R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
L. F UCHS
P. S CHULTZ
Endomorphism rings of valued vector spaces
Rendiconti del Seminario Matematico della Università di Padova, tome 65 (1981), p. 103-110
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Endomorphism Rings Spaces.
L. FUCHS - P. SCHULTZ
(*)
The
study
of valued vector spaces as a tool to obtain information about the socles of abelian p-groups hasproved extremely
useful.We continue this
approach
with thestudy
of theendomorphism rings
of valued vector spaces. As we shall see,
they
resemble-as ex-pected-endomorphism rings
of abelian p-groups.We discuss two
aspects
of theendomorphism rings.
Firstly,
weinvestigate
therelationship
between two valued vector spaces whoseendomorphism rings
areisomorphic.
Our theorem isanalogous
to theBaer-Kaplansky
theorem on abelian p-groups,[3],
but in the
present
caseisomorphism
isreplaced by
a weaker notion: a vector spaceisomorphism
which does notnecessarily
preserve valua-tion, only inequalities
between values.Secondly,
wegive
aring-theoretical
characterization of endomor-phism rings
of valued vector spaces ingeneral.
This result is motiv- atedby
Liebert’s theorem[4]
on theendomorphism rings
ofseparable
abelian p-groups, and its
analogue
forhomogeneous separable
torsion-free groups
by
Metelli and Salce[5].
In ourproof,
we use ideas fromboth of these papers.
We consider vector spaces V over a fixed field 0 which are
equip- ped
with valuations into atotally
ordered set(or olass)
-V. We assumethat _T’ has a maximum element oo and that every
non-empty
subsetof T has a supremum. A valuation of V is a function v : V - T such
(*)
Indirizzodegli
AA.:Department
of Mathematics, TulaneUniversity,
New Orleans, LA 70118, U.S.A.;
Department
of Mathematics,University
of Western
Australia, Nedlands,
W.A. 6006, Australia.104
that
(i) v(a)
= ooexactly
if a =0;
(ii) v(aa)
=v(a)
for all 0 in 0 and all aE Y;
(iii) v(a + b)
2 min(v(a), v(b))
for all a, b E V.A
morphism
between two valued vector spaces is a 0-linear map which does not decrease values. We writemorphisms
on the left.The set of all
morphisms
from V to V forms a0-algebra,
th6 endo-morphism ring
ofTr,
which we denote End V. We shallregard
End Vas an abstract
0-algebra,
without valuation.For
unexplained terminology
andelementary properties
of valuedvector spaces we refer to
[1]
and[2].
1. Valued vector spaces with
isomorphic endomorphism rings.
Let V and W be valued vector spaces. A map g : ~’ -~ W is cal- led a
pseudo-isomorphism
if(a)
it is a vector spaceisomorphism;
(b) v(a) v(b)
for a, b E V~ if andonly
ifNotice that
if ~
E EndTr,
then EndW,
and thecorrespond-
ence
gives
rise to aring isomorphism
between End V’ and End W. We wish to showthat, conversely,
everyisomorphism
between the endo-morphism rings
is inducedby
apseudo-isomorphism
of the valuedvector spaces.
THEOREM 1. Let V and W be valued vector spaces and 1jJ: End V -
- End yY an
algebra isomorphism.
Then there exists apseudo-isomor- phism
Y -~ W such thatFor
brevity,
y write E = End Tr and E* = EndW’~
and set~*
="PE
for ~
E End TT,If E is a
primitive idempotent
in then E* is one in E*. As E V is1-dimensional,
its non-zero elements have the samevalue,
so wecan
preorder
the set ofprimitive idempotents
of Eby setting
Notice if and
only
ifeEB =F
0.Consequently
y ip preserves thepreorder
ofprimitive idempotents, exactly
if8* e*.
Let us select in the
support
ofY, (supp
V = 0 inV}),
astrictly descending
chain which isinversely
well-ordered in the
ordering
ofT,
and which is cofinal in supp V in thesense that for every y E supp V there is
C ~
such that y.As is a summand of
V,
someprimitive idempotent Ec- E
satisfies moreover, ute can choose these -,,(~ C Â)
to bepairwise orthogonal.
It is evident that there areendomorphisms $jg
of Y(for
all d C ~
Â)
such thatThe
endomorphisms 8a
and~a~ satisfy:
(i)
8(1 arepairwise orthogonal primitive idempotents;
It is clear that the
endomorphisms s) and ~*
in E*satisfy
thesame conditions.
By primitivity, ~~
W is1-dimensional,
and(ii)
im-plies
that~a~
will map onto We wish to showthat,
forevery a
Â,
we can select aCa E s:
W such that = co for all o (2.Suppose
that these Ca have been so chosen for every a z. If -r - 1exists,
choose et so as tosatisfy
= c,-,. If r is a limit ordinal2
choose c, tosatisfy
c~ for some d T.Then
for ao T,
~;TCT ==
exce for some a E0
and(iii) guarantees
that a = 1.We are now
ready
to define a mapg : V -
W. Given 0 # aE Tr, pick
an a(1 and an q c E such that a = nao(our
choice of the aa ensuresthat this is
possible),
y and let106
This P is
well-defined,
for if a = forsome $
E .Eand p
> d, thenao implies (E-nEop)Ep=
0 whence(E*2013n*Eop)E*p=
0 and$* cg =
- It is
straightforward
to checkthat p
is a vector space iso-morphism
between V and W. To show that it is apseudo-iso- morphism,
note that ifv ( c~ )
fora, b
then = b for somez ejE7. Write a = b then
(~2013~)~=
0 whichimplies (x* ~*-
o. Hence =pb,
and thusv(pb),
indeed.Finally,
every c E w~ is of the form c = for some and (].Consequently,
completing
theproof
of the theorem.It is
straightforward
tocheck
thatif g
is apseudo-automorphism
of
Tr,
thenis an
order-automorphism
of supp V. In certain cases, e.g. if supp V iswell-ordered,
theidentity
map is theonly order-automorphism.
Inthese cases, a
pseudo-automorphism
of V isnecessarily
an automor-phism ;
therefore Theorem 1implies
that then allautomorphisms
ofEnd V are inner.
(This
is well known forordinary
vector spaces V where supp V may be viewed as asingleton.)
2. A characterization of
endomorphism rings.
Our next purpose is to characterize
intrinsically
thoserings
whichare
endomorphism rings
of valued vector spaces.Let .E = End V be the
endomorphism ring
of a valued vectorspace Tr.
By
I we shall denote the set ofprimitive idempotents
in.E,
and
by .Eo
the left ideal of Egenerated by
I. First we show that thefollowing
hold:(i)
Forall n
E Eand p
e1,
there is a a c I such that = i7e.(ii)
Forall e,
d EI,
eithereEa
=A 0 or0;
whichever isnot 0 is a 1-dimensional
subspace
of E.(iii) If,
forsome ~
d E I both 0 andoEd # 0,
thentheir
product
0 either.(iv)
E iscomplete
and Hausdorff in thetopology
where a sub-base of
neighbourhoods
of 0 consists of left annihilators of elements ofI,
andEo
is dense in E in thistopology.
In
fact, (i)
follows from the fact thatqov
is an at most 1-dimen-sional
subspace
ofTT,
so it is anindecomposable
summand of V.To prove
( ii ),
observe that = 0 if andonly
if cannotbe
mapped
onto This is the caseexactly
if If> v (~),
thenAs =
~TT
and 0implies 0, (iii)
is clear.Finally,
y to prove(iv),
note that allendomorphism rings
are com-plete
Hausdorff in the finitetopology.
In thepresent
case,{1]
E ==
0}
=E(1- or)
for any a E Tr where c~ is theprojection
to the firstsummand in V = V’
(for
a suitablesubspace
V’ ofTT) .
In otherwords,
the finitetopology
of .E has a subbase ofneighbourhoods
of 0consisting
of left annihilatorsAnn 9
of in E.Given q
E E andai , ... , the
subspace
~’spanned by
the aI, ..., an is a summand of V~. If a is aprojection
V - W and U ={1]
E ... = qan =0}
is the
corresponding neighbourhood
of0,
then 1 - ~ E U. As U is aleft ideal of E
U;
here qn EEo
since ~c is the sum of nprimi-
tive
idempotents.
Thedensity
of.Eo
in E is now clear.What we have said so far establishes the
necessity part
of thefollowing
theorem.THEOREM 2. Let E be a
0-algebra
with 1. E is theendomorphism ring of a
valued vector space Vif
andonly if
Esatisfies
conditions(i)-(iv).
In order to prove
sufficiency,
let Esatisfy (i)-(iv).
The set I ofprimitive idempotents,
which is notempty by (iv),
can bepreordered by setting,
or EI,
This relation is
trivially
reflexive(as a E aEa).
Itstransitivity
follows from
(iii),
while(ii) implies
that it is a totalpreorder.
Theclasses
[ o ]
under theequivalence e - or exactly
aform a
totally
ordered set.h,
and we define a functionby
_[ o] .
We can nowadjoin
to T newelements,
so that -P willcontain oo and suprema for all of its
non-empty
subsets.We
give
a detailedproof
in case h has a smallestelement,
andthen indicate how this has to be modified in the
general
case.108
Let
[E]
be the smallest element in DefineFor o
E I, OY
is never0,
because(ii)
and theminimality
of[8] imply
that
(lV
=(lEe
is 1-dimensional. Weassign
the valuef ( O )
to theelements
of e V:
This definition is
unambiguous,
for ifpEe
= a = for some p, o E Iand ~,
q EE,
thenboth (2a
= a and a, thus 0 ~ od EeEa
and0 ~ 0’p E
aE(2 imply [(2]
_[d]. Furthermore, (i) guarantees
that wecan
assign
a value to every a E V.In order to ascertain that v : V - h
yields
a valuation of the vec-tor space
V,
we have toverify
thatv ( a + b )
> min(v(a), v(b))
forall a, b Set a =
$E7 b
= qi(~, ~
EE) ; by (i)
(2a = a and ab = b for someAgain by (i), ~(a -~- b) -- a -f- b
for some reI;
therefore either 0 or 0
(or
else a-f- b
= 0 in which casethere is
nothing
toprove).
Hence either # 0 or0,
that iseither
t(~)
orf (or) ~ t( 1’),
as desired.Every E
E E induces anendomorphism E
of V viawhere a
(r~ E E).
To seethat ~
does not decreasevalues,
sup- posethat
a E Isatisfy o(qs)
_ ?7E and ==(cf. (i)).
It isenough
to consider the case0;
then =J$oqs implies
0 whence
f (~) f (a),
i.e. induces thezero
endomorphism
ofV,
i.e. then in view ofeEe
# 0 for alleEl
we conclude from(iii)
that = 0 forall p
c 7.We infer
that E c- Ann
forall p
e-1,
so the Hausdorflproperty
in
(iv) guarantees that ~
= 0.Consequently, E
can be viewed as asubring
of End V = F.For =
e V
is 1-dimensional in view of(ii).
Thuswe can write
(~ E E).
Given any we then have ux = X8 for someBy (i),
some o E I satisfies Clxe = y8, wheref (d) > f(o) since p
doesnot decrease values. Hence 0
which, along
with 0implies
as
stipulated by (iii).
Hence andthere is
a ~
E E such that~x
= For any y = ne E Tr we now have(where
we set eq8 - ax for some a E0), showing
thatflë
= Henceit is evident that
This
implies
at onceNext,
let n be aprimitive idempotent
in F. Then flz for asuitable z E Tr.
By ( i ),
GZ = z for some GEl whence we obtainWe conclude that the finite
topology
of I’ has a subbaseconsisting
of left annihilators
(in I’’ )
of the elements of I. It also follows that the finitetopology
of F induces thegiven topology
of E.We
proceed
toverify
that.Eo
is dense in .F’. Let a E .F’ and U =- r1
(ej c- 1; j
=1,
... ,n )
aneighbourhood
of 0 in F. Sinceby (iv) Eo
is dense inE,
there is an q E.Eo
such that1 - q
E U r1 E.Manifestly,
U is a left ideal of~’,
so i.e. U.Here an E
Eo
as is evident from =Eo,
soEo
is dense in.Z~’,
indeed.To conclude this
proof,
note thatEo
E ~’ andEo
is dense in F.By (iv),
.E iscomplete,
sonecessarily
E =.F,
as we wished to prove.If 1-’ fails to have a smallest
element,
then weproceed
as follows:Just as in the
proof
of Theorem1,
we choose adecreasing
chainof
primitive idempotents
which is cofinal in I. As in Liebert’s theoremon the
endomorphism rings
ofseparable
abelian p-groups[4],
we usethe fact that
oEa
is 1-dimensional if cre
in our chain to define a directsystem
of left ideals of the form and we take V to be the direct limit of thissystem.
Now the Hausdorff
property
of thetopology
on E ensures that Eis
canonically
embedded as asubring
of End TT = I’. In theproof
110
above that = for
every p E I,
wereplace
the minimal idem-potent
Eby
some J in our chain and use the canonicalembedding
of
Ej
in .h to conclude thatFE, = Eo.
Finally,
theproof
that the finitetopology
on F induces thegiven topology on E,
and thatEo
is dense in 1~ followsexactly
as in theproof
above.REFERENCES
[1] L. FUCHS, Vector spaces with valuations, J.
Alg.,
35 (1975), pp. 23-38.[2] L. FUCHS, Abelian p-groups and mixed groups, Les Presses de l’Université de
Montréal,
1980.[3]
I. KAPLANSKY,Infinite
AbelianGroups,
Univ. ofMichigan
Press, Ann.Arbor, 1969.
[4] W. LIEBERT,
Endomorphism rings of
abelian p-groups, Studies on AbelianGroups,
Gunod, 1969, pp. 239-258.[5] C. METELLI - L. SALCE, The
Endomorphism Ring of
an Abelian Torsion-free Homogeneous Separable Group,
Arch. der Math., 26 (1975), pp. 480-485.Manoscritto pervenuto in redazione il 19