A NNALES DE L ’I. H. P., SECTION A
A RNE J ENSEN
S HU N AKAMURA
The 2D Schrödinger equation for a neutral pair in a constant magnetic field
Annales de l’I. H. P., section A, tome 67, n
o4 (1997), p. 387-410
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387
The 2D Schrödinger equation for
aneutral pair in
aconstant magnetic field
Arne JENSEN
Shu NAKAMURA
Department of Mathematics, Aalborg University,
Fredrik Bajers Vej 7, DK-9220 Aalborg 0, Denmark.
E-mail: matarne@math.auc.dk
Graduate School of Polymathematics, Nagoya University, Chikusa-ku, Japan 464-01 1
E-mail: shu@math.nagoya-u.ac.jp
Vol. 67, n° 4, 1997, Physique théorique
ABSTRACT. - We consider the
two-body Schrödinger operator
for a neutralpair
ofparticles
in two-dimensional space with a constantmagnetic
field.The two
particles
interactthrough
apotential.
We prove absolutecontinuity
of the
spectrum
under several differentassumptions
on thepotential.
Theseassumptions
cover both the Coulomb and the Yukawapotential.
We discusssome
explicitly
solvable models.Key words: Schrodinger operator, magnetic field, absolutely continuous spectrum.
RESUME. - Nous considerons
Foperateur
deSchrodinger
d’unepaire
neutre de
particules
bidimensionnelles soumise a unchamp magnetique
constant. Les deux
particules interagissent
par l’intermédiaire d’ unpotentiel.
Nous demontrons que le
spectre
est absolument continu sousplusieurs
conditions sur le
potentiel.
Ces conditions sont satisfaites par lespotentiels
de Coulomb et de Yukawa. Nous consideronsquelques
modelesexplicitement
solubles.Annales de l’Institut Henri Poincaré - Physique théorique - 0246-021 1
Vol. 67/97/04/$ 7.00/@ Gauthier-Villars
388 A. JENSEN AND S. NAKAMURA
1.
INTRODUCTION
We consider the
Schrodinger operator
for a neutralpair
ofparticles
intwo-dimensional space with a constant
magnetic
field. Thisoperator
isgiven by
acting
on H =L 2 ( R4 ~ ~ .
Here(~,7/)
ER4 = R2
xR2 ,
=1, 2
denotes the masses, e the
(positive) charge, -i8x
the momentum, the vectorpotential,
and V the interaction between thepair.
Themagnetic
field B = is assumed to be constant. In this paper thespectrum
of H is studied.It is well-known that the
spectrum
of the oneparticle
Hamiltonian2m (px - eA(x))2
onL2(R2)
consists of the Landaulevels {eB m (n+1 2) ] n
=0, 1, 2, ...).
Thespectrum
is purepoint
andinfinitely degenerate. Hence,
if we take V - 0 in
( 1.1 ),
then thespectrum
of H is also purepoint
andinfinitely degenerate. Physically
thiscorresponds
to the classical motion of theparticles
in the constantmagnetic
field in two dimensions. If we furtherassume that the total
charge
is zero, which will be donethroughout
thepaper, then the
particles might
be able to movefreely
in themagnetic
field.Thus we arrive at our
problem:
QUESTION. -
Isabsolutely continuous, if V ~
0?The answer is yes for a
fairly large
class ofpotentials, including decaying potentials
of Coulomb and Yukawatype,
andgrowing potentials,
i. e.V(~) 2014~
oo asIxl
2014~ oo. These results are described in detail in Section3,
and then some solvable models and extensions are discussed in Section 4.
In Section 5 we
give
some results on theanalogue
of effective mass inour model.
We
expect
to findabsolutely
continuousspectrum partly
fromanalogy
with the
corresponding
classicalsystem
of twoparticles
withcharges
ina constant
magnetic
field. The classicalequations
of motion admit solutions of the form(~(~), y(t~~ _ (tv, d + tv),
where vand d
are chosen such the Lorenz force on eachparticle
xB
cancels the force from thepotential
2014W(±6!).
This cancellation iseasily
shown to takeplace
for e.g. the Coulomb interaction V = and in both dimension two andthree,
in the latter case v andd
are vectors in theplane orthogonal
toB.
See
[11] ]
for discussion of theproblems
thistype
of motion causes in thestudy
of themany-body problem.
Annales de l’lnstitut Henri Poincaré - Physique théorique
By analogy
with solid statephysics
one could call thepair
with theinteraction considered here for an exciton. See
[ 1,
page626ff]
for a discussion of excitons.One may ask whether there exist non-constant
potentials
such that thespectrum
of H is notpurely absolutely
continuous. We have not been able to answer thisquestion.
It seems to be a non-trivialquestion
in inversespectral theory.
The idea of the
proofs
is thefollowing:
We follow theargument
ofAvron, Herbst,
and Simon[2]
toseparate
the center of mass motion. Thisyields
afamily
ofoperators
ER2, where 03BE
is the totalpseudo-
momentum. We show that each has
purely
discretespectrum,
and theeigenvalues depend analytically
on~.
Then we use ananalogue
of theFloquet-Bloch theory
forperiodic Schrodinger operators
to show absolutecontinuity
of thespectrum
of H. Thekey
element of theproof
is to showthat the
eigenvalues
ofK()
are non-constant withrespect
to~.
Wegive
several conditions on V for this
property
tohold,
thusobtaining positive
answers to the
question
above.The
proofs give
more detailed information than mentioned above. Forexample,
if V is a non-trivialpotential,
such thatV (z)
0 for all z ER2, V(z) -
0 as oo, andeB/ml,
then in the case m1 = m2 thespectrum
of H consists of an infinite sequence ofnon-overlapping
intervals
(bands),
with theright endpoints
ateBk/ml, k
=1, 2,
....Finally
some remarks on results in the literature. We refer to[5, 6, 7, 14]
forgeneral
results and references onmagnetic Schrodinger operators.
Recently
there has been considerable interest in themany-body Schrodinger
operator
with a constantmagnetic
field in space dimension three(for
eachparticle),
and several results on thescattering theory
have been obtainedby
Gerard andLaba,
see the review paper[11] and
references therein. Theproblem
considered in this paper seems not to have been treated before.2. NOTATION. PRELIMINARY RESULTS We
study
theoperator
’
on H =
L2~R4~,
where we write(x, y)
ER4
=R2
xR2 ~xl, x2~,
and for the momentum
operators
px =-2~~ _ -i~~2 ~,
etc. WeVol. 67, n° 4-1997.
390 A. JENSEN AND S. NAKAMURA
assume the
magnetic
field is constant with value B >0,
and use the Coulomb gauge, so the vectorpotential
isgiven by
(2.2)
To state our
assumptions
on thepotential
V we recall the definition of the Kato classK2
in dimension 2: V EK2,
if V E andThroughout
the paper we suppose that V satisfies thefollowing (rather weak) assumption.
ASSUMPTION 2.1. - V is a real-valued
function, decomposed
as V~ _Y~ - Y , T~~
>0,
such thatV+
E and V- EK2.
Under this
assumption
it is well-known(see
forexample [14])
that H isdefined as a
quadratic
formon Q(Ho) n Q(V+ ),
withCÜ(R4)
as a formcore. Thus H is well defined as a
self-adjoint operator
on H. If furthermore V E thenCo (R 4)
is anoperator
core for H.Since H describes a neutral
pair,
the center of mass motion can beremoved. Let
(2.3)
denote the total
pseudo-momentum,
which is thegenerator
of themagnetic
translation group. For a neutral
system
thecomponents
commute, i. e.~2~ _ 0,
which can be verifiedby
directcomputation.
On the otherhand,
it is well-known(and
easy toverify)
that k commutes with H.Thus
{~~1,~2}
form acommuting family
ofself-adjoint operators,
and therefore can bediagonalized simultaneously,
see[2, 8].
In order to carry out concretecomputations,
we introduce ananalogue
of the Fourier transformcorresponding
to k. Let us write(2.4)
Then k is written as
(2.5)
Generalized
eigenfunctions
of thisoperator
aregiven by
(2.6)
and this leads to the definition of the transform
(2.7)
Annales de l’Institut Henri Poincaré - Physique théorique
LEMMA 2.2. - ~ is a
unitary operator
on andsatisfies
(2.8) (2.9)
Moreover,
(2.10)
This Lemma follows
by simple computations.
Note that theexpression (2.10) depends
on the choice of gauge. Now in thevariable ç
appears
only
as aparameter,
hence we can write(2.11)
where the
operator
isgiven by
theright
hand side of(2.10), acting
on
L2(R2).
Since(2.12)
we can translate to
get
(2.13)
where ~ denotes
unitary equivalence.
We first consider thespectrum
of the free term(2.14)
LEMMA 2.3. - The
spectrum of Ko
isdiscrete,
and isgiven by
(2.15)
with
multiplicities. Furthermore, Ko
has compact resolvent. Theground
state is
simple
andgiven by
the Gaussian wavefunction
In
general,
theeigenfunctions
have theform
(2.16)
where
hn(z)
is apolynomial
in z.Vol. 67, n 4-1997.
392 A. JENSEN AND S. NAKAMURA
Proof - Let q
=eB/2
and let(2.17) (2.18)
Then it is easy to show that
(2.19)
and
{a*j, ak}, j
=1, 2,
k =1, 2,
form acommuting family
of creation- annihilationoperators,
i. e.for j
=1, 2, k
=1, 2,
Thus we learn from standard
arguments
that thespectrum
ofKo
isgiven by
theright
hand side of(2.15),
withmultiplicities.
Then it is clear thatKo
has
compact
resolvent. Theground
state isgiven by
the solution toand these lead to
The solution is the Gaussian function
(up
to aconstant),
and thus theground
state is
simple.
Then theeigenfunction corresponding
to theeigenvalue
is
given by
which is of the form
(2.16).
DLet E
N}
denote anon-decreasing
enumeration of withrepetition according
tomultiplicity.
We note that(2.20)
We also note that for ml = m2 the distance between distinct
eigenvalues
is
eB/m1.
Ifm1 ~ m2,
andm1/m2
isrational,
then the distance betweenAnnales de l’lnstitut Henri Poincaré - Physique théorique
distinct
eigenvalues
is bounded from belowby
apositive
constant. Ifm1/m2
is
irrational,
then the distance can bearbitrarily
small for nsufficiently large.
The
following expression
forKo
will be useful insubsequent computations.
Let
m
=-l
+m2
denote the reduced mass, andL3
= zlpz2 - the thirdcomponent
ofangular
momentum. Then(2.21)
This formula can be rewritten as
(2.22)
where
(2.23)
3. ABSOLUTELY CONTINUOUS SPECTRUM FOR H
In this section we
give
our main results on thespectrum
of Hgiven by (2.1 ).
Thespectrum
is shown to bepurely absolutely
continuous under several differentassumptions
on V. The idea of theproof
is similar to theFloquet-Bloch theory
forperiodic Schrodinger operators.
We will showthat the
family
ofoperators ~.K(~~ ~
isanalytic
withrespect
toç,
and eachoperator
hascompact
resolvent. If we can show that theeigenvalues
arenot constant with
respect to ç,
absolutecontinuity
of thespectrum
of H follows. For this purpose we introduce thefollowing assumption.
ASSUMPTION 3.1. - V
satisfies Assumption
2.1 and oneof
thefollowing
three conditions:
such that
(3.1)
THEOREM 3.2. - Let V
satisfy Assumption
3.1. Then H haspurely absolutely
continuous spectrum.This Theorem is
proved
in a series of Lemmas. Webegin by noting
thateach has
purely
discretespectrum.
Vol. 67, n° 4-1997.
394 A. JENSEN AND S. NAKAMURA
LEMMA 3.3. - Let V
satisfy Assumption
2.1. Then haspurely
discretespectrum for each ~ ~ R2,
and the resolvent iscompact.
Proof -
We use theunitarily equivalent expression
=Ko + ~ ~ - -,~)
from
(2.13).
Thisoperator
is defined as aquadratic form,
hence+
Y~’ - /3))
== +V~+~’ - {3))
çQ(Ko).
Thus wehave, using
Theorem
A.l,
where denotes the nth
singular
value of theoperator
A. It follows thatKo
+V+ (.
-{3)
haspurely
discretespectrum,
since alternative(a)
inTheorem A.l. holds. Now V- is
Ko
+V+ ( . -03B2)-form-bounded
with relativebound zero, hence
Ko
+V( . - {3)
hascompact
resolvent andpurely
discretespectrum,
see[13,
TheoremXIII.68].
DIn order to
apply
TheoremA.5,
we fix oneparameter ~2,
orequivalently,
The nth
eigenvalue
of is denotedEn(ç) (repeated according
tomultiplicity).
We note that underAssumption
2.1 is ananalytic family
of
type
B(see [9]),
thus the next result is well-known.LEMMA 3.4. -
R2. non-degenerate eigenvalue,
then there exists 8 > 0 such that
for 1~1 - ç~1 8
analytic
in~1. If
isa j-fold degenerate eigenvalue,
i.e. we have== ... there exist 8 > 0
and j analytic functions f 1 (~1), ... , f~ (~1 ),
such thatfor
all~1
with~~1 - ç~1
8.Thus we can relabel the
eigenvalues En
toget
afamily
with eachfunction
analytic
in the~1-variable.
Theseanalytic
functions are denoted£n(ç),
hence~En ~~~ ~ ] n
=1,2,...}
=={£n(ç) ‘ n
=1,2,...},
for eachç
ER2 .
In order toapply
Theorem A.5 we need to show that each~n (ç)
is non-constant. For the cases
(i)
and(ii)
inAssumption
3.1 we use thefollowing property.
LEMMA 3.5. -
Suppose
that Vsatisfies Assumption
2.1 andY ( z ) -~
0 as~ z I
--~ 00. Thenfor
each n,En (ç)
--~En (oa)
- 00.Annales de l’lnstitut Henri Poincaré - Physique théorique
Proof -
We use therepresentations (2.13)
and(2.22)
here. Theproof
is based on the
cut-and-paste technique (or geometric perturbation theory),
where we
decompose R2
into twopieces. Let x
EC° ( [0 , oo ) )
be a smoothcut-off function such that 0 1 for all r >
0,
and(3.2)
We choose another smooth cut-off
function x
E such thatFurthermore,
let(3.3) (3.4)
and
(3.5)
We write
(3.6)
The map
JR : j~(R~) -~ L2(R2)
denotes theisometry given by
Then we can
approximate by
It is easy to see that(3.7)
with
TR
=LR,j3JR -
Asimple computation
shows that for c > 0(3.8)
where C is a constant
independent
of R. Now we note that(3.9)
for some constant C >
0,
due to the(pz - A(z))2-form-boundedness
ofNote that the form bound is
independent
of~3.
Vol. 67, n° 4-1997.
396 A. JENSEN AND S. NAKAMURA
Let
Fn (R, /3)
denote the ntheigenvalue
ofL~.
If R issufficiently large,
the
inequality (3.9) implies
thatFn(R, ~3)
is the ntheigenvalue
ofBut then
(3.7)
and(3.8), together
with the Rieszintegral representation
forthe
projection
onto theeigenspace, imply
that we have(3.10)
for
sufficiently large R, independently
of/3
ER2.
We take anarbitrary
c > 0 and fix R so
large
that theright
hand side of(3.10)
is less thanc/3.
Now the same
arguments
can beapplied
to the case Y -0,
which we denoteby /3
= oo. On the otherhand,
it follows from the definitions that(3.11)
As a consequence of these observations we
get
(3.12)
and the
right
hand side converges to zero as1131
- 00. We choosebo
> 0so
large
that theright
hand side of(3.12)
is less thanc/3
for >bo.
Then we have
LEMMA 3.6. - Let V
satisfy Assumption 3.1-(i). Then for
GR2,
n e
N,
we haveProof. -
We use the PoincaréPrinciple,
Theorem A.2. Let 03C6j denote thejth eigenfunction
of and letJY~
= CL~(R~).
We have for any p E
JYn
since due to
(2. 16)
the zero-set of p has measure zero, andby assumption
0.
Annales de /’Institut Henri Poincaré - Physique théorique
Since
Xn
isfinite-dimensional,
we haveand the claim follows from the Poincaré
Principle.
DLEMMA 3.7. - Let V
satisfy Assumption 3.1-(ii).
Thenfor
each n E Nthere exists
bo
> 0 such thatEn ~~)
>En for
any/3 with 1131 ]
>bo.
Proof -
We use the notation from theproof
of Lemma3.5,
andtry
to estimate the differenceFn (R, ,~) -
If we use theAgmon
methodfor
exponential decay estimates,
we can show that for any 03B3 eB/4, (3.13)
The
proof
isstandard,
and will beomitted,
see forexample [3, 4].
Inthe same manner we can obtain
(3.14)
with the same constant C as in
(3.13).
On the otherhand,
we canchange
the definition of
W~,,~ slightly
to obtain the estimate(3.16) below, namely,
we let
(3.15)
We take
!3
with1!31
= 4R and use theassumption (3.1)
such that we haveif R is
sufficiently large. Hence,
we also haveand
(3.16)
We then choose a so that 0 36a
~y eB/4.
Weget
if R is
sufficiently large.
DVol. 67,n° 4-1997.
398 A. JENSEN AND S. NAKAMURA
REMARK 3.8. - In the
proof
above we use(3.1)
from3.1-(ii)
fora
e~~ 144,
but this is notoptimal.
Infact,
we can show aeB/8
is sufficient
by modifying
theproof (which
then becomes somewhatcomplicated).
LEMMA 3.9. - Let V
satisfy Assumption 3.1-(iii).
Thenfor
each n E Nwe have
~n (~3) -~
00 as - 00.Proof -
Choose R > 0 such that > 0for Izj
> R. Let x~ denote the characteristic function of theR},
and letx~
= 1 - x~. Wedecompose
V= ~1 ~ v2
=XRV
+XR V.
ThenVi
isand
~2 >
0.Moreover,
due to3.1-(iii)
we haveThus we obtain as
quadratic
forms for some constant cIt follows that each
eigenvalue
of~"(/9) diverges
toinfinity
as 2014~oo. DProof of
Theorem 3.2. - We writewhere
For each fixed
~2
eacheigenvalue
ofÇ2)
is(locally)
ananalytic
function of
~1 by
Lemma 3.4.By
Lemmas3.5-3.7,
3.8 eacheigenvalue
cannot be constant in hence all conditions in Theorem A.5 are satisfied.
Thus
~"(~2)
haspurely absolutely
continuousspectrum
for each~2.
ThenH is also
purely absolutely continuous, by
Theorem A.3. 0For the interval near the bottom of the
spectrum
of H we can show absolutecontinuity
under differentassumptions
on V.ASSUMPTION 3.10. - Let V
satisfy Assumption 2.1,
andfurther
0as
jzl
-~ oo, andV(z)
>0 for all z
ER2.
Annales de l’lnstitut Henri Poincaré - Physique théorique
THEOREM 3.11. - Let V
satis, fy Assumption
3a 1 D. Then infa(H)
=El (00),
and there exists ~ >
El(oo)
such that~~
Ca(H),
and H isabsolutely
continuous on~E1 (00), .~~.
’Proof -
It suffices to show that the functionEl ()
is not constant.Note that
E1 ( oo )
isnon-degenerate by
Lemma 2.3. Weagain
usethe
representation together
with(2.22).
SinceV ~ 0,
we haveEl ( ~ ) >
for all/3
ER2 .
Now let us assume =Ei(oo)
forsome
/3. Let ~
be a normalizedeigenfunction
ofcorresponding
tothe
eigenvalue El ({3).
Thenand hence
(~,V(- -
0. SinceV (z)
> 0 for all z, thisimplies 03C8
= 0. Therefore we haveEl (ç)
> forall 03BE
ER2. Together
withLemma 3.5 this
implies
that~1
is non-constant. The result now followsas in the
proof
of Theorem3.3,
if we note(2.20).
DWe now
give
two results whichrequire
more restrictiveassumptions
onthe
potential.
Theproofs
willonly
be sketched.ASSUMPTION 3.12. - Let V
satisfy Assumption 2.1,
andfurthermore
V E
C1(R2)
such thatfor
some v ER2, ~ Iv I
==1,
’
(3.17)
THEOREM 3.13. - Let V
satis, fy Assumption
~.12. Then thespectrum of
His
purely absolutely
continuous.Proof. -
Weonly
outline theproof.
The detailedarguments
are similarto the
arguments
in Section 5. LetR2
and let denote one of theeigenvalues
of which is assumed to beregular
in a smallneighborhood
of/3o.
Let r denote a circle centered at with asufficiently
smallradius,
such that no othereigenvalues
are on or inside Ffor all
/? with 1{3 - {30 I
8. LetLet p
EL2(R2),
such that 0. Standardarguments
fromperturbation theory
thengive
us the formulaVol. 67, nO 4-1997.
400 A. JENSEN AND S. NAKAMURA
It follows from the
assumption (3.17)
thatE ~~3)
is not constant close to{3o.
Thisargument
can beapplied
to alleigenvalues
and almost all valuesof
{3.
Theproof
is then concluded as above. DASSUMPTION 3.14. - Let V
satisfy Assumption
2.1. Assume there exist constantsV)
ER, Y+ ~ Y°,
and v ER2, ~ Ivl
=1,
such thatuniformly
in z on compact subsetsof R2.
THEOREM 3.15. - Let V
satisfy Assumption
3.14. Then the spectrumof
His
purely absolutely
continuous.Proof -
Theproof
is based on thegeometric perturbation theory
and isa variant of the
proof
of Lemma 3.5. Webriefly
comment on thechanges
necessary. We define
(3.18)
as a
replacement
for(3.3)
and introduceUsing (3.18)
we letand define
With these and other obvious modifications the
arguments
in theproof
of Lemma 3.5 can be
repeated.
We note that theeigenvalues
ofsatisfy Fn (R, +00)
- +V~
as R - oo . Similararguments apply
in the case t
0,
with an obviouschange
in the definition(3.19)
andthe final result is
Since
V~ 7~ Y°,
we see that eacheigenvalue
is non-constant, and theproof
is
completed
as above. DFinally
we note for later use thefollowing
result.Annales de l’lnstitut Henri Poincaré - Physique théorique
PROPOSITION 3.16. - Assume V
real-valued,
V EL°° (R2 ~
withand
V(z) ~
0 asIzf
---+ ~. Then theground
stateE1(03BE) of K(ç)
isnon-degenerate for all ~
ER2.
Proof -
Standardarguments
fromperturbation theory
show thatfor all n E N and
all ç
ER2.
This estimatetogether
with theassumption (3.20),
Lemma3.5,
and(2.20) yield
the result in theProposition.
D4. SOLVABLE MODELS AND SOME EXTENSIONS
In this section we discuss some
explicitly
solvablemodels,
and wegive
some extension of the results in the
previous
section.We first consider the case where we add an external constant electric field E E
R~ B {0}.
For Y - 0 weget
anexplicitly
solvableproblem,
and ingeneral
for bounded V we show that thespectrum
isabsolutely
continuous.Since the two
particles
haveequal
andopposite charges,
we have withoutpotential
the Hamiltonianwhich fits into the framework of Section
2,
and we can carry out thedecomposition
as above. Thisargument
also shows thatHo(E)
is a well-defined
self-adjoint operator.
We state the result in the~-formulation,
see(2.13),
and use the form(2.22).
We have(4.2)
where
(4.3)
Vol. 67, n° 4-1997.
402 A. JENSEN AND S. NAKAMURA
The
spectrum
ofK 1 (E)
can be foundexplicitly,
since thisoperator
isunitarily equivalent
toKo (see (2.22))
via amagnetic
translation.This observation was also made in
[15],
wherescattering problems
inspace-dimension
three were considered.We conclude that has
compact
resolvent. Thespectrum
isgiven by
(4.4)
where is a
non-decreasing
enumeration of theeigenvalues of Ko ,
asin Section 2 .
Obviously,
eacheigenvalue
is non-constant in/?. Furthermore,
each
eigenvalue
covers Ras {3
variesthrough R2. Repeating
thearguments
in Section3,
we conclude thatHo(E)
haspurely absolutely
continuousspectrum equal
to R.This
explicit
result can begeneralized
as follows.PROPOSITION 4.1. - Let V E
LCX)(R2) be
real-valued and let E ER21 ~0~.
Then the operator
(4.5)
has
purely absolutely
continuous spectrumequal
to R.Proof. -
As above we havewith
Since
Kl (E)
hascompact
resolvent andffd (Ki (E)) _ ] n
EN},
and since V isbounded,
theoperator
+V(z - {3)
hascompact
resolvent. We writeStandard
perturbation theory yields
(4.6)
Annales de l’Institut Henri Poincaré - Physique théorique
for all n E N and all
/3
ER2.
ThusK(E"~)
hascompact
resolvent and itseigenvalues
aregiven by
(4.7)
Using (4.6)
we see that theeigenvalues
are non-constant in/3,
and coverR as
{3
variesthrough R2.
Thus thespectrum
ofH(E)
isabsolutely
continuous and
equals
R. DREMARK 4.2. - One can also
apply
Theorem 3.15. Under theassumptions
V E
C1(R2)
and E . +E2
> 0 for all z ER2
we conclude that thespectrum
of H ispurely absolutely
continuous. We should also add acondition that allows us to define
H(E) (see (4.5))
as aself-adjoint operator.
Let us now consider the
particular
caseV(z)
=coz2,
the harmonicoscillator
potential.
We also include an external constant electric fieldE,
but this time we allow E to
equal
0. We take(4.8)
and
decompose
as aboveSome
straightforward algebraic manipulations give
(4.9)
where
w5
=e2 B2
+2Mco.
Theoperator
isunitarily equivalent
to the
operator
(4.10)
via a
magnetic
translation. Therefore hascompact
resolvent. Theoperator
in(4.10)
isquadratic
in pz and z. It is well known that itsspectrum
Vol. 67, n° 4-1997.
404 A. JENSEN AND S. NAKAMURA
can be
computed explicitly,
see forexample [ 12]
for details. One finds that theeigenvalues
ofK(E,
co;{3)
aregiven by
(4.11) They
areobviously
non-constant in/3.
We state the results as follows.
PROPOSITION 4.3. - Let E E
R2
and let co > 0. Then the operator H( E, co ) given by (4.8)
haspurely absolutely
continuousspectrum a(H(E, co ) )
==oo),
wherewith
Proof -
Theproof
follows from theexplicit
formula(4.11 )
for theeigenvalues
andarguments
as above. DREMARK 4.4. - Since
V(z)
=c0z2
+ E . z satisfiesAssumption
3.1-(iii),
we know from Theorem 3.2 that thespectrum
ofH(E, co)
ispurely absolutely
continuous. Lemma 3.9 furtherimplies
that thespectrum
is a half-line. The above resultgives
anexample
where the bottom can be determinedexplicitly.
5. EFFECTIVE MASS
In this section we
give
some results on theanalogue
of effective masscomputation
forperiodic Schrodinger operators.
Here westudy
the effectivemass for the bottom of the
spectrum. Namely,
we look at the Hessian matrix:Annales de l’lnstitut Henri Poincaré - Physique théorique
where is the lowest
eigenvalue
ofK(~~,
andço
is the minimalpoint
of
El (g) . By
thedefinition,
isnonnegative.
If isstrictly positive,
the inverse of the
eigenvalues
are calledeffective
masses,by analogy
toperiodic Schrodinger operators,
see[1] ]
for thephysics background
and[10]
for somerigorous
results. These values areexpected
to dominate thelong-time
behavior of the the time-evolution of states with energy near the bottom of thespectrum.
Example
5 .1 . - LetV(z)
=coz2. Then, taking
E =0,
nl =0,
n2 = 0 in(4.11 )
andusing (2.12),
we findwhere
w5
=e2B2
+2Mco.
Thus isgiven by
and theeffective mass is
In the
following,
westudy
theproperties
of(eij)
andgive
a sufficientcondition for the strict
positivity
of thismatrix, i.e.,
the finiteness of the effective masses. Without loss ofgenerality,
we may suppose~o
= 0.Moreover,
we supposeASSUMPTION 5.2. -
El (ç) is non-degenerate for 03BE
ER2.
A sufficient condition for
Assumption
5.2 isgiven by Proposition
3.16. Asbefore,
wealways
supposeAssumption
2.1. We use thefollowing
notation:1jJ
is theground
state ofK(0), i.e.,
= with11’l/J11
= 1.P(~)
is the
projection
onto theground
state ofwhere r is a
sufficiently
small circle aroundIf ç
is in a smallneighborhood
of0,
it is easy to see thatWe write
LEMMA 5.3
Vol. 67, n° 4-1997.
406 A. JENSEN AND S. NAKAMURA
Proof. -
For the sake ofsimplicity,
we setEl (0)
= 0 without loss ofgenerality. By differentiating
=g(~),
we obtainBy
directcomputations,
we see that theright
hand side isgiven by
where r is a small
circle
around 0. Then we useand the claim follows
by simple computations.
We note that each term inthe
right
hand side of(5.1)
issymmetric
in i andj.
DIn order to
compute
theright
hand side of(5.1 ),
weemploy
thefollowing expression
for(5.2)
where m and e are
given
at the end of Section2,
andIt is easy to see that
We set
LEMMA 5.4.
(5.4)
Annales de l ’lnstitut Henri Poincaré - Physique théorique
Proof. - By
directcomputations,
we haveand the claim follows. 0
By (5.3)
and(5.4),
we learnOn the other
hand,
it is easy to seeCombining
these with Lemma5.3,
we obtain our main result of this section:THEOREM 5.5. - With the notation introduced
above,
(5.5)
holds in the
operator
sense onC2,
where12 x 2
is the 2by
2 unit matrix.The
proof
is astraightforward computation,
which we omit.COROLLARY 5.6. -
If 4(El (0~ - F) E2 ~Q~ - E1 ~0~,
then is non-degenerate, i.e.,
theef~ f’ective
masses at the bottomof
the spectrum arefinite.
In
particular,
if ml = m2, then e =0,
and we have asimpler picture.
Namely,
isgiven by
Hence, by
theCourant-Weyl principle,
the discreteeigenvalues
ofK(0)
converges to those of h as B - 0.
If,
moreover, F is discrete ina(h),
thenThus we have
These
imply
thefollowing:
COROLLARY 5.7. -
Suppose
ml = m2, and suppose F is discrete ina(h).
Then
(eij)
isnon-degenerate if |B| is sufficiently
small.Vol. 67, n° 4-1997.
408 A. JENSEN AND S. NAKAMURA
A. AUXILIARY RESULTS
This
appendix
contains theprecise
statement of some results needed inour
study,
and in a few cases outlines ofproofs.
. A.I. Min-max and max-min
For reference we state
precisely
the min-max and max-minprinciples
used in our
study.
We recall the
following
result forquadratic
forms from[ 13] .
It is there called the min-maxprinciple.
Here weprefer
to follow[16]
and call it theCourant-Weyl principle.
THEOREM A.1. - Assume H is
self-adjoint
and bounded below. Let(A.l )
Then
for
eachfixed
neither(a)
there are neigenvalues
below the bottomof
the essentialspectrum,
and(H)
is the ntheigenvalue (counted
withmultiplicity)
or
(b) (H)
is the bottomof
the essentialspectrum.
An alternative formulation is what in
[ 16]
is called the Poincaréprinciple,
and for
consistency
one could call it the max-minprinciple.
THEOREM A.2. - Assume H is
self-adjoint
and bounded below. LetThen the alternative in Theorem A.l holds.
A.2. Results on
decomposable operators
In this
part
of theappendix
wegive
some results on thespectrum
ofa
decomposable operator.
The results are well-known and are stated here for easy reference.THEOREM A.3. - Let
(M,
be aa-finite
measure space and let T =~~
be adecomposed self-adjoint
operator~~
Then thefollowing
results hold:(i)
For any bounded Borelfunction
FAnnales de l’lnstitut Henri Poincaré - Physique théorique
Proof -
For the results(i)-(iii)
we refer to[13,
TheoremXIII.85].
For(iv)
we note that theproof
in[ 13]
can be localized to the interval I. DDEFINITION A.4. - A function
f :
R ~ R is said to bepiecewise strictly
monotone, if there exists apartition
R =Uj~NIj
intodisjoint
intervals whose
endpoints
have no finitepoint
ofaccumulation,
such thatthe restriction of
f
to eachIj
isstrictly increasing
orstrictly decreasing.
THEOREM A.5. - Let T =
~R
be adecomposed self-adjoint
operator on the space H =
~R H’dm.
Assume( 1 )
For each mER has compact resolvent.(2)
For each m ~ R and n E N(3)
For each n E N thefunction
isbounded,
andpiecewise strictly
monotone, andfurthermore
thepiecewise
inverse isLipschitz
continuous.
(4)
The map nt - ismeasurable,
andfor
each mERn
EN~
is an orthonormal basisfor H’.
Then T has
purely absolutely
continuous spectrum.Proof. -
Theproof
is a variant of theproof
of[ 13,
TheoremXIII.86].
We outline it for the sake of
completeness.
DefineThe
subspaces 1in
areclosed, pairwise orthogonal,
and due toassumption (4)
Furthermore, Hn
CD(T)
andT(Hn)
CLet p
EHn, 9(rn) =
A
computation
shows =~~f~~r~(R~.
ThusUn :
1jJ
-f, Un : L2(R)
defines aunitary
map.Let
T"
= Then acomputation
shows thatThus
Tn
ismultiplication by
the function which satisfies the conditions inassumption (3),
and therefore haspurely absolutely
continuousspectrum.
DVol. 67, n° 4-1997.