C OMPOSITIO M ATHEMATICA
S HIGEYUKI K OND ¯ O
The rationality of the moduli space of Enriques surfaces
Compositio Mathematica, tome 91, n
o2 (1994), p. 159-173
<http://www.numdam.org/item?id=CM_1994__91_2_159_0>
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The rationality of the moduli space of Enriques surfaces
SHIGEYUKI
KONDO
Department of Mathematics, Saitama University, Shimo-Okubo 255, Urawa, Saitama 338, Japan
Received 5 October 1992; accepted in final form 5 April 1993 (Ç)
0. Introduction
The purpose of this paper is to prove the
rationality
of the moduli space wÀf ofEnriques
surfaces(defined
overC) suggested by Dolgachev [Dl].
Recall thatoeV is described as a Zariski open set of
D/0393
where -9 is a boundedsymmetric
domain
of type
IV and of dimension10,
and r is an arithmeticsubgroup acting
on D
(Horikawa [H]).
It is known thatD/0393
is aquasi-projective variety (Baily,
Borel[B-B]).
We shall prove:THEOREM. N is
birationally isomorphic
to the moduli spaceN5,cusp of plane
quintic
curves with a cusp.It is known that
N5,cusp is
rational([Dl]).
Hence we have:COROLLARY. JI( is rational.
Let C be a
plane quintic
curve with a cusp. Let X be a K3 surface with aninvolution T obtained as the double cover of P2 branched at C and the tangent line at the cusp. Then
H2(X, Z)~03C4*~ ~
U 0Dg
as lattices. As in the case ofEnriques
surfaces(Namikawa [Na]), by using
the Torelli theorem for K3 surfaces(Piatetskii-Shapiro,
Shafarevich[P-S])
and thesurjectivity
of theperiod
map(Kulikov [K]),
we can see that the moduli space ofpairs (X, i)
isdescribed as a Zariski open subset of
9’/F’
where -9’ is a boundedsymmetric
domain of type IV and of dimension
10,
and r’ is an arithmeticsubgroup (Theorem 3.7).
We shall prove that the map fromN5,cusp
toD’/0393’
obtained asabove is birational
(Theorem 3.21).
We remark here that ageneral
K3 surfaceas above has no fixed
point
freeinvolution,
and hence it is not the unramifieddouble cover of any
Enriques
surfaces.However, forgetting D/0393
andD’/0393’
being
moduli spaces, we shall see that there is anequivariant
map from -9 to D’ with respect to r andr’,
and this induces anisomorphism D/0393 ~ D’/0393’
(Theorem 4.1).
1. Preliminaries
(1.1)
A lattice L is a free Z-module of finite rank endowed with anintegral symmetric
bilinearform ( , ). If L and L2
arelattices,
thenL ~ L2
denotesthe
orthogonal
direct sumof L1
andL2.
Anisomorphism
of latticespreserving
the bilinear forms is called an
isometry.
For a latticeL,
we denoteby O(L)
thegroup of self-isometries of L. A sublattice S of L is called
primitive
ifLIS
istorsion free.
A lattice L is even if
~x, x)
is even for each XE L. A lattice L isnon-degenerate
if the discriminant
d(L)
of its bilinear form is non zero, and unimodular ifd(L) =
+ 1. If L is anon-degenerate lattice,
thesignature
of L is apair (t +, t-) where t+
denotes themultiplicity
of theeigenvalues
+ 1 for thequadratic
formon L (8) R.
Let L be a
non-degenerate
even lattice. The bilinear form of L determines acanonical
embedding
L - L* =Hom(L, Z).
The factor groupL*/L,
which isdenoted
by AL,
is an abelian group of orderId(L)I.
We denoteby I(L)
thenumber of minimal generator of
AL.
We extend the bilinear form on L to one onL*, taking
value inQ,
and defineWe call qL the discriminant
quadratic form
of L. We denoteby O(qL)
the groupof isomorphisms
ofAL preserving
the form qL. Note that there is a canonicalhomomorphism
fromO(L)
toO(qL).
A
non-degenerate
even lattice L is called2-elementary
ifAL ~ (7Lj27L)’(L).
Itis known that the
isomorphism
class of an even indefinite2-elementary
latticeL is determined
by
the invariants(r(L), l(L), 03B4(L)) ([N1],
Theorem3.6.2)
wherer(L)
is the rank of L andWe denote
by
U thehyperbolic
lattice definedby
which is an evenunimodular lattice of
signature (1, 1),
andby Am, Dn,
orEl
an evennegative
definite lattice associated to theDynkin diagram
of typeAm, Dn
orEl (m 1,
n
4,
1 =6, 7, 8).
We remark thatEs
is unimodular. Also we denoteby ~m~
the lattice of rank 1 defined
by
the matrix(m).
For a lattice L and aninteger
m,
L(m)
is the lattice whose bilinear form is the one on Lmultiplied by
m. Insection
3,
we shall use the fact that bothU(2)
andD4n
are2-elementary
latticeswith l = 2, 03B4 = 0.
(1.2)
A compactcomplex
smooth surface Y is called anEnriques surface
if thefollowing
conditions are satisfied:(i)
thegeometric
genuspg(Y)
and theirregularity q( Y) vanish;
(ii)
ifKy
is the canonical divisoron Y, 2Ky
= 0.Note that the unramified double
covering
of Y definedby
the torsionKy
is aK3
surface X,
a smooth surface withq(X)
= 0 andKX
= 0. The secondcohomology
groupH2(Y,Z)
isisomorphic
to ZIO~Z/2Z,
whereZ/2Z
isgenerated by
the canonical class. The free part ofH2(Y, Z)
admits a canonicalstructure of a lattice induced from the cup
product.
It is an even unimodularlattice with
signature (1, 9)
and hence isometric to U QEs (e.g. [N1],
Theorem1.1.1).
In the same way, the latticeH2(X, Z)
is isometric toL = U ~ U Et) U O
Es
~Es. By
definition of K3surface,
the Picard groupPic(X)
is asubgroup
ofH2(X, Z)
which admits a structure of lattice induced from that ofH2(X, Z).
We call thisPic(X)
the Picard lattice of X.Let Y be an
Enriques
surface and X itscovering
K3 surface. Let 6 be thecovering
transformation of X and Q* the involution ofH2(X, Z)
induced froma. Then 03C3* determines two
primitive
sublatticesIt is known that M ~
U(2)
~E,(2)
and N ~ U 0U(2)
~E,(2) (e.g. [B-P],
§1.2).
Let úJx be thecohomology
class of a non-zeroholomorphic
2-form on Xin
H2(X, C)
which isunique
up to constant. This class satisfies thefollowing
Riemann condition:
where
denotes the bilinear form onH2(X, C)
induced from the cupproduct
and03C9X
thecomplex conjugation
of tox. We remark that 03C9X is contained in N~ C
since there are noglobal holomorphic
2-form on Y PutThen -9 is a union of two
copies
of boundedsymmetric
domain of type IV and of dimension 10.By [B-B],
thequotient D/0393
is aquasi-projective variety.
Thecorrespondence
Y -[wx]
mod r defines a well-defined map from the set ofisomorphy
classes ofEnriques
surfaces to(D/0393)0
=(D/0393)BH, where
e is aclosed irreducible
subvariety.
Thecorresponding point [03C9X]
in(D/0393)0
is calledthe
period
of Y. It follows from the Torelli theorem forEnriques
surfaces that(D/0393)0
is the coarse moduli space ofEnriques
surfaces. For more details werefer the reader to
[H],
and itsimprovement [Na].
2. The curves related to
Enriques
surfacesIn this
section,
we shall devote the observation ofDolgachev [D1, 2]
on therelation between
Enriques surfaces, plane quintic
curves with two nodes andplane quintic
curves with a cusp. For theproof
of ourtheorem,
we shallonly
use
Proposition
2.2.(2.1)
Let Y be anEnriques
surface. Asuperelliptic polarization
D onYof degree
8 is a divisor on Y such that D =
2(E
1 +E2), Ei
anelliptic
curve on Y withEl’ E2
= 1(see [C-D], Chap. IV, §7).
It is known that ageneral Enriques surface,
in the sense of Barth-Peters[B-P],
has 27·17·31 distinctsuperelliptic polarizations of degree
8 up toautomorphisms ([B-P],
Theorem3.9).
Let be the moduli space of
Enriques
surfaces with asuperelliptic polarization
ofdegree
8. Then the aboveimplies
that the naturalmap §
from
to
N =(D/0393)0
is ofdegree
27 17.31. Note that 27 17 - 31 =23(24 + 1)24(25 - 1)
and recall that23(24
+1)
isequal
to the number of even theta characteristics on a smooth curve of genus 4 and24(25 - 1)
is thenumber of odd theta characteristics on a smooth curve of genus 5. In
[D2], Dolgachev
gave a map cp from to5,cusp
ofdegree
27.17.31 whichfactorizes
where X is the moduli space of
pointed
curves of genus 4 anddeg
9 1 =23(24
+1), deg
lp2 =24(25 - 1).
For theprecise
definition of (pl, lfJ2, we refer the reader to[D2].
Here we mention that apointed
curve(C, q)
of genus 4 is obtained as the normalization of aplane quintic
curve with two nodesand q
is the
point
residual to the linepassing through
the nodes. The last one isnaturally appeared
as the Hessian of a net ofquadrics
inp4.
The base locus of this net is the branched curve of themorphism
ofdegree
2 definedby IDI
from Y to the intersection of two
quadrics
in P4 of rank3,
where(x D)
is anEnriques
surface with asuperelliptic polarization
D ofdegree
8. Also aplane quintic
curve with a cusp isnaturally appeared
as the discriminant of the conic bundle associated to a cubic threefold. The last one is constructed from the canonical model of a curve of genus 4. Thus we have two maps of the samedegree:
This and the
following
suggest that JIt may be rational too.PROPOSITION
(2.2) ([Dl], §8, (e)). N5,cusp
is rational.Proof.
The moduli space ofplane quartic
curves with a cusp is rational([Dl], Example 5).
The sameproof implies
the assertion. D3. K3 surfaces with some involution
The purpose of this section is to see that
N5,cusp
isbirationally isomorphic
tothe moduli space of the
pairs
of K3 surfaces X and its involution r withH2(X, Z)~03C4*~ ~
U ~Dg.
(3.1)
Let C be aplane quintic
curve with one cusp q. Let L be the tangent line of C at the cusp. In thefollowing,
we assume:ASSUMPTION
(3.2).
L meets C at another distinct twopoints
pl, P2.Consider the
plane
sextic curve C~L. Let X’ be the double cover of P2 branched at C~L and X the minimal resolution of X’. Then X’ has a rational doublepoint of type E7
over q and two rational doublepoints of type A
over pi, p2. The X is a K3 surface which is reconstructed as follows.Taking
successive
blowing-ups
ofP2,
we have a rational surface R with thefollowing
curves as in
Figure
1.Fig. 1.
where C’ and L’ are the proper transforms of C and L
respectively,
and thehorizontal lines except C’
(resp.
thevertical lines)
are smooth rational curveswith self-intersection number -4
(resp. -1).
Then X is obtained as the doublecover of R branched at C’ and the smooth rational curves with self-intersection number - 4 in the
Figure
1. Hence X has smooth rational curves as inFigure
2:Let T be the
covering
transformation of X ~ R. Note that each curve inFigure
2 is
preserved by
T.LEMMA
(3.3). Pic(X)~03C4*~
contains a sublattice isometric to U Et)D8.
Proof.
The 9 curves exceptF10
inFigure
2 define anelliptic pencil
with asingular
fibreof type 8 (type 1*
in the Kodaira’snotation)
andFI 0
is a sectionof this
pencil.
Hence these 10 curves generate a sublattice ofPic(X)~03C4*~
isometric to U O
D8,
DTaking
anisometry H 2(X, Z) ~
L = U Et) U Q U Et)E8 O E.,
defineWe remark here that S and N’ are
primitive
inL,
i.e.L/S
andL/N’
are torsionfree.
PROPOSITION
(3.4).
S ~ U CD.
and N’ ~ U CU(2)
eE8.
Proof. Obviously
S ~Pic(X)~03C4*~.
Note that both S and U 0Ds
are 2-elementary
lattices. It follows from[N2],
Theorem 4.2.2 that(r(S) 2013 l(S))/2 = #{smooth ranonai curves nxea Dy Ti = 4
where
r(S) (resp. l(S))
is the rank of S(resp.
the number of minimal gener- ator ofAs).
Hencer(S)
= 10 andl(S)
= 2.By
Lemma3.3, Pic(X)03C4*>
con-tains
U E9 Ds
which has the same invariants. Thus we have S =Pic(X)03C4*> ~
U QD..
Then N’ is an even indefinite2-elementary
lattice with the invariant(r(N’), l(N’), b(N’)) = (12, 2, 0)
because N’ is theorthogonal comple-
ment of S in the unimodular lattice L
([NI], Proposition 1.6.1.).
Since theisomorphism
class of an even indefinite2-elementary
lattice is determinedby (r, 1, 03B4) ([NI],
Theorem3.6.2),
we have N’ ~ U E9U(2)
E9E8.
D Remark(3.5).
Both S and N’are even indefinite2-elementary
lattices and hence thehomomorphisms
are
surjective ([N1],
Theorem3.6.3). By [N1], Proposition 1.14.1,
any y EO(S)
or
y’ E O(N’)
can be lifted to anisometry
of L. Inparticular,
if y acts onAs trivially,
then it can be lifted to anisometry acting trivially
on N’. SinceS ~ U~ D8, qS ~
qD.. . HenceAs - (Z/2Z)2 and qS ~ [01/2 1/20]. A direct
calculation shows that
0(qs) - Z12Z
and the generator ofO(qs)
is inducedfrom the
isometry
i inO(S)
definedby i([Fi]) = [Fi],
3 i10,
andi([F1]) = [F2] (Note
that the classes[Fa
ofFi (1
i10)
inFigure
2give
a base of
S).
DEFINITION
(3.6).
Now we define:Then -9’ is a union of two
copies
of boundedsymmetric
domain of type IV and of dimension10,
and r’ actsproperly discontinuously
on D’.By [B-B], D’/0393’
is a
quasi-projective variety.
PutThen r’ acts on 1’.
By
the same reason as in the case ofEnriques
surfaces([H], II,
Theorem2.3),
theperiod [03C9X]
of any K3 surface X as above is contained in(D’/0393’)B(H’/0393’).
We remark here thatJ(’/r’
is a irreduciblehypersurface
inD’/0393’ (see
thefollowing Proposition 3.9). By
the similarproof
as that of
Enriques
surfaces([Na]), using
the Torelli theorem for K3 surfaces[P-S]
and thesurjectivity
of theperiod
map[K],
we have thefollowing
theorem. For our purpose, we do not use this
theorem,
and hence we omit theproof.
THEOREM
(3.7). (D’/0393’)B(H’/0393’) is
the coarse moduli spaceof the pairs (X, -r)
where X is a K3
surface
andr is an involutionof
X withH2(X, Z)03C4*>
-- U Et)D8*
DEFINITION
(3.8) ([N3], [Na],
Theorem2.15).
A vector 1 in N’ withl, l>
= -4 is called of even type if there is a vector m in S =(N’)~
withm,m> = -4
and(m
+l)/2~L. By
Remark3.5,
the set of( - 4) -
vectors inN’ of even type is invariant under the action of T’’. Put
Then
by
thefollowing proposition, J("/r’
is an irreduciblehypersurface
inD’/0393’.
PROPOSITION
(3.9).
Let l and l’ be two( - 2)-vectors in
N’(or (-4)-vectors of
even
type).
Then there is anisometry
y E r’ with03B3(l)
= l’.Proof.
This follows from the sameproof
as in the case ofEnriques
surfaces([Na],
Theorems2.13,
2.15 andProposition 2.16).
~ In thefollowing,
we shall see that the setbijectively corresponds
to the set ofprojective isomorphism
classes ofplane quintic
curves with a cuspsatisfying
theAssumption
3.2.LEMMA
(3.10).
Let X be a K3surface
constructed in(3.1)
and[cox]
itsperiod.
Then
[wxJ
mod r’ E(Ç)’/r’)o.
Proof.
As mentioned in(3.6), [Wx]
ED’BH’
and hence it suffices to see that[wx]
is not contained in H". Assume[wxJ
E Yt". Then there exist( - 4)-vectors
m in S and 1 in N’ with
(m
+/)/2eL
and~03C9X,l~
= 0. Consider the latticeS~~-4~ generated by
S and 1.By adding
a vector(m
+1)/2,
we have asublattice K in
Pic(X)
in whichS~~-4~
is of index 2. Thend(K) = d(S)·d(~-4~)/[K:S~~-4~]2=4.
Recall that X has an
elliptic pencil 03C0
with a sectionF10
and asingular
fibreF of type
8 (see
theproof
of Lemma3.3).
Itgives
adecomposition
S =
U E) D8
where U is
generated by
the classes of a fibre andF 10,
andDs
isgenerated by {Fi}1i8.
Since U isunimodular,
U isprimitive
inK,
i.e.K/U
is torsion free.By using
the factAu
={0}
and[NI], Proposition 1.5.1,
we caneasily
see thatthis U is also the component of a
decomposition
K = U QK’,
where K’is a
negative
definite even lattice of rank 9 withd(K’)
= 4 and K’ ~D8*
If
D.
is notprimitive
inK’,
then there is an even lattice M of rank 8 with K’ ~ M :DD..
Sinced(D.)
=4, d(M)
= 1 and hence M ~E..
SinceEs
isorthogonal
toU, Es
should begenerated by
components of F(see [Ko],
Lemma
2.2),
which isimpossible.
If
D.
isprimitive
inK’,
then theorthogonal complement
ofD.
in K’ isisometric
to ~-2m~ (m E N).
Theprimitiveness implies
thatK’/(D8 ~ ~- 2m»
is embedded into
AD8 ~ (Z/2Z)’
andA~-2m~ ~ Z/2mZ ([Nl], §1.5).
HenceK’/(D8~~-2m~ ~ Z/2Z.
Therefore we have m = 2by using
theequation d(K’)
=d(D8)·d(~-2m~)/[K’:D8
e~-2m~]2. By [Nl], Proposition 1.5.1,
K’is obtained from
D. ~~-4~ by adding
an element « = x* +y*
where x* ED*
and
y*~~-4~*
withqDe(X*)
=q(-4)(Y*)
= 1. Note that such x* andy*
areunique
moduloD. and ~-4~ respectively.
Hence we can putThen a2
= - 2, ~03B1, [Fi]~
= 0(1 i 7)
and~03B1, [F8]~
= 1. Thus K’ ~D9,
which is also
impossible.
DRemark
(3.11).
If wedrop
theassumption (3.2),
i.e. L tangents to C at a smoothpoint,
then there is a( - 4)-vector
of even type inPic(X). Therefore,
in this case,[03C9X]
EH".
DEFINITION
(3.12).
Let X be a K3 surface with[cox]
E(D’/0393’)0.
PutNote that
C(X ) n Pic(X)
isnothing
but the set of classes ofnumerically
effective divisors. The
following
is ananalogue
of[Na], Proposition
4.7.LEMMA
(3.13). C(S)
=C(X)
n S (D R.Proof. Obviously
the left hand side contains theright.
LetxeC(S)
and03B4~0394B03B4(S).
Theprimitiveness
of S in Limplies
that03C4*(03B4) ~
ô.By
theHodge
index
theorem, (b - t*(b»2
0 and hence(b, t*(b»
> - 2. Note that03C4*(03B4) ~ -03B4
and~03B4,03C4*(03B4)~ ~ 0, -1
because[cox] ~D’B(H’ ~ H").
Henceb
+ 03C4*(03B4)
E S with(ô +03C4*(03B4))2 -
2. If(ô +t*(b))2 = - 2,
then b +t*(b)
EA(S),
and hence
~x, 03B4
+t*(b)
> 0. If(ô
+03C4*(03B4))2 0,
then ô +03C4*(03B4) E P(X)
andhence
~x, 03B4 + 03C4*(03B4)~ > 0.
Since~x,03B4~ = ~03C4*(x),03C4*(03B4)~ = ~x,03C4*(03B4)~,
we have~x,03B4~
> 0. ~(3.14).
For b EA(S),
define sa EO(H2(X, Z)) by
Then the group
W(S) generated by {s03B4|03B4 ~0394(S)}
acts onP(S)
andC(S)
is afundamental domain with respect to its action on
P(S) ([V]).
(3.15) Surjectivity.
We shall see that eachpoint
incorresponds
to aplane quintic
curve with a cuspsatisfying (3.2).
Let X be a K3 surface with itsperiod [03C9X]~(D’/0393’)0.
First note that X has an involution i withH2(X, Z)03C4*>~ U
~D.,
Infact,
the involution of S E9 N’ definedby aIS
=ls
and
03C3|N’ = -1N’
acts onAs
0AN’ trivially
because S and N’ are2-elementary.
Hence
by
Remark3.5,
we can extend a to anisometry à
ofH2(X, Z).
Obviously à
fixes theperiod
of X. Moreoverby
Lemma3.13, or
preserves effective divisors on X. Therefore it now follows from the Torelli theorem for K3 surfaces[P-S]
that à is induced from an involution 03C4 of X with -r* = à.LEMMA
(3.16).
There exists anelliptic pencil
n: X - pl with asingular fibre
F
of
typeDn (n 8)
invariant under the actionof r.
Proof.
Consider anorthogonal decomposition
S= U~D8
and takef~U
satisfying that f2
= 0 andf
isprimitive (i.e. f =
me, e EU, implies m
=± 1). By
Lemma 3.13 and the fact stated in
(3.14),
we may assume thatf
isnumerically effective,
if necessary,replacing f by ç( f)
where~~O(H2(X, Z))
withcp(S)
c S. Thenf
defines anelliptic pencil 03C0:X ~ P
1 such thatf
is thecohomology
class of a fibre of 03C0([P-S], §3,
Theorem1).
Consider thenegative
definite sublattice K in
{the orthogonal complement
off
inPic(X)I/ Z[f]
generated by ( - 2)-elements.
Then K rrK1~ ···
OK,,
whereKi
is a latticeisometric to
Am, Dn
orEl. By
the sameproof
as that of[Ko],
Lemma2.2, n
hassingular
fibres of typeK 1, ... , Kr .
SinceDs
cK,
03C0 has asingular
fibre Fof type
Dn (n 8).
Since T* actstrivially
on thisD.,
F is invariant under theaction of T. D
LEMMA
(3.17).
Wekeep
the same notation as in Lemma 3.16. Then n = 8.Proof.
Recall that F consists of thefollowing
smooth rational curves:Fig. 3.
If
03C4(F1)
=F2
or03C4(F1)
=Fn,
thenFB - F2
orF 1 - F"
is( - 4)-vector
in N’ ofeven type. Since
~03C9X, Pic(X)~
=0,
this contradicts theassumption [cox]
E(D’
/0393’)0.
HenceT(Fi) = Fi (1
i n +1).
Now if n9,
then S contains adegenerate
lattice of rank n + 1 10generated by
components ofF,
which isimpossible.
DThus the
singular
fibre F consists of smooth rational curves as in thefollowing:
It follows from
[N2],
Theorem 4.2.2 that the set of fixedpoints
of 03C4 is thedisjoint
union of a smooth curve C of genus 5 and 4 smooth rational curvesE1,..., E4 (see
theproof
ofProposition 3.4).
Since03C4(Fi)
=Fi (1
i9), F3
and
F7
are fixed curves of T. Thisimplies
thatF 5
is also fixedby 03C4
and 03C4 actson
F, (i
=1, 2, 4, 6, 8, 9)
as an involution because the set of fixedpoints
of ris the
disjoint
union of smooth curves. Thus we may assume thatE1
=F3, E2
=F 5
andE3
=F7.
ThenFi (i
=1, 2, 8, 9)
meets either C orE4.
If C meetsall
FI, F2, F.
andF9,
thenE4. Fi = 0 (1 i 9)
and hence S =U Q D8
contains a
degenerate
lattice of rank 10generated by
components of F andE4.
This is a contradiction. Also if C meets
only F and F2,
thenE4
meetsF. and F9.
In this case,(F7
+F8
+F9
+E4)2 = C·(F7
+Fg
+F9
+E4)
= 0. Thiscontradicts the
Hodge
index theorem.Similarly
it does not occur that C meetsonly F1
or C meetsonly F and F..
Thus we may assume that C meetsFI, F2, F. and E4
meetsF9.
Note that this is the same situation as inFigure
2.Now
taking
thequotient X/(s)
andcontracting exceptional
curves onX/(s) successively,
we have aplane quintic
curve with a cuspsatisfying
theAssumption
3.2.(3.18) Injectivity.
Let C and C’ beplane quintic
curves with a cuspsatisfying (3.2).
Let X and X’ be thecorresponding
K3 surfaces to C and C’respectively.
PROPOSITION
(3.19). If [03C9X] = [03C9X’] in (L’/0393’)0,
then C isprojectively isomorphic
to C’.Proof.
Let{Fi}
or{F’i} (1
i10)
be smooth rational curves on X or X’as in
Figure 2, respectively.
It suffices to see that there exists anisomorphism
between the
pairs (X, r)
and(X’, r’)
which sends{Fi}
to{F’i}.
Letbe an
isometry
with03B3([03C9X]) = [cox,]
and03B303BF03C4* = (t’)* 0 y. By
Remark3.5,
ifnecessary,
changing F
1 andF2,
andreplacing
yby
03B303BF~ for some~~(H2(X, Z))
with~03BF03C4* = 03C4*03BF~
and9IN’ = 1N,,
we may assume thaty([FJ)
=[F’i] (1
i10).
Thenby
thefollowing
Lemma 3.20 and Lemma3.13, y(C(X))
cC(X’).
Therefore it now follows from the Torelli theorem for K3 surfaces[P-S]
that y is induced from anisomorphism
as desired. DLEMMA
(3.20). C(S) = {x~P(S)| (x, [Fi]~
>0,
1 i101.
Proof.
Thefollowing proof
is ananalogue
of[Na], Proposition
6.9. We usethe same notation as in
[V].
Let W be thesubgroup generated by
reflections S[Fi](1
i10).
Its Coxeterdiagram Y-
is defined as follows: the vertices of 1correspond
to{Fi}
1i 10 and two verticesFi
andFi are joined by
asimple
lineiff Fi·Fj =
1. Then Y- containsonly
twoparabolic subdiagram 8
andÊ.
whichall have the maximal rank 8. Also £ contains no Lanner’s
diagram
and nodotted lines. Hence it follows from
[V],
Theorem 2.6 that W is of finite index inO(S).
Hence thepolyhedral
coneis contained in
P(S) (see [V],
p. 335.By
a directcalculation,
we can also seethe last assertion without
using
the aboveVinberg’s theory).
If there exists asmooth rational curve E with E ~
F,
and[E] E S,
then E -Fi
0 for all i andhence
[E]
EP(S),
i.e.E2 0,
which isimpossible. Similarly
there is no smoothrational curve E with
i(E) - E
= 1. Nowlet 03B4~0394(S)
andx E P(S).
Let D be airreducible component of l5 which is a smooth rational curve. Then the above
implies
thatD=Fi
for some i or03C4(D)·D 2 (Since [03C9X]~(D’/0393’)0, r(D) -
D ~0).
In the latter case,(D
+03C4(D))2
0 and hencex, [D
+03C4(D)]~
> 0.Thus
~x, 03B4~
> 0 for any XEP(S)
with~x, [FiJ)
> 0(1
i10).
D Thus(D’/0393’)0 bijectively corresponds
to the set ofprojective isomorphy
classesof
plane quintic
curves with a cuspsatisfying (3.2).
Let
N0 be an
open setof N5,cusp consisting plane quintic
curves with a cuspsatisfying (3.2).
For anyfamily W - S
ofplane quintic
curves with a cusp, wecan construct a
family
Et - S of K3 surfaces with an involution as above.Associating
itsperiod
with each member ofPI,
we obtain aholomorphic
map from S toD’/0393’.
Therefore we have aholomorphic
map03BB: N0 ~ (D’/0393’)0
which is
bijective by
the above argument. LetN0
be acompactification
ofN0
with normal
crossing boundary.
Thenby
Borel’s extension theorem[B], Â
canbe extended to a
holomorphic
map fromil,
to theprojective compactification of D’/0393’
due toBairly-Borel [B-B].
Henceby GAGA, 03BB
isregular.
Since  issmooth and
bijective
on a Zariski open set, we now conclude:THEOREM
(3.21). N5,cusp is birationally isomorphic
toD’/0393’.
4. Proof of the
rationality
The main purpose of this section is to prove the
following:
THEOREM
(4.1). D/0393 ~ (as quasi-projective varieties).
Proof.
For a lattice(L, ~ , ~),
we denoteby L(1/2)
the free Z-module L with thesymmetric
bilinear form( , )/2
valued in Q. Fix anorthogonal decompo-
sition N = U
~ U(2)
OE,(2).
ThenN(1/2)
=U(1/2)
Q U QEs
and the sublat- tice2U(1/2) = {2x| x~ U(1/2)1
ofU(1/2)
is isometric toU(2).
Under thisisomorphism,
we consider the lattice N’ ~U(2)
(f) U ~Es
as a sublattice2U(1/2)
~ U ~Es in U(1/2) Q U
~Es.
LetO(N(1/2))
be the group of isomor-phisms
of Z-modulepreserving
theform (, )/2. Obviously
N andN(1/2)
define the same bounded
symmetric
domain -9 andO(N)
=O(N(1/2)).
Let e1, e2 be a base ofU(1/2)
with the matrix(~ei,ej~) = [01/2 1/20] and e3,..., el2
a base of
U p E8.
With respect to thisbase,
any g EO(N(1/2))
has a matrixdecomposition
For
g’ E O(N’), similarly, g’ = A’ , B’D’] with
respect to a base {2e1, 2e2’
e3,...,e12} of N’.
LEMMA
(4.2).
For g =C
D~O(N(1/2)), g’
=C’ D’
~O(N’),
any entriesof
B and C’ are evenintegers.
Proof.
Put H = 01/2
and K =
«ei, ej~)3i,j12.
Theng~O(N(1/2))~tAHA+tCKC=H, tAHB+tCKD=0,
tBHB+tDKD=K.Let
{bi}1i10
be the first row vector ofB, {b’i}1i10
the second row vector ofB and A =
a, a2 .
Since U QEs
is even, thediagonals
ofK,
’CKC anda3 a4
’DKD are even
integers.
Then theequation
’AHA + tCKC = Himplies
thata1·a3
= 0,
a2. a4 ~ 0and a1·
a4 + a2·a3 ~ 1(mod 2).
Since any entries of’CKD are
integers,
theequation
’AHB + ’CKD = 0implies a1·b’i
+ a3·bi
---0,
a2·
t
+ a4·bi
~ 0(mod 2),
1 i 10. Theseimply that bi and b’i
are even.Next let
g’ = [A’C’ B’D’] E O(N’).
Let{ci}1i10
be the first column vector ofC’, t(a1, a3)
the first column vector of A’. ThenNote that
N(1/2) = (N’)*
and el, e2 generateAN, = (N’)*/N’.
Sinceg’
preservesAN,
andU~E8
isunimodular, 03A3(ci/2)ei+2~U~E8
and hence Ci is even.Similarly
any entries of the second column of C are even. D12 12
Let z
= E
zi ei c- -q and z’ =z’ 1 (2e 1)
+z2(2e2) + E z’iei
E -9’ behomogeneous
i= 1 i=3
coordinates. We define a
biholomorphic
mapAlso
by
Lemma4.2,
thehomomorphism
is well-defined and an
isomorphism
of groups. SinceqJ(g(z») = tf¡(g)(qJ(z»
forany g~O(N(1/2)),
9 induces anisomorphism
fromD/0393 = £Q/O(N) = D/
O(N(1/2))
toD/0393’ = D’/O(N’).
SinceN(1/2)
and N’ define the same rational structure onD,
9 can be extended to anisomorphism
between theprojective compactifications
ofD/0393
anddue
toBairly-Borel [B-B].
Thus we haveproved
Theorem 4.1. DCombining
Theorem 4.1 and Theorem3.21,
we have:THEOREM
(4.3). D/0393 is birationally isomorphic
toN5,cusp.
By Proposition 2.2,
we now conclude:COROLLARY
(4.4).
The moduli space JIof Enriques surfaces
is rational.Remark
(4.5).
The author does not know thegeometric meaning
of theisomorphism
in Theorem4.1,
inparticular,
whether there is a birationalisomorphism g
fromN5,cusp
to -47forming
thefollowing
commutativediagram (using
the notationof §2),
which isconjectured by Dolgachev [D2]:
Acknowledgement
This work was
begun
while the author was a visitor at theUniversity
ofMichigan.
1 would like to thankIgor Dolgachev
forinviting
me and forvaluable conversations.
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