C OMPOSITIO M ATHEMATICA
N ICOLE A RTHAUD
On Birch and Swinnerton-Dyer’s conjecture for elliptic curves with complex multiplication. I
Compositio Mathematica, tome 37, n
o2 (1978), p. 209-232
<http://www.numdam.org/item?id=CM_1978__37_2_209_0>
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209
ON BIRCH AND SWINNERTON-DYER’S CONJECTURE FOR ELLIPTIC CURVES WITH COMPLEX MULTIPLICATION. I.
Nicole Arthaud
Sijthoff & Noordhoff International Publishers - Alphen aan den Rijn
Printed in the Netherlands
Introduction
Let K be an
imaginary quadratic field,
and E anelliptic
curve withcomplex multiplication by
thering
ofintegers
of K. Assume that E is defined over a finite extension F ofK,
and letL(EIF, s)
be the Hasse-Weil zeta function of E over F.Deuring
has proven thatL(E/F, s)
can beanalytically
continued over the wholecomplex plane, by identifying
it with aproduct
of Hecke L-series with Grôs- sencharacters(see [7],
Theorem7.42).
Theconjecture
of Birch andSwinnerton-Dyer
asserts thatL(EIF, s)
has a zero at s = 1 of orderequal
to gF, the rank of the groupE(F)
ofpoints
of E with coor-dinates in F.
Recently,
Coates and Wiles[4]
made some progress on a weak form of thisconjecture. Namely, they
showed that if K has class number 1 andF = K,
thengF > 1 implies
thatL(EIF, s)
does indeed vanish at s = 1. The aim of the present paper is to extend Coates and Wiles’proof
to the case in which K has class number1,
E is still defined overK,
but the base field F is now anarbitrary
finiteabelian extension of K.
THEOREM 1: Let K be an
imaginary quadratic field
with class number1,
and E anelliptic
curvedefined
overK,
withcomplex multiplication by
thering of integers of
K.If
F is afinite
abelianextension
of
K such that E has apoint of infinite
order with coor-dinates in
F,
thenL(E/F, s)
vanishes at s = 1.In a
subsequent,
butconsiderably
moretechnical,
paper[1] ]
inpreparation,
we shall prove ananalogous
result when(i)
no restriction is made on the class number ofK, (ii)
the base field F isagain
supposed
to be an abelian extension ofK,
andfinally (iii)
the torsionpoints
of E are assumed to generate over F an abelian extension of K(see
Theorem 7.44 of[7]
for a necessary and sufficient condition for(iii)
to be valid forE).
Since the methods of[4] depend crucially
onthe
explicit knowledge
of class fieldtheory
for abelian extensions ofK,
there seems to be littlehope
atpresent
ofproving
results likeTheorem 1 without
hypotheses (ii)
and(iii)
above.The broad outlines of the
proof
of Theorem 1 followfairly closely
the
arguments
in[4]. However,
there are somesignificant
and inter-esting
innovations indealing
with anarbitrary
finite abelian extension of K as base field. Inparticular,
certainpartial
Hecke L-functions with Grôssencharactersplay
a natural role in theproof.
This is instriking analogy
with thetheory
ofcyclotomic Zp-extensions,
wherethe values of
partial
L-functions formed with characters of finite ordergive
the coefficients ofStickelberger
ideals(see [2]). Also,
we havesimplified
theproof
of[4]
in several cases(cf.
theproof
ofTheorem
19).
In
conclusion,
1 wish to thank John Coates for hisguidance
withthis work.
1. Notation
To a
large
extent, we follow the notation of[4].
Thus K will denotean
imaginary quadratic
field with class number1, lying
inside thecomplex
field C, and 6 thering
ofintegers
of K. As in the Intro-duction,
E will be anelliptic
curve defined overK,
whosering
ofendomorphisms
isisomorphic
to 6. We fix a Weierstrass model for Ewhere g2, g3
belong
toC,
and where the discriminant of(1)
is divisibleonly by
theprimes
of K where E has a badreduction,
and(possibly) by
theprimes
of K above 2 and 3. Letp(z)
be the associated Weierstrassfunction,
L theperiod
lattice ofp(z),
and)(z) = (p(z), p’(z».
Choose III E L such that L = no. Weidentify 0
with theendomorphism ring
of E in such a way that theendomorphism corresponding
to a E 0 isgiven by e(z) - e(az).
If a E0,
we writeEa
for the kernel of theendomorphism
a of E.Let tp
be the Grôs-sencharacter of E over K as defined in
[7], §7.8.
We denote the conductor ofJi by f,
and writef
for some fixedgenerator
off.
Let F be an
arbitrary
finite abelian extension ofK,
which will be fixed for the rest of the paper. We write S for the finite setconsisting
of
2, 3,
and all rationalprimes
q which have aprime
factor inK,
which is either ramified in
F,
or at which E has a bad reduction.Henceforth,
p will denote a rationalprime,
whichsplits
inK,
and which does notbelong
to the finiteexceptional
set S. We write p andp-
for the factors of p inK,
andput
7r =tp(p). Thus, by
the definition ofol,
17" is agenerator
of the ideal p.Finally, let g
denote the leastcommon
multiple
of the conductor of41
and the conductor ofFIK.
2.
C omputation
of conductorsWe now compute the conductors of various abelian extensions of K which occur in the
proof
of Theorem 1. Thearguments
are similar to those in§2
of[4].
If a E(9,
recall thatEa
is the group of a-divisionpoints
on E.LEMMA 2:
Let b = (h)
be anymultiple of
the conductorof ip.
ThenK(E,,)
is the ray classfield of
Kmodulo b .
PROOF:
By
the classicaltheory
ofcomplex multiplication,
the ray class fieldmodulo b
is contained inK(Eh).
To prove the converse, we use the notation and results of Shimura[7].
LetU(b)
be thesubgroup
of the idèle group of K as defined on p. 116 of[7],
and let x be any element ofU(b)
with jCoo= 1. Since the conductorof tp
dividesb,
itfollows from Shimura’s
reciprocity
law(cf.
theproof
of Lemma 3 in[4])
that the Artinsymbol [x, K]
fixesEh.
ThusK(Eh)
is contained inthe ray class field
modulo h ,
and theproof
of the lemma iscomplete.
Recall
that g
is the least commonmultiple
of the conductor of03C8
and the conductor of FI K.Also,
p is any rationalprime,
not inS,
whichsplits
inK,
say(p) = pp-
LEMMA 3: For each n ?
0,
the conductorof Fn
=F(E1T"+I)
over K isequal
tof n
=,nll. Moreover, if en
denotes the ray classfield of
Kmodulo
f n,
thenen
is thecompositum of Fn
and H =K(Eg),
andF,, nH = F.
PROOF: Let An denote the conductor of
Fn/K.
SinceFn
CK (E g1T"+I),
and the conductor of this latter field is
f n
=gpn+l by
Lemma2,
we concludethat g"
dividesfn.
On the otherhand,
it is clear that the conductor of F over K divides gn.Also,
as E has agood
reductioneverywhere
overFn (see
Theorem 2 of[4]),
the Grôssencharacter of E overFn
must be unramified. As the Grôssencharacter of E overFn
is thecomposition
of the norm map fromFn
to K with41,
it followsthat the
conductor f of t/1
divides gn.Combining
these last twofacts,
we conclude
that g
divides gn. Butp"" divides gn
becauseFn
containsthe ray class field modulo
p"".
As(p, g)
= 1by hypothesis,
we deduce that gn =f n,
as asserted. To prove the final statement of thelemma,
we recall that
e,,
=K(E,,.,i) by
Lemma2,
and thuséBn
iscertainly
the
compositum
ofFn
and H. Now p istotally
ramified inK(E,.-,i) by
the rudiments of Lubin-Tate
theory.
As p does not divide the conductor of F overK,
it follows that eachprime
of F above p istotally
ramified inFn.
Since p does notdivide g by hypothesis,
and His the ray class field
modulo g by
Lemma2,
we deduce thatFn
fl H =F,
asrequired.
3.
p-Adic logarithmic
derivativesWe use the same notation as
[4]
for the f ormal groupsÊ
and Z.Thus
Ê
is the f ormal groupgiving
the kernel of reduction modulo pon
E,
and Z is the Lubin-Tate formal group for which[-rr](w) _
irw + wp.
By
Lubin-Tatetheory, Ê
and W areisomorphic
over thering C,,
ofintegers
of thecompletion Kp
of K at p. For a fullerdiscussion,
see
§3
of[4].
Choose a fixed
algebraic
closureKp
ofKp.
We can assume thatE,
lies inKp,
and we define the extension 0 ofK p by
Put G =
G(4JIKp).
Of course, G is endowed with the canonical character X, with values inZ p, giving
the action of G onE.,,
orequivalently,
onW,,. Thus,
if A is anyZp[G]-module,
it has a canoni-cal
decomposition
where
A (k)
is the submodule of A on which G acts via the k-th powerof Y.
Let u be a fixed
generator
f orW,,
so that u is a localparameter
for 0. Let U be the group of units of 0 which are = 1 mod u. For 1 S k S p -2,
we definehomomorphisms
as follows. If a E
U,
we choose any power seriesf (T) = Y-;=o akT k
with
ak EOr"
such thatf (u) = a.
We then define’Pk(a)
to be the residue class inC,,Ip
of the coefficient ofTk
in the power seriesT (d/d T) log f (T).
Since 1 S k S p - 2 and the ramification index of 0over
K.
is p -1,
it is easy to see that’Pk(a)
isindependent
of thechoice of
f (T),
and so is well defined.REMARK: In
defining
çk in[4],
one insisted that the power seriesf (T)
had ao = 1. It is more convenient for thearguments
in§4
to work with power series whose constant term is notnecessarily
1. Ofcourse, the two definitions of çk are the same for
1:5 k :5 P - 2.
However,
one cannot define çp-iby
thepresent
method.In the
proof
of Theorem1,
we shallonly
be interested in the case in which 0 contains no non-trivial p-power roots ofunity.
Recallthat, by
Lemma 12 of[4],
if p> 5,
then 0 can contain a non-trivialp-th
root of
unity
if andonly
if 7T + if = 1. The next lemma isplain
fromLemmas 9 and 10 of
[4].
LEMMA 4: Assume that 0 contains no non-trivial
p-th
rootof unity.
Let k be aninteger
with 1:5 k :5 p - 2. Then ÇOk vanishes onUU) for jO k mod(p - 1), and çk
induces anisomorphism
Now consider our fixed finite abelian extension F of
K,
andFo
=F(E,).
Let 9’ be the set ofprimes
ofFo
above p. For each qe 91,
letFo,q
be thecompletion
ofFo
at q, and writeUq
for the units inFo,q
which are == 1 mod q. Put
Now assume
that p splits completely
in F.Thus,
for each qe Y,
there exists anisomorphism r4: Fo,q -"+ 0,
which preserves the valua-tions of both fields.
Composing
thisisomorphism
with the map çkgiven by (3),
we obtain ahomomorphism
We define
to be the
product
of thehomomorphisms (5)
over all q E 9.Plainly
G =
G(FOIF)
=G( tPl Kp)
acts on(4),
because it acts on each of theUq
in the natural way. The next lemma is now
plain
from Lemma 4.LEMMA 5: Assume that 0 contains no non-trivial
p-th
rootof unity,
and that psplits completely
in F. Let k be aninteger
with1:!g k:5 p - 2. Then ’PF,k vanishes on
OU u) for jO
kmod(p - 1),
and ’PF,k induces anisomorphism
Put
d = [F : K].
Inpractice,
we shall use thefollowing
immediateconsequence of Lemma 5.
COROLLARY 6: Under the same
hypotheses
as Lemma5,
let A beany
Zp[G]-submodule of
ou.Then, for
eachinteger
k with 1 - k:5p -
2,
theeigenspace (OUI A)(k) 0 if
andonly if lI’F,k(A)
has dimension less than d over thefield (Jp/p.
4.
Elliptic
unitsAs in
[4],
a vital role in theproof
of Theorem 1 isplayed by
theelliptic
units of Robert[6].
Webegin by briefly recalling
the definitionof these
elliptic
units. Let 9 be the setconsisting
of allpairs (A, y),
where A =
{a j : j
EJI
and JV =1 nj : j
EJ},
here J is anarbitrary
finiteindex set, the aj are
integral
ideals of Kprime
to ,S and p, andthe nj
are rational
integers satisfying Ejj nj(N a j - 1)
= 0. Given such apair (A, JV),
weput
where
8(z, aj)
is as defined at thebeginning
of§4
of[4].
Recall thatf n
=gIp"+’
is the conductor ofFn
=F(E,.,i)
over K. Asbefore,
lete,,
be the ray class field of K modulo
f n.
If pn is anarbitrary primitive f n-division point
ofL,
Robert[6]
has shown that8(Pn, A, J{)
is a unitof the field
en- Moreover,
as(A, JV)
ranges over0,
theO(pn, A, X)
form asubgroup
of the group of units of9lln.
We denote thissubgroup
by C(6n,
and call it the group ofelliptic
units of9lln (note
that Robert’s definition of the group ofelliptic
units is different fromours).
Asimilar argument to that
given
in theproof
of Lemma 20 of[4]
showsthat
C(6n
is stable under the action of the Galois group oféBn
overK,
and is
independent
of the choice of theparticular primitive f n-division point
pn.Finally,
we define theelliptic
unitsCn
ofFn
=F(E,.,i)
to bethe group
consisting
of the norms frome,,
toFn
of all units inC(6n.
Forsimplicity,
we often write C f orCo.
Let p =
nlg,
where q =(g).
Here L = no is theperiod
lattice ofp(z).
Asabove,
leteo
be the ray class field of K modulof o
= gp.Lemma 3 tells us that we have the
diagram
of fieldsIf L is any finite abelian extension of
K,
and c is anintegral
ideal of Kprime
to the conductor ofLIK,
we write(c, LIK)
for the Artinsymbol
of c for the extensionLIK.
We now choose and fix a set B ofintegral
ideals ofK,
which areprime
tof o,
and which are such that{(b, gj/,o/ K) : b E B}
isprecisely
the Galois group ofeo/Fo.
It is thenplain
from(7)
that the restrictions of the(b, 9ltol K), b
EB,
to H isprecisely
the Galois group ofHIF.
If a is an
arbitrary integral
ideal of Kprime
to S and p, we defineLEMMA 7:
A (z, a) is
a rationalfunction of p(z)
andp’(z)
withcoefficients
in F.PROOF: This is
entirely
similar to the firstpart
of theproof
ofLemma 21 of
[4],
and so we omit it.It is now convenient to introduce some
notation,
which will be usedrepeatedly
in this section. Let W denote the Galois group of F over K.If c is an
integral
ideal of Kprime
to the conductor ofFIK,
we writeUc for the Artin
symbol (c, FIK). Finally,
if a E CO andR(z)
is a rational function ofp (z), P’(z)
withcoefficients
inF,
thenR,(z)
willdenote the rational
function
ofp(z), p’(z),
which is obtainedby
letting a
act on thecoefficients
ofR(z).
Let k be an
integer > l.
Recallthat ap
denotes the Grôssencharacter of E. For each aE CO,
we introduce thepartial
Hecke L-functionwhere the summation is over all
integral
ideals a ofK, prime to g,
such that the Artinsymbol
CFa isequal
to a. It can be shown that(F(CF, k; s)
can beanalytically
continued over the wholecomplex plane.
Let£F(a, k)
denote the value of(F(CF, k; s)
at s = k.LEMMA 8: For each o-
EEW,
we havePROOF: Let c be an
integral
ideal ofK, prime
to g, such that u = UC.By
the definition of theGrôssencharacter ol
in[7],
we haveIt follows
easily
from theexpression
forO(z
+1(b)p, a)
as a rational function ofp(z), p’(z),
with coefficients in H(see (23)
of[4]),
thatIf Y is any lattice in the
complex plane,
let{(z,:£)
andp(z,:£)
bethe Weierstrass zeta and
p-functions
of Y. DefineThen
(cf.
theproof
of Lemma 21 of[4]) il(z, Y)
has the power seriesexpansion k=, dk(!£)Zk, where q = ol(c)p
andThus we must show that
ck(a, o,),
as defined in Lemma8,
satisfiesAs in
[4],
we putkk
=12(-I)k-lp-k.
We write 9B for a fixed set ofgenerators of the ideals in B.
Also,
we let y denote a fixed generator of the ideal a, and c a fixedgenerator
of c. The argument now breaks up into three cases. Much of thereasoning
is similar to that in theproof
of Lemma 21 of[4],
so that we refer there for details from timeto time.
Case 1. We suppose that k -- 3. Since
we conclude
easily
from(10)
thatWe now write
4i(bc) =,E(bc)bc,
where b is the generator of b inB
andE(bc)
is a root ofunity
inK,
and argue inexactly
the same wayas in Case 1 of the
proof
of Lemma 21 in[4].
In this way, it follows thatwhere N denotes the norm from K to Q. Let W denote the group of
roots of
unity
of K. Since theGrÕssencharacter «/1
is defined modulo g, the natural map of W into(O/g)X
isplainly injective. Now,
as H isthe ray class field
modulo g by
Lemma2,
we canidentify
the Galoisgroup of H over K with
(Clg)xl
W via the Artin map. Since the Artinsymbol
of c =( c )
forF/K
isequal
to u, it is therefore clear thatli£bc:
li EW,
b Eg}J}
is acomplete
set ofrepresentatives
of thoseelements in
(O/g)X,
whose Artinsymbol
has restriction to Fequal
to u.In other
words,
is the set of all
algebraic integers
inK, prime
to g, such that the Artinsymbol
forF/K
of the associatedprincipal
ideal isequal
to a. Sincewe can
plainly
rewrite the aboveexpression
fordk(L)
aswhere wk
denotes the number of roots ofunity
inK,
it follows thatNow consider
dk(a-1L). Recalling
that a =(y),
it follows from(10)
that
Substitute y =
r(a)E-1(y)
for the first occurrence of y on theright
hand side of this
equation. Again arguing
in the same way as in Case 1 of theproof
of Lemma 21 in[4],
we obtainNow
is the set of all
algebraic integers
inK, prime to g,
such that the Artinsymbol
forFIK
of the associatedprincipal
ideal isequal
to UU4. ThusWe have theref ore proven
(11)
in this case.Case 2. We assume that k = 2.
Now,
for any latticeIf,
where
S2(y)
is as defined at thebeginning
of§4
of[4]. Taking If
=L,
we deduce from
(9)
thatArguing
as in theprevious
case, we obtaind2(L) _ lk2CF(o,, 2).
Similarly, d2(a-1L)
=À2.p2(a)(F(uUtt, 2),
and so we obtain(11)
in thiscase.
Case 3. We assume that k = 1. If 5£ is any
lattice,
letH(s,
z,Y)
denote the
analytic
continuation in s of the series(this
series converges forR(s)
>3/2). Then,
as is shown in case 3 of theproof
of Lemma 21 of[4],
we havewhere
g(Y)
is defined in the sameproof.
First take Y = L. It follows from(8)
thatwhere r =
ybeb (03C8r(bc)p) (here, by
the limit as s -1, we mean
the value of theanalytic
continuation at s =1).
Asbefore,
we deduceeasily
thatNext take 0 =
y-’ L.
ThenTaking
the factory-’
out of each a, andrecalling
thatg( y-’ L) _ Nag(L),
we conclude thatWe now argue in the same way as in case 1 to deduce that
Combining
these twoexpressions
ford1(L)
andd1(a-1L),
we see that(11)
is true for k = 1. Thiscompletes
theproof
of Lemma 8.COROLLARY 9: For each
integer
k &1,
and each U ECO, a-kCp(u, k) belongs
to F.Moreover, if
T ECO,
then(a-kCF(U, k»’ =f2 -kCF (,ro-, k).
PROOF: The first assertion is
plain
from Lemmas 7 and8,
ontaking
a 76 1 to be an
integral
ideal ofK, prime
to S and p, such that Uo. = 1.The second assertion follows
similarly,
onnoting
thatck(a, U)T
=Ck(a, TU)
for all k ? 1 becauseA,(z, A.)T = ATu(z, a).
HereAu(z, a)T
denotes the rational function of
p(z)
andp’(z),
with coefficients inF,
which is obtainedby letting
Tact on the coefficients ofA,(z, a).
Let
.pF
denote the Grôssencharacter ofF,
which is obtainedby composing ol
with the norm map from F to K.Plainly .pF
is un- ramified outside g.Thus,
for eachinteger k - 1,
we can definethe
product being
taken over allprimes 13
of F which do not divide g.Of course,
LF(O-’F, s)
will not, ingeneral,
be aprimitive
HeckeL-function,
but this will not beimportant
in theproof
of Theorem 1.Let Î
denote the group of allhomomorphisms
from W into the group of non-zerocomplex
numbers. If 8e ’à,
we associate with it thecomplex
L-functionOne verifies
immediately
that we have theproduct decomposition
The next lemma
gives
the basicrationality properties
of the value ofLF(03C8}, s)
at s = k.LEMMA 10: For each
integer k ? 1, n-kdLF(03C8}, k) belongs
toF,
and the ideal that itgenerates is fixed by
the actionof
Cfi.PROOF:
By (12)
and the first assertion ofCorollary 9,
we see thatvk -
n-kdLF(03C8, k) belongs
toM,
where M is the field obtainedby adjoining
to F the values of all (J EW. But, again by (12),
it is clearthat Vk
is fixedby
the Galois group of M overF,
and sobelongs
to F.Now take T to be any element
of Cfi,
and let Tl be an element ofG(M/K)
whose restriction to F is T. The second assertion of Corol-lary
9implies
thatwhence it is
plain
from(12)
that the ideal in Fgenerated by vk
is fixedby W.
REMARK: If W has no
quadratic characters, (12)
and(13)
show thatLF(41F, k)
isactually
fixedby %,
and sobelongs
to K.We now
investigate
theintegrality properties
of the numbers inCorollary
9 and Lemma 10.Let 13
be anyprime
of Flying
above p,Fqg
thecompletion
of F atB,
andCe
thering
ofintegers
ofFe.
Wecan view
A,(z, a)
asbeing
a rational function ofp(z)
andp’(z)
with coefficients inFqg,
via the canonical inclusion of F inFe.
Hence wecan
expand A,(z, a)
in terms of theparameter t
=20132p(z)/p’(z)
of theformai group
Ê.
LEMMA 11:
Let q3
be anyprime of
F above p. In termsof
theparameter t =
-2p(z)lp’(z), Au(z, a)
has anexpansion
whose
coefficients
allbelong
toÙga,
and whereh o,u«(1, 13)
is a unit in.
PROOF: This is the same as the
proof
of Lemma 23 of[4] (on recalling
that(g, p)
= 1by hypothesis),
and so we omit the details.LEMMA 12: Let k be an
integer
with 1 _ k S p - 1. Then(i) for u E , f2 -kCF (u, k)
isintegral
at eachprime of
F above p, and(ii)
f2 -kd LF(IPF, -k k)
isintegral
at eachprime of
F above p.PROOF: In view of
(12),
it isplain
that(ii)
is a consequence of(i).
We now
proceed
to deduce(i)
from theprevious
lemma. Let w be the parameter of the Lubin-Tate formalgroup W
such that[ir](w) =
7rw + wP
(cf. §3
of[4]).
Fix aprime 13
of F above p. For the moment, take a to be anarbitrary integral
ideal ofK, prime
to S andp. Since t
can be written as a power series in w with coefficients in
(j J"
it followsfrom Lemma 11 that
A,(z, a)
can beexpanded
as a power series in w, sayf ( w),
with coefficients inCe,
and whose constant termf (0)
is aunit in
ûq3. Moreover,
sinceZ = W + Y" 2 aiw’,
wherea; = 0
unlessi --- 1
mod(p - 1) (cf.
Lemma 7 of[4]),
the coefficients ofz’
andwk (05 k:5 p - 1)
in thez-expansion
ofA,(z, a)
and inf (w)
areplainly equal.
It follows that the coefficients ofz’
andw’ (1 :!5 k :5 p - 1)
in thez-expansion
ofz(d/dz) log Au(z, a)
and inw(d/dw) log f (w)
arealso
equal.
But the coefficients of this latter series lie inOh
becausethe constant term
f (0)
off ( w)
is a unit inCe.
We conclude from Lemma 8 thatis
integral at 13
for 1 S k S p - 1. We now make aspecial
choice of theideal a. Let e denote a
generator
of the ideal(12g)nZ.
Choose n tobe a rational
integer, prime
to p, such that 1 + new is not divisibleby p,
and take a =(1
+ neir).
Then Na --- 1modp.
Also Ua = 1 becausethe conductor of
F/K divides e,
andqi’(a) = (1
+en71’)k
= 1mod p,
because the conductor of03C8
divides e. ThusNa _ ek(a)
is a unit at p,and so assertion
(i)
follows from(14).
Thiscompletes
theproof
ofLemma 12.
We now prove a technical
lemma,
which establishes the existence of dpairs (A, N)
in9,
withproperties
which will be needed later in this section. Tosimplify
the statement of thelemma,
we choose afixed
numbering
of the elementsof W,
say UJ, ..., ad, with ai = 1.LEMMA 13: Let k be an
integer
with 1 k p - 2. Then there exist dpairs (A (h)@ V(h»
E9,
wherewith the
following properties. Firstly, .pk(al);i1é
1 modp. Secondly, for
1 :5 h
:5 d,
we have(i) .pk(a Bh» == 1 mod p, (ii) aag>
=1, (iii) aaj> = (J’hl,
and
(iv) n 2 is prime to
p.PROOF: Let e denote a generator of the ideal
(12g)
n Z, and let13
mod p be a generator of«(JI p)X.
First consider the case h = 1. Let n be a rationalinteger, prime
to p, such that 1 + ne7T isprime
top,
and takea B1) = (1 + en 17" ).
Choosea 2’ _ (a 2’),
wherea 1)
is analgebraic integer
in Ksatisfying a 2’ ---
1 modeù,
anda 21 --- B
mod 17". Letn B1) = N a 21 -1
andn 21 _ -(N a i’ - 1 ),
so thatn 2’
isprime
to p because(p, ne) = 1. Moreover,
as the conductorof .p divides e,
we have.pk(a B1)
= 1 mod p, and.pk(a31) == j8
1 mod p.Finally,
both ideals areprime
to S and pby construction,
and(J’ ,,(1) = aaj>
= 1 because the conductor of F over K also divides e. Thiscompletes
the case h = 1.For h >
1, again
choosealhl = (1
+neir)
andn(h)
=_(Na(h) _ 1).
Takea 2 (h)
to be anintegral
ideal ofK, prime
to S and p, such that0, 2 0,h
and letn (h) = Na (h) 2 _1.
Theproof
of the lemma is nowcomplete.
So far in this
section,
we have made nohypothesis
on the decom-position
of p in the extensionFIK,
other thanrequiring
that p doesnot
ramify
inFIK.
We now suppose, until furthernotice,
that psplits completely
in F. We use the notation of the last part of§13.
Thus 91 will denote the set ofprime
ofFo
=F(E,)
above p, and 6/1, willagain
be
given by (4).
Letbe the canonical
embedding
ofFo
in theproduct
of itscompletions
atthe
primes q
in 91. Recall that C denotes the group ofelliptic
units ofFo,
as defined at thebeginning
of thissection.
We write OE for thesubgroup
of Cconsisting
of all elements which are - 1mod q
foreach q E f:f. Let
i(OE)
be the closure of1,(OE)
in thep-adic topology.
Our aim is to
compute,
for 1:5 k p -2,
theimage
ofi(OE)
under thehomomorphism
’PF,kgiven by (6).
Recall that 0 is the field
Kp(E1T)’
which lies inside our fixedalgebraic
closure ofK,,.
Since psplits completely
in Fby hypothesis,
the
completion
ofFo
at each q in Y isplainly topologically
isomor-phic
to 0. Tosimplify notation,
weadopt
thefollowing
convention.We fix one
embedding
ofFo
in0,
and view thisembedding
assimply being
an inclusion. This amounts tochoosing
one fixedprime
inY,
which we denoteby
q. Let f2 denote the Galois group ofFo
overK(E,).
Since p istotally
ramified inK(E,),
andsplits completely
inFolK (E’Ir)’
the otherprimes
in Y aregiven precisely by the q«
fora E
il,
and theembedding
ofFo
in 0corresponding
toq’
isgiven by
r itself. With this
convention,
the map(15)
issimply given by
Now take x to be any
elliptic
unit in OE. Moreexplicitly,
let1(T)
bethe
point
ofE, corresponding
to our chosengenerator
u ofZ,
underour fixed
isomorphism
fromÊ
to 6.Then, by definition,
x will be ofthe form
for some
pair (A, S) belonging
to 9. Now f2 =G(FoIK(E,»
iscanonically isomorphic
to W =G(FI K)
under the restriction map, andwe shall
identify
these two Galois groups in this way when there is nodanger
of confusion. Since f2 fixesE7T’
it is thenplain
thatwhere
Au(z, aj)
is as definedjust
after Lemma 7LEMMA 14: Let x be the
elliptic
unit in 0152given by (17). Then, for
each
integer
k with 1 --5 k:5 p -2,
we havewhere
PROOF: We can obtain a power series
f,(w),
with coefficients in(J fH
such thatf,(u)
= x’ in thefollowing
manner. Let w be the parameterof the Lubin-Tate f ormal
group 6,
andexpand
the rational function ofp(z)
andp’(z),
with coefficients inF, given by
as a formal power series in w. Denote the power series obtained in this way
by f,(w). By
lemma 11 and the fact that t can be written asa power series in w with coefficients in
C.,
we conclude thatf,(w)
does indeed have coefficients in
C..
It is thenplain
that XU =f,(u).
Moreover,
as z = w+ l’ 2 aiw’,
where ai = 0 unless i = 1mod(p - 1) (cf.
Lemma 7 of[4]),
we see that the coefficients ofz’
andwk (0 S k S p - 1)
in the seriesexpansions
of(18)
in terms of z and wmust be
equal.
Thus the conclusion of the lemma is now clear from Lemma 8 and the definition of lp p,k·We now come to the first main result of this section. Since the
elliptic
units ofFo
are stable under the action of the Galoisgroup of Fo
over K
(cf.
Lemma 20 of[4]),
itfollows,
inparticular,
that(S)
is aZp[G]-submodule
ofô/1,
where G =G’(Fp/F).
We can therefore take the canonicaldecomposition (2)
ofOkli(OE).
We follow theterminology
of
[4]
and say that p is anomalous for E if ir + 1-T = 1.THEOREM 14: Assume that p is a
prime
number >5satisfying (i)
p does notbelong
to thefinite exceptional
setS, (ii)
psplits
inK,
say(p) = pp, (iii)
psplits completely
inFI K,
and(iv)
p is not anomalousfor
E. Let OE be the groupof elliptic
unitsof Fo
=F(E7T)’
which arem 1 mod q
for
each q E Y.Then, for
eachinteger
k with 1 --5 k S p -2,
theeigenspace (ûllli(0152)ik)
is non-trivialif
andonly if 12-kdLF(k , k)
10 mod q
for
each q E Y.REMARK:
By
Lemma10, f2-k DLF«PF, -k k)
n 0 mod q for oneprime
q in Y if andonly
if the same congruence is valid for all q in Y.PROOF: We
adopt
the same convention asbefore,
in which wehave fixed one
prime
q inY,
and viewFo
asbeing
contained in 4J. We make use of thefollowing
formalidentity
in the groupring F[lâ],
which is very reminiscent ofcomputations
withStickelberger
ele-ments in
cyclotomic
fields. For each a EW, put
By Corollary 9, £%a, k) belongs
to F. WriteThen,
for eachintegral
ideal a of K which isprime
to g, weplainly
have
where
By Corollary 6,
theeigenspace (OU/ i (OE»(kl
will be trivial if andonly
if’PF,i i (0152))
has dimension d over the finite fieldFp
with p elements.This
suggests
that westudy
theimage
under lpF,k ofany d
elements of). Suppose
therefore that(A(hl, S*(hl) (1::;
h sd)
are any d ele-ments of 0. Let Xh,
given by (17),
be theelliptic
unitcorresponding
to(A(h), X(h».
We assume that xl, ..., xdbelong
to OE. Writeand
For o- E 19 and 1 h
d,
we definewhere
8j( U, a h»
isgiven by (21).
It is thenplain
from(20)
that wehave the
identity
We
let -
denote the d x d-determinant form from thebhu (h
=i,..., d, o- c W).
By
Lemma14,
the determinant of the d vectorsis
equal to H
mod q. We nowproceed
tocompute S.
To thisend,
let14
be the group ofhomomorphisms
from 19 to themultiplicative
group of non-zerocomplex
numbers. LetUt = 1,
U2,..., ad denote the distinct elements ofri, and XI
=1,
X2, ..., Xd the distinct elements ofÎ.
Write Tand 1
for the d x d-determinants formed from theX; ( yh ),
Xi(uh’) (1 -«5 i, h --5 d), respectively. Applying
each ofthe xi
to theequation (22),
we conclude thatWe now make two observations. Put
L1;{ffr}, k) = ADLF( -k k).
Then itis