A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
M. F URI
M. M ARTELLI
A degree for a class of acyclic-valued vector fields in Banach spaces
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 1, n
o3-4 (1974), p. 301-310
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http://www.numdam.org/
A Degree for
aClass of Acyclic-Valued Vector Fields
in Banach Spaces.
M. FURI - M.
MARTELLI (*)
1. - Introduction.
Let S be the unit
sphere
of a Banach space E. We say that an upper semicontinuous multivalued map is an admissible vectorfield
ifthe
following
conditions are satisfied:i)
ç issingularity free,
i.e.0 ~
Im(~);
ii)
99 is acompact
vectorfield,
that is= x -.~(~),
where -oEis a
compact
multivalued map(Im (.I’)
iscompact);
iii) gg(x)
iscompact
andacyclic
for every x E F.We want to define a
function y (called characteristic)
from the set 0of all admissible vector fields into
Z2
with thefollowing properties:
1)
Normalization :,y(-r) = 1,
where is theinclusion;
2) Homotopy :
if 990 and qi arehomotopic (in
a sense that will be definedlater)
then =3) Solvability:
ify(c~) ~
0 then 99 isessential,
i.e. it does not admitan admissible extension to the closed unit ball D of
E;
4) Antipodality :
if9?(x) ==-p(-x)
for all x E S thenx(cp)
= 1.The
problem
ofdefining
a characteristic for admissible vector fields waspreviously
studiedby
A. Granas - J. W. Jaworowski[9]
and S. Williams[13].
The characteristic of A. Granas - J. W. Jaworowski satisfies all of the above
properties
but thespace E
considered is finite dimensional. S. Williams removed the condition that .E is finite dimensional but obtainedonly
theproperties
2 and 3.(*)
Istituto Matematico « U. Dini >>, VialeMorgagni 67/A,
Firenze.Pervenuto alla Redazione il 22 Febbraio 1974.
We would like to recall that A. Granas
[7]
obtained acharacteristic, satisfying
all theproperties
for convex valued admissible vector fields defined in a nonnecessarily
finite dimensional Banach space.2. - Notations and definitions.
Throughout
this paper we use the reducedv’ietoris-Cech homology theory
withcompact
carriers and coefficients inZ2 (see [6]).
We denoteby A)
thep-th homology
group of thetopological pair (X, A)
and wesay that X is
acyclic
if =0)
= 0 for everyinteger
p.Two admissible vector fields 990 and ~1
(see Introduction)
are said to behomotopic,
if there exists an upper semicontinuouscompact
multi-valued
map H: S X I -oE,
where I is the unit interval[0, 1],
with the fol-lowing properties:
a) H, :
S -oE definedby Ha(x)
=H(x, t)
is an admissible vector field for everyt E I ;
Such a map is called an admissible
homotopy joining
cpo and ~1.We shall use
frequently
the well-knownVIETORIS MAPPING THEOREM
(see [1]).
Let X and Y becompact
metricspaces and
f :
X --~. Y be continuous and such that1-1(y)
isacyclic for
every y E Y(i.e. f
is inverseacyclic).
Thenf*:
is a~aisomorphism for all p.
3. - The definition of characteristic.
Let 99: S -oE be an admissible vector field and denote
by
.F’ itscompact part,
PutQ(99)
=(p(S))
=inf {lly JJ
: y E Ob-viously e(qJ)
> 0 sinceqJ(S)
is closed and0 w
Let p :I’(~S) -~
.~ be amap such that Im
(p )
is contained in a finite dimensionalsubspace
of Eand for all that is p is a finite dimensional
e(cp)-approsimation
of the inclusioni : F(,) .E.
The existence of such amap is ensured
by
thecompactness
ofF(S) (see [8]).
LetEn+1:J 1m (p)
anddenote
by T’n
thegraf
ofFjsn (Sn
= S f1E,,,,).
We definep : 1"~ --j.
Eby p(x, y) =~2013p(~/).
We shall prove that and sop
inducesa map
303 Since the
projection
yr: Sn(defined by n(x, y)
=x)
is inverseacyclic, by
VietorisMapping
Theorem we have Therefore~,~
is eitheran
isomorphism
or the zero map. Weput
p,En+1)
= 1 in the firstcase and p,
En+1)
= 0 in the second one. We shall prove that p,En+1)
is
independent
of Im(p)
and p. This allows us to define a character- isticx(q) of q by putting x(q)
=X(99,
p,En+1)
where p is anarbitrary
finitedimensional
e(q)-approximation
of the inclusion i:F(S)
E andWe need some
preliminary
Lemmas.LEMMA 1..Let above. Then
PROOF.
Clearly p(.T’n)
cEn+1.
Moreoverp(x, y)
=x -p(y) = (x
-y) + + (y -p(y))-
But(since (x-y)
and~~ C Q(99).
Therefore
0 0 p (r,,,). Q.E.D.
LEMMA 2. Let
(X, A)
and(Y, B)
becompact
metricpairs
and letf : (X, A) - ( Y, B)
be an inverseacyclic
map such thatf -1(B)
= A. Thenis an
isomorphism for
all p.PROOF. Consider the
following
commutativediagram
where f’ and f"
are the maps definedby f.
Sinceby
VietorisMapping
Theoremthe
maps fl and fl
areisomorphisms
the Five Lemmaimplies that f*
is anisomorphism. Q.E.D.
Let
En
CEz+i
be twosubspaces
of E with dimensions n and n+
1 re-spectively.
CallE:+1
and the two closedhalf spaces
ofEzi
such thatEn
=E:+1
n andput S)
=E +1
and~
_ ~S’.Clearly
~Sn = S nS+
USl
andn En = ~S+
n Denoteby rn, rn-1
thegraphs
ofFjSn, respectively.
We
T’n
U andrn-1
=r)
nLEMMA 3.
1~~ ,
propertopological
triad and theMayer-Vietoris
map L1: -~. an
isomorphism.
PROOF. Let us show first that
7~ ~
is a propertopological triad,
i.e. the inclusions
are excisions. Consider the
following
commutativediagram:
where n’ and are the maps defined
by
the andi :
(8n, Sn-1)
~ is the inclusion.By
Lemma 2n; and ;rff
areisomorphisms. Therefore i*
is anisomorphism since,
as it isknown,
y 7: is an excision. Theproof for j
is similar.Consider now the
Mayer-Vietoris
sequence ofr.+, r:;) :
Since
by
VietorisMapping
Theorem and areacyclic
it follows that 4is an
isomorphism. Q.E.D.
In the
following
twoPropositions
we prove thatEn)
is inde-pendent
of and p.PROPOSITION 1.
X(99,
p,En)
isindependent of
thefinite
dimensional sub- spaceIm ( p ) .
PROOF. It is
enough
to prove that p,En+1)
=En)
where.En
c * LetP,: h’n
- andP": .I-’n_1
- be the two maps definedby
p. Thefollowing diagram
is commutativeby
thenaturality
ofMayer-Vietoris
map L1:It is known that the bottom arrow is an
isomorphism.
The same is truefor the
top
oneby
Lemma 3. Thus theProposition
isproved. Q.E.D.
According
toProposition
1 we can define now z= p,En)
whereEn
is any finite dimensional
subspace
of Econtaining Im(p ) .
PROPOSITION 2..Let po and P1 be two
finite
dimensional tionsof
i :F(S)
- E.Then
Po)
=X((p, P1).
305
PROOF. For any
e[0y 1]
define(1 - t)p,(y) + tp1(y).
Since there existsEn+1 containing Im(po)
andIm( pi )
we haveIm(pt)
c for any tc [0, 1].
It is easy to see that pi
is
ae(q)-approximation
of Thusby
Lemma 1 the map
pt(x, y) = x - pt(y)
is such that0 ~ Im( pt)
for all t E[0, 1].
Therefore is
a homotopy from Tn
intojoining
po and FrQ.E.D.
Let 99
be an admissible vector field. We define its characteristic:where p
is a finite dimensionale((}?)-approximation
of andIm(p).
The above twoPropositions
insure thatX(99)
is well defined.4. - The four
properties
of the characteristic.In this section we shall prove that our definition of the characteristic of an admissible vector field satisfies the four
properties
we have mentionedin the Introduction.
THEOREM 1 be the inclusion. Then
z(i)
= 1.PROOF. It is trivial.
Q.E.D.
THEOREM 2
(Homotopy). Let qo
and be twohomotopic
admissible vectorfields.
Then =x(cp1).
PROOF. Let H: ,S X I -o .E be an admissible
homotopy joining
andDenote
by Fi: S-o E
the =t),
where .F’ is thecompact part
of H(i.e. t)
=x - H(x, t)).
Let p :Im(.F’) -~. _E
be a finite dimen- sionalQ(99) -approximation
of i : -> E and takeEn+1:) Im( p) .
Denoteby Tn,
thegraphs
of andF1/Sn respectively.
Consider the
following diagram:
where
p(x, t, y) = x --~(y)
andj°(x, y) = (x~ 0, y), y) _ (x~ 1, y).
Clearly
the characteristic ofk = 0, 1,
is definedby
thecomposite
map
p*oj:;
in other wordsZ(99k)
==1 if is anisomorphism
andX(99k)
= 0otherwise. Therefore the Theorem is
proved
if we showthat j* and j*
areisomorphisms.
Consider the
following
commutativediagram:
where
y)
= x,y) = (z, t)
andq(x, t)
= x.By
VietorisMapping
Theorem a., and q* are
isomorphisms,
therefore alsoj*
is anisomorphism.
Q.E.D.
Let cp : S -o E be an admissible vector field.
By
an admissible extensionof q
we mean a multivaluedmap 99
from the closed unit ball D of E into E such that:is
singularity free;
ii) §5(z)
=x-F(x),
where.F:
D ---o E is acompact
multivalued map;iii) §5(z)
iscompact
andacyclic
for everyiv)
= ~p.We shal
call 99
inessential if it admits an admissible extension and essential otherwise(see [8]).
THEOREM 3 an admissible vector
field.
Thenif X(99) 0,
cp is essential.PROOF. Assume
that 99
is inessential. We shall prove thatX(99)
= 0. Con-sider an admissible
extension §5
of 99. Let p be a finite dimensionale(§5)- approximation
of i :F(D)
- E andIm( p).
Denoteby f’n
andTn
thegraphs
ofØ/Dn+1
andrespectively,
where D andWe have the
following
commutativediagram:
where j
is the inclusion ofBy
307
Vietoris
Mapping
Theorem isacyclic.
So~~~
which defines the character- istic of g~, is the zero map. Thereforex(q)
= 0.Q.E.D.
We recall that a multivalued map
p:8-oE
is odd iffor any x E S. In order to prove that the characteristic of an odd admissible vector field is one we need the
following
result due to J. W. Jaworowski[11].
Let X be a metrie space such that
Ñj)(X) = 0 i f 0 c p c n -1
andZ2 .
Let 6: X - X be a continuous involution
(i.e. or - a
is theidentity
onX)
and~ f : X -~. ~S~a a
continuous map such thatfor
any Thenan
isomorphism.
THEOREM 4
(Antipodality)
Letp: S -0 E be
an odd admissible vectorfield.
ThenX(99)
= 1.PROOF. Let q:
F(8) -+E
be a finite dimensionale (99) -approximation
ofi :
F(S)
- E andEn+1:J Im(q).
SinceF(S)
issymmetric
withrespect
to theorigin
we can definep (y) = (q(y)-q(-y))j2
for anyYEF(S).
It is easyto see that
p (y) == - p (- y),
andLet
hn and p
be as usual. Since F is odd we can define an involution (1on
Tn by o-(~)=(2013~2013~).
We have.P(o’(~~))=~(2013~2013~)==2013~+
+
x -p{y) = p(x, y).
Thenby
Jaworowski’s Theoremp*
is an iso-morphism. Q.E.D.
5. - Some consequences.
In this section we
give
someapplications
of the characteristic. In par- ticular wegive
a version of theSweeping
Theorem and we extend toacyclic
valued maps the Theorems of
Birkoff-Kellogg [3]
and Rothe[12].
We need the
following
Lemma.LEMMA 4. The characteristic
of
the admissible vectorfield cp(x)
= x - Xo,one
if
and zero otherwise.PROOF. If then defines a
homotopy
betweenthe inclusion z : S ~ .E and 99. Thus
x(q)
= 1by
Theorems 1 and 2.If
~~ >
1 the map§3 : D
-* E definedby §3(r)
= x - xo is an admissibleextension of g~. Then = 0
by
Theorem 3.Q.E.D.
We remark that two admissible vector fields of the form
qo(z)
= x - xoand
p¡(x) == x - Xl
have the same characteristic if andonly
if x,,and x, belong
to the samecomponent
ofEBS.
Let be an upper semicontinuous
compact acyclic
valuedmap. Define E
by P(x, t)
=x - F(x, t)
andput yi(r)
=P(x, t).
THEOREM 5
(On
theSweeping).
Let 1Jf be as above and assume that"Po(x)
= x.If
x,belong
todifferent components of
and to the samecomponent of
then either Xo EIm(1Jf)
or x, EIm(Vf).
PROOF. Assume that xo,
x, 0 lm(T).
We shall prove that ifthey belong
to the same
component
of thenthey belong
to the samecomponent
of.EB~S.
Since is closed we can find a continuous map a: such that
a(0)
= x, anda(1 )
= xl. DefineY 1 , , / 1 w Ill
Clearly
03C30 (]o (] 1 and (] 1 .Moreover 1= a and
60 = al.
Therefore Sinceand
J)(z)
= x - xl it follows that Xlbelong
to the samecomponent
ofby
Lemma 4.Q.E.D.
COROLLARY 1. Let as in Theorem 5.
If belongs
to the unbounded
component of
and thenY E Im(1Jf).
PROOF. There exists such that
lBz!1 > 1,
and zbelongs
to the unbounded
component
of It followsthat y
and zbelong
todifferent
components
of and to the samecomponent
ofTherefore
by
Theorem 5Q.E.D.
Let .F : S -0 E be an upper semicontinuous
compact acyclic
valued map.We shall say that .F has an invariant direction if the
equation
x eÂF(x)
has a solution for some £ > 0 and 1t e S.
We
give
now a multivalued version of theBirkofi-Kellogg
Theorem[3].
THEOREM 6. Let .F : S -o E be as above. Assume that .E is
infinite
sional and Then F has an invariant direction.
PROOF. Define
~~(x) = x - ~,.I’(x).
We want to prove that0 E g~~(S)
forsome
~.>
0. Since zerobelongs
to the boundedcomponent
ofEES
it isenough
toshow, by Corollary 1,
that there exists£o > 0
such that zerobelongs
to the unboundedcomponent
of We shall prove in fact that there exists~.o >
0 and such that the half line00}
does not intersect
309
Let defined
by n(x)
=By assumption F(S)
is acompact
subset of son(F(S)) c S
iscompact. Therefore,
sincedim E =
+
00, there existsxo c- 8
such that It follows that== 0. Since is an open
neighborhood
of the com-pact
set2013~(~)
there exists 8 > 0 such thatB(- F(S), E)
_0,
wherethere such
Let
Åo
be such that Since we haven
B(-
= 0. But ~S’ - cB(- Âoe)
and so0.
"
Q.E.D.
By
apositive
cone in a Banachspace E
we mean a convex subsetQ
of Esuch that
Q
n~- Q~ _ 101
and2Q
=Q
for every 1 > 0.THEOREM 7. Let F : S r’1
Q
-oQ
be an upper semicontinuouscompact acyclic
valued map. Assume that E is
infinite
dimensional and0 ~ F(Q).
Then Fhas an invariant direction.
PROOF. The set 8
n Q
is anAR,
since it is a retract of the convex setQE(0) (see [10]).
Therefore there exists a retraction r: S - S nQ.
Considerthe map and
apply
Theorem 6.Q.E.D.
We remark that the above result could be
proved, using
theEilenberg- Montgomery
Theorem[5],
also in the finite dimensional case sinceQBB(0, s)
is an AR for every s > 0.
The
following
result is an extension of the well-known Rothe’s The-orem
[12].
THEOREM 8. Let F: D -o E be an upper semicontinitous
compact acyclic
valued map such that and 2 > 1
implies 2x 0 F(x) .
Then F has afixed point.
PROOF. We can assume that F is fixed
point
free on S. The two ad-missible vector fields
qo(z)
_ ~ andP1(X) = x - .~’(x)
arehomotopic
via theE defined
by O(x, t) = x - t-I’(x) .
Infact,
XES and0 C t C 1
implies
and so0~2013~(~).
Therefore is essentialsince
X(99,,) =
1.Q.E.D.
COROLLARY 2
(Eilenberg-Montgomery [5]).
Let X be acompact
metric ARand X be an upper semicontinuous
acyclic
valued map. Then F hasa
fixed point.
PROOF.
By
a well-known result of Kuratowski(see [4])
we canregard X
as a closed subset of a Banach space E. Since X is an AR there exists a
retraction ~:jE7->~. Let
~O > 0
be such thatX c De
whereSince
by
Theorem 8 For has a fixedpoint
x.On the other hand x must
belong
to X and so it is a fixedpoint
of F.Q.E.D.
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