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Exercise 3: Some Lie Groups

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Quantum Field Theory

Set 4

Exercise 1: Classical field theory

Consider a scalar fieldφwith cubic potential interacting with an external sourceJ(t, ~x). The Lagrangian density has the form

L= 1

2∂µφ ∂µφ−λ

3−φJ.

Find the equation of motion. Assuming that the parameterλis small we can look for a solution of the equation of motion perturbatively. Substitute the ansatzφ=φ0+λφ1and factorize the terms with the same power ofλ.

Find the Green function of the problem (the solution of the equation G = δ(t)δ3(~x)) and use it to write the solution in the presence of a general sourceJ(x, t). Specialize to the simple source J(x, t) =J θ(t)θ(τ−t)δ3(~x).

(Hint: in order to solve the equation for the Green function go to Fourier space and write→ −((w+iε)2−k2).

What’s special in this particular choice of regularization?).

Consider the first order (inλ) equation and plug in the solution found forφ0; then solve forφ1.

Exercise 2: Affine transformations

Consider the two parameter Lie group acting on the real numbers defined by the transformations:

D(a) :x→ax T(b) :x→x+b.

• Define

U(a, b) =T(b)D(a) :x→x0=ax+b.

Show that this transformations defines a group.

• Consider the generators of the groupT, Dsuch that:

D(1 +a) =eiaD, T(b) =eibT, Find the commutation relations between the generators:

[T, T] =? [D, T] =? [D, D] =?

Exercise 3: Some Lie Groups

Consider the following Lie groups:

U(N) =

N×Ncomplex matrices such thatUU =U U = 1 , SU(N) =

N×Ncomplex matrices such thatUU =U U = 1,detU = 1 , O(N) =

N×Nreal matrices such thatRTR=RTR= 1 , SO(N) =

N×Nreal matrices such thatRTR=RTR= 1,detR= 1 , SL(N,C) ={N×Ncomplex matrices such that detA= 1}.

For each of them find a basis and the dimension of the Lie Algebra (recall that a Lie Algebra is a vector space).

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Exercise 4: Jacobi Identity

Show that, for any Lie Algebra defined by the commutation relations Ta, Tb

=ifabcTc , the followingJacobi identity holds:

X

d

fadefbcd+fbdefcad+fcdefabd

= 0.

This is a straightforward consequence of the identity:

Ta,

Tb, Tc +

Tb,[Tc, Ta] +

Tc,

Ta, Tb

= 0.

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