A NNALES DE L ’I. H. P., SECTION B
A NTOINE B RUNEL
S HLOMO H OROWITZ
M ICHAEL L IN
On subinvariant measures for positive operators in L1
Annales de l’I. H. P., section B, tome 29, n
o1 (1993), p. 105-117
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
105
On subinvariant
measuresfor positive operators in L1
Antoine BRUNEL
Universite de Paris-VI, 4, place Jussieu, 75252 Paris, France Shlomo HOROWITZ
(1)
Tel-Aviv University, Tel-Aviv, Israel
Michael LIN
Ben-Gurion University of the Negev, Beer-Sheva, Israel
Vol. 29, n° 1, 1993, p. -117. Probabilités et Statistiques
ABSTRACT. - We
study
theproblem
of existence of astrictly positive
invariant element for a
positive operator
T onL1,
and show itsequivalence
with a ratio limit theorem for T*.
THEOREM A. - Let T be a
positive
operator onL1 satisfying (*)
For there existsv E L
with0~v=T**v and v (f) > o.
00
Then there exists
uELi,
u>O a. e. and IfL T*nl=oo,
thenM=0
T u = u,
and(*)
is also a necessary condition.THEOREM B. - Let T be a Cesàro-bounded
positive
operator inL1.
Then(*) is equivalent
to(I - T*) Loo n L~ _ ~ 0 }.
RESUME. 2014 Nous étudions le
problème
de 1’existence d’un element strictementpositif
et sous-invariant pour unopérateur positif
T surL1,
etdémontrons
1’equivalence
avec un théorème limitequotient
pour T*.(~)
This research was started by the first two authors twenty years ago, but for variousreasons was not completed prior to Shlomo Horowitz’s untimely death in 1978. The other authors dedicate this paper to his memory.
Annales de l’Institut Henri Poincaré - Probabilités et Statistiques - 0246-0203
THEOREME A. - Soit T un
opérateur positif
surL1, satisfaisant
lacondition
(*)
Pour toute il existe v EL~ satisfaisant
0 ~ v = T** v etv(/)>0.
00
Alors il existe u > 0 p. p. ~ Si
L
ona T u = u,
n= o
’
et la condition
(*)
est aussi nécessaire.THEOREME B. - Soit T un
opérateur positif
Cesaro-borne dansLl.
Alors(*)
estéquivalente à (I - T*) L~ n L~ = {0}.
Birkhoff’s individual
ergodic
theorem wasoriginally proved
for measurepreserving transformations,
and thestudy
of necessary and sufficient conditions for the existence of anequivalent
finite invariant measure was soon startedby
E.Hopf
in 1932. Thestudy
continued later asfinding strictly positive
functions inL1 (m),
invariant under agiven positive
con-traction
T,
and it turned out that the conditions are in terms of the dualoperator
T*. See[K],
pp.142-145,
for the results and historical remarks.One of the necessary and sufficient
conditions, introduced by
Brunel is
(I - T*) Loo (~ L ) = ( 0 }.
Horowitz[H]
gave aproof
of suffi-ciency
withoutusing weakly wandering
functions.Sucheston
[S]
started thestudy
ofpower-bounded positive operators
inL1.
The ratio limit theorem for suchoperators
was studied in[I-Mo].
Derriennic and
Lin [DL]
extended Sucheston’sdecomposition
to Cesàrobounded
(sup~ B n Mn
oo, where Mn (T)=1n-103A3Tk)
n k=o Tk / positive operators
on
L 1 (m),
and obtained some necessary and sufficient conditions for the existence of u > 0 a. e., with T u = u. Some of these conditions wereextended to Banach
lattices;
for the latest results andreferences,
see[BS].
Sato
[Sa] proved
that for a Cesàro boundedpositive operator
onL 1 (m),
a. e. convergence of
M~(T*) f
for everyf E Loo
isequivalent
to theL1-norm
convergence ofMn (T) v
for everyv E L1. If,
in that case,lim
M" (T*) 1 ~ 0,
we have non-zeropositive
fixedpoints (invariant
meas-ures)
for T. If there existsu E L i
with u > 0 a. e. andT u u,
thenMn (T*) f
converges a. e. for every
(or
evenOrnstein
[0] studied,
for abstractpositive operators, the relationship
between invariant measures and the ratio limit
theorem, using
amethod
of "modifications"
(see
alsoThe
following proposition
follows from ideas in[0].
PROPOSITION 1. - Let T be a
positive operator
onL1 (X, £, m).
Thenthe
following
areequivalent:
.(i)
There existsu~L+1 (m),
u > 0 a.e.and T u~u.
n n
(ii)
For everyf,
g eL) (m),
the ratios£ T" f (x)/ £ T" g(x)
convergek = o
(to
afinite limit)
a. e. on the setS,= ..
x:03A3~k=0T*kg(x)>0},
and00
Furthermore, if (ii ) [or (i )]
issatisfied
and~, T*A; 1
= 00 ~. e., then wehave T u = u.
Proof. - (i)=>(ii).
T* is a contraction of and the Chacon- Ornstein theorem and lemmaapply.
(ii ) =>(i). By (ii ), lim 03A3nn~~ k=0 T*k f/ 03A3nk=0 T*k
1 exists a. e., andfor f~0
thelimit must be
positive
a. e. onSf={03A3~ T*k f>0}.
we may and do assumex=o
oJ
m finite. Define for
f
bounded measurablewhich exists
by
the dominated convergence theorem. is a measuren
by
theVitali-Hahn-Saks
theorem. NowT*"~~T~1 ~~T~/~j~.
t=0
LEMMA 2. - Let X be a
compact Hausdorff
space, and thea-algebra of
Baire sets. LetQ
be apositive operator
on C(X).
(i)
There exists a transition measureQ (x, A)
on X X ~ such thatQ f (x) = dy)
extendsQ
toB (X, ~).
(ii) satisfies
thenQ
can be extended toa linear contraction S
of L1 (X, ~, v).
Proof. - (i)
is a standard result:Q (x, A) = Q* 8x (A) (see [H]).
(ii )
Forf
E C(X)
we haveStandard
arguments yield
the result. Note that the dual of theL 1 (v)
contraction S is the
operator
R onL~ (v)
definedby R f= d(Q* ( f v))/dv.
THEOREM 3. - Let T be a
positive
operator onL1 (X, ~, m).
Assume(*)
For every there existsvEL satisfying
andv(f»O.
Then:(i)
There existsuELi (m),
u>O a. e. and T u _ u.n n
(ii)
ForT*k 1 (x)
converges a. e., andk=0 k=0
the limit is
positive
a. e. on(
x : k=0I: T*k f (x)
> 0 .J Moreover, the conver-
gence holds
if f u dm 00.
Proof -
We use for theproof
thefollowing reductions, given
in[H]:
L~ (X, E, m)
isisometrically
and orderisomorphic
to a space C(X)
withX
a(extremally disconnected) compact
Hausdorff space, the finite measure mcorresponds
to a measuremEC(X)*,
is a measure if andonly
if itsrepresentation jl
E C(X)*
isabsolutely
continuous withrespect
to
m, L~ (X, E, m)
isisometrically
orderisomorphic
toL~ (X, E, m) (~
is the
a-algebra
of Bairesets),
and theisometry
induces anisometry
ofLi (m)
andL 1 (m) .
Let
T
be therepresentation
of T inL1 (~2).
ThenT
also satisfies(*),
and
if ~L+1 (m)
satisfies Alsou - m « I - hi . Furthermore,
T* is
represented by a positive operator Q
on C(X).
The extension ofQ
to- satisfies
Q 7= T* f=m-a.e.
Thus,
we may assume X to be acompact
Hausdorff space, T*given by extending
apositive operator Q
onC (X),
andL~ (m)
= C(X)*.
The ideasnow follow
[H].
n-l n-l
CLAIM 1. - For every
f E
B(X, E), ~ T*k T*k
1 converges m - a. e.k=0 k=0
We may assume
f ’>
0. SinceT*k f = Qk f
a. e., we defineE={~:
limMn (Q) f (Q)
1(x) exists } .
n - oo
Assume
m (E~) > 0. By
theassumption
of thetheorem,
there exists withQ* v = v
andv(E’)>0. By
lemma2, Q
can be extendedto a contraction S of
L1 (v). By
the Chacon-Ornsteintheorem, Mn (Q) f/Mn (Q)
1=Mn (S) f/Mn (S)
1(v a. e.)
converges v - a. e. Hencev
(E~)
= 0 which is acontradiction, showing m (E~)
= 0.CLAIM 2. - For every n-l n-1 with
f dm>0
we haven -~ oo k=0 k=0
Let
B={x:
and letA = ( f > 0 ) .
n -> 00
Assume
m (A n B)>0.
Thenby
ourassumption,
there existswith
Q* v = v
andv(A~B)>0. Again, by
lemma2,
we use the Chacon-Ornstein theorem to obtain lim
Mn (Q) f (x)/Mn (Q) 1 (x) > 0 v - a. e.
onn - 00
A={/>0},
sinceimplies
But thenv
(A n B)
=0,
a contradiction. Hence m(A n B)
= 0.CLAIM 3. - For any
0~/eB(X, E)
there exists a such thatn- 1
and
T*n f (x)/ ~ T*k
1(.x-) -~
0 m - a. e.k=0
Assume m >
0,
soagain
there exists 0 _ v E C(X)*
withQ*
v = v andThe Chacon-Ornstein lemma
([K],
p.12) applied
toQ
as an-l
contraction in
yields Qk 1 (x) 0
v - a. e., sov(F’)=0,
k=0 a contradiction. Hence m
Now claims
1,
2 and 3 allow us todeduce, by proposition 1,
that there existsu E Li ,
u > 0 a. e.,satisfying
COROLLARY 4. - Let T be a
positive
operator onL1 (X, ~, m).
Assumeoo
that L
T*n 1= 00 a. e. Thenthe following
areequivalent:
n=o
(i )
There exists uE L 1,
u > 0 a. e. and T u = u.n n
(ii)
ForT*k f/ L T*k 1
converges a. e., with the limit~
~=0 o k=0 o
.00 . n
positive a. e.
a. e.(iii)
For every0 # f
EL+~
there exists v EL)
with 0 _ v = T* * v andv (f) > o.
Proof - (i)~(ii) by proposition
1.(iii ) ~ (ii ) by
theorem3,
and(i )
~>(iii ) by taking
dv = u dm.oo
Remarks. - 1. The
assumption L
T*n 1= oo a. e. is usedonly
forM=0
proving (ii)==~(i).
2. If T is a Cesàro bounded
positive operator satisfying (i),
then00
L
T*n 1 00 a. e. on Z(of
the Sucheston Y + Zdecomposition), by
n=0
theorem 3 .1 of
[DL]. Examples
withm (Z) > 0
as in[DL]
show that theassumption
ofcorollary
4 is not necessary for(i).
3. The
equivalence
of the conditions ofcorollary
4 is still trueif,
insteadoo
of L
T*n 1 = oo a. e., we assume thatn=O
for every f e L)
We have to show
only (ii)=>(i).
LetBy (ii)
for any
f~L+~.
In theproof
ofproposition 1,
we define(f) by integrating
overA,
and obtain ~m and invariant.4. If T is Cesàro bounded and has an
equivalent
finite invariant meas-oo
ure, then m
(Y) >0, and L
T*n 1= oo a. e. on Y. The nextexample
showsn=0
oo
that without any boundedness
assumption,
we mayhave L T*k
1 oo a. e.n=0
EXAMPLE. - On Z we take the
counting
measure, and forfen
we define where
w (n) = 2
forn > o, w (n) =1 /2
for
n o,
andw (0) = 1 .
Weeasily compute
(T*h)(n)=h(n-1)w(n-1)
forh~l~.
Defineu~l1 by u (0) = 1 ,
u n 1
forn>O,
~ andu n 1 2
2 I forIt is easy to check that T u = u.
T* 1 (n) = w (n -1 ), and, by induction, T*k
1 nk
w n -- For n - 0
T*k
1 n1 o0
( ) _ fl w (n - j). and 03A3~ T 1 (n) = 2.
*k Forj = 1 2 k=O
~k 1 00
n >_ -
1,
whenk > n, T*~
1(n) = k _ n - k + ~ - 2n’
soagain £ T*~
~:k1(n) ~
ao .2 2
k = 0We now
study
Cesàro boundedoperators.
Thefollowing
result wasoverlooked in
[DL].
LEMMA 5. - Let T be a Cesàro bounded
positive
operator inL1 (X, E, m).
Then ~
~ 0.Proof. -
The estimate in theproof
of theorem 2.1(v)
of[DL] yields,
for any
where K =
sup
.n
If condition
(*)
of theorem 3holds,
there exists a finite subinvariantmeasure J.l
equivalent
to m. Then T* is a contraction ofL1 (~),
andMn (T *) f
converges a. e. forf~L1 ( ), and,
inparticular,
for anyf
EL~
(by [DL],
theorem 3.1 andcorollary 3. 1,
whereonly
subinvariance isneeded.) Also, if m (Y) > 0 (Where
X = Y + Z is the Suchestondecomposi- tion),
T u = u onHowever,
the convergence ofMn(T*) f
does not seem to
yield directly
anequivalent
invariant measure, even ifm
(Y)
> o. On the otherhand,
the existence of anequivalent
finite invariantmeasure
implies ~(Y)>0.
THEOREM 6. - Let T be a Cesàro bounded
positive
operator onL1 (X, E, m).
Then thefollowing
areequivalent:
(i)
(ii )
limsup I Mn (T*) 1~ 1/00
> 0for
any A E L with m(A)
> 0.(iii)
For every there exists withv ( f ) > o.
Proof - (I) « (it) by
the meanergodic
theorem([K],
p.73) applied
toT*, since
- 0(lemma 5). (iii)
~(ii )
is obvious.(i )
~(iii): By
theseparation theorem,
thereexists 11 E L with 11 ( f ) ~ 0
and
T* * 11 = 11 .
We need apositive functional,
so let p= I 11 I.
ThenT** p >_ p, and p
( f ) >_ I
11(f)
> O. Let v = limi
T* *n p. Since T** is CesàroT* * v = v and
v(f»O
are obvious.LEMMA 7. - Let T be a linear operator on
L1 (m),
and assume(I - T*) Loo n L~ = { 0 }. Define
p( f )
=inf {
a :f
a +(I - for
some~ E Then:
1. p
(À)
= ~,for
every real number X.2. p
(.f ) + P (g)~
and p ~, >_ o.3. any real X.
4.
f>_g~
5.
P (T* f)=P(.f)~
andp(T* f-f) = P (f- T* f) = 0.
6.
IfvEL satisfies v ( f ) _ p ( f ) for
every thenT** v = v,
and v
(1)
=1.7. with
If,
inaddition,
T ispositive
and Cesàrobounded,
thenp ( f ) > 0 for OfEL.
Proof. -
1.Putting
a = X and 03A6 = 0 we obtain p(03BB) ~
X. If p(À) X,
there exist E > 0 and 03A6 ELoo
such that03BB ~
X - E +(I - T*)
O . Then(I - T*)03A6~
E,contradicting
theassumption (I - T*) Loo n L~ _ ~ 0 ~.
2. For
E > 0,
let03A62~L~
such thatf~03C1(f)+~+(I-T*)03A61,
Then
Hence
( f ) + p (g). Similarly,
we obtainp(~/)=~p(/).
3. Is
proved
asabove,
and 4. is easy.5. The first part follows from
For the second
part,
a=0and C==/ yield
andp(f-T* f)O yields
a contradiction as in( 1 ). Similiarly, p(T*/2014/)=0.
6. Let for every Then
v(T* f-f)O
andso T**v=v. we have
so
Finally, v(I)~1 imply v ( I ) = 1 .
7. Follows from 6. and a
general
consequence of the Hahn-Banach theorem([M],
p.272). [The inequality
v( f ) _
p( f )
for all the norm onepositive
invariant functionals isimmediate].
The final assertion follows from theorem 6..
Our next results will first
require
thefollowing
technical lemma.LEMMA 8. - Let F be
a family of functions
in1, satisfying:
(i ) if fi , f2
E ~’ andf 1 +f2 ’~ 1,
thenf l
(ii )
For each there exists suchthat f~F.
Then there exists an
increasing sequence {fn}~F
such that 1.Proof. - F
isnon-empty by (ii).
Letf dm|f~F}.
Thereexists a
function f0~F
such thatf0dm~a0 2.
Letit is clear that
003B11 ~03B10 2
and there exists afunction f1~
1-f0, f1~F
and/i~2~~-.
We defineby
induction a sequence of function00
such
that ~ ~~1,
n=n
/ " B
Assume that we have defined
{~}~=o
andif ~ ~ 1 )
defineB
k=0/
it is clear that 0 an + 1 _ _
a° ,
and there exists a functionfn+1~ 1- i .fn +
1 E ff such thatfn +
1 dm >_ It is clear thatfk
E ‘d n. Iff
E F andf _ 00 fk
thenf
dm _a°,
d n, hencef ~
0.Thus £ fk =1
and the lemma isproved.
k=0
LEMMA 9. - Let T be a linear
operator
onL1 (m)
such that(I - T*) Loo n L ) = ( 0 ~,
and assume that p( fn)
-~ 1 whenever 0_ fn _
1 satis-fies
1 a. e. Then there exists UELi
with T u = u, and m{ u > 0 ~
> 0 .Proof. ,-
We will show the existence of a finite measurep, ~ 0
suchthat
f
_ p( f )
for everyf
EL ~,
and obtain that, f dp _ p ( f )
for
every
f E Loo [by
lemma7, 3.],
so that p is invariantby
lemma7,
6.Let ~~ be the set of
positive
measures which are dominatedby
p:~e~~> /~~p(/), V/~0.
Let us define apartial
order in ~ asusual:
.tt ~ .t2 Ç> ~/~0.
be acompletely
ordered subset of and let Then there exists a
sequence { n}~{ 03B1}
suchthat n (X)~03C1.{ n}
is an ordered sequence andlim p,"
is an upper bound Henceby
Zorn’sLemma,
co
u has maximal elements.
Let
be a maximal element of If(X) 1,
define and then:
(i)
1 =>
r(~)
-~i ( 1 ), by
ourassumption.
CLAIM. -
If T(l)>0,
thereexists a f ’unction 0 _ g 1 _
and apositive
number r suchthat for
eachIf it is not true, then for every function and
0rr(l)
thereexists a function such that r Fix r, and define
n
We assumed
Hence
by
lemma8,
there exists anincreasing sequence {fn}
~F suchthat~, ~
1. But 1= lim limT(~)==~2014’>1,
a contradiction.n -~ oo r
So,
the claim isproved.
It is clear that for the set
A=={~>8}(8>0
smallenough)
we haver for
each
For
J.1’ = J.l +
rmIA,
we haveJ.1’ ~
J.1 and which contradicts themaximality
of J-l.Hence ~ (X)
=1.Let f~L~
be any function. It can be found a number such that/+~0;
thus :Hence p
is invariantby
lemma7,
6.LEMMA 10. - Let T be a Cesàro bounded
positive operator
onL1 (X, X, m).
Assume( * *) If
and a. e., thenn - 00
n
Then :
(i)
(ii )
There exists uELi, u ~ 0,
such that T u = u.(iii)
m(Y)
> o.Proof. - (i ) If R 0
there exist functionswith II (I - T*) ~n - f ~ ~ -~ 0,
so lim inf(I - T*) = R 0, hence f=
0.Clearly
(ii )
=>(iii ) .
(ii) By (i ),
we can use the convex functional p defined in lemma7,
andp ( f ) > 0
for0~/eL~.
Let0 -_ fn __ 1
withfn
-+ 1 a. e. Since p is orderpreserving, p {, f ’n) _
1. We show thatp ( fn)
- 1. If not, wehave, by taking
a suitable
subsequence,
Hence there exists(for n large
enough)
Since T ispositive,
Fix n.
By
lemma5,
we can choose k such so wen
obtain
Now
and
[I - M~ (T*)] - rt)
=(I - T* ~ .
Thus(I - T* ~ >_ - oc -1
so thatn
lim
inf (I - T*)
>_ 1- rt >0, contradicting (* *).
Hence p( fn)
~1,
and(ii)
follows from lemma 9.
THEOREM 11. - Let T be a Cesàro bounded
positive
operator onLi (X, :I:, m).
Then thefollowing
areequivalent:
(i) (w*-closure (I - T*) n L ; _ ~ 0 ) .
(ii)
Tsatisfies (* *) of
lemma 10.(iii)
There exists u > o a. e., with T u = u.Proof. - (iii )
~(i )
~(ii )
is easy. Note that(i )
~(iii )
can beproved directly by obtaining (as
in theorem6)
that for every there existuELi
with T u = uTaking
an invariant function with maximalsupport
willyield (iii ).
(ii)
~(iii).
We first show that if m(A)
>0,
then m({ ~
T*n1 A
= 00})
> O.00 00
Assume 03A3~n=0
T*n1 A
oo a. e., and let B={03A3~n=0
T*n1 A
> 0 . Sincecp
= ~
T*nlA
is finite a. e. and T* cp _ cp,L~ (B)
is invariant underT*,
n=0
and if we define S =
IB
T onL1 (B, m),
we have that S* = T*~L~
~B, m~.Clearly
S is also Cesàro bounded.
By property (ii)
forT*,
we have that S* alsohas the same
property. By
theorem3, [which applies,
in view oflemma 10
(i )
and theorem6]
converges a. e. on B to a limit which is
positive
a. e. on A. Sinceby
lemma
10, ~(Y(S))>0, ~ ~ ~ > 0,
and on that subset of~
B(n=o o
J/
/ 00 B 00
B also
lat (03A3n=0T*n 1 A / )= M E = 1 A diverges,
a contradiction to the assump- tion.We now
complete
theproof. By
theorem3,
there exists a finite subinvari- ant measure ~m, i. e.By
theorem 3 .1 of[DL] (where only
subinvariance is needed for the
proof),
T* can be extended to a contraction ofLi (~),
which has as conservativepart
Y anddissipative part
Z.By
oo
lemma
10, m (Y) > 0.
Letm (A) > 0. Then 03A3n=0T*n1A~
a. e. on the dissi-pative part Z,
with non zero measure. On thatset,
by
the Chacon-Ornsteintheorem, MN (T*) 1 A = e ~
M=0 n=0
converges a. e. to a
positive
limit. Hence ifn - 00
m (A) > 0. By
theorem 3 . 2 of[DL],
T has anequivalent
finite invariantmeasure.
Remarks. - It is
conjectured
that the conditions of theorem 6 notonly imply
the existence of anequivalent
subinvariant measure, but even the existence of an invariant one.For the
proof,
we need to show that the conditions of theorem 6imply
m (Y) > 0 [or (* *)
of lemma10],
but ourattempts
have failed.REFERENCES
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(Manuscript received October 9, 1991;
revised February 21, 1992.)