iscommutative}.
P.N. Stewart has shown that for any
special
radical class GlC con-taining
thegeneralized
nil radicalclass,
is
commutative}
is a
special
radical class(private communication).
For alternativerings,
Freidman[8]
hasshown,
ineffect,
that isassociative}
is a
hereditary
local radicalclass,
where W isSmiley’s
non-associativegeneralization [22]
of theBrown-McCoy
radical class.We now consider some further consequences of Theorem 3.4. Let
X, Y
be classes ofrings.
We denoteby l 0 OY
the class ofrings
Awhich have ideals I E 3E with
AII
E Y.PROPOSITION 3.8:
For a
ring A,
letA (a-,,) = n li li - A
andA/I E W (n Il. (A(u2)
isusually
called the commutator ofA.) Clearly A(an) C 1-5e(A)
if andonly
ifAIÇJJ(A)
EC(n).
PROPOSITION 3.9: Let A be a
ring
with a seriessuch that
Ai+t!Ai
EC(n) for
each i. ThenA(un) C B (A).
It has been shown
by Jennings ([14],
Theorem5.8)
thatA(u2)
isnilpotent
in this case. Freidman([7],
p.230)
hasproved
that if A has atransfinite
ascending
series with commutative factors thenA(u2)
islocally nilpotent.
The results
of § 1
indicate that in order to find moreexamples
of radical classes whose memberssatisfy
apolynomial identity
we haveto exclude
nilpotent rings
from consideration. We shall denoteby llt
the class of
hereditarily idempotent rings,
therings
whose ideals are allidempotent
or,equivalently,
therings
whosehomomorphic images
areall
semiprime (see [2];
also[5]).
llt is ahereditary
radical class([2],
Theorem
2).
THEOREM 3.10:
H n C(n) is a hereditary
radical classfor
each n.PROOF: llf rl
cg(n) =
llf nR(n)
and intersections of radical classes areradical classes
[15].
COROLLARY 3.11:
If OU is a
radical subclassof H,
then u ~(6 (n)
iSa radical class.
Taking
account of Theorem1.2,
weget
COROLLARY 3.12:
If gjl is a hereditary
radicalclass,
then e rlC(n)
is a radical class
if
andonly if
gjl C H.Armendariz and Fisher
[3]
showed that aring (not necessarily
withan
identity element)
in lit which satisfies apolynomial identity
isregular,
so all the radical classes inducedby
o-n in Theorem 3.10 and Corollaries 3.11 and 3.12 consist ofregular rings.
4.
Semi-simple classes,
restrictedattainability
A
variety
is a radical class(in
the associativecase) precisely
whenit is a
semi-simple class,
and this is so if andonly
if the identities of thevariety
are attainable. In this section webriefly
consider theseconcepts
and their connections with the standard identities.The
following
result is acompanion piece
toCorollary
3.11.PROPOSITION 4.1: Let g be a
semi-simple
classcontaining only semiprime rings.
Theng, rlC(n)
is asemi-simple
class.If
M C Y andevery
ring
in g is a subdirectproduct of rings
in.Ál,
then everyring
inY ~
C(n) is a
subdirectproduct of rings
in M flcg(n).
PROOF:
By
Theorem 1 of[16]
or Theorem 1 of[21]
we need toshow that 9, n
C(n)
ishereditary
and closed under subdirectproducts
and extensions. 9’ has these
properties
andC(n)
has the first two, whileCorollary
2.3implies
that the class ofsemiprime rings satisfying
an is closed under extensions. The last assertion follows from the fact that
(6(")
ishomomorphically
closed.COROLLARY 4.2:
If 9’ corresponds
to aspecial
radicalclass,
sodoes g fl
W(n) for
each n.Tamura
[25]
introduced the notion ofattainability
of identities in universalalgebra.
For our purposes, theconcept
is defined as follows.Let r be a set of identities and for each
ring
A letThen r is attainable if
A(F)(F)
=A(F)
for allrings
A. Moregenerally,
we say that r is attainable on a class 3t of
rings
ifA(F)(F)
=A(F)
forall A E 3t. The attainable identities for associative
rings
are describedin
[13].
We conclude
by demonstrating
thepartial attainability
of the stan-dard identities.
PROPOSITION 4.2: 03C3n is attainable on the class H
of hereditarily idempotent rings.
PROOF: Let P denote the class of
semiprime rings, 611
the radical classcorresponding
to thesemi-simple
class P flC(n) .
Then for A OE lltwe have
Since
A(03C3n) E lie,
we then haveA(03C3n)(03C3n)
=U (U (A))
=IM (A)
=A(un).
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(Oblatum 1-VI-1976) Mathematics Department University of Tasmania Hobart, Tasmania, 7001 Australia