R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
D AVIDE G UIDETTI
A maximal regularity result with applications to parabolic problems with nonhomogeneous boundary conditions
Rendiconti del Seminario Matematico della Università di Padova, tome 84 (1990), p. 1-37
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Regularity Applications
to
Parabolic Problems
with Nonhomogeneous Boundary Conditions.
DAVIDE
GUIDETTI (*)
Introduction.
The aim of this paper is to
study
mixedproblems
ofparabolic type
withnonhomogeneous (possibly nonlinear) boundary
conditions.The main tool is a certain maximal
regularity
result(theorem 2.1) allowing
tostudy
thegeneral problem by simple
contractionmapping arguments.
The basic idea comes from B. Terreni’s[TEI ]
andstarts,
from an
explicit representation
of the solution(formula 12) together
with suitable estimates in the linear autonomous case.
However,
while Terreni’s results areultimately
based on timeregularity assumptions,
hereeverything
is donestarting
from asuitable
spatial regularity
of the data on the lines of Da Prato- Grisvard’s work in the case ofhomogeneous boundary
conditions(see [DPG]).
Also we remark that thisapproach
allows to avoidregularity assumptions
on the initial datum of the kind of Terreni’s conditions5.1,
which seems to cause somedifficulties,
forexample
in the
study
ofglobal
solutions.Finally,
we considerequations
andnot
system.
The extension to this moregeneral
case does not seemto introduce further difficulties.
The paper is
arranged
as follows: the firstparagraph
contains thegeneral properties
of little Nikolskii spaces, which are thebasic spaces
(*) Indirizzo dell’A.:
Dipartimento
di Matematica, Piazza di Porta S. Do- nato 5, 40127Bologna, Italy.
we shall use, with a brief
study
of linearelliptic problems,
which isnecessary in the
following
and some variants of the results of sec-tion 2 in
[TE].
Here the basic results arepropositions
1.4 and 1.5.The second
paragraph
is dedicated to thestudy
of theparabolic
auto-nomous
problem
and is directed to prove the basic maximalregularity result,
theorem 2.1. The thirdparagraph
contains asimple
result ofperturbation,
with thestudy
of linear nonautonomousproblems.
Thefourth and final section is dedicated to
quasilinear problems.
Finally,
wespecify
that theexpressions
C and « const» will beused to indicate constant which may
change
from time to time.l.
Elliptic problems
in little-Nikolskii spaces.We shall be concerned with a class of
subspaces
ofLp(Rn),
theso called little Nikolskii spaces if
{) E ]0, 1],
p e
[1, +
it is defined aswith the usual modification if p =
+
oo and the natural norm. We remark that the space isexactly
the space of function of class ek which are bounded andlittle-holder
continuous with all the derivatives of order notexceeding
k.Now,
let S~ be an open(nonempty)
subset of Rn withsuitably
smooth
boundary.
We indicate withTo
the traceoperator To f
=118.0.
We pose
with the natural norm of
quotient
space11.I!k+8,v,.o.
The
proof
of thefollowing
result is routine(see
also[ZO]
for otherresults of
multiplication
in Besov and Nikolskiispaces):
PROPOSITION 1.1. - Let Q be an open
(nonempty)
subseto f
~ E ~,~(,~), u ~ ~,~(S~).
Then au Ea~~(S2)
An easy consequence of
proposition
1.1 is thefollowing :
consider adifferential
operator
Our interest in these spaces lies on the
following
facts: ifAo, A,
are a
couple
ofcompatible
Banach spaces(see [BL] 2.3),
and if wedenote with
(Ao, (ore ]0, 1 [)
the continuousinterpolation
space determinedby Ao, .~1 (see [DPG]),
for Ufol,
with
(here
and in thefollowing,
if J,E R, [~,]
will be theinteger part
ofA).
The well known Calderon-Stein extension theorem
implies (see [ST],
ch.
VI,
th.5):
PROPOSITION 1.2. Let Q be an open
subset o f
Rnsatisfying the
as-Assume
Ao ,
A arecompatible
Banach spaces and let - E]0, 1 [.
We recall that ~4. is of class
A1) (see
forexample [GR]
def.4)
it
(Ao,
A C(Ao, .Å.1)s,oo (continuous inclusions) (here ( , )s,~,
is the real
interpolation
functor of indexes s,PROPOSITION 1.3. Let Q be an open subset
o f
Rnsactisfying
the as-sumptions o f [ST],
ch.VI,
3.3..F’or p E]1, + 00[,
7c E N U weput
Assume so, SI, 82ER, 0 so
st s2.Then
~,~ (S~)
iso f
classA§’(Q)).
PROOF. If is sufficient to consider the case S2 = Rn.
One has
iteration
property.
In the same way,It remains to show that
If is the closure of in As
ç and is dense in
B;:1 (Rn),
the result follows.If s1
eZ, by
theorem 6.4.4 in[BL]y
for p E]1, 2],
So the result is
proved.
Now we consider a bounded open subset S~ of Rn with
boundary
of class and a linear differential
operator A(x, a) = ~ aa(x)
8"of order 2m. We assume that:
(A2) A(x, 8)
isproperly elliptic.
(A3)
There exists~o
E]nl2, ~c[
such thatFor k =
1, ... ,
m a linear differentialoperators
is
given,
in such a way that:(B3)
For k =1,
... , m, theboundary
8Q is noncharacteristic in each of itspoints
withrespect
toa).
(B4)
At eachpoint
x E8Q,
ifv(x)
is the inward unit vector to 8Q in xand ~ ~
0 any real vectorparallel
to theboundary in x,
we indicate with
t)($, A)
thej-th
root withpositive imaginary part
of the
polynomial
in+ zv(x))
- A.Then,
ifthe m
polynomials +
=1,
...,ml
arelinearly
inde-pendent
moduloWe shall consider the
problem
We remark that a
priori
estimates for(1) (case
ofregular prob- lems)
wereobtained,
forexample,
in[ADN], [BR1, 2, 3], [AR], [TR].
Here,
we need thefollowing
PROPOSITION 1.4. Consider
(1)
with theassumptions (A1 )-(A3),
u E
W2m,p(Q)
and solves(1),
then u E~,pm+ ~(S~)
andwith C
independent o f
u.PROOF. First of
all,
we look for anappropriate
apriori
estimate.We start
by assuming
that U C~,~m+8(S~),
suppB (xO, r)
with XO EQ,
r dist
(x°, By
the apriori
estimates of[BR1, 2, 3]
and[ADN],
one has
For 0
I~I
distwhich, by assumption (A1), implies
and
(here
const(x°, r)
indicates a constantdepending
on0153O, r).
Next,
let x° EaS2,
r > r’ >0,
u EÂ;m+8(Q), u(x)
= 0 ifB(x°, r’).
Then,
~c solvesIf r is
sufficiently small,
there existoperators 8), 8)
withcoefficients in and
02m-mk+l(,Q) respectively, satisfying (A1 )-(A3), (B1 )- (B4 )
andcoinciding
with and inBy
well known results(see [AG]~,
there existsÂo E C
such thathas a
unique
solutionwhich
belongs
to -By interpolation,
and
Applying
this estimate to(3)
andusing
the factthat,
if r’ is smallenough
by
localization one draws(2),
under theNow assume
only
thatAgain using Agmon’s results,
one proves that there exists such that
has a
unique
solutionand
Consider
with
(the
existence of follows from thedensity
of in/~(R")).
For r
large enough
theproblem
has a
unique
solution a inwhich
belongs
toThe usual
interpolation argument
provesthat,
ifNow assume is a solution of
(1 ),
withLet be the solution
(belonging
toOne has
and, using independent
of r.Then,
for r, s EN,
The a
priori
estimategives
with
s(r, s)
- 0 as r, s -~+
oo.It is
easily
seen thatlIu(r)- (r - + 00).
From this theresult follows.
The
following proposition
is on the lines ofinequality (2.13)
in[TE1] :
PROPOSITIOH 1.5. Assume
(A1)-(A3), (B1 )-(B3)
aresatislied. Let
A = with 1 p
-~-
00, 0 0p-1.
There existsC ~ 0
suchthat, i f
u E solvesA (x,
=f
in S~For the
proof
we need thefollowing
lenama :LEMMA p >
1,
0 0p-1. If
zs afamily o f
01functions
in R such that’
with A
independent o f
g and r.PROOF. As 0
p-1,
if we definesg ^ (x)
=g(x)
if0153n>O, g ^ (x)
= 0if
0,
we have thatg"e
and(see
theresult of
[SH]
andinterpolate) .
’ ’
One has also
First
o f all,
aLs8ume h =
(0, q),
with q>r. ThenAssume h =
(0, ’1]),
0 ’1] r.One has
The case h =
(0, q),
with 1J0,
can be treated in the same way.So,
and the result is
proved.
PROOF OF PROPOSITION 1.5. From
[AG1]
one draws the existenceof such
that,
iflarg
For
every x°
E ôD there exists an openneighbourhood
U ofx°,
~ : of class
02m+l,
such thatAs Q is
bounded,
there exist withcorresponding neigh-
bourhoods and
diffeomorphisms 0,,, ..1 (P,,
such thatx
3D C
(J
Let{1pl’ ...,
be apartition
ofunity
in aneighbourhood
~=1
of
3Dy
such thesupp 1pj ç; ~7, (i
=1, ...~).
Let be afamily
of 000 functions in
R,
such that = 1 ifX,.(t)
= 0 ift > r,
Now we remark
that, if g
c/~(R~ 1 p +
oo, 0 0 andsupple
Thisimplies
that(by
lemma1.6)
With the same
method,
so that
Choosing r
=IÂ-1!(2,m)
andusing
the momentinequality implied by
prop.
1.3,
the result follows.2. Linear autonomous
parabolic problems.
Now we shall use the results of
paragraph
1 to obtain a maximaregularity
result for linear autonomousparabolic problems
likeAs
already declared,
the main tool will be anexplicit representation
of the
solution, following
a methoddeveloped
in[TE1].
We remarkthat theorems of maximal
regularity
with nonautonomousboundary
conditions were also
obtained,
forexample, by
Solonnikov in a series of papers(see [501, 2])
in the moregeneral
case ofsystems, by
Agranovich-Vishik [AV] (anisotropic
Sobolevspaces),
Lunardi[LU]
and
[TE2] (spaces
of continuous and holder continuousfunctions).
However the result of theorem 2.1 seems to be new.
Now,
assume thatsatisfy
theassumptions
Define:
A is the
infinitesimal generator
of ananalytic semigroup {exp (tA):
00}
in Forsimplicity,
we shall assume(this
is not restrictive atall)
that c{~
Re z0}.
Fix 0 e]0, p-1[
and let u be a solution of(9), ~eCi([0,T];~))nC([0,T];~+~)) (here
andin the
following
weidentify mappings
of(t, x)
withcorresponding mappings
of t with values in a space of functions of domainS~).
Then
necessarily IE C([0, T] ; ~,~(S~)),
(1~ - 1, ..., m). By
themoment
inequality,
y which is a consequence ofproposition 1.3,
~~i-~/(2~)(~~~+~)) ~ ~
is a Banach space,oc=]0,l[,
),£%([0, T]; E)
=l$([0, T]; E) lim sup ~(t -
t E=
T]; E?~.
Thisimplies
Therefore,
we can assumeFinally, necessarily, Bk( ~ , 8) uo - gk(O)
=0,
for k =1,
.. , m.Now, suppose A
For k =1,
... , m theproblem
has a
unique
solutionM=JV~(~)~, By proposi-
tion
1.4,
if andoriented
from - 00 exp (- irpo)
to+
00 exp(iØo).
We have the
following
THEOREM 2.1. Assume
(A1)-(A3), (B1 )-(B4)
are8atisfied.
Then, (9)
has acunique
solutionWe start
by remarking that, owing
to(11),
Vg
E so that the lastintegral
in(12)
converges, at least inEP(Q).
To prove theorem2.1,
we startby considering
the firstintegral
in(12):
LEMMA 2.2. Let
PROOF. As 0 0
Â:(Q)
=(LP(Q), D(A))0/(2m) (See [DPG],
th.
6.10). So, by [DPG]
th.3.1,
we conclude thatT]; W2m,v(Q))
and
A(., 8) u
E0([0, T]; ~,~ (,~ ) ) .
Therefore the result follows fromproposition
1.4.LEMMA 2.3. Let
with
g(0)
= 0 . PutT hen u is the
only
solution inPROOF. One has
u(t)
=uo(t) +
withWe indicate
with 03B3t
thepositively
orientedboundary
ofThen
This proves that
Further, [0, T],
and
so that we have
and this
implies
Further,
and so
by
the residuetheorem,
as theintegral
isabsolutely convergent
in SoAnalogous
considerations take toplying
Fubini andCauchy theorems).
Sowe
cansay
thatW2m, V(Q)),
Now fix E E
]0, T[
anddefine,
for t E[8, T],
Thinking of Us
as a function with values in one can differentiate and obtainSo we have
proved that,
for every t E]0, T], u’(t)
exists inLP(92)
andequals A( ., 8)u(t).
A passage to the limit asgives
the finalresult.
LEMMA 2.4. Let
PROOF.
By
Lemma2.4,
As
already mentioned, A§(Q)
=(Lp(S~),
so,by
theorem 2.5in [DPG],
if then if andonly
ifFurther,
anequivalent
norm in~,~(S~)
isWe pose, for
We recall that
z(3)
- 0(3
-~0 ) .
One has
(owing
toproposition 1.5)
4--
On the other
hand,
Further,
so that
It is also
easily
seenthat,
for afiged t, I1(~, t) + I2(~, t)
~ 0(~ -~ +
tion 1.4.
Analogous
estimates prove thatNext,
we considerA( ~ ,
($
-+ oo)
and isuniformly majorized by
Also,
which can be treated as
the foregoing integral.
To prove that Ul E
0([0, T]; 22-+O(S?)
it is sufficient to remarkthat,
7 forand to observe that
and
apply
methodsanalogous
to theforegoing
estimates.So we have
proved
thatT]; ~,~’~+8(S~)).
As(du/dt)(t)
==
A(., a)u(t), 01([0, T]; ~,p(,S~))
and the lemma iscompletely
established.
PROOF OF THEOREM 2.1. First of
all,
we remark that it is not restrictive to assume ifmk = 0,
so that- becomes u -
UklaD
=0,
withSubstituting v
= u - gkto u,
theproblem
is reduced to the caseg = 0 if
mk = 0. Now, u(t)
=vo(t) + vl(t),
withBy
lemmata 2.2 and2.4,
One has
and so,
Again
forso that
From this
Therefore the result follows from
proposition
1.4.3. Perturbations and linear nonautonomous
parabolic probleans.
In this section we shall consider certain
perturbations
ofproblem (9)
of the kind
For 6 > 0 we define
We have :
LEMMA 3.1. Let
Xa
be ac Banach spaceo f type
a(a
E[0, 1[)
betweenFurther,
assumef or l~m~~2m2013 1, Yk, a is a
.space01 type
«and
space o f
betweenThen,
PROOF. In force of lemmata 2.2 and
2.4, M,
andV6 >
0.Moreover, by
lemma2.2,
(const independent
of 6 E]0, T]) .
This proves the result for
~a .
Ananalogous proof
isapplicable
toNk,,5.
THEOREM 3.2. Consider the
problem (14),
withM, Nk satislying
theassumptions of
lemma3.1, Nk
= 0i f
mk = 0. Then(14)
has aunique
solution UE
0([0, T]; ~,D~+e(SZ))
f1C"([O, T]; ~,~(S2)) for
everyPROOF.
Exchanging u
with u - uo, it is seen that it is not restrictive to assume0,
0(1 c k c m)
and look for a solution in.E7y.
So we can consider theequation
By
lemma3.1,
if 6 issuitably small, by
the contractionmapping prin- ciple, (15)
has aunique
solution inE8.
Then one canrepeat
the processtaking
as initial valueu(3).
As thelength
of definition of the local solution does notdepend
on thestarting point,
the solution is de- fined on[0, T].
To
give
anexample
ofoperators
and spacessatisfying
the assump- tions of lemma3.1,
consider the space which is oftype
a = 1-
0/(2m)
between andA,21+0(D) (see proposition 1.3)
anddefine
Assuming K~
with
w(3)
-~ 0(b ~ 0),
one has that IfÂ:(D)).
If
Now we consider the
problem
We h,, ve:
THEOREM 3.3..Assume the
assumptions (A1)-(A3), (B1 )-(B4)
aresatisfied by
Q and theoperators A(t,
x,a), (Bk(t,
x,a)k 1,
’Vt E[0, T]).
Further :
Then
problem (16)
has acunique
80lution u in the spacesuch that
B, (0,
... , 0.PROOF. For mk =
0,
w~e can divideby b(t, x)
and assumeb(t, x)
= 1.Now,
weput v(t)
=u(t)
- UO.Then,
we havewith
Owing
to theassumptions,
This shows that we can assume
Under these
(more restrictive) conditions, (16)
can be written asDefine as the solution of
in the space
The
assumptions (kl)-(k2)
assurethat,
if 6 issufficiently small,
T isa contraction in
Ea,
so that(16)
has a solution in[0, 6]
with 08 c
T.Starting
from the initial value in 3 one canprolounge
the solutionuntil 25
(if 2~ c T),
as thelength
of the interval of definition of the local solution does notdepend
on thestarting point
and the data.THEOREM 3.4. Consider the
problem
with
A (t)
=A (t,
x,a ), Bk (t)
= x,a ) satis f ying
theassumptions of
theorem 3.3. Further assume that ~ E
C([0, T] ; ~,p(S2))),
withXa
intermediate space
o f type [0,,I[)
between andwith intermediate
spaces of type between, respectively,
Then
(18)
has aunique
solutionPROOF. Analogous
to theproof
of theorem3.3, using + + M(t)
andBk(t) + Nk(t)
instead ofA(t)
andBk(t).
4.
Quasilinear problems.
Now,
we shall considerquasilinear parabolic problems
likeis the set of the derivatives of
order j
ofu).
We mention that
quasilinear problems
with nonlinearboundary
were considered for
example
in[FR] (very particular equations
ofsecond
order), [AM] (systems
in variationalform), [AT] (applying
thelinear results of
[TE1]
andfinding, by
the linearizationmethod,
solu-tions in
C1 +"( [o, ~] ;
r1Ca( [o, ~c] ; [GM] (existence
ofclassical solutions for
equations
with smooth coefficients anddata), [LU]
(applying
the results of the linearpart).
Here we shall
apply
the linearizationtechniques
to(19) using
theresults of sections 2 and 3 and
finding
solutions inC([0, r]; A2 I I (-Q))
nr1
T];
forsome Te]0, T].
We shallemploy
the follow-ing assumptions :
first of all ,~ is a bounded open subset ofRn,
withboundary
of class C°°. IfN(j )
is the number of multiindexes oflength
not
overcoming j,
we assume that:elliptic,
there exists§o
E]a/2, n[
such that(L6)
For k =1, ... ,
m, 1 and thesystem
ofoperators
( £ Bk,p(t,
x, " is normal in 8Q ‘dt E[0, T], VqkERN(mk-1)
suchthat,
for mj, the coordinatesof qj
coincide with thecorrespond- ing
coordinates of qk .(L7)
b’t E[0, T], x
EaS2, q
cRN(2m-l),
letv(x)
be the inward unit vector to 8Q in x 0 any vectorparallel
to theboundary
at x.Denote
by t3 (~; A)
thej-th
root withpositive imaginary part
of thepolynomial
inx, q; ~ + zv(x))
- A.Then,
ifIArg
the m
polynomials
in x,qk; E +
arelinearly
inde-m
pendent A)) (with
the coordinatesof q
coincid-; = i
ing
with thecorresponding
coordinates ofqk).
we pose
We remark
that,
ifWe have:
LEMMA 4.1..Let
PROOF. As the
inequality
(ro
bounded on bounded subsets ofRN(2m-l) XRN(2m-l»)
thebelonging
of
A(u)
toC([O, T]; ~,~(SZ))
follows. Thecontinuity
of .A. is a conse-quence of the estimate
(w
bounded on bounded subsets ofRY(2--
1> XRi7(2m- 1)).
We define
Then
T]; ~,p(S~~) ; C([0, T]; ~,~(S~)~.
From this the com-plete
result followseasily.
In each case,
PROOF. The
proof
does not differessentially
from theproof
oflemma
4.1, taking
into accountthat, if ~ >
2m -1+ np-1 + 0y
LEMMA 4.3. Let
Then and
PROOF. A
standard
consequence ofproposition
~..3.THEOREM 4.4. Assume
(Ll)-(L9)
aresatis f ied.
then there exists6 E
]0, T]
such that(19)
has aunique
solution in the spacePROOF.
Defining v
= u - uo , we can write(19)
in the formand consider the
problem
The
operators A(t, x, 8)
andBk(t,
x,8) satisfy
the assump- tions of theorem3.3,
while theoperators M(t) verify
those oftheorem
3.4,
whith.Xa
= for 2m -1+ np-I +
0~
2m+ 0, owing
to lemma 4.1.Further, by
lemma4.2,
theoperators Nk(t)
are conformal to the conditions of theorem
3.4,
withÂ;(Q),
Therefore, (21)
has aunique
solutionr1
C( (0, T]; ~,~m+8(S~)~.
Put z = v - w.Then,
with
Owing
toproposition
1.1 and lemmata4.1, 4.2, 4.3,
Ve > 0 there exist60 c ]0, T],
>0,
such thatVz1, Z2 E Ea ,
with 0 66,,
- 0
(3
-~0),
sothat,
for 3suitably small, by
the contractionmapping principle,
there exists lVl > 0 such that(23)
has aunique
fixed point in the set {x E Ed: ||z||EoM}.
We conclude with a
simple
result ofunicity.
THEOREM 4.5. Under the
assumptions (Ll)-(L9)
eresatisfied, if
PROOF. Put
Then
Fix
]o, 1 - By
theorem3.3,
theproblem
has a
unique
solution v e01([0, ~] ; h§’(Q))
nC([0, ~] ; h§"’+°’(Q) ).
By
theorem 5.4 in the solution v isunique
inAs u solves
(24)
in this space, u = v and soCi((0, 3] ; £§’(Q))
mn
C( [o, ~] ; 1§°’+ °’(Q)).
Therefore the result isproved
if 0 1-Viceversa,
one can iterate themethod, starting
from theassumption
UE
C~(10, 31 1 £I’(Q))
n0([0, 31 ~,2m+6’(~~1,
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