A NNALES MATHÉMATIQUES B LAISE P ASCAL
J ERZY K AKOL ˛
The Mackey-Arens and Hahn-Banach theorems for spaces over valued fields
Annales mathématiques Blaise Pascal, tome 2, n
o1 (1995), p. 147-153
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THE MACKEY-ARENS AND HAHN-BANACH THEOREMS
FOR SPACES OVER VALUED FIELDS
Jerzy K0105kol
Astract. Characterizations of the
spherical completeness
of a non-archimedeancomplete non-trivially
valued field in terms of classical theorems of FunctionalAnalysis
are obtained.1991 Mathematics
subject classification: : ,~651 D Spherical completeness
Throughout
thispaper K
=(h’, ( ))
will denote a non-archimedeancomplete
valuedfield with a
non-trivial valuation (
.I.
It is well-known that the absolute value functionI . |
of the field of the real numbers IR or thecomplex
numbers. C satisfiesthe following properties :
(i)
0H, |x| = 0 iff x = 0, (ii) |x
+|x|
+|y|,
(iii) |xy|
=|x||y|,
x, y E IR or x, y ~C.If K is a
field,
thenby
a valuation on K we will mean amap | . |
of K into 1R,satisfying
the above
properties;
in this case(.K, ~ .
.))
will be called a valuedfield.
We will assumethat K is
complete
withrespect
to the natural metric of K.It turns out that if K is not
isomorphic
to IRor C,
then its valuation satisfies thefollowing
strongtriangle inequality,
cf. e.g.[12], (ii’) I x
+max{|x|,|y|},
x, y E K.A valued field K whose valuation satisfies
(ii’)
will be called non- archimedean and its valuation non-archimedean.Let us first recall the
following
well-known result of CantorTheorem 0 Let
(X, p)
be a metric space. Then it iscomplete iff every shrinking
s equenceof
closed balls whose radii tend to zero hasnon-empty
intersection.148
Consider the set IN of the natural numbers endowed with the
following metric p
definedby p(m, n)
= 0 if m = n and 1 +max(~, ~)
ifm ~
n.Then the metric p is
non-archimedean,
i.e.p(m, n)
= 0 iff either m = n, orp(m, n)
for allm, n, k
E IN.It is easy to see that every
shrinking
sequence of balls in IN whose radii tend to zerohas
non-empty intersection;
note that every ball whose radius is smaller than 1 containsexactly
onepoint.
On the otherhand,
the ballsBl+ i ( 1), Bl+ z (2),
..., form adecreasing
sequence and their intersection is
empty.
Thissuggests
thefollowing,
seeIngleton [3] :
A non-archimedean metric space
(X, p)
will be said to bespherically complete
if theintersection of every
shrinking
sequence of its balls isnon-empty.
Clearly spherical completeness implies completeness;
the converse fails : The space(N, p)
iscomplete
but notspherically complete.
We refer to[11]
and[12]
for more info-mation
concerning
this property.Theorem 1 Let
(X, p)
be a non-archimedean metric space. Then(X, p)
isspherically complete iff given an arbitrary family
Bof
balls inX,
no twoof
which aredisjoint,
thenthe intersection
of
the elementsof
B isnon-empty.
The aim of this note is to collect a few characterizations of the
spherical completeness
of K in terms of the
Mackey-Arens,
Hahn-Banach and weak Schauder basistheorems, respectively,
see[5], [6], [7], [12].
The
Mackey-Arens
and Hahn-Banach theoremsThe terms " K-space" , "topology","seminorm
or norm" will mean a Hausdorfflocally
convex space
(lcs)
overK,
alocally
convextopology (in
the sense ofMonna)
and a non-archimedean seminorm
(norm), respectively
A seminorm on a vectorspace E
over K isnon-archimedean if it satisfies condition
(ii’). Clearly
thetopology T generated by
a normis
locally
convex. . Recall that atopological
vector space(tvs)
E ={E, T)
over K islocally
co~ve~
[10]
if T has a basis ofabsolutely
convexneighbourhoods
of zero. A subset U of E isabsolutely
convex(in
the sense of Monna[10])
if ax +,Qy
EU,
whenever x, y EU,
E,
1, |03B2|
1. For the basic notions andproperties concerning
tvs and lcs overK we refer to
[10], [11], [13].
A
locally
convex(lc) topology,
on(E, T)
is calledcompatible
with T, if T and ~y have the same continuous linearfunctionals; {E, T)*
=(E, ~y)*. (E, T)
isdual-separating
if
(E, T)* separates points
of E. If G is a vectorsubspace
ofE, ?~G
andT IG
denotethe
topology
T restricted to G and thequotient topology
of thequotient
spaceE/G, respectively.
If a is a finer l.c.topology
onE/G,
we denoteby y
:= T V a the weakestI.e.
topology
on E such that T q, = a,y~G
=T~G,
cf. e.g.[1].
The setsU n compose a basis of
neighbourhoods
of zero for q, whereU,
V run over basesof
neighbourhoods
of zero for T and a,respectively, q
:=EE/G
is thequotient
map.By
sup{, a}
we denote the weakest l.c.topology
on E which is finer than T and a.By
theMackey topology p.( E, E*)
associated with a lcs E =(E, T)
we mean the finestlocally
convextopology
on Ecompatible
with T. In[14]
Van Tiel showed that every lcsover
spherically complete
K admits theMackey topology.
In
(3j Ingleton
obtained a non-archimedean variant of the Hahn-Banach theorem for normed spaces, where K isspherically complete.
Theorem 2
If
E =(E, ~~)
as a normed space over K and K isspherically complete
and D is a
subspace of E,
thenfor
every continuous linearfunctional
g E D* there existsa continuous linear extension
f
E E*of
g such that =~f~.
This
suggests
thefollowing :
A lcs E will be said to have the Hahn-Banach ExtensionProperty (HBEP) [9]
if for everysubspace
D every g E D* can be extended tof
E E*. Itis known that every lcs over
spherically complete
K has theHBEP,
cf. e.g.~11~.
The
following
theorem characterizes thespherical completeness
of K in terms of clas-sical theorems of Functional
Analysis;
cf. also[5], [6]
and[12],
Theorem 4.I5. Theproof
of our Theorem 3 uses some ideas of
[4]
extended to the non-archimedean case.I°°
(resp. co)
denotes the space of the bounded sequences( resp.
the sequences oflimit 0}
with coefficients in Ii’.Theorem 3 The
following
conditions on K areequivalent : (i)
K isspherically complete.
(ii)
There exists g E(l°°)*
such thatg(x)
=~n
xnfor
every x E co.(iii) (I°°/co)* ~
0.(iv) Every
lcs over K admits theMackey topology.
(v) Every
Ics over K(resp.
K .normedspace~
has the HBEP.(vi)
Thecompletion of
adual-separating
lcs over K(resp.
K -normedspace)
is dual.separating.
(vii) Every
closedsubspace of
adual-separating
lcs over K(resp.
K-normedspace~
isweakly
closed.(viii)
For every lcs over K(resp.
K -normedspace )
everyweakly convergent
sequence isconvergent.
(ix) Every
weak Schauder basis in a lcs over K(resp.
K-normedspace)
is a Schauderbasis.
Proof
By
Theorem 4.15 of[12]
conditions(i), (ii}, (iii)
areequivalent. (i) implies (iv) : [14],
Theorem 4.17.(i) implies (v) :
:~3~, [11].
Theimplications (v) implies (vi), (v) implies (vii)
are obvious.(i) implies (viii) :
see~7~;
Theorem3, (2~, Proposition
4.3.(viii) implies (ix)
is obvious.(iv) implies {i)
: Assume that K is notspherically complete
and consider the space l~ of K-valued bounded sequences endowed with thetopology
Tgenerated by
the norm= supn x =
(xn)
E l~. Letf
be a non-zero linear function on I°° withf |c0
= o.Set E := I°° and F := co. Define a linear functional h on the
quotient
spaceE/F by
h(q(x))
=f {x),
where q : E -+E/F
is thequotient
map. Let a be thequotient topology
150
of
E/F.
Since(E/F, a)*
=0,
see(iii) implies (i),
F is dense in the weaktopology o(E, E*) (recall
that E* =F, [12],
Theorem4.17).
Observe that onE/F
there exists a K-normedtopology /3
such that(E/F, a)
and(E/F,,Q)
areisomorphic
and h is continuous in thetopology sup{ a, ~3~. Indeed,
choose a-o EE/F
such thath(xo)
= 2 and define a linear map T :: E/F --~ E/F by T(x) := x - h(x)xQ,
x EE/F.
ThenT~
= id. Define,Q :; T{a) (the image topology).
Then h is continuous in thetopology sup{03B1,03B2}.
Set 03B303B1 :=
7(E, E*)
V a, 03B303B2 :=E*)
Va. Then ya and 03B303B2
arecompatible
with
o(E, E*),
hence with T. Assume that E admits the finestlocally
convextopology
~ucompatible
with T. Theno(E, E*)
.On the other hand =
sup { a, ~3?.
Thereforef
is continuous in Sincef
is not continuous ino(E, E*)
weget
a contradiction. Theproof
iscomplete.
(vi) implies (i)
: Assume that K is notspherically complete. By
the Bairecategory
theorem we find a densesubspace
G of E withdim(E/G)=dim(E/F),
where E and F aredefined as above.
Indeed,
let be a Hamel basis of E and(Sn)
apartition
of Ssuch that S =
U Sn
and cardSn=card S, n
E IN.n~IN
For every n E
IN ,
we denoteby Gn
the vector spacegenerated by
theelements
whenn
s runs in
U Sk.
Then we have E =U Gn
and dimGn
= dim(E/Gn)
= dimE, n
E IN.k=1 n~IN
Then there exists m E N such that
Gm
is dense in E. Hence we obtain asubspace
Gas
required.
Let a be a K-normedtopology
onE/G
such that the spaces(E/G, a)
and(E/F, T~F)
areisomorphic.
Then thetopology,
:= T V a iscompatible
with T andstrictly
finer than T. LetEo
be thecompletion
of thedual-separating
K-normed space(E, ~).
Choose x EEoBE.
There exists a sequence(xn)
in E and y E E such that xin
Eo
and in(E, T).
Thenf (x - y)
= 0 for allfEE;
but x -~/ ~
0. Thiscompletes
theproof.
(vii) implies (i)
: Assume that K is notspherically complete.
The space G constructed in theprevious
case is closed in(E, ~y)
and dense in(E, o(E, E*)),
where E* :=(E, ~y)*.
(v) implies (i)
: Assume that K is notspherically complete.
Let(en)
be the sequenceof the unit vectors in
E,
where E is as above. Then en --~ 0 ino(E, E*), [13]. Clearly (en)
is a normalized Schauder basis in F. If x = EF,
then x =03A3n
xnen. Setg(x)
:=03A3n
xn. Then g is a well-defined continuous linear functional on F.Suppose
thatg has a continuous linear extension
f
to the whole space E. Thenf (en)
--~ 0 butg(en)
=1for all n E
IN,
a contradiction.(viii) implies (i) :
: See theproof
of theprevious implication.
(ix) implies ( i )
: Assume that K is notspherically complete.
The sequence( e n )
is aSchauder basis in
(E, o(E, E*))
but it is not a Schauder basis in theoriginal topology
ofE. The second
part
of this sentence follows from the fact that E is not of countabletype,
cf. e.g.[12].
On the otherhand, by
Theorem 4.17 of[12] (and
itsproof)
the space E isreflexive and for every g E E* there exists
(an)
E F such thatg( x) = En
xnan for everyx =
(xn)
E E. Since( E, ~( E, E* ) )
is asequentially complete
lcs[12],
Theorem9.6,
thenZkek
weakly
converges to x =(xn).
Remark In
[9]
Martinez-Maurica and Perez-Garciaproved
that whenever K isspher- ically complete,
then the localconvexity
is a three spaceproperty
i.e. if E is an A-Banachtvs over K and F its
subspace
such that F andE/F
arelocally
convex, then E islocally
convex. Is the converse also true?
By L(E, F)
we denote the space of all continuous linear maps between lcs E and F.A
topology
a on E will be calledcompatible
with thepair (E, L(E, F))
ifL({E, a), F)
=L(E, F);
if F =, as usual we shall say that a iscompatible
with the dualpair (E, E*),
where E* :=
L(E, K).
A lcs space F will be said to have the
Mackey-Arens property (MA-property)
if forevery lcs space E the finest
topology p.(E, L(E, F)) compatible
with(E, L(E, F)) exists,
~’7~ .
As we have
already
mentioned Van Tiel[14] proved
that if K isspherically complete,
then K has the
MA-property,
i.e. everyK-space
E overspherically complete
K admits thefinest
topology E*) compatible
with the dualpair (E, E*).
We havealready proved
the converse : If K is not
spherically complete,
then .~°° does not admit theMackey topology (l~, (.2°° ) * ).
HenceCorollary
K isspherically complete iff
it has theMA-property.
On the other hand one has the
following
Theorem 4
Every spherically complete
normedK-space
F =(F, ~.~)
has the MA-property.
We shall need the
following
Lemma 1 Let
E,
F be two vector spaces overK,
where F is endowed with a norm~~.~~
and p, q are seminorms on E. Let T E --~ F be a linear map such thatmax{p{x}, q(x)). If
F isspherically complete,
then there exists two linear mapsT=
: E ~F,
i =
1,2,
such that T =Ti
+T2
andP(x)~ q(x),
x E E.Proof Set
P(x, x)
=T(x), U(x,y)
= x, y E E. ThenU(x,y)
is aseminorm on E x E and = =
U(x,x).
Since F isspherically complete,
thenby Ingleton theorem,
cf. e.g.[6],
Theorem4.18,
there exists a linear mapPo :
E x E ~ Fextending
P such that~(P0(x,y))~ U(x, y),
x, y E E. Tocomplete
theproof
it isenough
toput Tl (x)
=Po(x, 0), T2(x)
=P0(0, x).
We shall also need the
following
lemma. Itsproof
uses some ideas of[1]
and[4].
.Lemma 2 Let
E,
F be twodual-separating K-spaces
overnon-spherically complete
Kand such that F is
complete
and E is aninfinite
dimensional metrizable andcomplete.
Then E admits two
topologies
T~ and T2strictly finer
than theoriginal
oneof
E and com-patible
with thepair (E, L(E, F))
and such that thetopology sup{1, 2}
is notcompatible
with
{E, L{E, F)).
152
Proof : Observe that E contains a dense
subspace
G withdim(E/G)=dim(l~/c0).
Leth be a non-zero linear functional on E
vanishing
on G. As above we construct on E twotopologies
r~ and r2strictly
finer than theoriginal
one r of E such that Tj~G
=r~G
and
(E/G, j/G)
isisomorphic
to thequotient
spacel~/c0, j = 1, 2,
and h is continuousin
sup{1, 2}.
We show that thetopologies ij, j
=1, 2,
arecompatible
with thepair (E, L(E, F)). Fix j
E{1, 2}
and non-zero T EL((E, rj), F).
There exists xo E E andf
E F* such that 0.Suppose
thatT~G
={o}.
Then the mapq(x)
-->f(Tx))
defines a non-zero continuous linear functional on
(E/G, rj/G),
q : E -~E/G
is thequotient
map. Since(I°°~c4)* ={0}, [12], Corollary 4.3,
weget
a contradiction. HenceT~G
is non-zero. Since G is dense in E and r and r~ coincide on
G,
there exists a continuous linear extension W of T to E. It is easy to see that T = W. . Hence T eL(E, F). Finally
the map x ~
h(x)y,
for fixed y EF,
defines a T-discontinuous linear map H of E into F such that H EL((E, sup Tl, T2), F).
.Proof of Theorem 4 Let E =
(E, r)
be a lcs and F thefamily
of alltopologies
on Ecompatible
with(E, L(E, F)).
It isenough
to show that thetopology
~c :=supF belongs
to F. Let T :
(E, )
-+ F be a continuous linear map. There exist seminorms pj onE, j =1, ... ,
n, continuous intopologies (/j
E,~’), respectively,
and M > 0 such that M maxpj(x)
for every x E E.Using
Lemma 1 one shows that T is r-continuous.1~j~n
Remarks
(1)
There existcomplete
normedK-spaces having
theMA-property
whichare not
spherically complete.
Infact,
assume that K isspherically complete;
then .~°° isspherically complete [12] ,
p.97;
hence ~°° has theMA-property (by
our Theorem4).
Onthe other hand there exists on the space ~°° another norm v which is
equivalent
with theusual norm, such that
(~°°, v)
is notspherically complete [12],
p. 50 and p. 98. On the other hand the space(e°°, v)
has theMA-property.
(2)
Let E be an infinite dimensional normed andcomplete K-space.
Since F :=03A0n En/ ~n En,
whereEn
= E for every n EIN,
isspherically complete
for any K[12],
Theorem
4.1,
thenby
our Theorem 4 the space F has theMA-property.
For concrete spacesput
E = then F = If K is notspherically complete,
thenby
Lemma 2 the space l~ does not admit theMackey topology
butl~/c0
has theMA-property.
Inparticular
there exists on e°° the finesttopology p compatible
with(~°°,
(3)
Let E and F beA’-spaces
and assume that E admits theMackey topology p
=E*).
Then the finesttopology
on Ecompatible
with((E, ~z), L((E, ~), F))
exists andequals
~c.(4)
In[13], Corollary 7.9,
Schikhofproved
that forpolarly
barrelled orpolarly bornolog-
ical
K-spaces (E, r)
where K is notspherically complete,
the finestpolar topology E*)
compatible
with(E, E*)
exists andequals
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