A NNALES DE L ’I. H. P., SECTION C
A. C ONZE
J.-M. L ASRY
J. A. S CHEINKMAN
A system of non-linear functional differential equations arising in an equilibrium model of an economy with borrowing constraints
Annales de l’I. H. P., section C, tome 8, n
o5 (1991), p. 523-559
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A system of non-linear functional differential
equations arising in
anequilibrium model
of
aneconomy with borrowing constraints
A. CONZE
CEREMADE, Universite Paris-Dauphine J.-M. LASRY
CEREMADE, Universite Paris-Dauphine
J. A. SCHEINKMAN University of Chicago (*)
Vol. 8, n° 5, 1991, p. 523-559. Analyse non linéaire
ABSTRACT. - We
study
the existence of solutions to a nonlinear func- tional differentialsystem
that describes theequilibrium
of adynamic
stochastic economy with
heterogeneous agents facing borowing
con-straints. Our model is a
generalization
of the one studied in Scheinkmanand Weiss
[3]
todisplay
the effect ofborrowing
constraints inaggregate
economicactivity,
and the mathematicaltechniques
that wedevelopp
canbe useful to deal with more
complex
models.The
system
hasaspects
of a freeboundary
valueproblem
in which thereare different
equations
for differentdomains,
with the domains themselvesClassification A.M.S. : 90 A 16, 34 A 34, 34 K 35.
(*) This research was supported by a NSF U.S. - France binational grant INT H4 13966 and by a NSF grant SES 8420930. Some of this work was done while Scheinkman was
visiting Universite Paris-Dauphine and some while Conze was visiting the University of Chicago.
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire - 0294-1449 Vol. 8/91 /OS/523/37/$5.70/ © Gauthier-Villars
and their
boundary
determinedby
the solutions. It also has some of the characteristics ofhyperbolic systems
that one would obtainby
differentiat-ing
Hamilton-Jacobiequations.
Theseaspects
combine torequire,
at leastapparently,
a veryspecific
newapproach
to the existenceproblem.
Onepayoff
of thistechnique
is that the existenceproof
is also analgorithm
for
computation.
RESUME. - On etudie l’existence de solutions d’un
systeme
differentiel fonctionnel non lineaire decrivant1’equilibre
d’une economicstochastique dynamique
avec desagents heterogenes
soumis a des contraintes d’endette- ment. Notre modele est unegeneralisation
de celui etudie par Scheinkman et Weiss[3] qui
mettait en valeur les effets de contraintes d’endettementsur l’activité
economique agregee,
et sa resolution introduit destechniques mathematiques
utilies pour la resolution de modelesplus complexes.
Le
systeme possede
certainsaspects
d’unprobleme
avec frontiere libre pourlequel
il y a desequations
differentes pour differentsdomaines,
les domaines et leur frontiere etant determines par les solutions. Ilpossede egalement
certaines descaracteristiques
dessystemes hyperboliques
obtenupar differentiation
d’equations
de Hamilton-Jacobi. La combinaison deces
aspects
nécessite uneapproche specifique
duprobleme
d’existence.L’un des
avantages
de cettetechnique
est que la preuve d’existence fournitun
algorithme
de calcul des solutions.1. INTRODUCTION
Our purpose is to
study
asystem
of non-linear functional differentialequations [see equations (3 .1 )
to(3 . 6) below]
that arise in thestudy
of adynamic
model in economics thatgeneralizes
the modeldeveloped
inScheinkman and Weiss
[3].
Thesystem
comes from adynamic
model inwhich each
agent
has to solve a stochasticoptimal
controlproblem.
This paper should be of interest to mathematicians: since it is very non
classical, system (3 .1 )
to(3. 6) requires
mathematicaldevelopments
thatare, at least to us, novel. The
system
at firstglance
looks like asystem
ofnon linear
delay equations. Actually,
as thesign
of thedelay
isreversed,
one can not consider these
equations
asdelay equations. Moreover,
asthe coefficients of the
equations
are discontinuous functions of the sol-utions,
thissystem
has a flavor of a freeboundary problem,
i. e. one inwhich there are different
equations
for distinctdomains,
with the domains themselves and their "free"boundary
determinedby
the solution.Finally
this
system
has also some of the characteristics of thehyperbolic system
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
that one would
obtain by differentiating
an Hamilton-Jacobiequation.
These
aspects
combined torequire,
at leastapparently,
a veryspecific
newapproach
to the existenceproblem.
The paper should also be of interest to economists: the
proof
of theexistence of at least one solution to
system (3 .1 )
to(3. 6) provides
anentirely
constructivealgorithm
and makes easy toproduce
simulations of the model.Similarly
to what often occurs whenderiving
the Hamilton-Jacobi- Belmanequation
for anoptimal
controlproblem,
we first make an heuris- tic derivation ofsystem (3 . 1 )
to(3. 6),
and then show that any solution to thissystem provides
anequilibrium
of the model.The paper is
organized
as follows: in section2,
we introduce the model and write it as anequilibrium problem
in which to everyagent
is associatedan
optimal
controlproblem.
We then expose heuristic considerations thatprovide system (3 .1 )
to(3 . 6).
In section
3,
we prove that every solution of thissystem
is anequilibrium
solution.
Section 4
presents
the existence of a least one solution tosystem (3 .1 )
to
(3.6).
We firstintroduce
a reducedsystem
that allows us to constructa map from a functional space to itself. We show that solutions of
system (3.1)
to(3 . 6)
are fixedpoints
of this map. We then expose the main theorem that claims the existence of at least one fixedpoint.
Sections
5,
6 and 7provide
a collection of results that allows us to prove the main theorem. Section 5 contains resultsconcerning
the reducedsystem.
In section6,
we construct asupersolution
and a subsolution tothe fixed
point problem.
In section7,
we show the convergence of thealgorithm
thatprovides
a fixedpoint.
Finally,
in section 8 wepresent
acomplementary
results in aparticular
case of the model.
2. THE MODEL
Consider an economy with a
large
number(infinite)
of each of twotypes
ofinfinitely long
livedindividuals,
indexedby i =1,
2. Each"agent"
consumes a
single good
and also works in theproduction
of thatgood.
His labor
productivity
is however random and determinedby
the "state"of the economy. At any time the
state j
is an element of a finite set J with 2N elements. Instate j
one unit of labor oftype
1 individualproduces a~
units of theconsumption good
while one unit of labor oftype
2 individualproduces cx - j
units of theconsumption good.
Ifstate j prevails
a state
change
will occur with anexponential probability
distribution withmean duration
I/pj.
If a statechange
occurs, theprobability
that the nextVol. 8, n° 5-1991.
state is kEJ is
given by
where for convenience we choosev, ,=0.
We
write 03BBj, k
=Pj
and theprocess {st} represents
the state at time t.( 1 )
In order to make the twoagents symmetric
from an ex-antepoint
ofview,
werequire
that associated to eachstate j
there is another state cpJ)
such that
CXcp (j) = cx - j’
and~~ ~ ~~, _ k = ~,~, k
for all k E J.This
hypothesis
allows us to write withoutambiguity - j
inplace
of cp(/).
At each
point
in time an individual must choose how much to work and how much to consume. There is also an asset that the individuals can use to save. We choose units in such that when any onetype
holds a unit of the asset percapita,
the other must hold zero. The initial distribution of money is assumed to be the same within eachtype.
At eachtime t,
at each event (0 EQ,
let p(t, o)
denote theprice
of a unit of theconsumption good. Agents
oftype i,
i =1, 2,
take p(t, ~)
asgiven
and solve theproblem (P ‘) [equations (2 . 1 )
to(2 . 4)] :
subject
toNotice that any solution to
(P’)
mustsatisfy
In
(P i)
the individual chooses anyconsumption
andworking plan
thatsatisfies the constraint that no
borrowing
is allowed. Anequilibrium
is astochastic process
p (t, co)
such that ifco)
andco)
solvefor
i =1, 2,
then(demand
for moneyequals supply),
and(demand
forgoods equals supply).
Notice that since constraint(2.3)
appears in
(Pi), equation (2.7) actually
follows fromequation (2.6).
In
principle
one could find anequilibrium by considering
for eachprocess
p (t, co)
the processyi (t, co)
that solves andchecking
whether(1) Formally, {st}
is a Markov process on a probability space (S2, J, P) withAnnales de l’lnstitut Henri Poincaré - Analyse non linéaire
(2.6)
holds. Economic considerationssuggest, however,
another route tocompute
at least oneequilibrium.
We willgive
here an heuristicargument
that anequilibrium
shouldsatisfy
a certain set of non-linearequations
and later
proceed
to showprecisely
that a solution to theseequations
isin fact an
equilibrium
and that theseequations
have a solution as well asexhibiting
analgorithm
tocompute
it.Let z
(t, (o)
denote the average amount of asset heldby type
1 at time t and in event co. Notice that due to theno-borrowing constraints,
we mayassume
Oz(t, co)
1. We will look at anequilibrium
wherewhere p is a
C~
1 function of its firstargument.
Inreality
it is moreconvenient to work with the
price
of money in terms ofgoods,
so wewrite
qj (z)
=1/p (z, j).
In order to treat the twotypes symmetrically,
weassume that
Thus,
one may think that consumers takez (t, c~)
and the functionsqj : [0, 1] - R
forall j E J
asgiven,
and solve(P i).
Assume further thatconsumers forecast that z will be an
absolutely
continuous functions suchthat,
where the derivativeexists,
where is function for
each j E J.
With this structure, we may redefine an
equilibrium
as a set of functionsqj : [0, 1 ] -~ R, j E J,
withq~ (z) = q _ ~ ( 1- z),
and a stochastic processz (t, co)
with values in
[0, 1],
such that if consumer i solves(P ‘)
withand
y2 (t, ~)
=1-z (t, ~),
i. e.type
i holds thepredicted
amount of money. Notice that the usualdynamic programming arguments imply
that in such anequilibria, ci (t, co)
=ci (z (t,
and simi-larly, h (t, ~) = l‘ (z (t, M)).
Other economic considerations can be used to further characterize the
equilibria. First,
notice that sinceU’ (0) = +00,
for any z, at least one of the twotypes
must work. Since eachtype
has an unlimitedpotential supply
of labor and has a lineardisutility
for it is natural toconjecture
that at each
state j
there exist az*
such that iftype
1works,
whereas if
z >_ z* type
2 works. The intuition here is that the richesttype
will demand most in order to sacrifice its leisure.Let us define
Vol. 8, n° 5-1991.
Since U is
strictly
concave, g =(U’) -1
is welldefined,
and hence ifz > z*
[using (2 . 5)
for i =2, (2 . 8)
and(2 . 10)],
we obtainSimilarly, if z z*,
thenAt we are free to define and we choose = o.
The
function aj
can beinterpreted
as themarginal
value of a unit ofmoney to consumer of
type
1 when the averageholdings
of histype
is zand he holds z. As such it is natural to
conjecture
thatgiven
that theutility
function forconsumption
isstrictly
concave, z t2014~a~ (z)
will bestrictly decreasing.
Since bothtypes
have the samemarginal disutility
per unit of labor the valuezj
should be determinedby
Clearly
such azj
does not need to exist. We will show however that or~~can
always
find anequilibrium
where(2 .11 )
has a solution in[0, 1].
Finally,
we notice that"money" yields
no directutility
and isorily
heldto finance future
consumption.
As of time t themarginal utility
of money, inequilibrium,
at time T isgiven by
the random variable(0)).
Since moneyyields
no directutility,
this randomvariable
should bean ff -martingale. Using
a first-orderexpansion,
weget,
Making dt - 0,
weget
Finally, then,
inequilibrium, a~ ( 1 ) = 0,
and weget
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
3. THE MAIN DIFFERENTIAL SYSTEM
Putting together
the results that have beenheuristically
derived in theprevious section,
weget
the set of non linear functional differential equa- tions which we callsystem (S) (equations (3 . 1 )
to(3 . 6)):
forall j E J,
with
and
Assuming
now that we have a solution tosystem (S),
we want toshow that the
corresponding
process of wealth z is such thatz (t, co) [resp. 1- ~ (t,
is a solution forproblem (resp. (P~)).
Thisis
provided by
thefollowing
theorem:THEOREM 1. - Let solution
of
system(S).
Letz (t, c~)
be theprocess defined
=(z) with j=
s( t, 03C9) if 03B1j a J (z)~03B1-ja-j ( 1- 2),
andZ=0 otherwise. Then the process z is a solution
of problem (P):
subject
towith
.
Since aj
anda- j
arestrictly positive and CIon [0, 1],
it is obvious thati
isessentially
bounded. We willonly
consider solutions to(P)
suchVol. 8, n° 5-1991.
that ess
sup | + t, 03C9)|
+ oo. From theprevious remark,
z satisfies thisrequirement.
Theproof
will use thefollowing
result:LEMMA 1. -
Proof of the
lemma. - We first show that for all ~0 andA~>0,
We set
Oz = z (t + Ot) - z (t).
Sincez is essentially bounded,
forsome R > o.
Using
this and a first orderexpansion,
weget
thatNow how evaluate
Using equations (3.1)
and(3.2),
We have(3.7).
Now consider the case where
(z (t))
=( 1-
z(t)).
Con-ditionally
ons (t + i) = s (t)
for every we havez (t + i) = z (t),
andhence
and
by continuity
ofthe ak and a’k,
weget
and
(3 . 7)
is established.The law of iterated
expectations
then holds for alli > o,
i. e.Q.E.D.
We now
give
theproof
of theorem 1.Proof of
theorem 1: LetAnnales clo I’Institut Henri Poincaré - Analyse non linéaire
Then it is easy to
verify
that thenwhile then
In
particular,
when y = zand y=z,
weget using
theexpression giving z
that if
CXj aj (z)
>CXj aj ( 1- z),
thenwhile if
(x~ a~ (z) ri- j a- j ( 1- z),
thenBy concavity
ofL,
we obtain for all T>O.Since as (t) (z (t))
has bounded variation weget
Since ess
sup y ~ . +00,
we have thatis
bounded on each[0, T]
withT>O. Also z is in
[0, 1] and
thus is bounded.Hence,
since(z (t))
is a bounded
martingale,
weget by applying
the results on stochasticintegral against
a squareintegrable martingale
as in[1] that
theexpectation
of the second
integral
is zero. We alsohave,
sincez (t)
and as ~t~(z (t))
areVol. 8, n° 5-1991.
bounded that lim
(z (T))
z(T) = 0,
and thusT+oo
Q.E.D.
4. EXISTENCE RESULTS
This section
provides
a necessary and sufficient condition for the exis-tence of a solution to
system (S).
Theproof
of this result isquite long,
but
entirely
constructive.Hence,
the mathematics which follows also pro- vide analgorithm
for the numerical construction of a solution.The
methodology
that is used here is first to show that a solution ofsystem (S)
is a fixedpoint
of a certain map. Themonotony
of this map, and the characterization of a sub and asupersolution
allows us to construct two sequences of functions that converge to fixedpoints,
i. e. solutions ofsystem (S).
We denote
by
E the space ofstrictly decreasing, strictly positive
continu-ous functions on
[0, 1]. Since #J=2N,
we have4.1. A reduced
system
Let v, a,
fl
be threegiven
constants with v > 0 and 0 a,p
1.DEFINITION 1. - For all
pair (u, v)
E E XE,
wedefine
the switchpoint
z*by:
Since z u
(z) - flv (z)
isstrictly decreasing,
this defines aunique point z* E [o, 1].
Given
(u, v)
in E xE,
we consider the functional differentialsystem (R) (equations (4 . 1 )
to(4 . 8) below)
in two unknown functions a and b:with
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
and
Note that
only
two of the three conditions of(4. 6)
to(4. 8)
hold whenz* = 0 or z*
=1,
while the three conditions hold when z*E ]o, 1 [.
But inthis last case,
only
two of the three conditions areindependent.
THEOREM 2. - Assume that g is
Cl, decreasing from ]0,
+oo[
intoitsef
and the map b H g
(a/b)/b
isincreasing.
For anypair (u, v)
E E xE,
thereexists a
unique
solution(a, b)
to system(R). Moreover, if
twopairs (ul, vl)
and
(u2, v2)
in E x Esatisfy
u2 and v2, andf (al, bl)
and(a2, b2)
are the solutions to system
(R) corresponding
to(ul, vl)
and(u2, v2)
respec-tively,
then one has a2 andb2 .
The
proof
of this theorem will begiven
later in section 5.Note that since the condition that is
increasing
is
equivalent
to the condition(2)
This may be
easily
seenby writting
that(set c = g (a/b),
i.e. a/b = U’ (c))
Also since U’ is
decreasing, g
isdecreasing..
Theorem 2 allows us to define a
family
of maps F(a, P, v; . , . )
fromE x E into itself
given by
where
(a, b)
is theunique
solution ofsystem (R).
Remark 1. - One can check that simultaneous
interchange of
a,03B2 Band
u, v leads to
interchange
a andb,
that is: F(a, ~i,
v; u,v) = (a, b) if
andonly if F ( (3,
oc, v; v,u) = (b, a).
(2)
The right hand side of (4.9) is the coefficient of relative risk aversion of the utilityfunction U.
Vol. 8, n° 5-1991.
4.2. The
complete system
as a fixedpoint problem
This section will show how to construct a solution to
system (S) by using
the map F defined above.For
all j E J,
we setSince
~,~, k = ~, _ ~, _ k,
we have~,~ _ ~ _ ~.
Since
~,~ _ ~ _ ~,
remark 1implies
thatHence,
for anyfamily of
functions inE,
we can define anotherfamily of
functions in Eby:
The map H is
by
theorem 2increasing,
i. e. for any u,u
inEJ
such thatV j
EJ, u
>-u
we haveV j
EJ,
H(u)
>_ H(u) .
Let G :
EJ EJ
begiven by
Note that since are
positive,
the map G is alsoincreasing. Hence,
the map H ° G is
increasing
fromE’
into itself.One has the
following
result:THEOREM 3. - A
family of functions
is a solutionof system (S) if
andonly if
its is afixed point for
the mapProof. - Suppose a E EJ
is a fixedpoint
of H ~ G.Fix j E J,
and setu = ~ v = ~ ~, _ ~, k ak. By equation (4. 6),
the switchpoint zj
of thekeJ J
’
keJ J
’
pair (u, v)
is also the switchpoint
of thepair a _ ~). Hence, equations
(4 . 1 )
to(4. 5) imply
thatequations (3 . 1 )
to(3 . 4)
are satisfied. Also(4. 6) together
with1 ] implies
that i. e.(3 . 5).
More-over, if the
equality holds,
then and(4. 7) implies equation (3. 6).
Hence,
a fixedpoint
of H°G is a solution ofsystem (S).
Conversely,
let a be a solution ofsystem (S). Then, (4.1) implies
thatand that the switch
point z*
ofa _ ~)
is well defined. Ifz* E ]o, 1 [,
then we have _ _and
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
By continuity, (3 . 2) implies
thatu (z*) _ (~,~ + ~,) a~ (z*). Exchanging j by - j gives v ( 1- z*) _ (~,~ + ~,) a _ ~ ( 1- z*).
Ifz* =1,
then(3 . 6) gives
u ( 1 ) _ (~,~ + ~.) a J ( 1 ). Exchanging j by - j gives
from(3 . 2)
that for allZE]O, 1[, v (z) (~,~ + ~,) a _; (z). Hence,
since we have(x~
u(1) ~ cx- j v (0).
Ifzj
=0,
thenexchanging j in - j gives oc~
u(0) _ a _ ~ v ( 1 ).
Hence, zj
is also the switchpoint
of thepair (u, v).
From(3 . 1 )
to(3 . 4),
we have that
(4.1)
to(4.5)
are satisfied. From the abovearguments showing
thatzj
is the switchpoint
of(u, v),
weget equations (4.6)
to(4. 8).
Q.E.D.
Showing
thatsystem (S)
has a solution is now reduced to demonstrate the existence of fixedpoint
for H ° G. As this map isincreasing,
the mainpart
of theproof consists
inshowing
the existence of asubsolution a
anda
supersolution
a. This will be done in section 6. Because of the lack ofcompactness
ofEJ,
we need tocomplete
theproof
with a convergence resultfor an
definedby
andaO=r¿or
which is in section 7.4.3. The existence result
(main theorem)
DEFINITION 2
(Undecomposability
of themodel). -
For iand j in J,
wesay that the
pairs (i,
-i )
and( j, - j)
are connectedif
there exists a sequenceio, ..., im in
J such that andim = ~ j (i.
e.im = - j)
such that..., m.
Recall that
~, _ m, _ p = ~,m, p
for allHence,
thepreceding
definition of a
path just depend
on the sets(i,
-i)
and( j, - j) (and
noton the ordered
pairs)
and this connection relation is anequivalence
relation.
We will suppose that each
pair (i,
-i)
is connected to anypair ( j, - j).
If this is not the case, one should break J in its connected
components
andstudy
themindependently.
DEFINITION 3. - We call
w-subset,
orworking
statessubset,
any set K c J such thatHence the
cardinality
of K isequal
to N for any w-subset.To each
w-subset,
we associated the N x N square matrix0=0(K)
withpositive
coefficientsi, j E K
xK)
definedby:
Using
thehypothesis
that~,i, J = ~, _ ~, _ ~
and for alli, j
and k inJ,
one verifies that
7~m, n > 0 implies 8~, ~ ~ 0
where(i, j)
is theunique pair
suchVol. 8, n° 5-1991.
that I =
, Fromthis,
one deduces that theconnectivity hypothesis
madepreviously implies
the classical notion ofundecomposability
for the matrix8,
i. e. for any(i, j)
E K xK,
there existsa
path io, ... , im
such thatio = i,
and9ik -1 ~
ik # 0 for all k=1,
..., m.We now define p
(K)
thelargest eingenvalue
of 8(K),
and a numberp > 0 which
plays
a crucial role for oursystem:
As the set of w-subset is
finite,
there exists at least one w-subsetKo
suchthat p = p
(Ko).
We now state the main theorem:
THEOREM 4. -
If
the relative risk aversion is less than orequals
to one,that is
then a necessary and
sufficient
conditionfor
the existenceof
at least onesolution to the system
(S)
is that psatisfies
p > 1.Let us recall that condition
(4 .11 )
isequivalent
to thehypothesis
onthe function
g = U’ -
1 made in theorem2, namely
g isdecreasing
andb H g
(a/b)/b
isincreasing.
One can
easily give
sufficient conditions whichimply
p > 1. Forinstance,
assume that there exist k E J such that
Consider now a w-subset K such that - k C K. From the definition of
8i,
~, one getsBut,
as~,k, - k = ~ - k~ k
and~,k
=~, _ k,
thisgives
us6 _ k, _ ~
> 1.Considering
the vector with
Xj=O
andx _ k =1,
it is easy tocheck,
since 8 haspositive coefficients,
that forall j
inK,
we haveApplying
the Perron-Frobenius theorem as stated in Nikaido[2],
weget
p(K)
> 1.Hence,
we have theCOROLLARY l. -
If
relative risk aversion is less than orequals
to one,and
if
condition(4 . 12) holds,
then the system(S)
has at least one -solution.In the case N =
1 ,
8(K)
reduces to a scalar for every K. We set a = ocl,[i
= a _1 and
03BB=03BB1, -1=03BB-1,
1, and weget
the:COROLLARY 2. -
If
N =1 and the relative risk aversion is less than orequals
to one, then a necessary andsufficient
conditionfor
the existenceof
at least one solution to system
(S)
is thatinf ~ a/(3,
Annales de l’Institut Henri Poincaré - Analyse non linéaire
4.4.
Decomposition
of theproof
of the main theoremTheorem 4 follows from
following propositions
1 to 4 bellow.Propositions
2 and 3 consist inconstructing
super and sub solutions to the fixedpoint problem
of the map H ° G.Proposition
4 consists inshowing
thatstarting
either from the super or subsolution,
the sequence of functions defined in section 4.2 converges to a fixedpoint
of H ° G.PROPOSITION 1. - When
p 1,
thesystem (S)
has no solution.Proof. -
Theproof
isby
contradiction. We assume thatp ~
1 and thatthere exist a solution to
system (S).
Let K be the w-subset definedby j E K
if1/2
andby choosing
any of the twointegers j and - j
ifz* =1 /2,
wherezj
denotes the switchpoint
associated to thepair
a-~).
Such a w-subset exists and is
unique
since forall j, z* =1- z*_ J.
For allj E K,
we havea~ (z) _- 0
andcp~ (z) > 0 if z 1 /2. Hence, equation (3 . 2)
andcontinuity
ofthe ak imply
For
all j ~ K,
we havez* =1- z*_ ~ and - j E
K.Hence, 1 /2 implies
From these two
equations,
weget
Hence,
with6 = o (K)
andAk=ak(1/2)
for allkEK,
weget
Let us first suppose that
p 1.
From one deduces that enis a contraction for n
sufficiently large (see
Nikaido[2]).
As e haspositive coefficients, A ~
e Aimplies by
induction thatA ~
en A.hence,
A =0,
which contradictsak ( 1 /2) > o.
We now turn to the case where p == 1. If
A ~
eA,
then one can prove that for some E > 0 and mEN.Also, (8m/( 1 + ~))n
is acontraction for n
sufficiently large.
Hence A = 0. If A = eA,
thenand
This last
equality implies
thatz* =1 /2 for j~
K. HenceVol. 8, n° 5-1991.
This establishes that B=MB where and
M=(mi,j.iEJ,jEJ)
withmi, j = ~i, jl(~i + ~).
From andL m~, j = ~,i/(~,i + ~.) l,
we deduce that M is a contraction.Hence,
B = 0jeJ J
which contradicts
a j ( 1 /2) > o.
PROPOSITION 2. - For any
y>O,
there exist afunction A~C1 ([0, 1])
such that
and
If
the constant ysatisfies y >_ sup { cxjlJ
EcxjlJ
EJ},
thena =
EE’
where
a~
= Afor all j
E Jsatisfies a >_
H(G (a)),
i. e.a
is asupersolution.
Proof. -
Theproof
is in section 6.PROPOSITION 3. -
Suppose
p > 1. Let K be a w-subset such that p = p(K).
Let B =
K)
be apositive eigenvector of
the matrix 8 = 8(K)
associatedto the
eigenvalue
p.For j E ( - K), define B~ by
define
B’’by
For ~ and ~sufficiently small,
is asubsolution
[i.
e. one has a EE’
and H(G (a))].
Proof’. -
Theproof stays
in section 6.PROPOSITION 4. -
If
there exists a anda
inE’
such thatthen the map HO G has at least one
fixed point.
Moreprecisely,
thesequences
(an)
and(a") defined by
are
respectively increasing
anddecreasing
and converge inE’
torespectively a*
which arefixed points of H
G.The
proof
ofproposition
4 is in section 7. Fromproposition
3 we maychoose 8 small
enough
toobtain a~a.
Hence thisproposition gives
aconstructive
algorithm
to find two solutionsa*
anda*
of ourequations.
In all simulations we did find
a*
=a* .
But atthe
time there is no theoretical evidence that thisequality always
holds.Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
5. PROOF OF THE RESULTS CONCERNING THE REDUCED SYSTEM
The
proof
of theorem 2 will be first established in aparticular
case,which we call balanced case, then in the
general
caseby
anapproximation procedure.
Weset f (a, b)=g(ajb)jb.
Theassumptions
made on gimply
that a H
f (a, b)
isdecreasing
and that b Hf (a, b)
isincreasing.
5.1. The balanced case
DEFINITION 4. -
(u, v) E E X E
is said to be balanceda u
( 1 )
v(0),
i. e. thecorresponding
switchpoint of definition
1 is in]0,
1[.
PROPOSITION 5
(proof
of theorem 2 in the balancedcase). -
Let a,[i
and v be
given
constants such that v > 0 and 0 oc,(3
1. Letf be
aC1 function from ]0,
+~[2
into]0,
+oo [.
Let(u, v)
E E + E and let z* E]0, 1[
be the associated switch
point.
Then there exists aunique pair (a, b)
solutionto
(5. 1 )
to(5. 7):
with
and
Moreover,
a and bsatisfy
Proof of proposition
5. - Set w(z)
= v( 1- z)
and c(z)
= b( 1- z).
From(5 . 1 )
to(5 . 7)
we obtainwith
Vol. 8, n° 5-1991.
and
This new
system
isequivalent
to a set of twoCauchy problems.
The firstone is a forward
Cauchy problem consisting
in two non linear O.D.E. onThe second one is a backward
Cauchy problem consisting
in two nonlinear O.D.E. on
[0, z*]:
Note that
replacing (P,
z, a, c, u,w) by (a, 1- z,
c, a, w,u)
in(5 . 9) gives (5.10).
This isagain
thesymmetry
of ourproblem.
Hence it suffices toprove existence and
unicity
for theCauchy problem (5.9).
As the function
f
isC1 on
the open set Q =]0,
+oo [ X ]0,
+oo [,
it is astandard result on
Cauchy problems
that(5.9)
has aunique
solution(a, c)
defined on a maximal interval
I +
which is eitherI + _ [z*, 1]
or1+ = [z*, z +] ]
for some
z + E ]z*, 1].
In the first case, we are done. In the second case, it is aproperty
of maximal solutions that(a (z),
c(z))
-~ aS~ when z -~z + ,
which means that for any
compact
C inQ,
there exist ~>0 such thatz + - E z z + implies (a (z),
c(z)) ~
C . This case will be eliminatedby
acorollary
to thelemma
below:LEMMA 2. - Let zl and z2 be two
points
inI+.
Let y and cp be twofunctions defined
on intervalI1,2
=z2[.
Assume that cp is continuous andy is C1,
and thatThen,
allzei. 2
one hasall z~I1,2 and z2z1,
one hasIn any
of
these two cases, one has that y isstrictly decreasing
on]zl, z2[.
Annales de l’Institut Henri Poincaré - Analyse non linéaire
COROLLARY 3. - A solution
(a, c) of (5 . 9) defined
on[z*, z + [
cannotsatisfy (a (z),
c(z))
--~ aSZ when z --~z + . Hence, I + _ [z*, 1 ] .
Proof. -
It is clearusing
the lemma that for all z,(a (z),
c(z))
remains inthe set C =
[u (z+)/v,
u(z*)/v]
X[w (z*)/v,
w(z+)/v]
which is acompact
set in Q.Q.E.D.
COROLLARY 4. - The
unique
solutionof equations (5. 2)
to(5. 7) satisfies (5 . 1 ) and (5 . 8).
Proof. -
It suffices to use theinequalities provided by
the lemma.Q.E.D.
Proof of
the lemma. - We assume z2 > zl 1(the proof
in the other caseis
exactly
thesame).
Let us first suppose that u is
C~.
Defineby y (z 1 ) = 0
and~y’ (z) _ - v/cp (z),
andby x (z) _ ( y (z) - u (z)/v) e’’ ~Z~. Using
thedifferential
equation
satisfiedby
y, weget x (zl) = 0
andAs
u’ o,
thisgives
x’ > 0 whichimplies x (z) > x (zl) = 0
for Wealso have
Hence y
isstrictly decreasing
and forIf u is not
C~
1 butonly
continuous andstrictly decreasing,
we can dothe same
computation using
the weak derivative onI 1, 2,
and weget (5 . 11 )
in the weak sense. Since u is
strictly decreasing,
weget Supp
u’ =I1,2
andbecause of
(5 . 11 ),
we have for thepositive
measure x thatThis
implies
Because of(5.12),
we havey’ 0
onz2[.
Q.E.D.
This achieves the
proof
ofproposition
5.We now
give
amonotony
result in the balanced case.PROPOSITION 6. - Let
(ul, VI)
and(u2, V2) be
two balancedpairs
suchthat and VI
>_ v2.
Let(a1’ b1)
and(a2, b2) be the unique
solutionsof (5 . 1) to (5 . 7)
withrespectively (u, v) = (ul, vl)
and(u, v) = (u2, v2).
Thena1
>_ a2
andb1 >_ b2.
Proof of the proposition. -
It is sufficient to prove the result in the twospecial
cases(ul
= u2, VI>_ v2)
and(ul >__ u2,
VI= v2).
Let n > 0 be aninteger
Vol. 8, n° 5-1991.
and
(uk, Vk)k E
o,..., 2"the
finite sequence of functionsAs
(a, P,
ui ,VI)
and(a, P,
u2,v2)
arebalanced,
there exists E > 0 such thatHence,
for allk E ~ 0, ...,~-1 },
which in turn leads to
1 (o) > ~ v2k + 1 ( 1 )
ifAlso
Moreover,
Hence
(a, P, uk, vk)
is balanced for all ...,2 n ~
if n isbig enough.
It suffices to compare the solution to
(R)
for et(uk + 1, vk + 1 )
withk=o, ..., 2n- l.
Annales de l’Institut Henri Poincare - Analyse non linéaire
Also the
symmetry
of thesystem (5.1)
to(5 . 7) implies
that each of thespecial
case reduces to the other one.So,
in theproof,
we will suppose that u2 and v = v2 = v.We now introduce the
auxiliary
functionsc2(z)=b2(I-z)
and With thesenotations,
thesystem becomes,
withi =1,2.
with
and
Recall that
z*
is the switchpoint
related to the balancedpair (ui, v),
i. e.OC Ui W
(Z*).
The
following
lemma will be very useful:LEMMA 3. -
If
u2 and vl = v2, thenProof. - Suppose
Take From the definition of the switchpoint,
weget
which contradicts Hence(5 .13)
isproved.
As w is
increasing,
we have w(zi ) >_
w(z2).
Hence weget
which
gives (5.14).
As al
and a2
aredecreasing, (5.13) implies
Also
Hence
(5.15).
From
(5 . 8)
it follows that for all v ci(z) >__
w(z),
and for allz >__
z2,v c2
(z) ~
w(z). Hence,
weget (5.16)
and(5.17).
Q.E.D.
We have to prove that
inequalities
and hold on[0, 1].
Vol. 8, n° 5-1991.