P ETER H. S CHMITT
The model-completion of Stone algebras
Annales scientifiques de l’Université de Clermont-Ferrand 2, tome 60, série Mathéma- tiques, n
o13 (1976), p. 135-155
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THE MODEL-COMPLETION OF STONE ALGEBRAS
Peter H. SCHMITT
Simon Fraser
University,
CanadaINTRODUCTION
The notion of
model-completion
was introduced and studiedby
A. Robinson in[ 5 ] ,
It leads to a
general theory
of«algebraically
closed» structures. Themodel-completion
of thetheory
of fields is thetheory
ofalgebraically
closed fields and thetheory
of real closed fieldsis the
model-completion
of thetheory
of ordered fields. Themodel-completion
of atheory
need not exist but if it does it is
unique.
It is known that themodel-completion
of thetheory
of Boolean
algebras
is thetheory
of atomfree Booleanalgebras.
Themodel-completion
of thetheory
of distributive lattices withoutendpoints
is thetheory
ofrelatively-complemented
distributive dense lattices without
endpoints.
These results arecommonly
known. In thispaper the
model-completion
of thetheory
of Stonealgebras
is determined. Furthermore thistheory
isproved
to becomplete,
substructurecomplete
andR - categorical.
This paper is
part
of the author’s Doctoral Dissertation submitted toUniversity
ofHeidelberg,
Fed.Rep.
ofGermany
inspring
1975. This work waspartially supported by
a
GraFoeG-grant.
I would like to offer my sincere thanks to G.H. Mueller and U.
Felgner
for muchencouragement
and assistance. I also wish toacknowledge helpful
remarksby
V.
Weisspfenning.
§
1. MODEL THEORETICAL PRELIMINARIESWe assume
familiarity
with the basicconcepts
of modeltheory.
We usecapital
Gothicletters
91,’,
... to range overmodels;
thecorresponding capital
Latin lettersA,
B ...always
denote thecorresponding
universe. If 9y is a substructure of T anda e Bthen 9Y
(a)
denotes the substructure of Bgenerated by
A u{a}. XY is the set
of all functions from X into Y and card A stands for the
cardinality
of A.1.1. DEFINITION : A structure IT is
called N0-homogeneous
if for any twofinitely generated
substructures 13 l’
B 2
of c,J anyisomorphism
ffrom ft
1onto B 2
and any a e Athere is b f A such that f can be extended to an
isomorphism
f from B1(a) onto B 2(b).
We shall
employ
thefollowing
two well-known theorems on No-homogeneous
structures.
1.2. THEOREM :
Any
twocountable N o-homogeneous
structureshaving upto isomorphism
the same
finitely generated
substructures areisomorphic.
1.3. THEOREM : If 9T is a countable N
o-homogeneous
structure then everyisomorphism
between two
finitely generated
substructures of U can be extended to anautomorphism
of 9TFor
proofs
of these theorems see[ 6 ]
lemma 20.1 and 20.4.1.4. DEFINITION : A
theory
T is called substructurecomplete
if for any two models 9’ i,91 2
of T and any common
substructure "
holds( ( il 2,b)b E
B’1.5. DEFINITION : A
theory
T* is themodel-completion
of atheory
T if(i) T*
(ii)
every model of T*can be embedded into a model of T*(iii)
for any two models iti,
tJ 2
ofT *
and any commonsubstructure f,
which isa model of T holds
These two definitions are related to the
concept
ofRo-homogeneity by
thefollowing
theorems.1.6. THEOREM : Let T be a
complete theory having only N0-homogeneous
models then T issubstructure
complete.
PROOF : In
showing
that T satisfies therequirements
of definition 1.4. we mayw.l.o.g.
assumethat
tT l’ 91 2
are countable models of T with # as afinitely generated
common substructure.Since T is
complete
there are a countablemodel IS
of T andelementary embeddings
gi from91 i
into ’C-z Since 6 isN0-homogeneous by assumption
themapping g2gi1
restricted to 2 1g1(B)
canby theorem
1.3. be extended to anautomorphism of S.
ThusSince gi is
elementary
thisimplies
We note the
following
converse of theorem 1.6.1.7. THEOREM : If T is N
-categorical
and substructurecomplete
then T hasonly
No-homogeneous
models. 0PROOF : Let 9T be a model of T. Since T is
N0-categorical 21
islocally
finite. Let IF..., an-I} , ~ 2 = (bO’ ..., bn-l}
be substructuresof ’41
f anisomorphism
between 1
and " 2
such thatf(ai)
=bi.
Substructurecompleteness yields
Let
an
be anarbitrary
element of A. Since T is No-categorical
there is aformula L (vo,
...,Vn) generating
thetype
realizedby
ao, ..., an > in VI . Nowusing (1)
we findbn e
A,satisfying 11 p
w[ bo,
...,bn I
. ThusaO’
...,an:>
and ...,bn>
realizethe same
type
in 9J whichimplies
that f can be extended to anisomorphism
from2(bn)-
§
2. ALGEBRAIC PRELIMINARIESWe
briefly
review thetheory
of Stonealgebras
as far as needed in thesequel.
Athorough
treatment may be found in
[
2] .
2.1. DEFINITION : A structure ;I =
A,
n , u , * ,0, 1
> is called apseudo complemented
distri-butive lattice if
A,
n , u ,0, 1
> is a distributive lattice with least andgreatest
element’
and the
one-place operation *
satisfies thefollowing
axiomsA
pseudo complemented
distributive lattice is a Stonea ebra
if in addition holds(SL3)
a * u a** = 1We denote the
theory
of Stonealgebras by
STA.There are two
interesting
substructures of a Stonealgebra
91 .The skeleto n of 9T =
Sk( 1,1 ) = ( a e A ~ a~~ - a)=(a*)a
eA ~ .
Sk( ~1 ) - Sk(
M),
n , u , * ,0,
1 > is a Booleanalgebra.
The set of dense
I
a* =0).
D( ?I ) = D(9! ),
n , u , 1 > is a distributive lattice withgreatest
element. Bothsubstructures are linked
together by
the structure map which is ahomomorphism
fromSk( 9J )
into the lattice of filters overD ( 9f) preserving
0 and 1 definedby all (a) = [x
EU is
upto isomorphism uniquely
determinedby
thetripel Sk( II), D( ~t ),
Let * be an
arbitrary
Booleanalgebra, D
a distributive lattice with 1 and a a homo-morphism from 18
intoF(!t ), the
lattice of filtersover X , preserving
0 and 1. For anyb E B we have o
(b)
uo(b*) =
D. Thus there are for any x E Duniquely
determinedelements xl,
x2
such thatx I
e o(b),
x2 E a(b* )
x - xl n
x2
We use the notation p
b(x),
x2 =P b * (x).
On the set of
pairs
A =(~x,b> ! I
b EB, x
eQ (b} ~
we define apartial
orderby
A,
> induces a Stonealgebra U.
We furthermore haveI - --
In the
following
weidentify
any Stonealgebra 91
with thealgebra given by Sk( ~), D( U ),
a> . We shalltacitly
use thefollowing
rules ofcomputation.
2.2. LEMMA :
We conclude with two lemmas
characterizing isomorphisms
andsubalgebras
in terms of thecorresponding tripels.
Theproofs
may be found in[ 1 ].
2.3. LEMMA :
Suppose
are Stonealgebras given by
thetripels *
1, I) i ,(i)
Let F be anisomorphism
fromU 1 onto 2
then there areisomorphisms
(ii)
IfD1 ->D2, f 2 ’ --+!2
areisomorphisms satisfying (B) then ( a )
defines anisomorphism from U 1
onto U 2.(iii)
Condition(o )
isequivalent
to2.4. LEMMA : Notation as in lemma 2.3.
(ii)
If( a)
to( y)
hold then V1 c; 91 2
(iii)
Condition( 7 )
isequivalent
toAt some
point in §
3 we shall make use of thefollowing representation
theorem2.5. THEOREM :
Every
Stonealgebra
is a subdirectproduct
of the three-element Stonealgebra (where A3 = { 0, e ,1 }
such that 0 e 1 and 0 ~ -1 , e *
= 1 ~ =0).
PROOF : see
[ 3 ].
§
3.NO-HOMOGENEOUS
STONE ALGEBRASBefore we state and prove the main theorem we
dispose
of some trivialexeptions.
A Stonealgebra 91
is called trivial if cardD ( 9’)
= 1 or card 4.The
proofs
of thefollowing
statements are easy or variations ofarguments
used in theproof
of the maintheorem,
so we omit them.3.1. THEOREM : Let U be a Stone
algebra.
(i)
If cardD( tl
= 1 thenSk( 9J) ~ ’t
and theproblem
is reduced to Booleanalgebras.
A Boolean
algebra
isN0-homogeneous
iff it has at most 4 elements or is atomfree.(ii)
If cardSk( 9T):;:
2 thenU is
N0-homogeneous
iffD(U) is N0-homogeneous
iff
D( 91 )
isrelatively complemented,
without antiatomsand without least element
(iii)
If cardS( 9T
= 4 thenen is N
o-homogeneous
iffD(
= 1.3.2. MAIN THEOREM : Let 91 be a nontrivial Stone
algebra.
81 is 4
o-homogeneous
iff thefollowing
conditions hold(PI) Sk( 19 )
is atomfree(PII)
isrelatively complemented
distributive lattice without antiatoms and without least element(PIII)
For all b eSk( 91 ), b ¡. 0, a (b)
has no least elementWe first prove
necessity
of the conditions PI to PIV.3.3. LEMMA :
Suppose U
is an B’o-homogeneous
Stonealgebra. bl, b2
E), bl
nb2 = 0 and b1, b2 =/ 0,1.
Then there is an
automorphism
g ofD( 9! )
such thatPROOF : Consider the
subalgebra R I c 9T generated by
«l,by’> , l,b 1*
> ,i,b 2 > , 1,b*2
> It iseasily
checked that there is an(
-embedding
F fromtT 1
into 91taking l,b2 >
to1,b1>. By N 0-homogencity
Fcan be extended to an
automorphism
F =g,f >
of 9T . Now lemma 2.3.yields
a
(bl)
= a(f(b2)) _ ( g(x) I
x e a(b2)}
and g is anautomorphism
of).
3.4. COROLLARY : If qy is a nontrivial
N0-homogeneous
Stonealgebra
thena 91
is anembedding.
PROOF : It suffices to show that for b
b/
0implies a (b) ¡.
Assumeb ~
0 and o(b) = {1~ .
Thisimplies
o(b ~ )
=).
By
lemma 3.3. a(b)
and a(b *)
have the samecardinality contradicting
theassumption card D(9’ )
> 1.3.5. COROLLARY : If 91 is a nontrivial
eo-homogeneous
Stonealgebra
then(PIV)
holds.PROOF : Let x, y be elements of
D(91) satisfying
x uy = 1.
Since cardSk( 91
> 4 we finda e 0 a 1.
By corollary
3.4. thisimplies : { 1 ~ a(a) D( ~. )
This enables us to choose u f
a(a),
v eo(a ~ )
such thatu = 1 iff x = 1 v = 1 iff y = 1
In any case u u
ve(7(a)na(a*)= (l) yields
u u v = 1.Denote
by Bg
the sublattice of 5lgenerated by [ x,y ~.
Denoteby 1)
1 the sublattice of ~generated by (u,v) . Obviously
there is anisomorphism f 1
fromZo onto D1
such thatDefine the
subalgebras 91 j of
9’for j - 0,1 by
The
mapping
F =f2
> , wheref2
is theidentity
mapon [ 0,1)
= is anisomorphism from U0
onto 91 1.N0-homogeneity
of 81provides
us with anautomorphism
F =f l, f2
> of Vextending
F. Let c be thepre-image
of a underf 2,
i.e.f 2(c)
= a.implies
x E
a (c)
andy e a (c*) proving PIV.
’
Conditions PI to PIII are derived in
quite
the same way so we omit the details.It is
easily
seen that the class of all Stonealgebras satisfying
PI to PIV is afinitely
axiometized
elementary class,
we denote itstheory by
STA~. Weproceed
to show that every model of STA* is No-homogeneous.
We start with thefollowing simple though
very useful lemma.3.6. LEMMA : Let ?I be an
arbitrary
Stonealgebra
x,y eD(21),
x y 1 and a ESk(91
Assume that the relative
complement
of y in[ x,l ]
exists and denote itby y’.
Assume further that the relativecomplement
of Pa(y)
in[ p a(x),
1]
exists and denote it likewiseby ( p a(y))’.
Then holdspa(Y’) = (p a(y»’ U Pa()°
PROOF :
y’
n y = x andy’
u y = 1implies p a(y’)
nP a(y)
=P a(x)
andPa(y)
=1,
i.e.
P a(y’)
is the relativecomplement
of Pa(y)
withrespect
to[ p a(x),1 ]
. It iseasily
checked that also
( p a(y))’
u Pa(x)
is a relativecomplement
ofp a(y)
withrespect
to[ p a(x),1 ]
.Uniqueness
of relativecomplements
in distributive latticesyields
the claim.We still need one
preparatory
lemma.3.7. LEMMA : Let 9T be a model of STA*. Then holds
(PV) 0 If
is anembedding
then there is c E
Sk( ~~ )
such that 0 c bPROOF :
(PV)
followseasily
from(PIII).
Iri
proving (PVI)
wedistinguish
thefollowing
three casescase I : x = y = 1
Use
(PI)
to find c e such that 0 c bcase 2 :
x X 1, y X
1 .Using (PIV)
we obtainCQ
e such that x E a(co),
y e o(c* ).
0Defining
c = c
0
n b we
obviously get
x eo(c) and y E a (c 0 c-7 0 (c*).
c = 0 wouldimply
o 0
x e
o(0)=i.l) ;
c = b wouldimply
b* >c 0 *
thus y Eo (b n b*) = { 1 } .
Both arecontradictory
to ourassumptions.
So 0 c b holds.case 3 :
x X 1,
y = 1By (PIII)
there is z Eo(b),
z x.By (PII)
there is7
ED(91 ) satisfying
z = x ny
and 1 = x u
y.
Note thaty X
1and y
ea(b). Using
case 2 we obtain c e0cb,xe
a(c), y
e a(c*).
Since y = lea
(c*) trivially
holds we haveproved (PVI).
,To prove
(PVII)
let ..., zn-I e a(b)
begiven satisfying
theassumptions. By
PII it ispossible
to choose ui eD(’"y )
such that for all i n : zi ui 1.By
wi we denote the relativecomplement
of ui withrespect
to[ zi
,1]
which existsby
PII :Using distributivity
we obtain thefollowing equation
Observing
thatwe conclude
Since a
(b)
is a filter we still have x n xo , y nyo
E a(b).
By (PVI)
we obtain c eSk(91) satisfying
and
This
implies
again exploiting
the filterproperty
of a(c),
resp. a(c*).
This
yields : zi 0 Q(c), zi e Q (c~)
for all i n.Since from zi e
a (c)
would followwi
e a(c)
anda(c)
nQ (c’~) _ ~ 1 ~ i.e. wi
= 1contradicting
the choice of ui. Alsozi
ea (x*)
would entail in the same way zi = 1again contrary
toassumption.
This
completes
theproof
of lemma 3.7.For the rest of this
paragraph
9T =18, :t,
a > will denote a model of ST A *. It is ourgoal
to show that 91 isNo-homogeneous.
To this end we consider two finitesubalgebras
ig D
i, Q i
>,
i =1,2
and anisomorphism
F :fl’ f2 > from U1 onto
9J ~.
Let x,a > be anarbitrary
element of A.ii 1;: ë 1 ’ % 1 , o ~ >
denotesthe
subalgebra
of 91generated byAu (x,a>).
Problem : Extend F to an
embedding
F =~’ f 1, f 2
>from i 1
into 91 .We shall
proceed
in thefollowing steps
,Step
1 Form the closure of Z undercomplements
Step 4
x,a >arbitrary
If
steps
2 and 3 will beaccomplished, step
4 is trivial becausex,~ x,l>n I,a > ,
STEP 1
Let
doi
denote the least elementof Z
i. For x eDig doi -’
x ~1,
x’ denotes therelative
complement
of x withrespect
todefines a
sublattice,
of % closed under ’ Iand
containing D i .
Set i71(a)=
a(a)
nD1
for a eB~. We
claim that~ 1 ~ ° 1 ~
is asubalgebra
of V -According
to lemma 2.4. we have tofor all y E Djandaffbe B,
Tobegin with
take z eDI.Bylemma3.6.we
have
Pa(z’) = ( pa(z))’ u
Sinceby assumption p a(z),
p~1 and D i is
closed under ’ we obtain p
a(z’)
cD i .
For
arbitrary
y=U (
xi nz’i) I
in)
eD 1
we haveNow we want to extend F=
fi , f 2
> to anembedding
F from91 1
into 91 .It is routine to check that there is an
embedding f 1
fromD 1 extending f 1
andsatisfying
In order to show that F =
fi , f > is an embedding from
I into 4!1 we needby
lemma 2.3.only
to know that for all a e Y e p = holds. This iseasily
checked
using
lemma 2.2. and 3.6.STEP 2
I
We
adopt
thefollowing
notationD i = ( do, ...,
and agree thatB1 = {b0,...,bk-l}
For « e
k2
we use the abbreviation b where Ob = b and 1 b = b*Similarly
for 1" êr2
where Od = d and Id = d’ and d’ is the relative
complement
of d in .Furthermore
p
1r stands for pbII. 1r"It is checked
by straightforward computation
that thefollowing
holdsx is an
arbitrary
element of D. We may restrict to the case x E a(b )
for some 7r Ek2’
*If we have solved this restricted
problem
wemight
take up thegeneral
caseby extending D1
successively to 5l 1
such that( p 7r (x) ) I ~r E k2 ~ ~ D l,
sincep~ (x)
e).
Noticing
that x11t
ek2 )holds
we will have finished.So we assume that x e a
(b 1T o )
holds for some ek2. Let D 1 be
the sublattice of D0 "
generated by D1
u(x) .
Since for all b eBl
eitherP b (x)
= x orp b(x)
= 1 holdsl,
substructure of 2l(of
courseQ 1(a)
= a(a)
nD 1).
We shall
distinguish
thefollowing
three casesCase 2.I. - Case 2.2.
Case 2.3. neither of the above
After case 2.1. and 2.2 have been
accomplished
case 2.3. will followtrivially :
we first extendto contain x n
do using
case 2.2. Now xn d 0
x and case 2.1,,applies.
CASE 2.1. :
Using step
1 we may suppose without loss pfgenerality that 2) 1
is closedunder
complements.
Theembedding f 1
preservescomplements
in the sense that X’ ismapped
onthe
relative
complement
of withrespect
toI
which we alsodenote by
We shall make use of the
following
3.9. CRITERION : There exists an
embedding
F : 91extending
F iff for every T eT2
there is
yT E D
such that thefollowing
four conditions aresatisfied :
PROOF OF 3.9. :
Necessity
is clearby taking yT = d ).
To prove
suffiency
set y *n{ YT I T
er2}.
Now 3.9.0 to 3.9.2imply (using 3.Q)
By
a well-known theorem onextending isomorphisms between Boolean algebras (see e,g. ~ [
71
p.
37) applied to Z I
and the interval[ do, 11 ]
there is anembedding f 1 from D1 intq %’
extending f i
such that71 (X)
= y. It remains to showf2 >
is anembedding from 2t 1
into 91 .First we note that for all b e
B~ and x c D i
holdsFor either holds. In the first case
>
In the second case
Using
3.9.3. thisyields (YT I T
c~2)
This
completes
theproof
of 3.10.Every
y eD 1
can berepresented
in the formI I . -
This
completes
theproof
of 3.9.Now let T e
r2
begiven.
We shall find yzsatisfying
3.9.0 to 3.9.3.In the trivial cases
d~
u x = 1 andd-r
u x’ = 1 we choose y = =respectively.
So we arrive at the non-trivial case :
d d u
x 1.We claim that this
implies
This can be seen as follows. x e
a(b7T ) yields
for all 7T ek2,
o
If
contrary
to 3.11(d
1 ux) =
1 would also be true, we obtainedFrom 3.11 and
p 7r (d ) pII
o(d1:
ux)
now follows :Using
theassumption
on 9f 2 >
we infer :By (PII)
and the fact that a a filter on ~ we may choose y T E Q(f 2(b’IT o))
such that :This
implies :
and satisfies 3.9.0 to 3.9.3.
This
completes
case 2.1.CASE 2.2. :
In this case we have
D 1 = D I u { x ~.
Since a(f 2(b ~. 0 ))
containsby (PIII)
no leastelement,
we may choose y e
0 ))
such that yThe
mapping f 1
definedby
is
certainly
anembedding from i) 1
into X -Furthermore holds I
This shows that
f l, f 2 > : if 1
20132013~ ~f is anembedding.
This
completes step
2.STEP 3 :
Let ië 1
be thesubalgebra
of Tgenerated by Bl
u( a).
bethe
of Z
generated by D 1
u{ Pa(x) I
x ED )
u pa*(x) I
x eD~).
Finally
= a(a)
nD i .
It is not hard to see thatR11 = ~ ~ ~, Z 1 , 6 ~ >
is a
subalgebra
of !1.Denote
by d 0
the least element of Z 1.Obviously d 0
is alsothe
leastelement
of3? i,
,For x ~
1, x’
denotes the relativecomplement
of x withrespect
tq1 ] , Step
1 allows us to assumew.l.o.g.
that 2 1 is closed under ’.We
begin
with three easy observations.The
right
hand side of 3.12 containsD 1 U i P a(x) (x)! I
x e and is closed under n and u . This is clear for n . For u we obtain3.13. : For all x e
Dl: [pa(x)]’ _
x’ nThis is checked
by
directcomputation.
3.14. :
D 1
is closed undercomplements.
Using
3.12 and 3.13 we obtain :By assumption
the last term is an element ofD I*
3.15. CRITERION : The
embedding
can be extended to anembedding
F :
ëiT 1
iff there is c e Bsatisfying
PROOF OF 3.15 : To prove
necessity
take c =f2(a).
On the other hand conditions 3.15.1/ 2ensure the existence of an
embedding f 2 from B1
into ?extending f 2
such thatf 2(a)
= c(see [7 ]
p.37).
We assert that
f 1
is.anembedding from i
1into Z .
To this end we have to verifv thatp.(x)
np a .(z)
=pa(u)
n pa~(v)
isequivalent
to theconjunction
of thefollowing
twoequations :
We continue with a list of
equivalent rearrangements
of the first of these twoequations.
Using
3.13.yields
Employing
the fact thatwe obtain
Bringing
theright
hand side intodisjunctive
normal form shows that thisequation
isequivalent
to theconjunction
of thefollowing eight equations :
Let
(Fn)
stand for theequation
obtained from(En) by replacing
x, u, u’ ...by
f1(x), f 1 (u), (f 1 (u))’
... and P a, aby
p c’p.
crespectively.
.We claim that for all 1 8
(Fn)
isequivalent
to(En).
Except
for n =2,7
this is trivial.The case n = 7 is
proved similarly
nowusing (3.15.3).
Performing
the samerearrangements
as we did above in the reverse direction we see that thesystem
ofequations (Fl) - (F8)
isequivalent
tois
equivalent
toThis proves 3.16.
It remains to show that
f l, f 2 >
is anembedding from 21 1
into U .This
completes
theproof
of 3.15.Enumerate
BI = (bog
..., For TE k2 b T
is defined as instep
2.3.17. CRITERION : F can be extended to an
embedding
Ffrom U1 into ti
iff for everyT E
k2
there is c i e B such thatPROOF OF 3.17. : To prove
necessity
take c . =72(b L
na).
Now assume c~ exists for every T e
k2 satisfying (3.17.0) - (3.17.4).
Set c =
U (c T
z ek2 ) .
We shall show that c satisfies(3.15.1) - (a.15.4).
(3.15.2)
isproved analogously.
(3.15.3)
Since Ek2 } - D I there
are for each y ED1 uniquely
determinedwhich in turn
yields
This proves one
part
of 3.15.3This proves the other
part
of(3.15.3).
(3.15.4)
Take anarbitrary
y EDIe
Lety T
be as above.Notice that
for. 1 1.2 y i E o (b ~ ) ~ Q (b i )
holds. ThusSo we obtain
Now assume
fl(y)
Ea (c*).
Thisimplies
This
completes
theproof
of 3.17.We now show that the axioms
(PI) - (PIV)
suffice to find the elements cz E Brequired
in(3.17).
Take an
arbitrary
i Ek2.
We firstdispose
of the trivial cases.If
bT
= 0 or a nb T
=0,
we choose c T = 0 and(3.17.0) - (3.17.4)
aretrivially
satisfied.If
b z
n a* = 0 we choosecT
=f2(br )
and arethrough again.
So we are left with the
only
non-trivial case : 0 a nbz b’t
.We enumerate a
i(br ) = {y0, "’,
we agree thatYO
is the least element of°1 (b 1" ).
For II e
r2
definey
" =U ( 7r O)yj I j
Jr )
as we have done instep
2.Furthermore
Xi
= for i= 1,2,3.
By property
P VI there isc-r
e thatThis
implies immediately
conditions(3.17.0) - (3.17.2)
and for all 71 E r2Since every
Yj
E can berepresented
asand for any b e B holds
we infer that also
(3.17.3) - (3.17.4)
hold.This
completes step
3 and weproved
the main theorem.3.8. EXAMPLE : We shall
explicitely
construct a countable model of srr /B *.We consider
subsystems
of the power setalgebra Q (the
(artesianproduct
of theset of rational numbers with
itself).
Let 18 0
be the Booleansubalgebra generated by
all suhsets of the form(a.h 1
Y, [ where(a,b ] _ ~ x
c anda,b,c,d E ° is an
atomfree countable Booleanalgebra.
A subset
X 9 Q x Q
is called thick if there are n E pi, qi EQ
such that thecomplement
The thick subsets form a distributive lattice denoted is
relatively complex
mented without antiatoms and without least element.
Forb E
Bodefine
eD~ ~ x ~ b~ ~
then (7 ) is a Stonealgebra satisfying (PI), (PII).
To prove(PIII)
let b eBo
and x E1)«
be surh that x -~ h~.Let the set theoretical
complement
of xbcu ((
c iI
i ~n ~
a n d , ii
such
that i X k implies boi n blk There
is such thatllpo ly (,,o bo. .1 ",,
Since
b Oi
is infinite there is pn EbOj’ Pn 0 [PO,
..., Define to be thecomplement
ofi -nl
then y ED0 and x y
b’*.To prove
(PIV)
let x, y be set theoreticalcomplements
of elements in1)~
such n y -. fi . We have to find an element b eBo satisfying
x r b and b*.Taking complements
we thenarrive at
(PIV).
We may
represent
x . y in thefollowing
way_ , , ..
where i
=/ j implies Pi I
p.. J For every i k there is an intervalhi r Q satisfying
-3.19. THEOREM :
(i)
STA* isN0-categorical
(ii)
STA* iscomplete
(iii)
STA* is substructurecomplete
’
(iv)
STA* is the modelcompletion
of STA.PROOF :
(i)
Let9T 1, en 2
be two countable models of STA*. We shall show that ICt, 2
haveupto isomorphism
the same finite substructures. Theorem 8.2. and 1.2 will thenyield 191 aff qj 2-
Let G =
B , J,
or > be a finite substructureof 9111
We mayw.l.o.g.
suppose thatis in fact a Boolean lattice. Since
D(
~12)
isrelatively complemented
without antiatomswe find an
embedding f 1
from intoD(" 2).
Now id > is anembedding
from
~0,1 ~ , ~ ,
Q ~ into~12
whichusing
the methodsemployed
instep
;3 of theproof
of theorem 3.2. can be extended to anembedding
F from " into~"2’
(ii)
Follows from(i) by Vaught’s
test.(iii)
Followsimmediately
from theorem 1.6.(ii),
and theorem :-1.2.(iv)
Since STA T STA* holds and STA* is substructurecomplete
it remains to show thatevery model of STA can be embedded into a model of ST,I*. If 9T is a model of ST ~
we shall construct an
increasing
sequence( w of
models of STA such thatU c B0 and
if n * 0
(mod 3)
then is atomfree and has no antiatoms and noleast element ’
if n E 1
(mod 3)
thenTn
satisfies axiom(PIII)
if n E 2
(mod 3) then * n
satisfies axiom(PIV)
andD( 1IB n)
isrelatively complemented.
Let * be the union of
(
w - Since the axioms(PI)
to(PIV)
arc ’*’ ’4 sentences and STA is even anequational theory B
will be a model of STA*extending
STA.If n = 0
(mod 3)
take11, n
to be the freeproduct
of 1 n-1 w -times with itself.(see [ 2 ],
section17, [ 4 ] ).
For the next two constructions we shall use theorem 2.5. Assume n 5 1
(mod B)
and"n-i "
"I 3 Take J = I x 4) x Q
and let ~ 0, ~ 0
be as in example
3.18.
The
mapping
F frominto UJ3 defined by F(f) (i,p,q)
=f(i)
is anembedding.
Consider the set C=
{g
cA 3 I
Vi eI( {p,q> c 1
eDo
&tP~>) I 0 ) e
It iseasily
seen that C is the universe of asubalgebra
G c
3
andF( n-1) C; (r. Using
the sameargument
as inexample
3.18. one showssatisfies axiom
(Plll).
If n ae 2
(mod 3) U I 3
taket n
=I 3 . Then IF n
isobviously
relatively complemented
and iff,
g eD(tB n)
aregiven satisfying
f u g = 1 define hby
Then h E
Sk( san)
and hf ,
h* c;; g.Thus f8 n
satisfies axiom(PIV).
This
completes
theproof
of theorem 3.19.REFERENCES
[
1] CHEN,
C.C.GRAETZER,
G.Stone lattices I. Construction theorems. Canad.
J.
Math. 21(1969)
884-894.[ 2 ] GRAETZER, G.
Lattice
Theory.
W.H. Freeman Co. San Francisco 1971.[ 3 ] LAKSER, H.
The structure of
pseudo-complemented
distributive lattices I.Subdirect
decomposition.
Trans. Amer. Math. Soc. 156
(1971)
335-342.[4] PRIESTLEY,
H.A.Stone lattices : a
topological approach
Fund. Math. 84
(1974)
127-143.[5] ROBINSON,
A.Introduction to model
theory
and the metamathematics ofalgebra.
North Holland P.C. Amsterdam 1963.
[ 6 ] SACKS,
G.Saturated Model
Theory.
W.A.
Benjamin,
Inc.Reading,
Massachusetts 1972.[7] SIKORSKI,
R.Boolean